O X F O R D I B S T U D Y G U I D E S Ti Kik Physics f o r T h e I B d I p l o m a 2014 edition 2 3 Great Clarendon Oxford Street, University Oxford. It Press furthers the research, scholarship, Oxford a the © Tim The in Kirk rights published rights form writing by law, of in department trade mark or the of by Kingdom University of publishing Oxford of excellence in worldwide. University Press in countries the No stored by author in any part a of means, University by licence or rights this been asserted publication system, without Oxford reproduction have retrieval of Rights of objective education other United 2014 reserved. reprographics the a 6DP, 2014 reproduced, any certain is OX2 University’s and registered and moral First All is UK Oxford, under Press, terms outside the scope Oxford or as of with above University be in permission expressly Enquiries the may transmitted, prior agreed organization. Department, the or the in permitted appropriate concerning should Press, at be sent the to address above. You must must British Data not impose circulate this Library this same work condition Cataloguing in in any on other any form and you acquirer Publication Data available 978-0-19-839355-9 1 3 5 7 Paper 9 10 used recyclable forests. 8 6 in 4 the The in production product made regulations Great of from manufacturing environmental Printed 2 this wood process of the book is grown a conforms country natural, in of sustainable to the origin. Britain Acknowledgements This work endorsed Cover: © has by been the James NASA/WMAP p205: NASA/WMAP We have by Six tried publication. any errors If or independently Baccalaureate Brittain/Corbis; p211: Artwork developed International Red to Science Marbles trace notied and the omissions at p191: Team; and Oxford contact all publishers the Chase p117: earliest from and is not (IB). Preuninger; vilax/Shutterstock; University copyright will be Press. holders pleased opportunity. to before rectify Introduction and acknowledgements Many people seem to think that you have to be really closely to the recently revised International Baccalaureate clever to understand Physics and this puts some people syllabus. It aims to provide an explanation (albeit very o studying it in the rst place. So do you really need a brief) of all of the core ideas that are needed throughout brain the size of a planet in order to cope with IB Higher the whole IB Physics course. To this end each of the Level Physics? The answer, you will be pleased to hear, is sections is clearly marked as either being appropriate ‘No’. In fact, it is one of the world’s best kept secrets that for everybody or only being needed by those studying at Physics is easy! There is very little to learn by hear t and Higher level. The same is true of the questions that can be even ideas that seem really dicult when you rst meet found at the end of the chapters. them can end up being obvious by the end of a course of I would like to take the oppor tunity to thank the many study. But if this is the case why do so many people seem people that have helped and encouraged me during the to think that Physics is really hard? writing of this book. In par ticular I need to mention David I think the main reason is that there are no ‘safety nets’ Jones and Paul Ruth who provided many useful and or ‘shor t cuts’ to understanding Physics principles. You detailed suggestions for improvement – unfor tunately won’t get far if you just learn laws by memorising them there was not enough space to include everything. The and try to plug numbers into equations in the hope of biggest thanks, however, need to go to Betsan for her getting the right answer. To really make progress you need suppor t, patience and encouragement throughout the to be familiar with a concept and be completely happy whole project. that you understand it. This will mean that you are able to apply your understanding in unfamiliar situations. The hardest thing, however, is often not the learning or the Tim Kirk October 2002 understanding of new ideas but the getting rid of wrong and confused ‘every day explanations’. This book should prove useful to anyone following a pre- university Physics course but its structure sticks very Third edition Since the IB Study Guide's rst publication in 2002, there have been two signicant IB Diploma syllabus changes. The aim, to try and explain all the core ideas essential for the IB Physics course in as concise a way as possible, has remained the same. I continue to be grateful to all the teachers and students who have taken time to comment and I would welcome fur ther feedback. In addition to the team at OUP , I would par ticularly like to thank my exceptional colleagues and all the outstanding students at my current school, St. Dunstan's College, London. It goes without saying that this third edition could not have been achieved without Betsan's continued suppor t and encouragement. This book is dedicated to the memory of my father, Francis Kirk. Tim Kirk August 2014 I n t r o d u c t I o n a n d a c k n o w l e d g e m e n t s iii Contents (Italics denote topics which are exclusively Higher Level) Intensity 39 Superposition 40 1 measurement and uncertaIntIes The realm of physics – range of magnitudes of quantities in our universe 1 Polarization 41 The SI system of fundamental and derived units 2 Uses of polarization 42 Estimation 3 Wave behaviour – Reection 43 Uncer tainties and error in experimental measurement 4 Snell’s law and refractive index 44 Uncer tainties in calculated results 5 Refraction and critical angle 45 Uncer tainties in graphs 6 Diraction 46 Vectors and scalars 7 Two-source interference of waves 47 IB Questions – measurement and uncer tainties 8 Nature and production of standing (stationary) waves 48 Boundary conditions 49 IB 50 2 mechanIcs Motion 9 Graphical representation of motion 10 Uniformly accelerated motion 11 Projectile motion 12 Fluid resistance and free-fall 13 Forces and free-body diagrams 14 Newton’s rst law 15 Equilibrium 16 Newton’s second law 1 7 Newton’s third law 18 Mass and weight 19 Solid friction 20 Questions – waves 5 electrIcItY and magnetIsm Electric charge and Coulomb's law 51 Electric elds 52 Electric potential energy and electric potential Work dierence 53 Electric current 54 Electric circuits 55 Resistors in series and parallel 56 Potential divider circuits and sensors 57 Resistivity 58 Example of use of Kircho's laws 59 Internal resistance and cells 60 2 1 Energy and power 22 Momentum and impulse 23 IB Questions – mechanics 24 Magnetic force and elds 6 1 Magnetic forces 62 Examples of the magnetic eld due to currents 63 IB Questions – electricity and magnetism 64 3 thermal PhYsIcs Thermal concepts 25 Heat and internal energy 26 Specic heat capacity 27 Phases (states) of matter and latent heat 28 The gas laws 1 29 The gas laws 2 30 6 cIrcul ar motIon and graVItatIon Uniform circular motion 65 Angular velocity and ver tical circular motion 66 Newton’s law of gravitation 67 IB Questions – circular motion and gravitation 68 Molecular model of an ideal gas 31 7 atomIc, nuclear and IB Questions – thermal physics 32 PartIcle PhYsIcs Emission and absorption spectra 69 Nuclear stability 70 4 waVes Oscillations 33 Graphs of simple harmonic motion 34 Travelling waves 35 Wave characteristics 36 Electromagnetic spectrum 37 Investigating speed of sound experimentally 38 iv c o n t e n t s Fundamental forces 7 1 Radioactivity 1 72 Radioactivity 2 73 Half-life 74 Nuclear reactions 75 Fission and fusion 76 citr disrge Structure of matter 77 citr rge 119 Description and classication of par ticles 78 IB Qestis – eetrgeti idti 120 Quarks 79 Feynman diagrams 80 118 12 QuanTum anD nuclEaR phYSIcS pteetri eet IB Questions – atomic, nuclear and par ticle physics 12 1 81 mtter wes 8 energY ProductIon 122 ati setr d ti eergy sttes 123 Energy and power generation – Sankey diagram 82 Br de te t 124 Primary energy sources 83 Te Srödiger de te t 125 Fossil fuel power production 84 Te heiseberg ertity riie d Nuclear power – process 85 Nuclear power – safety and risks 86 Solar power and hydroelectric power 87 Wind power and other technologies 88 Thermal energy transfer 89 Radiation: Wien’s law and the Stefan–Boltzmann law 90 Solar power 91 The greenhouse eect 92 Global warming 93 IB Questions – energy production 94 te ss deteriis 126 Teig, teti brrier d trs etig teig rbbiity 127 Te es 128 ner eergy ees d rditie dey 129 IB Qestis – qt d er ysis 130 13 oPtIon a – rel atIVItY Reference frames 131 Maxwell’s equations 132 Special relativity 133 Lorentz transformations 134 Velocity addition 135 Invariant quantities 136 Time dilation 137 9 WavE phEnomEna Sie ri ti 95 Eergy ges drig sie ri ti 96 Dirti 97 Length contraction and evidence to suppor t Tw-sre itereree wes: Yg’s dbe-sit exeriet 98 mtie-sit dirti 99 Ti re s special relativity 138 Spacetime diagrams (Minkowski diagrams) 1 139 Spacetime diagrams 2 140 The twin paradox 1 140 100 Resti 101 Te Der eet 102 xes d itis te Der eet 103 IB Qestis – we ee 104 Twin paradox 2 141 Spacetime diagrams 3 142 mss d eergy 143 Retiisti et d eergy 144 Retiisti eis exes 145 Geer retiity – te eqiee riie 146 Gritti red sit 147 Srtig eidee 148 crtre setie 149 Bk es 150 10 fIElDS pteti (gritti d eetri) 105 Eqitetis 106 Gritti teti eergy d teti 107 orbit ti 108 Eetri teti eergy d teti 109 Eetri d Gritti fieds red 110 IB Qestis – eds 111 IB Questions – option A – relativity 151 14 oPtIon B – engIneerIng PhYsIcs 11 ElEcTRomaG nETIc InDucTIon Induced electromotive force (emf) 112 lez's w d frdy's w 113 atertig rret (1) 114 atertig rret (2) 115 Retiti d stig irits 116 cite 11 7 Translational and rotational motion 152 Translational and rotational relationships 153 Translational and rotational equilibrium 154 Equilibrium examples 155 Newton’s second law – moment of iner tia 156 Rotational dynamics 157 c o n t e n t s v Solving rotational problems 158 Thermodynamic systems and concepts 159 Work done by an ideal gas 160 The rst law of thermodynamics 16 1 Second law of thermodynamics and entropy 162 Heat engines and heat pumps 163 fids t rest 164 fids i ti – Beri eet 165 Beri – exes 166 vissity 167 fred sitis d rese (1) 168 Rese (2) 169 IB Questions – option B – engineering physics 1 70 15 oPtIon c – ImagIng Image formation 1 7 1 Converging lenses 1 72 Image formation in convex lenses 1 73 Thin lens equation 1 74 Diverging lenses 1 75 Converging and diverging mirrors 1 76 The simple magnifying glass 1 77 Aberrations 1 78 The compound microscope and astronomical telescope Astronomical reecting telescopes 1 79 180 Radio telescopes 181 Fibre optics 182 Dispersion, attenuation and noise in optical bres 183 Channels of communication 184 X-rys 185 X-ry igig teiqes 186 utrsi igig 187 Igig tied 188 IB Questions – option C – imaging 189 16 oPtIon d – astroPhYsIcs Objects in the universe (1) 190 Objects in the universe (2) 191 The nature of stars 192 Stellar parallax 193 Luminosity 194 Stellar spectra 195 Nucleosynthesis 196 The Her tzsprung–Russell diagram 197 Cepheid variables 198 Red giant stars 199 Stellar evolution 200 The Big Bang model 201 Galactic motion 202 Hubble’s law and cosmic scale factor 203 The accelerating universe 204 ner si – te Jes riteri 205 nesytesis te i seqee 206 Tyes sere 207 Te sgi riie d teti des 208 Rtti res d drk tter 209 Te istry te uierse 2 10 Te tre te uierse 2 11 Drk eergy 2 12 astrysis reser 2 13 IB Questions – astrophysics 2 14 17 aPPendIX vi c o n t e n t s Graphs 2 15 Graphical analysis and determination of relationships 2 16 Gri ysis – griti tis 2 1 7 ANSWERS 2 18 ORIGIN OF INDIVIDUAL QUESTIONS 2 18 INDEX 2 19 1 M E A S U R E M E N T A N D U N C E R T A I N T I E S Te ream o psics – rane o manitudes o quantities in our uni erse ORDERS Of MAgNITUDE – RANgE Of MA SSES INClUDINg ThEIR RATIOS 52 Physics seeks to explain RANgE Of lENgThS Mass / kg nothing less than the 10 Size / m radius of observable Universe total mass of observable 26 10 Universe itself. In attempting to do this, the 48 10 Universe 24 10 range of the magnitudes of various quantities 44 10 22 will be 10 mass of local galaxy huge. radius of local galaxy (Mily ay 40 10 20 If the numbers involved are going to 10 (Milky Way) mean 36 10 anything, it is important to get some 18 feel 10 disance o neares sar 32 for their relative sizes. To avoid ‘getting lost’ 10 16 10 mass of Sun among the numbers it is helpful to state them 28 10 14 10 to the nearest order of magnitude or power 24 mass of Ear th 10 12 of ten. The numbers are just rounded up 10 or 20 total mass of oceans disance from ar o Sun 10 down as 10 appropriate. 10 total mass of atmosphere 16 disance from ar o Moon 10 Comparisons can then be easily made 8 because 10 12 working out the ratio between two powers of radius of e ar 10 6 10 deees ar of e ten is just a matter of adding or subtracting laden oil super tanker 8 10 4 10 whole numbers. The diameter of an elephant 4 10 m, does not sound that much ocean / iges mounain atom, alles building 2 10 10 10 larger human 0 10 than the diameter of a proton in its 0 nucleus, 10 mouse 15 5 10 m, but the ratio between them is 10 or 10 4 2 leng of ngernail 10 100,000 times bigger. This is the same ratio as 10 8 grain of sand icness of iece of aer 4 10 between the size of a railway station blood corpuscle (order 10 uman blood coruscle 12 6 2 of magnitude 10 m) and the diameter of 10 the bacterium 10 7 Earth (order of magnitude 10 m). 16 aveleng of lig 8 10 10 20 10 electrons 10 haemoglobin molecule 10 diameer of ydrogen aom 24 12 10 proton aveleng of gamma ray 10 28 14 10 electron 10 diameer of roon 32 16 10 protons RANgE Of TIMES RANgE Of ENERgIES Time / s 20 10 Energy / J Carbon atom age of the Universe 44 18 railway station 16 energy released in a supernova 10 10 age of the Ear th 34 10 10 14 10 age of species – Homo 30 12 Ear th 10 sapiens 10 energy radiated by Sun in 1 second 26 10 For example, you would probably feel 10 10 very typical human lifespan pleased with yourself if you designed a new, 8 10 22 10 1 year environmentally friendly source of energy energy released in an ear thuae 6 10 3 that could produce 2.03 × 10 J from 0.72 18 1 day kg 10 4 10 of natural produce. But the meaning of energy released by annihilation of these 2 14 10 10 numbers is not clear – is this a lot or is it 0 little? In terms of orders of magnitudes, 1 g of atter a this hear tbeat 10 10 energy in a lightning discharge 10 3 new source produces 10 joules This not per kilogram 2 10 period of high-frequency of produce. does compare terribly 6 energy needed to charge a car 10 4 10 sound battery 5 well with the 10 joules provided by a slice of 6 2 10 10 8 bread or the 10 joules released per kilogram inetic energy of a tennis ball 8 10 of passage of light across 2 petrol. 10 a room during gae 10 10 You do NOT need to memorize all of energy in the beat of a y’s ing the 6 10 12 values shown in the tables, but you should 10 vibration of an ion in a solid 14 try and develop a familiarity with them. 10 10 10 period of visible light 16 10 14 10 18 10 20 passage of light across 10 18 10 energy needed to reove electron an atom fro the surface of a etal 22 10 22 10 24 passage of light across 10 a nucleus 26 10 M E A S U R E M E N T A N D U N C E R T A I N T I E S 1 Te SI sstem o undamenta and deri ed units been fUNDAMENTAl UNITS Any measurement being made up of 1. the number 2. the units. Without both For example but without 17 if parts, a the person’s 17 you every quantity important can be thought of as (SI). ‘years’ measurement age might the months saw = In SI, science the we see the their In them, nothing. number answers There for are or be 17 years a not quoted situation but does is not old? statement as make Mass kilogram kg Length metre m In this Are of to the Having said candidates units to be possible this, who examination many xed the In Time second s case you ampere A mole mol kelvin K Electric would it is forget really to surprising SI symbol current of substance include the to units in (Luminous intensity understood, systems of they need measurement to be that dened. You need do units as different other the words, all all other combinations the fundamental measurement of candela cd) order other list of units units are speed. The know use the them precise denitions of any of these properly. so large of that the SI magnitudes. unit In (the these metre) cases, always the use involves of a large different measurements of does to to have are units, not in the non SI) unit derived not denition of is very common. Astronomers can use the fundamental units. contain a speed unit (AU), the light-year (ly) or the parsec (pc) For appropriate. Whatever the unit, the conversion to SI units is unit simple the unit like as for of follows questions. fundamental expressed example, as they astronomical units. System are ‘seventeen’ clear. (but be units SI orders can International base sense. DERIvED UNITS Having or 4.2 says order the Quantity Temperature actually use fundamental parts: Amount length In and the minutes, know and two developed. units can arithmetic. be 11 used to work out the derived unit. distance _ Since speed 1 AU 1 ly 1 pc = 1.5 × 10 m 15 = = 9.5 × 10 m time 16 = 3.1 × 10 m units of distance __ Units of speed = There units of are also some units (for example the hour) which are so time common that they are often used even though they do not form metres _ = (pronounced ‘metres per second’) part of into equations SI. Once again, before these numbers are substituted seconds they need to be converted. Some common unit m _ = s conversions are given on page 3 of the IB data booklet. 1 = m s The table below lists the SI derived units that you will meet. 1 Of the many ways of writing this unit, the last way (m s ) is the SI derived unit SI base unit Alternative SI unit best. 2 newton Sometimes particular combinations of fundamental (N) kg m kg m s units 1 pascal are so common that they are given a new derived name. (Pa) 2 2 s N m N m For 1 example, the unit of force is a derived unit – it turns out to hertz (Hz) s joule (J) kg be 2 kg m s 2 . This unit is given a new name the newton (N) so that m 2 s 2 1N = 1 kg m s . 2 watt The great thing about SI is that, so long as the numbers that (W) into an equation are in SI units, then the m (C) A come out in SI units. You can always ‘play safe’ (V) kg m 3 s ohm all the numbers into proper SI units. (Ω) kg m kg m 3 this would be a waste of time. weber (Wb) s are awkward. some In situations astronomy, where for the use example, of the SI 1 A 2 s 2 There 1 WA 2 V A Sometimes, 2 however, 1 A by 2 converting s s 2 also J answer volt will 1 s are coulomb substituted kg 3 becomes distances tesla (T) kg involved s 1 A V s 1 2 A Wb m 1 becquerel (Bq) s PREfIxES To avoid booklet. the repeated These can be use of very scientic useful but notation, they can an alternative also lead to is to errors example, 1 kW = 1000 W . 1 mW = 10 one 1W W (in other words, ) 1000 2 M E A S U R E M E N T A N D of the calculations. ____ 3 For use in U N C E R T A I N T I E S list It is of agreed very easy prexes to given forget to on page include the 2 in the IB data conversion factor. Estimation 1 ORDERS Of MAgNITUDE kelvin 1K is and It is important that a you simple way of use. to develop When mistake (eg checking resorting to the a using by the ‘feeling’ a entering answer calculator. for calculator, is the to The some it is data rst of the very make an very low at 373 temperature. K. Room Water freezes temperature is to A estimate paper make 1 mol 12 good g of carbon carbon in the 12. About ‘lead’ of a not allow the use of 273 K 300 K the number of atoms of pencil before (paper The same 1 s process can happen with some of the derived units. 1) 1 does at about numbers easy incorrectly). multiple-choice a boils m 1 Walking speed. A car moving at 30 m s would be fast calculators. 2 1 Approximate values for each of the fundamental SI units m s Quite a slow acceleration. The acceleration of gravity are 2 given 1 is 10 m s small below. kg A packet about of 50 sugar, kg or 1 litre of water. A person would 1 N A 1 V Batteries m Distance 1 s Duration between one’s hands with arms a about the range weight from a of an few apple volts heart beat (when resting – the mains is several hundred up to 20 or volts outstretched 1 of – generally more so, 1 force be it can Pa A very small pressure. small amount Atmospheric pressure is about easily 5 10 double with exercise) 1 1 amp Current Pa owing from the mains electricity when J A very lifting computer domestic is connected. device would The be maximum about 10 A current or of energy – the work done a to an apple off the ground a so POSSIblE RE A SONAblE A SSUMPTIONS Everyday these it is The situations assumptions often possible table some below quantity are are to go lists is very not complex. absolutely back some constant and work common even if In physics true they out we allow what know that us would assumptions. we often Be in to simplify gain happen careful reality it Assumption Object treated Friction No is Mass of as point particle energy (“heat”) connecting string, of ammeter Resistance of voltmeter resistance Material obeys Machine Gas is Object of is loss etc. is negligible is innite is is Many as Only a perfect black body 153.2 = not to Additionally At be we the Even end if of we the know calculation true. often have to assume that time. Linear mechanics all motion and situations thermal mechanics – translational but you need equilibrium to be very careful situations situations situations are too big or number 1.532 × molecules have equilibrium, perfectly e.g. elastic collisions planets SIgNIfIC ANT fIgURES too small for decimals are often notation: × between 10 gas Thermal 1 Any experimental uncertainty. the This quantity measurement indicates being the measured. should possible At the be quoted range same of with values time, the its for number 10 and 10 and b is 2 e.g. the out on. Circuits efcient scientic a all assumptions. going Circuits b a slightly turned much! is Circuits zero law a where too simple what Circuits elastic that in varying of assumption assume Many SCIENTIfIC NOTATION written making Thermodynamics radiates Numbers our to Almost zero battery Ohm’s 100% is by Mechanics: ideal Collision is if problem Many Resistance Internal not a understanding Example negligible thermal an an of signicant gures of uncertainty. used will act as a guide to the amount integer. For example, a measurement of mass which 3 ; 0.00872 = 8.72 × 10 is quoted (it has an A as ve rule the of for LEAST For a more implies ± gures), 0.1 to precise g results, M E A S U R E M E N T the value complete calculated an (it that page A N D whereas three one of of number is ± of 0.001 23.5 signicant (multiplication same analysis see uncertainty has calculations answer the g signicant uncertainty simple quote in 23.456 or g g implies gures). division) signicant is digits to as used. of how to deal with uncertainties 5. U N C E R T A I N T I E S 3 Uncer tainties and error in eperimenta measurement ERRORS – RANDOM AND SySTEMATIC (PRECISION Systematic graph of and the random errors can often be recognized from a results. AND ACCURACy) experimental between Errors the can be Repeating error recorded just categorized readings means value does and as that the random not reduce there is ‘perfect’ or a or A ytitnauq An difference ‘correct’ value. systematic. systematic errors. perfect results Sources of random errors include random error • The readability • The observer • The effects of the being instrument. less than systematic error perfect. quantity B Sources of of a change systematic in errors the surroundings. Perfect include results, proportional • An instrument value • An • The should with be instrument zero error. subtracted being from wrongly To correct every for zero error random and systematic errors of two quantities. the reading. calibrated ESTIMATINg ThE UNCERTAINTy RANgE observer being less than perfect in the same way every An uncertainty range applies to any measurement. experimental value. The idea is that, 3 An accurate experiment is one that has a small cm systematic instead error, whereas a precise experiment is one that has a of giving one value that 100 small implies random just perfection, we give the likely error. 90 range measured measured value value for the measurement. 80 1. Estimating from rst principles value 70 All measurement involves a readability probability error. If we use a measuring cylinder 60 to that result has a nd the volume of a liquid, we might 50 cer tain value 3 think that the best estimate is 73 cm , 40 but we know that it is not exactly this 30 3 value (73.000 000 000 00 cm ). 20 3 Uncertainty value = Normally 73 examples illustrating the nature of experimental (a) an (b) a accurate less experiment accurate but more of low cm . We say ± 5 cm 10 . the many situations analysing data is representing graphs below to the the best experiment. use a method graph. If uncertainties the explains line created error of by the the bar their error should range as due to below. of this is to presenting is the use case, error Example Analogue Rulers, scale moving Digital scale a digital neat bars. way 2. Estimating The meters with ± pointers Top-pan and Uncertainty balances, ± meters uncertainty (half scale the smallest division) (the smallest scale division) range from several repeated measurements use. represents graph uncertainty estimated Device If Since is precision precise gRAPhIC Al REPRESENTATION Of UNCERTAINTy t’ 5 results: readability of ± (b) Two In is 3 volume (a) range value the pass uncertainty through ALL range, of the the ‘best- rectangles bars. the time times, 1.94. the A ytitnauq C ytitnauq = the The taken average largest 0.18; and 1.98 uncertainty would for readings also of trolley 1.82 these = In to seconds smallest range. be a in go ve 0.16). can The to is be quote the a slope 2.01, 1.98 value time this is as measured 1.82, s. is 2.0 is 1.97, The calculated largest example appropriate be readings readings this down might taken ± s 0.2 and deviation (2.16 1.98 ve 2.16 ± of 1.98 as the 0.18 s. It s. SIgNIfICANT fIgURES IN UNCERTAINTIES In order from quantity B quantity D gure, E ytitnauq be be e.g. 4.264 4.3 to cautious calculations ± a N 0.4 acceptable when often calculation with N. are an This to quoting rounded that nds uncertainty can express be of uncertainties, up the ± to one value 0.362 unnecessarily uncertainties to of N a is force values to quoted pessimistic two nal signicant and signicant as it is also gures. 19 mistake For The best t line example, the charge on an electron is 1.602176565 ×10 is 19 assumed ± included by all the 0.000000035 ×10 C. In data booklets error 19 expressed bars in graphs. quantity F 4 the M E A S U R E M E N T the upper This lower A N D is two not true in graph. U N C E R T A I N T I E S as 1.602176565(35) × 10 C. this is sometimes C Uncer tainties in cacuated resuts MAThEMATICAl REPRESENTATION Of UNCERTAINTIES For example if the mass of a block was measured as 10 ± 1 Then g the fractional uncertainty is ±∆p _ , 3 and the volume was measured as 5.0 ± 0.2 cm , then the p full which calculations for the density would be as makes the percentage uncertainty follows. ±∆p mass 10 ______ Best value for density = _ 3 = = 2.0 g × cm In 11 ___ The largest possible value of 100%. p 5 volume density the example above, the fractional uncertainty of the density is 3 = = 2.292 g cm 4.8 ±0.15 9 ___ The smallest possible value of density = 3 = 1.731 g Thus cm or ±15%. equivalent ways of expressing this error are 5.2 3 density = 2.0 ± density = 2.0 g 0.3 g cm 3 Rounding these values gives density = 2.0 ± 0.3 g cm 3 OR We can express absolute If a be this uncertainty fractional quantity p expressed is as or in one percentage measured then the of three ways – Working uncertainties absolute cm ± 15% using uncertainty out the uncertainty There are some These are introduced range mathematical is very ‘short-cuts’ time that consuming. can be used. would in the boxes below. ±∆p ab _ MUlTIPlIC ATION, DIvISION OR POwERS In symbols, if y = c ∆y Whenever two or more quantities are multiplied or ∆a _ _ divided Then and they each have uncertainties, the overall + approximately equal to the addition of ∆c _ + a [note this is ALWAYS added] c b uncertainty Power is ∆b _ = y the relationships are just a special case of this law. percentage n If (fractional) y = a uncertainties. ∆y ∆a _ Then Using the same numbers from For ∆m = ± 1 |n = y above, | (always positive) a example if a cube is measured along 1 ∆m _ each side, ± ( = ) g ± 0.1 = ± ± ± 0.1 cm in length 0.1 _ 10% % Uncertainty in length = ± 0.2 = ± 2.5 % 4.0 Volume 3 = 4.0 g 10 3 ∆V be then _ = m to g = (length) 3 = (4.0) 3 = 64 cm cm 3 % Uncertainty in [volume] = % uncertainty = 3 × (% = 3 × (± = ± in [(length) ] 3 ∆V _ 0.2 cm _ = ± ( 5 V The total % = ) 3 ± 0.04 = ± 4% uncertainty in [length]) cm uncertainty in the result = = ± ± (10 14 + 2.5 %) 4)% 7.5 % % 3 Absolute 3 14% of 2.0 g cm 3 = 0.28 g uncertainty = 7.5% of 64 cm 3 cm ≈ 0.3 g cm 3 = 4.8 cm 3 ≈ 5 cm 3 So density = 2.0 ± 0.3 g cm as before. 3 Thus the calculation involves mathematical operations other division or raising to a cube = 64 ± 5 cm than There multiplication, of Oter unctions OThER MAThEMATIC Al OPERATIONS If volume power, then one has are no ‘short-cuts’ possible. Find the highest and lowest to values. nd the highest and lowest possible values. e.g. the each two have addition or more quantities uncertainties, of the sin θ if θ = 60° ± 5° the absolute are added overall or subtracted uncertainty uncertainties. is and equal to nis they of θ Addition or sutraction Whenever uncertainty 1 0.91 0.87 In If symbols y ∆y = = a ± ∆a 0.82 b + ∆b uncertainty (note of ALWAYS thickness in added) a pipe wall 55 60 65 θ external = radius 6.1cm ± of if pipe 0.1cm (≃ best internal = thickness of pipe radius 5.3cm wall = ± 6.1 of θ = 60° sin θ = 0.87 max. sin θ = 0.91 min. sin θ = 0.82 ∴ sin θ = 0.87 value to uncertainty in thickness 5° pipe 0.1cm (≃ 2%) ± 0.05 5.3cm worst = ± 2%) value used 0.8cm = ±(0.1 = 0.2cm + = ±25% 0.1)cm M E A S U R E M E N T A N D U N C E R T A I N T I E S 5 Uncer tainties in raps ERROR bARS Plotting one a time. their well allows Ideally error be UNCERTAINTy IN SlOPES graph bars. In different individually all of one the to points principle, for every worked visualize the should size single all of point the be the and readings plotted error so If with bar they at the gradient quantity, could should to be out. an the the uncertainty shallowest with of then the lines error obtained. This in the has been bars) the process of gradient. possible a ytitnauq a ytitnauq best t line graph uncertainties (i.e. the lines to the that range represented calculate points Using uncertainty is used the will give steepest are for still the a rise and the consistent gradient is below. steepest gradient shallowest gradient quantity b quantity b A full analysis gradient use of of the a in order best to determine straight-line error bars for the graph all of uncertainties should the data always in the make points. UNCERTAINTy IN INTERCEPTS In practice, it would often take too much time to add all the If correct error bars, so some (or all) of the following the intercept quantity, could be Rather worst the that value plot is and out assume error that bars all of for the each point – use other error bars the are within Only the the the plot These error limits gradient or of error often considering the the bar from limits the are an the the uncertainty shallowest with the result. furthest within • working same. Only is than the for the of this all the bars the line bar, error the rst ranges (see point, t. If then i.e. the it the line will of error This graph has uncertainties point best probably and the points last in t be points. the been of intercept. possible bars) process bars. important uncertainty intercept best error for most ‘worst’ of lines a ytitnauq • then used the to points calculate will give a rise considered. to • of short-cuts we is (i.e. can the Using lines obtain represented the the that steepest are still uncertainty and the consistent in the below. maximum value of intercept when calculated for the right). best value minimum value • Only include the error bars for the axis that has the worst for intercept of intercept uncertainty. quantity b 6 M E A S U R E M E N T A N D U N C E R T A I N T I E S vectors and scaars DIffERENCE bETwEEN vECTORS AND SC Al ARS If you unit. measure Together Some any they quantities quantity, express also quantity that quantity whereas has have a that must the have and has a number magnitude direction magnitude one it the associated direction only of is with is REPRESENTINg vECTORS a In quantity. called magnitude AND a them. A vector called most books whereas would a be quantity. For example, all forces are used direction. bold The to letter letter is represent list used to represents below a force shows a represent scalar. in some For a vector example magnitude other F AND recognized methods. a F, scalar a normal F or F vectors. Vectors are best shown in pull The in table the lists table some are common linked to one quantities. another The by rst their two quantities denitions diagrams 9). All the others are in no particular arrows: (see • page using the relative magnitudes order. of Vectors Scalars Displacement Distance Velocity Speed Acceleration Mass Force Energy Momentum Temperature the are vectors shown length of involved by the the relative friction arrows normal • the direction is shown strength (all Potential or strength of the arrows. ADDITION / SUbTRACTION Of vECTORS potential If we have force) eld the forms) difference Magnetic by weight direction eld the reaction vectors Electric of can a 3 N and a 4 N force, the overall force (resultant be Density 3 N anything between = Gravitational eld strength 1 Although the vectors used 7 N Area in many of the given examples N and 7 4 N N are depending on 5 N 3 N forces, the techniques can be applied to all vectors. the directions = involved. 4 N The way to take the It is also possible to ‘split’ one vector into two (or more) directions vectors. = into This process is called resolving and the vectors that we get the components of the original vector. This can be account 4 N are is called a to do a way of analysing a situation if we choose to resolve all into two directions that are at right angles to one and 3 N use 4 N = the the vectors scale very diagram useful 3 N 3 N COMPONENTS Of vECTORS 1 N parallelogram another. law of vectors. b This process is adding vectors ‘tail’ one the in same turn – as the F F a + b F ver tical of starting vector from the is drawn head of a the previous vector. Parallelogram of vectors F horizontal Splitting a vector into components TRIgONOMETRy These ‘mutually perpendicular’ directions are totally Vector independent of each other and can be analysed separately. both directions can then be combined at the work out the nal resultant this can be always time be solved consuming. using The scale diagrams, mathematics trigonometry often makes it much easier to use the vector. mathematical forces can very end of to problems If but appropriate, Push appropriate calculate functions when the of sine resolving. values of either or The of cosine. diagram these This is below particularly shows how components. Surface A v Weight θ nisA = force A A v components θ A P H V A H = Acos θ S P H H See page 14 for an example. S V W Pushing a block along a rough surface M E A S U R E M E N T A N D U N C E R T A I N T I E S 7 to Ib Questions – measurement and uncer tainties 1. An object is rolled from rest down an inclined plane. The 3. A stone is dropped down a well and hits the 1 distance travelled by the object was measured at seven different it is released. Using the equation d = water 2.0 s after 2 g t and taking 2 2 times. A graph was then constructed of the distance travelled g = 9.81 m s , a calculator yields a value for the depth d of 2 against the (time taken) as shown below. the well the best as 19.62 m. estimate of If the the time is absolute measured error in d to ±0.1 s then is )mc( /del levart ecnatsid 9 A. ±0.1 m B. ±0.2 m In order to C. ±1.0 m D. ±2.0 m 8 4. determine the density of a certain type of wood, 7 the 6 following measurements were made on a cube of the wood. Mass = 493 g 5 Length of each side = 9.3 cm 4 The percentage ±0.5% 3 of and length uncertainty the is percentage in the measurement uncertainty in the of mass is measurement ±1.0%. 2 The 1 0 0.0 0.1 0.2 0.3 0.4 2 (time taken) A. ±0.5% B. ±1.5% Astronauts What a (ii) quantity is given by the gradient of such data is valid the but graph suggests includes a that the systematic Planet Using [2] why wish cliff a as error. = Do these results suggest that distance is to (time 2.46 taken) ? Explain your answer. allowance for the systematic from s, the error, acceleration following graph of the shows object. that have been calculated and D. ±3.5% density is the gravitational tape measure m the of a stones ± 0.01 cliff, they m. timing They then fall displays The an acceleration overhanging measure each which second. from the height drop using three a times the similar hand-held readings recorded cliff. of to for one- three s and 2.40 drops are s. Explain a why tenth the of time a readings second, vary although by the more stopwatch [2] same data after the drawn as error readings to one hundredth of a second. [1] uncertainty b) ranges the ±3.0% calculate gives The determine stopwatch 2.31 than b) in C. [2] a) Making uncertainty proportional 2 (iv) to dropping 7.64 electronic [2] by steel s stones collected X hundredth (iii) the 2 graph? Explain for / s on (i) estimate 0.5 5. a) best Obtain the average time t to fall, and write it in bars. )mc( /del levart ecnatsid the form (value ± uncertainty), to the appropriate 9 number of signicant digits. [1] 8 c) The astronauts then determine the gravitational 2s acceleration a on the planet using the formula a g = Calculate a from the values of s and t, and . 2 g t 7 determine the g uncertainty 6 the in the calculated value. Express the result in form 5 a = (value ± uncertainty), g to the appropriate number of signicant digits. [3] 4 3 HL 2 6. 1 This question forces In an is between about nding magnets experiment, two and the their magnets relationship between the separations. were placed with their North- 0 0.0 0.1 0.2 0.3 0.4 0.5 2 (time taken) seeking poles and separation two lines acceptable 2. The the lengths of diagram to show values the for sides shows the the the of a range of gradient rectangular measured the of another. The force of repulsion, the are shown of in the the magnets, table d, were measured f, and the below. possible the plate values one 2 / s results Add facing with graph. are [2] measured, their Separation and d/m Force of repulsion 0.04 4.00 0.05 1.98 0.07 0.74 0.09 0.32 f/N uncertainties. 50 ± 0.5 mm 25 ± 0.5 mm a) Plot a b) The law of Which one of the following would be the best estimate of graph the of log relating (force) the force against to the log (distance). separation [3] is form the n f percentage uncertainty in the calculated area A. ± 0.02% C. ± 3% B. ± 1% D. ± 5% 8 I B Q U E S T I o N S – of the = kd plate? M E A S U R E M E N T A N D (i) Use the graph (ii) Calculate a to value U N C E R T A I N T I E S nd for the k, value giving of its n. units. [2] [3] 2 m e c h a n i c s m Definitions These technical terms • Vector quantities • Generally, • The units • The denition should always velocity and not be have a speed confused direction are NOT with their associated the same ‘everyday’ with thing. use. This is • acceleration of acceleration Whenever the constantly increasing A motion deceleration come of an speed means is – it Symbol its denition. precise. object slowing Displacement from is It is related changes, possible down, i.e. (m it to is s to negative ÷ s = change while at acceleration Denition s The m should note that important if the object is not in velocity For this constant if (not speed velocity is the reason if same thing acceleration the direction as moved in a The the does is in a straight line. change not in speed). necessarily mean changed. positive. Example distance going s acceleration. accelerate one 2 ) the called particular particularly 1 of In them. displacement from London SI Vector Unit scalar? to m or Vector 6 particular direction. Rome is 1.43 × 10 m southeast. 1 Velocity v or u The rate of change of The average velocity during a ight m s m s m s Vector 1 displacement. from change of displacement to Rome is 160 m s southeast. ________________ velocity London = time taken 1 Speed v or u The rate of change distance of distance. The speed average speed during a ight Scalar 1 gone from __________ London to Rome is 160 m s = time taken 2 Acceleration a The rate of change of change velocity. of The velocity on _____________ acceleration average the acceleration runway during of a plane take-off Vector is = time taken 2 3.5 m s means in that a forwards on direction. average, its This velocity 1 changes But instantaneous vs average It should of time) be is noticed very that different the to average the value (over instantaneous a (at during time. period value This one every At second the the means race, end that of by her the her 3.5 m s instantaneous rst 2.0 average speed seconds, speed over she the was had rst changing travelled 2.0 all the 10.04 seconds m. was 1 particular 5.02 time). m speed In the example below, the positions of a sprinter are shown s . was During these increasing – rst she two was seconds, her accelerating. If instantaneous she started at rest at 1 (speed different times after the start of a = 0.00 m s ) 5.02 m and her average speed (over the whole two race. 1 seconds) The average speed over the whole race is easy to work out. the total distance (100 m) divided by the total time (11.3 s then her instantaneous speed at 2 seconds It must is was be more than this. s) In fact the instantaneous speed for this 1 sprinter was 9.23 m s , but it would not be possible to work this 1 giving 8.8 m s . out from the information given. star t nish d = 0.00 m d = 10.04 m d = 28.2 1 m d = 47 .89 m d = 69.12 m t = 2.0 s t = 4.0 s t = 6.0 s t = 8.0 s t = 0.0 s In frames of reference technical moving If two things are moving in the terms what we from one frame of another. The velocities are doing is reference to a d = 100.00 m t = 11.3 s stationary road. We observer moved from on this the side frame of of the reference same 1 into straight line but are travelling at of 25 m into s the driver’s frame of reference. different 1 and speeds, then relative straight can velocities subtraction imagine we as two road work by out simple appropriate. cars at different m s were measured or increases example, along 30 m s 1 1 by 5 m s a speeds. 25 m s 1 If one car (travelling overtakes the other at car according gap between the cars addition For travelling 30 their 30 m s 1 ) (travelling at 1 25 m the s ), slow then car, according the relative to the driver velocity of of the one car overtaking another, as seen by an 1 fast car is +5 m s observer on the side of the road. one car driver overtaking of the slow another, as seen by the car. m e c h a n i c s 9 g 2. the use of graphs Graphs are happen graphs • very when that useful an can for object is provide displacement–time representing in motion. useful or the changes There are that three To possible make in one not graphs velocity–time or speed–time much acceleration–time are two common from these methods of determining particular depends graphs. The particular physical Finding To be a the little on what gradient more is being plotted on precise, of the one the a straight-line are it nd either at value), the clear object this is the versions from the section of the graph (this the nds component moves distinguish gradient of positive. should Many an graphs the that case scalar then versions (displacement or are are just there moving is (distance velocity) or as situation. More complicated the graphs of a velocity in a particular direction. the forward two then velocities backward by (or choosing up then which down), direction be It does clearly For matter labelled examination up. not on candidates example a which the get direction we choose, graph. the three speed–time types graph of graph might as a distance–time graph or even an be acceleration– or tangent to the instantaneous graph at one point (this nds graph. Always look at the axes of a graph very carefully. an value). Displ acement–time graphs velocity–time graphs acceleration–time graphs • • • The gradient graph is the of a displacement–time The velocity gradient graph is the of a velocity–time The acceleration The area under a displacement–time • The area under a gradient time is • to but average time the If between vector the interpreted • direction. the objects graph. line. could look muddled • beginning, considering quantity call 1. the line. physical we determined at by the graphs. If quantities the under graphs can There simple difference and directions • area introduced particular speed) • the things normally information distance–time Finding graph actually of is an not the acceleration– often rate of useful change (it of velocity–time acceleration) graph does not represent anything graph is the displacement useful • The area time e e speed = 1 rst 4 seconds acceleration is constantly object at constant increasing, rate of change acceleration of 20 m s of velocity is increasing see = 20 m s velocity still changing all = 5 m s the time acceleration is ero rate of object is slowin own acceleration = 1 20 1 = 5 m s 2 = acceleration is decreasing, 20.0 20 10.0 10.0 speed = velocity 2 at constant speed in 2 1 4 s m / noitarelecca = 20 m s acceleration– change acceleration = 20.0 1 20.0 an the 2 m / tnemecalpsid 20 1 speed = 0 m s object at constant 20 s m / yticolev 1– faster speed for 3 seconds is e objects velocity is increasin object returns at a object stationary under graph -20 m s 4 but velocity continues to increase 10.0 0 0 1.0 2.0 3.0 4.0 5.0 6.0 7 .0 8.0 1.0 2.0 3.0 4.0 5.0 6.0 7 .0 time / s 8.0 time / s istance travelle in rst 4 secons Object moves at constant speed, stops then returns. time / s = area ner rah 1 1 1 Change in velocity = = × 4 × 20 = 40 m s × 4 × 20 m = 40 m 2 2 Object moves with increasing, then constant, Object moves with constant acceleration then decreasing acceleration. then constant velocity then ecelerates. initial war 2 velocity is +ve ma. heiht = area ner rah s m / noitarelecca 1 4.0 = +10.0 × 0. × .0 m = 4.05 m .0 2 1 .0 s m / yticolev m / tnemecalpsid highest point at t = 0.9 s 2.0 object returns to hand at t = 1.8 s 2 acceleration 10 m s 0. 1.0 2.0 time / s 1.0 2.0 time / s –10.0 change in velocity = area under graph instantaneos ownwar 1.0 level of 1 = -10.0 ×1.8 m s velocity = ero .0 2.0 velocity is 1 = -18 m s at hihest oint time / s hand as zero neative displacement 1 (change from +9.0 to t = 0. s Object is thrown ver tically upwards. Object is thrown ver tically wars. 9.0 m s ) Object is thrown ver tically upwards. e x ample of equation of uniform motion A car speed accelerates after 8 1 (i) s = ut uniformly from rest. After 8 s it has travelled 120 m. Calculate: s + 2 2 at (ii) v 2 = u = 0 + = 900 = 30 2 as 2 1 ∴ 120 = 0 × 8 a = 3.75 + + 2 × 2 a × 8 = 32 a 2 –1 –2 10 m s m e c h a n i c s ∴ v m s 3.75 × 120 (i) its average acceleration (ii) its instantaneous u d practic al equations of falling objects A c alcul ations very order velocity of an to the object situations, to determine (or record its is how the acceleration) varies it in often real used is necessary motion. These when the constant if – this can the forget eld. If being in Taking in of variables considered symbols) is as (and their follows l light senses gate when through time is a for broken a that object cuts an beam which is device of light. the recorded. of the breaks the If object beam is initial v nal a acceleration average speed t time s distance be through velocity velocity (const) two a timer can light be following equations different link quantities. can v = u s = ( + at u + v _ gates used ) t to 2 calculate the between the average two velocity joined and a gates. = u computer together to calculations of + s = ut + make s velocity = The light gives as positive, out the graphs ashes of time intervals. light at 2 vt at rst from very equation the is denition acceleration. In derived of xed these symbols, terms this a pointed at an camera object is known as of the motion of any object 20 5 2.0 3.0 time / s 2.0 3.0 time / s 3.0 time / s 30 20 10 2 acceleration / m s 10 of would 2.0 the absence of air resistance, all falling objects have the be SAME is this denition In If resistance, displacement / m 1.0 brief air are 1.0 2 acceleration. strobe of 2 at can s A effects 2as 2 or the Several 1 direct is 45 ev+ sdrawnwod be gates motion gravitational 2 v 1 light accelerated uniform 1 the gate a velocity / m s 2 and ignore down travelled known, the in taken calculated. Alternatively, uniformly 1.0 these object of object free-fall the that of an is The the we free-fall ev+ sdrawnwod length u The beam of to include. be A example motion to case! Possible list vertical be acceleration don’t is only ev+ sdrawnwod methods equations check The laboratory important uniform motion the In and (v acceleration of free-fall, INDEPENDENT of their mass. u) _ a the only source the strobe developed light, then picture an light object’s Air t the will = is have This can give the be rearranged rst objects. to The = u + at second (1) equation comes t = 0.0 s from the denition of t = 0.1 s will Typically, resistance equation. motion. v resistance ev+ sdrawnwod captured of (eventually) the become graphs the of shapes affect a the falling shown motion object of all affected by air below. displacement / m straight line as 20 average velocity. t = 0.2 s s average velocity = t velocity becomes constant 5 t = 0.3 s Since the velocity is changing 1.0 uniformly we know that 2.0 3.0 time / s this 1 velocity / m s given velocity must be ev+ sdrawnwod average t = 0.4 s 23 by 20 (v + u) _ average velocity = 2 terminal 10 (u s + v) _ or = t t = 0.5 s This 2 can be rearranged velocity of 1 23 m s to 1.0 t 2.0 acceleration = zero timer can be (u + v)t _ s a strip of to make paper dots of at time regular other ftieth of a second). piece of paper is an object, and the allowed to fall, strip will the the distance have these two substituting dots by equations for one of 1.0 variables (see As for an recorded 2.0 3.0 time / s previous on page the of derived at terminal velocity object the is be attached and to can If using the equations (typically motion every (2) 2 The intervals = on ev+ sdrawnwod ticker arranged time / s 2 acceleration / m s A 3.0 give example the graphs show, the velocity does not keep on rising. It of eventually reaches a maximum or terminal velocity. A theiruse). object in a moved known by the time. piece of shorter falling time paper than a will reach falling its terminal velocity in a much book. m e c h a n i c s 11 p hz components of projectile motion If two them, children are the of known as path throwing the ball projectile is and catching always motion and the the a tennis same ball shape. shape is This called There between a motion are no horizontal is must parabola be forces in the acceleration. horizontal This means direction, that the so there horizontal is no velocity constant. ball travels at a constant horizontal velocity v v v 3 H 2 v v v v 4 H H v 1 H v 5 path taken by ball v v H H is a parabola d d H d H d H d H H v 6 v The only forces acting during its ight are gravity and friction. There In many situations, air resistance can be a It is moving horizontally and vertically is a constant vertical force acting down, so there is ignored. at the same constant vertical acceleration. The value of the vertical time 2 acceleration but the horizontal and vertical components of the motion is 10 m s , which v of one another. Assuming the gravitional the acceleration v 2 independent is force 3 is is always gravity. H v v this to v ver tical constant, due are v 4 H true. H velocity v v 1 H v 5 v v H H changes v 6 mathematics of parabolic motion The graphs of the components of parabolic x-d e x ample motion are shown below. y-d A a projectile is launched horizontally from the top of cliff. 2 2 initial horizontal velocity s m / s m / u H a a y x 0 0 t / s t / s g height of cli h 1 1 u y s m / s m / slope = y x v u -g v x 0 0 t / s t / s x u H m / y m / x slope = u x maximum height v v vertical 0 u 0 = motion horizontal 0 u = f motion u H t / s v t / s = ? v = u H 2 a Once the components have been worked out, the actual velocities s (or t displacements) at any time can be worked out by vector = = = 10 m s a h ? = 0 s = x t = ? addition. 1 The solution of any problem involving projectile motion is as 2 follows: s = ut + at 2 • use the angle • the time of launch to resolve the initial velocity into components. 1 2 of ight will be determined by the vertical component of so h = 0 + × 10 × t 2 velocity. 2h 2 ∴ • the range time of will be determined by the horizontal component (and t = 10 the 2h ight). t = s 10 • the velocity at any point can be found by vector addition. Since Useful ‘short-cuts’ in calculations include the following v = u + at v = 0 + 10 facts: 2h • for • if a given two speed, objects the are greatest released range is together, achieved one if with the a launch angle horizontal is m 45°. x = u × t H 10 velocity 1 = 20h 2h = u × m H and one from rest, they will both hit the ground together. 10 The final velocity v f 12 m e c h a n i c s is the vector addition of v and u H fd d - fluiD resistance When An or an object example a of moves this parachutist Modelling Physics moves the option precise through • Viscous • The falling (see a drag drag Relative • The shape • The uid For example path. When effect will is and a 12 of the of (and a shows resistance reduced uid the (a to or a note a gas), that page on is 11 for moving mathematical are there will reached how by the objects a frictional free-falling motion is analysis be a graphs complex of the uid resistance object, but will be simple frictional e.g. drag a that altered in predictions force affects spherical that mass these are acts the motion. through a liquid situations. possible. on object’s falling a The perfect Engineering sphere when it that: through a uid on: object with object property how, in and, called its to of account, the the the uid object is aerodynamic or not) viscosity). absence into in respect (whether the taken range See resistance motion the is liquid velocity Earth. uid points oppose size a terminal introduces dependent used uid be to of 167) Key velocity page the effect page acts is towards uid. force • through effect uid the extreme, resistance, vertical the and horizontal an the object that horizontal velocity can is in projectile components be reduced to of motion will velocity near follow will both a parabolic be reduced. The zero. parabolic path (no uid resistance) path (with uid resistance) e xperiment to Determine free-fall acceleration All experiments recorded than to determine measurements others. equipment This often of increased means the free-fall displacement use that, of acceleration and time. technology with a limited for Some potentially time an object are experimental brings available for based on set-ups greater the will precision experimentation, use be but it is of a more can constant introduce easier acceleration sophisticated for and more many use an object free-falls a height, h, from rest in a time, t, the acceleration, g, can be calculated using s = ut to be with equipment complications. repetitions 1 If equation more Simple attempted. 2 + at which rearranges 2 2h to give = . Rather than just calculating a single value, a more reliable value comes from taking a series of measurement of the 2 t 1 different times of fall for different heights h 2 = gt 2 . A graph of h on the y-axis against t on the x-axis will give a straight line graph 2 1 that goes through the origin with a gradient equal to g, making g twice the gradient. 2 Possible set-ups include: Set-up Direct e.g. a Comments measurement ball metre bearing of with a a falling stop object, watch and ruler Very simple eliminated. equipment air release timing of version Motion of recording falling falling on the and electronic above object attached object Distance The to fall to be and data logger All to analysis of falling object allows Addition all Capturing a the how often involves a of of to simple the just easily controlled, everyday the achieved great object laboratory timing be record so random precision such whereas and the of the of overall paper tape as a the motion plot very errors and taken) introduces is ball error possible bearing, effect of air fall a from set-up harder allows the to graphs. can even the be though effect resistance of on a will to object’s to be motion, can take be longer. identify. whole graphically however. programmed Experimenter needs to software. known the the data the Software associated against information but are for friction precise. and thus and appropriate logger object’s Timing accuracy systematic time and to data improve that analysis automated taken. can mean the moving operate be in can calculations to repetitions carefully detailed (not can visual measurements For technology measurements perform is signicant. precision of many fall negligible be considered understand Video be will record analysed. sensor of standard. will increased Physical meaning height ball Introduction automatically ticker-tape is resistance Ping-Pong Electromagnet set-up If scale, video allows recording detailed needed, which ICT. m e c h a n i c s 13 f d -d d • forces – what the y are anD what the y Do In the (the ball gains but of examples a in a below, changes velocity). general shape) There terms deformation measurement of a or or are one a force a can is kick) change many in the can any change’. newton cause motion different describe velocity forces (the (the types force The SI of as can say force cause the • The (N). but causes is zero change a NOT the one (a) deformation is a that fact force force Remember ball for (resultant) (resultant) forces, ‘the unit A deformation force needed that a force – there CHANGE in for of was the velocity causes a can deformation force a then is an the called is an velocity was, one in the acceleration, A (see is fact, from If constant. deformation ball another velocity. acceleration. constant cause in velocity page also not the so we (resultant) 16). important, caused by just wall. (b) change in velocity • One force precise can the act on only description • its magnitude • its direction • the object on • the object that • the nature of one a object. force To should be absolutely include kick kick kick causes deformation of football of a force on a motion of football following pulls) that exist in all describe the Electrostatic Magnetic One way (the pushes or force the Normal force reaction (or the part of a large object) force Upthrust Tension Lift these N of the force push the at force 20° to shown the in the horizontal example acting would ON the thus football boot’. forces is forces are resultant split into vectors, force its from vector two components. mathematics or more See other page 7 for must forces. more be A used force to nd can also details. Compression Friction categorizing 50 Since nature. force of the acts the forces a s vectors forces be Gravitational ‘a FROM football words description be Different types of forces The of it exerts kick causes a change in A Effect which whether (a) by vector mathematics example: block being pushed on rough surface they force diagram: result S, surface force from the contact between two surfaces or whether the P, push force force resultant exists even if a distance separates the W S objects. force The origin of all these everyday forces is either gravitational W or P electromagnetic. observe are due The to vast majority of electromagnetic everyday effects that weight we forces. (b) by components example: block sliding down a smooth slope me a suring forces The simplest force is to experimental use the method extension of a for measuring spring. When a the size spring of is a in resultant down R tension it increases in length. The difference between the natural slope = W sin θ length and stretched length is called the extension of a spring. component into slope resultant into = W cos θ θ slope = W cos θ - R θ = zero original component down slope length = W sin θ W, weight ex tension Vector = 15.0 cm addition ex tension 2 N = 5.0 cm free-boDy Diagrams 6 N In a free-body diagram mc / noisnet xe 15.0 mathematically, • one • all object (and ONL Y one object) is chosen F ∝ x 10.0 the forces on that object are shown and labelled. F = kx For example, if we considered the simple situation of a book spring constant 5.0 resting on a table, we can construct free-body diagrams for 1 (units N m ) either the book force / N 2.0 4.0 6.0 or the table. free-body diagram 8.0 free-body diagram for book: situation: for table: P, push from R , reaction from table T Hooke’s law Hooke’s law spring is book states of a of proportionality that up proportional k is to to called the the the elastic limit, tension spring the force, F. extension, The constant. x, R constant The , reaction E from Ear th’s SI R E W 1 units the for the spring extension, 14 we constant can are calculate m e c h a n i c s N m the . Thus by measuring surface w, weight of book weight of table gravitational pull of Ear th gravitational pull of Ear th force. n’ ne wton’s first l aw Newton’s acts’. says On is rst rst that a law of motion reading, resultant this states can force that sound causes ‘an object complicated acceleration. continues but No it in does resultant uniform not really force b motion add means in a straight anything no to the acceleration – line or at rest description i.e. of ‘uniform unless a a force motion resultant given in a on external page straight 14. force All it line’. l R P, pull from person R, reaction from ground W W, weight of suitcase If the suitcase is too heavy to lift, it is not moving: ∴ acceleration = zero since acceleration = zero resultant force = zero ∴ P + R = W c ∴ R W = zero R R P p F, air friction F W F is force for wards, due to engine P is force backwards due to air resistance At all times force up (2R) = force down (W). If F > P the car accelerates for wards. If F = P the car is at constant velocity (zero acceleration). parachutist If F < P the car decelerates (i.e. there is negative free-falling acceleration and the car slows down). downwards p d W, weight If W > F the parachutist accelerates downwards. W = F The parachutist is at constant velocity (the acceleration is zero). sdrawpu gnivom tfil As the parachutist gets faster, the air friction increases until R R 2 2 W The total force up from the oor of the lift = R The total force down due to gravity = W If R > W the person is accelerating upwards. If R = W the person is at constant velocity (acceleration = zero). If R < W the person is decelerating (acceleration is negative). m e c h a n i c s 15 e equilibrium If the be in resultant force translational Mathematically on an object is equilibrium this is expressed zero (or as then just in it is said to equilibrium). follows: Translational equilibrium being For is at rest. allowed to swing instantaneously Σ From F = rst situations law, we must know be in 1. An object that is constantly 2. An object that is moving in Since a at back rest if and but NOT the forth, he mean child is in there never the the in same thing previous are times as example when she is equilibrium. zero Newton’s following does example straight forces are that the objects in the equilibrium. at rest. with constant (uniform) velocity line. vector quantities, a zero resultant force means T no force IN ANY DIRECTION. T For 2-dimensional forces case balance then the in problems any object two is in it is sufcient non-parallel to show directions. that If this T the is the equilibrium. θ W W tension, T W At the end of the Forces are not swing the forces balanced in the centre are not balanced as the child is in circular but the child is motion and is instantaneously accelerating (see page 65). P, pull at rest. weight, W if in equilibrium: Tsin θ = P (since no resultant horizontal force) Tcos θ = W (since no resultant ver tical force) Different types of forces Name of force Gravitational force Description The force object Electrostatic Normal is, as objects force The force between magnets reaction The force between two this is The force Tension Compression The Upthrust be a rod (or force is tension This is that causes the This force wing m e c h a n i c s a is of result and/or as spring) the is between force electric right of force it that it – is page sometimes referred to as the weight of the 19. charges. angles to two of has the surfaces technically has end (squashed), the This see currents. at motion the – the surfaces. If two surfaces are smooth then them. stretched, that masses. their acts frictional force is of electric that relative a their ambiguous equal the equal ends and string the acts is to opposite rod along known opposite applies and of and this the as forces on another forces applies to surfaces. uid its Air resistance or friction ends pulling outwards. object. on its another ends pushing object. This inwards. is the opposite force. some can a acts compressed upward of as the of force result surfaces that opposes compression the the force thought string tension When of a only that can When The the a unfortunately, between drag 16 objects term force Friction Lift this The Magnetic force between but be an force that objects exerted aircraft to acts oat on an causes on in an object the object water (see when a when page uid aerodynamic lift it is submerged in a uid. It is the buoyancy force 164). ows that over enables it in the an asymmetrical aircraft to y way. (see The page shape 166). of n’ d e x amples of ne wton’s seconD l aw ne wton’s seconD l aw of motion Newton’s an rst acceleration. calculating way of law of the the stating states His second value the that of of force provides a acceleration. law an resultant law this second momentum a is use object. the This causes means The 1. of Use of F = ma in a simple situation 12 N 3 kg best concept concept no friction between block and surface is If a mass of 3 kg is accelerated in a 4 m straight line by a resultant force of 2 explained A correct using on page 23. statement momentum of 12N, Newton’s would be second ‘the law resultant force F = a = the acceleration to the rate of change of F momentum’. be s . Since ma is 12 _ 2 = = m proportional must 4 m s 3 If 2 2. we use SI units (and you always should) then the Use a is even easier to state – ‘the resultant force is of F = ma equal slightly more to complicated the rate of expressed change as of momentum’. In symbols, acceleration = 1.5 m s in law this situation is 12 N If follows a mass of 3 accelerated ∆p kg in a 3 kg friction force is straight line by a force of 12 N, and the resultant _ In SI units, F = 2 acceleration ∆t dp have _ or, in full calculus notation, F been is 1.5 acting. m s , then we can work out the friction that must Since = dt F p is the symbol for the momentum of a resultant Until not you make given have studied much here for sense, what but this this means version this of action of (but second a force = will the law 3 is This resultant force = × 1.5 4.5 N forward force friction completeness. equivalent Newton’s ma = therefore, An = body. force more law on a common) applies single when mass. way we If of = forward force resultant force stating consider the friction = 12 = 7.5 4.5 N the N amount friction normal reaction of mass stays constant ‘The resultant we can state the law as proportional to 3. Use of F = ma in a (max. 8.0 N) follows. the acceleration.’ resultant and In the force is If force we also equal to is use the SI units product then of the 2-dimensional situation ‘the 3 kg mass acceleration’. symbols, in SI units, 30 N 30° F = m a A mass What of 3 will maximum rl fr kg feels happen friction if a gravitational it is placed between on the pull a towards 30 block degree and the the Earth slope slope given is 8.0 of 30 that N. the N? lr rd rd rd w klgr normal reaction 2 friction Note: • The ‘F = ma’ version of the law only applies if we 3 kg use SI must units be in – for the equation kilograms rather to work than in the component mass into slope grams. 30° • F is the acting one resultant on an needs force. object to work If (and out there this the is are several usually resultant forces true) force then before component down applying the law. 30 N 30° • This is • There an are experimental no throughout Einstein’s exceptions the – Universe. theory of Newton’s (To relativity be laws takes over into apply absolutely at slope: values of speed and normal The precise, reaction block does the the F = ma version situation is of simple the acting on acceleration. changing If a – law for constant the force or can be example, mass situation a is changing accelerate into into slope the slope. mass.) used a giving more mass) down slope = 30 N = 15 N 8 × sin 30° whenever constant maximum force component slope: component The = not very down large the slope law. a friction force up slope = N down slope = 15 = 7 F = ma slope = constant difcult then (e.g. one ∴ a needs resultant force 8 to N dp _ use the F = version. dt F ∴ acceleration down m 7 = 2 = 2.3 m s 3 m e c h a n i c s 17 n’ d In statement of the l aw Newton’s second law is an experimental law that allows us symbols, to F = - F AB calculate the effect that a force has. Newton’s third law Key the fact that forces always come in pairs. It provides a way to see if we have remembered all the forces points The two is very easy to state. ‘When two bodies A and B interact, that A exerts on B is equal and opposite to the force exerts on A ’. Another way of saying the same thing is every action on one object there is an equal but Not on another that equal the and pair act on opposite different forces objects that act on – this the are NOT Newton’s third law same pairs. only the are same the forces type. In equal other and words, opposite, if the but force they that A must exerts be on opposite B reaction include that of ‘for in that • B forces the object force notice involved. means It to of • checking BA highlights is a gravitational force, then the equal and opposite force object’. exerted by B on A is also a gravitational force. e x amples of the l aw f - a - push of wall push of girl on girl on wall If one roller-skater push of push of pushes another, they B on A A on B both feel a force. The forces must be equal and opposite, but the acceleration will be dierent (since they A B hae dierent . m s . m s 2.5 m s masses. 1 The mass of the The force on the The person with the smaller mass will ain the reater girl causes her to accelerate backwards. elocity. wall (and Ear th) is so large that the force on it does not eectivel cause an acceleration. A B a – n’ d a R, reaction from table These two forces are not third law pairs. There must be another force (on a dierent object) that W, weight F, push for ward from the ground on the car pairs with each one: R In order to accelerate, there must be a for ward force on the car The engine makes the wheels turn and the wheels push on the W ground. EART force from car on ground = f the table pushes f the Ear th pulls the boo upwards on the boo down with force W, then the with force R, then the boo must pull the Ear th up boo must push down on with force W the table with force R 18 m e c h a n i c s - force from ground on car m d weight their Mass in and weight meanings is kg) the are have amount whereas the two very become of matter weight of different muddled contained an things. in object in is Unfortunately everyday a an language. object force in (measured (measured Although in N). these equilibrium, situations. were put denitions If an but object its Moon are are often about is taken weight less than muddled wanting worried to would about to is the be on Moon, less the or gaining they lose or its mass would gravitational Earth). because gain (the On are Earth the proportional. weight losing the be – what the forces they on denitions are very example, a lift would and give if are both the the different lift the same in object accelerated different object is and the scale upwards then the same, two terms talk actually R 2M W weight, W the values. mass. M if non-equilibrium the People are For into two they sdrawpu noitarelecca Mass new weight = 2W If the lift is accelerating Double the mass means double the upwards: weight R > To make even to things worse, physicists. the Some people choose object. Other force reading supporting you weigh bottom – a less the at pull ‘weight’ on gravitational on term the of an scale. top of gravity a is can to slightly W ambiguous dene people Whichever building be weight dene denition compared it you with as to at the be the use, the The safe possible! gravity thing to do Stick to the and you is to avoid phrase cannot go using the term ‘gravitational weight force’ or if at force all of wrong. less! Gravitational situation: force = m g 1 On the surface of the Earth, g is approximately 10 N kg , 1 whereas on the surface of the moon, g ≈ 1.6 N kg Weight can be dened as either (a) the pull of gravity, W or (b) the force on a suppor ting scale R OR R W Two different denitions of ‘weight’ m e c h a n i c s 19 s d factors affecting friction – static push = zero anD Dynamic block friction, F = zero P = 0 N Friction is surfaces. smooth It force arises on the relative that opposes because the microscopic motion (they the relative surfaces scale. are at If motion involved the rest) are surfaces then not are this is of stationary two F = 0 N perfectly prevented an example ecrof hsup gnisaercni from the block of static friction. If the surfaces are moving, then it is called P = 5 N stationary dynamic friction or kinetic friction F = 5 N push friction block P = 10 N stationary F = 10 N (= F ) max block accelerates Friction arises from the unevenness of the surfaces. P = 15 N F = 9 N The value of F depends upon max push causes • the nature • the normal motion to of maximum the two surfaces in contact. reaction force between frictional force and the the two normal surfaces. reaction The force are RIGHT proportional. If the two surfaces are kept in contact by gravity, the value of friction opposes motion, F acting to LEFT does key experimental fact is that the value of static depending the on the applied force. Up to a F , the resultant force is zero. object slightly < k force, the area of contact has started reduces. In moving, other the maximum value of words, certain F maximum upon friction friction changes depend max Once A NOT For example, F max if max For we try to get a heavy block to move, any value of pushing two surfaces F would fail to get the block to moving over one another, the dynamic force frictional below force remains roughly constant even if the speed accelerate. max changes coefficient of friction Experimentally, reaction force coefcient the are of maximum friction, e x ample frictional proportional. slightly. We use force this to and the dene normal the If a block is increased µ This turns coefcient coecient of friction = µ placed until out of the to on be static a slope, block an just easy the angle begins to of the slide experimental slope down way to can the be slope. measure the friction. reaction, R P R, reaction friction F F frictional force component of W down W θ F = µR max gravitational attraction slope (W sin θ) component of W into The coefcient of friction is dened from the maximum value slope (W cos θ) W that friction can take θ F = µ R max where It • should since the R be the = normal noted force If value value for for static dynamic friction, friction the is values less of friction will be < for W sin = W cos θ θ the is increased. block just starts F F moving, µ d • = R different When µ F than θ coefcients balanced, that maximum maximum reaction the coefcient has no of friction is a ratio between two forces – = max it F max units. static = R • if the zero surfaces i.e. µ = are smooth then the maximum friction is 0. W sin θ W cos θ = • the coefcient are stuck F ≤ f 20 µ R s of friction is together. and F f = less than 1 unless the surfaces = µ R d m e c h a n i c s tan θ w Definition of work when is work Done? Work is done when a force moves the direction of the force. If the the direction of the force, then its force point of moves application at right in angles Work is a scalar quantity. Its denition is as follows. to F no work has been done. θ 1) before after block now v work done = Fs cos θ at rest s moving – work has Work done = F s cos θ been done If the this distance force can and be the displacement simplied ‘Work done = are in the same direction, to force × distance’ block now 2) before after higher up – From this work has dene a denition, new unit the called SI units the for joule: 1 work done J N = 1 are N m. We m. been done force e x amples distance (1) lifting ver tically small distance force large force 3) before (2) pushing along a rough slope force dis e rg la a sm ce n ta e rc fo r lle spring has been compressed – after The task in the second case would be easier to perform (it work has involves less force) but overall it takes more work since work been done has force to 4) before done work is If force the spring distance be the is to overcome friction. In each case, the useful same. doing work compressed), is not then constant graphical (for example, techniques can when be a used. original length after F A book suppor ted by shelf – x no work is done F max 5) before after v constant x max velocity v the total area work under done is ecrof The the F = kx force–displacement friction-free su rface friction-free su rface graph. F total work done max object continues at constant velocity – = area under graph no work is done 1 = In the examples above the work done has had different x 0 • In • In • In 1) the force has made has been the object move the object lifted higher in the the spring has been equations In 4) and object 5), is NO work moving in is the work done include: work done when lifting something vertically = mgh compressed. done. Note that even the last example, there m represents mass (in kg) though g the for eld. where • ex tension max gravitational • 3) x faster. Useful 2) 2 k x 2 results. is no represents the Earth’s gravitational eld strength force 1 (10 moving along its direction of action so no work is N kg ) h represents the height change (in m) done. 1 • work done in compressing or extending a spring = 2 k ∆x 2 m e c h a n i c s 21 e d concepts of energy anD work Energy and work are linked together. When you do work on an object, it gains K ≈ 0 J energy and you lose energy. The amount of energy transferred is equal to the P = 1000 J work units done. of Energy energy is must a be measure the same of the as amount the units of of work work – done. This means that the joules. energy transformations – conservation of energy In by any situation, one object, it we must must conservation of • Overall total • Energy • There be be able gained energy. to by There account another. are several for the This is ways changes known of in as stating energy. the this If it is principle ‘lost’ of principle: K = 250 J P = 750 J K = 250 J the is is energy neither no of created change in any nor the closed system destroyed, total energy it in must just the be constant. changes form. Universe. P = 750 J energy types Kinetic energy Radiant Nuclear Gravitational energy Electrostatic energy Electrical Equations Solar energy for the energy rst three Elastic of Light energy are given energy energy Chemical energy types potential Thermal energy Internal 1 Kinetic potential potential energy energy below. 