Uploaded by yasarcereen

Quicksort

advertisement
Introduction to Algorithms
6.046J/18.401J
LECTURE 4
Quicksort
• Divide and conquer
• Partitioning
• Worst-case analysis
• Intuition
• Randomized quicksort
• Analysis
Prof. Charles E. Leiserson
September 21, 2005
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.1
Quicksort
• Proposed by C.A.R. Hoare in 1962.
• Divide-and-conquer algorithm.
• Sorts “in place” (like insertion sort, but not
like merge sort).
• Very practical (with tuning).
September 21, 2005
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.2
Divide and conquer
Quicksort an n-element array:
1. Divide: Partition the array into two subarrays
around a pivot x such that elements in lower
subarray ≤ x ≤ elements in upper subarray.
xx
≤≤ xx
≥≥ xx
2. Conquer: Recursively sort the two subarrays.
3. Combine: Trivial.
Key: Linear-time partitioning subroutine.
September 21, 2005
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.3
Partitioning subroutine
PARTITION(A, p, q) ⊳ A[ p . . q]
x ← A[ p]
⊳ pivot = A[ p]
Running
Running time
time
i←p
== O(n)
O(n) for
for nn
for j ← p + 1 to q
elements.
elements.
do if A[ j] ≤ x
then i ← i + 1
exchange A[i] ↔ A[ j]
exchange A[ p] ↔ A[i]
return i
Invariant: xx
p
September 21, 2005
≤≤ xx
≥≥ xx
i
??
j
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
q
L4.4
Example of partitioning
66 10
10 13
13 55
i
j
September 21, 2005
88
33
22 11
11
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.5
Example of partitioning
66 10
10 13
13 55
i
j
September 21, 2005
88
33
22 11
11
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.6
Example of partitioning
66 10
10 13
13 55
i
j
September 21, 2005
88
33
22 11
11
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.7
Example of partitioning
66 10
10 13
13 55
66
September 21, 2005
88
33
22 11
11
55 13
13 10
10 88
i
j
33
22 11
11
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.8
Example of partitioning
66 10
10 13
13 55
66
September 21, 2005
88
33
22 11
11
55 13
13 10
10 88
i
j
33
22 11
11
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.9
Example of partitioning
66 10
10 13
13 55
66
September 21, 2005
88
33
22 11
11
55 13
13 10
10 88
i
33
j
22 11
11
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.10
Example of partitioning
66 10
10 13
13 55
88
33
22 11
11
66
55 13
13 10
10 88
33
22 11
11
66
55
September 21, 2005
33 10
10 88 13
13 22 11
11
i
j
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.11
Example of partitioning
66 10
10 13
13 55
88
33
22 11
11
66
55 13
13 10
10 88
33
22 11
11
66
55
September 21, 2005
33 10
10 88 13
13 22 11
11
i
j
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.12
Example of partitioning
66 10
10 13
13 55
88
33
22 11
11
66
55 13
13 10
10 88
33
22 11
11
66
55
33 10
10 88 13
13 22 11
11
66
55
33
September 21, 2005
22
i
88 13
13 10
10 11
11
j
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.13
Example of partitioning
66 10
10 13
13 55
88
33
22 11
11
66
55 13
13 10
10 88
33
22 11
11
66
55
33 10
10 88 13
13 22 11
11
66
55
33
September 21, 2005
22
i
88 13
13 10
10 11
11
j
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.14
Example of partitioning
66 10
10 13
13 55
88
33
22 11
11
66
55 13
13 10
10 88
33
22 11
11
66
55
33 10
10 88 13
13 22 11
11
66
55
33
September 21, 2005
22
i
88 13
13 10
10 11
11
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
j
L4.15
Example of partitioning
66 10
10 13
13 55
88
33
22 11
11
66
55 13
13 10
10 88
33
22 11
11
66
55
33 10
10 88 13
13 22 11
11
66
55
33
22
88 13
13 10
10 11
11
22
55
33
66
i
88 13
13 10
10 11
11
September 21, 2005
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.16
Pseudocode for quicksort
QUICKSORT(A, p, r)
if p < r
then q ← PARTITION(A, p, r)
QUICKSORT(A, p, q–1)
QUICKSORT(A, q+1, r)
Initial call: QUICKSORT(A, 1, n)
September 21, 2005
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.17
Analysis of quicksort
• Assume all input elements are distinct.
• In practice, there are better partitioning
algorithms for when duplicate input
elements may exist.
• Let T(n) = worst-case running time on
an array of n elements.
September 21, 2005
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.18
Worst-case of quicksort
• Input sorted or reverse sorted.
• Partition around min or max element.
• One side of partition always has no elements.
