NATIONAL
SENIOR CERTIFICATE
GRADE 11
MATHEMATICAL LITERACY
COMMON TEST
SEPTEMBER 2023
MARKING GUIDELINE
MARKS: 100
SYMBOL
M
MA
CA
A
C
S
RT/RG/RD
NPR
SF
O
J
R
F
E
U
AO
EXPLANATION
Method
Method with accuracy
Consistent accuracy
Accuracy (Answer)
Conversion
Simplification
Reading from a table/ graph/ diagram
No penalty for correct rounding
Correct substitution in a formula
Opinion/ reason/deduction/example
Justification
Rounding off
deriving a formula
Explanation
Units
Answer only full marks
This marking guideline consists of 6 pages.
Mathematical Literacy(Grade 11)
QUESTION 1 [20MARKS]
QUE SOLUTION
1.1.1
2
NSC – Marking Guidelines
Common Test September 2023
ANSWER ONLY FULL MARKS
EXPLANATION
15;16;18;18;18;19;19;19;21;21;21;21;24 A
T/L
DH
L1
2A, Answer
(2)
1.1.2
DH
L1
CA from 1.1.1
2CA, Answer
21 CA
(2)
1.1.3
South Africa RT
2RT, Reading correct country
1.1.4
115 A
2A, Answer
1.2.1
Average monthly deposit =
RT
= 172,00 A
1RT, Dividing by 10
DH
(2) L1
DH
(2) L1
F
L1
1A, Answer.
(2)
1.2.2
A=
MA
= 70 A
1.2.3
B = £1720 – £700 - £560 MA
= £460 A
OR
B = £92 × 5 MA
=£460 A
Range = 92 – 28 MA
= 64 A
1.2.4
P(coin)= 0% A
1.2.5
ContinuousA
Copyright Reserved
1MA, Dividing correct values
F
L1
1A, Answer
1MA, Subtracting correct values
1A, Answer
OR
1MA, Multiplying correct values
1A, Answer
(4)
1MA, Difference
1A, Answer
(2)
2A, Answer
(2)
2A, Answer
(2)
[20]
DH
L1
P
L1
DH
L1
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Mathematical Literacy(Grade 11)
3
NSC – Marking Guidelines
QUESTION 2 [33 MARKS]
QUE SOLUTION
2.1.1 R400A
2.1.2
Common Test September 2023
EXPLANATION
2A, Variable cost
Total income = R600 × number of sandals sold F
2A, Answer
Total income = R600 × 20SF
=R12 000CA
CA from 2.1.2
1SF, Multiplying by 20
1CA, Answer
2.1.3
T/L
F
(2) L1
F
(2) L2
F
L2
(2)
2.1.4
Total cost = R2000 + R400×20SF
= R8000A
The statement is incorrectJ
1SF, Correct formula substitution
1A, Answer
1J, Justification.
F
L4
(3)
2.1.5
2.2.1
O
Correct, the company need to know when to make a
profit or loss for the number of sandals produced and
sold.E
Total distance =
M
= 637,25km CA
F
L4
1O, Answer
2E, Explanation
(3)
1M, Using rate correctly
M
L2
1CA, Answer
(2)
2.2.2
Metres =
1C, Dividing by 1000
C
1MA, Answer
AO
= 1,74 MA
2.2.3
M
L1
Surface area =
(2785×1630)+2×(2785×355)+2×(1630×355) SF
= 4 539 550 + 1 977 350 +1 157 300 mm2 S
= 7 674 200 mm2 A
(2)
M
L2
1SF, Correct substitution
1S, Simplification
1A, Answer
(3)
2.3.1
Number of tyres = 3 × 4 × 5MA
=60 A
1MA, Multiplying correct values
1A, Answer.
