- Mark Scheme
Question
1
Answer
B1
Marks
/
AO Element
Notes
3
B1
B1
3
2
Term independent of x: −2(4096)
+ 15
−8177
B1 for
M1 for use of 2
appropriate terms
A1
Guidance
- Mark Scheme
Question
3
Answer
B1 Squares:
B1 Rationalises, e.g.
Marks
5
/
AO Element
Notes
or rationalises
or squares
M1 Multiplies out, e.g.
Multiplies out
A2
A1 for
Guidance
- Mark Scheme
Question
Answer
Marks
3
4
/
AO Element
Notes
Guidance
B1
oe or
M1
soi oe or
A1
oe
4
5
M1
Alternative method
M1 for
M1
M1 for
M1
A1
or equivalent
M1 for writing with a
common denominator
A1 for
equivalent
or
- Mark Scheme
Question
6
Answer
M1 Either
or
or
Marks
5
or
AO Element
/
Notes
For expressing the terms
on the left hand side of
either one of the 2
equations in terms of
powers of 7, 49, 5 or
25
A1
or
A1
or
M1 leading to
and
For attempt to solve two
linear equations, with
integer coefficients and
constants, in terms of x
and y
A1
7(a)
M1
= 108
A1
A1 Perimeter =
3
For use of Pythagoras’
theorem and attempt to
expand and simplify
Guidance
- Mark Scheme
Question
7(b)
Answer
M1
Either
Marks
/
AO Element
Notes
Guidance
3
Either
For a valid method and
attempt to expand out and
simplify
Or
Or
For a valid method and
attempt to expand out and
simplify
A2 Area =
A1 for each term
[Total: 29]