T (n) = T (0) + T (n − 1) + Θ(n)
= Θ(1) + T (n − 1) + Θ(n)
= T (n − 1) + Θ(n)
= Θ( n 2 )
September 21, 2005
(arithmetic series)
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.19
Worst-case recursion tree
T(n) = T(0) + T(n–1) + cn
September 21, 2005
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.20
Worst-case recursion tree
T(n) = T(0) + T(n–1) + cn
T(n)
September 21, 2005
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.21
Worst-case recursion tree
T(n) = T(0) + T(n–1) + cn
cn
T(0) T(n–1)
September 21, 2005
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.22
Worst-case recursion tree
T(n) = T(0) + T(n–1) + cn
cn
T(0) c(n–1)
T(0) T(n–2)
September 21, 2005
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.23
Worst-case recursion tree
T(n) = T(0) + T(n–1) + cn
cn
T(0) c(n–1)
T(0) c(n–2)
T(0)
O
Θ(1)
September 21, 2005
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.24
Worst-case recursion tree
T(n) = T(0) + T(n–1) + cn
cn
T(0) c(n–1)
T(0) c(n–2)
T(0)
⎛ n ⎞
Θ⎜⎜ ∑ k ⎟⎟ = Θ(n 2 )
⎝ k =1 ⎠
O
Θ(1)
September 21, 2005
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.25
Worst-case recursion tree
T(n) = T(0) + T(n–1) + cn
cn
Θ(1) c(n–1)
h=n
Θ(1) c(n–2)
Θ(1)
⎛ n ⎞
Θ⎜⎜ ∑ k ⎟⎟ = Θ(n 2 )
⎝ k =1 ⎠
O
T(n) = Θ(n) + Θ(n2)
= Θ(n2)
Θ(1)
September 21, 2005
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.26
Best-case analysis
(For intuition only!)
If we’re lucky, PARTITION splits the array evenly:
T(n) = 2T(n/2) + Θ(n)
(same as merge sort)
= Θ(n lg n)
What if the split is
1 9
always 10 : 10 ?
T (n) = T (101 n ) + T (109 n ) + Θ(n)
What is the solution to this recurrence?
September 21, 2005
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.27
Analysis of “almost-best” case
T (n)
September 21, 2005
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.28
Analysis of “almost-best” case
cn
T (101 n )
September 21, 2005
T (109 n )
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.29
Analysis of “almost-best” case
cn
1
10
cn
9
10
cn
9
9
81
1
T (100
n ) T (100
n ) T (100
n )T (100
n)
September 21, 2005
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.30
Analysis of “almost-best” case
1
10
cn
9
100
9
10
cn
O(n)
O(n) leaves
leaves
…
Θ(1)
cn
log10/9n
9
81
cn
cn
100
100
…
1
100
cn
cn
cn
cn
…
cn
Θ(1)
September 21, 2005
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.31
Analysis of “almost-best” case
1
10
9
100
9
10
cn
Θ(n lg n)
Lucky!
September 21, 2005
O(n)
O(n) leaves
leaves
…
Θ(1)
cn
log10/9n
9
81
cn
cn
100
100
…
log10n
1
cn
100
cn
cn
cn
cn
…
cn
Θ(1)
cn log10n ≤ T(n) ≤ cn log10/9n + Ο(n)
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.32
More intuition
Suppose we alternate lucky, unlucky,
lucky, unlucky, lucky, ….
L(n) = 2U(n/2) + Θ(n) lucky
U(n) = L(n – 1) + Θ(n) unlucky
Solving:
L(n) = 2(L(n/2 – 1) + Θ(n/2)) + Θ(n)
= 2L(n/2 – 1) + Θ(n)
= Θ(n lg n) Lucky!
How can we make sure we are usually lucky?
September 21, 2005
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.33
Randomized quicksort
IDEA: Partition around a random element.
• Running time is independent of the input
order.
• No assumptions need to be made about
the input distribution.
• No specific input elicits the worst-case
behavior.
• The worst case is determined only by the
output of a random-number generator.
September 21, 2005
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.34
Randomized quicksort
analysis
Let T(n) = the random variable for the running
time of randomized quicksort on an input of size
n, assuming random numbers are independent.
For k = 0, 1, …, n–1, define the indicator
random variable
Xk =
1 if PARTITION generates a k : n–k–1 split,
0 otherwise.
E[Xk] = Pr{Xk = 1} = 1/n, since all splits are
equally likely, assuming elements are distinct.
September 21, 2005
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.35
Analysis (continued)
T(n) =
T(0) + T(n–1) + Θ(n) if 0 : n–1 split,
T(1) + T(n–2) + Θ(n) if 1 : n–2 split,
M
T(n–1) + T(0) + Θ(n) if n–1 : 0 split,
n −1
= ∑ X k (T (k ) + T (n − k − 1) + Θ(n) )
k =0
September 21, 2005
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.36
Calculating expectation
⎡ n −1
⎤
E[T (n)] = E ⎢ ∑ X k (T (k ) + T (n − k − 1) + Θ(n) )⎥
⎣k =0
⎦
Take expectations of both sides.