2 = 1 mv where m is the mass (in kg), v is the velocity (in m s ) 2 2 p 1 = where p is the momentum (see page 23) (in kg m s ), and m is 2m the Gravitational mass potential (in kg) energy = mgh where m represents mass (in kg), g represents 1 the Earth’s gravitational eld (10 N kg 1 K = 500 J Elastic potential energy ), h represents the height change (in m) 2 = k ∆x 1 where k is the spring constant (in N m ), ∆x is 2 the extension (in m) P = 500 J power anD efficiency 1. e x amples Power Power is energy the is rate 1. dened as the transferred. at which This work energy RATE is is at the which same grasshopper hindlegs as done. transferred to jumps (i) take its (mass push result power __ Power A 1.8 off for m 8 g) 0.1s high. speed, uses and its as a Calculate (ii) the developed. = time taken (i) PE gained = mgh work done __ Power = time 1 taken KE The SI unit for power is the joule at start = 2 mv 2 per K = 750 J 1 1 second (J s ). Another unit for power 2 mv is P = 250 J = mgh (conservation of 2 1 dened If the something velocity v watt is (W). moving against a 1 W at a = 1 J s energy) . constant constant v = √2gh √ 2 × 10 × 1.8 = frictional 1 = force F, the power P needed is P = F 6 m s v mgh _ (ii) 2. Power = Efciency t Depending on the situation, we can 0.008 × 10 × 1.8 __ categorize the energy transferred (work = 0.1 done) K = 1000 J as useful useful energy or not. would In be a light light bulb, energy , the the ≈ P = 0 J ‘wasted’ energy would be thermal 2. (and non-visible forms of radiant dene A 60W efciency as the ratio energy to the total equation Possible forms of total work IN energy OUT __ Efciency = total useful energy power IN OUT __ Efciency = total Since units. 22 m e c h a n i c s this is Often a it ratio is it power does expressed efciency is wasted hour? wasted Energy useful work OUT __ = useful an energy not as = 90% = 54W of 60W the include: Efciency has much energy Power transferred. lightbulb How of every useful W energy). 10%. We 1.4 energy IN have a any percentage. wasted = 54 = 190 × 60 kJ × 60J of m d Definitions – line ar momentum anD impulse conservation of momentum Linear The the momentum product of (always mass and given the symbol p) is dened as velocity. law linear of constant Momentum = p = mass × of provided a of linear system there is of no momentum interacting resultant states that particles ‘the total remains external force’. velocity To m conservation momentum see why, we start by imagining two isolated particles A and v B that collide with one another. 1 The SI units for momentum must be kg m s . Alternative • units of Ns can also be used (see below). Since velocity The force vector, momentum must be a vector. In any if it happens quickly, the change by of is called the impulse (∆p = F onto certain B, F will cause B’s momentum to amount. If the time taken was ∆t, then the momentum change (the momentum impulse) ∆p a situation, • particularly A AB change a from is given to B will be given by ∆p ∆t). = F B • By Newton’s third law, the force from B ∆t AB onto A, F will be BA equal and Since the opposite to the force from A onto B, F = - F AB BA use of momentum in newton’s seconD law • Newton’s second law states that the resultant to the rate of change of of contact for A and B momentum change change for for B, A is ∆p equal = - can write this • (nal momentum initial momentum) ∆p _ = then opposite to the (momentum of A ∆t. AB This means plus the that the total momentum of momentum B) will remain the same. Total = time Example of same, as ____ F and F A we the momentum. momentum Mathematically is forceis the proportional time taken ∆t momentum 1 A jet is brought This water leaves a hose and hits a wall where its interacting velocity 2 to rest. If the hose cross-sectional area is 25 cm argument isolated. , is conserved. can be particles If this is extended so the long case, as up the the to any system number of momentum of particles is still is still conserved. 1 the velocity of the water is 50 m s and the density of the 3 water is 1000 kg m , what is the force acting on the wall? el a stic anD inel a stic collisions The law of conservation of linear momentum is not enough to 1 velocity = 50 m s always 50 predict the outcome after a collision (or an explosion). m This depends example, a on the moving nature of railway the truck, colliding m , bodies. velocity v, For collides with A density of an cross-sectional 3 stationary truck m . Possible one second, a jet of water 50 m long hits = 0.0025 m (a) elastic collision the wall. new velocity = v So m of water mass of water hitting every wall = 0.0025 = 0.125 × 50 = 0.125 m A 3 volume are: 2 area = 25 cm at rest In outcomes B 2 water = 1000 kg m identical B m second hitting wall × 1000 = 125 kg (b) totally inelastic collision v every new velocity = second 2 1 momentum of water hitting wall = 125 × 50 = 6250 kg m s m m A every This water is all brought to rest, (c) inelastic collision 1 ∴ change in B second momentum, ∆p = 6250 kg m s v force = new velocity = 6250 _ _ ∴ 3v new velocity = ∆p = = 6250 4 N 4 1 ∆t m Example The a graph football below of m A 2 mass shows 500 g. the variation Calculate with the time nal of the velocity of force the B on ball. In (a), were in the the the trucks case would then collision. A no have to have mechanical collision in elastic energy which no at bumpers. If all be would mechanical this lost energy The football was given an impulse of approximately is lost is called an elastic collision. In reality, collisions N/ecrof 100 × 0.01 = 1 N s during this 0.01 s. between everyday objects always lose some energy – the 100 Area under graph is the total only real example of elastic collisions is the collision between 90 molecules. impulse given to the For an elastic collision, the relative velocity of 80 ball ≈ 5 N s approach p = mv always equals the relative velocity of separation. 70 p v In (b), the railway trucks stick together during the collision = 60 50 m (the 5 N s is relative what is velocity known as of a separation totally is zero). inelastic This collision collision. A large = amount 0.5 kg 40 1 the of total mechanical momentum energy is still is lost (as heat and sound), but conserved. = 10 m s 30 ∴ nal In energy terms, (c) is somewhere between (a) and (b). Some 20 1 velocity v = 10 m s energy is lost, but the railway trucks do not join together. This 10 is 0.00 0.02 0.04 0.06 0.08 an example of an inelastic collision. Once again the total 0.10 momentum is conserved. time/s Linear momentum is also conserved in explosions. m e c h a n i c s 23 ib q – 1. Two identical objects A and B fall from rest from 6. different A car and a truck are both travelling at the speed limit of 1 heights. what is If the Neglect A. 2. A air takes ratio it twice of the as long heights as A to from reach which the A 60 ground, and B fell? km twice B. is 1:2 given moving. C. an The initial trolley 1:4 D. push the A. slowing. trolley There while is a then a travels horizontal forward oor along What it is is true of the horizontal mass is a) force and a backward force, but vehicles the is a collide During the the on car as shown. The truck has car. forward force only a and the truck how become does compare the entangled force together. with the exerted force by exerted the the force and a backward force, but In truck what is on the direction car? will Explain. the [2] entangled vehicles move after the or will they be stationary? Support larger. your is head-on collision, larger. collision, There of directions on slowing? forward force backward C. opposite oor, force(s) b) There the in to the by forward B. but 1:8 along The gradually h resistance. √2 1: trolley get B forward force, which diminishes with answer, referring to a physics principle. [2] time. 1 c) D. There is only a backward Determine A mass is suspended from a ring How immediately does the attached by two further to the ceiling and wall as cord makes than as from an 45° three the angle with shown. the S and of the The f) less R vertical tensions cords T Both the do are in the The of T the in of the car [3] compare with the the truck during the collision? Explain. [2] car and is truck likely drivers to be are more wearing severely seat belts. jolted in the total the kinetic collision. violated? in a) A net R, [2] energy Is the of the system principle of decreases conservation as of a result energy Explain. [1] force three I of of magnitude the F acts on a body. Dene the force. [1] S A ball of mass 0.0750 cords kg is travelling horizontally with a 1 speed in Explain. diagram. tensions the compare combined labelled b) and acceleration of driver impulse How collision. the ceiling 7. R, the of shown. collision? The after ) T Which the h S e) cords km which acceleration is (in by d) cord speed force. wreck 3. the of 2.20 m s . It strikes a vertical wall and rebounds magnitude? horizontally. A. R > T > S C. R = S = T B. S > D. R = R > T S > T ball mass 2 4. A a 5. 24 N force horizontal A. 0.0 C. 0.6 An athlete horizontal causes a surface. trains by 2.0 kg The mass to coefcient dragging a accelerate of dynamic B. 0.4 D. 0.8 heavy at load 8.0 m friction s 0.0750 kg along is: 1 2.20 ms across a rough surface. Due to kinetic (i) the collision energy is Show that speed of Show that with the wall, 20 % of the ball’s initial dissipated. the ball rebounds from the wall with a 1 1.97 m s . [2] F (ii) wall is the 0.313 impulse N given to the ball by the s. [2] 25° c) The wall The athlete exerts a force of magnitude F on the load at of 25° to the at Once the load time t the = wall at time t = 0 and leaves the T sketch graph shows how the force F that the wall horizontal. exerts a) strikes an The angle ball is moving at a steady speed, the on the ball is assumed to vary with time t average F horizontal Calculate load b) The to frictional the move load is force average at value constant moved a acting of F on the that load will is 470 enable N. the speed. horizontal [2] distance of 2.5 km in 1.2 hours. Calculate 0 t T (i) the work done (ii) the minimum the load. on the average load by power the force required F. to [2] The time [2] Use the value c) The part athlete the load uphill at the same speed as in (a). Explain, average 24 pulls in terms power i B of energy required is changes, greater Q u e s t i o n s – why than in the T is measured electronically to equal 0.0894 s. move minimum (b)(ii). m e c h a n i c s [2] of impulse F. given in (b)(ii) to estimate the average [4] 3 T h e r m a l p h Y s i C s T cc t TemperaTure and he aT flow Kelvin and Celsius Hot Most and the cold are direction (sometimes in just labels which known as that thermal heat) identify energy will transferred when two placed order in thermal contact. to the concept of the object. ‘hotness’ of The direction thermal energy of the is determined by the use each object. Thermal ows from temperature of everyday in is words, of if to hot object between determine the transfer thermal of is. are then is to chose you do not dened, need but you to understand do need to the know details the of how relation either between thermometers Celsius are marked with the Celsius scale and temperature the In easy the relationship corresponding between a temperature temperature t as T as measured measured on the on Celsius the Kelvin scale. relationship The is (K) of = t means (°C) + 273 the zero ‘size’ of the units used on each scale is identical, but they have points. in objects the energy. that other temperature two direction is naturally temperature high will natural Thermal transferred difference temperature to is (°C). Notice the size of the units is 700 K identical on each scale. 400 °C mercury boils 630 K 357 °C 600 K energy of them. a placed the the scales elacs suisleC contact, difference it objects temperature scale. cold. elacs nivleK thermal how two been degrees an and different measure sensible Celsius energy hot an two the ‘hotness’ This The only and two T naturally them, has approximate of are scale natural between scale objects there Kelvin of There ow to scales quoted an time, the This Most leads – objects these are the be In naturally of between low – ‘down’ 300 °C from temperature. 500 K Eventually, be the expected to temperature. two objects reach When the this would 200 °C same happens, 400 K they are said to be in thermal 100 °C water boils 373 K equilibrium Heat is from not one a substance object has happened has been (heat) and its is that ows another. What that thermal transferred. refers transfer to of to the energy 300 K water freezes 273 K energy Thermal 0 °C mercury freezes energy 200 K carbon dioxide freezes -100 °C non-mechanical between a system surroundings. 100 K oxygen boils -200 °C hydrogen boils -273 °C 0 K The this Kelvin scale Zero is scale also Kelvin is is an absolute called called the thermodynamic absolute absolute zero temperature scale and a measurement on temperature (see page 29). direction of transfer of thermal energy In e x amples: Ga ses For a given temperature • The at sample are all pressure, 90° on the of a gas, related P, is the to the one force container pressure, the volume and the another. per unit • area from the gas wall. order to investigate how these quantities are interrelated, we choose: one quantity alter acting • and another thing to be quantity we the independent variable (the thing we measure) to be the dependent variable (the second measure). F p = A • 2 The SI units of pressure are N m or Pa Pa = 1 N third The specic mass needs values that to will be controlled be recorded (i.e. also kept constant). depend of gas being investigated and the type of gas on being the used m so Gas quantity (Pascals). 2 1 The pressure can also be measured in these need to be controlled as well. atmospheres 5 (1 atm ≈ 10 Pa) 3 • The volume, 3 (1 • m The V, 6 = 10 of the gas is measured in m 3 or cm 3 cm ) temperature, t, of the gas is measured in °C or K T H E R M A L P H Y S I C S 25 ht t g y KineTiC TheorY miCrosCopiC vs maCrosCopiC When analysing something physical, we have a choice. Molecules phase • The macroscopic whole and sees point how it of view interacts considers with its the system as of are the arranged in substance different (i.e. solid, ways liquid depending or on the gas). a surroundings. solids • The see microscopic how its point component of view parts looks interact inside with the each system to other. Macroscopically, This is because However So far we have looked at the temperature of a system in way, but all objects are made up of atoms have a molecules bonds are not xed are volume held in absolutely and a position rigid. The xed by shape. bonds. molecules a vibrate macroscopic the solids the around a mean (average) position. The higher the and temperature, the greater the vibrations. molecules According random to kinetic motion – theory hence the these name. particles See are below constantly for more Each molecule vibrates in around a mean details. position. Although is a atoms and combination this stage. mass The with of molecules atoms), particles velocities the can that be are are different difference thought is of continually as things not (a molecule important little ‘points’ at of changing. Bonds between The molecules in a solid are molecules held close together by the inTernal enerGY intermolecular bonds. If the temperature gained the (or lost) molecules of an energy. must object From have changes the gained then it microscopic (or lost) this must point have of liquids view, A energy. liquid The The two possible forms are kinetic energy and potential xed speed in a random direction also has molecules a xed are also volume but vibrating, its but shape they can are change. not completely energy. in position. There are still strong forces between the v molecules. This keeps the molecules move around close to one another, but ∴ molecule has KE they are free to each other. F equilibrium resultant force back towards equilibrium Bonds between position position due to neighbouring molecules neighbouring molecules; these can ∴ molecule has PE be made and broken, • The molecules have kinetic energy because they are allowing a molecule to Each molecule is free moving. To be absolutely precise, a molecule can have move. to move throughout the either translational moving (the in a kinetic certain molecule is energy direction) rotating or about (the whole rotational one or molecule kinetic more is liquid by moving around its neighbours. energy axes). Ga ses • The molecules have potential energy because of the A intermolecular forces. If we imagine pulling gas put. molecules further apart, this would require will work The intermolecular plus total energy inter that molecule are to not ll the xed in container position, in which and any it is forces against the molecules are very weak. This means that the forces. molecules The expand molecules between the always two the molecules potential) is possess called the (random internal they kinetic do are essentially occasionally independent collide. More of detail one is another, given on but page 31. energy Molecules in random of a substance. Whenever we heat a substance, we increase its motion; no xed bonds internal energy. between molecules so they are free to move Temperature of If the two is a molecules substances molecules have measure in a have the of the average kinetic energy substance. the same same temperature, average kinetic then their energy. he aT and worK Many same temperature people answers for of When have confused examination example, transfer • to that ‘heat thermal a force ideas rises’ energy moves about questions – is it when is heat very what and work. common is meant to is In read, that the upwards. through a distance, we say that work same average is v done. Work is the energy that has been transmitted from V kinetic energy one system to another from the macroscopic point of view. m M • When work individual is molecules with large molecules with small place. Heat mass moving with mass moving with either increase lower average speed higher average speed potential In 26 T H E R M A L P H Y S I C S both done is the microscopic is of say that kinetic or, energy a we energy the energy cases on molecules), that has energy course, being level heating been of both. on taken transmitted. the transferred. (i.e. has molecules It or can their scc t ccty meThods of measurinG heaT CapaCiTies and definiTions and miCrosCopiC e xpl anaTion In theory, if an object could be heated up with no energy loss, speCifiC heaT CapaCiTies then the increase in temperature ∆T depends on three things: The • the energy • the mass, given to the object 1. m, the two basic ways to measure heat capacity. Electrical method and The • are Q substance from which the object is experiment would be set up as below: made. heater (placed in object) 1000 J 1000 J mass m mass m substance X substance Y V voltmeter dierent temperature ammeter change A small temperature variable power supply change since more molecules I t V _ • the specic heat capacity c = m( T large temperature T 2 Sources of experimental ) 1 error change since fewer • loss • the of thermal energy from the apparatus. molecules Two different blocks with the same mass and same container warmed input will have a different temperature dene required the to thermal raise its capacity temperature C of by 1 an K. object as Different the it different samples of the same substance) values of heat capacity. Specic by energy 1 K. required ‘Specic’ to here raise just a unit means mass ‘per and the heater will also be heat of a unit take some time through for the the energy to be shared substance. Method of mixtures have capacity known specic heat capacity of one substance can be used is to the substance objects will The different will uniformly energy 2. (even the up. change. • We for energy nd the specic heat capacity of another substance. substance before mass’. temperature T (hot) temperature T A In B symbols, (cold) Q _ Thermal capacity C = 1 (J 1 K or J °C ) ∆T Specic Q _ heat c 1 = (J (m capacity Q = kg 1 K 1 or J 1 kg °C ) ∆T) mc∆T mix together Note • A particular gas can have many different values of specic heat mass m mass m A capacity – it depends on the conditions used – see page B 161. temperature T max • These equations refer to the temperature difference after resulting other to • from words, raise the it does for is only true If an it addition generally temperature the object the so is same long as a takes of object raised of an to the is not 402 lost of amount from from room amount same object go energy above certain 25 °C from °C to of to it In energy 35 412 the temperature, energy. °C °C. as This object. starts to Procedure: lose energy. which it The loses hotter it becomes, the greater the rate at • measure the masses • measure the two of the liquids m and m A energy. starting B temperatures T and T erutarepmet A B increase in • mix the • record two liquids together. temperature if no the maximum temperature of the mixture T max energy is lost If no energy is lost energy lost gained by from by hot the system substance then, cooling down = energy increase in cold substance heating up temperature m in a real situation c A Again, (T A the thermal T A ) = m max main energy from c B source of the (T B T max ) B experimental apparatus; error is particularly the loss while of the time liquids Temperature constant rate change of an object being heated at a the are being container more transferred. also accurate need to be The changes taken into of temperature consideration for of a result. T H E R M A L P H Y S I C S 27 p (tt) tt tt t definiTions and miCrosCopiC vie w When a substance constant even changes though phase, thermal the energy meThods of me a surinG temperature is still being remains The transferred. two below possible are very C/ ° erutarepmet measuring methods similar specic in heat for measuring principle capacities to latent the (see heats methods previous shown for page). 500 1. A molten lead method for vaporization measuring of the specic latent heat of water 400 set-up electrical circuit heater 300 liquid and solid to electrical solid mix 200 circuit 100 V water voltmeter 1 2 3 4 6 5 7 8 9 10 11 12 Cooling curve for molten lead ammeter A 13 14 time / min heater (idealized) beaker The amount called of the phase change The of energy latent from from energy associated heat. The technical solid to liquid liquid to gas given to the with is is the phase term fusion and for change the the change term for The the does amount point vaporization molecules is increase of thermal calculated vaporized not variable power supply is needs energy using to be provided electrical energy so it must be increasing their potential When the releases It is a • The specic latent heat L up vapour are being freezes broken bonds are and this created takes and common during at 100 a °C mistake phase must to think change. be The moving that the with the in same of as the molecules in liquid water at 100 • Loss • Some of specic amount change of of latent energy heat per of unit a substance mass is absorbed boiling mass m ) 2 error thermal energy must 2. A method fusion water vapour from of for will be the lost apparatus. measuring before the and specic after timing. latent heat of water average we as released example the during a the know the specic specic below, temperature of ice latent heat (at the 0 heat °C) is resulting of capacity fusion added mix is to for of water, water. warm In we can water the and the measured. phase. ice In its °C. dened or experimental water calculate The at The process Providing speed V. energy. this molecules molecules t = 1 energy. very speed bonds substance I recorded. energy. Sources Intermolecular water = I t V _ their (m kinetic to energy water symbols, Q 1 Specic latent heat L = (J kg ) Q = ML M In of the idealized energy constant point is situation transfer rate of into a increase of no solid in energy loss, substance a constant would temperature until result the rate in mix together a melting C°/erutarepmet mass: m water temp.: T graph with temperature vs no energy energy m energy example above, the specic heat capacity of the liquid ice mix than the line specic that gradient of heat capacity corresponds the line that to the of the liquid corresponds solid as phase to the the is amount of energy will cause a greater for the liquid when compared the • Loss • If T H E R M A L P H Y S I C S ) = m mix then, down L ice = + energy m fusion c ice gained by ice T water of experimental mix error (or the gain) ice had of thermal not started energy at from exactly the zero, apparatus. then an additional term in the equation in there order to would account in the energy needed to warm the ice up to solid. • 28 system phase. increase with T water the cooling than for temperature from water gradient greater solid lost (T water be given is by is Sources the lost c water A + m solid the the water solid and liquid mix Phase-change of temp.: T °C liquid If less mass: m temp.: 0 °C ice energy supplied/J In mass: m reached: Water clinging to the ice before the transfer. 0 °C. T g 1 The Ga s l aws For the outline experimental what might methods be shown below, the graphs below trends presented can in a be seen slightly more clearly different if this information is way. observed. (1) constant volume (a) constant volume pressure / Pa graph ex trapolates back to 273 °C absolute temperature / K 300 200 100 0 100 temp. / °C (2) constant pressure (b) constant pressure 3 volume / m graph ex trapolates back to 273 °C 300 200 100 m / emulov 100 3 0 absolute temperature / K temp. / °C aP / erusserp (3) constant temperature (c) constant temperature 3 volume / m 1 3 / m volume Points • to note: Although Celsius pressure and temperature, volume neither both vary pressure linearly nor From with volume to Celsius graphs for a xed mass of gas we can say that: p 1. proportional these is At constant V, p ∝ T or = constant (the pressure = constant (Charles’s law) T temperature. V • A different sample of gas would produce a different straight- 2. At constant p, V ∝ T or law) T line variation for pressure (or volume) against temperature 1 3. but both graphs temperature, absolute would 273 extrapolate °C. This back to temperature the is same known At As These as increases, the volume decreases. In fact they or ∝ p V = constant (Boyle’s law) do not is are always always known as expressed apply to the in ideal Kelvin experiments gas (see done laws. page with The 25). real These gases. are A real gas is said to ‘deviate’ from ideal behaviour under certain proportional. conditions • e xperimenTal invesTiGaTions 1. p relationships temperature zero pressure inversely T, V laws • constant low Temperature dependent t as the variable; independent V as the variable; P as (e.g. Volume high of gas concentrated the control. • temperature t measured pressure). is trapped sulfuric Concentrated in capillary tube by bead of acid. sulfuric acid is used to ensure gas remainsdry. pressure gauge • Heating gas causes • Pressure • Temperature it to expand moving bead. to measure P remains equal to atmospheric. surface of water of gas altered by temperature of bath; time xed volume of air is needed to ensure bath and gas at same as the temperature. water (or oil) bath air in 3. P as the independent variable; V dependent variable; ask tas • Fixed volume of gas is trapped in the ask. Pressure the control. zero of scale is trapped air measured by a pressure pressure gauge gauge. scale to to measure p • Temperature of gas altered by temperature of bath – time is measure V needed to ensure bath and gas at same temperature. (length 2. Temperature dependent t as the variable; independent P as the variable; V as the air and volume) pump oil column surface of oil control. oil temperature t measured capillary tube • Volume of gas • Increase • Temperature measured against calibrated scale. scale to measure V (length and volume) surface of water water bath bead of of changed; pressure of time gas is forces will be needed to oil column altered ensure to when gas is compress volume always gas. is at room sulfuric acid temperature. gas (air) zero of scale volume V T H E R M A L P H Y S I C S 29 T g 2 equaTion of sTaTe The three ideal gas one mathematical definiTions laws can be combined together to produce The relationship. concepts constant of pV a gas of are (an the all mole, molar introduced easily so measurable mass as to be and able quantity) to the to Avogadro relate the the number mass of _ = constant T This If constant we of molecules will compare different molecules weuse ideal gases, that the depend the value it are on of turns in out the denition of the this gas the to – mass and constant depend not mole their to type for on the type. state of gas. different this for n are present gas An case Mole moles The of pV of _ a universal is one values that of of follows P, V the and T gas (see 29). mole any gas. gas all ‘amount gas = the for page of in ideal laws masses number In that Ideal that is of the substance that basic SI substance’. is equal substance that unit One to for mole the of amount contains the constant. nT same number of particles as 0.012 kg of 12 The universal The SI constant is called 1 unit for R is J = 8.314 J molar gas constant carbon–12 R. it 1 mol 1 R the C). (slightly) When writing shortened to the the unit mol. K Avogadro 1 mol is ( This is the number of atoms in 0.012 kg K 12 constant, N of carbon–12 ( 23 C). It is 6.02 × 10 . A pV _ Summary: = R Or p V = n R T Molar nT mass The is mass called applies. e x ample a) What number 4) at will be room occupied by temperature 8 g (20 of helium °C) and A (mass × 10 an A, mole element then of a mass. the substance A has simple a molar rule certain mass mass will be N _ atmospheric n (1.0 one molar grams. = N 5 pressure If number, volume of the Pa) A number of atoms __ number of moles = 8 n = = 2 Avogadro moles constant 4 T = 20 + 273 nRT _ V = 293 K 2 × 8.314 × 293 __ = ide al Ga ses and re al Ga ses 3 = = 0.049 m 5 p 1.0 × 10 An b) How many atoms are there in 8 g of helium (mass number of 4)? ideal p, V gas and is T microscopic a one and that thus follows ideal description of the gases an gas laws cannot ideal gas be for all values liqueed. is given to ideal on The page 31. 8 n = = 2 moles Real 4 providing 23 number of atoms = 2 × 6.02 × 1.2 × however, that the can approximate intermolecular forces are behaviour small enough 10 to 24 = gases, be ignored. For this to apply, the pressure/density of the 10 gas must Equating linK beTween The maCrosCopiC and hand be the side of low and the right-hand the temperature side macroscopic of this must formula equation of be with state for moderate. the an right- ideal gas miCrosCopiC shows The equation macroscopic of state for properties an of ideal a gas gas, (p, V pV and = nRT, T). links Kinetic the that: three 2 theory nRT = N E K 3 (page 26) random describes motion a and gas for as being this composed theory to be of molecules valid, each of in these N _ But macroscopic properties must be linked to the n = microscopic , so N A behaviour of A analysis molecules. N _ 2 RT detailed of how a large number of = N E randomly K N 3 A moving molecules interact beautifully predicts another 3 formula that allows the links between the macroscopic and ∴ E R _ = T K 2 N A the microscopic only uses The the by be Newton’s assumptions mean to an detail of laws describe ideal this assumptions identied. and from a the The derivation handful of of the formula assumptions. microscopic perspective These what we (the molar derivation the is not required approach are by the outlined IB on syllabus the but following gas constant) T ∝ is so this proportional The result the of this derivation idealized gas are is that related the to pressure just two E = called the K 3 • The number • The average of molecules random present, kinetic N energy per molecule, E K 30 T H E R M A L P H Y S I C S average KE per molecule Boltzmann’s constant k . k = B N A 3 T R _ = T B 2 N A N E the B k 2 = are absolute R is K 2 pV constant) the R and quantities: to that E ratio 3 of (Avogadro shows K The A volume N equation N page. and A numbers temperature gas. and R xed mc g KineTiC model of an ide al Ga s A before • Newton’s single molecule laws apply to • molecular When walls a molecule of a changes there are no intermolecular during a the molecules • the molecules • the collisions are treated as (due There – are in random between there is (no no to its the off the momentum change momentum must is a in vector). the energy time is spent been the a wall force on the (Newton II). There must have been an equal and molecules lost) in have from motion opposite • the points • elastic bounces container molecule are of collision • • walls forces direction except the container. behaviour • hitting wall Assumptions: after wall force molecule on the (Newton wall from the III). these • Each time there is a collision between collisions. a The pressure of a gas is explained as molecule exerted and on the the wall, a force is wall. follows: • The average forces time on means constant • This we all the wall that force force what of the call there on per microscopic over the unit a is period of effectively wall area from of the a the gas. wall is pressure. result F P = A Since overall force of on wall on molecule The pressure of a gas is a result between the the molecules, molecules and gas the of the have any pressure l aw Macroscopically, the • (see can If be the the at Charles’s l aw a constant pressure proportional this to its page of 29). gas is the its follows of have – in Microscopically as temperature energy a Macroscopically, temperature analysed molecules kinetic a gas more they are • Fast on molecules change hit Thus the the goes up, • average A higher moving The of will have momentum walls of the microscopic molecule molecules hit Faster For the both in is this pressure, proportional kelvin can (see be temperature molecules moving a walls with force (see page to lower the will we a measure the temperature slower. the on Thus the energy. we any 29). analysed as temperature, inversely of At molecules We cannot cannot reduce go their further! (see means (see faster • left). page seen The molecules hit at the a constant pressure proportional 29). to be to of its a gas is volume Microscopically this can correct. constant means that will temperature the molecules average of gas have a speed. are walls these greater the microscopic • left). The the If the volume of the gas exerts force on moving more goes the rate at which will constant. increases, these take place on a unit • area Increasing container the volume decreases of the faster the wall must go down. which so the average The average force on a unit area molecules the rate total force hit the with wall – decreases. of often. the wall can thus be the same. • If the average total force decreases total Thus the pressure remains the pressure decreases. same. up. high pressure low temperature each wall from low temperature pressure that the greater. reasons, wall microscopic molecule container. force be a remain • force because energy the • is of move imagine kinetic Macroscopically, when the • zero, zero constant • they gas constant moving of • gas boYle’s l aw a be collisions each a temperature then • of at follows • they a average. moving greater volume Microscopically • faster we molecules lower kinetic kelvin of energy container. to volume as kinetic the absolute walls temperature average of a collisions the overall force goes low pressure high temperature up. high temperature constant constant temperature pressure low volume high volume low volume high volume constant volume low pressure high pressure Microscopic Microscopic pressure justication of the Charles’s justication of Microscopic justication of Boyle’s law law law T H E R M A L P H Y S I C S 31 ib qt – t yc The following information relates to questions 1 and 2 b) below. An electrical information A substance A graph of is its heated at a constant temperature against rate time of is energy shown heater for written swimming on its pools has the following side: transfer. below. 50 Hz erutarepmet (i) 2.3 kW Estimate how many days it would take this P heater N O (ii) to Suggest heat two the water reasons in why the this swimming can only be pool. [4] an approximation. 6. L a) A cylinder tted [2] with a piston contains 0.23 mol of M helium gas. K piston time helium gas 1. Which regions existing in a of the mixture graph of correspond two to the substance phases? The A. KL, MN and following piston B. 2. LM and All regions D. No regions which in B. LM × 10 Pressure = 1.0 × 10 Temperature = 290 region MN OP of the graph is the specic heat capacity 7. This A When the volume of a gas is isothermally compressed smaller volume, the pressure exerted by the gas on Use this the walls increases. The best microscopic of the C. the pressure increase individual gas student at gas is that molecules molecules average repel velocity frequency walls 4. A lead stops. is at the smaller a a value for the universal are of each gas of other with is made in the calculation is (1) about determines home. mass more determining the specic latent heat of She the takes specic some ice latent from heat the of fusion freezer, of measures and mixes jug. it She with stirs a known until all the mass ice of has water in melted an and the nal the temperature gas temperature in of the the mixture. freezer and She the also initial strongly hitting the wall is molecules with of the water. greater records her measurements as follows: the Mass of ice used m 0.12 kg 12 °C 0.40 kg i red result, assumption compressed molecules collisions the (2) volume greater bullet As calculate explanation She the to (a)(i). temperature D. data ice. measured B. the question measures A. Pa K constant. State insulating for 3 m the its container the to ice a with of fusion 3. helium greatest? in D. the 3 5.2 (ii) C. for = gas KL available shown. 5 substance A. are position Volume (i) the the NO C. In data OP into the an iron plate, temperature of where the it lead deforms increases Initial and by temperature of ice T i an Initial mass Initial temperature of water m w amount ∆T. For an identical bullet hitting the plate with twice of water T 22 °C 15 °C w the speed, what is the best estimate of the temperature increase? Final A. ∆T B. 2 ∆T C. 2 ∆T temperature of mixture f The specic heat capacities 1 c = 4.2 kJ 4 In and c = 2.1 kJ and ice are 1 kg °C i winter, in some countries, the water in a swimming Set up the needs to be appropriate during the process of representing coming to energy thermal heated. equilibrium, Estimate equation, pool transfers a) water 1 °C ∆T a) 5. of 1 kg w D. T the cost of heating the water in a typical specic swimming that latent will heat L enable of ice. her to Insert solve values for the into the i pool from may choose Clearly 5 °C to show information to a suitable consider any will temperature any estimated be reasonable values. for size The swimming. of heat Density of the pool. b) following capacity of water 4186 J 1000 kg kg (i) (ii) per kW h Estimated of electrical energy c) K Explain in State do not solve the [5] physical your meaning equation an assumption experiment, in Why she should the mixture has melted? (but of not each each energy transfer symbol). [4] you setting up have made your about equation in the take the temperature (a). [1] of immediately after all the ice [1] [7] Explain of – T H E R M A L P H Y S I C S from molecular ice Q u E S T I o n S but [4] Calculations I B above, $0.10 values e) 32 data m d) Cost the 1 3 water from equation. term useful: 1 Specic equation You does not the microscopic behaviour, increase why while it point the is of view, in temperature melting. terms of the [4] 4 w a V e s Oo DefinitiOns Many an systems object xed the continually average same time simple HarmOnic mOtiOn (sHm) involve point path between interchange vibrations moves (the through repeats. of energy or oscillations; to-and-fro mean space about position) taking Oscillations between a Simple a when retracing xed involve kinetic the and proportional is caused mean F Mass moving Kinetic Potential energy energy Moving Elastic mass energy store two springs a moving vertical an and force also as object displacement restoring position -x F = in the is from that motion always a must proportional xed point. always to the that takes directed be place towards, This and acceleration pointed towards displacement from the or F = - (constant) × x ma ∝ -x or a = - (constant) × x the negative sign signies that the acceleration is always pointing back springs towards Mass its dened of potential The horizontal a to, is a, position. ∝ Since a between by mean motion acceleration, is the potential. harmonic the on spring Moving Elastic mass energy the mean position. potential in the 2 acceleration a / m s springs and gravitational potential A energy displacement x / m Simple pendulum Moving Gravitational -A Buoy up bouncing and down in pendulum potential bob energy Moving Gravitational buoy PE water An of of bob buoy and water oscillating Moving Points Elastic PE • ruler as a result sections the bent to note about SHM: of The time period T does not depend on the amplitude A. It is ruler isochronous of one end being of the • displaced while Not of the other is all oscillations are SHM, but there are many everyday examples ruler natural SHM oscillations. xed Denition e x ample Of sHm: ma ss between twO springs Displacement, The instantaneous x measurement: m) object mean from its distance of the (SI moving position (in a simple harmonic motion specied Amplitude, A The direction) maximum displacement (SI displacement velocity acceleration against ti me against ti me against ti me large displacement to right measurement: m) from the mean maximum right zero displacement velocity position zero velocity mass m Frequency, f The number of maximum left oscillations large force to left completed per measurement unit is time. the The number acceleration SI of small displacement to right cycles per second or Hertz right (Hz). small velocity to left Period, T The time taken (SI measurement: s) mass m left 1 for one complete oscillation. T = small force to left f Phase This is a measure of how ‘in step’ zero right difference, ø different particles are. If moving displacement large velocity to left maximum together they are in phase. ø is mass m velocity left measured in either degrees (°) or zero net force zero acceleration radians (rad). complete 360° cycle so or 2π 180° rad or π is one rad small displacement to left is right completely out of phase by half a small velocity to left cycle. A phase difference of 90° or mass m left π/2 rad is a quarter of a cycle. small force to right object oscillates betwe en ex tremes large displacement to left maximum right displacement zero velocity zero velocity mass m maximum left acceleration large force to right displacement, x amplitude, A mean position W A V E S 33 gh o ho oo acceleratiOn, VelOcity anD Displ acement During sHm • acceleration • velocity • acceleration leads leads velocity by displacement and 90° by displacement 90° are displacement 180° velocity out of phase • displacement • velocity lags lags velocity acceleration by by 90° 90° time T T 3T 4 2 4 T acceleration energy cHanges During simple HarmOnic mOtiOn During total SHM, energy Energy in energy must SHM is is interchanged remain constant. proportional • the mass • the (amplitude) • the (frequency) between The KE and oscillation is PE. said Providing to be there are no resistive forces which dissipate this energy, the undamped to: m 2 2 E tot p Graph showing the variation with distance, x of the energy during SHM k x x x 0 0 tot k Graph showing the variation with time, t of the energy during SHM p t 34 W A V E S T T 4 2 3T 4 T tv v intrODuctiOn – rays anD waVe frOnts Light, sound examples of and ripples wave They all transfer • They do so • They all surface of a pond trans Verse waVes are all Suppose shown energy without they the motion. • which on a from net one motion place of to the another. medium a stone is thrown into a pond. The continuous oscillations. Two A out as situation through oscillations (vibrations) of one sort or (1) wave front diagram A spread travel. involve another. Waves below. oscillations wave wave important are involves pulse categories a succession involves of (2) ray diagram SHM. wave just are of one individual oscillation. transverse and direction of longitudinal (see below). The pages The table gives some examples. energy ow following common to all analyse some of the properties that are waves. cross-section through water Example of energy A object transfer wave pattern moves Water ripples oating (Transverse) down’ Sound The waves (Longitudinal) the Light The gains an ‘up wave pattern at a given out from centre and instant of time motion. sound received eardrum at an ear makes wave pattern slightly vibrate. ‘up’ and ‘down’ wave (Transverse) back of stimulated the eye when (the light is retina) is waves Buildings collapse during top T and L) along of a A ‘sideways pulse’ will travel rope a rope that is held taut between that there These Compression waves A compression pulse will spring The down (Longitudinal) a spring that is is held between two lOngituDinal waVes longitudinal The wave. parallel to The fronts This the is the several of are the parts direction of of of aspects to important wave the energy energy because direction of oscillations should whereas the this to wave all that can be waves. pattern. wave that The are wave fronts moving transfer. The rays together. highlight the transfer. in be of noted the the that above medium. the rays diagrams. are This at is right always angles the to the wave case. the This are crest, trough people. It a the the taut • is are aspects movement direction oscillations as as travel • Sound known known people. highlight a is is two • (Transverse) down wave wave down studied. stretched the the earthquake. Note Waves of an bottom (Both edge of pond received. The Earthquake later in time centre of pond energy wave is an example of a transverse wave because the transfer. oscillations are at right angles to the direction of energy o transfer. Transverse uids A point (high view from above on the pressure) where (2) ray diagram (1) wave front diagram mechanical (liquids or wave is everything waves cannot be propagated through gases). where known is ‘far as everything a is ‘bunched compression. apart’ (low pressure) A is together’ point known as a rarefaction. displacement loudspeaker of molecules to the right distance to the left along wave rarefaction rarefaction rarefaction v wave moves to right situation cross-section through wave at one instant of time rekaepsduol compression direction compression variation of pressure of energy transfer average pressure motion of air molecules in wave pattern moves same direction as energy out from loudspeaker transfer distance along wave Relationship between displacement and pressure graphs W A V E S 35 wv h DefinitiOns There are motion also some in more shown Because waVe equatiOns useful on the terms detail. the The that table need to below be dened attempts to in order explain to analyse these terms wave and There they are graphs. graphs seem The on to be identical, you need to look at the axes of the graphs The displacement–time wave. they The will All the not graph other start on the points their displacement–position points along left on represents the oscillations wave at will exactly the oscillations oscillate the same in a for one similar point manner, In this the wave at graph one on the instant of right time. represents At a later a The on but graphs it can will be retain used to the same represent simple It applies taken for ‘snapshot’ time, all one the period time, the wave moved on by the of wave all the will means one must be have that and waves. complete of the wave, pattern will wavelength, given the speed T have transverse waves of λ the wave by distance ________ λ = = T time AND wavelength to is shape. longitudinal relationship speed, time. c moved • very wave time This • a oscillation the but is links frequency. carefully. • that because 1 Since = f T the y-axis records direction of this direction of the displacement only the value displacement. wave were at energy, right of So, the the if displacement. this wave angles to displacement would the It be a direction does were NOT parallel longitudinal of the specify wave to wave. energy, the c the If this the In be a transverse λ words, = frequency × wavelength wave. x / tnemecalpsid x / tnemecalpsid + f wave velocity would = T A time / s λ e x ample A stone is thrown onto a still water A surface and oating impact creates cork point 1.0 a m has away the displacement–time wave. A small from the following graph (time is position / m measured hits Symbol Displacement x mc/tnemecalpsid Term Denition This as a measures result Zero its a change wave displacement position. the of the For distance passing refers to mechanical (in undisturbed that metres) a has particular the mean waves that taken the the place point. (or average) displacement particle moves is from the from the instant the stone water): 2 1 time/s 0 1.4 1.5 1.6 1.7 1.8 1 position. 2 Amplitude A This is the position. its maximum If the amplitude wave is displacement does not lose from any the of its mean energy a) constant. the 2 amplitude of the wave: cm ......................................................... Period T This is the time taken (in seconds) for one complete b) oscillation. It is the time taken for one complete the speed d to pass any given of the wave: wave c point. = 1.0 ____ = t 1 = 0.67 m s 1.5 ......................................................... Frequency f This is the number of oscillations that take place in one c) second. 50 Hz The unit means used that 50 is the cycles hertz are (Hz). A frequency completed every the frequency of the wave: of 1 second. f = 1 ____ = T = 3.33 Hz 0.3 ......................................................... Wavelength This λ is wave one the shortest between another. distance two ‘In points phase’ (in that means metres) are in that along phase the two the with d) the c λ are moving exactly in step with one wavelength points another. = f For of the wave: 0.666 ______ = = 0.2 m 3.33 ......................................................... example, crest on the a distance water compression to from ripple the or next one the one crest to distance on a the from sound next one wave. 1 Wave speed c Intensity I This is pass a The the speed stationary intensity of (in m s ) at which the wave fronts observer. a wave is the power per unit area 2 that The is received intensity by of a the observer. wave is The unit proportional to is W the m . square 2 of The period and the frequency of its amplitude: any wave are I ∝ A inversely related. For example, if 1 ___ frequency of a wave is 100 Hz, then its period must be exactly of 100 In symbols, 1 T = f 36 W A V E S a second. the eo electrOmagnetic waVes Visible light part a is one possible of much f / H larger λ / m 3 source spectrum of similar 22 waves that are 10 all 13 10 electromagnetic. Charges that are 2 1 10 accelerating radium generate 12 10 frequency electromagnetic elds. If an wavelength 20 electric 10 15 3 × 10 charge 7 Hz m 10 γ-rays oscillates, 11 10 it will produce a 19 varying electric magnetic eld and 10 10 at 10 X-rays right angles to one 18 10 another. X-ray tube 9 10 These oscillating propagate elds (move) 1 7 10 as a transverse wave 8 10 through space. Since the sun no physical UV matter 16 10 is involved in this 7 10 propagation, can travel vacuum. they through The 15 a 10 V I S I B L E speed 6 10 UV wave can light bulb be 14 calculated electric from and constants 10 basic magnetic and it IR is the same electromagnetic 8 3.0 × 13 10 forall waves, 1 10 m s . 15 1 × 10 Although H 5 10 4 10 12 z 10 all 3 10 electromagnetic waves are 11 identical m / λ htgnelevaw this zH / f ycneuqerf of electric heater 10 in their nature, they 2 10 have very different microwaves 10 properties. This is 10 Violet because range of of the 1 huge 10 Indigo frequencies microwave oven 9 (and thus in ELBISIV involved 10 energies) the electromagnetic spectrum. 1 Blue 8 shor t radio waves Green 10 1 Yellow See page 10 132 Orange (option A) for more 7 10 Red details. 2 10 standard broadcast TV broadcast aerial 6 10 3 10 5 10 4 10 long radio waves 4 10 6 14 3 × 10 Hz 10 m 5 10 3 10 radio broadcast aerial W A V E S 37 iv d o od 1. Direct metHODs The most d direct method to measure the speed of sound is to record the time taken t for sound to cover a known distance d: speed c = . In t 1 air a at normal possible race or can side hands) the experiment seeing Echoes the pressures of to claps two be a wooden used to heard. with temperatures, would building be and their With to use planks put that be the is stop being source not hit it When observer by is for at and of the difference hearing the the sound buildings) an achieved, approximately time other possible this to together) and is travels watch surrounded practice, echoes. a sound in the can frequency of s . event same allow to m between same experimenter the 330 8 Given seeing some place. the adjust clapping f an much event distance Standing echo the the from a can be (e.g. away a the of of of light ring of a d or in sound clapping recorded speed (100m distance pulse frequency larger to (3× starting m pistol s ), for a more). front (e.g. a of a tall single synchronize (counting 1 10 the wall clap the number of (e.g. of the sound claps of in 1 a given time) and the time period T between claps is just T = . In this time, the sound travels to the wall and back. The speed of f sound In A is thus either graph should go Timing the above through pulses a of A or c = fλ , the reliable allow the result speed will of be achieved sound to be if a range calculated of distances, from the rather gradient of than the one single best-t value straight is line used. (which over smaller timers through distances and water to / or be requires data small loggers. time This intervals equipment to be would recorded allow, for with precision. example, the It is possible speed of a to sound automate wave investigated. a sound electronic a can cathode of techniques fork) that sound be can ray from (e.g. is can frequency Comparisons Wavelength and measurements tuning Frequency The of calculated if we measure a sound’s frequency and wavelength. measurement microphone (e.g. a) more will origin). speed Stroboscopic d) the a time electronic rod Appropriate c) situations against sound using metal Frequency b) 2df. inDirect metHODs Since a) the = distance process along 2. of of c the be oscilloscope the graph ashing source of controlled light the at (CRO) allow of [page the time known 116] can period display and frequency) a hence can be graph the used of the frequency to measure oscillations to be the of a sound wave. calculated. frequency of the vibrating object sound. source using a known frequency source (e.g. a standard tuning fork) or a calibrated generator. also be made between the unknown frequency and a known frequency. measurement interference destructive of waves interference. (see The page path 40) can be difference employed between to these nd two the path situations difference will be between consecutive positions of λ source of S frequency f * path A path B 1 λ detector (microphone 2 D and cathode ray oscilloscope (CRO)) b) Standing can • in • c) A be waves revealed the (see period pattern electronically resonance page 48) in a gas can be employed using tube (see made a small page by dust in movable 49) allows the maxima will be column length . factOrs tHat affect tHe speeD Of sOunD Factors include: • Nature • Density • Temperature • Humidity 38 of material (for (for the location of adjacent nodes. The positions in an enclosed tube microphone. the 2 3. nd tube λ adjacent to either: an air). W A V E S ideal gas, c ∝ √T ) for different maxima to be recorded. The length distance between i intensity The sound intensity, I, is the amount of energy that a sound wave brings to a unit area every second. The units of sound 2 intensity It are depends W on m the . amplitude of the sound. A more intense sound (one that is louder) must have a larger amplitude. 2 Intensity This ∝ (amplitude) relationship between intensity and amplitude is true for all waves. elcit r ap a fo tnemecalpsid sessap evaw dnuos a nehw louder sound of same pitch time 2 I ∝ A The inVerse square l aw Of raDiatiOn As the distance increases, the of an power observer received from by a the point source observer will of A the energy spreads out over a larger area. A doubling will result in the reduction of the power the point received to the of the original A source power of a sphere of radius r is calculated using: radiates received a total per unit power area P in (the all directions, intensity I) at a a distance quarter area 4πr of then distance = decrease If as surface 2 light r away from the point source is: value. P _____ I = 2 4πr area 4A For area A a given radiation from the inverse is area of receiver, inversely point source square law the intensity proportional to the and to the receiver. applies to of This all the received square is of the known as distance the waves. 2 I A waVefrOnts anD rays As introduced the motion of on a page 35, wavefront waves can and/or in be described terms of rays. in terms of ∝ ray from A is the the path taken by the wave energy as it travels out source. wavefront where rays spreading out x the dimensions, wavefront is a surface oscillations is the a are joining in wavefront neighbouring phase is a line with and one in points another. one In two dimension, the point. wavefront point source of wave energy W A V E S 39 soo If interference Of waVes When and two we waves can of work of superposition. at any time the out the The where same meet, resulting overall the type they wave using disturbance waves meet is at the the any vector point and of waves have then constructive principle sum the frequency interfere the the or same amplitude interference at a and the same particular point can be destructive. graphs the wave 1 displacement (at P) disturbances individual that would waves. This have is been shown produced by each of the below. A (a) wave 1 tinu / time time wave 2 displacement (at P) 1 y 0 t / s A time time (b) wave 2 tinu / resultant displacement (at P) 2 y 0 t / s zero result 2A (c) wave 1 + wave 2 = wave 3 tinu / y time time 0 constructive t / s Wave superposition tecHnic al l anguage Constructive are ‘in There step’ is a – interference with zero interference step’ destructive they one another phase takes are place – they difference place said e x amples Of interference takes to when be out are the said between the of when waves phase. two to be them. are waves in A Destructive exactly There Water phase. are ‘out waves ripple waves. of tank can Regions interference. be of used to view the large-amplitude Regions of still water interference waves are are of water constructive destructive interference. several Sound different ways of saying this. One could say that the phase It difference is equal to ‘half a cycle’ or ‘180 degrees’ or ‘π is possible frequencies Interference can take place if there are two possible routes ray to travel between the constructive from two source rays is a interference to observer. whole will If number take the of path the difference = n λ path difference = (n → make any it noise up. A in terms computer of the can component then same frequencies but of different generate phase. This difference wavelengths, ‘antisound’ will interfere a position with the original sound. An observer particular in space could have the overall noise level if the waves superimposed destructively at that position. constructive Light 1 + ) λ → destructive The colours seen on the surface of a soap bubble are a result 2 of n = 0, 1, 2, 3 . . constructive constructive or destructive interference to take place, of the waves must be destructive interference of two light One phase linked or ray is reected off the outer surface of the bubble the whereas sources and . rays. For the other is reected off the inner surface. coherent. superpOsitiOn Of waVe pulses Whenever different each wave waves individual pulses meet, meeting wave. at y = overall a) the the principle same y + 1 point y + 2 y of in superposition space is just applies: the At vector any sum of instant the in time, the displacements net that displacement would have that been results 3 b) i) A A pulse Q A pulse P A pulse Q ii) P + Q = 2A P + Q = A ii) A = 0 iii) iii) A A A A pulse Q pulse P pulse Q 40 W A V E S from produced etc. i) pulse P in then place. reduced path analyse that for exactly a to radians’. pulse P by po o pOl arizeD ligHt Light is part oscillating to one the electric another transverse of of waves and is the and (for waves; propagation. dened magnetic more both The to direction bre wster’s l aw electromagnetic be of elds details elds plane the see are of spectrum. at that page right vibration plane that It are at 132). angles of is made right They to up of A angles are the is direction the electric of in light for this be partially refracted reected eld incident general, always the electromagnetic contains ray will, ray ray is the boundary and are at is right angles If the to as the The two ray another, The angle polarizing media reected reected one plane-polarized. known between refracted. plane-polarized. totally condition on reected ray and then of the incidence angle propagation. reected ray is totally plane-polarized plane vibration of EM wave containing direction of electric incident ray electric oscillations direction θ is unpolarized eld oscillation medium 1 (vacuum) i medium 2 (water) of magnetic θr distance eld transmitted ray along is par tially polarized oscillation the wave represents electric eld oscillation into the paper There are an innite number of ways for the elds to be oriented. represents electric eld oscillation in the plane of the paper Light of (or any vibration EM wave) varies is said randomly to be unpolarized whereas if the plane-polarized plane light θ + θ i has a xed plane of vibration. The diagrams below represent = Brewster’s electric elds of light when being viewed ‘head 90° r the law relates the refractive index of medium 2, n, to on’. the incident angle θ : i sin θ sin i = θ i _____ n _____ = = tan θ i sin θ cos θ r A unpolarized light: over a period of time, the electric period of time, the electric eld only oscillates in eld oscillates in one direction random directions A mixture of polarized plane-polarized. If light the and plane unpolarized of light polarization polarizer from polarized light: over a an detect is partially rotates in is a device plane at that beam. plane 90° which of light Most and the is light said to sources laboratory processes be circularly emit that produce are the is a polarizer light used to to preferentially absorbs allowing any light in transmission only this. uniformly b) polarized. unpolarized microwaves plane-polarized analyser polarization a) the produces An light. material particular the any unpolarized polarized Polaroid one is i light often whereas radio plane-polarized waves. Light can be waves, as a radar result polarized as of trans- a parent result of exhibit ray reection double that enters or selective refraction a crystal is or split absorption. In addition, birefringence into two where some an plane-polarized crystals unpolarized beams that indicates the have mutually perpendicular planes of polarization. zero transmission preferred directions malus’s l aw When Optic ally actiVe substances plane-polarized preferred direction light will is allow incident a on an component analyser, of the light its to An be optically plane transmitted: of active polarization solutions (e.g. sugar substance of light is that solutions of one that passes rotates through different the it. Many concentrations) are opticallyactive. 0 analyser analyser ’s θ plane of θ θ preferred vibration original direction rotated plane of 0 through vibration cos θ angle θ transmitted component of plane-polarized light optically active electric eld after analyser seen head-on with substance = cos θ 0 electric eld amplitude, 0 2 The intensity of light is proportional to the (amplitude) . 2 I is transmitted intensity of light in W W m m 2 Transmitted intensity I ∝ E 2 I is incident intensity of light in 0 ∴ 2 I ∝ E 2 cos θ as expressed by Malus’s law: θ 0 is the angle between the plane of vibration and the analyser’s 2 I = I cos θ preferred direction 0 W A V E S 41 u o o o pOl arOiD sungl a sses Polaroid is molecules aligned wires a material selectively with will the absorb molecules selectively cOncentratiOn Of sOlutiOns containing light in absorb long chain that the molecules. have same electric way that a The For elds grid a given optically which the plane • length of active solution, polarization is the angle rotated is θ through proportional to: of The of the solution through which the plane- microwaves. polarized • The light passes. concentration A polarimeter It consists is a of the device solution. that measures θ for a given solution. grid electric of two polarizers (a polarizer and an analyser) that absorption viewed are eld initially aligned. The optically active solution is introduced head on between the maximum two and the transmitted analyser is rotated to nd the light. stress analysis Glass grid electric When be light transmitted electric • normally allow The by with and a person vertically absorb light standing up, with Polaroid electric plastics under through coloured oscillating some placed passed head on worn glasses transmission viewed eld and when lines become stress. stressed are birefringent When plastics observed in polarized and the then (see page white analysed, regions of 41) light is bright maximum stress. dark elds to horizontally oscillating overall intensity elds. absorption will mean that the light is reduced. • Light that has horizontally • Polaroid reducing reýected from plane-polarized sunglasses ‘glare’ will from horizontal to some preferentially horizontal surfaces will be extent. absorb reýected light, surfaces. • liquiD-crystal Displ ays (lcDs) LCDs are include crystal used in a calculator is wide displays sandwiched birefringent. One surrounding the variety and between possible liquid of different computer two glass arrangement crystal is shown applications monitors. electrodes with The and crossed With no liquid polarizer that rst liquid is • polarizers below: polarizer. The liquid of potential a rotate • This The all screen has a the the electrodes, light would twisted difference, through the between absorb crystal means reach reector crystal would that appear the second through the black. structure causes the passed and, plane of in the absence polarization to 90°. that light reecting can pass surface through and be the second transmitted polarizer, back along its polarizers original • With • A no direction. pd between the electrodes, the LCD the molecules appears light. liquid pd across the liquid crystal causes to crystal align with the transmitted • electrodes The extent controlled electric and to by this which the eld. This section the of means the screen LCD appears less will light will appear grey or be darker. black can be pd etched into glass light enters the • Coloured ålters • A can picture can be be built used up to from create a colour individual image. picture elements. LCD from the front • furtHer pOl ariz atiOn e x amples Only transverse concentrated are waves on transverse the are can be polarized. polarization able, in of principle, light to Page but be 41 all EM Microwave cm) has waves that can laboratory. conducting polarized. plane • Sound waves, being longitudinal waves, cannot be The nature of radio and TV broadcasts means that of radiation used are 42 to polarized receive and the aerials need maximum W A V E S to be possible properly signal the signal aligned strength. (with wires. vibration a typical demonstrate Polarization absorbed. If of can the be grid the wavelength wave electric are eld of a characteristics demonstrated wires if Rotation of the grid is microwaves often to using aligned the a few in the grid parallel microwaves to of the will polarized. be • be they to be transmitted. through 90° will allow the wv hvo – o reflectiOn Of twO-DimensiOnal pl ane waVes reflectiOn anD transmissiOn In general, different when media any it is wave meets partially the reected boundary and between partially two The transmitted. are diagram reected convention below at we a shows what boundary. always happens When measure when working the angles plane with waves rays, between by the rays normal and incident ray the drawn normal. at right The angles normal to incident incident ray angle i the is a construction line that is surface. normal reected ray reected reected angle r ray medium (1) medium (2) transmitted ray surface medium (2) is optically Law of reection: i = r denser than medium (1) types Of reflectiOn When ray. a single This place type from single ray of an light ‘perfect’ uneven incident diffuse of ray is l aw Of reflectiOn strikes a reection surface smooth is such generally as very the scattered mirror it different walls in all of produces to a the single reection room. directions. a In this This is reected that takes situation, an can a example The the of a reection. a location be principles line at and one direction of the angles to all directions The the of in ray A which must ignores and ray is light always wavefront. optics nature images diagrams optics. direction geometric particle optical ray geometric noitceer esuid noitceer rorrim light leaves in of of using propagated. right study light leaves in is nature out showing energy be and worked The the wave light. rays spreading out wavefront point source of light We see objects not give become out by light visible receiving by with light themselves a source of that so has we light come cannot (e.g. the from see Sun them. them or a in Most the light objects dark. bulb) do Objects because diffuse When reections have taken place that scatter light from the source towards our a mirror reection takes place, the eyes. direction using the specify The surfaces of the to picture scatter the of the laws the ray measure imaginary all reected of ray reection. directions angles In be respect line predicted order involved, with construction can it to called to is usual an the normal. light in all directions. For as example, the angle normal. Light from the right incident between The angles the normal to the the to a angle is always incident surface surface as ray is the shown taken and the line at below . central bulb sets normal o in all directions. incident ray r i reected ray The • laws the of reection incident angle are is that: equal to the reýected angle • An obser ver ‘sees’ the painting by the incident the normal ray, all the lie in reýected the same ray and plane (as receiving this scattered light. shown Our brains travel in are able straight to lines. work out the location of the object by assuming that rays The second order to should mirror is not (e.g. in be be the statement precise obvious (such as suddenly out diagram). of the is and that the only is a one of ray in arriving the an in omitted. represented reected plane included often odd at It a above) direction page). W A V E S 43 s ’ d v d e x amples refractiVe inDe x anD snell’s l aw Refraction In takes general, change the of a place wave that direction. change in at wave the boundary crosses The the reason speed that boundary for has between this will change taken two media. undergo in 1. a direction A is place. Parallel-sided ray will parallel The always direction overall sideways. As with reection, considering ray travels water), If the ray into then ray of the an the is ray directions between optically ray travels light the angles of into refracted denser light an the is always and less from from towards the medium a the of the example parallel-sided one with block of this has is block which been shown it to travelling entered move the the in a block. ray below. by normal. (e.g. dense the specied the medium refracted optically away are ray to effect An block leave air If incident ray a into normal. then the glass normal. normal ray leaves block parallel to incident ray 2. Ray travelling between two media refracted If incident ray a ray goes between two different media, the two individual ray less dense medium refractive indices using following the can be used to calculate the overall refraction equation n more dense medium sin θ 2 _____ n sin θ 1 = n 1 sin θ 2 or = n 2 sin 2 n refractive index of θ medium 1 medium 2 1 θ angle in medium 1 1 n refractive index of 2 ray refracted θ angle in medium 2 2 towards normal Suppose water. shown normal a ray The of light refraction is shone that into takes a sh place tank would that be contains calculated 1st air refraction: water sin a _____ n (n refracted as below: = 1.0) (n glass air (n = glass = 1.3) sin water b = 1.6) glass ray incident ray more dense medium 2nd refraction: n × c less dense medium sin b = glass n b × sin c water a n ray refracted away glass sin c _____ _____ = n from the normal Snell’s law allows us to work out the angles a ray is refracted sin(angle of between two b involved. Overall When sin water different the refraction is from incident angle a to refracted media, angle incidence) c. ________________ the ratio is sin(angle of a constant. sin a _____ refraction) i.e. n = sin a _____ = sin b _____ × overall sin The constant is called the refractive index n between the = media. waves This in ratio the is two equal to the ratio of the speeds of c sin sin b c two n the water media. sin i _____ = sin If the refractiOn Of pl ane waVes refractive particular then n r you index number can for and assume a the that particular other the substance medium other is is not medium is given as a mentioned air (or to The in reason speed of for the the change in direction in refraction is the change wave. be normal absolutely correct, a vacuum). Another way of expressing this medium 1 is to say that the refractive index of air can be taken to (e.g. air) be 1.0. i For example given the refractive index for a type of glass might boundary be as n r medium 2 (e.g. glass) = wavelength smaller 1.34 glass since speed reduced This means incident that angle a of ray 40° entering would the have a glass from refracted air with angle refracted ray an given by Snell’s law (an experimental law of refraction) states that sin 40° _______ sin r = = 0.4797 sin i sin r ____ 1.34 ∴ r = the ratio The n sin θ glass glass = V air air _______ = n air _____ = sin ratio n is equal sin 1 2 for a given frequency. ratio of the speeds in the different ← speed of wave in medium 2 ← speed of wave in medium 1 2 ______ ___ = sin V θ 1 W A V E S the V 2 ___ n glass to θ = V θ glass 44 constant, 28.7° ____ n = 1 media ro d tOtal internal reflectiOn anD critic al angle e x amples In 1. general, boundary It is, both between under complete This can 1 certain (total) in the two and refraction can happen at the What a media. when a denser with ray sh sees under water entire world outside water is circumstances, reection happen travelling n reection possible no to meets the visible in an angle of twice the guarantee transmission at boundary critical angle all. and it is medium. < n par tial 2 transmission θ grazing 1 emergence n 1 critical angle c n 2 θ θ At greater than the critical angle, the surface total c of the water acts like a mirror. Objects inside 2 reection 1 the water are seen by reection. 