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Source monitoring

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Source monitoring
Gazala Habib
Air pollution sources of regional importance
Sources of air pollution
Biomass burning
Biomass fuel combustion
Chemical Fertilizers
On-road transport
Brick Kilns
Dairy Farm
Power generation
Industries
Municipal waste burning
Diesel tractors
Off-road combustion
Construction activity
08/09/23
Approaches for Emission Estimates
2
Area of Research
• Emission rate
• Emission inventory development
• Exposure assessment and risk
estimate
• To decide control equipment
Data requirement
•
•
•
•
•
•
•
•
•
•
•
Gas velocity
Gas temperature
Static pressure in duct
Barometric pressure
Duct diameter
Concentration of pollutant
Emission source name and location
Date and time
Wind speed and direction
Control system operating conditions
Process operating conditions
Challenges in Aerosol measurement at sources
08/09/23
5
Sampling particles from stack/duct
• Isoaxial Sampling
• Iso kinetic sampling
• Sub iso kinetic sampling
• Super iso kinetic sampling
• Anisoaxial sampling
• Particle size distribution
• Particle losses
• Wall losses due to charging
• Thermophoresis losses
• Evaluation parameter for
dilution tunnel
𝑣!" = 𝑐#,%&'(#!
2βˆ†π‘
𝜌)
𝑸𝒔
Rotameters with
needle valve
βˆ†π’‘
Dilution tunnel
Versatile Source Sampling System (VS3)
Rotameter with
needle valve
Zero air
Particle
sampling probe
DR=10-40
DR=30-100
08/09/23
8
On-field emission measurement images-Residential sector and open burning
Outdoor open kitchen
08/09/23
Semi-closed kitchen
9
Evaluation of VS3
v Homogenous mixing
v Gas-to particle conversion
v Particle wall losses
𝐷𝑅 =
𝑄"
β„Ž# − β„Ž"
=
𝑄#
β„Ž"
𝑅𝑒𝑠𝑖𝑑𝑒𝑛𝑐𝑒 π‘‘π‘–π‘šπ‘’ (𝑑)
π‘‰π‘œπ‘™π‘’π‘šπ‘’ π‘œπ‘“ π‘‘π‘–π‘™π‘’π‘‘π‘–π‘œπ‘› 𝑑𝑒𝑛𝑛𝑒𝑙
=
πΉπ‘™π‘œπ‘€ π‘Ÿπ‘Žπ‘‘π‘’
Phase equilibrium time (t):
time required for
conversion of VOCs to
particles (<0.5 second)
Negligible particle losses
!
CO2 concentration in longitudinal
and axial direction at different
dilution ratio had insignificant
difference
ü The ratio of (𝝉) >4 for achieving
phase equilibrium of aerosol inside
dilution tunnel (Guo et al. 2016).
!
ü At different dilution ratios (𝝉) was
always greater than 4 indicated
complete gas-to-particle
partitioning
10
Jaiprakash et al. AEROSOL SCIENCE AND TECHNOLOGY2016, VOL. 50, NO. 7, 717–731
Velocity measurement and
Dilution ratio calculation
πΉπ‘™π‘œπ‘€ π‘Ÿπ‘Žπ‘‘π‘’ π‘œπ‘“ π‘‘π‘–π‘™π‘’π‘‘π‘–π‘œπ‘› π‘Žπ‘–π‘Ÿ 𝑄"
𝐷𝑅 =
=
πΉπ‘™π‘œπ‘€ π‘Ÿπ‘Žπ‘‘π‘’ π‘œπ‘“ 𝑒π‘₯β„Žπ‘Žπ‘’π‘ π‘‘
𝑄#
Quantity measured
Instruments
Range
Velocity
Pitot tube
>5 m/s
Hot wire anemometer
50 mm/s - 40 m/s
Venturi meter
1 L/s – 100 m3/s
Orifice meter
1 cm3/s – 100 m3/s
Rotameter
0.01 cm3/s – 50 L/s
Mass flow meter
0.1 cm3/s – 2 l/s
Laminar flow element
0.1 cm3/s – 20 L/s
Spirometer
1-1000 L
Soap bubble spirometer
1-1000 cm3
Piston meter
1-1000 cm3
Wet test meter
Unlimited
Dry gas meter
Unlimited
Manometer
1-200 kPa [0-2 atm]
Micromanometer
0-0.5 kPa [0 – 0.005
atm]
Aneroid pressure gauge
0-30 kPa [0-0.3 atm]
Bourdon tube gauge
>20 kPa [>0.2 atm]
Flow rate
𝑄"
𝐢𝑂$%#&'()*+ − 𝐢𝑂$%",-)+#"
𝐷𝑅 =
=
𝑄#
𝐢𝑂$%",-)+#" − 𝐢𝑂$%(./,#0+
π‘ƒπ‘Žπ‘Ÿπ‘‘π‘–π‘π‘™π‘’ π‘π‘œπ‘›π‘π‘’π‘›π‘‘π‘Ÿπ‘Žπ‘‘π‘–π‘œπ‘› 𝐢1
π‘Š2 − π‘Š,
=
𝑉*
Volume
Pressure
Flow rate measurement through
particle collection substrate
•
•
•
• Variable-head meter-Venturi
and orifice meters
• Variable area meter- Rotameter
• Variable area
• Constant pressure
•
4/$
2 βˆ†π‘
𝑄 = π‘˜π΄$
𝜌3
𝐴
1− $
𝐴4
$
Differential pressure
k=0.98 and k=0.62
Critical orifice downstream
pressure<0.53*Upstream
pressure.