September 21, 2005
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.37
Calculating expectation
⎡ n −1
⎤
E[T (n)] = E ⎢ ∑ X k (T (k ) + T (n − k − 1) + Θ(n) )⎥
⎣k =0
⎦
=
n −1
∑ E[ X k (T (k ) + T (n − k − 1) + Θ(n) )]
k =0
Linearity of expectation.
September 21, 2005
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.38
Calculating expectation
⎡ n −1
⎤
E[T (n)] = E ⎢ ∑ X k (T (k ) + T (n − k − 1) + Θ(n) )⎥
⎣k =0
⎦
=
=
n −1
∑ E[ X k (T (k ) + T (n − k − 1) + Θ(n) )]
k =0
n −1
∑ E[ X k ] ⋅ E[T (k ) + T (n − k − 1) + Θ(n)]
k =0
Independence of Xk from other random
choices.
September 21, 2005
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.39
Calculating expectation
⎡ n −1
⎤
E[T (n)] = E ⎢ ∑ X k (T (k ) + T (n − k − 1) + Θ(n) )⎥
⎣k =0
⎦
=
=
n −1
∑ E[ X k (T (k ) + T (n − k − 1) + Θ(n) )]
k =0
n −1
∑ E[ X k ] ⋅ E[T (k ) + T (n − k − 1) + Θ(n)]
k =0
n −1
n −1
n −1
= 1 ∑ E [T (k )] + 1 ∑ E [T (n − k − 1)] + 1 ∑ Θ(n)
n k =0
n k =0
n k =0
Linearity of expectation; E[Xk] = 1/n .
September 21, 2005
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.40
Calculating expectation
⎤
⎡ n −1
E[T (n)] = E ⎢ ∑ X k (T (k ) + T ( n − k − 1) + Θ(n) )⎥
⎦
⎣k =0
=
=
n −1
∑ E[ X k (T (k ) + T (n − k − 1) + Θ(n) )]
k =0
n −1
∑ E[ X k ] ⋅ E[T (k ) + T (n − k − 1) + Θ(n)]
k =0
n −1
n −1
n −1
= 1 ∑ E [T (k )] + 1 ∑ E [T (n − k − 1)] + 1 ∑ Θ(n)
n k =0
n k =0
n k =0
n −1
= 2 ∑ E [T (k )] + Θ(n)
n k =1
September 21, 2005
Summations have
identical terms.
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.41
Hairy recurrence
n −1
E[T (n)] = 2 ∑ E [T (k )] + Θ(n)
n k =2
(The k = 0, 1 terms can be absorbed in the Θ(n).)
Prove: E[T(n)] ≤ an lg n for constant a > 0 .
• Choose a large enough so that an lg n
dominates E[T(n)] for sufficiently small n ≥ 2.
n −1
Use fact:
1 n 2 lg n − 1n 2
k
lg
k
≤
(exercise).
∑
2
8
k =2
September 21, 2005
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.42
Substitution method
n −1
E [T (n)] ≤ 2 ∑ ak lg k + Θ(n)
n k =2
Substitute inductive hypothesis.
September 21, 2005
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.43
Substitution method
n −1
E [T (n)] ≤ 2 ∑ ak lg k + Θ(n)
n k =2
≤ 2a ⎛⎜ 1 n 2 lg n − 1 n 2 ⎟⎞ + Θ(n)
n ⎝2
8 ⎠
Use fact.
September 21, 2005
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.44
Substitution method
n −1
E [T (n)] ≤ 2 ∑ ak lg k + Θ(n)
n k =2
≤ 2a ⎛⎜ 1 n 2 lg n − 1 n 2 ⎞⎟ + Θ(n)
n ⎝2
8 ⎠
= an lg n − ⎛⎜ an − Θ(n) ⎞⎟
⎝ 4
⎠
Express as desired – residual.
September 21, 2005
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.45
Substitution method
n −1
E [T (n)] ≤ 2 ∑ ak lg k + Θ(n)
n k =2
= 2a ⎛⎜ 1 n 2 lg n − 1 n 2 ⎞⎟ + Θ(n)
n ⎝2
8 ⎠
= an lg n − ⎛⎜ an − Θ(n) ⎞⎟
⎝ 4
⎠
≤ an lg n ,
if a is chosen large enough so that
an/4 dominates the Θ(n).
September 21, 2005
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.46
Quicksort in practice
• Quicksort is a great general-purpose
sorting algorithm.
• Quicksort is typically over twice as fast
as merge sort.
• Quicksort can benefit substantially from
code tuning.
• Quicksort behaves well even with
caching and virtual memory.
September 21, 2005
Copyright © 2001-5 by Erik D. Demaine and Charles E. Leiserson
L4.47
Download