2 3 2. Prismatic reectors O source A prism surface Ray1 This ray is partially Ray2 This ray has reected and partially be a refracted angle of nearly 90°. ray refracted of is the angle incidence θ name of 90°. for the given The to the critical critical ray that angle be the used prism in at place of greater a mirror. than the If the critical light strikes angle, it the must totally internally reected. The Prisms critical can of refracted. is has the are used in many optical devices. Examples include: a angle • periscopes over ray. a – the double reection allows the reection means user to see crowd. c Ray3 This ray angle. has The critical is angle Refraction reected ray an at said angle the to can of incidence cannot occur boundary be be totally and so greater the stay inside internally worked out as ray than must the be medium critical • totally 2. The • reected follows. For the binoculars – binoculars do SLR the critical the cameras double not – have the to view be too that the long through the lens is reected up to eyepiece. ray , binoculars periscope n sin θ 1 = n 1 2 sin The prism arrangement delivers the θ 2 image to the eyepiece the right way θ = 90° = θ up. By sending the light along the 1 instrument three times, it also allows θ 2 c the binoculars to 1 ___ ∴ sin θ be shor ter. = c n 2 eyepiece lens metHODs fOr Determining refractiVe inDe x e xperimentally Par t of ray identied in several positions objective lens glass block 1. Locate paths through a taken solid by and different measuring rays its either by position or sending aligning a ray objects Par t of Par t of ray in by eye. Uncertainties in angle measurement are dependent on ray identied block can be inferred protractor measurements. (See diagrams on left) from measurements 2. Use a travelling depth and microscope apply following to measure real and apparent formula: ray heading towards real centre will not be depth of object _______________________ n = apparent refracted entering the block 3. Very accurate depth of object measurements of angles of refraction can be semi-circular achieved using a prism of the substance and a custom piece glass block of equipment call a spectrometer centre W A V E S 45 Do There DiffractiOn When Waves waves also pass through spread around apertures obstacles. they This tend to wave spread property out. is • called d > some (or • the The important becomes wavelength diffraction geometric are Diffraction is large points relatively in to note more comparison from these important to the size diagrams. when of the the aperture object). wavelength needs to be of the same order of magnitude λ as shadow region the aperture for diffraction to be noticeable. practic al signific ance Of DiffractiOn Whenever d of an observer electromagnetic receives waves, information diffraction from causes the a source energy to λ spread out. This spreading takes place as a result of any geometric obstacle d ≈ in the way and the width of the device receiving the λ shadow region electromagnetic radiation. Two sources of electromagnetic diraction more waves impor tant with smaller that out and not they are angularly interfere can be with close one resolved to one another. (see page another This can will both affect spread whether or 101). d obstacles Diffraction λ d > because λ effects they meaning are that mean that smaller light will it than is impossible the diffract ever wavelength around the to of see atoms visible atoms. It is, light, however, d geometric geometric possible shadow shadow devices region region • CDs can to image where and be DVDs stored recording λ • The – the smaller needs to be maximum depends on the wavelengths. considered amount size and of the Practical include: information method that used for microscope using a light – resolves microscope. items The that cannot electrons be have λ geometric geometric d an shadow effective wavelength region of visible light is much (see page smaller than the 127). region • Radio telescopes resolution together a λ in greater geometric – the possible. an size of Several array diameter astronomical λ that shadow wavelength d < using information. electron resolved d ≈ atoms diffraction to and objects. the create with (See dish radio a a virtual greater page limits telescopes radio the can maximum be linked telescope ability to with resolve 181) d geometric shadow region shadow region e x amples Of DiffractiOn Diffraction even if provides we can not the see reason why we can hear something it. λ d = width of Diffraction obstacle/gap wave energy is received in geometric shadow region. ba sic ObserVatiOns Diffraction etc.) have is a a wave size that effect. is of The the objects same involved order of (slits, apertures, magnitude as the wavelength. If There is a central maximum intensity. halfway between the minima. As the angle increases, the intensity of the maxima decreases. angle 1st minimum 46 W A V E S look eyes diffraction say, Other maxima occur roughly Diraction of a single slit. you your intensity this at the a distant light taking street spreads place explanation is light around a at sideways your night and – is this as eyelashes! simplication.) then a squint result of (Needless to to -o o v principles Of tHe twO-sOurce interference matHematics The location of the light and dark fringes can be mathematically pattern derived T wo-source interference is simply another application in one of two ways. The derivations do not need to be of recalled. the principle roughly the of superposition, same for two coherent sources having amplitude. Method T wo sources • they • there are have is a coherent the same constant The if: the frequency phase relationship between the two 1 simplest slits as way is shown to consider two parallel rays setting off from below. sources. parallel rays regions where waves are in phase: constructive interference destructive S 1 interference path dierence d θ p = dsin θ θ S 2 If these must S S but 2 1 two arrive the light distance T wo dippers in water moving together are coherent sources. rays in is from called regions of water ripples and other regions with no loudspeakers both connected to the same signal coherent sources. This forms regions of loud and is soft set-up is shown for viewing below. experiment. A It is two-source known as interference Young’s monochromatic source with double out only one frequency. Light of from light the called interferes fringes, can and be patterns seen on of the light and From is one that twin slits (the dark of an then light the two started extra rays out distance. in phase This extra difference. whole can number only of happen if the wavelengths. path Mathematically, = n λ n is an integer – e.g. 1, 2, 3 etc.] light slit In sources) travels path interference a difference the Path gives 2 patch, rays sound. [where A bright two generator Path are source the a waves. difference T wo in The This Constructive forms result phase. geometry difference other words of = n the d λ situation sin = θ d sin θ regions, screen. Method If a 2 screen is used to make the fringes visible, then the rays region in which Se-p 1 from the two slits cannot be absolutely parallel, but the superposition occurs physical set-up means that this is effectively true. p separation sin monochromatic θ = s of slits light source X tan P θ = D If θ is small sin θ ≃ tan θ S 1 p S X 1 S so X 0 = s D θ S 2 Xs ___ θ ∴ p = D s N For 2 constructive source interference: twin source slit p possible p = nλ = nλ slits (less than 5 mm) screen 0.1 m S 2 X 1 m D s n ____ ∴ positions D nλD _____ ∴ Se-p 2 The use of X = n a laser makes the set-up s λD ___ easier. fringe separation d = X X n double + 1 = n s screen λD ___ laser ∴ s = d slit This equation only applies when the angle is small. Example The experiment strips across the results screen in as a regular pattern represented of light and dark below. Laser are light 0.1 placed intensity distribution of mm 5.0 wavelength apart. m How 450 far nm apart is are shone the on two fringes on slits a that screen away? view seen 7 fringe width, d d = = s intensity dark bright dark 4.5 × 10 × 5 ______________ λ D _____ = 0.0225 m = 2.25 cm 4 1.0 × 10 bright W A V E S 47 n d odo o d (o) v stanDing waVes A special that case of interference occurs when two waves meet There are some These are called movement are: standing • of the same of the takes wave same in space travelling In these on place is so the nodes. are called rope The that points called are always where antinodes. because the wave the The at rest. maximum resulting pattern – it is its amplitude that changes remains over time. A frequency comparison • the amplitude xed • points in opposite conditions a with a normal (travelling) wave is given below. directions. standing wave will be Stationary formed. wave Normal (travelling) wave The conditions needed to form standing waves seem quite Amplitude specialized, but standing waves are in fact quite common. All points wave often occur when a wave reects back from a boundary on have route are that interfere Perhaps of it came. (nearly) Since and the equal the reected produce simplest a amplitude, wave standing way of these and two the waves to consider two along a waves rope. The is 2A It is at amplitude the a standing wave travelling in zero The series of at antinodes. the nodes. would All points oscillate All what points oscillate opposite diagrams the same with the same below frequency. shows same amplitude. wave. picturing transverse stretched the the incident with directions on have can Frequency be points wave along maximum wave All different amplitudes. the the They frequency. happens. Wavelength This is twice the This is the shortest resultant wave distance from one distance (in metres) wave 1 moves → node (or antinode) along the wave a) wave 2 moves ← to the next node (or between tnemecalpsid antinode). that are two in points phase with total one Phase distance All points one next b) tnemecalpsid total in between node and node are All another. points along the wavelength moving different a have phases. phase. wave 1 Energy Energy is not transmitted distance wave, an c) but it energy Energy by the does by the is transmitted wave. have associated t with it. total wave 2 Although the example left involved transverse waves on a rope, distance sid a All d) can also instruments wave inside the be created involve the instrument. using sound creation The of a or light waves. standing production of laser light tnemecalpsid total involves a standing light wave. Even electrons in hydrogen wave 2 atoms distance A can be standing explained longitudinal imagine. The example – a diagram standing in terms wave below sound of can standing be waves. particularly attempts to hard represent to one wave. tnemecalpsid total wave 2 zero wave 1 Production antinode distance of standing waves antinode tnemecalpsid latot etc. etc. node max. distance movement A node standing antinode movement antinode 48 wave musical sound e) A standing wave node – the W A V E S pattern node remains xed node longitudinal standing wave node bod odo As bOunDary cOnDitiOns The boundary that must when met standing meets mode be conditions these of at the waves the edges are boundary the of system (the taking the boundaries) place. conditions specify will Any be a of the standing possible the that that standing pipe resonant boundary can displacement system wave before, waves conditions exist node. waves closed at are one in conditions the An tube. open shown A end for a determine closed must pipe end be an open the standing must be a antinode. at both Possible ends and a end. system. N = node l 1. If Transverse the string oscillate. is waves xed Both at ends on a each of the A = antinode string end, string the ends would of the reect string a 1st harmonic cannot travelling wave frequency = f 0 and thus a standing wave is possible. The only standing waves λ 0 that t these boundary conditions are ones that have nodes at A each end. The diagrams below show the possible resonant = 2l A N modes. λ' = l N = node l A = antinode f ' = 2f 0 λ 0 = 2l st 1 harmonic = A f N 0 A N A 2l λ" = A N N 3 f " = 3f 0 A N A N A N A f ' = 2f λ' = l, 0 Harmonic modes for a pipe open at both ends A N = node l A = antinode 1st harmonic 2 λ" = f " = 3f l frequency = f 0 3 0 λ 0 A N A N = 4l A 4l λ' = 3 l f ' = 3f f "' = 4f λ"' = 0 0 2 A N A N A N A N A 4l λ" = 3 Harmonic modes for a string f " = 5f 0 The resonant fundamental are called mode or the that has rst harmonics. the lowest harmonic. Many frequency Higher musical is called resonant instruments the N modes (e.g. A guitar etc.) involve similar oscillations of metal Longitudinal sound waves in a longitudinal enclosed the in a standing pipe. reections As that wave in take the can be set example place at both up in above, organ the this modes for a pipe closed at one end instruments column results of include the ute, that the involve a trumpet, standing the wave recorder in and a column organ of pipes. air from ends. e x ample An A pipe air A N ‘strings’. Musical 2. A piano, Harmonic violin, N resOnance tube pipe (open at one end) is 1.2 m long. Tuning fork of Calculate its fundamental A frequency. known frequency 1 The speed of sound is 330 m s λ l = 1.2 m ∴ = 1.2 m = 4.8 m (rst harmonic) x 4 N ∴ λ v = fλ 330 ____ f = ≃ 69 Hz 4.8 Resonance will occur at dierent values of x The distance between λ adjacent resonance lengths = 2 W A V E S 49 ib 1. A qo – v surfer region is out where beyond the the ocean breaking waves are surf in a deep-water sinusoidal in shape. b) On the (i) crests are 20 m apart and the surfer rises a vertical diagram distance draw m from the speed wave trough to crest, in a time of 2.0 s. What the marker 1 1.0 m s C. 5.0 m s is to indicate the direction in which moving. [1] indicate, with the letter A, the amplitude of waves? the A. arrow is (ii) of an of the 4.0 above The wave. [1] 1 B. 2.0 m D. 10.0 s (iii) 1 indicate, with the letter λ, the wavelength of the 1 m s wave. 2. A standing wave is established in air in a pipe with one [1] T closed (iv) draw the displacement of the string a time later, 4 and one open end. where T is Indicate, the period with the of oscillation letter N, the of new the wave. position of the marker. X [2] 1 The c) The air molecules near X wavelength of the wave is 5.0 cm and its speed is 10 cm s Determine are (i) the (ii) how frequency of the wave. [1] T A. always at the centre of a compression. far the wave has moved in s. [2] 4 B. always C. sometimes at D. the at the centre never at centre at the the of of a centre a Interference rarefaction. of a compression and d) sometimes By what rarefaction. centre of a compression or a The rarefaction. of is This question is about sound to meant diagram the by below arrangement 3. waves reference for principle of constructive (not drawn observing the superposition, explain interference. to scale) [4] shows interference an pattern waves. produced by the light from two narrow slits S and S 1 A sound wave variation wave at of of frequency particle one 660 Hz displacement instant of time is passes through withdistance shown air. along 2 The P the below. y 0.5 n S 1 θ ϕ monochromatic displacement /mm d distance / m 0 M light source O 0 x S 2 0.5 D a) State a whether transverse this wave is an example of a longitudinal wave. single slit or screen [1] double slit b) Using data from the above graph, deduce for this sound The distance and screen S S 1 is d, the distance between the double slit 2 wave, on (i) the wavelength. the is D and diagram are D ≫ d small. such M is that the the angles mid-point θ of and S [1] observed (ii) the amplitude. [1] (iii) the speed. [2] S 1 that a distance y a distance S there from is a bright point O on fringe the at point screen. P on Light ϕ the from diagram below represents the direction of oscillation of e) a (i) is travels 2 X further to point P than light from S 2 The it screen, S n 4. shown and 2 1 State the condition in terms of the distance S X 2 disturbance that gives rise to a and wave. a a) By redrawing direction of the wave diagram, energy add arrows transfer to to show illustrate the wavelength bright fringe at of the light λ, for there to be P . [2] (ii) Deduce an expression for θ (iii) Deduce an expression for ϕ in terms of S X and d. [2] 2 the the in terms of D and y . [1] n difference (i) (ii) a a between transverse For wave longitudinal and [1] wave. a particular 1.40 mm 1.50 m. and The arrangement, the distance distance y is the from the separation the slits distance to of of the the the slits screen eighth is is bright n [1] 3 fringe A wave travels along a stretched string. The diagram below string the f) shows the variation displacement of small is M. marker The the with string attached undisturbed distance at to a the particular the position along of string the at instant the string is of in point time. Using (i) A labelled shown as O your the (ii) and the answers wavelength the angle separation to of of θ (e) the the = to 2.70 × 10 rad. determine light. fringes [2] on the screen. [3] a 5. dotted from A bright source of light is viewed through two polarisers line. whose preferred directions are initially parallel. Calculate the direction of wave travel angle the M 50 I B Q u E S t I o n S – W A V E S through which transmitted one intensity sheet to half should its be turned original to value. reduce 5 E l E C t r i C i t y a n d m a g n E t i s m Eecc ce C ' ConsErvation of ChargE T wo of types of positive contains charge and no exist negative charge, or – Coulomb’s l aw positive charge matter and cancel that negative. each contains Equal other. equal amounts Matter that amounts The are diagram far shows away from the the force between inuence of two any point other charges that charges. of distance positive and Charges are negative known charge, to exist is said to because be of electrically the forces neutral. that r F exist F q between all charges, called the electrostatic force: force like q 1 charge charges repel, F unlike charges + The F directions charges. - - + F F - - F F + are important always experimental other Each observation is that charge In order are for be created physically the they each by charge moved friction. In this to from remain on repel. other must feel and one object to another. the the object, it normally between kq an along they they force force the q q 1 be If – a inversely 2 the the line forces joining are away the from are unlike charges, the forces attract. of the same size as the force on is proportional proportional to to the the size square of of both the = k 2 2 r This is 2 _ = insulator. charges. q 1 _ to are charges, process F needs forces like one. Experimentally, can distance electrons – charge other charges objects the are is conserved. Charged of they towards the very If F each A charge attract. + F force 2 r known as Coulomb’s law and the constant k is called before the neutral hair a neutral Coulomb slightly medium constant. different called In form the fact, using the a permittivity, law is different often quoted constant for in the ε comb value of first charge value force between q F two point second charge 2 = charges of q 1 distance between 2 4πε 0 the charges constants permittivity of free after space (a constant) attraction positive hair negative 1 _ - k = + - 4πε + comb 0 + - If + - there overall are two force or can more be charges worked out near another using vector charge, the addition. + force on q (due to q A ) C overall force on q A electrons have been transferred (due to q and q B q from hair to comb B q A The total charge before any process must be equal to the force on q (due to q A total charge charge afterwards. without an It equal is impossible negative to create charge. This is a ) B positive the law of q C conservation of charge. Ve f ee fe Electrical ConduCtors and insul ators A material electrical it is charge to atom. allows conductor. called of that an is the If electrical always as a ow charge of cannot insulator. result charge of In the through ow solid ow it is through a conductors of called electrons conductors Electrical insulators an material the ow from atom brass acetate dry wood glass ceramics E l E c t r i c i t y a n d M a g n E t i s M ) C 51 Eecc e In ElECtriC fiElds – dEfinition A charge, electric in the or combination eld eld, around the value it. of of If charges, we the place force is a said test that it to produce charge feels at at any any point point practical doesn’t an The denition will on the value of the test charge the of the test charge electric or charge charges eld, E, needs that to are be small being so that = is = force per unit positive point test charge. q only. 2 Coulomb’s law can be used to relate the electric eld around a A point charge to the charge producing the eld. q A test charge placed at A 1 _ E = 2 4πε would feel this force. r 0 When A test charge placed at B • not using to charge would feel this force. • q not to these muddle sitting use the equations up in the the you charge eld (and mathematical have to be producing thus very the feeling equation for careful: eld a and A test charge around a would charge point feel a different force at different charge for other situations (e.g. the eld parallel around plates). points q 1 rEprEsEntation of ElECtriC fiElds This At is any done using point in a eld lines. eld: two opposite • the direction of eld is represented by the direction of the charges eld • the lines closest magnitude eld lines to of that the passing point eld near is that represented by the number of point. + The eld here + The eld here must be strong must be as the eld lines weak as the two like are close eld lines charges together. are far apar t. The direction of the force here must be a negatively F as shown. charged Field The around resultant point The a charges parallel eld is positive electric is eld shown eld point lines to at conducting charge any the position due to a collection of right. between two plates mean that the two oppositely charged electric parallel metal plates uniform. Electric eld • begin • never • are on + lines: positive sphere (radial eld) charges and end on negative + + + + + + + + charges cross close together when the eld is strong. – – – – – – – – – parallel eld lines in the centre Patterns 52 + E l E c t r i c i t y a n d M a g n E t i s M of electric elds – the force) 1 B it considered. F E depend situations, disturb a Eecc e ee eecc e eece EnErgy diffErEnCE in an ElECtriC fiEld When placed means done. that As potential a charge is the mass a if it an energy. has as the charge result as a eld, around Electric a idea its electric moves result, same up, in a in charge an will its mass gravitational electric either potential of a in is an energy or This work lose the ElECtriC potEntial diffErEnCE force. will eld. we increases. If example we A a is the falls, potential its gravitational below a positive potential charge is energy moved decreases. from the left, the depended the charge quantity difference difference, we the energy charge would that per or actual on double remains unit pd, was the xed charge. between difference that In difference position energy between This the is B. This results in an increase in electric Since the eld is uniform, the force is = the two points per unit charge moved difference work done __ = potential constant. = This it very easy to calculate the work charge W _ V makes B the A charge energy. and points. __ position A called difference energy to moved. energy the between example B The energy Potential mass on and doubled difference. This lift the between If that eld. If In be electric energy electric gravitational potential a eld gain energy position in feels = q done. The basic unit for potential difference is the joule/coulomb, 1 J C . A electric very important eld, the point potential to note difference is that for between a given any two points force needed to move charge is single two + + q a xed points scalar does not quantity. depend on The the work path done taken between by the these test q charge. A technical way of saying this is ‘the electric eld is conservative’. distance d units The smallest amount of negative charge available is the charge position of lower electric on an electron; the smallest amount of positive charge is the potential energy potential energy charge small Charge moving in an electric on so a we proton. use the In everyday coulomb, situations C. One this unit coulomb of is far too negative eld 18 charge Change in electric potential energy = force = E × From q × d page 52 for a denition of electric eld, the example above the electric potential its . than the electric potential energy at B volt A. We B. to If put we in let this go amount of the of work charge at B to it push would eld. This push potential would energy accelerate would be the it the be charge pushed from by so same of 6.25 × 10 electrons. given the a unit new of potential name, the difference volt, V . (pd) is Thus: that as = 1 J C potential difference are Potential difference is different the the loss gain probably words the for better the name A use as it reminds you that it is measuring the difference the two points. in working at the atomic scale, the joule is far too big to in use kinetic is and When electrical total thing. between electric a is to to by would same have carried 1 energy at denition, This Voltage greater charge E 1 In the 1 JC See is distance for a unit for energy. The everyday unit used by physicists energy. for its this gained of situation name, 1 the by is the electronvolt. electronvolt an electron is simply moving As the through could be energy a guessed that potential from would be difference volt. 19 1 B electronvolt = 1 volt × 1.6 A + × 10 C 19 + = velocity v The in normal SI prexes kiloelectronvolts latter unit is 1.6 very × 10 also (keV) apply or common J so one can measure megaelectronvolts in particle energies (MeV). The physics. Exmpe Calculate the speed of an electron accelerated in a vacuum by A positive charge released at B will be a pd of 1000 V (energy = 1 KeV). accelerated as it travels to point A 19 KE gain in kinetic energy 1 = loss = Eqd in electric 2 mv potential of electron = V × e = 1000 = 1.6 × 1.6 energy × 10 16 1 2 mv 2 × 10 J 16 = 1.6 × 10 J 2 2 mv = 2Eqd 7 v = 1.87 × 10 1 m s 2Eqd _ ∴ v = √ m E l E c t r i c i t y a n d M a g n E t i s M 53 Eecc ce ElECtriC al ConduCtion in a mEtal Whenever for charges moving complete move charges circuit, a and we the current say path that a that cannot be CurrEnt current they is follow maintained owing. is called for any A current the is circuit. length of the name Without Current a of time. is the symbol, denition Current ows THROUGH an object when there is a potential difference ACROSS dened electrical as the charge. I. for It rate is Mathematically current is of ow always given the expressed as the follows: object. A battery (or power supply) is the device that creates the potential difference. charge owed __ By convention, currents are always represented as the ow of positive charge. Current Thus = time conventional current, as it is known, ows from positive to negative. taken Although ∆Q _ currents can ow in solids, liquids and gases, in most everyday electrical I circuits = dQ _ or (in calculus notation) I = dt ∆t the currents ow through wires. In this case the things that actually move are the 1 coulomb __ 1 negative electrons opposite to the – the conduction direction of the electrons. representation The of direction conventional in which current. they As move they ampere = is 1 second move 1 1 the interactions work needs speed of to the between be done. electrons the conduction Therefore, due to the electrons when current a and current is called the ows, their lattice the drift ions metal means heats up. A = 1 C s that If a it is current ows in just one direction The known as a direct current. velocity A current that constantly changes conventional current, I direction is positive ions conduction electrons drift velocity is conduction possible speed these could electrons. unit a the so be time All a is the or that are metal drift currents positive that speed in estimate Suppose volume average In to equation. velocity are negative; the not number available to of electrons comprised all the currents density move) of is n, of the the using the movement involve generalized of just the charge-carriers charge on each drift charge-carriers movement (the carrier is q and v average so number so charge distance of charge of moved moved by charge-carriers moved past a a past charge-carrier a point moved point, ΔQ = = past A a nAvΔt × = point × v × Δt vΔt = n×AvΔt q ∆Q _ current I = I = ∆t It is interesting nAvq to compare: 4 • A typical drift speed of an electron: 10 1 m s 2 (5A current • The speeds • The speed in metal conductor of cross section 1 to their random mm ) 6 of the electrons due motion: 10 1 m s 8 54 of an electrical signal E l E c t r i c i t y down a n d a conductor: approx. M a g n E t i s M 3 × 10 1 m s and of number Δt, volume ac. In SI per their as units, the 1 held in place It or and metal wire Electrical known (rst C one an the 1 A s then alternating ampere coulomb = way is a is the other) current the derived base unit unit Eecc cc ohm’s l aw – ohmiC and non-ohmiC bEhaviour The graphs typical below show how the current varies with rEsistanCE potential difference for some Resistance devices. between current. (a) metal at constant (b) lament lamp is the mathematical potential If difference something has a ratio and high (c) diode resistance, it means that you would temperature tnerruc tnerruc tnerruc need it in a large order potential to get a difference current potential to across ow. difference __ Resistance = current V In symbols, R = I potential potential potential dierence dierence dierence We be dene equal a to new one unit, volt the per ohm, Ω, to amp. 1 1 If current the and device is potential said to proportional (like Ohm’s states law temperature In ohmic. lament that remains the are proportional Devices where lamp the or current current diode) owing (like are the and said through a metal at potential to be piece constant ohm = 1 V A temperature) difference are not non-ohmic of metal is proportional to the potential difference across it providing the constant. symbols, V A be the difference ∝ I [if device temperature with constant is constant] resistance (in other words an ohmic device) is called a resistor resistor. powEr dissipation All this energy is going into heating up the resistor. In symbols: energy difference __ Since potential difference = charge charge P owed And current = V × Sometimes is more useful to use this equation in a slightly taken different means it = time This I owed __ that (energy potential difference difference) × (charge __ owed) × (charge e.g. current energy __ = form, difference __ P = V × P = (I P = I I × but R) × V = I × R so I = owed) (time time taken) 2 R 2 V _ Similarly This energy difference per time is the power dissipated by P = the R CirCuits – KirChoff ’s CirCuit l aws An electric circuit can contain E x amplE many A 1.2 kW electric kettle is plugged into 3.4A different devices or components. The the 250 V mains supply. Calculate 5.5A mathematical applied to relationship any components V component in a = or IR can groups be (i) the (ii) its (i) I current drawn 2.7A of resistance circuit. 1200 _ When to analysing look at the a circuit circuit as a it is important whole. = = x 4.8 A 250 The 250 _ power supply providing the is the device energy, but that it is The second any loop, that determines what through the the fundamental the total must potential when conservation be sum circuits: electric of to completely per and zero. Any within energy. These laws dissipated loop The across in the loop (potential known as and can be Kirchoff’s stated example larger circuit. below across the component).Care betaken to get the sign of any of loop the 12.0 - means 5.3 x potential mathematically = 0 loop in a consideration + that: 2.7 3.2 difference = 0. across the bulb, circuit If the chosen loop direction is from x = 6.2 V as: negative side of a battery to its pd = +12v ∑I one correct. the law: shows Anti-clockwise are • First Ω source the The laws 52 the pd collectively = unit the charge needsto conservation = laws drop of R circuit. analysing conservation energy difference thecomponents apply (ii) around whole must Two that current of ows states 4.8 charge circuit law is pd = -3.2v (junction) positive side, this is an increase in + Second The rst law: law ∑ states V = that 0 (loop) the potential when algebraic and the calculating value the is positive + sum. + pd = -5.3v sum of the currents at any junction in • If the direction around the loop pd = +2.7v is + the circuit into a is zero. junction current The must owing out current be of equal a owing to the junction. In in the same owing is a direction through potential the drop as the component, and the value this pd = example (right) the unknown negative when calculating the example x = 5.5 + 2.7 3.4 = 4.8 of the use of Kirchoff’s sum. circuit current -x is An the - current laws is shown on page 59. A E l E c t r i c i t y a n d M a g n E t i s M 55 re ee e ElECtriC al mEtErs rEsistors in sEriEs A series circuit The current The total has must be potential components the same difference connected everywhere is shared one in after the among another circuit the since in a continuous charge is chain. conserved. A current-measuring ammeter. series components. needs at It the to be should point meter be where measured. is called connected A the an in current perfect power supply ammeter would have zero resistance. (24V) A meter that difference should I is be measures called placed component or considered. A a in potential voltmeter. parallel components perfect It with the being voltmeter has I innite (2A) resistance. (2A) R R 1 R 2 (3Ω) 3 (4Ω) (5Ω) Example of a series circuit M We resistor ul by eletrial thermal enery can work out what share they take motor liht enery mehanial and thermal enery enery and thermal looking at each component in turn, e.g. enery is The oner ted potential resistor = I × difference across the across the R 1 into enery The potential bulb potential = I × difference R 2 dierene R = R total + R 1 + 2 R 3 (6 + 8 + 10 = 24 V) This always applies to a series circuit. pd of power supply Note that potential Total resistance = 3Ω + 4 Ω + 5 Ω = 12 V rEsistors in parallEl parallel the circuit branches and allows the charges more than one possible route circuit. V total I I total total V I I R 1 1 1 I + I 2 I 3 + I 2 3 V I I 2 2 R 2 V I I R 3 3 3 M Example Since the potential each of a parallel power circuit supply difference xes across it. the potential The total difference, current is just each the component addition of has the 1 _ 1 = = total I + 1 I + 2 V _ = I R 3 V _ + R = 3 47 _ 1 _ = R R total 1 _ + R 1 1 _ 1 Ω 60 + R 2 60 _ 3 ∴ R = Ω total 47 = 56 E l E c t r i c i t y a n d 1 Ω 60 R = 1 _ 1 Ω 5 20 + 15 + 12 __ V _ 2 1 + 4 total + R 1 1 + 3 1.28 M a g n E t i s M Ω the same currents branch. I correctly across calculates each the individual Ω the around IR difference component A = in total. as well as calculating it across pe e cc e potEntial dividEr CirCuit The a example potential ‘divide up’ calculate the the common circuits constant way to to the this needs after way a called by one also to be solving to the divider a divider, the does (a a circuit the from not One After to start potentiometer) power smallest supply. resistor is is (a) the pd (b) the reading resistance needs to should be be taken into signicantly account: the across has a resistance of 20 kΩ. the on 20 the kΩ resistor voltmeter with with the the switch switch open closed. 6.0 V internal 10 kΩ remains the 20 kΩ only again. V the designing going to 20 kΩ be 20 _________ (a) connected voltmeter of often When that the electrical change, is below the difference a correct circuit most involving potential are unless the the Calculate: can ratio ammeter’s of In resistors You the work An involving two battery. problems or circuit. variable the of resistor considered. current of because considered. calculations produce potential so E x amplE example approach is change your an difference the potential to is when assume ensure variable best but is taken resistance also It potential mistakes is right ‘share’ resistances resistance the divider. the voltmeter’s A on pd = × (20 potentiometer’s smaller. (b) + resistance given A potentiometer has 6.0 = 4.0 V 10) of 20 kΩ resistor and voltmeter combination, R, by: 1 1 _ 1 _ = R 1 + kΩ 20 20 3 terminals – the 2 ends ∴ and the central connection R = 10 kΩ 10 _ ∴ pd = × (10 + 6.0 = 3.0 V 10) sEnsors A light-dependent resistor (LDR), is a device whose output voltage resistance surface. In order resistor Both to R, will two both difference, the measure the V, R >> is preferred the V I circuits provide across resistance a and range and of characteristics (A of current, the B) of below readings I, for through potentiometer, an are R. this depends An on increase the in amount light causes LDR circuit decrease in on its resistance. LDR, there will be a the LDR. that (circuit shining decrease in pd across potential Providing a light When light shines on the unknown constructed. the of B) pd V total • Circuit because B allows the the range of readings potential is greater. difference across R (and When light shines on the hence the current through R) to be reduced down to zero. 10 k Circuit A will not go below the minimum value LDR, there will be an achieved increase in pd across when the variable resistor is at its maximum value. the xed resistor. • Circuit the B allows current value V the potential through R) to that be supplied can be difference increased by across up the to R the power (and hence maximum supply in A supply regular intervals. depends on a The range maximum of of values resistance obtainable of the by Circuit variable A resistor. thermistor on its have is a resistor temperature. a means negative that an Most whose are temperature increase in value of resistance semi-conducting coefcient temperature (NTC). causes depends devices a that This decrease in Circuit A – variable resistor resistance. variable resistor divider Both circuits difference of a of to these create sensor devices sensor circuit can be circuits. depends used The on in potential output an potential external factor. A V R supply When the temperature V of the thermistor increases, 10 kΩ there will be an increase in pd across the xed resistor. Circuit B – potentiometer pd V total A of the thermistor NTC increases, there will be a thermistor decrease in pd across V R supply V the thermistor. potentiometer E l E c t r i c i t y a n d M a g n E t i s M 57 re rEsistivity The resistivity, ρ, of a material is dened in terms of Exmpe its 7 resistance, R, its length l and its cross-sectional area A The resistivity 100 m of copper is 3.3 × 10 Ω m; the resistance of a 2 length of wire of cross-sectional area 1.0 mm is: l R = ρ A 100 _ 7 R = 3.3 × 10 × = 0.3 Ω 4 The units this is of the resistivity ohm must multiplied be by ohm the metres metre, (Ω not m). Note ‘ohms per 10 that metre’. invEstigating rEsistanCE The resistivity equation a) Proportional b) Inversely These a) relationships with R l has through the predicts length proportional Increasing b) to is an the Increasing can like be to l the the the resistance by another resistance R of a substance A of will be: substance cross-sectional predicted putting overall that of of area considering resistor 2R. in the resistors series. Doubling l substance. in series Doubling means l is and the doubling R. in parallel: same So R as ∝ putting l. A is with like R has putting an another overall resistor resistance in of To through practically Control the vs I resistor will be a in series. straight R in line series going parallel. Doubling Doubling A means A is the same halving R. So as R putting ∝ an identical resistor in parallel. R in 1 . A graph of R vs will be a straight line A A origin. investigate Independent R 1 . 2 going identical of origin. A R parallel an graph these relationships, variable: we Either variables: A or l have: l or A (depending on above choice); Temperature; Substance. Data Data collection: For analysis Possible sources • Temperature • The each • a • R range can Values of error/uncertainty variation of the value of be of R of independent values for calculated and the V and from variable: I the should be gradient independent recorded of variable a V vs I analysed graph. graphically. include: substance (particularly if currents are high). Circuits should not be left connected. 2 πd ___ 2 cross-sectional area of the wire is calculated by measuring the wire’s diameter, d, and using A = πr = . Several sets of 4 measurements • The small using 58 a should value vernier of the be taken wire’s calliper or diameter a E l E c t r i c i t y along the will length mean of the that the micrometer a n d wire M a g n E t i s M and the readings uncertainties in generated a set should using a be ruler mutually will be perpendicular. large. This will be improved Ee e K c' KirChoff CirCuit l aws E x amplE Great care positive an needs or alternative equal to the ∑(emf) Process to = of the whe n co ncep t of the a pp lyi ng of em f se cond pr od ucts K ir c h off ’s ( se e l aw pa g e wh ic h of c urr e nt in symbols a nd 6 0) ma y l aws as to e n su r e s ou rc es he lp of a voi d that e ver y e l e c t r ic a l c on fu s io n : term e n e rg y in can ‘R ou n d t he be an y eq u at i on used c l os e d is a l on g c o rr e c t ly wit h c ir c u it , t he V = su m id en t i ed IR of to as provide t he em fs is r e si s t an c e ’. follow Draw It helps to set • It helps to be a points full are the • Use • Identify circuit up as being diagram. the for a Kirchoff’s a and × as rst to R possible. considered law the to apply in (use currents current, loop I equations precise unknown direction emfs ta ke n T he ∑(IR) • Give be state me nt sum • • to negativ e . symbols solution identify shown substituting difference V is a numbers and difference units. between two points in the circuit so specify which two labels). Kirchoff’s senses before Potential and to mark the their equations directions will be appropriate relationships second Go law. all on the diagram. If you make a mistake and choose the wrong negative. between around the currents. loop in one direction (clockwise or anticlockwise) adding the below: emf ε With chosen direction around I I loop in the direction shown, ε and IR are both positive in the Kircho equation: chosen direction around loop ∑ R I (emf) = ∑ (IR) I (If chosen direction opposite to that shown, values are negative) • The total problem • Use • A number to be simultaneous new loop of able can different to be equations be equations generated by Kirchoff’s laws needs to be the same as the number of unknowns for the solved. to identied substitute to check and that solve for calculated the unknown values are values. correct. Exmpe Sub 6v (1) into (4) 20Ω 30i + 10(i 2 1 i ) = 5 = 5 (5) = 24 (6) = 19 = 0.1727 = 172.7 = 6 = 0.8182 = 0.08182 2 + 1 i i + 1 10i 40i 2 1 (3) × 4 120i + 1 40i 2 10Ω (6) - (5) 110i 1 i i 3 ∴ 3 i A 1 i i 2 mA 2 (3) ⇒ 10i 30i 2 1 30Ω 5v ∴ i A 2 Kirchoff 1st law junction i + i 1 C(or = 2 i D) = 81.8 = 172.7 mA + = 254.5 mA (1) 3 i 81.8 mA 3 Kirchoff 2nd law 10i and + ACDB 20i 3 Sub (1) into 10 (i ∴ 6 = 6 = 6 (2) (2) + 1 i ) + 20i 2 1 30i + 10i 1 Kirchoff = 1 2nd law 30i CEFD 10i 2 (3) 2 and = -5 (4) 3 E l E c t r i c i t y a n d M a g n E t i s M 59 ie ece c e ElECtromotivE forCE and intErnal rEsistanCE When used a 6V up some battery inside the internal charge is connected battery itself. resistance. around the circuit The is still in a circuit In other some words, TOTAL energy 6 but volts, energy the will battery difference some of this ‘perfect battery’ be internal resistance ε (e m f) = 6 V r has per unit energy is terminals of battery used from up one made For inside the terminal available historical charge battery. of by the the a energy battery chemical reasons, around The the circuit is to difference the other reaction TOTAL called in energy the is the per less unit than charge the R total battery. difference ex ternal resistance per electromotive unit force e (emf). m f = I × R = I(r = Ir = emf total However, but In an remember energy practical that difference terms, emf it is per is not a force charge exactly (measured (measured the same as in in newtons) if no current = I (R + Ir p d, V ‘lost’ volts r) CElls and battEriEs electric IR potential V An + ows. terminal ε R) volts). IR difference + battery is a = ε - Ir dEtErmining intErnal rEsistanCE device consisting of one or more cells E xpErimEntally joined together. which converts In a cell, a chemical reaction takes place, To stored chemical energy into electrical experimentally (and There are two different types of cell: primary and determine the internal resistance r of a cell energy. its emf ε), the circuit below can be used: secondary. terminal pd, V A primary cell cannot be recharged. During the lifetime of battery battery V the cell, the chemicals in the cell get used in a non-reversible terminal terminal reaction. Once electrical energy, a primary cell is no longer able to internal provide emf, ε resistance, r zinc–carbon secondary reaction reverse reused car that cell many and designed the current times. away. batteries is produces electrical battery, thrown to alkaline be Common nickel–cadmium batteries. energy the cell examples and examples recharged. electrical charges Common is The include lithium-ion chemical reversible. allowing a tnerruc A is I include it it to A ex ternal resistance, R be lead–acid I batteries. Procedure: The charge capacity of a cell is how much charge can ow before • the cells stops working. T ypical batteries have charge capacities Vary external more) are measured in Amp-hours (A h). 1 A h is the charge that a current of 1 A ows for one hour i.e. 1 A h = 3600 current terminal (and thus potential electrical difference energy) varies is with drawn time. A from Repeat readings. • Do leave a maintain however, • loses do its its not. terminal The initial pd terminal value throughout potential its of a values get of a V number and I (ideally over as 10 wide a or range Take care real current of running for too long (especially at I). that nothing overheats. cell analysis: cells, typical • The • A relevant equation, V = ε Ir was introduced above. cell: plot of V on the y-axis and I on the x-axis gives a straight quickly, line • to cell, perfect lifetime; difference not high Data would R readings possible. • • the matching C. disChargE CharaCtEristiCs When of ows as when resistance that graph with has a stable and reasonably constant value for most of its lifetime. This The is followed graph particular by below type of a rapid shows decrease the lead–acid to discharge car zero (cell • gradient • y-intercept = - r discharges). characteristics for = ε one battery. rECharging sECondary CElls In discharge characteristics order DC to power recharge source. a secondary The negative cell, it is terminal connected of the to an external secondary cell is ambient temperature: 25 °C connected 13 positive to the terminal negative of the terminal power of source the power with the source positive and the terminal 12 )V( egatlov lanimret of 11 the the secondary voltage cell. output of In order the for power a charging source current, must be 10.5 9.5A 14.3A 5.6A 3.0A than that source 9.6 33A 55A 9 charging 8 of and the the battery . cell's process A large terminal will take less difference potential time but between difference risks ow , higher secondary cell being charged 7 .6 I 7 2 3 5 10 20 30 60 2 3 5 10 I 20 power source discharge time (slightly higher pd) E l E c t r i c i t y a n d M a g n E t i s M the power means damaging + 60 to slightly 10.8 10 0 I, that the the cell. mec ce e magnEtiC fiEld linEs There the are many similarities electrostatic force. In between fact, both the magnetic forces have force been geographic Nor th Pole and shown to ar th be two (see aspects page 78). of It one is, force – the however, electromagnetic much easier to interaction consider them as A magnet free to completely separate forces to avoid confusion. move in all Page 52 introduced the idea of electric elds. A similar S concept directions would is used for magnetic elds. A table of the comparisons between line up pointing these two elds is shown below. along the eld lines. A compass is Electric eld Magnetic eld normally only free to Symbol E N B move horizontally, so it Caused by … Charges Magnets (or electric ends up pointing along the horizontal component of the eld. currents) geographic The magnetic Nor th pole of the Affects … Charges Magnets (or electric South Pole compass points towards the geographic currents) Nor th Pole − hence its name. Two types Charge: positive and Pole: North and An of … negative electric current mathematical Simple force Like charges repel, Like poles unlike charges attract unlike poles given order the to help concept of visualize eld a lines. magnetic This time eld the we, eld once lines again, are on page be seen in pole • is eld placed The – also in a direction eld called ux magnetic of the lines. eld, force is it If will shown a ‘test’ feel by a the 63. the also the cause a magnetic magnetic elds eld. The produced The eld patterns due to in different magnetic diagrams this way currents below. thumb use lines (current direction) of I magnetic of attract can In value repel, is rule: can South current North force. direction of the lines. curl of ngers • The strength of the force is shown by how close the lines are gives direction of I to one eld lines another. A ‘test’ South pole The eld lines are circular around the current. here would feel a Force here The direction of the eld lines can be remembered with the right- force in the strong since hand grip rule. If the thumb of the right hand is arranged to point opposite direction. eld lines are along the direction of a current, the way the ngers of the right close together. hand naturally Field pattern curl will give the direction of the eld lines. Overall force is in N S direction shown Force here of a straight wire because a Nor th weak since carrying cross-section pole would feel a eld lines are current into repulsion and an far apar t. current page attraction as shown. rotate N N S S current out A small with of magnet the iron eld (iron placed lines. in This lings) will the is eld how also a line would rotate compass up with until works. the lined Small eld lines pieces – of page up Field Field induced pattern Despite all to of the become an little isolated similarities bar of a at circular coil they A willbe pattern long current-carrying coil is called a solenoid. magnets. magnet between electric elds and magnetic eld pattern of elds, For • it should be remembered that they are very different. A magnet as a bar magnet does not feel a force when placed in an electric cross-section eld. • solenoid is the same example: A positive stationary • Isolated • The charge in a does not magnetic charges exist feel a force when placed N eld. whereas isolated poles do S poles of solenoid can not. be predicted using Earth itself has a magnetic eld. It turns out to be right-hand grip rule similar to that of a bar magnet with a magnetic South pole Field near the geographic North Pole as shown pattern for a solenoid below. E l E c t r i c i t y a n d M a g n E t i s M 61 mec ce magnEtiC forCE on a CurrEnt force on current S When a current-carrying magnetic interaction is as wire is between placed the two in a magnetic results in a eld force. the This N known the motor effect. The direction of this force is at I I right as angles shown to the plane that contains the eld and the current below. thumb force (F) rst nger (force) (eld) B eld (B) I F zero force second nger current (I) F (current) I force at right I θ angles to plane of N Fleming’s left-hand Experiments show rule that the force is proportional to: S current and eld • the magnitude of the magnetic • the magnitude of the current, • the length • the sine eld, B lines of the current, L, I that is in the magnetic eld F force maximum I of the angle, θ, between the eld and current. when current and The magnetic eld strength, B is dened as follows: eld are at right F = BIL B = sin θ or angles F _ IL A new sin unit, 1 1 N A θ the tesla, is introduced. 1 T is dened to be equal to 1 m . Another possible unit for magnetic eld strength is 2 Wb Since magnEtiC forCE on a moving ChargE A single force in charge moving exactly the through same way a magnetic that a eld current feels m also a feels a force. this case the force on a moving charge is proportional the the magnitude of the magnetic • the magnitude of the charge, • the velocity • the sine eld, force velocity An example the of of possible on the a moving charge this eld be is is magnetic charge the would magnetic term is always resultant when at right ux an at motion to right can electron angles density. its angles be enters below. B S of of the the charge, angle, θ, q v between the velocity of the charge electron and We of can the the use these magnetic equivalent F eld. to relationships eld the strength, previous to B. give This an alternative denition is denition F F exactly denition. N F F _ F = Bqv sin θ or B = qv sin θ An 62 E l E c t r i c i t y a n d M a g n E t i s M electron moving at right angles to a magnetic eld to circular. a velocity to: shown • Another the where In . region as Ee e ec e e c e The formulae used on this page do not need to be two parallEl wirEs – dEfinition remembered. of thE ampErE straight wirE The eld one moves weaker. • the pattern Two around away from the Experimentally value of the a long straight wire, the the eld current, is wire shows strength of the proportional that as eld of gets parallel the there to: is a it feels a the inverse distance of the away is distance doubled, away from the the magnetic the medium wire, eld r. will If a magnetic owing magnetic force. Newton’s • of current producing I current-carrying concepts The third law down eld. forces pair wires eld of the The on provide and wire, other the a good magnetic each wire wires are is wire in an example force. Because is this eld example the r l length l 1 The eld These also depends factors are on summarized in the around the 2 wire. I equation: I 1 2 B µI 1 B _ B a forces. halve. length • so of 1 = B 1 2πr F r force I felt by I 2 B 1 = B × I 1 B = field produced by × l 2 2 I 1 1 r I ∴ 1 force per unit = 2πr length of I 2 I B I 1 l 2 2 = l Magnetic eld of a straight 2 current = The constant medium µ is around called the the wire permeability changes. and Most of changes the time if B we I 1 the consider 2 I I 1 2 = r the eld around a wire when there is nothing there – so we 2πr length l 1 use the value for the permeability of a vacuum, µ . There length is l 2 0 almost no difference between the permeability of air and the I I 1 2 permeability of a vacuum. There are many possible units for this B 2 2 constant, but it is common to use N A or T m 2 A force Permeability and permittivity are related constants. In felt you know one constant you can calculate I the F B 1 2 B × I 2 if by other = words, B 1 × r l 1 1 other. B 2 In the SI system of units, the permeability of a vacuum is ∴ force per unit B = field produced by I 2 7 dened to have a value of exactly 4 π × 2 2 10 N A . See the length of I I 1 2 = denition of the ampere (right) for more detail. 2πr B I 2 l 1 1 = l 1 magnEtiC fiEld in a solEnoid = B I 2 The magnetic eld of a solenoid is very similar to 1 the I I 1 magnetic eld of a bar magnet. As shown by the parallel 2 = eld 2πr lines, the magnetic eld inside the solenoid is constant. It µI I 2 ____ might seem surprising that the eld does not vary at all inside Magnitude of force per unit length on either wire = 2πr the solenoid, but this can be experimentally veried near the This centre of a long solenoid. It does tend to decrease near The ends of the solenoid as shown in the graph equation is experimentally used to dene the ampere. the coulomb is then dened to be one ampere second. If we below. imagine amp two innitely separated by a long wires distance of carrying one a metre, current the of one equation would 7 predict not up the force possible can be to per have arranged unit length innitely with very to be 2 × long wires, long wires 10 an N. Although experimental indeed. This it is set- allows the axis forces to be measured The mathematical of long and equation ammeters for this to be properly constant eld at calibrated. the centre I I a solenoid is n magnetic field along B axis constant = µ ( ) I l field B in centre Thus the eld only • the current, I • the number of • the nature depends on: n turns per unit length, distance l (n = number of turns, l = length) It Variation of magnetic eld in a is of independent the of solenoid the core, µ cross-sectional area of the solenoid. solenoid E l E c t r i c i t y a n d M a g n E t i s M 63 ib Qe – eecc e 1. Which one of the eld patterns below could be produced by 12 V battery two point charges? A. C. B. D. a) On the correct circuit voltmeter 2. Two long, vertical wires X and Y carry currents in the and pass through a horizontal X sheet of The Y b) An are scattered on the card. Which one of diagrams best shows the pattern be (The dots show where the wires formed X and Y voltmeter allow the V-I showing and an the ideal characteristics of this [2] and why (i) cannot (ii) cannot alternative a the ammeter are connected correctly in above. Explain the potential be increased be reduced circuit potential by the (i) Draw enter for difference to to 12 across the lamp V . [2] zero. [2] measuring the V-I characteristic divider. a circuit [3] that uses a potential divider to iron the the V-I characteristics of the lament to card.) be A. symbols ammeter measured. enable lings? would circuit ideal the c) following to circuit uses lings add an card. the Iron that of same lamp direction above, positions found. [3] C. (ii) Explain why difference zero The graph lament B. this circuit across the enables lamp to be the potential reduced to volts. below lamps [2] shows A and the V-I characteristic for two 12 V B. D. potential dierence / V lamp A lamp B 12 3. This question sphere The and diagram vacuum is the about below that the motion of electric shows carries a eld electrons an in isolated negative due that to metal electric a charged eld. sphere charge of in 9.0 a nC. 0 0 0.5 1.0 current / A a) On the diagram pattern due to draw the arrows charged to represent the electric eld sphere. [3] d) State and explain dissipation b) The at electric points that 9.0 the nC eld outside sphere is strength the acts situated at at sphere as the can though its a centre. surface be the sphere determined point The of charge radius of by of a which lamp potential has the difference greater of 12 power V . [3] and assuming magnitude the for The two battery lamps as are shown now connected in series with a 12 V below. 12 V battery sphere 2 is 4.5 × 10 m. Deduce that the magnitude of the eld 4 strength An c) at electron (i) (ii) is surface initially Describe the (iii) the the surface Calculate State at the the rest path of the and of sphere on the followed is 4.0 × surface by the 10 of 1 V the electron m . [1] sphere. as it leaves sphere. initial explain [1] acceleration whether the of the electron. acceleration of [3] the lamp A electron remains decreases as it constant, moves increases away from the sphere. the electron [2] e) (i) State that (iv) At a certain point 6 6.0 × 10 between 4. In of order a 64 to lamp, the student i B the speed of how in the lamp current in lamp A compares with B. [1] is 1 m measure a P , lamp B or s . Determine point the sets P and the the potential surface voltage-current up the Q u E s t i o n s following – of (V-I) (ii) difference the sphere. electrical the [2] characteristics Use (iii) the total Compare circuit. E l E c t r i c i t y a n d V-I M a g n E t i s M characteristics current the from power the of the lamps to deduce battery. dissipated by the [4] two lamps. [2] 6 c i r c U l a r M o t i o n a n d g r a v i t a t i o n Um u m Mechanics of circUlar Motion MatheMatics of circUl ar Motion The The is phrase used going Most to ‘uniform describe around of the a circular an object circle time this at motion’ that constant also means is diagram acceleration speed. is below – constantly allows which us must to also work be out the the direction direction of the of the centripetal centripetal force. This direction changing. that situation diagram vector diagram v B the circle is horizontal. An example of change in velocity directed in uniform circular motion would be the towards centre of circle B motion of a small mass on the end of a v A string as shown below. v v B A A v + change = v A The mass moves at object has changed has changed. work of uniform circular is important to remember that the speed direction is of the changing object all the out is this the to v Since the . The two points magnitude of A and velocity B is B on a always horizontal the same, circle. but Its the velocity direction B velocities average are change in vector quantities velocity. This we vector need to diagram use is vector also mathematics shown to above. example, circle. the This is direction always of the the case average and change thus true in for velocity the is towards instantaneous the centre acceleration. constant, For its v between even of though from moving motion In It shown A constant speed Example is a mass m moving at a speed v in uniform circular motion of radius r time. 2 v Centripetal acceleration a = [in centripetal towards the centre of the circle] r 1 v m s A 1 force must have caused this acceleration. The value of the force is worked out v m s using Newton’s second law: 1 v m s Centripetal force (CPF) F = m a centripetal centripetal 2 m v ____ 1 v m s = 1 [in towards the centre of the circle] r v m s 1 For example, if a car of mass 1500 kg is travelling at a constant speed of 20 m s speed is constant but the direction is around a circular track of radius 50 m, the resultant force that must be acting on it constantly changing works Circular motion – the direction out to be of 2 1500(20) __________ motion is changing all the time F = = 12 000 N 50 This constantly changing direction means It that the velocity of the object is is really starts changing. The word ‘acceleration’ is an object’s velocity means that an object in total motion MUST be the The if the speed acceleration circular motion acceleration. the centripetal centripetal is a when it that goes centripetal in a circle. force It is a is NOT way of a new force working that out must have been. This total force must result from all the other what forces object. See point to the examples note is that below the for more centripetal details. force does NOT do any work. (Work accelerating particle called The understand = force × distance in the direction of the force.) constant. of is force nal done even to something uniform One circular on changes. on This acting used the whenever important constantly force the travelling needed acceleration in centripetal is to cause called the force e x aMples Ear th's gravitational attraction on Moon Ear th Moon R R cos θ θ F T cos θ T friction forces T sin θ R sin θ between tyres and road θ mg W A conical pendulum – centripetal force provided by horizontal component of tension. At a par ticular speed, the horizontal component of the normal reaction can provide all the centripetal force (without needing friction). C i r C u l a r m o t i o n a n d g r a v i t a t i o n 65 au u m radians Angles been angUl ar velocity, ω, and tiMe period, T measure achieved. (symbol: °) (symbol: rad) the fraction They but in is can, of studying a more of a complete course, circular useful be circle that measured motion, the in has An degrees radian measure. object travelling changing direction. changing even We dene the if in As its motion a its result speed average angle circular is constant angular turned is be constantly constantly (uniform velocity, circular symbol ω motion). (omega) as: ∆θ ____ ____________ ω must velocity = = average radius time r taken ∆t 1 The s θ distance along units The of angular instantaneous velocity angular are radians velocity is the per second rate of (rad change s of ). angle: circular arc dθ ___ ω = rate of change of angle = dt y 1. Link between ω and v v The arc fraction length s of to the the circle that has been achieved is the ratio of In circumference: a an time angle s ____ fraction of circle Δt, the object rotates Δθ s = θ = ∴ s = rΔθ r 2πr θ In degrees, the whole circle is divided up into 360° v denes the angle θ degrees) = = Δt v s ____ θ(in = as: = × = x rΔθ _ s ___ which rω Δt rω 360 2πr 2. In radians, the whole circle is divided up into 2π Link The which denes the angle θ Angle/° radians) × period ω T 2π In this time, the total r 0 0.00 5 0.09 2π ___ small angles (less ω than 0.1 rad or 5°), the arc 45 two radii form a 3. shape to a or are just a triangle. ratio, angle turned is complete 2π one radians, full circle. so: T = ω 0.74 Circular motion equations = 60 Since Substitution of the above equations into the formulae for 1.05 centripetal radians T to that 4 approximates period taken and π the time time 2π ___ = T about the = 2πr For and is Angle/radian s = time as: s ____ θ(in between radians force and centripetal acceleration (page 65) provide π the 90 1.57 = versions that are sometime more useful: 2 following relationship applies if 2 180 working in 3.14 = π 2 v centripetal radians: acceleration, a 4π r _____ 2 = = rω = 2 r T 3π ___ sinθ ≈ tanθ ≈ 270 4.71 = 360 6.28 = 2 θ 2 2 mv ____ centripetal 2π force, F 4π mr _______ 2 = = mrω = 2 r T 1. circUl ar Motion in a vertic al pl ane Uniform circular motion of a mass on the end of a string At The a horizontal plane requires a constant centripetal force the to tension the magnitude of the tension in the string will not of in the the circle:, string, T, and the weight, mg, are in the same act direction and top in and add together to provide the CPF: change. 2 mv Circular motion in the vertical plane is more complicated as top the ______ T + mg = top weight of the object always acts in the same vertical to object the will speed component the circle. the bottom tension in The its and the slow weight maximum and the of up string will that speed minimum also down acts will speed change be during along when will the the occur during its at one r direction. To The motion tangent object the is top. remain in the vertical circle, the object must be moving with due a to certain minimum speed. At this minimum top speed, v top at the The tension object’s is zero and the centripetal force is provided by min, the weight: revolution. 2 m(v ) top In a vertical circle, the tension of the string will always act at min __________ 90° mg = r to the up or object’s slowing velocity it down. so this The force does no conservation of work in energy speeding means it that: v = top 1 mgy + rg √ min 2 mv = constant 2. At the bottom of the circle:, 2 a) SITUATION DIAGRAM The H tension directions in the and the string, T, resultant and the force weight, provides mg, the are in opposite CPF: 2 mv bottom ________ T mg = bottom r r In small mass order the O m to circle complete must top of the circle. the be circle the large with vertical enough sufcient circle, for the the speed(v the object gains min PE at to = top Energetically KE object the rg ) √ (= bottom arrive mg to × at of the complete 2r) so it path must y lose the same 1 ) bottom of KE: 1 2 m(v L amount mg2r = 1 2 m(v min ) top 2 = mrg min 2 2 2 ∴ b) FREE-BODY DIAGRAM (v ) bottom ∴ v = bottom The 4gr = rg min 5rg √ min mathematics in the above example (a mass on the end of a F instantaneous string) acceleration In can place of also T, apply the for tension any in mg reaction 66 C i r C u l a r m o t i o n a n d g r a v i t a t i o n from the surface. vehicle the rope, that is there ‘looping is N, the the loop’. normal n’ 11 Universal ne wton’s l aw of Univers al gravitation If you trip over, you Newton’s theory going It of on. this is of called theory is will fall down universal the ‘universal’ statement towards the gravitation gravitation that every ground. explains because mass in The what at the the is gravitational following • The • There law all attraction the other between masses two in point the Universe. masses is The given by deals with be = 6.67 × 2 10 N m 2 kg noticed: is a force acting point on masses. each of the masses. These forces are Universe value an only should G core EQUAL attracts points constant of and OPPOSITE (even if the masses are not equal). the • The forces are • Gravitation always attractive. equation. m forces act between ALL objects in the Universe. m 1 2 The forces objects only become involved are signicant massive, but if one they (or are both) there of the nonetheless. r The m m 1 Gm 2 r below should same the spheres. In gravitational field strength table the as if the two masses be compared with the one on page 61. the example gravitational on eld the can left be F the eld g = strength the out to centres be of The be value using for the Newton’s law: 2 r gravitational the numerical = r g by… turns at GM ____ 2 Gravitational Caused masses concentrated calculated GMm _____ Symbol spherical were 2 r The between 2 F = 2 interaction m 1 F ∝ same as eld the strength at acceleration the due surface to of gravity a on planet the must surface. Masses force _____ Field Affects… One strength is dened to be Masses type of… mass force _____ Mass Acceleration = (from F = ma) mass Simple force rule: All masses attract For The gravitational eld is therefore dened as the the Earth force 24 M = 6.0 × 10 kg F per unit mass. g m = = small point test mass 6 m r = g = 6.4 × 10 m 11 test 24 6.67 × 10 × 6.0 × 10 ________________________ 2 = 6 mass m (6.4 × 10 9.8 m s 2 ) 2 F F value of g = F m 2 mass M e x aMple producing 1 In order to calculate the overall gravitational eld strength gravitational eld g at any point we gravitational 1 The SI units for g are N kg These are the same as m s strength use of is eld a vector vector strength addition. at any of both point The overall between the Earth and the Earth and . quantity and can be represented Moon must be a result pulls. by There the eld use 2 . the Field must will be a single point somewhere between lines. the Moon gravitational masses eld lines Earth, is where zero. after the Up this total to this point the gravitational point the overall eld overall pull is due pull to is towards these back the to two the Moon. beyond X overall pull is towards Ear th Moon up to X overall pull is back to Ear th Moon sphere point mass r X 1 Field strength around masses (sphere and r 2 point) gravitational eld distance between Earth and Moon = (r + 1 If resultant gravitational GM EARTH Earth _______ near surface of the Earth = zero, _______ 2 r 1 C i r C u l a r X Moon = 2 eld at ) 2 GM r Gravitational eld r 2 m o t i o n a n d g r a v i t a t i o n 67 iB Qu – u m 1. A a ball is tied vertical position. acting to a plane. Which on the string The and rotated diagram arrow at shows shows the a the uniform ball direction at of speed its the in a) (i) lowest net On to force the diagram represent position ball? above, the forces draw on and the label ball in arrows the shown. [2] [1] (ii) A b) 5. State and Determine This the question a) Dene b) The explain is whether speed about gravitational of the rotation of gravitational eld ball is the in equilibrium. ball. [2] [3] elds. strength. [2] B C gravitational eld strength at the surface of 1 Jupiter is 25 N kg and the radius of Jupiter is 7 7.1 (i) × 10 m. Derive an expression for the gravitational D eld 2. A particle uniform of mass circular thecentripetal m is moving motion. force with What during is one constant the total speed work v of in done its strength mass constant by revolution? [1] (ii) Use at M, the its surface radius R of and a planet the in terms gravitational G. your [2] expression in (b)(i) above to estimate 2 mv ____ A. Zero the mass of Jupiter. [2] B. 2 6. 2 C. Gravitational D. A particle P is moving anti-clockwise with Derive an in a horizontal diagram correctly shows the direction of v and a acceleration a of the particle P in mass The radius B. a of a c) v C. D. [3] the Earth On the A eld a value diagram satellite eld the P r = 0.33 angle mass with of is about 0.25 kg constant m. 30° for The eld at km its mass draw outside of that the orbits Earth. satellite feels circular is and surface of the lines the the is 9.8 N kg . to Earth. [2] represent the Earth. the is v to along attached a to a string and horizontal the ceiling is made circle and of to radius makes an vertical. ver tical r = 0.33 m Q u e s t i o n s – C i r C u l a r m o t i o n a n d Earth why weightless. motion. attached the Discuss P speed string with i B the below 30° 68 6400 strength a of is [2] a and v d) ball a P v rotate eld from v P A away 1 gravitational question gravitational [1] A. This the distance the shown? Calculate 4. of M. gravitational position for function the b) velocity as circle. point Which potential expression constant strength speed and 2πmv a) 3. elds 2 mv g r a v i t a t i o n is in an the gravitational astronaut inside [3] 7 ato mi c , nuclE ar and pa r t ic l E p h ys i cs E e Emission spEctra and absorption spEctra E xpl anation of atomic spEctra When In light (or an can be called a are a few a of prism light is element the light element sodium is frequencies a in diffraction present, The various an lamp the are absent an element if is For a all a emits, Exactly continuous the input the is levels the to spectrum topic This is is shone called through an absorption when it is in gaseous If be of enough a the electron for the reason can is of put is to in, an 77, without electron and can overall given energy quantized. these quantum page positive occupy be elements only See ‘escape’ now only said why part is cannot atom particular signicant nucleus. they energy Electrons the The to that happens, xed obitals. bound means ionized. are forms If this energy levels are This energy. to ‘allowed’ These correspond energies theory are (see HL 12). of When light of the ‘allowed’ same electrons model. atom. said – energy that the atom, atomic and emitted sign an the leave contains example, often lamp. If be element but This colours would frequencies question. light. grating. this light The in emits a street present its continuous, colours. from it into or not energy it were spectrum. characteristic to enough splitting spectrum, particular particular by using continuous yellow-orange the given frequencies emission only is analysed frequencies) possible its element an electron moves between energy levels it must emit form. or absorb to the energy. The energy emitted or absorbed corresponds spectrum. difference prism This (or diraction photons. grating) frequency energy is between emitted or the two allowed absorbed as energy levels. ‘packets’ of light corresponds to a of light called spectra: emission set-up slit sample A higher energy (shorter photon wavelength) of higher light. of gas The energy of a photon is given by spectral energy light emitted in joules frequency of 1 Speed lines light in in m s Hz from gas E = hf prism spectra: absorption set-up Since c = λ = fλ slit (or diraction light hc ___ Planck’s constant E grating) 34 6.63 source × 10 J s spectral Wavelength in m lines sample of gas all frequencies Thus the frequency of the light, emitted or absorbed, is xed (continuous spectrum) by sodium 330 415 420 569 the levels 590 6 15 energy are emission 334 365 366 398 405 389 helium 319 36 1 37 1 382 546 to the a given the element, absorption) levels. this spectrum Since means will also the that be energy the unique. 