Velocity at throat is the speed of
sound and further reduction in
down stream pressure does not
increase the velocity through
the throat
πΆπ‘Ÿπ‘–π‘‘π‘–π‘π‘Žπ‘™ π‘œπ‘Ÿπ‘–π‘“π‘–π‘π‘’
𝑄 = 11.7π‘˜π΄6
k=0.98, 0.62
𝑄789 ∝
1 π‘šπ‘š 𝐻𝑔 = 133.3 π‘ƒπ‘Žπ‘ π‘π‘Žπ‘™
𝑄 = 𝐢: 𝐴6
2π‘”π‘š2
𝜌3 𝐴2
4/$
ü
ü
ü
ü
𝐢* = π‘Ÿπ‘œπ‘‘π‘Žπ‘šπ‘’π‘‘π‘’π‘Ÿ π‘π‘œπ‘’π‘“π‘“π‘–π‘π‘–π‘’π‘›π‘‘ = 0.6 − 0.8
𝐴+ = 𝑂𝑝𝑒𝑛 π‘Žπ‘Ÿπ‘’π‘Ž π‘Žπ‘‘ π‘“π‘™π‘œπ‘Žπ‘‘ π‘π‘œπ‘ π‘–π‘‘π‘–π‘œπ‘›
π‘š, = π‘€π‘Žπ‘ π‘  π‘œπ‘“ π‘“π‘™π‘œπ‘Žπ‘‘
𝐴, = πΆπ‘Ÿπ‘œπ‘ π‘  π‘ π‘’π‘π‘‘π‘–π‘œπ‘›π‘Žπ‘™ π‘Žπ‘Ÿπ‘’π‘Ž π‘œπ‘“ π‘“π‘™π‘œπ‘Žπ‘‘
𝑝4
𝑇4
STP=At sea level t=0 C
and p= 1 atm
𝑄789 = 𝑄;/*
𝜌:
𝜌789
4/$
= 𝑄;/*
𝑝:
𝑝789
4/$
Source monitoring plan
• Source location
• Gas flow rate: velocity pressure or Gas
kinetic
• Measurement of static pressure (velocity
pressure=total pressure-static pressure)
• Wall type
• Static tip
• Low pressure
• Velocity
• Vane probe velocity meter
• Mass flow sensor/anemometer
• Volumetric flow rate for turbulent flow
Carbon balance method for
emission factor calculation
𝑣 = 𝑐1,*%+=1#
2βˆ†π‘
𝜌3
𝑣 = π‘£π‘’π‘™π‘œπ‘π‘–π‘‘π‘¦ 𝑖𝑛 π‘š/𝑠
𝐢1,*%+=1#
= π‘π‘œπ‘’π‘“π‘“π‘–π‘π‘–π‘’π‘›π‘‘ π‘“π‘œπ‘Ÿ 𝑆
− 𝑑𝑦𝑝𝑒 π‘π‘–π‘‘π‘œπ‘‘ 𝑑𝑒𝑏𝑒
βˆ†π‘ = π·π‘–π‘“π‘“π‘’π‘Ÿπ‘’π‘›π‘‘π‘–π‘Žπ‘™ π‘π‘Ÿπ‘’π‘ π‘ π‘’π‘Ÿπ‘’
𝜌3 = 𝑑𝑒𝑛𝑠𝑖𝑑𝑦 π‘œπ‘“ 𝑓𝑙𝑒𝑒 π‘”π‘Žπ‘ 
Emission factor calculation
𝐢# ×𝐷𝑅×𝑉!"
𝑔
𝐸𝐹
=
π‘˜π‘”
𝐹
𝑉#& = π‘£π‘œπ‘™π‘’π‘šπ‘’ π‘œπ‘“ 𝑒π‘₯β„Žπ‘Žπ‘’π‘ π‘‘
π‘ƒπ‘Žπ‘Ÿπ‘‘π‘–π‘π‘™π‘’ π‘π‘œπ‘›π‘π‘’π‘›π‘‘π‘Ÿπ‘Žπ‘‘π‘–π‘œπ‘› 𝐢# =
𝐹 = π‘€π‘Žπ‘ π‘  π‘œπ‘“ 𝑓𝑒𝑒𝑙 𝑒𝑠𝑒𝑑
The carbon balance method used for emission factor calculation
𝑔
𝐢𝑔
𝑔
π‘š0
𝐸𝐹= 𝐢𝑀𝐹,.!/
∗
𝑔
𝑀1
𝑔
π‘˜π‘”
π‘˜π‘” βˆ†πΆ
+
βˆ†πΆ
12!
