2 ax +bx+c=0 a≠0 2 D=b -4ac D>0 x1;2 −b ± √D = 2a D=0 b x=− 2a D<0 не имеет решения 2 x +px+q=0 x1 + x2 = −p { x ⋅x =q 1 2 2 ax +bx+c, a ≠ 0 2 ax +bx+c= a(x-x1)(x-x2)
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