579 403 396 384 436 unique (and between ygrene mercury 313 difference 412 439 447 47 1 492502 588 668 397 hydrogen 380 389 410 434 486 656 allowed energy wavelength, λ 300 310 / nm 320 330 levels 340 350 360 370 380 390 400 450 500 550 600 650 700 yellow approximate colour blue orange invisible (IR) Emission spectra sodium 330 415 420 569 365 366 398 405 389 helium 319 36 1 37 1 382 436 546 frequency absorbed ygrene 334 photon of pa r ticular energy level to higher energy level 590 6 15 mercury 313 electron ‘promoted’ from low 579 403 396 412 439 447 47 1 492 502 588 668 allowed 384 397 hydrogen 380 389 410 434 486 656 energy levels wavelength, 300 310 λ / nm 320 330 340 350 360 370 380 390 400 450 500 550 600 650 700 yellow approximate colour blue orange invisible (IR) Absorption electron ‘falls’ from high photon of pa r ticular energy level to lower energy level frequency emitted spectra A t o m i c , n u c l e A r A n d p A r t i c l e p h y s i c s 69 ne isotopEs When a electrons different outer nuclE ar stability chemical of the properties of a of takes properties varies that protons. from because element in the general, it involves Different element exists In place, concerned. particular charge number atoms chemical electrons positive reaction the to are elements xed nucleus outer have arrangement element. different the – by in The the atomic decay is words, of the The numbers imply name given contains of different a to a particular specied neutrons). chemical Some properties. species number of nuclides of atom protons are the A nuclide (one and same a alpha of of same chemical properties and is the nuclides same These number nuclides of are protons called but isotopes different – whose – same they numbers (α), decay beta particular that For small the number (β) The (see or gamma nuclide present. process page The (γ) depends graph by 72). It which they involves radiation. greatly below on shows the the exist. nuclei, • For large • Nuclides of of the number of neutrons tends to equal protons. nucleus nuclei there are more neutrons than protons. number they above the band of stability have ‘too many have number contain and will tend to decay with either alpha or beta of decay protons. unstable. the specied element contain a neutrons neutrons’ the are radioactive structures • will of stability stable nuclei called emission chemical amount other nuclear of Many (see page 72). the neutrons. • Nuclides below neutrons’ N ,rebmun nortuen notation mass number – equal to number of nucleons A chemical symbol and the will band tend of to stability emit have ‘too few positrons (see page 73). 160 150 140 130 120 Z 110 atomic number – equal to number of 100 protons in the nucleus Nuclide notation 90 80 E x amplEs 70 Notation Description Comment C carbon-12 isotope of 2 C carbon-13 isotope of 1 60 12 1 6 13 2 50 6 238 3 U uranium-238 Pt platinum-198 40 92 198 4 same mass number 78 30 as 5 198 5 Hg mercury-198 same mass 20 number 80 as 4 10 Each element atomic number. whereas In has No.4 general, concerned Chemists a No.1 and use chemical No.2 are use nucleus same are symbol examples and of its two own isotopes, 0 not. physicists the the and No.5 when with unique this rather notation notation than but the tend to they 10 20 30 40 50 60 80 atom. include the represent the Key 12 overall charge on the atom. Thus C can 6 carbon nucleus to a physicist or the N carbon atom to a on the context. If the charge is present becomes unambiguous. Cl must refer number of of neutrons protons the 35 situation number chemist Z depending to a ■ naturally occurring stable ● naturally occurring α-emitting nuclide ○ articially ▲ naturally ▵ articially produced ▿ articially ▼ articially ▼ articial chlorine 17 ion – an atom that has gained one extra electron. produced occurring nuclide α-emitting β -emitting nuclide nuclide + 70 A t o m i c , n u c l e A r A n d 90 100 atomic number, Z are whole 70 p A r t i c l e p h y s i c s β -emitting nuclide produced β -emitting nuclide produced electron-capturing nuclide decaying by nuclide spontaneous ssion fe e strong nuclE ar forcE The protons repel, they means a nucleus must there together. few in be must things about repelling be Without are it this positive. one another the WE ak nuclE ar forcE all another force nucleus Since all keeping would ‘y like the the charges time. The This do nucleus apart’. We It must be a force. strong. If the proton repulsions are calculated it that is far too It must the gravitational small to be able attraction to keep between the nucleus the force be very short-ranged anywhere other than as we inside do the not It is likely tend to Large to The to involve have nuclei keep name the equal need to neutrons of force aspects as together. observe well. more • force is things It strong neutrons nuclear in • order standard that we that have observe (above). been As fundament These detail model are a on information daily in (or Gravity, all a particle identied result forces about of along being two is with that force on around the in two It must are and interactions to Weak. page 78. is have is the force of attraction between all be • forces is attractive – masses are we alpha wish beta to but be able emission. and another to We explain know a force: Many nuclei are stable and beta emission short-ranged other than as we inside do the not observe this nucleus. name ones given nuclear electrons, to (e.g. this force, it positrons protons force is involves and and the the lighter neutrinos) as well as neutrons). weak nuclear force This single force as includes either all the electrostatic forces or that we normally magnetic. • Electromagnetic forces involve • Electromagnetic forces can • The range • The electromagnetic charged matter. be attractive or repulsive. exist. More below: objects pulled if including explain identied four Outline listed heavier of imbalances • that At the end the of electromagnetic of force charges forces electrostatic always involved to be nuclei nuclei, occur. strong (e.g. categorize mass. Gravity very the different • weak. always signicant Gravity can why Most Electromagnetic forces Gravity • 72) stable. stability only known this anywhere Unlike The the ‘new’ nuclear there are Strong discussed ‘everyday’ based model, interactions) forces is involved standard Electromagnetic, these about basis as the physics be not particles othEr fundamEntal forcEs/intEractions The be nucleus about must the the Mechanisms page explains are nuclei neutrons. together. this must the left) they this • Small and of (see box why nucleons nucleus. protons proportionately nucleus given the numbers unstable. nuclear (see thus is force • are force and emission does • nuclear apart gamma few clear y however, know all • strong not on the force aspects on the 19th and of is an relatively atomic laboratory century, the the force innite. strong level – give tiny rise to scale. Maxwell magnetic more is showed force were fundamental that just the two electromagnetic together. force. • The • Despite range of the gravity force is innite. • the above, the gravity force is relatively quite The mathematics Maxwell’s At least one of the masses involved needs to be large for to be noticeable. For example, the gravitational attraction between you and this book is negligible, but (drop between this book and the Earth is easily Friction (and of The Newton’s law governing of this gravitation describes the is described by the many force other ‘everyday’ between atoms forces) and this is is simply the governed by the interaction. demonstrable it). electromagnetic considered • force the electromagnetic force electromagnetic force result of the equations. the • effects of weak. to be force aspects and of the the weak single nuclear force electroweak are now force. mathematics force. particlEs that E xpEriEncE and mEdiatE thE fundamEntal forcEs. See page 78 summarizes onwards which for more particles details about experience the these standard forces and Gravitational Particles experience All model how mediate Graviton W the are Weak Quark, fundamental structure of matter. The following table mediated. Electromagnetic Gluon + Particles for they Charged Strong Quark, Gluon 0 , W , Z A t o m i c , Gluon γ n u c l e A r A n d p A r t i c l e p h y s i c s 71 r 1 ioniZing propErtiEs Many atomic process by which radioactive involves are they decay. the different nuclei possible decay Every emission EffEcts of radiation unstable. of is The At called decay one radiations of molecular the complex alpha (α), beta (β) ionization as DNA ionization chemical in or the reactions could RNA. cause This surrounding (called damage could medium metabolic directly cause is it to to enough pathways) a cease to biologically functioning. interfere taking with place. damage can result in a disruption to the functions that are taking place or within gamma an an such the Molecular nucleus: level, molecule Alternatively, three from the important the cells that make up the organism. As well as potentially causing the cell (γ). to die, could this be could the just cause prevent of the cells from dividing transformation of the and cell multiplying. into a On malignant top of this, it form. α As all body systems tissues that have are built been up of affected. cells, The damage to these non-functioning can of result these in damage systems can to the result body in death β for the animal. If malignant cells continue to grow then this is called cancer γ radiation s afEty Alpha, the All beta and gamma all come from There nucleus three means that radiations that substance, electrons as they are go collisions to be ionizing. through occur removed from should This a which There cause that have lost or be called ions. This the radiations to be as explains Run their ionizations detected. dangerous occur in molecules, can be dose terms ways of of an of ionizing extra the dose radiation. (for information protecting oneself Any example received from or too hospital having the large an procedures X-ray benet a dose. it scan) gives. These can be follows: away! simplest method you and and of the reducing source. the Only dose received is electromagnetic to increase radiation the can distance travel this follows an inverse square relationship with large distance. nature. Don’t waste time! biologically such as you have to receive a dose, then it is important to keep the time of this DNA, exposure function safe It If important in main a property • When as receiving electrons distances also thing patient three between allows a atoms. gained ionizing such in justiable are The are no summarized • Atoms is result to a minimum. affected. • If you can’t Shielding also be run can used away, always to limit hide be the used behind to something! reduce exposure for the both dose received. patient and Lead-lined aprons can operator. propErtiEs of alpha , bEta and gamma radiations Property Effect Alpha, on photographic lm α Beta, Yes 4 Approximate ion pairs number produced in of β Gamma, Yes γ Yes 2 10 per mm travelled 10 per mm travelled 1 per mm travelled air 2 Typical absorb material needed to 10 mm aluminium; piece of A paper few mm aluminium 10 cm lead it Penetration Typical ability path Deection Low length by E in and B air A elds few Medium cm Behaves Less like a 7 Speed About 10 positive charge High than Behaves like 1 m one a 8 s About 10 m Effectively negative charge s atomic numbers and the very variable mass balance on each side of 10 Y (Z the + e.g. 1 m s 0 → + β 1) + ν 1 90 gamma dEc ay × A X Z numbers deected 3 8 , A The naturE of alpha , bEta and Not 1 m innite 90 Sr → 0 Y 38 + β 39 + ν 1 equation. When a nucleus decays the mass • (95 numbers and the atomic numbers = 93 + 2 and 241 = 237 + Gamma rays are unlike the other two 4) must radiations in that they are part of the 0 balance on each side of the nuclear • Beta particles are electrons, β electromagnetic spectrum. After their 1 0 equation. or e , emitted from the nucleus. emission, the nucleus has less energy 1 4 • Alpha particles are helium nuclei, The explanation is that the electron is α but its mass number and its atomic 2 4 or formed 2+ He . In alpha decay, a when a neutron decays. At the ‘chunk’ number have not changed. It is said to 2 same of the nucleus is emitted. The time, called that remains will be a an 0 1 1 4) → + 2) 241 e.g. α Since 2 237 Am → 95 + 4 Np 93 + an virtually + mass it A t o m i c , does no not charge affect α A n d p A r t i c l e p h y s i c s energy → Z has an + Z Excited Lower state state excited state. 0 X and the from A X 2 n u c l e A r lower ν 1 antineutrino no a changed A β 1 have to 0 p equation. 72 emitted 4 Y (Z is antineutrino. n → (A X Z particle different nuclide. A another portion γ 0 energy state r 2 antimattEr The nuclear One mode l important existence of given thi ng on tha t antima tte r. is p ag e not Eve r y 77 is s ome wha t me n ti on e d fo rm of t he r e matter si m p li ed . is has the and the antimatte r it s 1 1 p → form of a nti ma tter. If ma t t e r an d a n t im at t er 0 n 1 equivalent + a nnihi l ate e ac h oth e r. N ot e le c t r on , a p os it r on , is + ν +1 19 → 0 F 10 woul d an + β 0 Ne they of c am e 19 together v e r s io n emitted. + + β 9 + ν +1 s ur pr is i ng l y, + antimatter form of is rare b ut radioactiv e positron decay. In it do e s d e ca y thi s ex is t. tha t de ca y Fo r ca n a e xa m p le , t a ke pr oton pla ce is de c a ys The positron, The antineutrino into a pl u s or decay all you measured that take in in (Bq) a natural time. terms place becquerels is the of a The the unit with 1 phenomenon activity number of time. Bq = more Some background radiation around 1 of This of any and is given individual nuclear decay going is per α, on source nuclear information , emission is the are is cosmic and γ taking identies decays quoted β value in details see gamma radiation place in typical varies page counter, this which would detects be and measured counts the using a number accompanied form of by a the neutrino. neutrino. rays will received the be as a responsible, result surrounding sources from 78. of country of to country but The radiation, and there radioactive materials. background from pie but place will also decays chart the to be that below actual place. second. food Experimentally is antimatter ne ut r on , For Radioactive β a no t h er be t a medicine nuclear industry Geiger of ionizations buildings/soil radon taking will place always inside detect the GM some tube. A radioactive working Geiger ionizations counter taking place cosmic even when there is no identied radioactive source: there is a medicine – 14% background A reading detector of count 30 as counts registering a result per 30 of the minute, ionizing background which events, radiation. corresponds would not be to nuclear industry – 1% the unusual. buildings/soil – 18% To analyse necessary the to activity correct of for a given the radioactive background source, radiation it is cosmic – 14% taking place. natural It radiation radon – 42% would be necessary to record the background count without the 85% food/ radioactive source present and this value can then be subtracted drinking water – 11% from all readings with the source present. start random dEc ay Radioactive external a sample This of means particular time. All decay is conditions. a random For radioactive that is nucleus we material there is know no going is process example, the way to does of of not is within a not the affect knowing decay chances and increasing decay a affected by temperature the rate whether certain of or period happening in of decay. not a to sample, we On average the of time. atoms of a the process is random, the large numbers of rate in decay certain Mathematically Although number in the would atoms radioactive of given decay the number a that with number is of next expect of decay the an is the of a sample. then N, If sample This can expect were decaying is to be proportional process. The a more proportionality decreases expressed we there number exponential element, this atoms minute. certain atoms to the means number exponentially in larger. that of over time. as: atoms dN ___ involved allows us to make some accurate predictions. If ∝ we - N dt A t o m i c , n u c l e A r A n d p A r t i c l e p h y s i c s 73 h- e half-lifE There is a decreases with exponential In of the we decay choose. is an is in a that every exponential a particular below, the always This happening think have shown to to allows time the us property decrease, that taken for half whatever express called the the In but mathematical same, to quantity property. the several number starting chances half-life, T1. life six of of of nuclides statement decay (or nuclide present is that substance can vary with with from in the activity) substance is a a time sample half-life of a the a taken to is short fractions of a half An time taken of takes long will a decay second to the number for the nuclides time quickly. millions of rate to to times. a A is days. In will working a matter common radioactive reality, remain, i.e. a how six is much applying mistake material after out of 3 is to days days the think then (two radioactive half-life it that will half-lives) if all a property the half- decay ‘half of in a quarter. increase of stable 1 equivalent sample half-life half-life decay. the particular large for situations, remains decay of radioactive of ‘daughter ’ nuclei ‘parent’ nuclei halve. decay. nuoma A a of half’ The 2 half-life simple material ecna decay time curves graph nuclides value E x amplE temptation A Half-lives after 2 half-lives years. 3 yaced ot elbaliava sedilcun fo rebmun 4 1 number = x N after 2 half-lives 2 0 1 of the original The time taken to halve from parent’ nuclei will remain 4 T1 any point is always T1 2 2 (x) x number = N 3 1/2 6 time / days 12 9 2 x The decay of parent into daughter 2 14 e.g. The half-life of C is 5570 years. 6 N 1/4 Approximately N how long is needed before less than 1% of a 14 1/8 sample of C remains? 6 N 1/16 T 1 T1 T1 2 Fraction T1 50% left T 1 time 2 Time 2 2 2 half-life 25% 2T 1 2 Half-life of an exponential decay 12.5% 3T 1 2 4T 1 ~ 6.3% ~ 3.1% ~ 1.6% ~ 0.8% 2 invEstigating 5T 1 2 half-lifE E xpErimEntally When measuring the activity of a source, the background rate 6T 1 2 should be subtracted. 7T 1 2 • If the half-life activity → A the against simple normal could be method → A is of from of readings activity exponential simple graph then can be taken of 6 half lives 7 half lives ln the and against shape. graph quick (activity) time Several and but against values then not the time would should of half-life averaged. most ∴ approximately give calculated If the half-life a from is straight line and the could decay be produced. constant over a way to the gradient. See page result used long, then the activity will period of time. In this case calculate the number of nuclei effectively one needs present, N, available to throw of a die radioactive and A n d six to decay. Each represents nd no longer then -λN. n u c l e A r the simulate Every dt A t o m i c , of is a random decay. The process dice and can represent throw represents a unit of be dN ___ 74 to 217. use = years needed simul ation is a 38990 years can time. constant = 37000 This nuclei • years accurate. be be 33420 produce The This = time. graph read is short, p A r t i c l e p h y s i c s available. a nucleus decaying meaning this die ne e artificial transmutations There is nothing that we can do to units change the likelihood Using Einstein’s equation, 1 kg of mass is equivalent to 16 of a certain conditions be done particle we by or articial rst radioactive can decay make nuclear bombarding another a small the nucleus In incoming but reactions with nucleus. transmutations. ‘captures’ happening, a Such and happen. nucleon, reactions general, object under the an This an are target then certain 9 can × the alpha 10 J atomic useful. called of energy. scale The This other are nucleus a units electronvolt megaelectronvolt is of (see often huge amount energy page tend 53), or of to energy. be more At more usually, the used. 19 1 eV = 1 MeV 1 u 1.6 × 10 J emission 13 takes out place. by alpha The rst Rutherford particles ever in and articial 1919. the transmutation Nitrogen presence of was was bombarded oxygen was = 1.6 × 10 J carried of mass converts into 931.5 MeV by detected Since spectroscopically. work mass in and units energy that are avoid equivalent having to it do is sometimes repeated useful to multiplications 2 4 14 2+ He + 17 N 2 → 1 O 7 + by the (speed of light) . A new possible unit for mass is thus p 8 1 2 MeV The mass numbers (4 + 14 = 17 + 1) and the atomic c . It works like this: numbers 2 If (2 + 7 = 8 + 1) on both sides of the equation must 1 MeV c worth of mass is converted you get 1 MeV worth balance. of energy. unifiEd ma ss units WorkEd E x amplEs The individual masses involved in nuclear reactions are Question: tiny. In order unied mass common in the to compare units, isotope u. of carbon-12 atomic These carbon, atom (6 are masses dened carbon-12. protons and physicists in terms There 6 often of are the 12 neutons) use most How nucleons and one much decayed 14 mass unit is dened as exactly one twelfth the energy shown 14 C → would in the be released equation if 14 g of carbon-14 below? 0 N 6 unied as + β 7 + ν 1 mass Answer: of a carbon-12 atom. Essentially, the mass of a proton and the Information mass of a neutron are both 1 u as shown in the table 1 ___ 1 u 27 = mass of a (carbon-12) atom = 1.66 × given below. 10 atomic mass of carbon-14 atomic mass of nitrogen-14 = 14.003242 u; kg 12 mass* of 1 proton = 1.007 276 = 14.003074 u; u mass mass* of 1 neutron = 1.008 665 u mass* of 1 electron = 0.000 549 u of electron = 0.000549 u 14 mass of left-hand side = nuclear mass = 14.003242 = 13.999948 = 14.003074 of C 6 * = Technically these are all ‘rest masses’ – see option 6(0.000549) u 7(0.000549) u A u 14 nuclear mass of N 7 ma ss dEfEct and binding EnErgy The table above shows the masses of = neutrons and mass It should be obvious that if we add together the masses of right-hand side = protons, bigger gone what 6 than neutrons 12 wrong? keeps u, the The the and 6 mass answer nucleus electrons of a becomes bound we will carbon-12 clear get atom. when a difference = mass has of difference its between component the nucleons assembling a mass is u 13.999780 LHS u RHS investigate of called a nucleus the mass and the nucleus, the protons defect. and released per decay = 0.000168 u = 0.000168 × = 0.156492 MeV 931.5 MeV masses If one 14g imagined 0.000549 together. energy The + number What we u 13.999231 of = 6 13.999231 protons. of C-14 is 1 mol neutrons 23 would initially need to be brought together. Doing this ∴ takes Total number of decays = N = 6.022 × 10 A work because the protons repel one another. Creating the bonds 23 ∴ between the protons and neutrons releases a greater Total energy release = 6.022 = 9.424 × × 10 10 = 9.424 × 10 = 1.51 ≈ 15 × 0.156492 MeV amount 22 of energy than the work done in bringing them together. MeV This 22 energy released must come from somewhere. The answer lies 13 × 1.6 × 10 J in 10 Einstein’s famous mass–energy equivalence relationship. 2 ∆E = × 10 J GJ ∆mc NB Many examination the masses calculations avoid the need to consider 1 energy in joules mass in kg speed of light in m s mass In is Einstein’s possible The binding when It a be convert energy nucleus comes also equation, to from the a nucleus a measure a is of is its the is that the in individual from mass. to of its of energy energy energy and that component The be form into amount needs binding another directly assembled decrease energy into mass mass binding added nucleons. in The is the opposed electrons to the by atomic providing you with the nuclear mass it versa. released nucleons. energy order mass and vice as of to would separate defect is thus energy. A t o m i c , n u c l e A r A n d p A r t i c l e p h y s i c s 75 f fission Fission nuclei is energy in reactors involve can the are the and A 1 atomic the + is a the nuclear into A typical to might + single break is and used in reaction with up whereby nuclei a Since in nuclear two the the chain might neutron. into large release the This one original production reaction neutrons reactions, to but of is causing neutrons, occurring. lose it neutron three It enough is the there reaction is technically energy to go the quite on has resulted possibility difcult and initiate of to a get further achievable. smaller be: 92 Ba 1 Kr 56 that nucleus nucleus reaction smaller reaction uranium 141 92 the up bombs. reaction U → 0 It uranium typical to break process. 235 n given to bombarding cause nuclei. name induced + 3 36 n + energy 0 Ba141 n U-235 Kr-92 A ssion reaction A fusion Fusion is nuclear are name reaction to nuclei process. reaction binding EnErgy pEr nuclEon the induced larger chain It join the to whereby and is given the small together release reaction Whenever nuclei into energy that in reaction of the ‘fuels’ this a are nuclear in energy. calculate nucleus the a reaction lower In order binding divided by to state compare energy the (ssion energy total per or fusion) than the the energy nucleon. number of releases reactants. This states is the nucleons. of energy, Mass different total One of the loss be nuclei, binding the products must the source physicists energy nuclei of the with for the the largest 56 all stars including the Sun. A typical binding energy per nucleon is iron-56, Fe. 26 reaction that is taking place in the Sun A is the fusion of two different reaction hydrogen 3 H + 1 to produce 4 H → 1 1 He + 2 n + feasible if the products energy per nucleon when compared of with the the reaction have a greater reactants. helium. VeM / noelcun rep ygrene gnidnib 2 energetically isotopes binding of is energy 0 hydrogen-2 helium-4 fusion hydrogen-3 iron-56 10 ssion energetically possible 8 6 4 fusion energetically 2 possible neutron nucleon One of the fusion reactions happening 20 40 60 80 100 120 140 160 180 200 number in the Sun Graph 76 A t o m i c , n u c l e A r A n d of binding p A r t i c l e energy per nucleon p h y s i c s se e introduction All or matter that otherwise, is combinations hundred, present type in form elements symbol; the or made of so, atoms. a name has There are types of and the living a the The different a Each hydrogen, elements, us, of Atoms element. has e.g. up different nature. an atomic modEl surrounds of only a chemical chemical of and in all is the atom the negative called in at must good all the – known a a energy nucleus. vacuum. to the All an The nuclear small levels. The Overall evidence as very nucleons). charge. nothing be model, describes different (collectively these simplest atomic century arranged atoms single of basic last central The of Oxygen The has the combination with one oxygen molecule H O. chemical of two atom nucleus The called full list itself contains positive charge electrons provide only atom is nuclear support neutral. model The of the developed surrounded a and tiny vast bit of seems of so and all the the electrons protons almost majority atom during by the neutrons mass mass the but of all volume strange that of is there it. symbol symbol hydrogen is was the Protons H. model, nucleus a of Neutrons Electrons 1 Negligible O. Relative atoms water mass 1 Charge Neutral +1 1 elements 2 is shown consist in of protons, a a periodic table. combination neutrons and of Electron ‘clouds’. The positions of the 6 electrons Atoms three are not exactly known but they are most likely to things: nucleus be found in these orbitals. The dierent orbitals electrons. correspond to dierent energy levels. m cell m DNA protons nucleus Atomic model of carbon atom This so In the basic atomic model, we are simple orbital protons, nothing neutrons, and has limitations. should Accelerated constantly lose charges energy (the are known changing to radiate direction energy means the made electrons upof model electrons electrons are accelerating). – more. E vidEncE One of the most experiment. most of them detectable huge law existence were The of of alpha pieces within to the mathematics repulsion isotopes of particles expected structure angles. square convincing Positive from travel gold of the provides evidence were straight atoms. the for ‘red’ at evidence a The gold the amazing for model leaf. gold that of The leaf. discovery showed Evidence for nuclear thin through experiment nucleus. the The was numbers electron the energy atom relative idea that comes size and behind some of from this the being deected levels comes the velocity Rutherford–Geiger–Marsden of the experiment alpha at from any alpha was particles given emission to were angle and particles see if meant there deected agreed with absorption was that any through an inverse spectra. The neutrons. positive nucleus vacuum 1 in 8000 par ticles gold foil target ‘rebound’ gold screens 8 about 10 m thick from the foil. atom beam of most pass α-particles source of straight θ α-particles stream of through α-particles positive α-particle detector about 1 in 8000 some are deviated is repelled back through a large deected by nucleus NB not to scale. Only a minute percentage angle θ of α-particles are scattered or rebound. Rutherford–Geiger–Marsden experiment Atomic explanation of Rutherford–Geiger–Marsden experiment A t o m i c , n u c l e A r A n d p A r t i c l e p h y s i c s 77 de e cl a ssific ation of particlEs consErvation l aWs Particle Not many, accelerator many classes of leptons whereas were of of the These particles. were ‘light’) Protons and the into mesons are in between the the the (= hadrons (linear no baryons. of Another are out called elementary structure, of smaller elementary mediation of the be baryons that is, reactions if they are have of not are The quarks, not two strong boson, Combinations particles. always, after a a On were collision to of these broken a number the reactions – 1) that conrmation charge, the ‘baryon the laws law of the same. A laws there conservation number’ then of momentum fundamental e.g. of always of simply physicists assigned was study conservation were top never baryon number suggested of 1 total (and number similar law of applies. new such is also an of Another elementry elementary composite particles. properties. composed of particles, and different combinations there are three particle properties of inside all quarks. mesons of to one whether their that always is in conserved weak in all ‘charm’ were are often, examples electromagnetic and interactions. they and are the elementary various or composite, quantum numbers can that be specied are related in to laws that have been discovered. The quantum numbers the that particles are include: charge, property strangeness, is not the charm, same as an lepton object’s number, actual baryon colour – number see page and colour 79). Inside (or there mass identify electric particle has its own antiparticle. An antiparticle has the same mass as three is particle but all its quantum numbers (including charge, etc.) are opposite. one There and not and are its antiquarks); Strangeness but ‘Strangeness’ are hadrons quarks reactions. particle, Every baryons in particle. particles All conserved interactions, (this quark and were baryons laws known mass-energy. assigned lepton these already that The classes • all all of possible. experimental leptons used called were are some or they constituents. particles exchange Higgs of to Some rules If were before particles rise and other number. conservation the that angular) to conservation terms and and gave physics. laws antibaryons All of particle baryon all between place bosons’. internal made to appeared but Particles take conservation Other ‘exchange reactions did applied particles. bosons all that hadrons and involved gauge are baryons. is called – The interactions were original hadrons leptons. neutrons particles Two neutrons are identify identied and and electrons subdivided Protons class particles (= ‘heavy’). ‘new’ experiments are some particles (e.g. the photon) that are their own antiparticle. antiquark. thE standard modEl – lEptons There are six different leptons and six different antileptons. The Electric six leptons are considered to be in three different generations ‘Generation’ or charge 1 families three The in exactly different electron the same generations and the way of electron that quarks there (see neutrino are considered page have to ν 79). a number Similar 1 to a muon family example, The lepton principles the Lepton For have +1. are and antielectron (electron used the number whenever to tau is a family) assign family also and lepton is antimuon number of neutrino leptons in must the also muon of 1. neutrino) neutrino) M M M almost numbers of +1 or = 0 are only four in created, be all an created family almost 0 = 0 or = 0 or almost 0 0 e μ (electron) (muon) (tau) M M M τ 1 reactions. antimuon = 0.511 or is so that always the interactions = 105 2 = 1784 2 c MeV MeV c total that exist: Gravity, for greater which the it mass can of exist. the The exchange range of particle, the weak the smaller interaction + Electromagnetic, All four interactions exchange particle the Strong of or can particles. particles. smaller the and be Each The range of as Weak. thought of as interaction bigger the the force being has mass its of mediated own the MeV 2 c conserved. The fundamental or members. E xchangE particlEs There τ (tau-neutrino) MeV an ν μ (muon- antielectron number conserved muon the ν (electron(electron notpeL neutrino of 3 e lepton 0 family) 2 be by an exchange exchange boson, In the masses particle disappear virtual by out is between its exchange physics, surrounded particles concerned. of a of all the inversely two real cloud in Interaction particles virtual proportional takes one place cloud is (W can W be their when Z thought The by ) are of as appear or The being of these interaction more the large. and lifetime mass. one absorbed and that vacuum. to of other the particle. Relative Range Exchange Particles strength (m) particle experience 8 Quarks, different 15 Strong 1 ~10 gluons gluons photon Charged 2 The exchange results in repulsion between the two Electromagnetic 10 Weak 10 innite particles + W 13 From the needed as the than to of create energy is 78 point of view these the proscribed of quantum virtual particle by the A t o m i c , mechanics, particles, does not uncertainty ∆E exist is for a longer (see A n d 0 , W , Z so lepton long time page Quarks, 18 ~10 energy available principle n u c l e A r the 39 Gravity 10 innite graviton All ∆t 126). p A r t i c l e Leptons and p h y s i c s time small 0 , particles surrounding particles particles of particles the is bosons are unaffected by the strong force. Q Isolated standard modEl – Quarks The standard that six all model matter types of accepted is particle considered quark theory. fundamental, of and six Each which of to be types these means physics the composed of lepton. particles they is do not of This is theory is the any threes. says combinations to quarks three Gravity is not explained by the are exist. made whereas quarks all hadrons are made up particles from called different quarks. standard are quark and six types of antiquark. This very all up of in twos quark a and or an combination of antiquarks). be Name of particle proton (p) Quark u u d u d d six u d s u u d (pi-minus) d u (pi-plus) u d (K d s (n) structure of different Λ types antiproton of made or only (a model. combinations There are exist quarks deeper lambda fundamental can two quarks neutron All They from baryons (either Baryons structure. cannot Mesons antiquark) of currently considered have that neatly matches (p) the - Mesons six leptons that strong force are also known to exist. Quarks are affected π by + π the (see below), whereas leptons are not. The weak 0 K ) zero interaction Electric can change one type of quark into another. The ‘Generation’ the charge 1 2 force full between description u c t (up) (charm) (top) the 2 e 3 2 = 5 MeV 2 c this is still the strong interaction M = 1500 MeV chromodynamics. quarks green M of is interaction termed QCD but theory – 3 quantum + quarks (g) is or a property blue (b). The called quantum colour. Antiquarks can All be difference quarks antired between can ( r), be red (r), antigreen ( g) 2 c M = 174 MeV c or d s b (down) (strange) (bottom) antiblue because ( b). they The have two up quarks different in a proton are not identical colours. 1 - e Only 3 skrauQ 2 M = 10 MeV 2 c M = 200 MeV white (colour neutral) combinations are possible. 2 c M = 4700 MeV c Baryons must contain r, g and b quarks (or r, g, b) whereas 1 All quarks have a baryon number of + mesons contain a colour and the anticolour (e.g. r and r or b 3 and 1 All antiquarks All quarks have a baryon number of a strangeness number of 0 colour except quark The all c that quark other has is a strangeness the quarks only have quark charm number with a of of interaction colour between objects with interaction and is chromodynamics. The force-carrying There are gluon carries eight different explained types of colour by a is number gluon each force. details = quarks is sometimes Eight different types of gluon of QCD do not need to be combination of colour and the mediate it. recalled. called is the zero rather gluon. mass. Each Isolated sufcient isolate quantum called with If the The a energy quark, than six quarks is then isolated and supplied more gluons a This is gluons cannot hadron hadrons quarks. colour-changing to or in known anticolour and are: G be order mesons as will , G r g observed. to be quark , G r b a called +1, increases. called theory particle between 0. Quantum chromodynamics (Qcd) The force 1. charm number The the The s etc.) - 3 have b, attempt to produced connement. , G b g , G br , G g b gr their For example when a blue up quark emits the gluon G it loses br emission and absorption by different quarks causes the colour force. its As the gluons interaction The themselves between overall effect is are gluons that coloured, themselves they bind there as will well quarks as be a colour between together. The blue colour antired, quarks. so absorbing and red this becomes colour gluon must will a red be up left become quark behind). a blue (the A gluon red down contains down force There are two additional colour-neutral gluons: G and 0 between quarks increases as the separation between b g G , 0 quarks making r quark quark. g b a total of r eight gluons. b g r u u G G + π G G rb G gb G gb rb G 0 bg gr b p u d r b g g G b G rg rb d g strong intEraction The colour the same interaction thing. fundamental and Properly, force mesons. It is interaction is the as the effect is a proton of the particles considered that and that quarks binds together all between strong The are is in a the into The in the of can composite In addition in the (such boson. which and an This the with nucleons detection the predictions a generations there additional Large of three model was particles overall nucleons. to standard boson strong particles colour-neutral interaction exchange baryons nucleus. quarks essentially the residual colour-neutral together the the interaction interaction gluons. between interaction involve strong colour by neutron) mediating to the binds force b higgs boson the mediated interactions short-range The and r Hadron the in acquire particle for highly proposed can are mass. Higgs that of leptons four massive 1964 Collider that the to In boson, explain 2013 of quarks gauge the the the the Higgs process scientists announced matched and classes by working experimental standard model’s boson. be particles + (π mesons: interaction π is , π or always π°) whereas seen as the the fundamental exchange of colour gluons. A t o m i c , n u c l e A r A n d p A r t i c l e p h y s i c s 79 fe Some rulEs for draWing fE ynman diagrams Feynman diagrams interactions. probability of mechanics, which an in interaction, in The is be used diagrams are interaction order it an can to nd necessary interaction represent used taking out to can to take calculate place. the add to possible In overall together place. the particle • overall in quantum Used the of an possible properly and as a tool simple for calculations pictorial model but, of at this possible level, • Exchange are a the going Feynman from books way, left reverse turn diagrams to right these the page below and two the axes). the x-axis y-axis To anti-clockwise by construction out. These will quark–quark leptons are solid (vertex) of correct has an represent a diagrams: arrow going lepton–lepton transition. straight can particles are either lines. wavy or or Z°) or curly broken (photons, (gluons). be Time ows from left to right. Arrows from left to right interactions. represents represents view the diagram ± represent In a in the ways they they or help in going or Quarks • seen one • W mathematical rules junction transition probability all simple Each them in time space the right (some • The alternative the to particles left labels travelling represent for the forward antiparticles different in time. travelling particles are Arrows forward shown at from in the time. end of line. 90°. • The junctions exchange will particle be linked by a line representing the involved. E x amplEs An e electron emits a photon. An electron absorbs a photon. e e e γ γ A positron emits a photon. A + + e positron absorbs a photon. + e e + e γ γ A photon produces an electron and positron pair). a γ An electron and a positron meet and e e positron (an electron annihilate (disappear), producing a γ + e + photon. e u Beta decay. A down d quark ν + d changes into an up W quark + π with the emission of a W W before + particle. after This decays into u an ν e electron and an antineutrino. Pion The top vertex decay. The quark and antiquark annihilate to produce involves + a quarks, the bottom This into an antimuon and a muon electron leptons. and positron annihilate γ An produce two up quark (in a proton) emits u u to decays neutrino. involves An particle. vertex e e W photons. a + gluon which in turn transforms π g into a This reaction down/antidown quark pair. d γ result of p → a could take place proton–proton as a collision: d + + e Simple n diagrams can also p be A p + π° p p + mediates n + the π strong nuclear p drawn with exchanges between force between a proton and a hadrons. e neutron in a nucleus. π° W Beta decay (hadron version) ν e n probability usEs of fE ynman diagrams Once a possible diagram, for it certain is interaction possible vertex corresponds all terms, the the the More complicated 80 to to a use it been to identied calculate processes to take mathematical probability using need to fundamental has of the the with be considered included Feynman probabilities place. term. a By interaction Each line adding can be In and a together in A t o m i c , order to the same calculate n u c l e A r overall the A n d outcome overall p A r t i c l e real momentum diagram time a chosen the Feynman energy with of in represent calculated diagram. diagrams n diagram, particles particles the virtual p h y s i c s be The Lines or obey in diagrams accurate entering particles the leaving mass, they do exist to not for a apply. that are answer. the energy intermediate and relationship detected. more more must providing uncertainty cannot the lines and relationships. represent conservation for outcome. calculation, diagram and stages have to short Such in the obey enough virtual ib Qe – , e e 1. A sample The of radioactive half-life of Ra 226 material can be contains dened as the the element time it Ra takes (ii) 226. Explain a for can A. the mass of the sample to fall to half its original half the number of atoms of Ra C. half the number of atoms in the 226 in the sample D. 2. the volume Oxygen-15 of the decays to sample to fall nitrogen-15 to half with a to 2 minutes. A pure its to original half-life sample of of 100 masses g, of is placed oxygen in an and airtight nitrogen the but of oxygen Mass After container of which is with 0 g 100 B. 25 g 25 g C. 50 g 50 g D. 25 g 75 g in 4 is X undergoes is mostly also radioactive. in the wood [2] a carbon-12, small which proportion of is carbon-14, When at a that tree time is cut down, the with half-life decays a carbon-14 of Carbon-14 decays by beta-minus emission to nitrogen-14. be the equation for this decay. [2] nitrogen For an old wooden bowl from an archaeological site, the g carbon count-rate is 13 from newly Explain a sequence of of counts beta per cut why diminishes nuclide they nuclei. minutes, will (i) radioactive magnesium deuterons years. rate A the before dating trees there average 3. give a b) A. to energy value. Write Mass the kinetic of oxygen-15, container. in with carbon carbon stable, a) the necessary decay. 5,800 mass is decay. present approximately react Radioactive The sample it minimum value. 9. B. why certain particles minute. wood the with beta is 52 even per kg corresponding counts activity time, detected The per from minute. the though of count bowl the probability of radioactive Z decay decays to form a new nuclide Y. Z + could The sequence of β, β α, B. α, β, In α the D. Rutherford constant. Calculate α, β, scattering experiment, a stream of B. are is red scattered at a thin gold foil. Most This question of the α D. go scattered a nuclear of in the time the ssion reactor for providing power splitting of The is to be of absorption the neutrons nucleus and the of generated by a by into neutron the ssion two release of U results smaller nuclei energy. The plus a splitting occur in activity. many ways; for example foil. radioactive between nuclear uniformly. + material now has about 1/16 of 90 U → If the half-life measurements is is 4 hours the 143 Sr + Xe 38 + neutrons + energy 54 its a) previous a 235 92 piece the [3] about reactor, 235 A is uranium-235. n 5. of power. of can through age particles number are approximate randomly. rebound. C. the bowl. α In A. [3] γ electrical particles nucleus β 10. 4. carbon-14 emitted wooden C. individual be (ii) A. any 2 is radiations of difference The nuclear ssion reaction in (i) approximately How many neutrons are produced in this reaction? A. 8 [1] hours. (ii) B. 16 hours. C. 32 hours. Explain each why the reaction is release crucial of for several the neutrons operation of in a ssion reactor. D. 60 (iii) 6. a) Use the standard fundamental (i) A model particles, to the describe, internal in terms structure of of: An (iii) Baryons The sum (iv) electron (iv) before of Show nuclear the that the of of masses the is of uranium 0.22 the u this ‘missing mass’? released in is power about 200 plus greater ssion energy reaction ssion masses reaction rest becomes Draw Feynman diagram for (i) β the than products. [1] above MeV . [2] station Suppose a proton undergoes a strong interaction with a ϕ content: ud) to produce a neutron and Use conservation produced in this laws to deduce the of ssion structure of reactor, ssion 550 power MW . station Estimate generates the reactions occurring minimum each stating any assumption you second have in made the about particle at another the particle. power particle number (quark nuclear decay. electrical A the rest Mesons + 7. the thesum ssion A of neutron What proton (ii) b) b) [2] hours. efciency. [4] reaction. 11. Which of the following is a correct list of particles upon which 238 8. a) Two properties of the isotope of uranium, U are: 92 the strong nuclear force may act? 234 (i) it decays radioactively (to Th) 90 (ii) it reacts chemically (e.g. with uorine to form UF features responsible for of the these structure two of widely uranium different atoms protons and C. neutrons neutrons B. protons and electrons electrons D. protons, neutrons ). 6 What A. and and electrons are properties? [2] 2 b) A beam of deuterons (deuterium nuclei, H) are 1 accelerated through a potential difference and are then 26 incident on a magnesium target ( Mg). A nuclear reaction 12 occurs an (i) resulting alpha the production of a sodium nucleus and particle. Write this in a balanced nuclear equation for reaction. [2] i B Q u e s t i o n s – A t o m i c , n u c l e A r A n d p A r t i c l e p h y s i c s 81 8 E N E R G Y P R O D U C T I O N Energy nd poer genertion – sney digr ENERGY CONvERsIONs The production achieved with the thermal single into using a release energy process, work repeating must of variety of but their be the the ElECTRIC al POwER PRODUCTION power energy continuous use in of a transfer around different completely actions the of thermal can implies involve electrical systems, from fuel. that In starting this in electrical A energy a to energy fuel is turn is used power used to turbines generate continuously the all same. principle, cyclical from is work of are Any energy In to conversion cycle. some a world often converted machines xed of the boil and electrical difference (see stations to water the to process thermal make motion energy. page the release of is steam. the essentially energy. This The turbines Transformers alter steam is the the thermal used is used to potential 114). process system useful to the surroundings that is no longer available to perform electrical output useful work. energy, in This accordance thermodynamics Energy An unavailable (see conversions arrow (drawn with page are energy the left known principle of as the degraded second law of 162). energy in from fuel represented from is to right) using Sankey represents diagrams. the energy heating and changes taking place. The width of the arrow represents the sound in power or energy involved at a given stage. Created or degraded transformers energy is shown with an arrow up or down. friction and heating losses Note that Sankey diagrams are to scale. The width of the is 2.0 cooling tower useful electrical output in the diagram on the right mm losses (condenser) compared with 12.0 mm for the width of the total energy from Sankey the fuel. This represents an overall efciency of diagram representing the energy ow in a typical 16.7%. power station steam fuel (coal) turbine to transformer generator boiler water condenser Electrical energy generation POwER 1 Power is dened as the rate at which energy is energy _ Power = time 82 E N E R G Y P R O D U C T I O N converted. The units of power are J S or W . Priry energ y ourc e On RENE wablE / NON-RENE wablE ENERGY sOURCEs The law created of nor societies the conservation destroyed, are input it concerned, of energy, Renewable whereas of of just if we sources run Renewable states changes we need wish to energy non-renewable eventually energy that form. to use identify are sources As far devices sources those of energy that energy as of • require be up up, is and Of sources solar for a as a these fuel supply of It they are possible in the managed example, to burn however, cut renewable somewhere be For wood is, available can make the source (fusion). to way. source be the source rst then If of this renewable are this to is is or cut clearly replant properly trees at the managed, energy. must place. a trees possible down. sources in if have Most got of their the energy energy used by coal cells can be traced back to energy radiated from the Sun, oil but active a rate could humans photovoltaic as course from hydroelectric possible same it Non-renewable hand, renewable non-renewable. out. sources other non-renewable down used used It a energy. be the effectively neither human that cannot can is heaters natural wind not quite all of it. Possible sources are: gas • the • gravitational Sun’s radiated • nuclear • the energy nuclear energy of the Sun and the Moon biofuels Sometimes taken the when sources deciding are hard whether to a classify source is so care needs renewable or to be point that sometimes worries students is that the no eventually source sources is are run out perfectly as a source renewable! considered from the of energy This point is of for true, view the but of Earth, all life the keep Sun in runs mind out, then so will life on Earth. Nuclear as their might of above energy (such think list is that there complete. are Many other sources everyday of sources energy from as coal or oil) can be shown to have derived of their these on the Sun’s radiated energy. On the industrial scale, Earth. Other energy needs to be generated from another source. things you plug anything electrical into the mains electricity you include: have • atoms energy. so When to you the electrical When within heat Sun energy, will stored internal not. Although One energy Earth’s sources source (both so ssion they must and be fusion) consume a material sPECIfIC ENERGY aND ENERGY DENsITY you pay use. must non-renewable. to be In the electricity-generating order using to one provide (or you more) of company with the this for energy, original list of the the energy company sources. COmPaRIsON Of ENERGY sOURCEs Fuel Renewable? CO Specic Energy 2 1 Two quantities are useful to emission consider energy(MJ kg ) density 3 when making different energy and Specic the of fuel sources the energy comparison as comparisons energy energy provides between energy – per Specic vary depending specic (MJ m ) on type) density a fuels liberated consumed. (values between the useful and is unit Coal No Yes 22–33 23,000 Oil No Yes 42 36,500 Gas No Yes Nuclear No No Waste No Yes 10 variable Solar Yes No n/a n/a Wind Yes No n/a n/a Yes No n/a n/a dened mass energy is 54 37 1 measured in J kg 7 8.3 × 10 12 1.5 × 10 (uranium) specic energy energy released from fuel ___ = mass Fuel choice inuenced the fuel greater of can by needs the fuel be consumed particularly specic to mass be of energy transported: fuel that Hydro when the needs stored – water in dams to Tidal be transported, the greater the Yes No n/a n/a n/a No n/a n/a Wave Yes No n/a n/a Geothermal Yes No n/a n/a Yes 30 21,000 cost. Pumped Energy density liberated per is unit dened volume as of the energy fuel 3 consumed. The unit is J storage m Biofuels energy e.g. Some density types ethanol energy release from fuel ___ = volume of fuel consumed E N E R G Y P R O D U C T I O N 83 foi ue poer production As ORIGIN Of fOssIl fUEl Coal, fuels or oil and have beneath Coal is of This exposure in been hundreds matter. natural to the swamps. very been high a years as fossil timescale from fuels. that involves accumulations converted into temperatures fossil and of fuels pressure the tens Oil by upon plant layer of matter decaying that used matter to buried exist is this formed in a gas, be obtained possible to as as into life. well a plant more similar sea. Natural more turned marine also grow by became microscopic can dead was material timescale dead that it the These surface. from Layer known over of has Earth’s formed are produced millions matter the gas matter other Over substances, the geological coal. manner The as and compressed. from the compression occurring by-product manufacture in during gas from remains took of place under underground the the pockets, production of oil. It is coal. decomposed. ENERGY TRaNsfORmaTIONs Fossil fuel power once again Sun. For Some of can stations be used example, this release to turn millions matter has of energy in turbines. years eventually ago fuel Since energy been by all burning fossil radiated converted it. fuels into The were from the thermal Sun was storage in fossil the the supplied on rate to used converted (by the to convert original water source photosynthesis) of into into this steam that energy living plant was the matter. chemical compression energy in in plants fossil fuels fuels EffICIENCY Of fOssIl fUEl POwER sTaTIONs data typical then matter, energy E x amPlE Use is living coal. chemical photosynthesis solar energy Energy energy originally a this (in 500 page and tonnes MW per coal the previous hour) red at page which power to coal calculate must be The efciency design. At of the different time of power stations publishing, the depends following on the gures apply. station. Fossil fuel Typical efciency Current Answer maximum 8 Electrical power supply = 500 = 5 MW = 5 × 1 10 J s efciency 8 Power released from fuel × 10 / efciency Coal 35% 42% 8 = 5 = 1.43 × 10 / 0.35 9 × Natural 1 10 J Rate of consumption of coal = 1.43 × = 43.3 kg = 43.3 × 60 = 1.56 × 10 7 10 / gas 45% 52% 38% 45% s 9 3.3 × 10 Oil 1 kg s 1 s Note that thermodynamic considerations limit the maximum 1 × 60 kg 5 hr achievable efciency (see page 163). 1 kg hr 1 ≈ 160 tonnes hr aDvaNTaGEs aND DIs aDvaNTaGEs Advantages • Very of high energy • Fossil • Still • Power Can 84 is fuels cheap links • energy’ released are and a be ‘energy small easy compared can water used from relatively when stations and be Disadvantages ‘specic to built to mass density’ of fossil – a great deal transport. other sources anywhere with of • fuel. energy. good transport Combustion acid products can produce products contain pollution, notably rain. • Combustion • Extraction • Non-renewable. • Coal-red of fossil fuels can ‘greenhouse’ damage the gases. environment. availability. directly in E N E R G Y the home to provide P R O D U C T I O N heating. power stations need large amounts of fuel. Nucer poer – proc e The PRINCIPlEs Of ENERGY PRODUCTION Many This a nuclear fuel ssion page a moving Among to not In each fast. In An the nucleus other further are uranium-235 release of of this reaction, to words fragments initiate – use overview individual uranium the stations burned reaction. 76. causes on is power split the more reactions ‘fuel’. energy is achieved is described an incoming The If chain is using on very these of go created. of run of of that the number the speed a general the is of surface reached so-called the the There likely are the likely. have given of of the when mass be ensure reaction took time and reactions that, goes place decreasing as the chain of then the to the chain took and on on reaction place, the initiate number then ssion the process process they of a a has the is can to cause a important the ssion ones are: way’ neutrons. block fuel reaction on ‘in the further the neutron nuclear slowed of on Two of fuel exact (before assembled occur. been increases reaction This of is together happens assembled. nature so it The the do a from stage when exact fuel the lost a value being of used assembly . particular Before size fuel depends the nuclei causing As goes factors. energy) block). a neutron potential mass of cause be the fewer several the trend, ssion to would on neutron shape to a (or critical critical and by a all If to each reactions increase control. depends • chances more needs from stop. • As If reactions chance reactor neutron would out soon reaction nuclear one reaction. reactions The a only further would high. is a number are neutrons reaction design average, would neutron fragments temperature neutrons. a the process apart. then as are can energies ssion. In moving cause that general, too further fast make the to them make reactions more neutrons the created reactions neutrons down. mODERaTOR, CONTROl RODs aND hE aT distributors E xChaNGER to electricity kinetic energy Three important components in the design of all consumers nuclear rods reactors and the are heat the moderator, the control exchanger. nuclear thermal energy energy electrical energy thermal • Collisions between the neutrons and the nuclei of energy the moderator slow them down and allow further losses reactions • The to take control place. rods are movable rods that readily to environment absorb neutrons. removed control • The from the heat to occur of the They the chain a be reaction introduced chamber in or order to concrete shields reaction. exchanger in can place allows that is the nuclear sealed off reactions from the rest control rods environment. The reactions increase the (moveable) temperature in the core. This thermal energy is moderator steam to pressurizer transferred to heat water and the steam that is turbines produced A general (PWR It uses or turns design the for pressurized water as the turbines. one type water of nuclear reactor) moderator and is as reactor shown a here. HOT coolant. secondary WATER coolant circuit aDvaNTaGEs aND DIs aDvaNTaGEs Advantages • Extremely high ‘specic energy’ – a great deal pump heat of energy is released of uranium. from a very small mass exchange steel pressure vessel • Reserves of uranium large compared to fuel rods oil. Disadvantages • Process primary produces radioactive nuclear waste pump that is currently just coolant stored. circuit • Larger possible risk if anything should go wrong. Pressurized • Non-renewable (but should last a long water nuclear reactor (PWR) time). E N E R G Y P R O D U C T I O N 85 Nucer poer – ety nd ri ENRIChmENT aND REPROCEssING Naturally occurring uranium-235. percentage more uranium Enrichment composition is contains is the less process increased to NUClE aR wE aPONs than by 1% which make of A this nuclear nuclear whereas ssion likely. amount been of addition to sustaining by-product nucleus uranium-235, ssion of can a which conventional capture uranium-239. This undergoes 238 1 U + nuclide nuclear fast-moving undergoes further neutrons to to also to A energy as a • associated Moral uranium-238 is form issues associated destructive neptunium-239 threat plutonium-239: of prevent • Np + β 93 239 239 with and weapons with warfare. capability that any huge Weapons plutonium as the have fuel. include: weapon Nuclear since deployment non-nuclear has the Second been aggressive of aggression weapons acts used have World as against a that such War the deterrent the to possessors capability. + unimaginable consequences of a nuclear war have υ many + countries to agree to non-proliferation β + υ 1 treaties, Reprocessing involves treating used fuel waste from recover uranium and plutonium and to deal A fast breeder reactor is one a small attempt number of to limit nuclear power technologies nations. with • products. which nuclear to design A by-product of the peaceful use of uranium for energy that production utilizes weapons. ssion the 0 Pu 94 to nuclear nuclear produces 1 → 93 waste with nuclear uranium associated their nuclear The forced other both in ssion U 0 → 92 reactors released using controlled nuclear 92 239 Np involves capable formed reactor. β-decay β-decay is is of → 0 U This 239 n 92 239 plutonium-239 reactions. of station uncontrolled designed Issues In power an is the creation of plutonium-239 which plutonium-239. could it be right have used for for the nuclear the small production number capability to of of nuclear countries prevent other weapons. that Is already countries from hE alTh, s afETY aND RIsk acquiring Issues associated generation • If the of with control rapidly the electrical rods increase use were its of energy rate all of nuclear power stations nuclear for removed, the production. reaction would fUsION RE aCTORs Completely ssion would cause an explosion meltdown of the core. The radioactive the reactor could be distributed around the causing many fatalities. Some argue that current the in of such a disaster means that the use of is be a risk not targets worth for taking. terrorist Nuclear The reaction produces not much of this radioactive waste is power decay within page 76) nuclear ionize material of a low level risk and is produced for millions decades, which of • The this waste uranium mining the The will years. is to mined involves extra a signicant remain The the and of of in from the are is waste and The necessary from from plant risk. ore to any is also protect the needs the mine nuclear to be to a power secure safe. used to of the produce civilian nuclear E N E R G Y and the reaction the signicant same as The (if amounts takes and requires place creating use of nuclear hydrogen into a state power weapons. P R O D U C T I O N of matter’, in which in atoms but move fuel associated used, it could of in be hydrogen, sustained) radioactive the Sun temperatures plasma state (as high (this electrons and independently). design challenges are associated conning can be the plasma at sufciently to sites. mines. uranium reprocessing reactors. waste. outlined is enough the protons are Currently the amount solution underground signicant uranium the ssion with maintaining dangerously current secure precautions involved station By-products 86 geologically transportation station • so workers power and fuel operation radioactive • in is atomic bound density bury signicant will and radioactive of problems waste. principal of potential the stations not radioactively supply produce reaction ‘fourth While of attacks. to • many terrible on could theoretical nuclear The energy nuclear plentiful would scale the without surrounding is area offer generation material with in reactors and power thermal knowledge? include: Fusion uncontrolled that for fusion to take place. high temperature and s or poer nd ydroeectric poer sOl aR POwER (TwO TYPEs) There are arrives two at the ways of Earth’s harnessing surface from solar radiation the radiated the energy that glass/plastic Sun. cover A photovoltaic photocell) into a cell converts potential a difference semiconductor to cell very produces much not a current. require a (otherwise portion do are deal known the as It uses Unfortunately, voltage used of to and run energy. a radiated (‘voltage’). this. small They great of it a solar a of not electrical Using or directly piece typical is cell energy able to in water out provide devices them warmer photovoltaic that series do would cold water in generate higher higher voltages and several in parallel can provide a current. solar radiation reective insulator slices of copper pipe (black) behind pipe semiconductor active solar heater thermal energy solar energy in water metal layer aDvaNTaGEs aND DIs aDvaNTaGEs Advantage • Very ‘clean’ • Renewable • Source production source of – no harmful chemical by-products. energy. photocell of energy is free. Diadvantage An active designed hot and solar to water capture that would heater it save as (otherwise much typically on the thermal produces use known of as energy can electrical be a as solar panel) possible. used source of energy in a Can only • Source • A be utilized during the day. of energy is unreliable – could be a cloudy day. The domestically energy. of hYDROElECTRIC POwER The • is very large area would be needed for a signicant amount energy. aDvaNTaGEs aND DIs aDvaNTaGEs hydroelectric power station is the Advantage gravitational potential energy of water. If water is allowed to move • downhill, the owing water can be used to generate electrical Very ‘clean’ production – no harmful chemical energy . by-products. The • water As can part stored of in gain the its gravitational ‘water large cycle’, reservoirs as potential water high can up energy fall as is as in several rain. It ways. can • Renewable • Source source of energy. be of energy is free. feasible. Diadvantage • Tidal power during • Water a low can reservoir. be more back of pumped Although than few trap water at high tides and release it • Can • Construction only be utilized in particular areas. tide. be down the schemes the hill, from the low energy energy this a used regained ‘pumped large-scale reservoir methods to do when storage’ of to this the a pumping water system storing high under of dams will involve land being submerged water. must ows provides one energy. energy lost due to friction throughout gravitational KE of water + PE of water E N E R G Y P R O D U C T I O N 87 wind poer nd oter tecnoogie ENERGY TRaNsfORmaTIONs There is winds of great that this the a deal blow energy temperature due to hot as a air of the course, are The ows kinetic around is, atmosphere of Earth. the heated to differences rising or cold maThEmaTICs energy involved The Sun. cause air original Different different in density of air ρ the source parts of r temperatures. pressure sinking, differences, and thus wind speed ν air result. blades turn wind 2 The In So area one ‘swept second mass of air out’ the by the volume that passes blades of air the of the that turbine passes turbine in the one energy m available per second A = πr turbine second 1 Kinetic = = = v A v Aρ 2 = mv 2 1 2 = (vAρ)v 2 heating 1 Ear th 3 = Aρv 2 1 In other words, power available 3 = Aρv 2 In practice, calculate, the but kinetic it energy cannot all be of the incoming harnessed as the wind air is easy must to continue to energy lost move in other words the wind turbine cannot be one hundred per KE of turbine electric energy due to friction – cent efcient. A doubling of the wind speed would mean that the throughout available power would increase • Diadvantage aDvaNTaGEs aND DIsaDvaNTaGEs • Source of energy is unreliable – by a factor Some to could of consider spoil the eight. large wind generators countryside. Advantage be • Very ‘clean’ chemical production – no a • by-products. A very for • Renewable • Source of source energy of is day without a large area signicant are far the the three inclusion for 90% include With most amount of of the is reduce that the energy primary fuels: at world’s the solar, demand developments dependence on coal of sources and natural writing this consumption. wind, tidal, expected with guide, biomass to rise use gas. Other renewable fossil in in worldwide With this accounts primary and the energy the fuels geothermal. future, can the help to The energy typically a The sources are not conversion storage convenient for individual impossible going to take however, fuels to for predict place predict many decrease 88 to a takes over this technological the coming continuing years be Best positions noisy. far from for wind generators centres of widely used are population. capability Power place that results to storing in to come. dependency E N E R G Y years. Current dependence The over hope time. when is It on that is the we are models, will important P R O D U C T I O N that use of or is consumer are electrical with vary a having typical the only energy electrical fuels challenge, a with everyday of Currently viable in for (a petrol). everyday limited demands. electrical pumped large-scale capacity society. energy (e.g. very generation demand. the are rened capacitors) to be future storage method of a typical system is approximately 75% use. The meaning one those of quarter the of the energy development associated of supplied new is wasted. technologies particularly with: • renewable energy • improving the sources fossil be to need systems spare energy or can sources source) compared match that a aware developments electrical batteries companies energy source secondary users NE w aND DE vElOPING TEChNOlOGIEs is Can • secondary of (e.g. hydroelectric fuels. process energy versatile devices that It • often common efciency and covered energy. most very of Primary of be secondary energy oil, time energy renewables: global hope fossil uranium, the need free. common main would energy. sECONDaRY ENERGY sOURCEs By wind. harmful able be efciency of our energy conversion process. Ter energ y trn er PROCEssEs Of ThERmal ENERGY TRaNsfER CONvECTION There In are energy very and several from a hot important than There faster is a one Any of fourth moving object a are given these by to processes radiation. more processes which cold process molecules object called called transfer can be situation happening the surface thermal the This of a Three convection probably at evaporation. leaving of achieved. conduction, practical processes the involves same time. involves liquid that the convection, of a bulk (a liquid expand the up thermal movement or a and hotter gas). thus uid because a energy of When its part density rises moves matter. up. This of is the current is its boiling point. Evaporation causes is set two take colder causes up as a points place heated The heating it because in a tends uid room shown uid to sinks to and warm below. is Cool air is denser and below only uid reduced. Central convection between can Hot air is less dense cooling. sinks downwards. CONDUCTION In a thermal conduction, substance substance. hot if the without For from example, other Conduction is thermal any end the molecule to is bulk one placed process by energy (overall) end in of a a hot which is transferred movement metal cup spoon of kinetic along of the soon feels tea. energy is passed molecule. The ow of air around a room Air is warmed is called a convection current. by the heater. macroscopic view Convection HOT COLD thermal energy thermal energy Points • to in a room note: Convection cannot take place in (and many a solid. Examples: RESERVOIR RESERVOIR • The pilots of convection gliders currents in order birds) to stay use naturally above the occurring ground. Thermal energy ows along the material as a result • of the temperature dierence across its ends. Sea breezes the microscopic view day will rise onto • the the (winds) land from Lighting in HOT the re room are the During in often hotter above shore. a is a land the the to the and will convection. sea. This there night, chimney towards due than the will be a situation mean that During means a hot air breeze is reversed. breeze ows re. COLD The faster-moving molecules at the hot end pass RaDIaTION on their kinetic energy to the slower-moving molecules as a result of intermolecular collisions. Matter is not radiation. Points to Poor conductors are called thermal Metals tend because allows a to be very different quick good thermal mechanism transfer of conductors. (involving thermal All gases (and most liquids) radiate the This up the transfer have a of thermal temperature energy above by zero to a electromagnetic re to ‘feel the waves. heat’, your If you hands hold are your receiving is the radiation. For most electrons) everyday energy. objects • in (that insulators hand • objects note: kelvin) • involved All tend to be poor this radiation is conductors. in the infra-red part of HOT Examples: the electromagnetic OBJECT • Most clothes keep us warm by trapping layers of air – a spectrum. poor more • If For conductor. one walks around a house in bare feet, the oors that details of the are electromagnetic better conductors (e.g. tiles) will feel colder than the see that the a are good same piece insulators temperature. of metal feels (e.g. (For colder carpets) the same than a even if reason, piece of they on are a page When used for cooking food, saucepans from the source of heat to the given o from at cold Points to • object all surfaces. note: day An at room temperature absorbs and radiates wood.) conduct If it is at constant temperature (and not changing thermal state) energy radiation is 37. energy. • spectrum, oors then the rates are the same. food. E x amPlE • A • Surfaces cork – a poor conductor surface poor • that that radiators Surfaces that is a are good light (and are radiator in poor dark colour is also and a good smooth absorber. (shiny) are absorbers). and rough are good radiators (and outer plastic cover good absorbers). hot liquid • If the temperature of an object is increased then the surfaces silvered frequency of the radiation increases. The total rate at par tial vacuum between so as to reduce which energy is radiated will also increase. glass walls to prevent radiation convection and • Radiation can travel through a vacuum (space). air gap conduction (poor conductor) Examples: insulating space A thermos ask prevents heat loss • The • Clothes the Sun warms in the summer radiation from Earth’s tend the to surface be by white – radiation. so as not to absorb Sun. E N E R G Y P R O D U C T I O N 89 Rdition: wien’ nd te sten–botnn bl aCk-bODY RaDIaTION: sTEfaN-bOlT zmaNN l aw wIEN’s l aw In Wien’s general, on many the radiation things. It is given possible out to from come a up hot object with a depends theoretical the displacement intensity of the law relates radiation is the a wavelength maximum at λ to which the max model for emitter the will ‘perfect’ also be a emitter perfect of radiation. absorber of The ‘perfect’ radiation – a temperature of the black body T. This states that black λ T = constant max object absorbs all of the light energy falling on it. For this The reason the radiation from a theoretical ‘perfect’ emitter value of the constant can be found by experiment. It is is –3 2.9 known as black-body × 10 m radiation does not depend on the nature of surface, but should be noted that in order to use this the it does depend upon its wavelength should be substituted into the the equation emitting It radiation constant, Black-body K. in metres and the temperature in kelvin. temperature. 3 2.90 × 10 _ At any given temperature there will be a range of different λ (metres) = max emitted. This (and Some variation hence frequencies) wavelengths is shown in will the be of radiation more graph intense that than ytisnetni wavelengths T(kelvin) are others. below. The is peak wavelength approximately stinu yrartibra / ytisnetni λ 500 = 500 nm = 5 10 from the Sun nm. max 7 5 × m 3 2.9 × 10 _ so T = K 7 5 4 = × 10 5800 K 3 2 wavelength / nm λ max = 500 nm 1 We its can analyse surface light from temperature. a star This and will be calculate much less a value than for the 0 temperature 400 1200 800 egnaro der wolley eulb neerg teloiv wavelength / nm of visible light be the absolutely above actually graph precise, as the something it is not correct intensity, that could but be to this called label is the the the often y-axis done. intensity It and core. might so Cooler stars (lower frequencies) Radiation To in Hot stars will give out all frequencies 1600 emitted will well of tend only give visible from to appear out light planets – will white the in higher they will peak in colour. wavelengths appear the red. infra-red. on is function. INTENsITY, I This is dened so that the area under the graph (between two The wavelengths) gives the intensity emitted in that intensity of radiation is the power per unit area that is wavelength 2 received range. The total total power page 195) area radiated. under The the graph power is thus radiated by a a measure of Black-body (See given the object. The unit is W m per unit Power _ I is by the = A by: 2 Surface area in m 4 P Total power Although spectrum = radiated stars is and in σAT Stefan-Boltzmann W planets approximately are the not perfect same as emitters, black-body constant their radiation radiation. power radiated by object area ____________________________________________ e EqUIlIbRIUm aND EmIssIvITY = power If the temperature of a planet is constant, then the power radiated per unit area by black body at same temperature being thus absorbed by the planet must equal the rate at which energy is 4 being If it absorbs must of radiated go up into more and absorption if space. energy the then its The planet than rate of it is in radiates, loss of temperature thermal then energy must go is the equilibrium. p order to estimate the power absorbed than its rate down. or eσ A T temperature greater albEDO Some back In = emitted, of concepts are radiation space. The received fraction by that a is planet is reected reected back is straight called the the albedo, following the into α. useful. The Earth’s albedo varies daily and is dependent on season Emissivity (cloud The Earth and its atmosphere are not a perfect black e, is dened as the ratio of power radiated per has by an object to the power radiated per unit area by a a high value. at the same temperature. It is a ratio and so on has no P R O D U C T I O N global scattered power __ = total E N E R G Y The Earth. units. albedo 90 Oceans black total body latitude. unit (30%) area and have a low value but body. snow Emissivity, formations) incident power annual mean albedo is 0.3 s or poer sOl aR CONsTaNT The amount of power that arrives from the Sun is measured by the solar constant. It is properly dened as the amount of solar 2 energy that falls per second on an area of 1 m above the Earth’s atmosphere that is at right angles to the Sun’s rays. Its average 2 value is about 1400 W m . 