MP
L2
(2)
2.3.2
Radius =
=
1M, Dividing 2785mm by 4
M
1MCA, Dividing diameter by 2
MCA
1CA, Radius
=348,125mmCA
2.4.1
Indirect proportionA
2.4.2
Number of workers =
=18 A
2.4.3
BA
Copyright Reserved
M
L3
(3)
2A, Answer
M
M
(2) L1
1M, Dividing 144 by 8
1A, Answer
M
L2
(2)
2A, Answer
M
(2) L1
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Mathematical Literacy(Grade 11)
4
NSC – Marking Guidelines
Common Test September 2023
M
L3
2.4.4
1A, Starting
point
1A, Any other
correct point
1CA, Joining of
points
A
CA
A
(3)
[33]
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Mathematical Literacy(Grade 11)
5
NSC – Marking Guidelines
QUESTION 3 [27 MARKS]
QUE SOLUTION
3.1.1 Floor plan- a layout of the house that shows the
inside/internal of the house from the top view/bird
eye view. E
Elevation plan – a diagram that shows the height of
the wall/roof of the house from the
outside/external.E
Common Test September 2023
EXPLANATION
2E, Floor plan
T/L
MP
L4
2E, Elevation plan
(4)
3.1.2
Doors = 8RT
Windows = 5RT
1RT, Number of doors
1RT, Number of windows
3.1.3
Number scale/unit scale/Ratio scale. A
One unit on the plan represents 110 units in the real
house. E
Roof overlap/roof overhangA
1A, Correct scale
1E, Explanation
MP
L2
(2)
3.1.4
3.1.5
P (B) =


= 0,428571…..
= 0,429 R
3.1.6
3.2.1
A= East elevationRD
B= North elevationRD
RT
Tariff =
C
= R1,3999CA
MP
L2
(2)
2A, Answer
Accept: drain
1RT,Correct Numerator
1RT, Correct Denominator
MP
(2) L4
P
L3
1R, Correct rounding
(3)
2RD, Correct elevations
MP
(2) L4
F
L2
1RT, Correct value
1C, Divided by 100
1CA, Answer
(3)
3.2.2
3.2.3
3.2.4
To ensure customers do not waste electricity. O
OR
To control the usage of electricity.
Total cost = (600 × 182,21) + (90 × 309,71) MA
= 137 199.9cents
100C
= R1371,999CA
= R1 372 R
Customers have information on how much electricity
they use.J
Customers able to decide when to use less or more
electricity.J
Service provider eliminates the need for estimated
billing.
Copyright Reserved
F
L4
2O, Opinion
(2)
1MA, Multiplying by correct rates
F
L3
1C, Dividing by 100
1CA, Answer
1R, Correct Rands
(4)
F
L4
2J, Justification
2J, Justification
(4)
[28]
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Mathematical Literacy(Grade 11)
6
NSC – Marking Guidelines
QUESTION 4 [20 MARKS]
QUE SOLUTION
4.1.1 Total budget =
R260000+R130000+R90000+R45000+R35000+R20000
+R18000+R15000+R13000+R12000 M
=R638 000×2 MA
=R1 276 000CA
Common Test September 2023
EXPLANATION
T/L
DH
L3
1M, Adding correct values.
1MA, Multiplying by 2
1CA, Total budget
(3)
4.1.2
Mean A
4.1.3
Mean = R500000+R250000+R180000+R90000+R70000
R40000+R35000+R30000+R25000+R20000M
10MA
= R124 000CA
2A, Correct measure of central
tendency
DH
L2
(2)
4.2.1
4.2.2
RT
Start time = 08:10 – 2hrs 40min MA
=05:30
OR
Start time = 10:00 – 4hrs 30min
= 05:30
OR
Start time = 11:40 – 6hrs 10min
= 05:30
OR
Start time = 13:40 – 8hrs 10min
= 05:30
OR
Start time = 15:00 – 9hrs 30min
= 05:30
OR
Start time = 16:40 – 11hrs 10min
= 05:30
Median =


= 39,24km A
= 39km R
4.2.3
4.2.4
To eliminate unfit athleteE
OR
To ensure that the marathon is completed on a stipulated
time.
No of Litres =
MA
= 709,30litres CA
= 700 litresR
Copyright Reserved
1M, Adding ALL correct values
1MA, Dividing by 10
1CA, Answer
(3)
1RT, Reading correct day time
1MA, Subtracting correct duration
DH
L3
M
L2
(2)
1MA, Adding correct distances
1MA, Dividing by 2
DH
L2
1A, Answer
1R, Correct rounding
(4)
2E, Explanation
MP
L4
(2)
1MA, Dividing 30 500l by 43
1CA, Answer
1R, Rounding
M
L3
(3)
[20]
TOTAL MARKS: 100
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