12
0
𝑀12!
π‘š
π‘š0
πΈπ‘šπ‘–π‘ π‘ π‘–π‘œπ‘› 𝑖𝑛
𝑀1
𝑀12
(2.85 − 2.5)×100
=
= 11667
1×10&0 ×30
πœ‡π‘”
π‘š0
Problem 1b. What would be the concentration in exhaust?
Cπ‘œπ‘›π‘. π‘œπ‘“ π‘π‘Žπ‘Ÿπ‘‘π‘–π‘π‘™π‘’π‘  𝑖𝑛 𝑒π‘₯β„Žπ‘Žπ‘’π‘ π‘‘ = 𝐷𝑅 ∗ πΆπ‘œπ‘›π‘π‘’π‘›π‘‘π‘Ÿπ‘Žπ‘‘π‘–π‘œπ‘› 𝑖𝑛 π‘ π‘Žπ‘šπ‘π‘™π‘’π‘‘ π‘Žπ‘–π‘Ÿ
𝑔
= 𝐸𝐹#
×𝑓𝑒𝑒𝑙 π‘π‘œπ‘›π‘ π‘’π‘šπ‘π‘‘π‘–π‘œπ‘› 𝑖𝑛 π‘˜π‘” ∗ π‘‘π‘Žπ‘¦π‘  π‘œπ‘“ π‘Žπ‘π‘‘π‘–π‘£π‘–π‘‘π‘¦ 𝑖𝑛 π‘Ž π‘¦π‘’π‘Žπ‘Ÿ
π‘˜π‘”
Problem 1c. Determine the emission factor of particles if 100 kg of wood
was burned in 30 min.
𝐸𝐹# 𝑖𝑛
π‘Š, − π‘Šπ‘‰%
π‘ƒπ‘Žπ‘Ÿπ‘‘π‘–π‘π‘™π‘’ π‘π‘œπ‘›π‘π‘’π‘›π‘‘π‘Ÿπ‘Žπ‘‘π‘–π‘œπ‘› 𝐢# 𝑖𝑛 π‘ π‘Žπ‘šπ‘π‘™π‘’π‘‘ π‘Žπ‘–π‘Ÿ
𝑔
𝑦
𝐸𝐹
Problem 1a. The particle is collected on quartz filter of initial weight 2.5 mg
from monitoring of brick kiln stack. The final weight of the filter was
measured as 2.85 mg. The monitoring was conducted for 30 min at 1 LPM.
Determine the concentration of the particle in sampled air which was
diluted using 40 LPM clean air.
𝑔
π‘€π‘Žπ‘ π‘  π‘œπ‘“ π‘π‘œπ‘™π‘™π‘’π‘‘π‘Žπ‘›π‘‘ π‘’π‘šπ‘–π‘‘π‘‘π‘’π‘‘
=
π‘˜π‘”
π‘€π‘Žπ‘ π‘  π‘œπ‘“ 𝑓𝑒𝑒𝑙 π‘π‘’π‘Ÿπ‘›π‘’π‘‘
𝑔
26389
=
= 263.89
π‘˜π‘”
100
πΆπ‘œπ‘›π‘. 𝑖𝑛 𝑒π‘₯β„Žπ‘Žπ‘’π‘ π‘‘ =
40
×11667 = 466667 πœ‡π‘”π‘š&0
1
Problem 1c. What would be the mass of particles emitted in 30 min if the
measured average velocity of exhaust was recorded as 10 m/s? The stack
diameter was 2.0 m at sampling point.
π‘€π‘Žπ‘ π‘  π‘œπ‘“ π‘π‘Žπ‘Ÿπ‘‘π‘–π‘π‘™π‘’π‘  π‘’π‘šπ‘–π‘‘π‘‘π‘’π‘‘ = 𝑉!" ∗ πΆπ‘œπ‘›π‘π‘’π‘›π‘‘π‘Ÿπ‘Žπ‘‘π‘–π‘œπ‘› 𝑖𝑛 𝑒π‘₯β„Žπ‘Žπ‘’π‘ π‘‘
𝑉!" = πΆπ‘Ÿπ‘œπ‘ π‘  π‘ π‘’π‘π‘‘π‘–π‘œπ‘›π‘Žπ‘™ π‘Žπ‘Ÿπ‘’π‘Ž π‘œπ‘“ 𝑑𝑒𝑐𝑑×𝑣!"
𝑉!" =
πœ‹ 3
2 ×10×30×60 = 56549 π‘š0
4
56549 π‘š0 ×466667
𝑀# 𝑖𝑛 𝑔 =
= 26389
104
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