2 This is not that often the less same than as the half of power this that arrives arrives at the on 1 m Earth’s of the surface. Earth’s The surface. amount Scattering that arrives and absorption depends greatly in on the the atmosphere weather means conditions. incoming solar radiation 100% 1% absorbed NB These gures are only guidelines in stratosphere stratosphere because gures vary with cloud cover, water vapour, etc. troposphere clouds reect 23% 24% absorbed in troposphere clouds absorb 3% 4% reected from the Ear th’s surface surface of the Ear th 24% direct 2 1% diuse 45% reaches Ear th’s surface Fate Different received parts will of also the of incoming Earth’s vary with radiation surface the (regions seasons at since different this will latitudes) affect how will receive spread out different the rays amounts have of solar radiation. The amount become. atmosphere is a near-uniform 23.5 ˚ thickness all around the Ear th MN > PQ RS R S Nor th Pole N o m t a e c a f r u s e r e h p s M > TU T r o 60 ˚ incoming solar p ic s eg de h tr a E fo o f C radiation a n c e r travelling in 30 ˚ E q T r o p i u a to near parallel r lines c o f P C a p ri 0 ˚ c o T U rn Q South Pole 30 ˚ Radiation has to travel through a 60 ˚ 90 ˚ greater depth of atmosphere (RS as compared with TU) in high latitudes. When it reaches the surface the radiation is also spread out over a greater area (MN as compared with PQ) than in lower latitudes. The effect of latitude on incoming solar radiation Tropic of Tropic of Capricorn Cancer SUN Summer Summer in nor thern hemisphere The Earth’s orbit and in southern hemisphere the seasons E N E R G Y P R O D U C T I O N 91 Te greenoue eect PhYsIC al PROCEssEs O S E Some solar radiation is Short wavelength radiation is received reected by the atmosphere the to Sun and warm causes up. The the surface Earth will of emit the E Some of the infrared from Earth radiation passes through and Ear th’s surface the atmosphere and is lost in space Outgoing solar radiation: infra-red 2 radiation (longer wavelengths radiation coming from than Solar radiation passes the 103 W m S through the clear atmosphere the Sun) Net outgoing infra-red because 2 ncoming solar radiation: the Earth is cooler than the Sun. Some radiation: 240 W m of 2 33 W m this in infra-red the radiation atmosphere is and absorbed by re-radiated in gases all directions. G This and is known the gases as in the the greenhouse atmosphere effect that R E E N Net incoming H radiation are called U S E G A S E S absorbed and reemitted by the solar radiation: absorb greenhouse gas molecules he 2 infra-red O Some of the infrared radiation is 240 W m greenhouse direct eect is the arming of the gases. The net atmosphere effect and the is that the surface of Solar energy absorbed upper the Earth Ear th’s surface and the troposphere by atmosphere: are Surface gains more heat and 2 warmed. as real The name is greenhouses potentially are warm as 2 W m confusing, a result infrared radiation is emitted again of Solar energy is absorbed by the a different mechanism. Ear th’s surface and arms it and is coner ted into heat causing 2 The be temperature constant energy The process the the equals energy. of if of the rate the Earth’s at rate without Earth would it temperature than °C effect the emission of longae infrared rediation bac to the atmosphere radiates it is 1 W m will absorbs a E natural temperature much of it which the be average which at greenhouse and surface the lower; Moon the is Sources: Oanagan niersity ollege in anada epartment of eography niersity of Oford nited States Enironmental rotection gency E Washington limate change 1 he more science of climate change contribution of oring group 1 to the second assessment report of the 30 colder than the Earth. nte rgoernmental anel on limate hange E and WO ambridge ress 1 • GREENhOUsE Ga sEs The main balance release • greenhouse in the due to gases atmosphere industry Methane, CH . can and This is are naturally be altered technology. the occurring principal as a They but result of Chlorouorocarbons propellants the of their are: Each component depleting of these resonance of and the gases (see ozone absorbs page (CFCs). cleaning 168). Used solvents. as They refrigerants, also have the effect layer. infra-red The radiation natural as a frequency result of of oscillation of 4 natural gas and fermentation. amounts of the product Livestock of and decay, plants decomposition produce the or signicant methane. bonds If the is equal driving occur. • Water, H O. The small amounts of water vapour in the within to The the molecules frequency the natural amplitude (from of the frequency of the the gas is radiation of the molecules’ in the infra-red emitted molecule, vibrations from region. the resonance increases Earth) will and the upper 2 temperature atmosphere (as opposed to clouds which are condensed levels in greatly • the as a a signicant atmosphere result of effect. do not industry, The average appear but local to water alter dioxide, CO . Combustion dioxide signicantly Overall, into the increase plants atmosphere releases the which greenhouse (providing they are will take place at specic depending on the molecular energy levels. greenhouse gases in the Ear th’s atmosphere 2 carbon absorption Absorption spectra for major natural levels vary. Carbon The vapour can effect. growing) ytiv it prosb A can have increase. water frequencies vapour) will 1 Methane CH 4 0 1 Nitrous oxide N O 2 remove carbon dioxide from the 0 atmosphere 1 during photosynthesis. This is known as Oxygen, O 2 carbon & Ozone, O xation 3 0 • Nitrous oxide, N O. Livestock and industries 1 2 (e.g. of the production nitrous remain in oxide. the Its of Nylon) effect upper is are major signicant atmosphere for Carbon sources as long it can periods. dioxide CO 0 2 1 Water vapour In addition the following gases also contribute to the H O 2 0 greenhouse effect: 1 • Ozone, O . The ozone layer is an Total important 3 atmosphere region of the atmosphere that absorbs high 0 energy UV photons which would otherwise be 0.1 harmful to living organisms. Ozone also adds 0.2 0.30.4 0.60.8 1 1.5 2 3 4 5 6 8 10 20 30 to Wavelength (µm) the greenhouse effect. [After J.N. Howard, 1959: Proc. I.R.E 47, 1459: and R.M. Goody and G.D. Robinson, 1951: Quart. J. Roy Meteorol. Soc. 77, 153] 92 E N E R G Y P R O D U C T I O N Go ring • POssIblE C aUsEs Of GlObal waRmING Records show increasing in that the recent mean temperature of the Earth has Changes linked been years. • Cyclical The rst in to, the for intensity example, changes suggestion in of the radiation increased the Earth’s could be solar orbit caused and by emitted are by the Sun activity. volcanic natural activity. effects or could 0.6 be caused by human activities (e.g. the increased burning of annual mean fossil fuels). An enhanced greenhouse effect is an increase 5-year mean 0.4 0.2 in the greenhouse In 2013, Change) 0 the IPCC report inuence warming has effect by human (Intergovernmental stated been since caused the that the ‘It is mid–20th Panel extremely dominant activities. cause of on likely the Climate that human observed century’. 0.2 Although is that it that is still the being debated, increased the generally combustion of fossil accepted fuels has view released 0.4 extra 1880 All 1900 atmospheric suggestions • for Changes in 1920 models this the 1940 are highly increase 1960 1980 complicated. 2000 Some the carbon dioxide greenhouse into the atmosphere, which has enhanced effect. possible include. composition of greenhouse gases in the atmosphere. E vIDENCE fOR GlObal waRmING One piece been of drilled Isotopic evidence in the analysis atmospheric variations that links Russian allows the temperature warming base temperature concentrations of global Antarctic of and at to greenhouse carbon to increased Vostok. be estimated gases. dioxide Each are The and air record very levels year’s of new bubbles provides closely greenhouse snow fall trapped data gases adds from in comes another the over ice from layer cores 400,000 ice to can years core the be used ago data. The ice core has ice. to to the measure present. the The correlated. Antarctic Ice C ore Concentration C° vmpp / 2 4 380 2 340 0 OC 2 300 -2 -4 260 -6 220 -8 180 -10 400,000 350,000 300,000 250,000 200,000 150,000 100,000 50,000 0 Years before present ppmv = par ts per million by volume • mEChaNIsms Predicting deal in of the There global • the future uncertainty, Earth are and many its effects as the of global warming interactions atmosphere mechanisms are that involves between extremely may a different the warming reduces overall the rate only reduces albedo. of heat This ice/snow will cover, result in an which in increase The rst small the Temperature increase absorption. increase reduces the solubility of CO in the the of exist increase trapped deforestation atmosphere, carbon four initial in feedback. • subsoil An (called in tundra) temperature that may support cause a CO result the in the reduction release in of further number of trees 2 turn in release does into reduces warming. Global Not CO of frozen 2 • rate with vegetation. signicant systems complex. increase Regions simple great xation. mechanisms temperature are temperature. This Some have people examples increase has process of gone is processes on to known suggested that as the whereby cause a a further positive current sea 2 temperature and thus increases atmospheric involves • Continued and the vapour global warming atmosphere’s is a will ability greenhouse to increases may be ‘corrected’ by a process which concentrations. increase hold both water negative feedback, and temperatures may fall in the future. evaporation vapour. Water gas. E N E R G Y P R O D U C T I O N 93 Ib quetion – energ y production 1. A wind The generator source of this converts wind wind energy energy can be into electric traced back energy. to Calculate solar a) energy arriving at the Earth’s the in a) Outline solar b) the energy energy List one use of transformations converts advantage wind into and wind one involved energy. from 1 P = for a the wind per cooling second carried away by the water tower; [2] b) the energy per c) the overall efciency second d) the mass produced by burning the coal; [2] [2] disadvantage of of the power station; [2] the generators. expression available the as of coal burnt each second. [1] [2] 5. The energy surface. maximum generator theoretical power, This question is about tidal power systems. P, a) Describe b) Outline c) A the principle of operation of such a system. [2] is one advantage and one disadvantage of 3 Aρv using such a system. [2] 2 where A is the area swept ρ is the density out by the small air v is the table wind a wind the is proposed. Use the data in to calculate the useful the total output energy power of available this and system. speed. maximum generator below estimate Height Calculate system and hence c) power blades, the of tidal theoretical whose blades are power, 30 m P, for low between high tide and tide 4 m long Trapped water would cover an 1 when a 20 m s wind blows. The density of air 6 area of 1.0 × 10 1.0 × 10 2 m 3 is 1.3 kg m . [2] 3 Density d) In practice, under these conditions, the of Number only provides 3 MW of electrical Calculate (ii) Give the efciency of this generator. Solar reasons of explaining why the power output theoretical 2. This a) question Give one one is is about example example less power of a than the a [2] b) sources. renewable energy non-renewable energy are such. source source and why they classied day 2 [4] as models. Distinguish, a in terms solar of the heating energy panel and changes a involved, photovoltaic State an appropriate (i) solar (ii) photovoltaic heating domestic use for cell. [2] a panel. [1] cell. [1] and 26 c) explain per climate maximum output. energy of tides and actual between power m [2] a) two –3 kg power. 6. (i) water generator The radiant power of the Sun is 3.90 × 10 W . The [4] average radius of the Earth’s orbit about the Sun is 11 b) A wind year. If show farm there that turbine c) State produces is are the wind average about two ten 400 35,000 MWh turbines power of on output energy the of in 1.50 a and farm the one kW . disadvantages × it 10 m. may be The albedo assumed of that the no atmosphere energy is is 0.300 absorbed by atmosphere. [3] of using wind power to generate Show that at Earth’s the the intensity surface incident when the on Sun a solar is heating directly panel overhead 2 electrical 3. This power. question is is [2] about energy d) transformations. 966 Show, W m . using [3] your answer to (c), that the average intensity 2 incident Wind power can be used to generate electrical an energy ow diagram which shows the Assuming starting with solar energy and ending energy, generated by windmills. Your indicate where energy is degraded. This question that is about a coal-red power station which Electrical power output from station Temperature at cooling Temperature leaves which = 200 MW = 288 K = 348 K = 4000 water tower at cooling which water tower 1 Rate of water ow through tower kg s 7 Energy content of coal = 2.8 × = 4200 10 1 J kg –1 Specic 94 . the Earth’s surface behaves [3] as a black-body no energy to (d) is to absorbed show by that the the atmosphere, average use temperature Earth’s surface is predicted to be 256 K. [2] Outline, with reference to the greenhouse effect, why is average than enters Wm surface temperature of the Earth is higher cooled. Data: the that answer the the water 242 [7] f) 4. is diagram of should surface with your electrical Earth’s energy and transformations, the energy. e) Construct on heat of I B water Q U E s T I O N s – J kg E N E R G Y 1 K P R O D U C T I O N 256 K. [4] 9 W a v e p h e n o m e n a Sil i i hL SImpLe harmonIc motIon (Shm) equatIon tWo e x ampLeS of Shm SHM Two the occurs when resultant the forces acceleration, a, on is an object directed are such towards, that and 1. proportional to, its displacement, x, from a xed common Mass, m, on ∝ -x or a = -(constant) × mathematics of SHM is simplied if the constant the of another Thus the between constant general ω a and which form for x is the approximate to SHM are: spring that: mass is identied called the equation as the angular that of the spring is negligible compared to the of mass proportionality that vertical x • The a point. Provided a situations is of the load square frequency. denes SHM • friction • the (air friction) is negligible is: spring obeys Hooke’s law with spring constant, k at 2 a = -ω x all The solutions for this equation follow below. The times (i.e. elastic limit is not exceeded) angular • the gravitational • the xed eld strength g is constant 1 frequency period, T, ω has the units of of the oscillation rad by s and the is related following to the time ω end of the spring cannot move. equation. 2π _ Then it can be shown that: = T k 2 ω = m m Or T = 2π √ IdentIfIc atIon of Shm In order the to analyse following a situation procedure to should decide be if SHM is taking place, 2. The simple Identify all the forces acting on an object when it an arbitrary distance x from its rest position a free-body Calculate this points the • is back towards of SHM must be resultant the has in force proportional motion Once and mass m the mass of of the the string is negligible compared with the load diagram. the force l using mass • length that: is • displaced of followed. Provided • k pendulum the the the mean object been to using must second displacement position be identied, following Newton’s (i.e. and F law. equation ∝ of friction • the maximum (air friction) • the gravitational • the length is angle negligible of swing is small (≤ 5° or 0.1 rad) always x) then SHM. the • If motion Then it can of be eld the strength pendulum shown g is is constant constant. that: form: g 2 ω restoring force per unit displacement, = k l ____ a = - ( oscillating mass, × ) m x l Or • This identies the angular frequency ω as ω ( = m ) or Note √( m ) = equations = that equation k ω T . Identication of ω allows 2π the be g mass and thus of the does pendulum not affect bob, the m, time is not period in of this the quantitative pendulum, to √ k _ 2 T applied. e x ampLe acceLeratIon, veLocIty and dISpL acement A 600 g mass is attached to a light spring with spring constant –1 30 N m . durIng Shm The variation and displacement, angular The frequency precise object hand with is of the of of an the acceleration, object doing a, SHM velocity, depends v, on the (a) Show (b) Calculate that (a) Weight the the mass does frequency SHM. of its oscillation. ω. format when set time x, of the clock equations relationships is started correspond depends (time to an t = on zero). where The oscillation of mass = mg = 6.0 N the Additional displacement on k x x down means when mass = upwards. Since F ∝ x, in the mean position when t = 0. The right hand m equations maximum correspond displacement to an oscillation when t = when the object is Since SHM, T = 2π at √( 1 = x sin ωt x = x 0 cos = ωt = ωx a = -ω cos k 0.6 _ ) = 2π √( 30 ) = 0.889s ωt v = -ωx a = -ω 0 sin 1 _ = T 0 v = 1.1 Hz 0.889 ωt 0 2 2 x sin ωt x 0 cos ωt 0 displacement x The rst force oscillate 0. f x will set (b) of resultant mass _____ ____ is the the withSHM. object that left two equations can be rearranged to produce 0 the ωx 0 following relationship: _______ velocity 2 v = ± ω √ (x x ) 0 x is the amplitude of the oscillation measured in m 0 t is the time taken measured in T T 3T 4 2 4 time T s 2 ω –1 ω is ω t the is full an angular angle = time s measured in radians. x 0 acceleration A velocity equation. • acceleration m _ • displacement k • velocity = ω with rad acceleration is completed frequency 2π _ T increases in • angular following that measured • oscillation The frequency 2π is when related (ω t) to the = 2π time rad. period T by the leads leads velocity by displacement and 90° by displacement lags velocity by 90° are 180° out of phase 90° √ lags acceleration by W a v e 90° p h e n o m e n a 95 e s i sil i i hL During SHM, Providing energy there are is no interchanged resistive between forces which KE and dissipate PE. The total energy is this 1 E = energy, the total energy must remain constant. The oscillation E is + k E 2 = m ω p 1 2 (x x ) + said to be The kinetic 1 2 x = 2 m ω x 0 2 2 undamped Energy energy 1 E 2 m ω 0 2 = can 1 2 mv be calculated 2 = m ω in SHM is proportional • the mass m • the (amplitude) 2 (x k x to: from 2 ) 0 2 2 2 • The potential 1 E = energy 2 m ω can be calculated the (frequency) from 2 x p 2 E total p Graph showing the variation with distance, x of the energy, during SHM k x x x 0 0 total k Graph showing the variation with time, t of the energy, during SHM p t 96 W a v e T T 3T T 4 2 4 2 p h e n o m e n a dii hL The intensity plot for a single slit is: Ba SIc oBServatIonS Diffraction is a wave effect. The objects involved intensity (slits, apertures, etc.) have a size There is a central maximum intensity. that is of the same order of magnitude Other maxima occur roughly halfay 10 as the wavelength of visible light. beteen the minima. n gil dii bsl sw s the angle increases, the intensity of the () straight maxima decreases. edge 1.1 0.4 angle b = slit idth (b) single 1st minimum λ θ long slit = λ θ = θ λ = b b b b ~ 3λ λ The angle of the rst minimum is given by sin θ b () circular λ For small angles, this can be simplied to θ = . b () single long slit b ~ 5λ 1 have e xpL anatIon The shape derived of by 1 of the maximum amplitude and thus be 5 the relative applying an intensity idea called versus angle Huygens’ plot can maximum be principle. of the central 25 intensity. We For 1st minimum: can treat the slit as a series of secondary wave sources. In the b sin θ forward up to direction give a (θ = zero) maximum these intensity. are At all any in phase other so they angle, there is a difference between the rays that depends on the λ λ ∴sin θ path = add = angle. b The for overall the rst sources The result is the minimum across the condition for slit addition is that cancel the rst of the all the angle sources. must The make all condition of the Since angle is small, b out. maximum out from the centre θ sin θ ≈ λ 3λ when the path difference across the whole slit is θ is . At this ∴ 2 θ = b angle the slit can be analysed as being three equivalent sections λ each having a path difference of across its length. Together, for 1st minimum 2 two of these sections will destructively interfere leaving the 1 resulting amplitude to be of the maximum. Since intensity path dierence across slit = b sin θ 3 2 ∝ (amplitude) , the rst maximum intensity out from the 1 centre will be of the central maximum intensity. By a similar 9 argument, the second maximum intensity out from the centre will SIngLe-SLIt dIffractIon WIth WhIte LIght When a single component slit is colour illuminated has a specic with white light, wavelength and each so Red the rst order associated maxima and minima for each wavelength will be Violet located at a different angle. For a given slit width, colours incident white light with longer than colours wavelengths with short (red, orange, wavelengths etc.) (blue, will diffract violet, etc.). more zero order The Violet maxima for the resulting diffraction pattern will show all the rst order colours central of the rainbow position and with red blue and appearing at violet nearer greater to the Red angles. W a v e p h e n o m e n a 97 tw-s i ws: y ’s bl- hL sli i douBLe-SLIt Interference The double-slit This to can be only taken Decreasing that the interference take into the total place if account slit slits when width intensity pattern the will of will out that be on page innitely working mean light shown are the the 47 small. was In overall observed decreased. The derived practice double pattern assuming they slit have more pattern (a) Young ’s fringes for innitely narrow slits each nite interference becomes interference that a was behaving The diffraction pattern and will slit width. as more become shown to a perfect pattern of point each source. slit needs below. ‘idealized’. harder like Unfortunately, it will also mean observe. (c) Young ’s fringes for slits of nite width relative intensity intensity angle θ bright fringes (b) diraction pattern for a nite-width slit intensity angle θ λD s = still applies but dierent fringes d will have dierent intensities with it being possible for some fringes angle θ to be missing. InveStIgatIng young’S douBLe-SLIt e xperImentaLLy Possible page set-ups for the double-slit experiment are shown on 47. The most width accurate are microscope Set-up 1 measurements achieved that is using a for slit travelling mounted on a separation and microscope. frame so that it fringe This can be is a moved region in which perpendicular to the direction in which it is pointing. The superposition occurs microscope separation moved by of slits precision is moved the across microscope ten can or more be read is often fringes off from and the the distance scale. The monochromatic of this measurement improved by utilizing a light source vernier In the scale. simplied version (set-up 2) of the experiment, fringes S 1 can still be bright enough to be viewed several metres away S 0 from the slits and thus they can be projected onto an opaque S 2 screen (it is separation dangerous can be then to look be into directly a laser beam). measured with Their a source Set-up 2 twin source slit possible slits (less than 5 mm) double screen 0.1 m laser 1 m positions In the original source is set-up diffracted at (set-up S so 1) as to light from ensure the that coherent light. monochromatic S 0 receiving and S 1 Diffraction takes slit are 2 place providing S 1 and S are narrow enough. The slit separations need to be 2 approximately order were of 0.1 separated transparent will need they 1 mm can 98 to be or be mm (or by (or less) less). thus This approximately translucent) darkened viewed using W a v e to a the would 0.5mm situated allow slit 1m the widths provide on a away. fringes microscope. p h e n o m e n a are fringes screen The to be of the that (semi- laboratory visible and screen ruler. mlil-sli ii hL the dIffractIon gratIng The the slit diffraction overall that appearance experiment considers further takes the slits. (see effect A place of page on series the 98 the of (a) 2 slits at an individual fringes for nal parallel in more Young’s details). interference slits slit (at a affects double- This section pattern regular of adding separation) is (b) 4 slits called a diffraction Additional condition angle be at slits for at grating the same constructive which unaffected the by light the separation will interference. from number slits of adds slits. In not affect other the words, constructively The situation the will is (c) 50 slits shown below. θ path dierence Grating patterns between slits = d sin θ uSeS θ One of the main uses of a diffraction grating is the accurate d experimental For constructive interference: measurement light contained on diffraction a interference in a given grating, takes place of the different spectrum. the angle depends at on If wavelengths white which light is of incident constructive wavelength. Different path dierence = nλ wavelengths can thus be observed at different angles. The between slits [λ, 2λ, 3λ] accurate nλ measurement with an (and thus accurate formula also applies The to the difference Young’s between angle of the of provides the colour of exact light the experimenter wavelength that is being = d sin θ The measurement arrangement. the measurement frequency) considered. This of is apparatus called a that is used to achieve this accurate spectrometer. double-slit the patterns is R most third (and part of the four th) noticeable at the angles where perfect constructive interference order spectrum not shown does not have a take place. signicant If there angular are only width. two T wo slits, sources the that maxima are just 2nd order will out V of phase interfere to give a resultant that is nearly the same R amplitude as two sources that are exactly in phase. 1st order resultant interference V pattern white light white central source A maximum time V diraction grating source B R V The addition just out pattern of of more phase will be slits with totally its will mean neighbour. that The each new overall slit is interference destructive. R overall interference pattern is totally destructive time The addition following of further slits at the • the principal maxima maintain • the principal maxima become • the overall so the same slit separation has the effects: amount pattern of light increases in the same much being let separation sharper through is increased, intensity. W a v e p h e n o m e n a 99 ti lll ls hL pha Se changeS There that in are also detail many involve the condItIonS for Interference patternS situations the reection conditions interference, one consideration. A when for needs phase to interference of light. When constructive take change any is or take place analysing A parallel-sided reections that lm are can produce taking place interference at both as surfaces a of result the of the lm. destructive phase the can changes inversion of into the wave E that can take place at a reection interface, but it does not air D always happen. It depends on the two media involved. A C The technical ‘undergone term a for phase the inversion change of of a wave is that it has π’. thickness d • When light is reected back from an optically denser lm medium there is a phase change of π (refractive index = n) ϕ • When light medium is reected there is no back phase from an optically less dense change. air B n < n 1 ϕ transmitted wave 2 (no phase change) ϕ = zero when viewed n 1 along the normal n 2 F reected wave From point A, there are two possible paths: incident wave (no phase change) n 1 1. along path AE 2. along ABCD in in air the film of thickness d < n 2 reected wave These (π phase change) incident wave the rays then interfere optical path difference. The path AE in and air is we need to equivalent calculate to CD in the film n 1 So path difference = (AB + BC) in the film. λ n 2 In addition, the phase change at A is equivalent to path 2 difference. λ transmitted wave So total path difference = (AB + BC) in film 2 (no phase change) λ = n(AB + BC) + 2 By geometry: (AB + BC) = FC e x ampLe = The equations in the box on the right work out the angles 2d cos ϕ for λ ∴ which given eye If constructive wavelength. receives white rays light is and If destructive the leaving used source the then of lm the interference light over is a an place extended range situation take of source, values becomes for for path difference = 2dn cos ϕ + a 2 if the θ 2dn or cos ϕ = mλ when ϕ = 0, : destructive 2dn = mλ: destructive λ more if 2dn cos ϕ = m + λ: constructive 2 complex. or two Provided colours cancel. The as can be • an • soap oil the may thickness reinforce appearance seen lm when on the of surface the along the looking of lm a lm is small, direction will be in bright then which one or others colours, when such ϕ = 0, 2dn = mλ: m = 0,1,2,3,4 constructive at of water or appLIc atIonS bubbles. Applications • The of design aircraft. If parallel of thin lms non-reecting the thickness of include: radar the coatings extra for coating is military designed so rays from an that eye focused radar signals destructively interfere when they reect ex tended source from both surfaces, then no signal will be reected and an at innity aircraft • of thickness of the give Design constructive allow of the and would reduce A surface thin place solar for transmittance p h e n o m e n a and the a A can typical takes of slicks the surfaces strong amount lm oil be of destructive thickness cells. of wavelengths non-reecting panels takes W a v e undetected. Measurements angles) 100 go Measurements that • could of oil for energy added so at this by spillage. interference to be that and signals known (blooming), at being (at calculated. lenses reection wavelength place caused electromagnetic any of usefully destructive thus wavelength. solar these surfaces transmitted. interference maximum rsli hL ytisnetni evitaler dIffractIon and reSoLutIon If two sources another, the eye said at to of then can be light they tell the apertures affects to the the close as one sources The right very seen two resolved. examples are are apart, diffraction eye’s show in ability how angle single then the pattern to the to of light. sources that resolve (a) resolved one source takes sources. appearance of If are place The two line angle θ sources a slit. will The depend resulting on the diffraction appearance is the that takes addition place of the at two appearance overlapping relative These and diffraction intensity examples the of light look diffraction patterns. at that at the The different situation takes place graph of angles is of at a a line slit. A the resultant alsoshown. source more of two sources clearly separate light common resultant intensity (b) just resolved situation would be a point source of light, and the diffraction diraction pattern that takes place at a circular aperture. The situation is exactly of source B the same, aperture. point but As diffraction seen source is on thus takes page 97, place the concentric all the way diffraction circles around pattern around the of the the of source A central angle θ position. The geometry of the situation results in a slightly slightly dimmer different value for the rst minimum of the diffraction pattern. appearance For a slit, the rst minimum was at the angle λ θ = two maxima visible b (c) not resolved resultant intensity For a circular aperture, the rst minimum is at the angle 1.22 λ _ θ diraction pattern = b of source B of source A If two one sources are diffraction just resolved, pattern is then located on the top rst of minimum the of maximum of angle θ the other diffraction pattern. This is known as the Rayleigh criterion. appearance appears as one source how e x ampLe Late one night, a student was observing rst a far away the distinguish car two was when points of she light. could T ake Since θ small 1.8 _ the θ = [x is distance to car] x car approaching from a long distance distance away . between the headlights to be 1.8 m. 1.8 __ She noticed that when she rst observed the When just ⇒ resolved x = 4 1.525 headlights of the car, they appeared to 1.22 × λ _ θ one point of light. Later, when the car × 10 be = = 11.803 ≃ 12 was b closer, she became able to see two km separate 7 1.22 × 5 × 10 __ points of light. If the wavelength of the = light 0.004 can be taken her pupil as 500 nm and the diameter of 4 = is approximately 4 mm, 1.525 × 10 calculate Example: reSoLvance of dIffractIon gratIngS As a result of on a grating’s resolvance, between possible a Rayleigh’s ability R, of a to resolve diffraction wavelength resolvable criterion, being there is different grating is limit placed wavelengths. dened investigated, wavelength a difference, λ, as and the the In The the that ratio sodium are 589.00 smallest a close nm and diffraction one spectrum another 589.59 grating, nm. the (the In there Na order resolvance are two D-lines). for these must wavelengths These to be are resolved by be Δλ. 589.00 _ λ _ R = = = 1000 0.59 Δλ λ _ R emission to = Δλ In For m, any given being and the grating, observed total R (rst number of is dependent order: slits, m N, = on 1; on the second the diffraction order: grating that m order, = are 2, etc.) the rst order illuminated spectrum, whereas requirement drops in to the only at least second 500 1000 order slits must be spectrum, the slits. being illuminated. λ _ R = = mN Δλ W a v e p h e n o m e n a 101 t dl hL analysis doppLer effect The Doppler effect of wave a a as movement When a of is result the source the of name the given to movement the of change the of source the frequency or A the observer. of sound is moving: change Sound waves are emitted at a particular frequency from of shows sound but • police When a the of that a frequency stationary, hear • quickly observer, the pitch if can car or the is source be moving will detected be if away from received. the source is moving. ambulance sound is frequency also observer of the lower passes change you from on high the to road, low you can frequency. It the is high when it is approaching and low when it is going away. source. • • The speed of the sound wave in air does not change, Radar detectors moving the motion of the source means that the wave fronts are object. ‘bunched up’ ahead of the means that the stationary observer receives of reduced For Reduced the wavelength corresponds to an increased of speed the of a change reected in the wave. the effect to observer) be noticeable needs to be with light moving at waves, high the speed. a source an of light observer, of a the particular observer frequency will receive is moving light of a away lower sound. overall higher effect is frequency that than it the observer was emitted will by hear the sound source. at a This frequency the source is moving towards the observer. A If the source be from red the part other of the spectrum colours, this is has lower called a of light is moving towards the red observer, shift. there a blue shift mathematIcS of the doppLer effect movIng Source moves the all similar will Source Since than applies • when the Doppler (or frequency. The the measuring frequency from of measure by wavelength. If • to this sound source waves used do source. • This be They all frequency • can but A to D with velocity, u , speed of waves is v Mathematical stated on this equations that apply to sound are page. Unfortunately the same analysis does not apply to light λ o – the velocities medium. It is, can not be however, worked possible out to relative derive an to the equation moving source for u s that turns out to be in exactly the same form as t the A light • BC D stationary equation the for relative sound as velocity long of as two source conditions and are detector is met: used stationary in obser ver obser ver receives sound receives sound at lower frequency at higher frequency • the this equations. relative velocity Providing change in frequency v << change due to is a lot less than the speed of light. c wavelength relative relative motion Δλ _ v source speed and of observer Received v Δf f' = f _ frequency = v ≈ u s v c λ f at P speed f' = f v ± u s of light source Received v relative f' = f motion frequency v + u s at Q movIng oBServer e x ampLe The frequency measured 200 Hz by when frequency of a the will approaching a car’s horn stationary car be the is at heard if observer is observer rest. the car is at 1 30 m s ? (Speed of sound 1 330 m s .) u o f S = 200 f’ = ? u = 30 v = 330 f = Hz O 1 m s s 1 in a time t, observer has moved u t m 300 _ o 200 ( 300 = 200 × = 220 Hz 1.1 If observer is moving away from source: v u o f' = f v ± u v o f' = f v If observer is moving towards source: v + u o f' = f v 102 W a v e p h e n o m e n a s 30 ) in as What air is els liis dl hL 1. Train The going sound frequency, on the the through emitted but the platform resolved passenger a station by a sound will is used of to train’s received change. component that 4. moving At the by any a of velocity the is of passenger instant train’s calculate whistle constant • standing time, it The galaxies relative light is towards frequency Receding – red shift intensities received from of the the stars different in wavelengths distant galaxies can of be analysed. the • The light • The measured shows a characteristic absorption spectrum. received. received frequency associated wavelengths with particular are not elements the as same as those measured in the laboratory. • For the have vast been spectrum train passing majority shifted (i.e. to red shift (see The magnitude of stars, towards lower page all the the red received end frequencies). of The the frequencies visible light shows a 202). time • of the red shift is used to calculate the through station recessional 2. Radars – speed many countries the police use radar to measure speed to see provides evidence for the Big if they are breaking the speed model of the creation of the Universe. of 5. vehicles and measurement Bang In velocity Rotating object limit. The reected transmitted wave RADAR wave rotation measured side of of by the luminous looking object for objects a (e.g. different compared with the Sun) Doppler the can shift be on one other. λ RADAR light red shifted rotating star moving car transmitter stationary V λ' Police light blue shifted • Pulse of microwave radiation of known frequency emitted. • Pulse is reected off moving car and received back at view above pole source. 6. • Difference in emitted and received frequencies is used Broadening • calculate speed of Absorption Double Doppler effect taking Moving car receives a frequency that is higher as Moving car it is lines emission a moving atomic energy spectra levels provide (see page evidence for 69). Precise measurements show that each individual level than is emitted and place: • ◊ spectral car. discrete • of to actually equivalent to a small but dened wavelength observer. range. ◊ acts as a moving source when sending • signal 3. Medical physics – blood ow red is can blood used to gas will be molecules use cells a in pulse an measure of ultrasound analogous the speed of way a to that measure a moving pulse car the of speed of Different will microwaves are to moving Doppler so light from molecules shift. be molecules general have a Doppler range of speeds broadening of so there the discrete (above). A higher kinetic receiver a wavelengths. • transmitter subjected measurements • Doctors The back. temperature energies spectral and means hence a wider more distribution broadening to of the line. skin incident reected sound sound ν s red blood cell W a v e p h e n o m e n a 103 IB Questions – wave phenomena HL 1. When pitch is at a train of the rest. travels sound This is towards you hear you is sounding different its from whistle, when the the much train displacement the sound waves are travelling faster toward the wave closer graph fronts of the sound reaching you are below atom the wave further the carbon carbon atom atom may such be that any ignored. shows x in the from a its variation with equilibrium molecule of time t position of of a methane. spaced together. 10 x / ×10 C. than the thedisplacement you. hydrogen B. of because The A. lessmassive fronts of the sound reaching you are spaced m 2.0 apart. 1.5 D. the sound the speed frequency emitted by the whistle changes with 1.0 of the train. 0.5 2. A car is travelling at constant speed towards a stationary 13 t / ×10 0.0 observer emitted note a) of whilst by the its horn horn frequency With the aid frequency is is a sounded. 660 720 of is Hz. The The frequency observer, of the however, note hears a Hz. 0.5 1.0 diagram, explain why a higher 1.5 heard. [2] 2.0 1 b) If the speed of sound is 330 m s , calculate the 27 The speed of the car. mass from 3. This the question emission Light from upon a is about using spectrum a of hydrogen atom is 1.7 × 10 kg. Use data [2] sodium of a diffraction grating to the graph above view (i) to determine (ii) to show its amplitude of oscillation. [1] sodium. discharge tube is incident that the frequency of its oscillation is normally 13 9.1 × 10 Hz. [2] 5 diffraction grating having 8.00 × 10 lines per metre. (iii) The spectrum contains a double yellow line of to show that the maximum kinetic energy of the wavelengths 18 hydrogen 589nm and 590 c) a) Determine the angular separation of the two lines in the second order spectrum. State why Sketch a graph velocity it is more difcult to observe the line when viewed in the rst order spectrum. This question is about thin lm v to of transparent thin lm is starting the Assuming as shown in the the [2] variationwith hydrogen at t = velocity that the 0. atom used diagram time one t of period (There is no need to of add [3] of the hydrogen atom is to coat its frequency of oscillation f is given spectacle expression below. k _ 1 _ coating, refractive = glass lens, refractive √m 2π index = 1.00 for axis.) motion f air, refractive J. interference. sometimes bythe lenses show the simpleharmonic, A 10 [1] d) 4. × double valuesto yellow 6.2 [4] oscillation b) is when the viewed atom nm. index = 1.30 p index = 1.53 where k is hydrogen the force atom and per unit the carbon displacement atom and between m is the a mass p ofa proton. (i) Show that incoming the value of k is approximately 1 560 N m . [1] light (ii) Estimate, using your answer maximumacceleration e) boundary A a) State the phase is transmitted (ii) is reected at at is classied (i) Describe (ii) Electromagnetic what which occurs boundary boundary A to into light is transmitted the b) Light of at the lm. 9.1 [1] B. boundary A from the lm into [1] Determine required so that 570 the the nm in air smallest reection is is incident thickness of minimized on the for the coating normal incidence. 5. Simple a) A [2] harmonic body is conditions harmonic b) In a and necessary model the for the greenhouse equilibrium. the body to effect State the execute two simple I B [2] of carbon massesattached 104 and from motion. simple atom motion displaced by a greenhouse meant by a the atom. [2] gas. a methane atom can spring. Q u e s t I o n s A radiation of greenhouse gas. [2] frequency × 10 Hz is in the infrared electromagnetic spectrum. theinformation given in region Suggest, (b)(ii), of the based why on methane is [1] air. wavelength coating. a (d)(i), hydrogen 13 that classied (iii) is as to the boundary B change (i) Methane of molecule, be regarded hydrogen – a hydrogen as two atom w a v e is p h e n o m e n a as a greenhouse gas. [2] s 10 f i e l d s Hl P ( ) • describing fields: e The • concept the of eld lines gravitational can eld, g, be used around a to visually mass (or the collection This of test masses) • the The represent: electric eld, E, around a charge (or collection • of Magnetic elds can page In cases object • all placed at a gravitational also be the represented eld particular eld = is the point force in per using force the unit per eld tes t eld lines unit test • (see with: p o i nt An is N kg mas s This electric eld = force per unit test point positive force both line, the angles is represented gravitational work same to a moved method the by the direction of and electric elds, as a the eld of be done (force and distance line, no work will be done (force perpendicular). mapping needed new potential will direction) are energy denes gravitational • for in distance consider eld. ) eld alternative to the moved: are right and 1 (units: at point that, is a moved of lines. means object along charges). 61). direction eld the to concepts (see elds move of around between electric an object points potential in the and below). charge 1 (units: Forces and • the The the N are C ) vectors direction and of magnitude eld more page lines precise eld the of are lines force the to represent that force o ne deni ti o n, would is (fo r eld object of (gravitational as the placed the eld. the In potential force at an a or per electric) unit particular analogous test is point point in denition, (gravitational, V , or test a test how object. clo se of a ux ) is dened as the Potential is points, and A energy point result object of the that the eld. and A the B, in an at A there per If will be mathematical per electric the eld) test is at the on a two test (or that B difference, done object. eld means potential potential work unit gravitational In general, moving work will be is a moving charge done. different. a mass between When work Between the is between two done, points two points, A the and B, ∆V object points must as it moves between two points then the increase. object The relationships a between If work is done by the test object as it moves between the two points then the full are between the two points must decrease. shown Gravitational page in and a positive potential energy B, potential potential on on Potential difference ∆V (electric and gravitational) • as by m a gn e t ic e has magnitude a e xa m p le • g electric,V unit the by 112). or electric) dened an d eni t io n Potential , V (gravitational The felt rep r e s e nted another se e both be potential difference between two points, 110. work potential, V ∆V = g done moving a test mass ___ energy _ Gravitational = g test mass mass –1 Units 1 Units of V = J kg of ∆V = J kg g g Electric potential difference between two points, energy _ Electric potential, V = e charge work done moving a test charge ___ ∆V = e test 1 Units of V = J C (or charge volts) e 1 Units of ∆V = J C or V (volts) e Thus to points calculate in a eld W = q∆V W = m∆V the we work done, W, in moving a charge q or a mass m between two have: e g f i e l d s 105 Hl ep e x amPles of equiPotentials equiPotential surfaces The best around way a two is the object same. dimensions equipotential. with representing charged potential In of the A to These they good contour is on are of a the identify would way lines how electric the called be potential regions where equipotential represented visualizing as these varies The diagrams below show is positively +40 V of to equipotential lines for various situations. surfaces. lines lines the all ve with units 1 charged of J kg sphere start map. 25 + mass contour lines 50 +30 V 3-d surface +20 V 100 shallow +10 V 200 steep contour lines contour lines close fur ther apar t Equipotentials point The contour heights that are high lines the an are can a be height. low that right the represents left. Points that potential gravitational in a Each are and the line points potential. gravitational situation up up sphere that are a Contour a low lines are 150 V 150 V 100 V done 50 V joining have the potential. 30 V 20 V charge rightshows 10 V 1 200 J kg the and points represent eld. point The charge-conducting changing joins high a eld. drawn electric the on gravitational electric points same of same equipotential same Lines up at on landscape represent of with diagram the value down The of outside mass. equipotentials for 40 V an 1 150 J kg isolatedpositive point 1 100 J kg charge. Equipotentials point for two point charges (same charge) and two masses. rel ationsHiP to field lines There lines is of a another. line, simple relationship equipotential we Imagine stay at the the – they between are contour same electric always lines. height If at we eld lines right angles move along in the gravitational we are moving and to a one + contour eld. - This -80 V 80 V does to not the require work gravitational because force. Whenever we move at right along angles an 60 V -60 V electric 40 V equipotential line, we are moving between points that have -40 V the 20 V same electric Moving at potential right angles – in to other the words, electric no eld is work the is being only way done. to Equipotentials avoid doing work in an electric eld. Thus equipotential -20 V 0 V for two point charges (equal and opposite lines charges). must be at right angles to eld lines as shown below. +V = 70 V 60 V 50 V 40 V zero potential often d 30 V taken to be negative 20 V terminal of battery 10 V 0 V eld line Equipotential It should be lines noted between that charged although the parallel correct plates. denition of equipotential zero potential is at innity, most of the time we are not lines really interested interested that in in some in the the actual value of situations the (such value of potential, difference as the in we are potential. parallel only This conducting means plates) it always at 90° is Field lines and equipotentials are at right angles easier setting than 106 f i e l d s to sea imagine level correctly as the the using zero zero at for innity a different point. gravitational for the zero. This contour is just lines like rather Hl g p p gravitational Potential energy It is easy when a Earth’s to work mass out moves the difference between two in gravitational different heights energy near the it lost The difference in energies = m g(h - h 2 potential must value point ) in • are this two important derivation strength g is has points assumed constant. to be of of energy the negative at gravitational space is mass, moving dened a in m, given potential as the was towards zero point, done innity, M, the and potential P . energy work at mass of in a mass at moving any it from 1 innity There energy potential energy the surface. The If to that point. The mathematics needed to work this out note: that However, the gravitational Newton’s is not trivial It turns since the force changes with distance. eld theory out that of G M m _ universal with gravitation distance. vertical This distance states that equation we move the can is eld only not MUST be very Gravitational CHANGE used if the equation gives zero everyday The true assumes PE at the situations zero of that the surface but it gravitational of is the Earth. of mass m = - (due to M) large. gravitational not energy r the This • potential potential This works energy of is the a scalar path quantity taken from (measured in joules) and is independent innity. for fundamental. potential energy is taken as innity. potential energy decreases as zero of potential energy taken gravitational force does work to be at innity M m F 4 F m 3 F m 2 F m 1 as m moves towards M in the force on m increases gravitational Potential We can dene the energy the esc aPe sPeed gravitational potential V that measures The escape speed of a rocket is the speed needed to be able to g per unit test mass. escape the getting (work W _ V to gravitational an innite attraction distance of the planet. This means away. done) __ = g m (test We mass) know that gravitational GM _ potential at the surface of a planet = - 1 The SI units of gravitational potential are J kg . It is a scalar R p quantity. (where R is the radius of the planet) p Using Newton’s law of universal gravitation, we can work out This the gravitational potential at a distance r from any point means that for a rocket of mass. mass m, the difference between GMm _ its V energy at the surface and at innity = g R p r GMm _ Therefore the minimum kinetic energy needed = R p In other words, GM V g = r 1 GMm _ 2 m (v ) = esc R 2 p so ______ This formula and the graph also works for spherical masses 2GM _ v = √( esc (planets masses etc.). is just The the gravitational addition of potential the as individual a result of potentials. lots of This This an easy sum since potential potential due to 1 a scalar p derivation assumes the planet is isolated. quantity. potential due to A 1 m is ) R is = -40 J kg 1 m 2 = -30 J kg e x amPle The escape speed from an isolated planet like Earth (radius of 6 Earth R = 6.37 × 10 m) is calculated as follows: E __________________________ 11 24 2 × 6.67 × 10 × 5.98 × 10 ___ v = esc √( ) 6 6.37 × 10 m overall potential 1 = (-40) + (-30) J kg 8 m m = 2 1 1 × 10 ) √(1.25 m s 1 = -70 J kg 4 = 1.12 × 10 1 m s 1 Once you another, have the the potential difference at one between point them is and the the potential energy you at ≈ The to move a unit mass between the two points. It is vast the path km s majority of rockets sent into space are destined to independent orbit of 11 need the Earth so they leave with a speed that is less than the taken. escape speed. f i e l d s 107 Hl o gravitational Potential gradient energy of an orbiting s atellite GMm _ In the diagram below, a point test mass m moves in a We already know that the gravitational energy = r gravitational eld from point A to point B. _____ 1 The difference in gravitational potential, The ΔV kinetic energy GM _ 2 = m g v but v = √( ) r 2 (Circular average force × distance motion) moved ______________________ = = -g×∆r m GM _ 1 ∴ The negative doing the sign work direction from has done is g. is because directed Since g is directed away the from M gravitational towards and M, thus force is in but the the opposite attractive, kinetic energy m = = r 2 force So total energy = KE + GMm _ 1 r 2 PE work 1 GMm _ GMm _ r r be in going from A to B, so the potential at A = < 2 potential at B. Note GMm _ 1 = to r 2 that: 1 distance moved • In the orbit the magnitude of the KE = magnitude 2 of ∆r • the The overall must have have mass M PE. energy a total enough of the energy energy to satellite less is than escape the negative. zero (A satellite otherwise Earth’s it would gravitional eld.) distance r • A In order orbit, B to the increase move total in from energy orbital a small must radius radius increase. makes the orbit To to be total a large precise, energy go radius an from a F average large average eld between A and B, g = negative number to a smaller negative number – this m is an increase. (towards M) This ΔV = -g × can be summarized in graphical form. Δr g ygrene ΔV _ g = ∆r ΔV ___ 1 is called the potential gradient. It has units of J kg kinetic energy in orbit 1 m ∆r 1 (which are the same as N kg 2 or m s ). orbital total energy The gravitational gradient. elds The (see eld strength equivalent page is equal relationship to also minus applies the for potential radius electric 109). gravitational potential energy in orbit The WeigHtlessness One say way that of it is supporting If the the the different extreme lift value weight of the of force a person recorded is to on a of set values the version cable up breaks in a lift, they depending on the of apparent In the situations lift (and occurs if passenger) –2 accelerates the down at 10 station the m s to space stay in resultant . The in same an and to be the orbiting the station, force the of of space astronaut the weightless term weightlessness for ‘weight’, objects station are in gravitational in it the is free-fall would free-fall pull duration better on also to of call the this fall. Given situation together. appear weightless. The together. the astronaut provides the needed orbit. force centripetal appear ambiguity astronaut centripetal these would possible space would lift. and person the An were acceleration An the scale. scales record dening This causes the acceleration. is true for the orbital path 2 accelerating down at 10 m s gravitational R = zero satellite and pull the acceleration. contact 2 resultant force a = 10 m s down = W so, There force satellite once and on the is the velocity no between again, is a circle satellite’s the astronaut we have gravitational attraction on W apparent weightlessness. astronaut provides centripetal no weight will force needed to stay in orbit be recorded on scales 108 f i e l d s e p p Hl Potential and Potential difference The concept of electrical potential difference Potential due to more tHan between two points was introduced one cHarge on page 105. As the name implies, potential difference is just the difference If between the potential at one point and the potential at another. Potential several charges potential simply a measure of the total electrical energy per unit charge at a given space. The denition is very similar to that of gravitational at up point, the contribute it can be to the total calculated individual potentials by due to the potential. individual potential increases a point adding in all is charges. zero of potential Q 3 r 3 taken to be at as charge is moved P innity in against repulsion +Q r 2 r q q F 1 q F 4 q F 3 2 F 1 potential at point P As q comes in the force on q increases. = (potential due to Q ) Q 1 If the total work done in bringing a positive test charge q from innity to 2 a Q 1 point in dened an to electric eld is W, then the electric potential at that point, V, ) + (potential due to Q ) 2 is 3 be W _ V + (potential due to Q The = electric potential at any point outside a q charged The units for potential are the same as C or volts. Q _ V = 4πε r o This equation only applies the units for potential as single point to if its Q a charge. sphere is exactly the same difference: V laitnetop 1 J conducting all the charge had been concentrated at centre. Potential and field strengtH V = 4πε r o potential dierence = (V V B A ) potential = V A distance potential = V B F F B A +Q q Potential inside a cHarged sPHere Charge • distribute Outside as • will if all Inside the the sphere, charge the itself was sphere, uniformly the eld on lines concentrated there is no net the outside of a and equipotential at point a q B at the contribution conducting surfaces centre from the of are the A sphere. the same sphere. charges distance d outside Bringing a positive charge from A to B the sphere and the electric eld is zero. The potential gradient is thus also means work needs to be done against zero meaning that every point inside the sphere is at the same potential – the electrostatic force. the The potential graphs at below the sphere’s show how surface. eld and potential vary for a sphere of radius direction of a at A and B point charge 1 (a) / V m Q (positive) B A point charge direction of force max slope falls 2 applied by external o as r agent on test charge q at A and B a 1 The Q work done δW = - E q δx [the negative sign = max 4πε 2 r/m is a because the direction of the force needed opposite to the direction to 0 do the work is V/ V Therefore E = E] δ W _ 1 (b) of q δ x point δ V _ = charge - In δ W _ [ δ since δ V = q x ] words, V max slope falls electric eld = - potential gradient 1 o as r volt _ Units = 1 (V m 1 ), N C metre Q = 4πε max V 1 a 0 a r/m f i e l d s 109 e p Hl comParison betWeen electric & gravitational field Electrostatics Force can be Coulomb’s Gravitational attractive law q – for q 2 = attractive Newton’s law m 2 F = for point masses 2 G 2 r – m 1 _ k 2 4πε charges always _ = E Force q 1 _ F repulsive point q 1 or 2 r r o Electric eld Gravitational charge electric producing mass field gravitational = F k 2 q g 2 4πε r o 2 1 = = r m 2 2 test Electric charge potential due test to a point field Gm 1 1 = = producing field q q F E eld field Gravitational charge r mass potential due to a point mass, m 1 q q 1 = V = 1 k _ e 4πε Gm 1 _ V r r = - g r o Electric potential Gravitational gradient = _ g - = - ∆r Electric ∆r potential q energy q 1 = qV p Gravitational q 2 = energy GMm _ 2 _ = k E e 4πε potential q 1 _ E gradient g e _ E potential ∆V ∆V = mV p r r = - g r o uniform fields Field A strength constant is equal eld thus to minus the potential 2. gradient. Constant The • A constant will • In potential equate 3D this planes to a that are gradient xed means electrical eld means: change that i.e. in a given spaced in distance potential. equipotential equally increase surfaces apart. In 2D will be at electric (e.g. a capacitor in the middle In the diagram plates equipotential eld is V in – between see page charged 52) is parallel effectively plates constant section. and below, the the potential separation of difference the plates is across d. Thus the the V lines will be equally spaced. electric potential gradient is and the constant eld in the d V centre • Field lines (perpendicular to equipotential surfaces) will of the spaced parallel Constant gravitational gravitational eld near the surface of a planet is At the The units V m 1 and N C are and can both be used for electric eld between E the surface of the Earth, the eld lines cannot remain two charged uniform throughout effect. is the parallel plates and effectively there constant. 1 . eld plates The = lines. Strictly, 1. E d equivalent equally plates, be will will be an edge It straightforward to show be that at the edge, the eld must have dropped to half the 2 perpendicular to the Earth’s surface. Since g = 9.81 m s , the value 1 potential gradient must also be 9.81 J kg in the m . that are 1,000 m apart represent but modelling the eld as constant Equipotential everywhere surfaces centre, 1 changes of between the parallel plates with the edge effects potential occurring beyond the limits of the plates can be acceptable. 1 approximately equal to 10 kJ kg +V = PE using PE = mgh PE from 1st principles zero at surface zero at innity 70 V 60 V 50 V 40 V zero potential often d height = 3 km 30 V 6.255 × 10 30 000 J J 20 V 10 V taken to be negative terminal of battery 0 V height = 2 km 6.25 × 10 20 000 J J Equipotentials height = 1 km 6.253 × 10 10 000 J J PE ierence PE = 10 000 J 6.2603 × 10 0 J surface of Ear th 110 f i e l d s J lines between charged parallel plates. ib q – Hl 1. Which one of the variation of the potential energy, following kinetic GPE, graphs energy, of an best KE, and orbiting represents of the satellite the (ii) Calculate gravitational at a distance whilst the centre of the Calculate ygrene ygrene B. KE b) (i) the of the Space Shuttle [2] energy Shuttle What forces, inside needed to put the the into if orbit. any, Space act [2] on Shuttle the astronauts whilst in orbit? [1] KE (ii) 0 Explain 0 Shuttle r why feel astronauts aboard the Space weightless. [2] r GPE c) GPE ygrene D. ygrene C. speed Earth? Space A. the orbit. r (iii) from in Imagine an astronaut Space Shuttle, and Space Shuttle. By approximations, 2 10 m m outside from making calculate the the exterior centre of walls mass of appropriate assumptions how would long it take of the the and for this GPE astronaut force of to be pulled gravity alone. back to the Space Shuttle by the [7] KE 0 0 5. r a) The diagram below shows a planet of mass M and radius R p r KE GPE R p X M R 2. The diagram between two below illustrates charged parallel + some equipotential metal + lines plates. + + The gravitational distance R 80 V from potential the centre V due of the to the planet planet is at given point X by GM _ V = R 60 V where 0.1 m G is the universal gravitational constant. 40 V Show that 20 V the gravitational potential V can be expressed as 2 g R 0 p _ V = R - - - where g is the acceleration of free-fall at the 0 surface The electric eld strength between the plates 6 NC B. 8 NC the planet. [3] is 1 A. of b) 1 C. 600 NC D. 800 NC 1 The graph below due to planet the shows varies how the gravitational with distance R from potential the V centre 1 of the planet for values of R greater than R , where p 6 R = 2.5 × 10 m. p 3. The diagram shows equipotential lines due to two objects 6 R/10 m 1 5 10 15 0 gk J object 1 object 2 1 01/V 6 2 3 4 5 6 The two objects could be 7 A. electric B. masses charges of the same sign only. 8 9 only. 10 C. electric D. masses charges of opposite sign only. Use or electric charges of any sign. (i) 4. The Space the Earth. the Space 6.0 × Shuttle The orbits shape of about the 300 orbit is km above circular, the data from the graph to [1] the and surface the mass determine a value of of of g . [2] 0 (ii) show that the minimum energy required to 4 Shuttle is 6.8 × 10 kg. The mass of the 24 10 Earth raise is a satellite and radius of the Earth is 6.4 × 10 mass 3000 kg to a height 6 6 kg, of 3.0 m. × 10 m above the surface of the planet 10 is a) (i) Calculate the gravitational launch and change in potential its arrival the Space energy in orbit. about 1.7 × 10 J. [3] Shuttle’s between its [3] i B Q u e s t i o n s – f i e l d s 111 11 E l E c t r o m a g n E t i c i n d u c t i o n ie eee e (e) HL inducEd Emf When a production of inducEd Emf by rEl ativE conductor moves through a magnetic eld, an emf is motion induced. The emf induced depends on: An • The speed of the wire. emf ux is are induced cut. situation; • The strength • The length of the magnetic the wire in the magnetic can calculate the magnitude the of the induced considering an electron at a conductor is more whenever than mathematical just a lines way of of magnetic picturing the denition. magnetic equilibrium in ux eld ∆ϕ is perpendicular passing through to the the area surface, ∆A is the dened in emf terms by a eld. magnetic We has in ux eld. If of it But the of the magnetic eld strength B as follows. middle ∆ϕ of the wire. The induced electric force and the magnetic _ force ∆ϕ = B ∆A, so B = ∆A are balanced. ϕ In negative end a uniform eld, B = A B B An F alternative name for ‘magnetic eld strength’ is ‘ux density’. m electric eld down wire If the area is not perpendicular, but at an angle θ to the eld due to charge separation lines, potential the equation becomes 2 ϕ charge q = B A cos θ (units: T m ) length l dierence V θ F is the angle between B and the normal to the surface. e B B v Flux 1 due to emf, F = E × q = e ( ) × force due to movement, F be measured in webers (Wb), dened as follows. = = 1 T m relationships allow us to calculate the induced emf ε in q a l Magnetic Wb These V force also 2 positive end Electrical can moving wave is terms of ux. B q v m in a time ∆t: V So B q v = ( l q ) l V = B l v N As no current is owing, the emf ε = ε If the wire was part of a complete = potential S difference B l v circuit (outside the magnetic area swept out ∆A = l∆x ∆x eld), the emf induced would cause a current to ow. ∆x _ ε = B l v since v B l ∆x _ = then ε = ∆t × B × × × × × × × ∆t boundary of B but l ∆x = ∆A, the area ‘swept out’ by the conductor in a time B ∆A ____ ∆t so ε = ∆t b c ∆ϕ ___ but × × × × B ∆A = ∆ϕ so ε = ∆t ex ternal agent coil emf exer ts force F In words, ‘the emf induced is equal to the rate of cutting of ε × × × × × × a × × × ux’. l If the conductor moved, the same is effect kept is stationary and the magnets are produced. × velocity v × d × E x amplE induced 1 An current I × × × aeroplane that can be Vertical If this situation was repeated with a rectangular coil with each total section emf 200 ab would generate an emf equal to generated m generated will thus across magnetic across eld = 10 × 30 × B v l N that in one side and the was inside emf. 112 the the other The would of side the two situation coil (ab) (cd) is magnetic emfs above, is a moving outside eld, would current through the each oppose eld. side one only the If ows would another whole generate and no eld coil an current ow. E l E c t r o m a g n E t i c = 6 × 10 = 0.06 when magnetic the = wings be 2 Note Estimate the maximum wings. 5 emf = . its 10 T (approximately) Bvl. 5 ε s component Earth’s Length The at N of turns, ies × i n d u c t i o n V V 200 = 30 m (estimated) pd le' f' HL transformEr-inducEd Emf lEnz’s l aw Lenz’s law states that An emf is magnetic ‘The direction able to ow, of it the induced would oppose emf the is such that change if which an induced caused current also produced eld changes in a with wire if the time. were it.’ If the turn amount of a coil of is ux ϕ, passing then the through total ux one linkage (2) (1) with I all N turns Flux of linkage the = coil N is given by ϕ motion The universal situations S N N rule that involving applies induced to all emf can now be S stated as motion ‘The magnitude proportional to of an the induced rate of emf change is of ux linkage.’ Current induced in this direction, ∆ϕ _ This the force would be upwards is known (left-hand rule) ∴ original motion would Faraday’s the magnet combined opposing motion. law can be explained in terms of the conservation of energy. The and Lenz’s together mathematical generated law Faraday’s law ε = N ∆t the induced eld would repel be opposed. Lenz’s as If current were induced this way, in in the statement a coil law of N can be following for the turns emf, with a ε, rate of ∆ϕ electrical ___ change of ux through the coil of : Δt energy generated within any system must moved through result from work being done on the ∆ϕ _ system. When current ows, a conductor is a magnetic eld and an ε induced = -N Δt an external force is needed to keep the conductor moving (the The external force balances the opposing force that Lenz’s law predicts). The does work and this provides the energy for the current to another change the that case, object way, the caused then which generated if a it, force would without direction then it would an would be generate work of be acting generated an being induced even to that greater current did support further emf – not the oppose change. accelerated electrical and the the number of rate of turns change is of Faraday’s ow. law Put on external ux force dependence If the energy and the change) the this is negative Lenz’s sign (opposing the law. was moving would be done. applic ation of faraday ’s l aw to moving and rotating coils There are moving many or situations rotating coils. involving To decide magnetic whether elds or not with an Example: emf A is generated and, if it is, to calculate its value, the physicist Earth procedure • coil • can Choose At is to the be the μT) her passes hand so through that a the ring magnetic on her eld of the hand. of time, Δt, over which the motion of the considered. beginning through (50 used: period be holds following one of turn the of period, the coil, work ϕ . out Note the that ux the passing shape of initial the coil ϕ • At = the one is not relevant just the cross-sectional area. BAcosθ end turn of of the the period, coil ϕ work using out the the ux passing equation above. through Note that nal the of sense the the of eld the is opposite magnetic the same eld but direction, it is is important. passing If the through magnitude the coil in then 5 B = 5 × ϕ = • = the ϕ If there be in is no induced. a coil of change nal • T initial Determine Δϕ 10 -ϕ nal N ux, Δϕ: initial overall If in ϕ there turns ∆ϕ change is a will of ux change be: in then, ux overall, then the no emf emf will induced In 0.1 s, she magnetic Estimate quickly eld the of emf turns the her Earth no generated hand through longer in the goes 90° so through that the the ring. ring. Answer: _ ε = -N Δt 2 Estimate of cross-sectional 5 ϕ = 5 × 10 area of ring, A ≈ 4 × 10 1 cm 4 = 10 2 m 9 cos(0) = 5 × 10 Wb initial ϕ = 0 nal 9 ∴ ∆ϕ = 5 × 10 Wb 9 ∆ϕ 5 × 10 _ _ magnitude of ε = N = 8 = 5 × 10 V 1 Δt 10 E l E c t r o m a g n E t i c i n d u c t i o n 113 ae e (1) HL coil rotating in a magnEtic fiEld – ac rms valuEs If the output of an ac generator is connected to a resistor an gEnErator alternating The structure of a typical ac generator is shown current will ow. A sinusoidal potential difference below. means a sinusoidal current. coil (only one eld lines power, turn shown) 2 cur ve (not a sin cur ve) cur ve is a sin P (= V × I ) P B o C average A power N S D time P o = 2 carbon brush The graph shows that the average power dissipation is half the slip rings (rotate with coil) peak power dissipation for a sinusoidal current. 2 2 I R I 0 0 _ carbon Average power P _ = = 2 ( √ brush R ) 2 output Thus the effective current through the resistor is 2 √ ac (mean value of I ) and it is called the root mean square generator current or rms current, I rms The coil of external wire force. rotates As it in the rotates magnetic the ux eld linkage due of to the an coil I changes 0 _ I with time current and to induces ow. The an sides emf AB (Faraday’s and CD of law) the causing coil = √ force opposing the motion (Lenz’s law). The work the coil generates electrical ac coil rotating at constant speed will values square for value voltage current that is or being used. are In quoted, Europe it is this the root value is energy. 230 A currents) done mean rotating sinusoidal 2 experience When a (for rms a produce a V , whereas in the USA it is 120 V . sinusoidal V 0 _ induced emf. Increasing the speed of rotation will reduce V the = rms √ time period induced of emf the (as oscillation the rate of and increase change of the ux amplitude linkage is of 2 the 1 increased). P = V I rms = I rms V 0 0 fme decudni 2 P = I max V 0 0 V V V R rms 0 _ = = _ = I time I I 0 coil rotated constant speed of at double the rotation means induced speed emf is sinusodial rms transformEr opEration An alternating and an potential alternating iron core difference potential is put difference into is the given transformer, out. The value primary coil of or the output potential decreased) by difference changing transformer increases transformer decreases the the can turns voltage, be changed ratio. A whereas a (increased I step-up I p s step-down input ac the output ac voltage. voltage ε voltage ε p The following method • The for sequence calculating output turns voltage of all is calculations the relevant xed by the provides the s correct values. input voltage and the ratio. number of turns N number of turns N p • The value current of the (using V load = I that you connect xes the s output ε R). N = • The (P value = V of the output of the input power is xed by the values The for • The P So = how this ideal value V power is equal to the output power • transformer. of the input The coil current can now be calculated (using I). • p does the transformer manage to alter the voltages in on and hence the output i n d u c t i o n pd an alternating induces rate increased E l E c t r o m a g n E t i c structure alternating This and way? 114 I s I). value an N s Transformer • s = ε above I p p an of across magnetic emf. The change number voltages the primary alternating of are of eld links value ux turns related creates magnetic of eld with the linkage, an in the within iron emf depends increases on the secondary. by the turns the core. secondary induced which ac the The ratio. with input and ae e (2) HL transmission of ElEctric al powEr Transformers efcient play a very transmission of important electrical role in power the over lossEs in thE transmission of powEr safe and large In distances. of addition the warm • If large amounts of power are being distributed, then to power up, power supply there are losses lines, also associated which losses with cause the the associated resistance power with lines to non-ideal the transformers: currents used will be high. (Power = V I) • • The wires must cannot dissipate have some zero resistance. This means • 2 • Power dissipated is P = I R. If the current is large then of transformer result Eddy core. will be very Over large windings in the (joule heating) transformer warming of a up. distances, currents The are currents unwanted are currents reduced by induced laminating in the the iron core large. into • the the 2 (current) Resistance they power the power wasted would be individually electrically insulated thin strips. very • Hysteresis losses cause the iron core to warm up as a signicant. result • The solution is to choose to transmit the power at a potential Only a small Flux losses current needs to only A very high are 100% cycle of changes to its magnetism. caused potential efcient by if magnetic all of the ‘leakage’. magnetic A ux transformer that is ow. produced • continued difference. is • the very • high of difference is much more efcient, by the primary links with the secondary. but lamination very • Use dangerous step-up to the user. transformers to increase the voltage for the secondary primary transmission for the stage protection and of then the end use step-down transformers user. Current diodE bridgEs The efcient using the transmission alternating appropriate current V is of electrical (ac) and supplied. power is transformers Many electrical best can achieved negative ensure devices is negative) allowed but and is B ow from A prevented from following is to to B (A is positive from B to and A (A B is is positive). are, V rms d however, designed conversion on A from to ac operate into dc is using called direct current rectication (dc). The which relies diodes. diode is connected. direction allow with a two-terminal characteristics An ideal (negligible current reverse to electrical depending diode allows resistance ow in the device on current with reverse that which to forward has way ow in bias) direction different around the but (innite it is forward does not resistance tnerruc edoid electrical O bias). Symbol: diode voltage B A allowed current direction E l E c t r o m a g n E t i c i n d u c t i o n 115 re HL rEctific ation 1. Half-wave A single smoothing circuits rectication diode will Diode-bridge convert ac into a pulsating dc: direction a circuits (dc) but smoothing (see page provide still device 117 for a pulsates. is current In required. more that order One to ows in achieve possibility is a a one steady pd, capacitor details). + + + AC load + output from load supply rectifying circuit smoothed half-wave rectication voltage across voltage smoothed output load across load time time In half-wave available in rectication, the negative electrical cycle of energy the ac is that not is utilized. smoothed full-wave rectication 2. Full-wave rectication voltage A diode bridge (using four diodes) can utilize all the across electrical energy that is available during a complete unsmoothed output cycle load as shown below. time A + Note • that: The output output load is still uctuating slightly; this is known as the ripple AC B C+ • The capacitor is acting as a short-term store of electrical supply energy. • The • In capacitor order to is constantly ensure a slow charging discharge, and the discharging. value of the D capacitor constant C needs (see to page be chosen 118) is to ensure sufciently that the time large. voltage across load invEstigating a diodE-bridgE rEctific ation time circuit E xpErimEntally In the diode In bridge the the positive half from negative diode of cycle, current ows through the A→C→B→D. half bridge the of from the The display using cycle, current ows through D→C→B→A. The y-input Current same Diodes • The • always ac on signal positive negative • The During side each through control, display controls pd across oscilloscope allows allows a the changing an the load is best achieved (CRO). sensitivity pd appropriate on the of the y-axis. calibration of CRO The the the load resistor in the time period of the x-axis oscillations. the is fed to point the in points the same where directions. opposite ends join. of is two output of two taken from the junction of the diodes. is taken from the junction of the diodes. half-cycle one set of parallel-side diodes ch 1 che 1 ch 2 che 2 evy p evy p conducts. 