Catalina Montijo-Vindas
CRN: 83671
09/08/2023
Textbook homework 1 :2-14, 2-37, 2-43, 2-65, and 2-79.
Fi 1200lb
-
=
FF
↑
=
FB 900/b
=
300
-
FR1200
=
lb
x
600
Find FA
To
Law
of
cosines
C a- b2
Answers:FA 615.9/b
=
=
G 46.930
+
-
2ab cost
=
C 900" 1200". 2(900) (1200) (Os (30%)
+
=
find
To
Fn=35.99
C 615.94247
=
FB 900/b
C
=
300
-
V
FR1200
=
>
lb
600
900 615.9 12004 2(615.9) (1200)
+
=
-
(Os) (
2
900 615.9 12004 2(615.9)(1200)
+
=
-
(0s)
(
900Z615.9 +1200"-2(615.9) (1200) (OS) (
(615.92 1200)
-
9002
-
+
(615.9" 1200)
=
-
+
2(615.4)(1200) (0s)
2(615.9)(1200)
-
9002-(615.9" +1220)
-
2(615.9)(1200)
(os E)
46.93%
-
=
COs +
(
615.9 FA
=
=
⑦
M
.
+
.
F 9004
=
>
#
0 5 9004
=
+
E2 7504C0S450 750;sin450
530.334
=
530.335
+
+
=
#3 6504()
-
=
FR F,
=
6505(5)
Fz 3
+
+
5204-3905
=
530.334
900i
+
=
FR 1950.334
=
530.334 5204 3905
+
+
-
140.335
+
(FR) (1950.33)" (140.33)"
=
+
IFR 1 1955.4
=
F
IFRF1955.4
N
N
Tan"),(40.33) is
=
an
at
angle
of
4.120
in the
positive direction.
⑥
a
+
<
+
3
-
<
-
-
3
#
*
F=850(*)
->
Fz
F5
=
=
-
-
850(5)
J
(300 4-625c0s (300
625sin
-
i
6804
=
=
-
750sin(450)4 730cs(45)y
+
FR 6809
=
-
5105
-
312.54
-
-
5105
312.54-541.35
=
-
5315
5314
+
541.35 5314
-
5315
+
->
FR
-
=
(FR)
O
163.54
-
520.35
7163.5)7520.3)"
545.4N
=
=
tan"(203) 72.60
=
=
IFml 545.4N
=
1800 252.6
+
an
at
direction
X
=
angle of252.6
counterclock wise in
a
negative
Fi(xy)F,C0s60 150
=
=
Fix
Fzy
Fiz
*
150
=
45
sin
106.19
=
150(0545 106.1j
=
=
300 sin
=
600259.8
# 106.14 106.19 259.84
=
+
+
7
Fz SOON
=
FIX
--
F(y
-
L
-
500 COS
=
60 250Y
=
500c0s45
=
F.z 500
=
353.554
=
Cos 120
-
=
250
-z 2504 353.555
+
=
Fm (106.19
106.13
+
=
-
250
259.8) (2504 353.555 250K)
+
+
-
+
FR 143.94 459.655 9.8
+
=
+
IFR1 143.97459.65 9.87
=
-
<x
cos
=
Bycos
-
&zcos
-
1
1
143.9
481.7
=
72.60
2x 72.60
17.40
3 y 17.40
88.830
5z 88.830
=
=
481.7
459.65
=
=
481.7
1
9.8
481.7
=
=
·
FX Fsin OzCOSO
=
Fy FsinGzsin
=
Fz FCOSOz
=
F 4SON
=
8z 450
=
0
1200
=
45°COs 1200
FX 4SOsin
=
-
1594
=
V=
Fix 450
=
?
Sin 450 Sin 1200
N
Fz 450C0545
318.195k
=
=
*B
*
275.55
=
8>900
cosx
U
cos" B cos)
+
+
1
=
(05')I-cos(us c0s"(60)
+
=
VOU=60
F
=
-
1594
2765 3184
+
+
->
Fz 4244 3005
+
=
-
300
Ix 60080(020
FR 634N
=
x
10S450 424
=
=
300;
Fz 400
N
⑧
(OS 170
=
↑
=
=
-
300k
65.30
=
B 24.80
=
5 88.40
=
FR
=
-
1594
2765 318k
+
-
FR 265.164
=
+
424i 3005
+
+
575.575
+
a
18.2k
+
(FR) 265.16575.S7718.24
=
(FRF634N
&cocposits.Re
V
cost
=
(182)
8.o
=
-
300