7.11.2023
geradengleichung
g
i
32
1- ↳ Nz
,
3N -14g
=
y
5
b-
=
4y
=
-3N -15
-3-4^+5-4
=
r-y-pehsenschn.tt
steigug
835
4)
:B
(1)
a)
E
"
:(1:11 ! /
n
,
n,
=
=
=
)
b)
-2mi
E
:&
-
M2 -1
3h3
-_
Ñ
0
E
(1) ) Eg )
-
=
Ñ
=
5)
a)
A
_
,
N2
2h ,
+
s
nzt
hi + Nz +
=
=
4
:
2h2
-
4h3
-
=
4h3
=
0
O
=/
-4
↳ =3
=
±
29
:& (911-1-4)=0
-
:
4k
-
,
(f)
2h32
5h3
0
=0
:@ -841-171=0
E
F-
n
Nz
-0
392 -17N }
:n→=r( 1) +
h→
=
hi
F-
c)
-
4h , 1-
=
( %-)
=
-
9 Ri
:
+
-1%+4%1+41;)
:*
9/7
-3/7
nz=7
±
±
¥11;)
(
a.
.
3nz=o
-1
=
Nz
r( { / is ( ?
+
Zn
,
-8ns -123
(0121-1)
,
B
Parametergieichy
0
a
(61-510)
Ñ
:
Nonviolent eidny
,
=
c
(110/1)
(f) ᵗf§ ) try! )
t
n→= Con
:
n→
=
n ,
,
-7ns
-
2h2
-1ns
-
-0
O
ñ=( ÷ )
E
:& -1%1-1%11=0
koordintegleichg
=
-2mi
-
Na -15ns
=
-7
'
422-1323
=
-9