1 time 1 base set oscillation at = 2.5 8 mS cm cm on screen 1 _ ∴ frequency = = 0.02 116 to time- e be sides output side negative positive • varying ray (C→B) parallel twodiodes The ows direction. • of the that: match • of cathode appropriately base Note a E l E c t r o m a g n E t i c i n d u c t i o n 50 Hz = 20 mS to ce HL The c apacitancE Capacitors is of are devices proportional to the proportionality is that pd can store across called the the charge. The capacitor capacitance V charge and the stored q constant capacitance different • C The of a parallel plate capacitor depends on three factors: area same of area each A plate, and • The separation • The material the of A. Each plates the plate overlap plates, is one assumed another to have the completely. d Symbol: dielectric between material. the plates Different which is materials called will the have different C values charge in coulombs of a constant permittivity of air called is its permittivity, effectively the same as ε. the 12 of a vacuum (free space), ε = 8.85 × The permittivity 2 10 C 1 N 2 m . 0 q C Thepermittivity = of all substances is greater than ε 0 V capacitance in The farads pd in relationship is: volts εA _ C The farad (F) measured is a µF , in very nF large or unit and practical capacitances A F = 1 C to be dielectric across the 2. parallel material dielectric is is introduced, induced. This change increases separation the capacitance. of the pd across a capacitance allows the charge calculated. c apacitors in sEriEs and parallEl The a V measurement stored d when pF . 1 1 = are effective total capacitance, C , of the combination In of total C 1 capacitors (C , C 1 , C 2 , etc.) in a circuit depends on whether 3 +q the capacitors capacitor are joined equation can together be used in on series or individual in parallel. capacitors The or q 1 1 on pd the V combination. 1 q q total 1 _ C q and C C 2 _ = total _ = , C 1 = , 2 etc. 2 V V total V 1 +q 2 q 2 1. In 2 series C C 1 +q q V 2 3 +q q + pd C 2 +q q + C + 3 +q q 3 V V 1 3 V 2 3 pd V 3 V total The charge stored in each capacitor is the same, q and the pd pds across the total the individual capacitors add together to total pd The q = q total = q 1 = q 2 = pd V = V total + V 1 + in give 3 the V q q total q q 1 _ C 1 total = V total q 3 q _ q _ = + = ∴ = V q + V total + = V 3 + q = 3 C total C V 1 + C 1 V 2 + C 2 V 3 3 V = C V + C 1 V + C 2 V 3 + ∴ ⋯ C = C + 1 C + ⋯ 2 2 capacitors 5 μF , 10 μF and 20 μF are added if three combined capacitance capacitors 5 μF , 10 μF and 20 μF are added in in parallel, the to C 1 e.g. series, charges 1 _ C three V 2 parallel if = q parallel = the together 3 ∴ series and add C 2 1 _ C V stored. 2 1 C _ C 1 1 _ same, capacitors + C series the C 2 q q C charge 1 total _ is individual + C ∴ capacitor the _ + total of 3 2 _ = C each each V 2 _ ∴ across q 3 stored e.g. V give the combined capacitance is: is: C = 5 + 10 + 20 = 35 μF parallel 1 _ 1 = 1 _ + 5 C 1 _ + 10 7 _ = 20 1 μF 20 series 20 _ ∴ C = = 2.86 μF series 7 E l E c t r o m a g n E t i c i n d u c t i o n 117 c e HL The product and is initial The SI pd multipliers). c apacitor (rc) dischargE circuits If the two resistor, a ends of current a charged will ow capacitor until the are joined capacitor is together with a discharged. τ V of given = RC the is called symbol τ the (the time constant Greek letter for the circuit tau). RC unit for τ will be seconds (NB: care needed with SI 0 t - +q ∴ q 0 q = q τ e 0 0 Since the charge, current the I and following the pd V equations are both also proportional to the apply: t - I when S is closed, = I τ e 0 switch S t - V = V the current I will ow τ e 0 Where in direction shown q V 0 0 _ I _ = = 0 R RC Example R A 10 μF capacitor Calculate During the discharge the value of maximum the I the is discharged time constant through τ for the a 20 kΩ circuit resistor. and (b) the process: fraction • (a) discharge down to current, I, drops from an of charge remaining after one time constant initial a) τ b) After = RC = 10 μF × 20 kΩ = 200 ms zero 0 • the value of the stored charge, q, drops from an one time constant, initial 1 q maximum q down to = q e = 0.37q 0 zero 0 0 • the pd value of across the the pd across resistor), V, the capacitor drops from (which an initial is also q/µC the maximum V 0 q = down Applying to V zero. Kirchoff’s law around the loop 0 C gives q 0 = IR + q exponential 0 C dq _ Since I is the rate of ow of e decay charge, dt q dq ___ 0 = R + O dt dq q _ _ = - RC dt This has stored. given t/ms RC C the The rate of ow solution is of an charge proportional exponential decrease to of the charge charge time charge 0 100% 1RC 37% 2RC 14% 3RC 5% stored by: time (s) t _ - RC q = q e capacitance resistance charge remaining 118 2% 5RC <1% (Ω) original After charge E l E c t r o m a g n E t i c 4RC (F) 0 i n d u c t i o n 5 time constents, the capacitor is effectively discharged c e HL c apacitor charging circuits If the is charged. two ends of an uncharged capacitor are joined together with a resistor, a current will ow until the capacitor C R when S is closed, the current switch S I will ow in direction shown until capacitor is charged emf During the charging ε process:, • the value of the charging • the value of the stored current, I, drops • the value of the pd across the capacitor, • the value of the pd across the resistor from an initial maximum I down to zero 0 charge, q, increases from zero up to a nal maximum value, q 0 V, increases drops from an from zero initial up to a nal maximum q/C ε maximum down to value, ε zero. I/mA ε nal charge = ε initial current = 0c q R 0 I 0 1 exponential q 1 ( e ) 0 growth I exponential 0 e O The equation for the RC increase of charge O t/ms on the capacitor (which decay does not RC need to be t/ms memorized) is: t q = ( q - 1 ) τ e 0 EnErgy storEd in a chargEd c apacitor A charged energy capacitor when there can is a provide a potential temporary difference V store of across electrical V/V the V 0 V 0 capacitor. one plate The charge, and q on q, that the is other stored plate is as distributed shown with below. +q There is V an electric eld between the (nal potential) on 1 0 plates. V 2 +q 0 2 (average potential) 1 q q area = 0 V 0 2 O pd q V Q/C 0 2 In the charging process, as more charge is added to the 1 E capacitor, the Thegraph pd across (right) it shows also how increases with charge stored in the the pd across capacitor the energy stored, E, is the 1 2 = 2 C CV 2 that represented by both charging and discharging are exponential charging the If a circuit is arranged in which a capacitor spends area equal under q = capacitor during processes. process.Thetotal 1 qV 2 proportionally. Note varies = time charging and discharging through the same value thegraph. resistor, to the then in capacitor the discharging the capacitor to one complete during time. the The charge up cycle, charging result to more time over the than several same E l E c t r o m a g n E t i c charge pd as it will loses cycles the be will power i n d u c t i o n added during be for supply. 119 ib Qe – eee HL 1. The primary of an ideal transformer has 1000 turns and the 5. Two loops of wire are next to 1 secondary the input 100 turns. power is 12 The current in the primary is 2 A each and W . There emf Which one of the following about the secondary the secondary power output is current 20 secondary power A 0.2 0.2 D. 20 in variation 1.2 alternating loop loop 1 and A ~ 2. A 12 A in with loop 1 time is of the shown as W 1 in each of the graphs below. In which graph 120 W 12 W represent the current in loop line 2 2? 1 1 I A does W best C. of to output line B. source 2 here. true? current A. a shown connected ammeter The secondary is as current an and other I 2 2. This question is about electromagnetic induction. t A small coil is placed with its plane parallel to a long 2 current-carrying wire, as shown t straight (no current) A below. B 1 1 I I current-carrying small coil wire t t 2 2 C 6. A D loop eld. A of A 4 cathode potential (i) State Faraday’s law of electromagnetic induction. (ii) Use in the the 3. The the through to explain changes, why, an when emf is the induced current in coil. diagram between [2] law wire [1] shows magnetic two V / ecnereid laitnetop a) a simple poles. brushes, generator Electrical each with contact touching a slip the is coil rotating wire Ω of negligible resistor ray is oscilloscope difference resistance connected measures across the is across rotated its the resistor in varying as a magnetic ends. shown induced below. 2 1.5 1 0.5 0 0.05 0.15 0.25 time / s 0.35 –0.5 –1 maintained ring. –1.5 –2 a) If the coil above N is how rotated at potential twice the speed, difference would show vary on the with axes time. [2] S b) What is the rms difference,V , value at the of the induced original potential speed of rotation? [1] rms c) At the instant when the rotating coil is oriented as shown, across the a graph showing resistor varies with how time, at the the power dissipated original speed of in the rotation. a) A 3μF capacitor is charged to 240 V . Calculate the brushes chargestored. A. is B. has its maximum C. has the Estimate same constant value as in all other rms direct current current rating would of an electric produce the heater same is 4A. power What The the time it would take for the charge have calculated connected to in the (a) 240 to V ow through mains a 60 W light electricity. 60 electric heater? charged W 240 V capacitor light in (a) is discharged [2] through a bulb. dissipation (i) in of direction. c) The amount orientations. bulb reverses the value. you 4. [1] zero. b) D. [3] the 7. voltage Draw Explain why the current during its discharge will [2] notbe constant. [2] 4 _ A. √ C. 4 A B. 4A 2A D. 8A (ii) Estimate time taken for the capacitor to 2 √ (iii) dischargethrough the Will during the Explain 120 the i B Q u E s t i o n s – E l E c t r o m a g n E t i c i n d u c t i o n bulb your light answer. light bulb. [2] discharge? [2] 12 Q u a n t u m HL a n d n u c l e a r P h y S i c S P Photoelectric effect Under (such certain as conditions, zinc), electrons einStein model when are light emitted (ultra-violet) from the is shone onto a metal surface Einstein surface. introduced thinking of light as the idea being of made up of particles. More detailed experiments (see below) showed that: His • Below a certain threshold frequency f , no photoelectrons are emitted, explanation was: no 0 matter how long one • waits. Electrons certain • Above the threshold frequency, the maximum kinetic energy of depends on the frequency of the incident The number of electrons emitted depends on the not depend escape intensity of the light and is no on the in a order from the energy surface. is called This the work does of the metal and given frequency. the There need energy light. function • surface minimum minimum • the these to electrons at noticeable delay between the arrival of the light and the emission symbol ϕ of • The UV light energy arrives in lots electrons. of These observations cannot be reconciled with the view that light is a wave. A wave little packets frequency should eventually bring enough energy to the metal energy – the of packets any of are called photons. plate. • The by energy the being in each frequency used, packet of UV whereas is xed light the that number is of StoPPing Potential e xPeriment packets window to The UV vacuum transmit UV stopping frequency of potential UV light depends in the on linear the by shown in the graph s V laitnetop gnippots micro- ammeter V variable power supply (accelerating pd) per of second the is xed source. The energy carried by a photon is below. given G arriving intensity way • (quar tz) the by Planck’s constant 34 6.63 E × 10 J = frequency energy s in joules light in of Hz frequency threshold frequency, f 0 • In the apparatus above, The are emitted by the cathode. They accelerated across to the stopping potential is a measure of anode potential maximum kinetic energy of the photon is electron surface potential the absorb energy of different the large enough, enough it energy gives to the leave the difference. Max The If by electrons. the electrons photons. are the then Different photoelectrons between cathode KE of electrons = V of the metal. e and • Any ‘extra’ energy would be energy _ anode can also be reversed. [since pd = retained by the electron as kinetic charge In this situation, the electrons energy. are and decelerated. At a certain value e = charge on an electron] of • potential, the stopping potential, V 1 ∴ no more photocurrent is observed. If the energy _ 2 mv = V e ∴ v = √ the have before at been brought to the photon will still is too gain of energy but it will this soon rest share arriving the electron m 2 The small, amount photoelectrons of 2V e , it with other electrons. anode. Above high-intensity UV the incoming threshold energy of frequency, photons = energy photocurrent needed to leave the surface + kinetic energy. low-intensity UV In symbols, of same frequency E = hf ϕ max V s potential hf = ϕ + E or hf = ϕ + V e max This means against that stopping a graph e x amPle line of the be a maximum velocity of gradient h _____ is frequency should e straight What of potential electrons 2 KE _ ∴ emitted from a zinc surface (ϕ = 4.2 eV) v = when √ m ______________ illuminated by EM radiation of wavelength 200 nm? 19 2 × 3.225 × 10 __ = 19 ϕ = 4.2 eV = 4.2 × 1.6 × 10 19 J = 6.72 × 10 34 c Energy of photon = h J √ 31 9.1 × 10 8 6.63 × 10 × 3 × 10 ___ = 5 = 8.4 × 10 1 m s 7 2 λ × 10 19 = 9.945 × = (9.945 10 J 19 ∴ KE of electron 6.72) × 10 J 19 = 3.225 × 10 J Q u a n t u m a n d n u c l e a r p h y s i c s 121 m ws hl of Wave–Particle duality The photoelectric light can behave demonstrated like all two – waves. effect like it of light particles, reects, So what waves but its refracts, exactly is clearly wave nature diffracts it? It demonstrates and seems can that also interferes reasonable be just to it but as nature 2. If ask light a correct wave Physics tries imagining or answer fundamental and to is it to a particle? matter this even question of is philosophical understand models can properties, de light light Broglie its and ’yes‘! level, explain behaviour. At the light what it Sometimes is is. it and most just can it complete. helps Light to is particle think just wave–particle show wave We do helps to have there wave should hypothesis properties be is a that link all and waves between moving can the have two this by think particles matter models. associated with them. This matter wave have can be a correct speed. of it light. as a This particle, dual duality properties, can particles such as properties? have probability function associated with the moving This wave experiment 1. At very these model ‘yes’. Most having does small not gaps. Once a people denite explain In again order they why to imagine size, electrons diffract have a moving shape, they dual position can be must nature. See below. high energies: situations, negligible is particles nature. the In The a answer little through the compared pc rest with = E energy their of the energy of particles can be motion. ‘matter thought example, particle. the rest energy of an electron (0.511 MeV) is of negligible a sometimes is called show as diffracted light. For wave’ as is waves the electrons de Broglie hyPotheSiS If of and model questions. Is The wave electrons Again 1. a neither if it has been accelerated through an effective potential The difference of 420 MV to have kinetic energy of 420 MeV . In 2 (amplitude) of the wave at any given point is a measure of the these probability of this wave nding the particle at that point. The wavelength is given by the de Broglie the total energy of an electron MeV . The de Broglie wavelength of 420 MeV 420 photons is the × 10 2.9 × 10 m 19 × 1.6 ×10 E 2. λ = 6 for is: 15 = hc _ = pc electrons 8 6.6 × 10 × 3.0 × 10 ___ λ hc _ = effectively equation: 34 λ is of 420 matter circumstances wavelength in At low energies m In these situations the relationship can be restated in terms of 34 h is Plank’s constant = 6.63 × 10 J s 1 the 8 c p is the is speed the of light momentum = of 3.0 the × momentum p of the particle measured in kg m s (in non- 1 10 m s relativistic mechanics, P = mass × velocity): particle h λ = p The higher equation a the was photon’s energy, the introduced wavelength lower on from the page its 69 de as Broglie the energy, E. wavelength. method In order of This calculating for the wave For example, electrons accelerated through 1 kV would gain a KE 16 of 1.6 × 10 J. Since KE and non-relativistic momentum are 2 p nature of particles to be observable in experiments, the particles 23 related by E = K often have very high velocities. In these situations the , this gives p = 1.7 × 10 1 kg m s 2m proper 34 6.6 × 10 __ calculations are relativistic but simplications are λ possible. = 11 = 3.9 × 10 m 23 1.7 electron diffraction e xPeriment In order through spacing to a will be gap in electrons show diffraction, of the crystal atoms impinges diffracted same an electron order as provides upon its according to the gaps. carbon If 10 daviSSon and germer e xPeriment (1927) ‘wave’ must wavelength. such powdered × a then travel The beam the atomic The diagram and Germer below shows electron the principle diffraction behind the Davisson experiment. of electrons lament wavelength. movable accelerating p.d. screen electron ~1000 V detector + electron ~ beam ϕ scattered electrons heater powdered vacuum T arget graphite The circles correspond interference carbon takes provides to place. every the angles They are possible where circles constructive because orientation of the gap. A powdered higher A accelerating potential for the electrons would result in a beam are momentum for each electron. According to the de of scattered the wavelength of the electrons would thus would mean bigger than circles would the constructive 122 that the size wavelength move in to interference of so there smaller are Q u a n t u m the gaps would angles. accurately a n d is now be The a target surface. The nickel crystal. intensity of The these electrons scattered their depends on accelerating the speed potential of the electrons difference) and (as the determined angle. proportionally less diffraction. predicted veried strikes the decrease. by This from Broglie electrons relationship, electrons higher angles The of experimentally. n u c l e a r p h y s i c s A maximum that scattered quantitatively condition from intensity agrees adjacent with atoms was the on recorded at constructive the surface. an angle interference HL a sp ss Different introduction As we have already absorption) electron seen, provide energy atomic evidence levels. See spectra for page the 69 (emission quantization for the levels. and of for the laboratory atomic The hydrogen: 1 = H wavelengths. Balmer spectrum of In Swiss found 1885 that a the atomic hydrogen consists schoolteacher visible wavelengths called tted of ( λ Jakob – m mathematical (see the – a have attempted model models page of to matter describe explain was the the these Bohr electrons by energy model using 125). 1 _ 2 2 m n particular Johann a modern 1 _ R λ emission models quantum wavefunctions set-up. hydrogen SPectrum The rst ) wavelength whole number larger than 2 i.e. 3, 4, 5 etc formula. These wavelengths, shown to be just wavelengths known one that all of as the several had Balmer similar similar series, series formulae. of were later can the Lyman For the Balmer (n possible These For = 3), each be series series Brackett case the of (n n = constant lines = 4), R , 2. (in the The and other the called ultra-violet series Pfund the (n range) are = Rydberg the 5) n = 1. Paschen series. In constant, has H 7 expressed in one overall formula called the Rydberg the formula one unique value, 1.097 × 10 1 m . e x amPle The diagram emitted below when an represents electron some falls from of n the = 3 electron to n = energy levels in the hydrogen atom. Calculate the wavelength of the photon 2. energy level / eV 0 0.9 1.5 n = 3 ‘allowed’ energy levels 3.4 n = 2 ground state: n = 1 13.6 19 Energy difference in levels = 3.4 1.5 = 1.9 eV = 1.9 × 1.6 × 10 19 J = 3.04 × 10 J 19 3.04 × 10 __ E Frequency of photon f = = 14 = 4.59 × 10 Hz 34 h 6.63 × 10 8 c Wavelength of photon λ 3.00 × 10 __ = = 7 = 6.54 × 10 m = 654 nm 14 f This is in the visible part of 4.59 the × 10 electromagnetic spectrum and one wavelength in the Balmer series. + When Pair Production and Pair annihil ation Matter and absorption place page be a but • in radiation or emission absorption 73, for every The other e an is not by restricted matter spectra, matter antimatter of are radiation emission property antiparticle + or of ‘normal’ corresponding every interactions particle opposite. electron, that which For e (such above). particle to As the as if takes introduced exists, has they the there same mass β ) is a electron two combined initially sufcient one e and photons. momentum zero, directions. and example: (or on will an create then The the reverse energy can antimatter). a positron Each of two the Much masses of the particles with energy of the particles that is the any will also into of annihilate has a a be of energy excess pair travelling possible pair typically momentum electron–positron photons process convert e photon – goes going in opposite photons particles into into of (one the the and was matter rest kinetic positron, have been created. Typically for pair + (or β ) production to take place, the photon needs to interact with a + • The antiparticle for a proton, p is the antiproton, p nucleus. • The When they antiparticle a particle annihilate radiation. certain energy, As for and one seen on conservations momentum a its neutrino, ν is an corresponding another page and and and 78, in the these antineutrino, antiparticle mass is converted annihilations particular the ν must conservation involved that meet into The in must nucleus the take momentum, is overall place. the not changed conservation Without interaction its in of the momentum ability could not interaction to ‘absorb’ but and is energy some of the occur. obey of charge. Q u a n t u m a n d n u c l e a r p h y s i c s 123 HL B The Bohr model Niels Bohr atom and orbits, took lled there the in are standard the only ‘planetary’ mathematical a limited model details. number of of the Unlike hydrogen makes planetary ‘allowed’ second predict the a postulate transition = E electron. Bohr suggested that these orbits used (with radiation between stable the full emitted equation) when an to electron orbits. E 2 the be of orbits hf for can wavelength had 1 xed 4 m e 1 _ e multiples of angular momentum. The orbits were _ quantized by terms this of angular momentum. quantization were in The exact energy levels agreement h 2 ) 2 n 0 predicted with ( 2 2 8ε in 1 _ = n 1 2 c the but f = λ discrete wavelengths of the hydrogen spectrum. Although this 4 agreement with experiment is impressive, the model has e m some 1 associated with λ it. 8ε ( 3 ch 2 postulated An electron The only where does stable the not radiate orbits angular energy possible for when the momentum of in a electron the orbit stable are ) 2 is should be noted that: orbit. • this • the equation is of the same form as the Rydberg formula. ones an values predicted by this equation are in very good integral agreement h multiple n 1 that: It • 2 n 0 Bohr 1 _ = 2 problems 1 _ e _ ∴ with experimental measurement. 34 of where h is a xed number (6.6 × 10 J s) 2π • called Planck’s constant. the Rydberg constant can be calculated from other (known) Mathematically constants. Again the agreement with experimental data is good. nh _ vr m = e 2π [angular The momentum is equal to m When electrons absorb) move between • stable orbits they radiate (or the same other atoms • = if of energy. F centripetal to this model are: vr] e • limitations the or rst approach elements, ions it with postulate is used fails more to to than (about predict predict one angular the the emission correct spectra values for electron. momentum) has no force electrostatic theoretical 2 e _ justication. v m 2 e _ = ∴ 2 4πε • r r theory predicts that electrons should, in fact, not be stable 0 in nh _ but v [from = 2πm 1st ε n orbits around a nucleus. Any accelerated electron postulate] r should e 2 circular radiate energy. An electron in a circular orbit is 2 h accelerating so it should radiate energy and thus spiral in to 0 _ ∴ r = (by substitution) 2 πm the nucleus. • it is unable to account for • it is unable to account for e e Total energy of electron = KE + PE relative intensity of the different lines. 2 1 where KE e _ 1 2 m = v the ne structure of the spectral lines. = e 2 2 (4πε r) 0 2 e _ and PE = - [electrostatic 4πε PE] r 0 4 1 so total energy E = e _ - e _ = - n 2 4πε 2 r 8ε 0 This • nal the equation electron overall it is has e m 2 shows bound n 2 h 0 that: to negative 2 (= ’trapped by’) the proton because energy. 1 • the energy of an orbit is proportional to – . In electronvolts 2 n 13.6 _ = E – n 2 n The nucle ar radii and nucle ar denSitieS Not s u r p r i s i n g l y, more massive nuclei have larger volume of 4 V Detailed analysis spherical of the distribution of data implies positive that charge the with nuclei an have d e n s i t y. The results are consistent nucleus, 4 3 = πR V, of radius, R is given by: = 3 πAR 0 a 3 3 essentially Where constant a radii. with a the mass number A is equal to the number which the protons and neutrons can be nucleons 3A _ A The in of model imagined to number of nucleons per unit volume = = 3 be V 4πAR 0 hard spheres that are bonded tightly together in a 3 _ sphere = 3 4πR of constant d e n s i t y. A nucleus that is twice the size of a 0 27 3 smaller nucleus will have roughly 8 (=2 ) times the mass. The mass density The can nuclear be radius modelled R by of the element with atomic mass number ρ of a nucleon = Where R A 1.7 × 10 kg), 3 × 1.7 × 10 __ so the 17 = = 3 15 4πR R (≈ nuclear 27 3m _ ρ = m A relationship: 1 R is is: 3 4π(1.2 × 10 2 × 10 3 kg m 3 ) 0 0 This 15 is a constant roughly equal to 10 m (or 1 is a vast density (a teaspoon of matter of this density has fm). 0 12 a 15 R = 1.2 × 10 m = 1.2 mass ≈ 10 kg). The only macroscopic objects with fm. 0 density e.g. The radius of a uranium-238 nucleus is predicted to be 1 15 R = 124 1.2 × 10 × (238) Q u a n t u m 3 m = 7.4 a n d fm n u c l e a r p h y s i c s as nuclei are neutron stars (see page 200). the same HL t S • Schrödinger model Erwin Schrödinger waves and using to • proposed wave give a The (1887–1961) an mechanics. physical alternative The meaning description quantum of has wavefunction does. ψ is • At a complex is no on the model of Copenhagen to the particles mechanics wavefunction • built in concept the (matter physical of hydrogen of and/or a wave radiation) but the than atom is a electron varying other • any instant different The and The at square any of of in of a of The the how with wavefunction of nding in has different square of particle • When in an a wavefunction wavefunctions particle within of develops is like with in the wave. the space the photon, The but the absolute the given and etc.) standing for to the (electron atom is or at by that waves energy of ψ,|ψ , density is of a real is made complete be on reasons the observed a string the wavefunction physical to be have same is particle at a one xed not true is for point. the said As an electron moves actual likely position 1s orbital in lose kinetic in as a be ‘cloud’ in space some is of places undened. hydrogen from total energies orbitals. it is the In more for the general likely as to energy because they be that energy found at a of result the further 18 = -2.18 × 10 J 1s 5 10 15 20 25 18 = -0.545 × 10 J 2s to 5 or 10 15 20 wavelength the from have electron the nucleus. 25 2p electron the nucleus 10 15 20 25 it 18 = -0.242 × 10 must to location. for away xed increased 5 wavefunctions. the possible is the (electron other away number nding are different distance place. the will value cloud electron photon, given wavefunction probability observation collapse, visualized values There this other amplitude corresponding be more the 2 • its is This square space. travelling point the but can 1s time, interacts probability etc.) places, It in ψ. ytisned ytilibaborp • of points mathematics orbital density. number mathematics time this way Electron at in electron mechanics. wavefunction meaning The matter interpretation mathematics terms of opposite J charges. 3s Lower a kinetic lower energy momentum means and that the de it would Broglie be travelling relationship with predicts a 5 longer that The wavelength. t the This boundary wavefunction means that conditions provides a the have way of possible particular nding point is a an electron measure of at that working the particular out probability of radius. the |ψ nding 15 20 25 3p shapes. probability 5 2 of 10 wavefunctions at the any given electron 10 15 20 25 at 3d that distance away from the nucleus – in any direction. 2 p(r) = | ψ ∆V 5 10 15 20 25 10 probability space, of detecting the electrons in a small volume radius (×10 of Probability The it wavefunction hard to exists visualize. in Often all the three dimensions, electron orbital is which makes pictured as atom. The exact position of the electron is not known but The where it is more likely to scale on wavefunction functions the for vertical some axis is orbitals in different the from hydrogen graph is central to quantum mechanics to and, graph. in we principle, know density a The cloud. m) ∆V should be applied to all particles. be. Example: In Schrödinger’s model there are different wavefunctions depending A on the total energy of the electron. Only a few particular particle is described as the following wavefunction: energies Ψ in in the at any an have ground given electron nding • wavefunctions only The it state time of at these a of distance the a can distance orbital The the energy in be this the of –13.6 model. to from of an atom. eV , The but the – electrons An its electron position wavefunction calculate electron nding probability conditions within of used away for boundary energies undened probability away. t total energy given resulting terms has is this that particular the for probability of nucleus. can the be described electron nding the at a in certain electron at orez si L edistuo can noitceted fo ytilibaborp result B x A probability of mid-point detection outside L L is zero L a 2 given distance away is shown in the graph below. ǀΨǀ % / ytilibaborp 100 80 60 x A 40 B 20 0 The 0 particle will not be detected at the mid point and the 5 distance from nucleus / 10 10 m probability of detection Q u a n t u m a n d at A = probability n u c l e a r of detection p h y s i c s at B. 125 t hsb pp ss hl s The heiSenBerg uncertainty PrinciPle The Heisenberg fundamental limit measurement. quantum of impossible a a arises and given less vice not because as a precisely They the of any the of and the momentum is it position known variables was and in are is this called quantities mathematical by exactly precise relationship linking these uncertainties. is to It has of can never out been a the (in – are profound. physical e.g. world Newton’s principle) deterministic. single even and us not a various this precision to Before was laws. make best A absolute future. is of the of theories allows the results takes work lack introduced, mechanics position future this theory about the principle of was deterministic probabilities its h _ ∆x∆p described Quantum momentum the theory predictions (or that implications quantum deterministic of ability precisely linked physical showed position a nature the He more are of result the The identies accuracy experimenter. exactly versa. principle possible limit measure the and conjugate is the simultaneously. determined, There This any to particle instant, to mechanics otherwise) of uncertainty possible further. range suggested of a determined of science only we for its would The at ever gives cannot particle precisely. possibilities that cannot It outcomes. Since momentum be It experiment. the uncertainty know any The predict us the given best we time, can do future. allow us to ≥ 4π calculate As ∆x The uncertainty in the measurement of the Heisenberg The uncertainty Measurements of energy in the and measurement time are also so long as himself said, it we is know not the the present conclusion exactly. of this position suggestion ∆p future of that is wrong but the premise. momentum linked variables. h _ ∆E∆t ≥ 4π ∆E The uncertainty in the measurement of energy ∆t The uncertainty in the measurement of time This eStimateS from the uncertainty PrinciPle Example calculation: The position of a proton is the measured 11 with an accuracy uncertainty in of the ± 1.0 × proton’s 10 m. position What 1.0 s is the calculation right (ground minimum later? 2. order state Impossibility is of of of a very rough magnitude electron an in H electron estimate for the atom but correctly electron’s is existing 13.6 kinetic predicts energy eV). within a nucleus of anatom. h _ ∆x∆p h _ ≥ ∴ ∆x × m∆v ≥ 4π 4π The above calculation can be repeated imagining an electron 14 being trapped inside the nucleus of size 10 m. If conned 34 h _ ∆v 6.63× 10 ___ ≥ = 27 4π×1.67×10 4πm∆x to 11 a space this small, the electron’s kinetic energy would be ×1.0×10 8 estimated to be a factor of 10 times bigger. An electron with 1 = 3200 m s an Thus The uncertainty uncertainty general in position principle principles but, to after can 1.0 also quote be s = 3200 applied Richard m to = 3.2 km illuminate Feynman energy nucleus some 3. Estimate on Physics, volume III, 1963), ‘[the of be taken too seriously; the idea is right but application] the order it of 100 would lifetime spectral of MeV have an cannot enough electron in be bound energy an to excited to a escape. analysis is linewidth associated with an energy atom’s state. emission must spectrum not the thus (Feynman The lectures of and not is usually taken to be very small – only discrete very wavelengths are observed. As a result of the uncertainty accurate’. principle, 1. Estimate When then the of an the size the energy electron is the uncertainty in atom, for its an known uncertainty of of a. its If electron to be Δx equate momentum an conned position we in can there within must the be atom. be two, an less this estimated atom, than means the with any with the is as: as h _ ∆p ≈ we take this be very given small. is, estimate can uncertainty be in range and difference An state however, limited transition energy excited the linewidth a of thus the between of the made energy, not proportional ΔE, the to the average of a lifetime, the in electron the momentum (∆p≈p), the as a value equations of for h _ the ∆E∆t ≈ classical 7 mechanics can estimate the kinetic energy of the If electron: ∆E = ∆t ≈ 5 × 10 eV 2 34 2 p 6.6 × 10 ___ h _ _ E = ≈ 7 K 2 2m 32π 2 4π ma × 5 × 10 19 × 1.6 10 10 The so diameter the of a estimation hydrogen of the atom kinetic 34 (6.6 × 10 is approximately energy is: ≈ 126 19 = 2 32π 1 31 × 9.3×10 m, 2 ≈ K 10 ) ___ E associated of levels an associated involved electron uncertainty transition Δt, 4πa uncertainty of two lifetime using Practically, uncertainty the 4π momentum zero. wavelengths is in principle inversely h _ ≈ 4π∆x If very the the will 10 × (10 1.5 × 10 J 2 ) eV Q u a n t u m a n d n u c l e a r p h y s i c s = 6.6 × 10 ≈ 1 ns ×10 in the excited state: t , p b s hl pbb Heisenberg’s the uncertainty quantum considered is is the less than relationship phenomenon a particle energy of that it is can be tunnelling. trapped needs to used The because escape (U ). to explain situation its In energy The energy being is E strong classical less being than of the the force emitted total within formed the inside alpha potential nucleus. the particle energy If uranium is 4.25 needed we imagine nucleus, it MeV to which escape an can the alpha only particle escape 0 physics, from if the a particle does potential not barrier have then enough it will energy always to escape remain by trapped tunnelling the very through long half-life the potential must mean barrier. that the In this example, probability of the 2 inside with two the a system. total walls An energy that are example of 4 1.2 J m would bouncing high. In be up a 500 and order to g tennis down get ball tunnelling process taking place (given walls, mgh = the 0.5 trapped × by tennis 10 the × ball 1.2 = needs 6 J. to have Since it a over one potential only has 4 ) must be very low. between of wavefunction of the ψ by J energy it must of repulsive Coulomb alpha par ticle potential ∝ 1/r remain walls. U In an equivalent U an atom needed to with energy escape), the situation E which rules of is (e.g. less an electron than quantum the physics trapped )r(V ygrene inside microscopic energy mean 0 that it is now possible wavefunction to zero when is it for the continuous meets the particle and sides to does of the escape! not drop The particle’s immediately potential well but X r nuclear the surface amplitude has a decreases nite width exponentially. then the This means wavefunction does that if the continue barrier on the attractive other side there is of the barrier (with reduced amplitude). Therefore nuclear a probability that particle will be able to escape despite potential not having does not enough use up energy any of to the do so. Escaping particle’s total the potential well energy. Example 2 – tunnelling electron microscope In a scanning tunnelling microscope, a very ne metal tip classically forbidden region is a scanned sample close metal to, but not surface. touching There is a (separated potential by a few difference nm), between U 0 the probe and the surface but the electrons in the surface do not E have enough energy to escape the potential energy barrier as par ticle energy represented however, by take wavefunction the work place of an and function a ϕ. Quantum tunnelling electron at the current surface tunnelling will will ow extend as can, the beyond incoming par ticle the wavefunction metal electrical par ticle wavefunction depends past the barrier used Ψ to surface. current on the Some will be electrons measurable. separation visualize atomic will of the tip tunnel The and the value the gap of the surface and current and can be structure. Ψ incident exit Reduced probability, but not reduced energy! An explanation principle. greater In total can order be for energy offered the (E + in terms particle ΔE = U to ). of the escape The it uncertainty would particle can need sample a ‘disobey’ 0 tip the law energy of conservation ΔE provided uncertainty it principle of energy ‘pays it by back’ ‘borrowing’ in a time Δt an amount such that of the applies: tunnelling h _ ∆E∆t current ≈ 4π path of The longer the barrier, the more time it takes the particle to the probe tunnel. possible Increased tunnelling uncertainty in the time will reduce the maximum energy. scanning tunnelling surface Example 1 – alpha decay microscope (STM) The protons within nuclei energy. 4.5 and For billion and It form emitted by alpha overall has emitting a particles there is a half-life an alpha already release of of sample exist of about particle: 4 Th 90 that uranium-238 decays 234 U→ 92 when example years. 238 neutrons + α 2 Q u a n t u m a n d n u c l e a r p h y s i c s 127 t s hl the nucleuS – Size In the gold example below, e x amPle alpha particles are allowed to bombard atoms. If the α particles approach to the have gold an energy nucleus (Z of = 4.2 79) 19 As they approach the (2 × 1.6 × 10 MeV , is the given closest by 19 ) (79 × 1.6 × 10 ) ____ 12 gold nucleus, force of they repulsion. feel If a 4 × π × 8.85 × 10 × r an alpha particles 6 alpha particle directly for is the = heading nucleus, 4.2 × 19 × 10 1.6 × 10 it 19 2 × 1.6 × 10 × 79 ___ ∴ nucleus will be back reected along the r = 12 straight 4 × π × 8.85 × 6 10 × 4.2 × 10 same 14 = 5.4 × 10 m closest approach, r path. It will close as it collides Alpha have can. with Note the particles energy. As got that none nucleus are they as – emitted come in of they the do from they alpha not their gain particles have actually enough source with electrostatic energy. a nucle ar Sc attering e xPeriment involving known potential electronS energy and lose kinetic energy (they slow down). At the Electrons, closest approach, the alpha particle is temporarily electrons and all its energy is as leptons, do not feel the strong force. High-energy stationary have a very small de Broglie wavelength which can be potential. of q the right order to diffract around small objects such as nuclei. q 2 ____ Since electrostatic energy = , 4πε and we know q , the charge The diffraction pattern around a circular object of diameter D 1 r 0 on an alpha particle and q , the charge on the gold nucleus we has its rst minimum at an angle θ given by: 2 can calculate r. λ sin θ ≈ D [Note that this small angle approximation is usually not de viationS from rutherford Sc attering in appropriate to use to determine the location of the minimum high energy e xPerimentS intensity Rutherford scattering is modelled in terms of the around repulsion between the alpha particle and the but this is being used to give an approximate answer coulomb target a spherical object. A more exact expression nucleus. that is λ sometimes used for circular objects is sin θ = 1.22 ] D At relatively low energies, detailed analysis of this model High accurately predicts the relative intensity of scattered energy at however, given the angles scattered of scattering. intensity At departs high from (400 MeV) electrons are directed at a target alpha containing particles carbon-12 nuclei: energies, predictions. Fixed scattering angle, electron beam range of alpha xed θ par ticle energies detector detector thin sample α 60° + scattering The results are shown below: angle 208 Pb lead target intensity of 82 diracted The scattered intensity electrons derettacs fo ytisnetni evitaler depar ts from the Rutherford (logarithmic °06 ta selcit rap ahpla scattering formula at about scale) 27 .5 MeV 2 10 35 diraction angle (θ) 10 alpha The rst The de minimum is θ = 35° energy Broglie wavelength for the electrons is effectively: in MeV 34 hc _ λ 8 6.6 × 10 × 3.0 × 10 ___ = = Eisberg, R. M. and 20 Porter, 25 C. E., 30 Rev. 35 Mod. 400 40 Phys. 33, 190 high energies the alpha particles are beginning to 10 1.6 × begin enough to nucleus box on 128 have in the to the an more target effect. detail, In nucleus order high to for the strong investigate energy electrons nuclear = θ 15 = sin 5.4 × 35 get the can size be force of to the used (see right). Q u a n t u m a n d n u c l e a r p h y s i c s × 10 15 close 3.1 19 × 3.1 × 10 __ λ _ ≈ sin these × 15 (1961) D At 15 = 6 E 15 So radius of nucleus ≈ 2.7 × 10 m 10 m 10 m HL n s energy le velS 226 The The energy levels in a nucleus are higher than the energy levels decay of 222 Ra into 226 Rn of Ra 88 the a electrons gamma are but photon observed. two the nuclear is principle emitted These the from energies energy is levels same. the nucleus correspond in the When to same only the way an alpha discrete difference that particle the or energies between photon energies α correspond to the difference between two atomic energy levels (4.59 MeV) Beta particles energies. the In are this observed case case of beta amount of energy to there minus is have continuous another decay) released a that in the particle shares decay the is spectrum (the antineutrino energy. xed α of by Once the (4.78 MeV) in again the 222 difference Rn* excited state between the nuclear energy levels involved. The beta particle and γ the photon 86 ground antineutrino can take varying proportions of the energy available. 222 (0.19 MeV) The Rn state antineutrino, however, is very difcult to observe the undetectable needed and the to existence particle, account (angular) decay decay of the for properly a the difference It ‘missing’ momentum mass virtually neutrino. mathematically. involving requires when is energy analysing Calculations mean that for the how much energy is → ν has form place, decay. For example, isotope + β + ν an antineutrino mentioned radioactive namely before, decay positron can decay. another also In take this we available an equation 1 been of full is: 0 He is The tritium 2 where As existence. of 3 H 1 in 0 0.5 a proton within the nucleus 1 decays beta its decay 3 decay, know 86 below). snortcele fo rebmun accepting beta box conrmed neutrinoS and antineutrinoS Understanding (see into a neutron and the antimatter of energy / MeV version hydrogen, tritium, decays as of an electron, a positron, which follows: 3 The 3 3 H → distribution of the electrons is emitted. 0 He 1 energy + β 2 emitted in the beta decay of bismuth-210. 1 1 1 p → mass difference for the decay kinetic energy of these electrons 0 n 1 The The + + β 0 + ν +1 is is + In between –2 19.5 keV c . This means that the zero and 1.17 this case, the should have 19.5 keV of kinetic The neutrino (and antineutrino) must In fact, a few beta particles are electrically neutral. Its mass would with this energy, but all the others to be very small, or even zero. It is less about than half this. this The value average and energy there antineutrino the decays seem gamma to follow photon. a is All similar is away no to the detect. excess One of energy the but it is triumphs very of beta particle pattern. to be physics able to of the design last e.g. hard the 19 Ne → antimatter + 9 14 C 0 F 10 14 the century experiments is form neutrino. → + β + ν +1 0 N 6 accompanying , neutrino. carries 19 have a have of emitted by be The energy. β MeV . beta accompanied particles positron, + 7 β + ν 1 was that mathematicS of e xPonential dec ay The basic relationship that In (N) denes e x amPle exponential decay as a random process is intercept = The expressed as follows: ln (N 0 gradient = -λ ) is half-life 10 days. of a radioactive Calculate the isotope fraction of a dN _ ∝ – N sample dt The that remains after 25 days. t constant of proportionality T between = 10 days 2 the rate of decay and the number of nuclei ln 2 _ λ available to decay is called the = decay T 2 constant and given the symbol λ. Its units λt N = N e 2 = 0 1 are 1 time i.e. 6.93 × 10 1 day 1 s or yr etc. -λt If t = T dN _ N 1 = N e 0 = -λN 2 N _ dt Fraction remaining = N The solution of this equation N = N 2 (6.93 e of a source, A, A = A = N = λN = e useful to take natural = 0.187 = 18.7% logarithms: ∴ (N) = λT 1 ∴ In ½ = -λT = - -λt ln 25) 0 2 e 0 2 is × e λt e 0 It 10 λT 0 So dt λt = × e _ dN _ activity A = N 0 The 0 = λt N N 0 _ is: ln (N e 1 ) 2 0 -λt = ln (N ) + ln (e ) ∴ 0 -λT 1 In ½ 2 = ln (N = ln (N ) λt ) λt ln (e) 0 ∴ ln (N) = (since ln (e) = of ln is N of the vs t form will 2 ln 2 _ ∴ This ln 1) 0 y give = a c + mx so a straight-line graph T 1 2 = λ graph. Q u a n t u m a n d n u c l e a r p h y s i c s 129 iB Qss – q pss hl 1. The diagrams show wavefunction Ψ horizontal axis electron the is of in the variation four all with different four diagrams uncertainty in distance electrons. the is the x The same. momentum of the scale For the R on the those which this constant From c) of the constant Ψ particles will not the that enter matter in the Geiger determining tube. the Explain decay sample. [1] largest? e) a) of why graph, determine a value for the decay λ. [2] Ψ The x 0 d) 0 f) Dene the g) Derive a h) Hence Ψ Ψ and 0 x now wishes to calculate the half-life. x 0 b) physicist x the half-life of relationship half-life a radioactive between the substance. decay [1] constant λ τ. calculate [2] the half-life of this radioactive isotope. 4. 2. The diagram represents the available energy levels of This How many emission lines could result from question biography between these energy of about the quantum Schrödinger concept. contains the following sentence: electron ‘Shortly transitions is an A atom. [1] after de Broglie introduced the concept of matter waves levels? in 1924, Schrödinger began to develop a new atomic theory.‘ energy a) Explain the determines b) Electron the term the ‘matter diffraction existence waves’. wavelength of of provides matter State such what evidence waves. quantity waves. What to is [2] support electron diffraction? 5. ground Light is maximum state [2] incident on kinetic a clean energy metal KE surface of the in a vacuum. electrons ejected The from max the A. 3 B. 6 C. 8 D. A medical physicist wishes to investigate the decay of the A Geiger–Müller sample of the determine counter isotope, as for different values of the frequency is its used decay to constant detect incident f light. and radiation measurements are shown plotted below. half- from 2.0 91 a and )J life. isotope measured a The radioactive is 12 of 3. surface shown. 01( voltage supply 1.5 xam and counter radioactive 1.0 K Geiger–Müller source tube 0.5 a) Dene the activity of a radioactive sample. [1] 0.0 4.0 Theory predicts sample should that the activity A of the isotope in 4.5 5.0 5.5 6.0 6.5 7 .0 7 .5 8.0 the 14 decrease exponentially with time t f according (10 H z) -λt to the equation A = A e , where A 0 and b) λ is the decay Manipulate straight this line variables if on for equation a semi-log the is the activity at t = 0 0 constant axes. the into a graph State a) Draw a line of best b) Use the graph (i) the Planck (ii) the minimum t for the plotted data points. [1] isotope. form is what which plotted will with variables give to determine a constant [2] appropriate should be plotted. electron [2] from energy the required surface of to the eject metal an (the work function). The Geiger emitted by the of particles as a graph counter detects source. detected of ln R as a The a versus proportion physicist function t, as of the records of time shown t the and count-rate plots the c) R data below. Explain Does the plot consistent show with an that the experimental exponential law? data briey how accounts for from surface the c) [3] particles the incident the Einstein’s fact of light is that this less no electrons metal than photoelectric if a the Explain. [1] 6. certain of value. Thorium-227 days to (Th-227) form undergoes radium-223 a-decay (Ra-223). A with [3] a sample half-life of of Th-227 1 ) 5 2 has an initial s / R( nI Determine 50 1 7. activity the of activity 3.2 of × the 10 Bq. remaining 1 2 3 4 The role of angular momentum in Geiger activity A counter of i B the does sample, not but measure rather Q u e s t i o n s b) Pair c) Quantum the Bohr model for [3] production and ahnihilation [3] 5 t / hr The after [4] hydrogen 0 thorium-227 days. Explain: a) 130 emitted frequency are 18 d) are theory – the the tunnelling total count-rate Q u a n t u m a n d n u c l e a r p h y s i c s [3] 13 O p T i O n a – R e l a T i v i T y Rr r The ObseRveRs and fRames Of RefeRence The proper treatment understanding thinking The reasons pages, from this but two is A not case we sitting the sitting the the a of so chair in are to relativity developed simple. will In this we apply way. that of the Newton’s relative like all velocity the velocities laws to are small different to object’s motion (or the view the think this mean point motion. that must situation. Sun’s in lack by is possible frames frame be of of to formalize reference. reference recorded in The to of the it) of This depends be The view they true, Earth the example on are but this another without taking is to out frame the called The Galilean simplest (S and as shown S') able be to reference. is in orbit person the shows that use the of between the two The that an different measurement measurements reference. theory of relativity …or moving at great velocity? observer. in of reference Since measurements one would equations into frame event. y' = y; z' = the will z; t' can relative be = the record the motion is position along the and time x-axis, of most same: t that an event is stationary according to one frame, it will be frames will record consideration according to the other frame – the transformations. situation with to 9. far, at moving are of page so this If do enough frames on book why Each relationship idea work this an Galile an TRansfORmaTiOns It considered in follow see Is this person at rest… an was mechanics following logically order treatment, assumes means different the They what probably of viewing be in and calculation This an place. point must involves completely consider rst from of a assumptions. chair their way Sun, theory time change need in velocities surprisingly in from only the in and straightforward Indeed around this are motion person rest. is in for large Einstein’s space they the object of about of one to consider frame (S') is two moving frames past the of reference other one different values between the for two the is x measurement. given The transformation by (S) x' = x vt below. We t = zero (two frames on top of one another) can use velocities. these The equations frames will to formalize agree on any the calculation velocity of measured in y the y or z direction, but they will disagree on a velocity in the frame S (stationary) y′ x-direction. Mathematically, frame S′ u' = u v 1 For example, if the moving frame is going at 4 m s , then velocity v an object 15 m moving in the same direction at a velocity of 1 s as recorded in the stationary frame will be measured as 1 x travelling at Newton’s 3 11 m s in the moving frame. x′ laws of motion describe how an object’s motion is t = later effected. y frame S y′ laws all is An that assumption the observers. time Time (Newton's interval is the Postulates) between same for all two underlying events frames and is the the these same for separation frame S′ between the same events will physical also laws be will the same apply in in all all frames. As a result, frames. velocity v x x′ piOn dec ay e XpeRimenTs In 1964 Centre the an for speed experiment Nuclear of at the Reseach gamma-ray failuRe Of Galile an TRansfORmaTiOn equaTiOns European (CERN) photons If measured that the the speed of Galilean light has the transformation same value equations for all cannot observers work for (see box on left) then light. had velocity of bicycle, v been the speed also is produced to be of light moving consistent with independent high The by degree of of called gamma-ray and at the found the the moving these speed speed speed of of of to photons light. light its close This being source, to a accuracy. experiment particle particles analysed the the neutral photons. decay pion Energy into of a two considerations Light leaves the torch meant that the pions were known to Light arrives at the observer be at velocity c with respect moving faster than 99.9% of the speed of at velocity c (not v + c). light to the person on the bicycle. and the speed of the photons was 8 be 2.9977 ± 0.0040 × 10 1 m s measured to The theory of relativity attempts to work out o p t i o n A what – has gone wrong. r e l A t i v i t y 131 mx’ to maXwell and The cOnsTancy Of The speed Of liGhT In 1864 Royal James Society mathematical was known electric the two – the E, Maxwell London. form at eld Clerk in that time but it His elegantly about also Maxwell’s are summarized equations. These in new magnetic a ‘rules’ four not of only eld unifying B at in the The a – what and link predict to the as nature be electric technical allows between known the changing the through the electromagnetic equations equations theory encapsulated expressed the The a were proposed electromagnetism. interactions presented ideas way space. the The speed predicted. electric which and they magnetic saying physics of It and of all this of elds is how that these electromagnetic turns out magnetic that this constants elds be the through elds waves can of move the space propagate propagate (including done in medium light) terms of through travel. ____ of 1 _ electromagnetic c waves. = √ ε µ 0 Most people know that light is an electromagnetic wave, This it is quite hard to understand what this actually means. equation wave involves the oscillation of matter, whereas wave involves the oscillation of electric important elds. The diagram below attempts to show is need that to the be understood speed of light in is detail. The independent the velocity of the source of the light. In other words, a and prediction magnetic not idea an of electromagnetic does A only physical 0 but from Maxwell’s equations is that the speed of light in this. a z vacuum This an has the prediction of inconsistency same the that value for constancy cannot be all of observers. the speed reconciled of light with highlights Newtonian oscillating electric eld mechanics the speed forced and (where addition of of light as to be resultant relative speed speed measured long-held time the the by assumptions the of of the light source). about would source the and be the Einstein’s equal to relative analysis independence of space rejected. y x b) cOmpaRinG elecTRic and maGneTic fields Electrostatic one forces another. aspects nature of of and magnetic Fundamentally, one force which – eld the is forces however, appear they electromagnetic observed depends very are different just different interaction. on the to The observer. For example: a) A Two identically velocities An observer charge moving at right angles to a magnetic in the charged this observer charges charged according as a to frame particles sees solely the particles a moving laboratory of reference will force see of electrostatic the that of is parallel reference. moving particles repulsion in with frame at with rest. between Thus the two nature. eld. F E An observer respect to in a the frame of reference magnetic eld that will is at explain rest the with force acting +q on the charge (and its acceleration) in terms of a magnetic force between 2 stationary charges is electrostatic force (F = Bqv) that acts on the moving charge. M +q stationary magnetic eld into paper F E initial force on moving An observer in a frame of reference where the laboratory moving charge is magnetic X X X X is at rest will see the total force between the two charges charge as An observer respect to on the an induced in charge magnetic a the frame charge (and electric its of reference will initial force that explain the is acceleration) that results at rest initial from in with force terms the acting combination charges its of are own frame. of cutting a electrostatic currents magnetic Each magnetic of charge eld and eld and is thus which moving will and each is moving stationary in the experience a charge in other’s Moving the creates laboratory stationary magnetic force. ux. F E X X X X X X X X initial force on stationary & F M +q force between 2 moving objects is a combination stationary charge is electric X X X of electric and magnetic X charge +q moving magnetic eld F E 132 magnetic. o p t i o n A – r e l A t i v i t y & F M s rtt pOsTul aTes Of special Rel aTiviTy The special theory of relativity assumptions or postulates. be be wrong, shown to If then is based either the on of two these theory of This fundamental postulates relativity could would the When discussing relativity we need to be even usually precise with our use of technical two the postulates speed important technical phrase is an inertial frame This means a frame of reference in which the inertia (Newton’s laws) apply. Newton’s the laws do not apply is frames either of reference stationary or so an moving inertial with frame is a laws rst be constant important idea to between grasp being is that there stationary is and no Newton’s laws link forces and resultant force on an object then its it could mean that special in a relativity vacuum is are: the same constant for all of physics are leads the on same from for all inertial Maxwell’s observers. equations veried. The second postulate and seems frame reasonable differentiate – particularly between being at since rest Newton’s and moving laws at do constant fundamental moving at If both are accepted as being true then we need to start constant accelerations. If there acceleration will be about space and time in a completely different way. If is in no of light experimentally thinking velocity. of postulate velocity. difference or velocity. not An rest velocity observers completely that at in can accelerating is laws The of object constant of • reference. the at terms. inertial One that moving more • than mean is be The wrong. could object doubt, we need to return to these two postulates. zero. simulTaneiTy One example everyday of of how simultaneity. If two are simultaneous. are simultaneous to all observers demonstrate The two the pulses ends carriage is of are As is know to but this that observer. will – We is experimenter carriage the understanding one far as rest. happen not the an positioned that the they of the she is in in the the pulses the is say if be simple velocity. ends the we should A exactly reect is that experimenter constant the expect case! disrupt us together experimenter Since relativity around normally consider at of world observer, is towards mirrors at events moving light the would this to is postulates of a train. to train. sends back of 1st pulse hits back wall a out Mounted towards concerned, the they events simultaneous middle She middle, that two way in pulses leave together our concept the at the whole 2nd pulse hits front wall experimenter that: • the pulses were • the pulses hit sent • the pulses returned the out simultaneously mirrors simultaneously simultaneously. pulses arrive together pulses leave together Interestingly, the arriving at observer on the platform does see the beams pulses arrive back the same time. The observer on the platform at mirrors will know that: together • the pulses • the left-hand were sent pulse out hit simultaneously the mirror before the right-hand pulse pulses return • the pulses returned simultaneously. together In general, point in events simultaneous space that take simultaneous The situation observer (on will the seem platform). travel at constant speed speed as far is at different towards means as that he times. the beam the very – different This both The and so left-hand the reection right will watched observer beams concerned, if they end of hand happen knows are a that travelling must the end on by hit carriage is the light the must same mirrors is moving to be place one events that simultaneous at different observer take to all points but not place at the observers in space same whereas can simultaneous be to another! stationary at the will moving away. left-hand end Do not dismiss fanciful to rely event to on is these be tried the rst ideas out. because The use postulate. of This the a experiment pulse of conclusion light is seems allowed valid too us whatever considered. This rst. o p t i o n A – r e l A t i v i t y 133 lort trorto lORenT z TRansfORmaTiOn e X ample lORenT z facTOR The formulae that depends observers, for on special the relativity relative all involve velocity a between We factor different v can a pply dene the Lorentz factor, γ as L o r e ntz shown the measure s train observer We the situation on on the page the tr a ns for ma t io n 1 33. S uppos e car r ia g e p l a tf o r m to be me a s ur es e qua t io ns the 5 0. 0 the to t he e x pe ri me n t m lon g sp ee d of an d the on the tr a in follows: 8 to be 2.7 × 1 10 m s (0.90 c) to the right. In thi s s i tua ti on, 1 _ γ = 4 γ ,rotcaf ztneroL 2 v 1 √ At 2 c low the velocities, Lorentz factor approximately to one – effects is equal relativistic are negligible. we know the according to time s the (t) and locations e x p e r i me nte r on 2 the experimenter 1. According Time 1 to taken carriage is on the for the is experimenter each given p la tfor m pulse to the speed of fr a m e on the reach mirror = time taken to the 8.33 ×10 for each denes a ∆t frame by of reference different to complete and different of space coordinates and time. In frame S, = 1.67 to an According to the experimenter on and take place at a given given time position (t). (x, y Observers and in z disagree on the numerical values for γ = relative Galilean transformations equations (page 2 _ 1 c to calculate what an observer in a second frame 1 _ = = we know the values in one frame but assume 2.29 √ 0.19 allowed will that taken for LH pulse to reach mirror at end of carriage record is if 2 c = Time us - √ 2 uniform coordinates. 131) S'), (0.9c) 1 √ √ 1 0.81 The (frame = coordinates) these platform 1 __ 1 __ motion the the event 2 a s ×10 ) v with round events according a the is: 8 ×10 1 _ measurements associated of 7 = total 2. characterized be end s pulse experimenter (3.0 will at S), ×10 50.0 _ be (frame speed of light, c lORenT z TRansfORmaTiOns observer’s train 8 3.0 journey can and 8 = v light. observer S) S' It near Total An measured ( f r am e by: 25.0 _ innity are t ra i n 3 ∆t approaches ( x) the given by: the v∆x measurement of time is the same in both frames. Einstein has ∆t' = (LH γ ( pulse ) ∆t ) 2 c shown that this is not correct. 8 where ∆t = 8.33 8 ×10 s, v = -2.7 1 ×10 m s (relative clock in frame S and clock in frame S′ are synchronized velocity of platform is moving to the left) and ∆x = -25.0 m to t = t′ = zero w hen frames coincide. (pulse moving to left) (two frames on top of one another) 8 ( ∴ ∆t' = (LH 2.29 ( pulse) 8.33 2.7 ×10 ) × ( 25.0) ___ 8 y ×10 - 8 (3.0 × 10 ) 2 ) frame S (stationary) y′ 7 = 1.91 = 1.9 7 ×10 1.72 × 10 frame S′ 8 velocity v Time is taken given for ×10 RH s pulse to reach mirror at end of carriage by: v∆x ∆t' x = (RH γ ( pulse) ∆t ) 2 c x′ 8 ( = time′ = t′ 2.29 ( 8.33 2.7 × 10 ) × 25.0 __ 8 time = t ×10 - 8 (3.0 × 10 ) 2 ) y 7 = frame S 1.91 ×10 7 + 1.72 × 10 7 = 3.63 × 10 s y′ Note that the time taken by each pulse is different – they do not arrive (x, y, z, t) frame S′ simultaneously according to the experimenter on the platform. (x′, y′, z′, t′) The return time for the LH pulse is the same as the time velocity v taken for the RH to initially reach the mirror (in each 8 case, x So ∆x total = 25.0 time m and taken for ∆t LH = 8.33 pulse × to 10 s) return to centre of x′ carriage is 8 Because the frames were synchronized, the observers total agree time' = (LH on the measurements measurements made of by y z. To different Lorentz transformations. dened above. The and These derivation between observers all of switch involve these we the the need to Lorentz equations is other use the factor, not This γ, is both as the = γ(x vt); Δx' = γ (Δx = γ ( t 2 ; Δt' = γ ( Δt 2 reverse transformations consequence of ×10 7 = 3.82 × 10 same as the experimenters total time observe the taken return for of the the RH pulses to The taken above for calculates the transformation, ) round that can also trip be is for 3.82 frame applied ×10 S', to the s. the The frame S ') the being relative also apply. velocity of These frame are S just (with In this to its situation, in the opposite direction. ∆x (in frame S) = 0 as pulse’s the pulse journey. returns a starting position. total ∆t' = pulse ) γ ( ∆t 2 ) = γ∆t c vx' _ = γ(x' + vt'); t = γ ( t' + 2 7 ) c 134 be total respect (either x so Lorentz v∆x to s pulse c c The 3.63 7 time vΔx ____ ) 7 + required. vΔt); vx _ t' ×10 simultaneous. Check: x' 1.9 pulse ) o p t i o n A – r e l A t i v i t y = 2.29 × 1.67 × 10 7 = 3.82 × 10 s vot to velOciTy addiTiOn When two observers value. The calculation cOmpaRisOn wiTh Galile an measure each other’s velocity, they will always agree on the equaTiOn of relative velocity is not, however, normally straightforward. The For example, an observer might see two objects approaching one another, as top line of the relativistic addition shown of velocities equation can be compared below. with velocity = 0.7c the Galilean calculation velocity = 0.7c u' At = low give of u same equation for the velocities. v values the equation relative only of v these value. starts two The to equations Galilean fail at high velocities. At high velocities, equation than c, gives person A stationary obser ver, C (rst frame S) each object predict be the than The that case the has the as the speed situation a relative relative of velocity velocity Lorentz factor of 0.7 between can c, the the only be the relative the Galilean answers of relativistic velocity that greater one is always less speed of than light. A r e l A t i v i t y (second frame S′) Galilean two transformations objects worked out would for be 1.4 objects c. would This travelling cannot at less light. considered is one frame moving frame S (stationary) y while give person B the If a can relative to another frame at velocity v frame S′ (moving) y′ velocity v x Application of the Lorentz x′ transformation gives the equation used to move between frames: u v _ u' = uv _ 1 2 c u' – the velocity under secondframe, u – the velocity rstframe, v In – the each of velocity these x-direction. velocity If under of the cases, be in the x-direction as measured in the consideration in the x-direction as measured in the S a second positive something should consideration S' is frame, moving substituted S', velocity into in the as measured means the motion negative in the along rst the x-direction frame, S positive then a negative equation. Example In the light. u' example So = u’ is relative u = 0.7 v = -0.7 above, person two A ’s velocity objects velocity of as approached measured approach – to be each in other person with B’s 70% frame of of the speed of reference. calculated c c 1.4 c _ u' = note (1 + the sign in the brackets 0.49) 1.4 c _ = 1.49 = 0.94 c o p t i o n – 135 irt tt spaceTime inTeRval Relativity has shown that pROpeR Time, pROpeR lenGTh & ResT ma ss our Newtonian ideas of space a) Proper time interval Δt 0 and time are incorrect. Two inertial observers will generally When disagree on their measurements of space and time but expressing agree on a measurement of the speed of light. Is else upon which they will the relativity, consider a good way everything spacetime. From as of imagining different one what ‘events’ observer’s length of taken time that between a events rework is (for giving proper time is the time as measured in out a agree? frame In the there light), anything time they example will the point in of is going on something view, is to where space. called It the turns observer events out could to take be the correctly place at shortest record for the same possible the point time in that any event. three measuring how long a rework lasts co-ordinates further time (x, y and ‘coordinate’ (t). An event z) is is can dene required a given to a position dene point its in space. position specied by these One in Moving frame measures a longer time for the rework four since in this frame the coordinates (x, y, z, t). rework is moving. As a result would for thing is be all of is best of Lorentz expected these that 2 come up with measurements two 2 x observers 2 y normal transformation, another totally – (x', will observer different y', z', agree t'). on numbers The amazing something. This mathematically: 2 - to four these stated (ct) On the 2 z axes, = (ct ') 2 - Pythagoras’s 2 x' 2 y' z theorem shows us that Clock that is stationary with the the __________ 2 quantity 2 √ (x + rework measures the proper 2 y + z ) is equal to the length of the line from time for which it lasted. 2 the In origin, other so 2 (x words, + it 2 y is + z the 2 ) is equal separation 2 (Separation in to space) 2 = (the in + of the line) . space. 2 (x length 2 y + z ) If A is moving running past 2 l 2 2 = x + y 2 A. slowly + z b) This for Proper past slowly B for means B. Both length then A. B From that A views will A ’s will are think point think that of time view, that B time is is is moving running correct! L 0 l z As before, different different observers measurements depending on their for relative will the come length motions. up of The with the same proper object length x of an object object y is at is the length recorded in a frame where the rest. Moving frame measures The two observers agree about something very similar a shor ter length for the to this, but it includes a coordinate of time. This can be rework’s diameter since thought of as the separation in imaginary four-dimensional the rework is moving in this frame. spacetime. 2 (Separation in spacetime) in spacetime) 2 = 2 (ct) 2 x 2 y z or 2 (Separation 2 = In (time 1 dimension, 2 this 2 (ct') 2 separation) (x') (space is simplied 2 = separation) to 2 (ct) (x) OTheR invaRianT quanTiTies In addition box to above), the all spacetime observers interval agree on between the values two of events three (see other Ruler that is stationary with the quantities or with associated reference • Proper time • Proper length to with a the given interval separation object. between These two events rework measures the proper length for its diameter. are: Δt 0 c) Rest mass m 0 L 0 The • Rest mass are four always observer. velocity. 136 quantities constant There mechanics, of mass depends on relative m 0 These measurement that are are are and said do not additional also o p t i o n to be vary – with quantities, invariant A invariant e.g. a as they change not of associated electric charge. r e l A t i v i t y with Once again it measurement taken other frames. mass A possible as measured particle’s rest is in in mass a important the The frame rest frame does to of not the mass where distinguish of the change. object an object object the from is is at all its rest. T to liGhT clOck A light clock deRivaTiOn Of The effecT fROm fiRsT is an pRinciples imaginary device. A beam If of light bounces ‘tick’ two mirrors – we imagine the t is the time by the light light As one on with their one light stationary clock clock. In then frame, a moving clock runs slowly and t' this is ‘tick’ of time between ‘ticks’ on the moving clock: t' is greater the than t the clock. shown the a is observer ‘ticks’ between l bounces stationary between time stationary taken a between path light in the taken clock derivation by that light is pulse leaves bottom mirror in moving l l at constant longer. the velocity We speed know of l′ is that light is xed ‘tick’ so the time ‘ticks’ must effect on a also – between moving be that the vt ′ clock longer. In This moving clocks the the time clock t , has moved on a distance = v t' _________ run slow – is called time 2 Distance dilation travelled by the light, l' = √ ((vt') 2 + l ) pulse bounces o top mirror l' The time between t' bounces = c Δt is the proper time ________ for 2 0 √ (vt') 2 + l __ this clock in the frame = c where the clock is at rest. 2 ‘tick’ t' 2 2 v t' + l _ 2 ∴ = 2 c 2 2 t' l v 2 ∴ 1 ( - ) 2 = 2 c c 2 l 2 but = t = t 2 c pulse returns to bottom mirror 2 v 2 ∴ t' ( 1 2 2 ) c 1 _ or deRivaTiOn Of effecT fROm lORenT z t' = ______ × t or t' = γ t 2 v √ TRansfORmaTiOn If frame S is a frame point in space, two events take place at the then the time interval between events must be the proper time interval, Δt equation is true for all measurements of time, whether these they two 2 c where This same 1 have been made using a light clock or not. . 0 Time dilation is then a direct consequence of the Lorentz transformation: νΔx _ Δt' = γ Δt ( - ) 2 c Where Δt = Δt , (the proper time interval) and Δx = zero 0 (same ∴ point time in space) interval in frame S', Δt' = γ∆t 0 o p t i o n A – r e l A t i v i t y 137 lgt otrto to or t rtt effecT Of lenGTh cOnTRacTiOn Time is not the only measurement that is e X ample affected by relative motion. There is another An unstable particle has a lifetime of 8 relativistic effect separation direction. called between The length two contraction. points contraction is in in space the According contracts same if direction to there as the a is (stationary) relative relative observer, motion in the 4.0×10 that moving motion. a) Its b) The s at in its 98% lifetime of in length own the the rest frame. speed of in it light laboratory travelled If is calculate: frame. both frames. _________ moving frame 1 __ γ a) = √ ∆t 2 1 (0.98) = 5.025 = γ∆t = 5.025 0 8 × 4.0 × 10 7 = 2.01 × 10 s Length contracts along direction b) In the laboratory frame, the particle moves of motion wh en compared Length with stationary frame. = speed × = 0.98 × = 59.1 m time 8 3 × –7 10 × 2.01 × 10 stationary frame In the particle’s frame, the laboratory moves 59.1 _ ∆l = γ Length contracts by the same proportion as time dilates – the Lorentz factor is = once again used in the equation, but this time there is a division rather than 11.8 m a (alternatively: multiplication. length = speed × 8 L = 0.98 × 3 = 11.8 m) × time 8 10 × 4.0 × 10 0 _ L = γ deRivaTiOn Of lenGTh cOnTRacTiOn fROm lORenT z TRansfORmaTiOn When we measure recording the instant time the position length of of each a moving end of the object, object then at one we are given where the length L object is at rest, we will be measuring the proper : 0 of according to that frame of reference. In other Δx' words the time interval measured in frame S between these = γ(Δx - vΔt) two Where Δx' = L (the proper length) and 0 events will be zero, Δt = 0. In this case, the length measured Δx Δt = is the length of the moving object L zero (simultaneous measurements of position of end of object) . 0 ∴ Length contraction is then a direct consequence of Length in frame S', L the = γ(L) 0 L Lorentz transformation, as, if we move into the frame, S', 0 _ L = γ Without The muOn e XpeRimenT relativity, no muons would be expected to reach the 6 Muons are leptons a massive (see page 78) – they can be thought of surface as at all. A particle with a lifetime of 2.2 × 10 8 more the laboratory 2.2 × version but they of an electron. quickly decay. They Their can be created average in lifetime is is travelling expected near to the travel speed less 6 6 at 10 s as measured in the frame in which the muons are rest. Muons (2.2 The are also created high up (10 km above the surface) × a light (3 × kilometre which 1 10 m before s ) would be decaying 8 10 × moving speed in of than s 3 × 10 muons means that = are the 660 m). effectively Lorentz moving factor is of × ‘clocks’. Their high high. ________ the atmosphere. Cosmic rays from the Sun can cause them 1 _ γ to be created travel with towards the huge Earth velocities some of – perhaps them 0.99 decay but c. As = they there is still = √ 7.1 2 1 0.99 a 6 Therefore detectable number of muons arriving at the surface of the an average lifetime 2.2 10 s in the muons’ Earth. frame as a of reference stationary will be observer time on the dilated Earth to is a longer time concerned. as From far this ‘shower of cosmic rays from Sun frame of Many muons the reference surface – will this they still is will last, decay exactly but what on average, some is will 7.1 make times it longer. through to observed. 6 In the They a tm o s p h e re the muons’ make Earth) it is frame down they to moving the with exist for surface respect 2.2 × 10 because to the s the on average. atmosphere muons. This (and means 10 km that the atmosphere will be length-contracted. The 10 km some muons decay before reaching surface distance as measured by an observer on the Earth will only some muons 10 ___ reach surface Ear th be = o p t i o n A – r e l A t i v i t y km. A signicant number of muons 7.1 enough 138 1.4 for the Earth to travel this distance. will exist long st gr (mo gr) 1 • spaceTime diaGRams Spacetime separation diagram a is visual Measurements actual We so way can be of introduced on representing taken from the page the 136. A beam geometry. diagram to Whatever spacetime • The calculate cannot represent limit represent. of The all the four simplest space dimensions number and of on representation one of the dimensions time as has shown one of diagram, space only the advance are is of from being used, by represented by proper for the frame separation shown that axes light traveller’s usually dimension of calculated values. we we was of time overall convention, line any at two they 45° to traveller separation reference, between a in can can path be of a axes. be spacetime. remained events the the In the stationary calculated so as below. one below. e X ample 1 Of spaceTime diaGRams emit par ticle at rest The advance events par ticle with constant speed of proper A→B→C→D spacetime time can be for the journey calculated from between the the values on the diagram. time/yr par ticle which star ts fast D 6 and then slows down 5 space An object line in (moving or stationary) is always represented as 4 a spacetime. C Note • light that: The values on the spacetime diagram are as would be 2 measured by the by an vertical observer whose worldline is represented axis. B • The t. vertical An axis alternative means that both in is the to above plot axes can spacetime (speed have of the diagram light same × is time), units time ct. (m, 1 This light- A years or equivalent). –0.5 –1 1 2 3 4 space/ly A journey through spacetime 2 Journey Space separation Time separation (Spacetime 2 (x)/ly (t)/yr separation) 2 (ct) (x) Advance of proper time according to 2 /ly traveller / yr _________ 2 2 (ct) (x) _ t' √ = c ____ 2 A→B 0.0 1.0 B→C 1.5 2.0 C→D 2.5 3.0 2 1 0 = √ 1 1.00 = 1.00 = 1.32 = 1.66 ____ 4 2.25 = √ 1.75 1.75 ____ The total advance according dilation The to an (see of page alternative proper observer time whose for the 9 traveller worldline is a is 1.00 vertical + line 6.25 1.32 on + this = √ 2.75 1.66 = 3.98 spacetime yr. This diagram. compares This 2.75 with difference the is an advance of example 6.0 of years time 137). journey direct from A → D shows a greater elapsed proper time. 2 Journey Space separation Time separation (Spacetime 2 (x)/ly (t)/yr (ct) separation) 2 (x) Advance of proper time according to traveller / yr _________ 2 /ly 2 2 (ct) (x) _ t' = √ c 1.0 A→D This is always true. A direct 6.0 worldline always 36 has a greater 1 = amount √ 35 of elapsed proper time than o p t i o n an A 35 = indirect – 5.92 worldline. r e l A t i v i t y 139 st gr 2 c alcul aTiOn Of Time dil aTiOn and e X ample 2 – cuRved wORldline lenGTh cOnTRacTiOn Time dilation and length contraction B are quantitatively represented diagrams. Refer a) dilation: to diagram on on spacetime page 139. 15 Time In the journey 12 direct 14 from B → C, the relative velocity 11 between 13 the traveller 1.5 and the stationary is = 2.0 10 observer ly _____ 0.75 c. The Lorentz 12 gamma yrs 9 factoris: 11 1 _ γ = 1 __ = ______ √ = ________ 2 1.51 10 8 2 √ v 1 0.75 1 time 2 9 c 7 8 The journey takes 2 yrs according to the 6 observer at measured rest. by This the means traveller will ∆t _ ∆t = γ∆t ⇒ ∆t 0 the proper 7 as 5 be: 6 5 2.0 _ = = 0 time =1.32 γ yr 1.51 4 4 as shown in the table on page 139. 3 3 1 2 rest 2 the journey length from B→C proper time 1 be 1.5 ly. contracted The to journey will be advance 2 = 1 to increase 2 in time measures increase in 2 in space at observer The contraction: Length b) length be O 1 2 3 4 5 6 7 8 9 10 L 1.5 _ 0 _ L = = = γ The relative the traveller’s taken makes shown space velocity time traveller ly 1.51 the This 0.99 to frame the to be of go travel from of c × 0.75 c, B C, → reference, distance 0.75 is from is according 1.32 yr = and 1.32 to Proper in than time the along proper a curved time worldline along the from straight event O to event from O to B. line B is smaller yr. the 0.99 ly as above. T t rox 1 As mentioned preference effect to on page 136, different (moving clocks the inertial run theory of observers slowly) is relativity – the always time the gives no This dilation same. to to the ‘twin paradox’. In this imaginary a time situation, on Earth twins compare while the their other views twin of time. undergoes a One This very twin star and back fast is a relativistic of far as the twin on trip out to because observer. will think the This that The difference Earth is concerned the other twin is means time that has the been twin that running remains slowly for on the When aged they correct according effect relative – time is velocity running between at different the two rates twins of the distance between and them. meet up again, the returning twin as in far ageing as both is of relative. them Neither are twin concerned, is getting time at the normal rate. It’s just that the moving has been twin the that she has been away for a shorter time than the other as recorded by the twin on the Earth. should The have is a time twin. it that: a thinks Earth but Remember again. passing moving the not younger; As prediction, formula. remains • distant strange two because identical very dilation This • leads seems the paradox is that, according to the twin who made the less. journey, the before the twin twin left on on the the Earth Earth was should moving have all aged the less. time and Whose so version after of time The is correct? solution equations two back would case then twin situation The on 140 o p t i o n A – r e l A t i v i t y up This are the 141. constant one Earth be of of is no has are from only relative them external situation must comes relativity in involve the on paradox again, resolution page the special observers meet The to of forces not realization motion. would longer the symmetrical and have For to the turn acceleration. symmetrical accelerated so for her that when the the twins to around. If this the view is the twins. of the correct. the twin paradox using a spacetime diagram is T rox 2 In ResOlvinG The Twin paRadOX usinG spaceTime order to to send check light whose signals version every of year. time The ‘is correct’, spacetime they agree diagram for diaGRams this The diagram below is a spacetime diagram for a journey to situation in the Earth’s frame of reference is shown below a (left). distant planet followed by an immediate return. Note According to the twin remaining on that signals • the distance to the planet = 3.0 relative velocity of traveller is sent is and no paradox; received; the they agree travelling on the twin has number aged of less than ly the • there Earth: 0.6 twin that stayed on Earth. c A more complicated spacetime diagram can be drawn for the 3.0 ___ • each leg • Total of the journey takes = 5.0 yr reference frame of the outbound traveller (below right). Note that: 0.6 journey time = 10.0 yr • The rst vertical The gamma factor • = has the travelling = _______ worldline stationary. When the travelling twin turns round, she leaves her 1.25 original 2 frame of reference and changes to a frame where 2 √ v 1 - 0.6 3 1 the 2 Earth is moving towards her at c according to c (= 0.6 c). 5 • So twin’s 1 _ _ = ______ √ i.e. years is 1 _ γ four the twin undertaking the Her relative velocity towards the Earth with respect to journey: her original frame of reference can be calculated from the 5.0 ____ • each leg of the journey takes = 4 .0 yr 15 1.25 velocity transformation equations as c (= 0.88 c) back. 17 • Total journey time = 8.0 yr • In this frame of reference, the total time for the round trip 3.0 ____ • the distance to the planet = = 2.4 ly would 1.25 be measured as 12.5 yr 4.8 ___ • relative velocity of Earth = = 0.6 c 8.0 reference frame 13 of outbound traveller 8 reference frame 10 of Ear th 12 9.2 10 8 9 11 8.4 7 9 t (yr) 8 7 10 inbound traveler 7 .8 8.4 v = –3/5 c 8 9 7 .6 7 inbound traveller 6 6.8 light signals 6 v = -15/1 7 c 7 8 from Ear th 6.8 6 5 7 6 )ry( t Ear th 5 5 6 v = -3/5 c 5 4 5 4 annual Ear th 4 signals v = 0 3 4 from Ear th 3.2 3.2 annual 3 signals 3 2.4 from 2.4 outbound 2 traveller 2 traveller 2 lines of 2 1.6 v = 0 1.6 outbound 1 simultaneity for traveller traveler 1 1 0.8 1 0.3 v = 3/5 c x (ly) x (ly) 8 7 6 5 4 o p t i o n 3 A 2 – 1 r e l A t i v i t y 141 st gr 3 RepResenTinG mORe Than One ineRTial fRame Mathematically transformation for the above calculations, process the to agree following with must the Lorentz apply: On The s ame spaceTime diaGRam • The Lorentz transformations describe how The space and time in one frame can be angle converted into S') situation in observed each frame in of another frame reference can of be and the reference. visualized and the x by (see page 141 for diagrams for each frame of is also possible same spacetime ct') moving to represent diagram. at A two frame inertial S’ frames on (coordinates x' the relative constant velocity +v The frame The S (coordinates same (that The x is, worldline to x and Lorentz and ct). ct, applies The as well to principles as both to x' sets and of are transformation is made by by A given for as The worldline the angle for the origin between axis. It the x' is: c ) frame S' rather than the spacetime axes for frame S x by axes the in axes in S' are different to the scales S. value is represented compared with by the ct a greater length on the ct' length on the x' axis. A given value is represented by a greater axes axis when The ratio compared with the x axis. ct'). changing position has used follows: coordinate the of the and ct at of the measurements on the axes depends on the coordinate velocity between the frames. The equation (which worldline. does • as v ( the when relative system (the same to • • axis and according • • tan scales used axis a ct' the examples). • is = reference • It is using 1 spacetime the axis The θ separate ct the axis measurements between measurements of of right angles not need to be recalled) is: ______ to 2 v 1 one another as normal. of units c _ = √ ct • The spacetime axes for + 2 ct' _ ratio frame S' has its x' and ct' axes both 2 v 1 2 c angled a in beam towards of the x = ct line (which represents a path of light. ct' • The coordinates of a spacetime event in S are read from the ct xand • The ct axes drawing x' directly. coordinates and lines ct' of a spacetime parallel to the ct' event and x' in S' are axes measured until they hit by the axes. x' Frame S Frame S' ct ct' (x', ct') = (0, 1) light (x, ct) = (γv/c, γ) (x', ct') = (1, 0) θ (x, ct) = (γ γ v/c) θ x D Summary • At ◊ C greater the S' speed: axes swing towards the x = ct line as the angle θ increases. ◊ x' the ct' with and the ct x' axes and x are more stretched when compared axes. B • Events that are simultaneous in S are that are simultaneous in S' on the same horizontal A line. • θ Events the x 1. Events A & B simultaneous are in simultaneous frame S' (A in frame occurs S before but are not B) 2 tan θ = = 0.25 8 ∴ 2. 3. relative velocity of frames S’ Events C & D occur at same Events C & D occur at different A pulse of according events 142 B light to or emitted both by frames and location = in A 0.25 frame locations event of S in arrives reference. It A – S'. frame at r e l A t i v i t y S event cannot C. o p t i o n c D arrive at x' axis. are on a line parallel to HL m rg 2 ma ss and eneRGy E = mc The most famous equation in all of physics is surely Einstein’s 2 mass–energy from? By length relationship now need to it should be E = not viewed mc be in a , a but where surprise different does that way, if it time then so Mass be come and equation and how does energy converted the can KE = equivalent. mass always numbers 1 as energy. are into be are and vice used, This means versa. but substituted. one that Einstein’s needs to Newtonian energy can mass–energy be careful equations about (such 2 mv or momentum = mv) will take different forms 2 when According constant at all have to should to Newton’s acceleration. do be is laws, If this achievable apply a – a constant was even constant force always faster force and produces true then than theory is applied. a any light. relativity velocity All The energy energy we E needed and can to be create a particle calculated from at the rest is rest called the rest mass: 0 2 wait. E = 0 yticolev If constant force – velocity as this m c 0 particle is given a velocity, it will have a greater total energy. predicted by Newton 2 E = γm c 0 speed of light, c constant acceleration time In practice, object gets this starts less to and does not approach less even if happen. the the As speed force soon of is as light, the the speed of an acceleration constant. yticolev constant force – velocity as predicted by Einstein speed of light, c acceleration decreases as speed gets close to c time The the force is object still must relativistic doing still equation work be is (= gaining needed force × kinetic for distance), energy therefore and a new energy: 2 E = γ m c 0 Note that some textbooks compare this equation with the 2 denition of rest energy (E = m 0 concept of relativistic mass c ) in order to dene a 0 that varies with speed (m = γm ). 0 The current The preferred adopt a new IB syllabus approach relativistic does is to not see formula encourage rest for mass this as kinetic approach. invariant and to energy: 2 Total energy = rest energy + kinetic energy = γm c 0 2 rest energy = m c 0 2 so, kinetic energy E = K (γ - 1)m c 0 o p t i o n A – r e l A t i v i t y 143 Rtt ot rg HL equaTiOns The of laws of energy concepts uniTs conservation still apply often in have of momentum relativistic to be rened and conservation situations. to take However into SI the account the units of viewing space and be it is example, dened p = as in the Newtonian product of in to these use equations. other units Sometimes, instead. the atomic scale, the joule is a huge unit. Often the time. electronvolt For applied useful new At ways can however, mechanics, mass and momentum p is gained velocity. by (eV) one difference of is used. electron 1 volt. if One it electronvolt moves is through a the energy potential Since energy mv difference __ Potential difference = charge In relativity to be it has a similar form, but the Lorentz factor needs 19 1 taken into eV = 1 V × 1.6 × 10 C consideration. 19 p = γ m = 1.6 is too × 10 J v 0 In The momentum of an object is related to its total energy. fact the 2 E 2 = p mechanics, 2 c 2 + m the relationship can be stated small a unit, so the standard SI In multiples relativistic electronvolt are used as 1 4 keV = 1000 eV c 0 6 1 In Newtonian and mechanics, momentum the relationship between MeV = 10 eV etc. energy Since is mass and comparable 2 energy units for are equivalent, mass. The it makes equation that sense links to the have two p _ E = 2 (E 2m = mc speed Do not be tempted to use the standard Newtonian 2 ) of the situation is relativistic, then you need to is a new unit included in for the mass unit – so the MeV that no c . The change of equations– number if denes light use is needed when switching between mass and energy – the 2 If relativistic a particle of mass of 5 MeV c is converted completely be It into equations. energy, the energy released would 2 possible In a to use similar keV way, the 5 MeV . would also be 2 c or GeV easiest c as unit a for unit for mass. momentum is the 1 MeV c . which b) e X ample The Large Centre Electron for Nuclear total energies with positrons of / Positron Research about 90 (LEP) collider (CERN) GeV . These at the accelerates electrons electrons links is positive are moving in identical charge. The the in opposite rest mass positrons to have direction electrons the same as these two carry energy unit to energy particles, use and if using the equation momentum. estimate their relative velocity of to since γ so large collide shown but best relativistic relative Positrons the approach. European then For This as velocity ≃ c below. a the electrons. c) Electron What is the total momentum of the system (the two Electron particles) ● before the collision? ● zero Total a) energy = 90 GeV Use the equations (i) the velocity of of Total special an relativity electron (with energy to = 90 GeV calculate, respect to the d) The collision causes new particles to be created. laboratory); (i) Total energy = 90 GeV = 90000 Estimate 2 mass = 0.5 ∴ ≃ c MeVc ∴ γ maximum total rest mass possible for the MeV new Rest the = 18000 particles. Total (huge) energy available = 180 GeV 2 (ii) the v momentum of ∴ an electron (with respect to max total rest mass possible = 180 GeVc the laboratory). (ii) 2 p 2 c 2 = E 2 m Give one reason why your answer is a maximum 4 c 0 Above 2 ≃ E ≃ 90 1 p 144 GeVc o p t i o n A – r e l A t i v i t y assumes that particles were created at rest Rtt x HL paRTicle acceleRaTiOn and elecTRic chaRGe e X ample In An 6 a particle charged basic accelerator particles principle are is to (e.g. a linear accelerated pass the up accelerator to charged very or high particles cyclotron), energies. through a The electron Calculate is its potential differences and each time, the particle’s through a pd of 1.0 × 10 V . velocity. series 6 Energy of accelerated gained = 1.0 × 10 = 1.6 × 10 = m 19 × 1.6 × 10 J total 13 energy increases as a result. of a charge The increase in kinetic J energy 2 E (ΔE ) as a result q passing through a potential 0 31 c = 9.11 × 8 10 × (3 × 10 2 ) 0 K 14 difference V is given by: = 8.2 × 10 J 13 qV = ΔE ∴ Total energy = 1.6 × = 2.42 10 14 + 8.2 × 10 K 13 × 10 J 13 2.42 × 10 __ ∴ γ = = 2.95 14 8.2 × 10 ______ 1 _ velocity = 1 - c √ = The phOTOns Photons the are speed particles of light, c. that have Their a total zero rest energy mass and and their travel frequency f relativistic momentum, at is 2 E 2 = p must 2 + m c that also links apply total to energy, E and photons: 4 2 c 0.94 equation p, 2 γ c 0 linked by Planck’s constant h: The E = hf rest photon mass a hf E p of photon is zero so the momentum of a is: = = h = c c λ 2 Note e X ample: dec ay Of a piOn neutral A typical pion (π 2 ) is a meson of in this example, total energy 2m c , so γ = 2 so v 0 0 A that rest mass m = 135.0 MeV c . = 0.866 c 0 mode of decay is to convert into two photons: Each photon will have a total energy of 11 0 π → 2γ 135 MeV and a = 2.16 × 10 J 1 The wavelength of these photons can be calculated: momentum photons a) Decay at will of 135 MeV c . The wavelengths of the be: rest 8 c λ If the have pion half was the at rest total when energy it of decayed, the each = 67.5 MeV = 1.08 × = 67.5 × 10 = 3.0 × 10 __ 34 h = 6.63 × 10 × 11 would E 2.16 × 10 15 pion: = 6 E photon 9.21 × 10 m 19 × 1.6 × 10 J Initial total momentum for the pion in the forward direction 11 Planck’s 10 constant J can can be used to calculate the be calculated from 2 wavelength E 2 = p 2 c 4 2 + m c 0 of one of the photons: 2 2 p c 2 = 2 E m 4 c 2 = (4 1)m 0 4 c 0 c E = h 1 p λ = √ 3 m c = 1.73 × 135.0 = 233.8 MeV c 0 8 c λ = 3.0 × 10 __ 34 h = 6.63 × 10 So × conservation of momentum in forward direction is: 11 E 1.08 × 10 233.8 = 2 × 135 × cos θ 14 = 1.84 × 10 m 233.8 _ ∴ cos θ = ∴ θ = = 0.866 270 The momentum Conservation emitted photon b) Decay in add the was to give initially means directions. together the pion momentum opposite while Suppose of of a The that total total, zero the as it was photons momentum once again, of at will of rest. 30° be each zero. moving pion was moving forward when it decayed 2 with a total emitted as energy shown 270.0 MeV c ; the photons will be below: photon 1 after before θ θ pion photon 2 o p t i o n A – r e l A t i v i t y 145 Gr rtt – t r HL pRinciple Of equivalence One of Einstein’s example There below are two ‘thought considers possible experiments’ an observer situations • The rocket could be far • The rocket could be at away rest to a how closed an observer’s view of the world would change if they were accelerating. The spaceship. compare. from on considers inside the any planet surface of a but accelerating forwards. planet. dropped rocket at rest dropped object accelerating will ‘fall’ for ward object will fall on planet towards oor towards oor planet astronaut feels a force when rocket is astronaut feels a force when rocket is accelerating for ward at rest on the surface of a planet Although these situations seem completely different, the observer inside the rocket would interpret these situations as being identical. This is Einstein’s and From principle down the near a a ‘principle reference of gravitational of massive equivalence’ equivalence, body – a postulate that states (see it can page eld the In principle should rocket both of inertial bend that the be deduced that light rays cases point that the rocket is was in and rays! a are bent beam equivalence light allows observer the of there of diagrams would exactly suggests There beam is a light 1 a that gravitational window high up in enter. and2, the see the light the small upwards that small to opposite accelerating is no difference between an accelerating frame of in a gravitational eld (see below) and that time slows 147). bendinG Of liGhT Einstein’s that eld. (see But no observer shining on window. is diagram3) wall at however, then light would opposite Einstein’s difference observer an the If, of is follow a diagram in a the hit a small principle between point of an path 4. effect This in the equivalence accelerating gravitational curved on wall below the point window. a eld. If this gravitational does states that observer is true eld there and then as is inertial light shown should in happen! the light hits nal position of wall light hits window when opposite below window window light hits below light hits window light hits nal position as rocket has of window speeded up window in an wall rocket original window accelerating when opposite rocket moves position light hits accelerating view rocket and in a upwards at of window inside stationary rocket constant rocket in a gravitational velocity eld 1 rocket at rest 2 in space 146 o p t i o n rocket moving with constant velocity A – r e l A t i v i t y 3 rocket accelerating upwards 4 rocket at rest in a gravitational eld Grtto r t HL cOncepT The can red maThemaTics general be of relativity experimentally shift words theory a – clocks clock on tested. slow the down ground makes One in a oor other such predictions effect is gravitational of a This gravitational eld. building that will In other run gravitational worked out frequency for ∆f a is time dilation uniform given effect can gravitational be mathematically eld g. The change in by slowly g∆h ∆f ___ _ = when compared with a clock in the attic – the attic is further 2 f away from the centre of the c Earth. where f is the frequency g is the gravitational emitted eld at the source strength (assumed to be constant) ∆h is the height c is the speed difference of and light. A clock on the ground oor runs slow when e X ample compared with a A clock in the attic the UFO travels Earth radio at signal (i) What (ii) If the the is a at such height of a of speed 200 frequency the of frequency signal was observer to km 110 remain above MHz received reected frequency of back the is by to above the sent the to point on surface. the A UFO. UFO? Earth, return one Earth’s what signal? would Explain be your answer. 8 (i) f = 1.1 g = 10 ∆h = 2.0 ∆f = × 10 Hz –2 The same seen that away effect a from can be imagined gravitational a mass (for eld in a affects example the different light. Sun), If way. light the is We have of s 5 shone photons m × 10 m light 5 10 × 2.0 × 10 __ must be increasing their gravitational potential energy as ∴ they move away. This means that they must be decreasing 8 × 8 (3 × 10 1.1 × 10 Hz 2 ) their –3 total energy. photon, be less the than Since frequency observed the is a frequency emitted measure away of from the the energy source of = a 2.4 × 10 received = 1.1 Hz = 109999999.998 ≈ 1.1 8 must ∴ f × 10 –3 – 2.4 × 10 frequency. Hz 8 (ii) The return Therefore frequency signal it will as × 10 will be arrive Hz gravitationally back at exactly blue the shifted. same emitted. At the top of the building, the photon has less energy, and so a lower frequency, than when it was at the bottom. The oscillations clock. the An clock of observer on the the at light the ground can top oor be of to imagined the be building running as the pulses would of a perceive slowly. o p t i o n A – r e l A t i v i t y 147 sor tg HL e vidence TO suppORT GeneRal Rel aTiviTy Bending of star light The predictions One main physicist The called idea was Arthur the visible the Moon not blocks same all stars relativity, the experiment of because the recorded light at just bending Eddington behind stars the general are the of of prediction a in those light by a of special relativity, gravitational eld. seem One so of strange the rst that we need experiments to strong experimental check this effect evidence. was done by a 1919. was the like of to measure Sun from is the different so the bright. Sun. time, If the the deection During a positions stars that of light solar of (from eclipse, the stars appeared a star) during near as however, the the edge a result stars total of the are of the visible eclipse Sun Sun’s mass. during were would the During few compared appear to with have the minutes the day, when positions moved. actual position of star apparent position Sun of star Moon not to scale! Ear th The angle of the shift of these stars turned out to be exactly apparent position usual position of star in sky during eclipse (compared with others) the angle as predicted by Einstein’s general theory of relativity. Gravitational lensing The bending very bend of extreme around the path effects. the of light Massive galaxy as or the galaxies shown warping can of deect spacetime the light (depending from quasars on which (or other description very you distance prefer) sources can of also light) so produce that the some rays below. image of quasar massive galaxy quasar obser ver image of quasar not to scale! In this strange situation, the galaxy is acting like a lens and we e vidence TO suppORT GRaviTaTiOnal Red shif T can observe multiple images of the distant quasar. Atomic clock frequency shift Because they are so sensitive, comparing the difference in Pound–Rebka–Snider experiment time The decrease in the frequency of a photon as it climbs recorded a gravitational eld can be measured in the measurements been successfully experiments to photons were to achieved do Pound–Rebka need this was be on The after sensitive, many done experiment. measured very in and frequencies they but occasions. 1960 ascended is of or they One of Physical Laboratory Tower at measurement original greater 148 Pound–Rebka Harvard accuracy by Pound o p t i o n A experiment and – was clocks can provide of gravitational red shift. One of the a clocks called taken to high remains on the altitude will faster. ground. by a The rocket, clock whereas that is at a the second higher one altitude the run the gamma-ray Global positioning system descended the global positioning system to be so accurate, general University. relativity The atomic have For Jefferson identical laboratory. is The two out direct of by repeated Snider. r e l A t i v i t y with the must satellite's be taken orbit. into account in calculating the details of cr tr o t HL spacetime. effecT Of GRaviTy On spaceTime The Newtonian forces between thinking changes spacetime both set travel two about in the is off way of masses. gravity shape caused from describing is In not general to think (warping) by mass. different gravity of in it as about on terms relativity of a spacetime. Think points is the the two but four going of As has been dimensions on by of explained, it spacetime. representing It spacetime is is very hard easier as a at to to imagine picture what is two-dimensional sheet. as warping travellers Earth’s the the way force, The of of who equator and north. On the surface of the Ear th, two travellers spacetime represented by at sheet who set o parallel to one another… Any you of mass have spacetime around P Q would itself. …may eventually meet: the P they They of travel could attraction Earth so they this between consequence travellers north explain of have their the to will them surface move paths get coming in come or of closer they the Earth straight in could closer terms explain being lines can Sun. explain be the (or bends) warping used The the Earth shortest warps greater to describe diagram situation. orbits possible the path below The Sun in spacetime. that takes the The place. orbit of represents Sun warps because it spacetime. is more This the Earth how Einstein spacetime travelling This turns mass warping out around along to be a Q and together the The curved As present the together. of it a as curved. across path. the force a The surface of the together. Sun Einstein curved showed by mass. how The spacetime becomes. spacetime or in spacetime more Moving other could matter you objects words, they be thought have, follow take the the the of as more being curved curvature shortest path • Mass ‘tells’ • Spacetime spacetime how to curve. of ‘tells’ matter how to move. with spacetime in applic aTiOns Of GeneRal Rel aTiviTy TO The univeRse a s a whOle General affect relativity each cosmology The Very sections and large the mass holes. now of of fundamental allows the the are relativity astrophysics of holes may the evidence can cosmic searching predicts Experimental to understanding far-reaching Universe presence black astronomers General is This development elements and other. option be at the the of in to the objects created in about the the Universe future interact development and fate of and the thus how Universe – they see D). detail. of Many are many current aspects (e.g. its large-scale structure, the creation of the predicted. galaxies. General relativity predicts how these may interact with matter evidence. gravitational existence how be radiation) centres appropriate existence for (option modelled background exist for predictions of these waves waves associated is being with high energy events such as the collision of two black sought. o p t i o n A – r e l A t i v i t y 149 b o HL At descRipTiOn When a gravity for density star of the would be of the Sun, all of its it collapse down details). The matter and in more becomes the thus star. described the stopping this dwarf. the star on itself of more and it of the fuel, (see the the force greater relativity, spacetime The severe near a masses can of stop more astrophysics the gravitational general curved. more the contracts greater terms terms more nuclear more the In and collapsing collapsing then up more becoming mass used collapsing spacetime If has makes option near star it the mass eld and folds in is greater the than this contraction. more over warped itself. until What concentrated we do not Spacetime into is a know around eventually left is point it called – the of any the process mass becomes a black that becomes so hole. great All that the singularity this collapsing curvature of depending on the star. is less electrons than play contraction. an The about 1.4 times important star that is part left the in is mass of the eventually called a white spacetime with If collapsing star is greater than this, the electrons extreme curvature cannot times halt the neutrons a mass play neutron more the contraction. of an star. extreme the Sun can important The A the also role curvature than contracting be and of mass stopped the star spacetime curvature near a – of this that near white up is a to three time left the is called neutron star is dwarf. schwaR zchild Radius The curvature extreme can be since that of attracted nothing forces are deected so spacetime nothing, into can the travel extreme near a not hole, faster that black near even a black light, but light. would be is can The singularity so escape. nothing than light hole can Matter get out gravitational severely hole. event horizon photon sphere At a particular distance Schwarzchild velocity is predicts that given by equal the from radius, to the the we the get speed escape centre, to of velocity a light. v called point the where the Newtonian from a mass M escape mechanics of radius r is formula _____ 2GM _ v photon sphere = √ r black hole If the escape velocity Schwarzchild If you were to approach a black hole, the gravitational radius is the speed would be of light, given c, then the by forces 2GM _ R on you the would photon increase. sphere. The This rst thing consists of a of interest very thin would shell of captured in orbit around the black hole. As we turns in, the gravitational forces increase and so the out that proper at that distance also longer this called e X ample of a black radius hole that has the same mass as for be able reason crossing object size is general also correct relativity. If if we we and get closer to the singularity, to crossing the the event approaching the communicate a with Schwarzchild horizon. black the hole An would Universe radius observer see time object. 30 our Sun (1.99 × 10 kg). The 11 observed time dilation is worked out from 30 2 × 6.67 × 10 × 1.99 × 10 ___ R ∆t = 0 Sch 8 (3 × 10 _ 2 ∆t ) = ______ R S _ = 2949.6 = 2.9 √1 m r km where 150 o p t i o n A use cross the we would increases. For the of escape no Calculate equation equations Schwarzchild velocity this fall the further 2 c light It photons = S be – r e l A t i v i t y r is the distance from the black hole. is outside. sometimes watching slowing an down ib qto – oto a – rtt 1. In the laboratory particle an of electric the the frame parallel current. alpha wire alpha 2. travels are in the The alpha b) The laboratory line the is as moving rocket of drift Explain frame of slow reference, velocity the moving wire of origin reference that the the of the alpha and carries station velocity electrons force on away station observer each in platform. platform T is strike Observer midway sitting travels in to between the middle both S is the of standing two the on strikes, train. the while Light from observers. the of 0.5 c [2] from speed the [2] rockets viewed at frame the a metal particle identical Earth reference, stationary this and identical. particle a) Two In particle of to are moving Earth. 0.80 from c along Rocket 1 relative rocket 1 at is to the same moving the speed away Earth 0.60 c straight from and rocket relative 2 b) to If observer S on observations 1 the that simultaneously, will conclude station the two explain that they concludes lightning why did from strikes observer not occur T his occurred on the train simultaneously. [4] rocket 1 0.80 c relative 0.60 c relative to Ear th to rocket 1 c) Which d) What on e) a) Calculate using the velocity of rocket 2 relative to the What be train, will the will the T conclude distance according be the platform, occurred between to T distance and the to T the and [1] scorch according between according rst? to marks S? scorch according [3] marks to S? [2] the (i) Galilean transformation (ii) relativistic equation. transformation HL [1] equation. [2] 5. b) will the on Earth, strike Comment on your answers in (a). In a laboratory experiment two identical particles (P and Q), each [2] of rest mass m , collide. In the laboratory frame of reference, 0 3 c) The rest mass of rocket 1 is 1.0 × 10 kg. Determine the they relativistic kinetic energy of rocket 1, as measured the an observer on are both moving at a velocity of 2/3 c. The situation before by Earth. collision is shown in the diagram below . [3] Before: 3. The spacetime diagram below shows two events, A and B, 2/3 c as observed in a reference frame S. Each event emits a P signal. Use the diagram to calculate, according to frame The time between event A and event Q S, a) a) B In the The time taken for the light signal leaving event A what at the position of event B. The location of a stationary observer who receives signal from events A reference, total momentum is the total energy of P and Q? [1] what simultaneously same collision can be of P and viewed Q? [3] according to P’s frame the of light of the [2] The c) frame is to (ii) arrive laboratory [2] (i) b) 2/3 c light reference as shown in the diagrams below. with velocity = v receiving the light signal from event B. [2] P (rest) d) The velocity event A and of a moving event B frame occurred of reference in Q which simultaneously. [4] b) ct / ly 6 In P’s frame of reference, (i) what is Q’s (ii) what is the total what is the total (iii) velocity, v? [3] momentum energy of of P P and and Q? [3] Q? [3] 5 c) B As a result formed, of but the the collision, total many energy of particles the and particles photons depends are on 4 the frame reference of reference. agree or Do the disagree on observers the in number each of frame particles of and 3 photons formed in the collision? Explain your answer. [2] A 2 6. The concept slower as of they gravitational approach a red-shift black indicates that clocks run hole. 1 a) Describe (i) 0 1 2 3 4 5 6 Relativity and is meant by red-shift. [2] 7 x / ly 4. what gravitational (ii) spacetime. (iii) a black [1] hole with reference to the concept of simultaneity spacetime. a) State two postulates of the special theory of relativity. b) Einstein proposed a ‘thought experiment’ along A particular lines. Imagine a train of proper length 100 through a station at half the speed of light. at two of lightning the train, strikes, leaving one at scorch the front marks on and one both has a Schwarzschild radius R. A the distance of measures 2R the from time the event between horizon two of events the to be 10 s. There at that for a person a very long way from the black hole the the rear a hole Deduce are hole m black passing black the person following [2] [2] time between the events will be measured as 12 s. train i B Q u e s t i o n s – o p t i o n A – r e l A t i v i t y 151 [1] 14 o p t i o n B – e n g i n e e r i n g p h y s i C s t ConCepts The Translational complex motion of a rigid body can be analysed as Every combination of two types of motion: translation and these types of motion are studied separately in Rotational particle this the same in the object Every instantaneous (pages 9 and particle moves in a in the circle object around the study velocity guide motion rotation. has Both motion a same axis of rotation 65). Displacement, in s, measured Angular m displacement, measured Velocity, change v, of is the rate of Angular displacement rate of in radians velocity, change ω, of in m is the angle 1 measured θ, [rad] 1 s measured in rad s ds v = dθ _ dt mg ω = dt Acceleration, change of a, is the velocity rate of Angular measured the acceleration, rate of α, is change of angular measured in rad 2 in m 2 s velocity dv _ a A bottle bottle thrown follows addition the of linear mass angles of the The of the is object. air predicted about described all these the by centre one (or motion is apply apply to to circular of angular mechanics of velocity, circular ω, has motion already (see centre to the frequency of rotation by the When angular been about and a of a The 2π motion of the translational rotational motion a) Translational the wheel and forward wheel the can at each be constant have analysed rotational velocity different as the v, the velocities. addition of motion. motion is bicycle is moving forward at velocity v so the formula: centre velocity v. of All mass points has on forward the translational wheel’s rim have motion a f translational angular and moving on the of = is points wheel’s ω linear bicycle different introduced 66) following dt e x ample: BiCyCle wheel using The linked = In Comparison motion page α dt velocities the and = the axes. described velocities of motion. displacements, angular quantities mass more) quantities Rotational of projectile using these displacement), all – rotation. concept with the rotates motion (angular axis as accelerations; accelerations; given path bottle Translational and a through s dω _ component forward at velocity v velocity translational component of velocity ν equations of uniform angul ar aCCeleration The denitions acceleration equations equations of can (page of average be 11). An constant Translational linear rearranged velocity to derive equivalent angular average constant rearrangement linear acceleration derives b) Rotational motion The wheel is at constant the rotating around the motion Rotational a rim motion have a angular tangential velocity ω. Angular Initial u Initial v Final component displacement axis points of of on rotation velocity v the (= wheel’s rω) angular velocity θ ω tangential i velocity All ν s Final central acceleration. Displacement velocity and the angular velocity component of ω f velocity ν Time taken Acceleration t Time a Angular taken t acceleration α ν [constant] v = u + at [constant] ω = ω f + αt i ν 1 s = ut + c) 1 2 at θ = ω t + Combined motion 2 αt i 2 2 The 2 v 2 = u 2 + 2as ω 2 = f ω + the 2αθ motion vector of the different addition of the points above on two the wheel’s rim is components: i Point at top of wheel is (v + (ω u)t s + f _ ω )t i _ = θ 2 moving with instantaneous = 2 velocity of 2ν, for ward Point in contact with Point at side of ground is at rest. with instantaneous velocity of Instantaneous velocity is zero 152 o p t i o n B – E n g i n E E r i n g p h y s i c s 2ν, at 45° wheel is moving to the horizontal t rel ationship Between line ar and rotational quantities When an object additional is just rotating translational about motion of a the xed object, axis, all and the there is c) Accelerations The total two components: linear acceleration of any particle is made up of no individual a) The centripetal acceleration, a , (towards the axis r particles values that of make linear acceleration. up that object displacement, They do, have linear however, all different velocity share the instantaneous and of linear same rotation – see page 65), also known as the acceleration. instantaneous Tangential velocity Angular values of angular acceleration. The displacement, link between angular these velocity values radial and involves velocity angular the distance 2 v from the axis of rotation to the particle. 2 _ a = r = rω r instantaneous velocity V 1 par ticle 1 Rotation about Centripetal acceleration Distance from axis of axis. All par ticles have same rotation (along the to particle radius) m 1 instantaneous r 1 angular velocity V 2 b) An additional tangential acceleration, a , which results t , instantaneous ω from velocity r 2 an angular acceleration taking place. If α = 0, then m 2 a = 0. t axis Instantaneous acceleration Angular acceleration of rotation (along (into the page) par ticle 2 V 1 the tangent) ≠ V 2 a a) Distance on travelled circular = rα t Displacements Angular displacement Distance path rotation = from to axis of particle rθ The total acceleration of the particle can be found by vector ______ 4 addition Distance rotation b) Instantaneous Linear from to axis of these two components: a = r√ ω 2 + α of particle velocities instantaneous Angular velocity (along velocity the tangent) v = Distance rotation ω from to axis of particle o p t i o n B – E n g i n E E r i n g p h y s i c s 153 t b the moment of a forCe: the torque Γ A particle when the particle is is in equilibrium vector zero sum (see of if all page its the 16). acceleration external In this is forces zero. This acting situation, all on the occurs force F the forces r pass real through objects create a called The do single not turning the torque a is always effect moment the moment Greek or point and pass about of the a Γ of a to zero. through given force uppercase torque sum axis. or letter force, the the The same The about point turning torque. gamma, F forces The and θ O on θ can effect is symbol axis of for rotation r Γ. an axis is dened ⊥ as perpendicular the product of the force and the perpendicular distance from distance from O the axis of rotation to the line of action of the force. to line of action of F moment or torque force line of action of F = Fr⊥ Note: • perpendicular The torque energy • Γ = Fr sin The can the quantity to be a pair of points is the of a system produce equal but of a about forces turning that all In this axes has effect. anti-parallel application. by torque rotation calculations, the the measured as is in N m, but only joules. clockwise of this directed the is being can of into be the rotation. opposite of that direction axis is the out forces no A common acting situation, drawn resultant the force example with to is different resultant perpendicular but torque the If a resultant (page 17). object (page 16) the force When then or anticlockwise treated torque In the considered. the the a vector example paper. direction, as If the torque For the vector considered above, force vector F the was would be paper. we as acts know this on there it an is no to be means its object then resultant in it must force translational acceleration accelerate acting on an equilibrium must be zero. plane Similarly, dened both rotational and transl ational equiliBrium is same are expressed any of with in directed Couples of vector applied does of axis along torque which be direction purposes couple energy θ about A and also distance if there is a resultant torque acting on an object then forces. it O F must be in have an angular rotational external torques acceleration, equilibrium acting on the only α. if object Thus the is an vector object sum will of all the zero. arbitrary x axis If an in object static is not moving equilibrium. and This not must rotating mean then that it the is said object to is be in d both For rotational rotational α In that to F = 2D 0 ∴ and ∑ Γ problems there the is plane problems, translational equilibrium. equilibrium: = (in no 0 the torque being three x-y plane), about any considered axis it is one sufcient axis (parallel directions (x, y to and the z) to show perpendicular z-axis). would In need 3D to be considered. For translational a In = 2D 0 three = F(x + = F d d) - ∑ F force axis clockwise – is sufcient two directions to different (x, y and z) show that directions. would there In need 3D to 5 N 3 N E n g i n E E r i n g f N axis into the p h y s i c s = example 2.25 N above, for rotational is equilibrium: no problems be x f B 0 F In o p t i o n it in This result is independent of position of axis, O 154 equilibrium: = problems, resultant Torque of forces ∴ considered. eb (a) Centre of gravity plank balances if pivot is in middle centre of gravity The effect object of can object’s gravity be on treated centre of all as a the different single force parts acting of at the the There is no moment about gravity. W the centre of gravity. If an of object gravity object is trivial be an – is not it is outside object of will uniform be in the uniform, possible the then for object. from a shape middle an and of density, the nding its object’s centre Experimentally, point and it is free to the object. If position if of centre the is (b) gravity you of gravity will always end up move, below rotates clockwise if pivot is to the then the left to suspend W the (c) centre plank not point plank rotates anticlockwise if pivot is to the right of suspension. W e x ample 1 10 m • All forces at • You do you calculate (for the • You need • When not an axis have have to zero choose moment the pivot about as the that axis axis. about which 4 m 6 m R 2 R torques, but it is often the simplest thing to do 1 W c W b that , weight of car • , weight of bridge reason to object Newton’s AND remember solving an in above). the sense two-dimensional is laws in rotational still apply. translational (clockwise problems equilibrium Often an equilibrium. it anticlockwise). sufcient about object This or is is can any in to ONE show axis. rotational provide a simple When a car goes across a br idge, the forces (on the bridge) are way of nding an unknown force. as shown. • The weight of an object can be considered to be concentrated T aking moments about right-hand suppor t: at its centre of gravity. clockwise moment = anticlockwise moment • (R 1 × 20 m) = (W b × 10 m) + (W c 2 × 20 m) = (W b × 10 m) + (W c the lines problem of order T aking moments about left-hand suppor t: (R If only involves three non-parallel forces, the × 4 m) action to be in of all the forces rotational must meet at a single point in equilibrium. × 16 m) Also, since bridge is not accelerating: R 1 When + R solving 2 = W b problems P + W c to do R with rotational equilibrium W remember: 3 b) e x ample 2 A ladder friction) a) of length at an Explain friction forces 5.0 angle why of the between m leans 30° to ladder the against the can smooth wall and stay the What stay in place if there is in meet the between (no vertical. only ground a must at a point minimum the ladder if in equilibrium coefcient and the of ground static for fraction the ladder to place? is ladder. R H (a) The reaction from the wall, Rw Rw and the ladder ’s weight (b) R P Equilibrium conditions:- R g v ( ) W = R 1 R = R 2 R h = Wx 3 v meet at point P. For ( ) H w equilibrium the force from wall moments 30° 5 m w the ground, Rg must also about Q pass through this point h (for zero torque about P). F f ∴ ∴ R g ≤ µ s R Rg is as shown and has R H ≤ µ s Rv a horizontal component W R w (i.e. friction must be acting) using µ & s ≥ W 60° Q x 3 µ s ≥ x 2.5 cos 60 = h 5.0 sin 60 ground ∴ o p t i o n B – E n g i n E E r i n g µ s ≥ 0.29 p h y s i c s 155 n’ c – ne wton’s seCond l aw – definition of moment of inertia F • Every particle in the object has the same angular xed axis of acceleration, α rotation angular tangential The acceleration dened moment of inertial, I, of an object about a particular axis is acceleration α by the summation below: a t O the moment of inertia distance from the of axis the or particle rotation par ticle rigid body 2 I Newton’s second law as applied to one particle in a rigid = ∑ mr body mass Newton’s second law applies to every particle that makes up a of and motion. small the must In the particles resultant also apply diagram each force if the above, with that a the mass acts on object object m one is F is undergoing is the particle. made up tangential The other radial not included. F = component, m a For = this cannot produce particle we can angular apply in individual the object rotational of lots of component Note that moment • A scalar • Measured • Dependent of inertia, I, is of quantity component, 2 the an large particle object acceleration Newton’s so second it in kg 2 m (not kg m ) is on: law: ◊ The mass ◊ The way ◊ The axis of the object mrα t 2 so torque Similar up the Γ = (mrα)r equations object can and be = mr created summed this mass is distributed α for all the particles that of rotation being considered. make together: Using this denition, equation 1 becomes: 2 ∑ Γ = ∑ 2 mr resultant α torque 2 or ∑ Γ = α∑ mr external in N angular acceleration in rad s m (1) ext Note that: Γ • Newton’s third law applies and, when summing up all = I α the 2 moment torques, forces the internal between external torques particles) torques are (which must sum result to from zero. the Only of inertia in kg m internal This the is Newton’s compared left. to F second = law for rotational motion and can be ma moments of inertia for different oBjeCts Equations for moments of inertia in different Object situations Axis of do not need moment rotation to be memorized. of Object Axis inertia of moment rotation of inertia thin ring (simple wheel) Sphere through centre, 2 perpendicular to mr r plane m 2 through centre 2 mr 5 thin ring through a 1 2 mr r 2 diameter m disc and cylinder (solid ywheel) through centre, 1 perpendicular to Rectangular lamina 2 mr 2 Through the r plane centre m of mass, 2 2 l + h _ perpendicular to m ( ) 12 l thin rod, length d through the plane of the centre, perpendicular lamina h 1 _ m 2 md 12 to rod d i. e x ample A torque of 30 N m acts on a wheel with moment of what is the angular velocity of the wheel? inertia ii. how fast is a point on the rim moving? 2 600 kg m . The wheel starts off at rest. 30 _ Γ a) a) What b) The angular acceleration is Γ = I α ⇒ α = produced? = 2 = I 5.0 × 10 2 b) wheel has a radius of 40 cm. After 1.5 i. ω = αt = 5.0 × 10 1 × 90 = 4.5 minutes: 1 ii. 156 o p t i o n B – E n g i n E E r i n g p h y s i c s v = r ω = 0.4 × 2 rad 600 4.5 = 1.8 m s rad s s r c energy of rotational motion Energy considerations complicated done. the In problems. the object often absence will be provide When of any stored as a Conservation of angul ar momentum simple torque resistive acts solutions on torque, rotational kinetic an the to object, work In work done is exactly linear the same motion to way that Newton’s laws can be applied to derive: on • the concept of the • the relationship impulse of a force energy. F between impulse and change in momentum • the law of conservation of linear momentum, F then Newton’s laws can be applied to angular situations θ to derive: r P • The axis of rotation concept Angular which Calculation of work done by a the the situation above, a As a result, an force F is applied and the done, W, is angular calculated as displacement of θ occurs. = F the × Γ (distance = I α we along know of torque and the time for acts: shown arc) that = W F = ΓΔt varies given to with an time object then can be the total angular estimated from the area below: × = impulse torque rθ = Γθ time. the This given Using impulse: product The under W the object impulse work angular is torque If rotates. the torque angular In of impulse to graph is an showing analogous object as a the to variation estimating result of a of the torque total varying with impulse force (see Iαθ page23). We can apply the constant angular acceleration equation to • substitute for The relationship angular 2 between angular impulse and change in αθ: momentum: 2 ω = ω f + 2αθ i angular impulse angular momentum applied to an object = change of 2 2 ω ω f ∴ W ( = I 1 i ___ _ ) - = means that we have = the object i 2 an equation for rotational The law of conservation of angular momentum. KE: The 1 E by Iω f 2 • This experienced 2 Iω 2 2 1 2 total angular momentum of a system remains constant 2 I ω K Work provided 2 rot done by the torque acting on object = change no resultant external torque acts. in Examples: rotational KE of object a) The total KE is equal to the sum of translational KE and A skater body rotational KE = translational 1 Total KE = KE 1 2 Mv + rotational KE that For a single The linear tangential spinning their on a vertical moment of axis inertia down by their drawing the This mass of allows the their arms is mass no to be in redistributed so from the axis of longer rotation thus at a signicant reducing Σmr 2 Ex tended arms mean Bringing in her arms larger decreases her moment radius and smaller velocity of ro tation. of iner tia and therefore particle increases her rotational momentum, speed angular arms. distance Iω angul ar momentum linear is reduce 2 2 + 2 The can KE: their Total who the v is m p, a particle of mass dened as the m which has velocity. a v momentum, momentum of L, about is the axis of moment of the rotation 2 Angular momentum, For a larger The angular rotation is L = L of L = (mv)r = (mrω)r = (mr )ω object momentum dened an object about an axis of as 2 Angular L Note • = momentum, ∑(mr )ω Iω that total angular momentum, a vector (in the same a vector for calculations) 2 • measured in • dependent kg m way that a L, is: torque is considered to be 1 s or N m s b) total on angular all rotations momentum taking of a place. planet For example, orbiting a star the would involve: The a Earth–Moon result between acts to the spinning of the planet about an axis through centre of mass the the oceans the orbital the star. angular the produces movement and Earth. Earth’s Earth’s spin angular tides of This on in the water, provides its own momentum. oceans. friction a axis The torque and As exists that thus angular momentum means that there conservation must be a and corresponding ◊ system relative the of planet’s the reduce reduces ◊ of momentum about an axis increase in the orbital angular momentum through of the Earth–Moon separation o p t i o n B – is slowly system. As a result, the Earth–Moon increasing. E n g i n E E r i n g p h y s i c s 157 s b summary Comparison of equations of line ar and rotational motion Every equation for linear motion has a corresponding Linear Physics principles A Newton’s Work second law F external done W m = energy E force The on a value determined by point of object A the the F resultant causes mass and of s = W = m Conservation of momentum v E P = F p = m The v v total linear momentum constant force Resultant provided of no a analysing approach is to appropriate a) Graph This not at In is the 10). any Thus is the value determined resultant by of the object the moment torque. I ω 2 P = Γ L = I The ω ω total constant acts. angular force m Moment Acceleration a Angular Displacement s Velocity v Linear p momentum the linear no of resultant a system external remains torque acts. Mass situation, momentum provided torque of Γ inertia I acceleration α Angular displacement θ Angular velocity ω Angular momentum L e x ample simplest situation A and use solid of cylinder, angle 30° as initially shown at in rest, the rolls down diagram a 2.0 m long slope below: relationships. to a situation, useful equal is extended 2 = Resultant equivalent equivalent instant the an The θ F displacement linear represent any the equivalent angular graph time. rotational imagine the of any system resultant proBlem solving and graphiC al work When Γ rot external used on K remains Symbols and 1 2 Momentum = torque acceleration. α 2 K Power I external acceleration inertia Γ motion rotational angular force. a 1 Kinetic is resultant = Rotational acceleration. acceleration the equivalent: motion resultant causes angular vs graph the the gradient of of linear area quantity to time and the angular the graph gradient instantaneous an displacement under of velocity 2.0 m vs does the (see displacement line page vs 30° time graph gives the instantaneous angular velocity. The b) Graph of angular velocity vs mass of Calculate This graph is equivalent to the cylinder is m and the radius of the cylinder a graph of linear velocity the velocity of the cylinder at the bottom of the vs Answer: time. In the linear situation, the area under the graph Vertical represents the distance gone and the gradient of the line height instant page 10). is equal Thus the to the area instantaneous under an acceleration angular fallen by cylinder lost = 1 vs gained 1 2 = mv + gives the total angular displacement gradient of an angular velocity vs time the instantaneous angular graph but I 2 = mR (cylinder) v Graph of torque vs ω = time R 2 This graph is equivalent to a graph of force vs time. 1 In ⇒ KE gained 2 = mv 1 mR _ 2 2 2 v _ + 2 2 the linear situation, the area under the graph total impulse given to the object which is equal to the 1 2 = mv + 2 change of momentum of the object (see page 23). area under the total the torque vs time graph 2 mv 4 Thus 3 the 2 = represents mv 4 angular impulse given to the object which Conservation is equal to the change of angular of energy momentum. 3 ⇒ mgh 2 = mv 4 ____ gh _ ∴ v = 4 √ 3 ___________ 4 × 9.8 × 1.0 __ = √ 3 1 = 158 o p t i o n B – R represents 1 the E n g i n E E r i n g m 2 acceleration. and c) 1.0 2 2 gives = and 1 the sin30 Iω 2 graph 2.0 mgh (see velocity KE time = at PE any is R. time p h y s i c s 3.61 m s see page 156 slope. tc cc definitions Historically, situations. powerful The the study These intellectual terms used of laws, need the behaviour otherwise of known to be laws led of to some very fundamental thermodynamics, provide concepts the that modern are applicable physicist with to a many set of other very explained. Most system macroscopic of the thermal time when The If surroundings its we energy are and this focusing the can our (see context it of do the gas as work behaviour a or whole. work of In can an ideal terms be of done gas in work on it. particular and In situations, energy, this the context, gas the we can gas focus gain can or be on the lose seen as a system surroundings. surroundings In studying behaviour thermodynamic Q gases the tools. Thermodynamic Heat ideal as study For on the example behaviour the of expansion an of a ideal gas gas, then means everything that work is else done can by be the called gas on the below). heat refers to the transfer HOT of a the quantity system This of and transfer thermal its energy between thermal energy ow surroundings. must be as a result of thermal a HOT temperature COLD energy difference. ow thermal energy ow HOT Work W In 1. this context, work done work = refers force × to the macroscopic transfer 2. distance of energy. work done F For = example potential difference × current × time heater F compression This is just example When a gas is compressed, work is done on the work the Internal U in (∆U = energy change done internal gas on it. is compressed, When a gas the surroundings expands it does on the being gas. do work on surroundings. The the a work gas power supply When another of internal energy intermolecular page can be forces thought and the of as kinetic the energy energy held due to within the a system. random It motion is of the the sum of the molecules. PE due to See 26. energy) This is different the system, the overall to the which total would energy also of system include with motion of the system and internal any PE due to external forces. energy U In thermodynamics, in internal it is the changes velocity (system also has kinetic energy) v energy that are being h considered. a gas must (e.g. is If the increase. liquid change internal increased, of → A then change gas) internal energy its also of height (system also has temperature of gravitational potential energy) phase involves a energy. The its Internal of an energy ideal monatomic The gas gas internal changes produces energy from the T same of to an (T ΔT. 3 page 30), E = K T B its the depends internal only on energy temperature energy is of a system is not the same as energy temperature. changes related to from the When U to (U average the + temperature ΔU). kinetic The energy of same per an ΔU ideal always molecule (see R = T, 2 gas ΔT) Since 3 k 2 ideal + total internal the internal energy U, is the sum of the total random kinetic energies of the N A molecules: 3 U = nN E A = nRT K [n = number of moles; N = Avogadro’s constant] A 2 o p t i o n B – E n g i n E E r i n g p h y s i c s 159 w b Work work done during e xpansion at Constant pressure Whenever a gas expands, it is done W = force = F∆x F × distance doing force _ Since work of on the its gas surroundings. is changing all If the the pressure time, area then F calculating is the complex. amount This is of work because we force the = pressure = pA constant done therefore pressure p cannot ∆x assume of × a work constant done distance). (work If the in done = the force pressure must also is constant then If and we can ∆V work done = p∆V the the force calculate if a gas positive) the positive) work done. p V diagrams and work done It is often useful thermodynamic is that the shown area to represent process under on the the a pV graph changes that diagram. An represents happen to important the work a gas during reason done. The for a choosing reasons for to this below. p erusserp A B area of strip p = p∆V = work done in expansion area under graph = work done in expanding fr om state A to state B ∆V This turns out to be generally volume V true for A expanding from any thermodynamic p erusserp p erusserp work done by gas process. work done by A state A to state B to state C atmosphere as gas contracts from state C to state D to state A B D C C volume V 160 o p t i o n B – increases its volume (∆V F is is constant pA∆x = changes change. So pressure = A∆x force so then W but equation E n g i n E E r i n g volume V p h y s i c s do this are then the gas does work (W is t c Q first l aw of thermodynamiCs There rst are law three is simply conservation energy Q happen As is = a a is laws statement applied to a to ∆U system, or it of the combination energy energy Q as given (or internal fundamental of can of the thermodynamics. principle system. then one both). do If an of The work of two of things can If + must ∆U increase it its is W W to are remember all negative, this is increasing. If it If is is taken what from the the signs system’s of these ‘point then then positive, thermal thermal is then (The negative, this energy is going into the energy is going out of the the internal temperature the internal positive, then the gas energy the energy temperature surroundings.(The of of system is of the is the gas is of gas the system increasing.) system is is decreasing.) doing work on expanding.) symbols If They is decreasing.(The W important mean. positive, If the It is system. thermal conserved ∆U this system. energy amount system If The of it is negative, the surroundings are doing work on view’. the system. (The gas is contracting.) ide al ga s proCesses A gas the can diagrams 1. undergo changes can any be number represented represent a type of of on different a process 2. Isochoric types of change pressure–volume called a or process. diagram reversible and Four important the rst law of 3. Isothermal processes are thermodynamics considered must below. apply. To be In each precise, case these process. Isobaric 4. Adiabatic (isovolumetric) In In an isochoric process, also the gas has isochoric below a constant The shows diagram an isobaric expansion constant an decrease has pressure. an process, diagram shows gas process in pressure. In an the isothermal gas has a diagram A B shows In an adiabatic there The below isothermal process constant temperature. p erusserp below a The isobaric p erusserp volume. the called isovolumetric an is energy an expansion the gas no transfer and if the between the surroundings. that process thermal This gas means does work it A must in result internal in decrease energy. compression p erusserp is a or A rapid expansion approximately B A adiabatic. volume V volume V done sufcient Isobaric change Isothermal = constant, or T = is because there time for is not thermal change energy p B This quickly constant, to be exchanged or with the surroundings. V = pV = constant positive Q positive an positive (T ↑) ∆U p erusserp ∆U W = zero constant, positive W positive or p = constant T Q below adiabatic shows expansion (volumetric) change V diagram T Q Isochoric constant The volume V A negative B ∆U negative (T↓) volume V W zero Adiabatic Q change zero e x ample ∆U A monatomic adiabatic gas doubles expansion. its What 5 5 3 3 is volume the as a change result in of W pressure? For p V 1 = p 1 negative (T↓) an a positive monatomic gas, the V 2 2 equation for an adiabatic 5 p V 3 2 1 _ = p 1 ( process ) V is 5 2 3 pV = constant 5 3 = ∴ nal pressure 0.5 = 0.31 = 31% of initial pressure o p t i o n B – E n g i n E E r i n g p h y s i c s 161 sc c seCond l aw of thermodynamiCs Historically stated in shown the many to be second law different equivalent of ways. to All one entropy and energy degradation thermodynamics of these has versions been can Entropy be of principle thermal there is energy nothing into to useful a property that expresses the disorder in the another. The In is system. stop the work. In complete practice, conversion a gas can is not details linked system. are to [S not the = important number k of but the possible entropy S of arrangements a system W of the ln(W)] B continue to expand forever – the apparatus sets a physical Because limit. Thus the continuous conversion of thermal molecules roughly into work requires a cyclical process – a heat are in random motion, one would expect energy equal numbers of gas molecules in each side of a engine. container. W An arrangement like this is much more likely T than one like T hot cold Q Q hot cold The Carnot showed In other words there that Q must be thermal energy number set-up hot > W ‘wasted’ to the cold reser voir. realization leads to possibly the simplest the second law of thermodynamics (the of arranging the molecules that the is arranging right greater entropy to of the than get the molecules the the number set-up system on on the the to of get the ways left. right is of This greater formulation than of ways the means This of on the entropy of the system on the left. Kelvin–Planck In any to increase. random process the amount of disorder will tend formulation). No heat engine, operating in a cycle, can take in its surroundings and totally convert it into other words, the total entropy will always heat increase. from In The entropy change ∆S is linked to the thermal ∆Q work. ___ energy change ∆Q and the temperature T. (∆S = ) T Other possible formulations include the following: thermal energy ow No heat pump can low-temperature reservoir transfer reservoir without work thermal to a being energy from a high-temperature done on it ∆Q (Clausius). T hot Heat The ows concept of from hot entropy objects leads to to one cold nal T cold objects. version of the ∆Q ∆Q second law. decrease of entropy = increase of entropy = T T hot The entropy of the Universe can never cold decrease. When thermal object, overall energy the ows total from entropy a has hot object to a colder increased. e x amples In The rst and second laws of thermodynamics both must many concept. to all situations. Local decreases of entropy are possible as elsewhere there is a corresponding A refrigerator is an example of a idea of is energy shared degradation out, the more is a useful degraded becomes – it is harder to put it to use. For example, can be the increase. internal 1. the energy more so it long situations The apply heat energy that is ‘locked’ up in oil released when pump. the oil the form It thermal energy taken from is is not burned. of In the thermal feasible to end, energy get it all – the energy shared released among many will be in molecules. back. ice box and ejected to surroundings 3. Water freezes which the receiving at 0 °C entropy the because increase latent heat) this of the equals is the temperature surroundings the entropy at (when decrease of source of work the water molecules becoming more ordered. It would not is the electric freeze at a higher temperature because this would mean energy supply that A 2. It the overall entropy of the system would decrease. refrigerator should be possible theoretical system boat around to for design increasing temperature of surroundings a propelling a -2 °C based atmosphere reservoir could The the be could and cold used as movement water heat be the 0 °C 2 °C The hot the sea reservoir. boat the as from cold the be engine. used water the of would a ICE through work ICE/WATER since done. WATER MIX since since This to is possible work warmed for BUT ever. and the it The cannot sea continue would atmosphere be entropy entropy entropy entropy entropy entropy decrease increase decrease increase decrease increase would of ice be cooled and eventually there formation be 162 no temperature < of surroundings difference. o p t i o n B – of ice = of of ice > of would E n g i n E E r i n g p h y s i c s formation surroundings formation surroundings h In he at engines A central engine. thermal The are concept A heat used in is order examples of heat any to combustion generate generalized study engine is that work. in It a A and in block shown uses a a is the source converts car energy engines. engine thermodynamics device do electrical heat of heat the power diagram of into work. turbines station representing in pressure of thermal a this, hot and the energy the some thermal reservoir isobaric must the been must A different ejected decrease in have been isovolumetric expansion). have isovolumetric energy (during to a pressure cold and increase amount reservoir the isobaric a isobaric expansion A B total work done by the gas COLD done W reser voir T ENGINE hot do compression). are below. reser voir T to from (during that work HOT order taken heat p erusserp both to the engine energy internal in thermal thermal energy energy Q Q isovolumetric isovolumetric increase in decrease in pressure pressure cold C hot D isobaric compression cold volume V The Heat thermal efciency of a heat engine is dened as engine work done ____ η In this context, temperature the word source (or reservoir sink) of is used thermal to imply energy . a = constant Thermal (thermal energy This be taken from the hot reservoir without causing the energy taken from hot reservoir) can temperature is equivalent to of rate of doing work ____ the hot reservoir to change. Similarly thermal energy can be given to η = (thermal the cold reservoir An ideal gas can without be used increasing as a heat its power to its a simple starting enclosed by example. conditions, the cycle but The the represents engine. The four-stage gas the pV diagram right has cycle done amount returns work. of The work the heat heat pump pump reservoir to a reservoir) useful work done __ η = input area done. The cycle of maximum changes possible that results efciency is in a heat called the engine with Carnot the cycle Carnot CyCles and Carnot theorem is a causes hot work heat engine thermal energy reservoir. must be being In to order run be in reverse. moved for this to from be A a The cold achieved, Such done. input HOT COLD work ∆W reser voir Carnot theoretical an cycle heat reser voir represents engine idealized p erusserp mechanical hot gas he at pumps A from temperature. energy represents taken the with engine is cycle the of processes maximum called a for possible Carnot a efciency. engine A Q hot thermal energy taken in B area = work done HEAT T T hot cold by gas during PUMP D Carnot cycle thermal energy thermal thermal C energy energy Q Q given out Q cold hot Heat cold V pump Once again Carnot an ideal thermodynamic used in time an the heat gas can processes engine, anticlockwise be can but circuit used be the as a heat exactly the processes will are represent pump. same all the The ones as It cycle consists of an p erusserp • Isothermal • Adiabatic • Isothermal total work • Adiabatic done on The opposite. cycle of ideal gas undergoing the following processes. were expansion (A → B) This expansion (B → C) processes. compression (C → D) isobaric compression A D the gas compression temperatures maximum of possible the (D hot → A) and efciency cold that reservoirs can be x the achieved. isovolumetric isovolumetric The efciency decrease in of a Carnot engine can be shown to be T increase in cold _ η = 1 (where T is in kelvin) Carnot pressure T pressure hot An B at C engine 20 °C. operates The at 300 maximum °C and possible ejects heat theoretical to the surroundings efciency is isobaric expansion 293 _ volume V η = 1 = 0.49 = 49% Carnot 573 o p t i o n B – E n g i n E E r i n g p h y s i c s 163 f HL The symbol representing density is the Greek letter normal pressure definitions of density and pressure rho, ρ. The force ΔF _ p average density of a substance is dened by the following = equation: ΔA average density m • _ ρ area mass Pressure is a scalar quantity – the force has a direction but = the V pressure does not. Pressure acts equally in all directions. volume 2 • • Density is a scalar The SI unit of pressure is N m 2 or pascals (Pa). 1 Pa = 1 N m quantity. 5 3 • The SI units of density are 3 • Densities can also be • Atmospheric • Absolute pressure ≈ 10 Pa kg m quoted in g cm (see conversion pressure is the actual pressure at a point in a factor uid. Pressure gauges often record the difference between below) absolute 3 • The density of water is pressure and atmospheric pressure. Thus if a 3 1 g cm = 1,000 kg m 5 difference Pressure at any point in a uid (a gas or a liquid) is pressure gauge gives a reading of 2 × 10 Pa for a dened 5 gas, interms of smallarea, the force, ΔA, that ΔF , that contains acts the normally (at 90°) to pressure separated ρ , then by the in a a uid increases vertical pressure with distance, d, difference, absolute pressure of the gas is 3 × 10 Pa. a point. variation of fluid pressure The the in Δp, BuoyanCy and arChimedes’ prinCiple depth. a uid If two of between points constant these two are Archimedes’ density, in points magnitude is: a uid, it principle states experiences to the a weight that when buoyancy of the uid a body upthrust is immersed equal displaced. B in = ρ V f f density of uid ∆p gravitational = eld g f strength ρ f 22N pressure The of total the difference pressure pressure at due a acting to given at the depth depth in surface 1 7N 12N depth a liquid is the (atmospheric addition pressure) density and the additional pressure due to the depth: B Atmospheric pressure density of B of uid 1 2 uid depth P = P + ρ 0 volume of f W W W uid displaced uid displaced (w = 5N) (w = 10N) (a) Note • that: Pressure depth is be expressed head) in approximately column • can (or As of a the mercury pressure is in known same (Hg) as or dependent terms a on of liquid. exerted 10 the equivalent Atmospheric m by a 760 column depth, the of A pressure mm high water. pressures at consequence principle object is of that displaces weight of a this oating its own uid. two weight of uid displaced points that are at the same horizontal level in the same = liquid that must liquid be the and same the provided liquid is they are connected total weight of duck by static. atmospheric pressure pa sC al’s prinCiple the water column exer ts Pascal’s principle states that the pressure applied to an a pressure at B equal to h excess gas enclosed liquid is transmitted to every part of the liquid, the excess pressure of pressure P whatever A B design solids • The pressure this means is independent that liquids will of the always cross-sectional nd their own area – level. of respond When a uid is in hydrostatic when all the equilibrium forces on a solid one end will be it takes. and when given it volume is of at rest. uid hydraulic to This principle (e.g. other on the solids transmit systems and is is central different to to the how forces. object its exerted liquids happens shape many Incompressible hydrostatiC equiliBrium A the the gas supply: P = hρg an end is incompressible held restraining transmit in place, stick) then is the pushed same at force object. forces whereas incompressible pressures. This are applied force F A 2 balanced. Typically external forces (e.g. gravity) are balanced load = F × (eor t) A 1 by a pressure gradient across the volume of uid (pressure load platform increases with depth – see above). downward force due to piston of piston of area A 2 pressure from uid above area A 1 volume of uid weight of uid W upward force due to contained in volume pressure from uid below 164 o p t i o n B – E n g i n E E r i n g hydraulic liquid p h y s i c s f – B c HL • the ide al fluid In most real following create be uid dene model. ow an This is extremely ideal simple uid that model complicated. can can be be used later Is non-viscous converted The of to rened to • the ow) box uid: incompressible – thus its density will be • constant. into of a not as of a steady uid. below). Does – a result thermal viscosity Involves realistic. ideal Is properties simple more An • a situations, real See have (as these page uid See ow, page no 167 energy for gets the denition uid. ow Under of energy. 167 angular opposed to conditions for an a turbulent, the analysis momentum – ow of it is or turbulent does chaotic, laminar not (see ow. rotate. l aminar flow, stre amlines and the Continuity equation speed ν 2 When of the ow the ow uid is of can said to a liquid have be is steady different laminar if or laminar, instantaneous every particle different velocities. that passes parts The through speed ν 1 a given is point made. place has The when the same opposite the of particles velocity laminar that pass whenever ow, the observation turbulent through a given ow, point takes have a area A area A 1 2 wide variation of velocities depending on the instant when the density ρ 1 observation is made (see page density ρ boundary 167). (streamlines) A streamline laminar given ow point is the means in the path that uid taken all by a particles must follow particle that the in pass same the uid through and In a a time Δt, of the tangent to a streamline gives streamline. the mass, m , entering the cross-section The direction m = ρ A 1 v 1 ∆t 1 the mass, m , leaving the cross-section A 2 instantaneous velocity that the particles of the uid have = ρ 2 point. No uid ever crosses a streamline. Thus a A 2 v 2 ∆t 2 collection Conservation of streamlines tubular tube can region through of its together uid ends dene where and a uid never tube only of ow. enters through its and is 2 at m that is 1 of Similarly the A 1 1 direction the This of mass applies to this tube of ow, so is leaves the ρ A 1 This sides. v 1 is = ρ 1 A 2 an v 2 ideal 2 uid and thus incompressible meaning ρ = ρ 1 A v 1 This a uid ows into a 1 is The uid must end up v 2 the narrow section of a The pipe: or Av = , so 2 constant 2 continuity Bernoulli work • A equation the Bernoulli equation the Bernoulli effeCt When = moving at a higher speed done equation and the results from conservation of a consideration energy when an of the ideal uid (continuity changes: equation). • This means the uid must have been • its speed (as a result of a change in cross-sectional area) • its vertical height as a result of work done by the uid pressure. accelerated forwards. The equation along any a quantity that is always of vertical uid height particles uid uid higher pressure lower pressure higher pressure lower speed higher speed lower speed constant streamline: speed density of identies given 1 pressure 2 _ ρv + ρgz + p = constant 2 gravitational density • This means there must be a pressure difference forwards with eld of a lower in the pressure wider in the narrow section and a higher pressure section. Note that: 1 Thus an increase in uid speed must be associated with strength uid a • The rst term ( 2 ρv ), can be thought of as the dynamic pressure. 2 decrease in uid pressure. This is the Bernoulli effect – the • greater the speed, the lower the pressure and vice The last two terms (ρgz + p), can be thought of as the static versa. pressure. • Each term in the 2 N • The the m last Pa, of J the Bernoulli B has several possible units: . above units leads gravitational unit volume o p t i o n m – to a new interpretation for equation: KE per equation 3 , + per PE unit + pressure = constant volume E n g i n E E r i n g p h y s i c s 165 B – HL appliC ations of the Bernoulli equation a) Flow out of a container d) Pitot tube to determine the speed of a plane A A pitot two liquid tube is separate attached facing forward on a plane. It has tubes: streamline direction small static of air ow pressure openings density ρ h B arbitrary zero impact opening static To calculate can apply the speed Bernoulli’s of uid owing equation to the out of a container, streamline shown pressure we tube above. total At A, p = At B, p = atmospheric and v = zero pressure tube atmospheric and v = ? • 1 + ρgz + p = front hole (impact opening) is placed in the constant airstream 1 ∴ The 2 ρv 2 0 + hρg + p called 2 = ρv + 0 + and the measures stagnation the total pressure), pressure P p (sometimes . T 2 ___ v = • The side • The difference hole(s) measures the static pressure, P . √ 2gh between P and P , is the dynamic T b) Venturi tubes pressure. A Venturi meter calculated from allows a the rate of ow of a measurement of pressure uid to The Bernoulli equation can be used to calculate airspeed: be 1 difference P P T 2 = ρv s 2 between two different cross-sectional areas of a pipe. ________ 2(P P ) T _ to metal end area A v = √ ρ constriction e) of area a Aerofoil (aka airfoil) ν A dynamic lift F B pressure P 1 ow of (e.g.) water, h density ρ 1 ν 1 manometer liquid aerofoil (e.g. mercury), density ρ 2 ν 2 • The pressure calculated difference by taking between readings of A Δh and B and can ρ be from air ow the 2 attached manometer: pressure P 2 P P A • This = ∆hρ B value g 2 and measurements of A, a and ρ allows the Note that: 1 uid speed at A to be calculated by using Bernoulli’s • equation and the equation of Streamlines closer together above the aerofoil imply a continuity decrease above in the cross-sectional area of equivalent tubes of ow aerofoil. 2∆hρ g 2 ________ v = 2 √[ A ρ ( a 1 ) • ] Decrease in increased • The rate of ow of uid through the pipe is equal to A × v cross-sectional velocity continuity). v > Fragrance spray • Since v > v 1 b. Constriction in tube causes low pressure • region as air travels faster in this section Bernoulli different the below-pressure zone • squeeze- When c. (height can difference and forms little droplets Squeezing as it enters the air jet bulb forces air through tube 166 o p t i o n B – tube the of E n g i n E E r i n g p h y s i c s implies (equation of P can be used difference not to calculate relevant) the pressure which can support aeroplane. attack become and ow aerofoil 2 the of of is too great, turbulent. the This ow over reduces Liquid is drawn up tube by pressure dierence a. of angle surface bulb < 1 equation weight area above 2 P 2 ow v 1 c) of leads to the plane ‘stalling’. the the upper pressure vc HL A) definition of visCosity An ideal uid different into are does layers thermal needed of not uid. energy to resist As a during maintain a the relative result there laminar steady motion is ow rate of no and ow. Tangential stress relative between conversion no external Ideal uids of velocity ∆v area of contact A work forces are retarding force -F non- accelerating force viscous whereas external force is acceleration). layers of a real uids needed Viscosity uid which to is are maintain an are viscous. a internal moving In a viscous steady friction with rate uid, of ow between different a F steady (no different The tangential stress is dened as: velocities. F τ The denition of the viscosity of a uid, η, (Greek letter Nu) = A is 2 in terms of two new quantities, the tangential RH side). stress, τ, • and Units of tangential stress are N m or Pa Δv the velocity gradient, (see B) Velocity gradient Δy The coefcient of viscosity tangential η is as: y velocity stress F⁄A _ __ η dened = = velocity (v gradient + v) Δv⁄Δy v 2 • The units • Typical of η values are at N s 1 m room or kg y 1 m s or Pa s v temperature: 3 ◊ Water: ◊ Thick 1.0 × 10 Pa s 2 • syrup: Viscosity is 1.0 very × 10 Pa sensitive to s changes of temperature. The For a class of uid, called Newtonian uids, velocity gradient is dened as: experimental Δv _ velocity measurements gradient (e.g. show many that pure tangential liquids). stress For is these proportional uids the to gradient = velocity coefcient Δy of 1 • viscosity is constant provided external conditions remain law • predicts the viscous drag force F that of velocity gradient are s constant. stokes’ l aw Stokes’ Units acts on The uid is columns a innite of uid in can volume. be Real affected by spheres the falling proximity through of the D perfect sphere when it moves through a walls uid: • uid at this point moves The of the size than of the container. the size particles of the of the uid is very much smaller sphere. with body (boundary layer) The forces on a sphere falling through a uid at terminal sphere has velocity are as shown below: uniform velocity D v uid upthrust F viscous drag F r driving equal opposing force viscous drag sphere sphere velocity innite expanse v r density ρ of uid η uid pull of Drag force acting on sphere in viscosity N of uid in Pa s density σ Ear th F = 6 W D 1 radius of sphere in m velocity of sphere in m s At terminal velocity v , t Note Stokes’ law assumes that: W = U + F D • The speed of the sphere is small so F that: = U W D ◊ the ow of uid past the sphere is 4 streamlined 6πηrv = 3 πr (ρ σ)g t 3 ◊ there is no slipping between the uid and the sphere 2 2r (ρ - σ)g __ ∴ v = t 9η speed turBulent flow – the re ynolds numBer Streamline ow rates ow the only ow occurs becomes at low uid ow rates. At high bulk Reynolds of ow radius vrρ R Note is extremely uid ow down a becomes pipe, number, difcult R, a predict turbulent. useful which to is number dened the When to as: exact conditions considering consider is the of uid = η It pipe density _ turbulent laminar of number turbulent: viscosity of uid that: when uid • The Reynolds number • Experimentally, uid turbulent R does not have any units – it is just a ratio. ow Reynolds o p t i o n B when – > ow 2000 is often but laminar precise E n g i n E E r i n g when predictions R < are p h y s i c s 1000 and difcult. 167 fc c c (1) HL Heavy damping Damping opposite involves direction particle. As resistive (or energy. As the a to frictional the particle oscillates, dissipative) the total force direction force energy it and of the that of does so is always motion of work the an is the oscillating against particle particle in forces completely taken this be loses proportional to the damping (e.g. for the or prevent the overdamping SHM taking the particle place in oscillations to return to involves a large viscous from zero resistive liquid) taking and place. displacement can The can time again long. Critical damping involves an intermediate value for resistive 2 (amplitude) with of the SHM, the amplitude decreases exponentially time. force such that displacement x ,tnemecalpsid Examples with π 2π 4π ω ω ω time, t is a time taken minimum. critically moving tnemecalpsid exponential envelope of the and the particle Effectively damped pointers for systems door closing to there is include return no to zero ‘overshoot’. electric meters mechanisms. overdamped critical damping time The above system is is small cycle. example said so a The to time oscillations be small shows the effect of underdamped) fraction period continue of for of the the a light where total the energy oscillations signicant damping is is not number resistive force removed affected of (the cycles. each and the The time overshoot underdamped taken for the oscillations to ‘die out’ can be long. • natural frequenCy and resonanCe If a system is temporarily position, the be natural at the system will displaced oscillate frequency of from as a its The equilibrium result. vibration This of ◊ oscillation the system. the will and systems with It is its own rst the can have natural choose the from to by chosen provided is to possible we with tap you tend also that you hear a wine note for possible glass a with short modes a knife, while. of will Complex vibration force a system subjecting the it to This to a changing periodic system. combination oscillate of When natural at any force driving each this and frequency that force driving forced forced values oscillations of the depends natural on: frequency and the frequency For it frequency. frequency. a of a many outside applied, rim the varies must the amount of damping noitallic so fo edutilpma oscillate if of comparative driving ◊ example, amplitude be frequency present in the system. light damping oscillations increased damping take the place which amplitude produces of the complex transient transient oscillations ‘die oscillations. down’, a Once steady heavy damping condition is achieved • The system • The amplitude in which: oscillates of at the the driving forced frequency. oscillations is xed. Each cycle driving frequency, f driving energy is dissipated as a result of damping and the driving natural frequency, f natural force does energy of work the on the system system. remains The overall result is that the Resonance constant. force at oscillation Typical q faCtor and damping The degree quality of factor denition damping or Q is measured factor. It is a by ratio a quantity (no units) called and the occurs exactly of the orders Car the of when same a system is frequency subject as the to an natural oscillating frequency of system. magnitude for suspension: different Q-factors: 1 3 the Simple pendulum: 10 is: 3 Guitar string: 10 7 energy stored Excited atom: 10 __ Q = 2π energy lost per cycle When Since the energy is amplitude of amplitude with Q approximately factor is the stored proportional oscillation, time can be to the measurements used equal to to of calculate the square of the decreasing the number of Q factor. is The In a system energy all used this is in provided to resonance by overcome situation, the Q the the and driving its resistive factor can amplitude frequency be forces is that calculated cause as: oscillations energy stored __ that are completed before damping stops the oscillation. Q = 2π × resonant frequency × power 168 o p t i o n B – E n g i n E E r i n g p h y s i c s constant, during loss one cycle damping. rc (2) HL pha se of forCed osCill ations After transient relationship oscillations between have these two died down, oscillations the is frequency complex of and the forced depends on oscillations how close equals the the driven driving system frequency. is to The phase resonance: phase lag φ/rad driven vibration 1 period behind 2 π driven vibration π 1 2 period behind 4 heavy damping light damping 0 f/Hz in phase natural forcing e x amples of resonanCe Comment Vibrations in machinery When other in operation, sections amplitude a Quartz oscillators A truck’s the generator Radio receivers Electrical circuits natural a the components the driving Many be the chosen The the circuit’s radio at natural region. of be as a the natural frequency Radiation atmosphere. an of causes (using the for that is the of for e.g. the at at to a drive known to a forces natural on the frequency, particular eld an the is engine the speed crystal in at the voltage its own from natural systems. The molecules removed, oscillating frequency. oscillate. resistors The its the The driving changing frequency particular by be When are of the provided will it to the that in have an receives. be increase in will Adjusting adjusted driving their aerial to equal frequency amplitude and stations. arranging amplitude of that frequency oscillations readily inductors) (electrons) waves station. molecules can radio other the and charges natural radio sounds free the electrical the the generate microprocessor water of causes Earth more driving to increased. allows their oscillation regular equal When to used charges dominate which is waves all particular will the this frequency a is high. eld. added capacitors, circuit by are oscillations. produce 92 electric clocks means frequency, from dangerously and temperature signal page in provide frequency vibrate. accurate which frequency of to crystal that connected emitted See the provided natural get electronics electrical result station’s may placed machinery driving seen designed of of the electromagnetic the instruments its of force i.e. frequency musical driven – can force if energy, frequency driving be provide produce driving energy the effect a with kinetic can force devices provides equals Greenhouse is a If vibration movements ovens parts Appropriate microwaves feel instruments feels These eld moving machinery. mirror oscillate. Microwave own Musical view mechanical electric the the particular crystal will frequency. Microwave a rear quartz crystal of of for of a column the greenhouse absorbed by of air oscillations gases the is in or to the a string to increase. infra-red greenhouse gases in details. o p t i o n B – E n g i n E E r i n g p h y s i c s 169 iB q – B – c 5 1. A sphere rest down plane, of of it the given mass an has m and inclined fallen sphere, v, a radius plane. vertical when it r rolls, When it distance arrives at without slipping, reaches h. the the Show base base that of the the from of 4. the a and speed incline In diesel a temperature changes is its engine, listed starting air of is initially 27 below. At °C. The the at a air end of pressure of undergoes the cycle, 1 × the the 10 cycle air is Pa of back at conditions. by: 1 An 2 A adiabatic 3 An 4 A a) Sketch, compression to 1/20th of its original volume. original volume. _____ 10gh _ v = [4] √ brief isobaric expansion to 1/10th of its 7 adiabatic expansion back to its original volume. 2 2. A ywheel of moment of inertia 0.75 kg m is accelerated cooling down at constant volume. 1 uniformly a) from Calculate rest the to an angular resultant torque speed of acting 8.2 on rad the s in 6.5 s. with undergoes. during this time. Calculate the the Accurate cycle values of are changes not that the gas required. [3] [2] b) b) labels, ywheel rotational kinetic energy of the If the pressure ywheel after the adiabatic compression has risen 6 to 6.6 × 10 In which Pa, calculate the temperature of the gas. [2] 1 when it rotates at 8.2 rad s [2] c) c) The radius applied of on the the ywheel is 15 circumference cm. and A breaking brings it to angular Calculate 3. A xed speed the mass of of value a gas pressure the shown V cycle of rad the s in and in [2] that it of is four processes: (i) is work done on (ii) is work done by (iii) does the gas? [1] from revolutions. changes such diagram 2 force. various volume the exactly breaking undergoes temperature, p 8.2 the force rest 1 an of d) taken round Explain to this ignition how cycle the of of the the 2nd gas? [1] air-fuel law of mixture take thermodynamics place? [1] applies changes. [2] below. aP HL 01/erusserp 5 5. X With the aid of diagrams, explain 2.0 a) What is b) The c) Pascal’s d) An meant Bernoulli by laminar ow effect principle 1.0 Z Y ideal uid [8] 3 6. Oil, of viscosity 0.35 Pa s and density 0.95 g cm , ows 1 3 1.0 2.0 3.0 4.0 volume/10 5.0 through 3 Deduce The following sequence of processes takes place A of radius 20 cm at a velocity of 2.2 m s whether the ow is laminar or . turbulent. pendulum clock maintains a constant amplitude [4] by means cycle. of X pipe during 7. the a m → Y the gas expands absorbs energy at constant from a temperature reservoir and and does the 450 J gas an electric available for power the supply. The following information is pendulum: of 2 Maximum kinetic Frequency of energy: 5 × 10 2 Hz J work. Y → Z the gas is compressed and 800 J of thermal energy Q transferred Z → X the gas from a) Is there the b) Is the X → Use d) What e) How What The in → the to Y change process quantity overall is to → in Y 30 reservoir. stage energy the or by absorbing energy Calculate: → → gas the its gas the than work the 450 The driving b) The power frequency needed done process J? on Explain. the [2] gas [3] energy of the gas Z? [2] X? is absorbed Explain by by your the the gas answer. area [2] enclosed by value. a a) [2] heat done by engine the gas is dened during a as cycle ____ Efciency = total If this p engine 170 V cycle represents determine i B energy the absorbed the cycle efciency Q u E s t i o n s – of during for the a a cycle particular heat engine. o p t i o n of the power supply [3] during Z. of work during more represented efciency of [2] internal energy Z Estimate net by determine thermal graph? a Explain. equal process the to initial internal Y? process the gas its absorbed graph much during X than, the is during g) less the during the change energy Y the to factor: reservoir. processes c) f) a a from returns oscillation: is B – heat [2] E n g i n E E r i n g p h y s i c s to drive the clock. [3] 15 o p t I o n C – I m a g I n g I ri In Ray dIagRams If an be object is placed in front of a plane mirror, an image order diagram will to is nd the location and nature of this image a ray needed. formed. image object upright same size as object laterally inverted The process is as follows: The • Light sets off in all directions from every part of the • (This is a result of diffuse reections from a source image of the Each ray of according • These light to rays the can that law be arrives of at the mirror is The the location rays are received of the image assumed to by reection distance in behind a plane the mirror mirror as is the always: object is front reected • upright • the (as opposed to being inverted) reection. by an seen have by same size as the object (as opposed to being magnied observer. or • same light.) in • formed object. the observer travelled in arises straight diminished) because • laterally • virtual inverted (i.e. left and right are interchanged) lines. (see below). Re al and vIRtual Images The image mirror term is is formed by described used to reection as a virtual describe in a images concave plane image. created mirror This when object rays but of in In the to be not, at light fact seem they do example coming of come not from pass above, from course, to the behind actually a single through rays the pass of that light mirror. behind point real image point. seem They the do mirror all. The opposite of a virtual image is a real (a) real image image. In actually this pass case, the through a rays of single light (b) vir tual image do point. I Real images mirrors, but they example, if you can or be by look formed by formed lenses. into the plane converging by For concave O surface of a spoon, you will see an image point of yourself. This particular image is object • Upside down • Diminished • Real. diverging vir tual point rays image metsys lacitpo mirrors be metsys lacitpo concave cannot I real point image rays O point object stICk In wateR The image leaving formed water is so as a result of commonly the seen refraction that most of light people forget air that will that the objects appear the bent rays travelling are in if that a made it is seem placed arrive straight to at in one’s strange. water. eyes A The must straight brain have stick water assumes been line. A straight when stick placed in appears bent The image of the end of the pen is: water • Nearer pen • o p t i o n to the actually surface than the is. Virtual. C – i m a g i n g 171 Cri ConveRgIng lenses A converging lens brings air parallel rays into one focus air point. normal converging lens normal parallel rays refraction at glass 1st surface refraction at 2nd surface The rays of light are all brought together in one point because of focal point the as particular a collection that The reason both that surfaces this of the happens is the refraction that takes place any spheres at lens. A thin will The power of a lens of of that converge lens with the lens. Any different-shaped lens converging compared poweR of a lens shape glass surfaces light will the has into always lens can blocks. formed one be one focus thicker It from be can thought be of shown sections of point. at the centre when edges. wave model of Image foRmatIon measures the extent to region in which waves are which lens light bends is the focal length. lens, P, P = is bent light The the by the more lens. and denition reciprocal of of the A higher thus the has power a power focal smaller of a length, O f : I 1 f real image (point to which object (source f is the focal length measured in m wave energy is concentrated) of wave energy) 1 P is the power dioptres A lens and of has lenses of the lens measured in m or (dpt) Formation power a focal are = placed approximately +5 length dioptre of close 20 is real together When their The terms two centre • The The of lenses need and to this of curvature of be each centre the images that they form, The the some focal the of of surface of a curvature lens for makes the lens it part of surface axis (ignoring diffraction) lens. the the line Technically two going it directly joins the through centres A axis lens (principal axis are will to focus) which brought thus rays to have a of that focus focal a lens were after point is the the the • The • The focal and of has length the linear (height) surfaces. no of passing on each focal is the distance magnication the between the image and m, the is the size ratio image magnication, m of the i _ = size h o lens centre of 172 o p t i o n C – focal point i m a g i n g the side. centre h size = object f on the through between (height) _ c to f of the point. units. linear cur vature point parallel a is lens is point principal principal dened. sphere. principal middle refraction thin • curvature sphere. by powers lens. • image add. analysing technical a converging cm. defInItIons When of c principal axis (PA) the size object. It I ri i c ImpoRtant Rays lens distant object In order position to determine of the image the nature created of a real image and inver ted given O object, we need to construct a f scaled diminished PA ray do diagram this, taken as the we by of the set-up. concentrate three paths on particular taken by In the rays. two of order to I f paths As soon these rays object at 2f have the been other constructed, rays can be the paths inferred. of all These f O important rays are described below. PA f Converging I real image lens inver ted 1. Any ray that was travelling same size parallel to refracted on the the principal towards other side the of axis focal the will be object bet ween 2f and f point lens. f O PA real inver ted f magnied I f object at f PA f f O PA 2. Any focal ray that point travelled will be through refracted the f vir tual image parallel upright to the principal axis. image at innity object closer than f I f f O PA PA f 3. Any the ray f that centre of goes the vir tual image through lens will upright be magnied undeviated. Converging lens images possIble sItuatIons f PA A ray diagram can be constructed as follows: f • An upright • The • This • The the paths of locates bottom top of arrow two the of the if it is real • if it is upright • if it is magnied its exact should image still An be of image rays the must axis from top be of on represents the the the top of the the object. object are constructed. image. principal axis directly above (or below) of the image created would include the following information: virtual or inverted or diminished position. be also important the • It principal image. full or the position A • description on noted consists formed observer that of even if receiving the all important the some other of parallel the rays rays rays rays sees are from are an just the used object. blocked image to In locate the image. particular, the The image real will off. located in the far distance (at innity). o p t i o n C – i m a g i n g 173 ti i lens equatIon There is a lIne aR mathematical method of locating the image formed by a lens. An analysis of the angles magnIfIC atIon involved shows that the following equation can be applied to thin spherical lenses: In 1 1 = cases, linear 1 + v f all magnication, u h v i _ m = = - u h o height of image __ m = height of object h object i _ = h o f f v = - u image For real images, negative and m is image is inverted For virtual positive images and upright object distance u Suppose u f = 25 = 10 would mean v cm cm 1 This image distance 1 that 1 1 _ = u f 5 _ 1 _ = v - = 10 3 _ 2 _ - 25 50 = 50 50 50 _ In other word, v = = 16.7 cm i.e. image is real 3 16.7 _ In this case m = = -1.67 and inverted. 10 Re al Is posItIve Care needs convention to be has taken to be with virtual images. • Distances are taken to be positive • Distances are taken to be negative • Thus the a virtual lens as image the The equation does work but for this to be the is if represented actually if traversed apparently by a by traversed negative value for the by v – light the in ray light other (i.e. ray distances to (distances to words, it will be object. image object f f object distance u negative image distance v Suppose u = 10 cm f = 25 cm 1 This would mean 1 that 1 = v 1 _ 1 _ 25 10 = f 2 _ 5 _ 50 50 = u other word, v = = - -16.7 cm i.e. image 3 16.7 _ In this case m =+ = +1.67 and upright 10 174 o p t i o n C – i m a g i n g is 3 _ = 50 _ In case, the following followed: virtual - 50 real object virtual on the and objects same image). and side images). of image m is is diri When dIveRgIng lenses A to diverging all come lens spreads from one parallel focus rays point on apart. the These other rays side of the constructing important appear other lens. 1. ray Any rays paths ray ray whose that can be was diagrams paths are inferred) travelling for diverging known (and lenses, from the which all are: parallel to the principal axis will concave lens be refracted the away from a focal point on the incident side of lens. focal point PA f 2. Any ray other that side of is f heading the lens, towards will be the focal refracted so point as to on be the parallel to focal length the The at reason both centre that this surfaces. when A happens diverging compared with is the lens the refraction will always that be takes thinner principal axis. place at the edges. PA f f defInItIons and ImpoRtant Rays Diverging lenses converging Centre of have lenses for curvature, the all same of principal the analogous following axis, focal denitions as 3. terms: point, focal Any ray that goes through the centre of the lens will be undeviated. length, linear magnication. f Note that: PA • The focal which to • As rays come the point that after focal length of is the were is on parallel passing point a point the to through behind diverging is the the the lens principal axis principal f from axis appear lens. diverging lens, the focal negative Images CRe ated by a dIveRgIng lens Whatever the focal the position point and the of the lens object, on the a diverging same side of lens the will lens always as the create an upright, diminished and virtual image located between object. If you look at an object through a concave lens, If you move the object fur ther out, the image will not it will look smaller and closer. move as much. object f f v u f object image image object inside focal length object outside focal length The For thin lens example, equation if an will object is still work placed at providing a distance one 2l remembers away from a the negative diverging focal lens of length focal of a length diverging l, the lens. image can be calculated as follows: Given: u 1 = 2l, 1 = -l, v = ? 1 + u f = v 1 f 1 = 1 - v 1 _ = u f 3 _ 1 - l = 2l 2l 2l ∴ v = - 3 1 This is a virtual diminished and upright image with m = + 3 o p t i o n C – i m a g i n g 175 Cri iri irrr geometRy of mIRRoRs and lenses The geometry of the paths of rays after Image foRmatIon In mIRRoRs reection by a (1) Concave spherical concave or convex mirror is exactly analogous to the object at innity paths of rays difference is through that converging mirrors reect or all diverging rays lenses. backwards The only whereas real rays pass through lenses and continue forwards. PA inver ted F 2f diminished (a) Convex lens I object between innity and 2f PA O real PA F 2f inver ted diminished f I (b) Concave mirror object at 2f O real PA 2f F inver ted same size PA I object between 2f and f f O real inver ted (c) Concave lens PA 2f F magnied I object at f PA vir tual O upright 2f PA f image at F innity object between f and mirror (d) Convex mirror vir tual 2f PA upright F magnied PA (2) Convex object at innity f This analogous equations detail for with behaviour lenses the sign can means be used that all (with conventions) with the denitions suitable and attention to I vir tual mirrors. upright PA An additional through (or (located at back along important towards) twice the the same ray the for centre focal mirrors of length). is the curvature This ray ray of will that the be travels diminished F 2f mirror reected path. object near lens vir tual PA F 176 o p t i o n C – i m a g i n g 2f upright diminished t i ii angul aR sIze ne aR and faR poInt The human distances describe point • from the and The eye can the focus eye. possible the far distance Two range point to objects the at terms of If different are useful distances – the bring then near occupies we point is the an see a subtends distance. near we to it object in bigger a closer more visual larger to detail. us (and This angle. is The our eyes because, technical are as still the term able object for this to focus on approaches, is that the it) it object angle. distance objects are the between the eye and the nearest object that same size can or be brought help from, into for clear focus example, (without lenses). It is strain also angle subtended known By as ‘least convention normal • the The distance be is taken to of distinct be 25 cm vision’. for vision. between can it distance the to the eye brought far and into point the is the furthest focus. This is distance object taken that to be close distant angle subtended innity for normal vision. object object by distant object 1. angul aR magnIfIC atIon The angular dened as normally the the and optical context. the magnication, It same ratio the between angle instrument. should as the M, be that The noted linear of the its an optical angle image ‘normal’ that the that instrument an object subtends situation angular as a is In subtends result depends on magnication Image The of formed this resulting seen at innity arrangement, by the image relaxed the will object be is placed formed at at the innity focal and point. can be eye. the is not magnication. h θ = i f top rays from object at θ o specied distance h θ i f bottom θ i top eye focused on innity f rays from nal image formed by optical θ In i this case the angular magnication would be instrument h θ f i M = D = = innity h θ f o D bottom This can is the smallest value that the angular magnication be. θ i Angular magnication, M 2. = Image formed at near point θ o In The largest visual angle that an object can occupy is when this placed at the near point. This is often taken as the the object is placed nearer to the lens. it The is arrangement, resulting virtual image is located at the near point. This ‘normal’ arrangement has the largest possible angular magnication. situation. θ i o h /D h i i D 1 a u v f 1 1 1 M h θ 1 + = θ o D h/D h - ⇒ 1 = = h θ o a D D D + = ∴ h i a f 1 f D h θ A simple lens can increase the angle subtended. It is usual to i f consider two possible θ f situations. i a D D So the magnitude of M = near + 1 point f o p t i o n C – i m a g i n g 177 arri spheRIC al A lens some a is said perfect are to reason, Spherical have point point spherical describe a image. do not fact of slightly different inner a be In general, are • of a The a of way lens objects • the A at a effect this is The effect point (as 46) the effect smaller is and for the to can could be the a for The be ray striking inner regions not of small effect: ray striking outer regions in range of focal points effect. longer be works outer sections for of lens not used away. given lens technical the total made can a There this only a a altered distance term aperture. amount by of diffraction The light aper ture (see worse. be by spherical) again no down axis into the shape the is point. be for effects mirrors on focus reduced that to striking This reducing aperture. would objects opposed the be those lens. course, stopping reduced page of to outer distortion correct particular disadvantage is lens used brought perfect of particular can decreasing for ways a be that images. the from will than would, spherical. will same object to term for produce lenses striking point if, not perfect the barrel the as is the rather shape such of with possible does reality, lens focus point light, several the In rays spherical confused circle that regions to aberration produce aberration the regions the an object eliminated using a mirror. reduced For by for all parabolic mirrors, using a aperture. Spherical aberration ChRomatIC Chromatic to describe aberration the fact that is the rays of term used different white light colours will be brought to a slightly V different The focus refractive point index by of the the same red lens. material used violet to make the frequencies lens of is different for R different light. R violet A point image object of will different produce a blurred red colours. V The effect can given colours using two a types an of eliminated (and different compound called be lens. reduced for materials This achromatic glass for produce two all) to compound but do not suffer from red focus focus up lens The is two opposite dispersion. Mirrors violet by make doublet. equal white light converging lens of crown glass Canada balsam (low dispersion) cement diverging lens chromatic of int glass aberration. (high dispersion) Achromatic 178 o p t i o n C – i m a g i n g doublet t c icrc ric c Compound mICRosCope A compound forms (the a real microscope magnied eyepiece lens) consists image which virtual magnied angular magnication acts image. is In of of as two the a lenses object magnifying normal – the being lens. adjustment, objective viewed. The this This rays lens real from virtual and this image the image real is eyepiece can then image arranged be lens. travel to be The rst considered into the located at as lens the eyepiece the near (the object lens point objective for and so the they that lens) second form lens a maximum obtained. objective construction lens f eyepiece lens f o e top half construction line line of object B real image formed f h by objective lens o θ i θ O f i h e 1 eye focused on near point to vir tual image see vir tual image (in practice h of top half of 2 it would be much nearer to the object eyepiece lens than implied here) M D h 2 h θ D i M = = h 2 h 2 _ 1 _ = _ = h θ h = h linear magnication produced by eyepiece × linear magnication produced by objective h 1 o D a stRonomIC al telesCope An astronomical distant object magnifying telescope being lens. adjustment, this also viewed. The rays virtual consists Once from image this is of again, real two this image arranged to lenses. real travel be In image this can into located at case, then the the be objective considered eyepiece lens and lens as forms the they a real object form a for but the diminished eyepiece virtual lens magnied image acting image. of as In the a normal innity. objective eyepiece lens lens f f o e construction line parallel rays all from real image formed in mutual top of distant object focal plane of lenses f e θ eye focused on innity i f θ o o θ o h 1 θ i vir tual image at innity h θ M f f i = o _ = _ = h θ f e o f The length of the telescope ≈ f o + f e o p t i o n C – i m a g i n g 179 aric rci c CompaRIson of RefleCtIng and RefRaCtIng ne wtonIan mountIng A small at mirror is placed on the principal axis of the mirror telesCopes to A refracting form a real telescope uses diminished an objective image of a (converging) distant object. lens This reect the image formed to the side: to image is concave then viewed by the eyepiece lens (converging) which, acting small at mirror mirror as a simple nal In magnifying glass, produces a virtual but magnied image. an analogous mirror distant set up so object. view as it Thus mirrors way, a as form to This would are reecting image, be a to in uses diminished however, produced used telescope real, would front produce a of be the a of difcult concave viewable F concave image image o a to mirror. that F' o can, like the refracting telescope, be viewed by the eyepiece eyepiece lens lens (converging). Once magnifying glass image. common the All Two Newtonian telescopes and again made to eyepiece the mountings mounting are the produces and have virtual, for acts but reecting the as simple telescopes Cassegrain large a magnied, apertures nal are mounting. in order to: C a ssegRaIn mountIng a) reduce b) collect diffraction effects, and A enough light to make bright images of low convex The mirror mirror has is a mounted central on hole the to principal allow the axis of image telescopes are reecting The because: convex mirror will add to the angular magnication achieved. • Mirrors • It do not suffer from chromatic aberration concave is difcult to get a uniform refractive index throughout small convex mirror a mirror large • volume Mounting a of glass large lens is harder to achieve than mounting F a • large Only mirror. one Reecting surface telescopes needs can to be easily the right suffer shape. damage the mirror eyepiece lens surface. 180 to o p t i o n C – i m a g i n g ex t F o the to viewed. sources. Large small mirror. power be Ri c sIngle dIsh RadIo telesCopes A single to a to form dish radio reecting an telescope telescope. image, the waves are reected that the receiver up is specic study of the the wavelengths naturally Rather much by operates longer curved radio under occurring than in RadIo InteRfeRometRy telesCopes a very reecting visible wavelengths receiving waves can emission of dish. be observation radio similar The from are The light stars, some pick used to than and other astronomical objects between about 10 m and received distance any at two apart creates of the of called a a radio telescope interferometry. (or but more) radio pointing virtual individual in radio can This be telescopes the same telescope improved process analyses that are direction. that is This much larger telescopes. galaxies, technique is complex as it involves collecting signals wavelengths from of resolution principle effectively The quasars a signals antenna to angular using radio tuned and way two or more radio telescopes (an array telescope) 1mm. in one central individual location. antenna The needs arrival to be of each carefully signal at calibrated an against a Radio telescope single shared reference signal so that different signals can be incoming radio combined as though they arrived at one single antenna. When waves the signalsfrom they that interfere. is the The equivalent single radio to maximum different result in is telescopes to create resolution telescope whose a are combined (though diameter added not is in together, telescope sensitivity) approximately to a equal Radio waves reect the separations of the antennae. o the dish and The principle can be extended, in a process called Very focus at the tip. Long Baseline Interferometry, to allow recordings of Receivers detect and radio signals (originally made hundreds of km apart) to be amplify radio signals. synchronized scientists Diffraction effects can signicantly limit the accuracy a signals. the radio telescope Increasing telescope’s that more the ability power can can locate diameter to resolve be individual of a radio different received (see sources telescope sources resolution from within different a millionth countries of to a second thus collaborate to allowing create a with virtual which to of radio telescope of huge size and high resolving power. radio improves and on ensure page 101). CompaRatIve peRfoRmanCe of e aRth-bound and s atellIte-boRne telesCopes The • following SB observations better • • to are • SB observations • SB facilities • The • There are is a great signicantly is an not There • SB telescopes • EB optical not can suffer subject deal added of telescopes and/or added EM in (SB) absorptions correct radiation their light continual space cost to of only in build due telescopes to the can Earth’s be made: atmosphere that hinder EB observations, giving for many atmospheric effects making new ground-based telescopes similar pollution wear getting and wider operate (UV , and exists the this / and radio tear for long wavelength repairs night as SB interference radio) are absorbed by the Earth’s atmosphere so SB a / a result into limit on alterations to variations whereas of as the a result Earth’s of nearby atmosphere human activity. (storms etc.). telescopes. telescope places temperature at IR wavelengths. debris effecting withstand can effectively from to difcultly to of from expensive need satellite-borne telescopes. possibility damage more • SB only and interference techniques do of from (EB) telescopes. wavelengths the possibility SB some signicant telescopes Earth-based free for computer resolution Many about are resolution Modern in points SB orbit and their a SB than size controlling and telescope EB telescopes it remotely, meaning that SB telescopes are weight. once operational. telescopes. can operate at all times. o p t i o n C – i m a g i n g 181 fir ic • optIC fIbRe Optic page bres 45) make a to ray between the ray angle, bre As the shown walls ray of will a bre. a is path. reection The transparent So bre always internal certain along the total long as always remain the the is by than bre angle the even if the of critical the • This medical images called to bouncing incident greater within idea bre In carry (see an type bre. Bundles from inside of optic the bres body. can This be used instrument to is endoscope. of optic Cladding surrounds the world. back the of bre a is known material bre. This as with cladding a a step-index lower optic refractive protects and index strengthens bre. right). page index the of of along travel wall (see on principle light light the bent refractive the guide of the on is use n 45, is the relation given between critical angle, c, and by 1 _ n = sin Two • c important In the into is uses of optic communication pulses used for of light are: industry. that telephone bres can Digital then travel communication, data can along cable be the TV encoded bres. This etc. types of optIC fIbRes The simplest Technically bre this optic is is known a step-index as a bre. multimode index index output prole pulse pulse step- n2 index bre. Multimode refers to the fact that light can n1 take different some page paths distortion 183). The of down signals the bre (see (multimode) which waveguide can result in dispersion, graded-index bre is multimode step-index an improvement. prole in speeds depending the This bre uses a meaning on their graded that refractive rays distance travel from at the index different n2 centre. n1 This has pulse. the Most graded narrow effect bres index. core – The a of reducing used in data optimum the spreading communications solution singlemode out is to step-index have of have a bre the a very multimode graded-index n2 n1 singlemode step-index 182 o p t i o n C – i m a g i n g diri, i i i ic r mateRIal dIspeRsIon The refractive frequency reason it of that passes index of any waveguIde dIspeRsIon substance electromagnetic white through light a is depends radiation dispersed triangular on the considered. into different If This is colours the when prism. the optical called a pulse along is light travels along an optical bre, different frequencies at slightly different speeds. This means that if the light involves out as the bre. a square a range wave of will frequencies, tend to then spread a out pulse as it of a reections. signicant or modal bre This is diameter, that can another cause dispersion. shorter means than that a rays the The path from path that a process stretching of length involves particular will not all arrive at the same time because of the different source distances of centre a dispersion will pulse travel has multipath the multiple As bre waveguide that travels they have travelled. starts along B This process is known as material dispersion C A cladding before transmission The after transmission problems of bres. optical same used These order of As light travels The scattered that entered The in or arrives the of optic by end bre. amount decibels an absorbed at the along the of The attenuation (dB). The glass. the signal bre, bre is The is said is some than be is energy of the the can be light intensity energy that attenuated. measured attenuation the intensity less to of on given a from scale path of therefore series of – a 5 10 be µm) km 40 the so very the narrow wavelength that along The have led singlemode) length dB. is dispersion (or have as directly factors attenuation processes:those scattering by bres core there the of cores of the the only (of the light one being effective bre. this overall algebraic is to step-index bre optic cable attenuation sum of the resulting individual attenuations. The logarithmic a modal magnitude attenuation would by monomode (approximately transmission attenuatIon caused development paths that in an takes the glass the wavelength optic caused absorbs by place the bre is a result impurities in light. the These in glass last of the and two several glass, the the extent factors are general to which affected by I attenuation (dB) = 10log of light used. A typical the overall attenuation is I o shownbelow: I is I the is intensity the of intensity the of output the power original measured input power in W measured in W 1 o negative in power. been See page It is A positive means that attenuation the signal would has imply been that the reduced signal amplied. 188 common for to another quote example of the the attenuation For example, use per of unit the decibel length scale. as 1 measured causes The in an dB input km . power attenuation per of 100 unit mW length is 5 to km of bre decrease calculated to as optic 1 cable rep noitaunetta has attenuation 6 mk Bd / htgnel tinu A 5 4 3 2 1 mW . 0.6 follows: 0.8 1.0 1.2 1.4 1.6 1.8 wavelength / µm 3 attenuation attenuation = 10 per log unit (10 1 /10 length 2 ) = 10 = -20 = -20 = -4 log (10 ) dB dB/5 km 1 dB km C apaCIty Attenuation noIse, amplIfIeRs and ReshapeRs causes information that bre. often This is capacity of an can upper be sent stated an in optical limit to along a terms bre of = the amount particular its bit of type digital Noise of scatterings optical capacity. rate × to distance to 1 A bre with a capacity of 80 Mbit s km can Mbit s 1 along a 1 km length of bre but a 4 km that in take any electronic place within circuit. an optical Any dispersions bre will also or add noise. amplier correct only 20 Mbit increases the effect of the signal strength attenuation – and these are thus also will tend sometimes called regenerators. An amplier will also increase any noise s that along inevitable transmit 1 80 the An is has been added to the electrical signal. reduce the effects of noise of 1s length. A reshaper by can returning transitions the signal between to the a series allowed o p t i o n C on and a 0s digital with signal sharp levels. – i m a g i n g 183 C cici The table below shows some common Options Wire pairs (twisted Two pair) the communication for wires communication can sender links. connect and Uses Very receiver of Advantages simple systems communication e.g. Very simple information. For simple link between to a Coaxial cables an noise transfer and interference. information at the a highest microphone, to example Unable a disadvantages cheap. intercom Susceptible copper wire and and amplier rates. and loudspeaker. This arrangement reduces electrical of two wires interference. Coaxial to cables transfer are signals used Simple Less A central wire is surrounded TV aerials to TV by wire of the second wire in the form Historically they straightforward. susceptible to noise compared receivers. to copper and from simple wire pair but noise still a are problem. an tube outer or cylindrical mesh. An copper standard for telephone insulator underground links. insulation separates the two wires. copper mesh outside insulation Wire links can frequencies but be the MHz of The about more A sent would intervals 0.5 to for a typical down need of 1 GHz frequencies wire. signal cable at higher attenuated length carry up will given 100 low-loss repeaters approximately km. upper coaxial limit cable is for a single approximately 1 140 Optical bres Mbit Laser light signals with s can down be used optical approximately frequency limit as to send bres the telecommunication same cables is volume data Compared and transfer including to equivalent coaxial capacity, cables optical with bres: of • have a • are • cost • allow higher transmission capacity video much smaller in size and weight data. attenuation bre high digital 1GHz. The Long-distance less than in an in a less optical for a wider possible spacing of coaxial regenerators cable. The repeaters even distance can between easily hundreds) of be tens (or • kilometres. offer immunity to electromagnetic interference • suffer from (signals in another • are very negligible one cross channel talk affecting channel) suitable for digital data transmission • provide • are good quiet when – security they carrying do not large hum even volumes of data. There • are the some repair of disadvantages: bres is not a simple task • regenerators thus 184 o p t i o n C – i m a g i n g are potentially more less complex reliable. and x-r HL IntensIty, qualIty and attenuatIon The effects intensity of X-rays and the on matter quality of depend the on two ba sIC x-Ray dIspl ay teChnIques things, the X-rays. The basic (for example more • The intensity, I, is the amount of energy per unit area principle than other carried by the The quality spread of of potentially image. If the It energy still be X-ray photons cause is the If is attenuated attenuation by will be the absorbed in simple given the by all from then the beam in it way spreads scattering is of to the said an out. and to are the parts (for is that the some X-ray example body beam skin and parts much darkens when a beam white areas of tissue). X-rays dominant ones for low-energy show up on an is X-ray shone on picture. X-ray beam forming to T wo as and the be X-ray beam, it processes photograph of photoelectric sharpness of an X-ray image is a measure of how easy it is X-rays. to scattering bones beam. X-ray the so the The effect lm beam. tissues contributing these absorbed, the name present remove nothing as matter, is is are without to beam there beam that harm desirable of attenuated. will the wavelengths Low-energy body imaging attenuate X-rays. them • X-ray will that Photographic is of bones) see X-ray photoelectric eect and the edges of beams the will result contrast different be will and organs scattered be to blur sharpness. or in the the To different patient nal help types being image reduce of and this tissue. scanned to reduce effect, a metal X-ray electron lter grid is added below the patient: photon low X-ray X-ray beam light electron low X-ray photon photon photon Simple scattering between zero affects and 30 X-ray photons that have energies keV . patient • In the photoelectric energy the to atom. cause It effect, one will of result the the in incoming inner one of X-ray electrons the to outer has be enough ejected electrons from ‘falling metal grid down’ into this energy level. As it does so, it releases some X-ray lm light energy. energies This process between zero affects and 100 X-ray photons that have keV . Alternatively Both attenuation transmission of processes radiation result as in shown a in near the exponential diagram enhance below. given energy of X-rays and given material there will be thickness that reduces the intensity of the X-ray X-rays that This is known as the half-value be used to detect and cause the ionizations, intensity used they needs are to dangerous. be kept to This an absolute by minimum. 50%. can a means certain software For Since a computer edges. This can be done by introducing something to thickness intensify (to noissimsnart X techniques enhance) of the image. There are two simple the energy enhancement: 100% • When X-rays radiated as strike visible an intensifying light. The screen photographic lm can is re- absorb I x = e this extra light. The overall effect is to darken the image in I 0 50% the • In areas an X-rays image-intensier screen and emitted half-value where produce from a are still tube, light. present the This X-rays light photocathode. (see strike causes These page a 187). uorescent electrons electrons are to be then thickness of absorber, x accelerated towards uorescent screen an anode where they strike another thickness The attenuation allows coefcient us to calculate the thickness of material. The µ is intensity a constant of equation the is as that X-rays = I give off light to produce an image. mathematically given any follows: ma ss attenuatIon CoeffICIent µx I and An e alternative way of writing the equation for the attenuation 0 coefcient The relationship between the attenuation coefcient and is shown below: the μ half-value thickness (ρ) is I = I ρx e 0 μ µ x1 = ln 2 Where ρ is the density of the substance. In this format, is ρ 2 μ x1 The half-value thickness The natural The attenuation of the material (in m) known as the mass known as the area attenuation coefcient , and ρx is ρ 2 ln 2 log of 2. This is the number density or mass thickness 0.6931 μ 2 Units of mass attenuation coefcient, 1 µ coefcient (in m = m 1 kg ρ ) 2 Units µ depends on the wavelength of the X-rays – short of area density, ρx = kg m wavelengths μ are highly are easily penetrating and these X-rays are hard. Soft ρx x-rays (ρ) I = I e 0 attenuated and have long wavelengths. o p t i o n C – i m a g i n g 185 x-r ii ci HL 1) Intensifying The screens arrangement page 185 are 3) of the shown intensifying screens described on below. X-rays emerging from patient Tomography Tomography is a photograph focus the All is patient. achieved by technique on a other regions moving that certain the makes region are source or the blurred of X-ray ‘slice’ out X-rays through of and focus. the This lm together. cassette front (plastic) motion X-ray tube front intensifying screen: phosphor double-sided lm about 12 mm rear intensifying screen: phosphor pivot point plane of cut felt padding cassette A B With a simple X-ray photograph it is hard to identify X-ray table lm problems within soft tissue, for example in the gut. There A′ are two general techniques aimed at improving B′ B′′ A′ B′ this motion situation. 2) Barium meals An In a barium its progress between Typically meal, along the gut the of barium of the a the and patient sulfate. dense gut substance can be The asked result to is swallowed monitored. surrounding is is tissue swallow an is a increase image. The and contrast increased. harmless in the solution sharpness extension out a pulse detector. around can in o p t i o n C – i m a g i n g of information a of CT and the X-ray the a tomography or X-rays patient analyse terms basic scan about The reconstruct 186 of tomography a set levels source and scan. the information the this are repeated. recorded of and the tube reaching detectors is a detectors X-radiation ‘map’ attenuation. computed set-up sensitive the process 3-dimensional X-ray of of and is In is A each then rotated computer able inside sends collects to of the body uric ii HL ultRa sound The is limit of of a- and b-sC ans human higher hearing frequency Typically ultrasound the range. MHz The than used is about this in is 20 known medical velocity of kHz. as Any that ultrasound. imaging sound sound is through just soft from within tissue There are an A-scan is as a two ways of ultrasound presenting probe, the (amplitude-modulated graph of signal strength the information A-scan scan) versus or the presents time. the The gathered B-scan. The information B-scan 1 approximately used are Unlike of 1500 the X-rays, m order s of meaning a few ultrasound is that typical wavelengths millimetres. not ionizing (brightness-modulated the so it can be used brightness of a dot scan) of uses light on the a signal for imaging inside the body – with pregnant to affect screen. very organ to scan display safely strength women for pulse example. of The emitting basic and principle receiving is to pulses use of a probe that ultrasound. is The capable ultrasound ver tebra is reected The time where at any taken the boundary for these boundaries between reections must be different allows us types to of work echo tissue. out A-scan display located. boundaries abdominal wall langis fo htgnerts reections from ver tebra organ time B-scan display probe A-scans organs path of ultrasound is The acoustic density, ρ, impedance and the of speed the an a of substance sound, is the product of the several at one which can where known If body image process useful well required. of aCoustIC ImpedanCe are is be = a arrangement precise B-scans time, all represent achieved are the a taken lines section using a of the internal measurement of can the be distance section assembled through large of same the number into body. of This transducers. c (i) Z the and (ii) ρc (iii) placenta probe 2 unit Very of Z strong between = kg m 1 s reections two impedances. take substances This can place that cause when have some the very boundary different is acoustic difculties. foetal • In order for the ultrasound to enter the body in the limbs rst skull place, the there needs patient’s skin. to be An no air air gap gap between would cause the probe almost all (ii) and of (i) the (iii) ultrasound to ultrasound is to • the Very be achieved density dense reection reected of objects and by tissue) straight putting between (such multiple as back. a gel the bones) images can The or oil probe can be transmission (of and similar the cause a created. of density skin. strong These need Building to be recognized and a picture from a series of B-scan lines eliminated. original 2nd reection reected reection by bone back to probe ChoICe of fRequenCy The the • choice choice Here, that of frequency between the can resolution be of ultrasound resolution imaged. and means Since the to use can be seen as attenuation. size of ultrasound the is a smallest wave object motion, path of diffraction ultrasound small effects object, we will be must taking use a place. small In order wavelength. to If image this a was organ the only factor to be considered, the frequency chosen beam reected would be as large as possible. from bone • Unfortunately attenuation increases as the frequency of 2nd reection back ultrasound war is used, back. If it increases. will this frequency all was be the chosen If very high absorbed only would and factor be frequency as none to be small will ultrasound be reected considered, as the possible. pIezoeleCtRIC CRystals These and They one quartz can be also crystals used generate crystal is change with used an pds for shape when alternating when pd receiving generation and to an electric generate sound current pressure detection. ows ultrasound. waves so On balance between frequency is about the the is 200 frequency two chosen extremes. often such It that wavelengths of has turns the to out part of ultrasound o p t i o n C – be somewhere that the the best body away choice being from i m a g i n g the of imaged probe. 187 Ii ci HL Mathematically, Rel atIve IntensIty le vels of ultRa sound The relative intensity are compared the decibel using levels the of ultrasound decibel scale between (dB). As its two points name Relative intensity level in bels, suggests, intensity level of ultrasound at measurement point _____ unit is simply one tenth of a base unit that is L called = log I intensity the bel (B). The decibel scale is level of ultrasound at reference point logarithmic. I 1 or Relative intensity level in bels = log I 0 Since 1 bel = 10 dB, I 1 Relative intensity level in decibels, L = 10 log I I 0 • nmR Nuclear process images or Magnetic but of one sections dangerous tumours Resonance that in is through techniques. the brain. (NMR) extremely It the It is body of is a useful. very It without particular involves the use provide any use of a in eld in conjuction with a large pulse of nuclei radio can resonance. detailed invasive • detecting After by the The pulse, emitting outline, the uniform The nuclei process • The spin of is of atoms as these a property means that called they spin. The time over can These The radio act like tiny • The will tend to line up in a strong magnetic eld. • The to signal (protons) nuclei a the a spin return to Larmor process frequency, called transition. their lower energy state waves. which radio waves are emitted is called the time waves processed magnets. • make nuclei at in follows: have nuclei applied energy eld. • • is this protons the radio relaxation In waves absorb non-uniform • magnetic a the complicated can If emitted produce analysis is and the their NMR targeted relaxation scan at times can be image. the hydrogen nuclei present. number of H composition so different energy the from nuclei applied varies with tissues the extract chemical different amounts of signal. RF generator • Thus RF signal forces protons to make a spin transition and eld S gradient ◊ coils The gradient eld allows determination of the point from RF coil which receiver ◊ The body the photons proton tissue at spin the are emitted. relaxation point where time the depends radiation is on the type of emitted. N permanent magnet relaxation time oscilloscope • They do not, particular high • The however, way that frequency particular magnetic called perfectly called the same frequency eld the – is and the Larmor line up – precession. as of the they This frequency precession particular oscillate happens of radio depends nucleus in at a a very waves. on involved. the It is frequency • CompaRIson between ultRa sound and nmR The • following NMR points imaging ultrasound brought • as the brought required NMR NMR expensive a and at quality a are the of when very machine patient but is and image 2-dimensional – process to of can 3-dimensional compared bulky easy point Ultrasound reections noted: measurements to produces produces very be equipment Ultrasound be • to is can is time perform care) rely scan, and on • with patient needs to consuming. (equipment can skill be be of ultrasound can • wave • energies ultrasound with the radio At the radio diagnostics • Detail • NMR produced by NMR is greater than by useful for very delicate areas of body e.g. NMR can 188 patients be more have to remain very still, ultrasound dynamic. o p t i o n C – i m a g i n g cavitation will tissue. in ultrasound cause avoid used absorb The this but that used the in and multiple energy energy associated associated NMR. NMR the energy frequencies possibility the the there energy – easily image. as can is no cause production and and can danger of as small damage intensities much of heating. used for possible. The strong magnetic elds used in NMR present and or problems brain. for • energy greater body of ultrasound. • particularly some which surrounding scan. is the clarity frequencies can bubbles enter the frequencies but Ultrasound not carry the gas typically do reduce with resonance repeated operator. Both waves can images patients with surgical implants / pacemakers. Ib qi – i C – ii 1. For each the nal of diagrams a) An A and object focal b) the following image formed. situations, Solutions locate should and describe found using The scale of mathematically. is placed length diverging 14 7 cm in front of a concave mirror of b) (i) focal length 12.0 cm is placed at point of a converging lens of focal length 8.0 object cm. is placed object focal 16.0 cm in front of the converging the graph lens. plotted A b) 6.0 is an student is given tube a) length cm in order cm. to two make a the length She nds A simple the cm 18 of behind converging a a convex lens the lenses, A of lens focal rst and by which she can a determine lengths [2] to be of lens A 10 cm as Focal length of lens B 50 cm a diagram arranged in the to show tube in how order should depth to a layer of gel is applied transmitter/receiver below the the and the and between the the skin. [2] pulse time strength lapsed of the between reected the pulse (ii) the for focal time that the pulse is received, t follows: 25 50 75 100 125 150 1 75 200 225 250 275 300 t / µs the to lenses make a should Indicate be telescope. pulses on A, B the diagram and C and the origin of the reected D. [2] Your The mean speed in tissue in this and muscle of the include: each lens; points for each lens; the position of the eye when the telescope is in use. On your diagram, mark the location of the The formed in the Is the image seen through above depth d of the organ beneath l of the organ O. 1.5 × graph, the 1 10 ms estimate skin and . the the scan is known as [4] an A-scan. State one intermediate tube. in which a B-scan differs from an A-scan. [1] [1] d) d) the is data above way image from scan [4] c) c) used Using length (iii) pulses being 3 labels its C ultrasound (i) d nd D (iii) diagram the also B (ii) Draw nd and A 0 length to [4] [4] and lens. Focal is skin length lens. B, the of telescope. each focal front convex cm method of in second additional Describe focal 18.0 why against stinu evitaler 2. placed / htgnerts eslup 3.0 is scan below An transmitted An O the is c) particular I ultrasound On focal this labelled Suggest [4] of of organ length, cm. lens purpose the the telescope upright State one advantage and one disadvantage of using or ultrasound upside-down? as opposed to using X-rays in medical [1] diagnosis. e) Approximately how long must the telescope tube be? 6. 3. Explain what is meant [2] [1] a) State and explain which imaging technique is normally by used a) Material dispersion b) Waveguide c) Spherical d) Chromatic e) dispersion f) aberrations g) A Cassegrain Total mounting Internal Step-index (i) to detect (ii) to examine A km km length of [2 optical bre has an attenuation each] a graph parallel through of below beam a . ampliers A as 5 mW signal represented is by sent the along the diagram the bone growth wire using two below. optical bre input power shows of the X-rays thickness ytisnetni 15 dB aberrations 1 4 broken [2] of a fetus. [2] bres The 4. a reection x of variation after it has of the been intensity I of transmitted lead. 20 15 output 10 = 5 mW gain = 20 dB gain = 30 dB 5 Calculate 0 a) the overall gain of b) the output power. the system 0 2 4 6 8 10 12 x / mm [2] b) (i) Dene half-value thickness, x estimate x . [2] 2 HL (ii) Use the graph to for this beam in 2 lead. 5. This question is about ultrasound (iii) a) State used a in typical value medical for the [2] scanning. frequency of Determine the reduce intensity scanning. diagram below shows an ultrasound transmitter placed in contact of lead transmitted required to 20% to of its with the value. [2] and (iv) receiver the [1] initial The thickness ultrasound A second metal has a half-value 8 mm. thickness x skin. 2 for this radiation of Calculate what d thickness intensity of of this the metal is required transmitted beam to by reduce 80%. the [3] O ultrasound transmitter and receiver layer of skin and fat l i B Q u e s t i o n s – o p t i o n C – i m a g i n g 189 16 o p t i o n D – a S t r o p h y S i c S ojs vs (1) Sol ar SyStem We live Each such on the planet as is dwarf diameter / Earth. kept in This its planets is one of elliptical like eight orbit Pluto or planets by the that orbit gravitational planetoids also the Sun – attraction collectively between this the system Sun and is known the as planet. the Solar Other System. smaller masses exist. Mercury Venus Earth Mars Jupiter Saturn Uranus Neptune 4,880 12,104 12,756 6,787 142,800 120,000 51,800 49,500 58 107.5 149.6 228 778 1,427 2,870 4,497 km 8 distance to Sun / × 10 m Relative positions of the planets Jupiter Venus Uranus Mars Saturn Ear th Neptune Sun Mercury Some Mercury of objects these planets orbiting (including around them the called Earth) have moons. Our other Moon small is 8 3.8 × 10 An asteroid m away is a and its small diameter rocky is body about that 1/4 drifts of the around Earth‘s. the Solar Venus System. Jupiter with There – the are many asteroid another planet orbiting belt. is An the Sun asteroid known as a between on a Mars collision and course meteoroid. Ear th Small meteors atmosphere Mars on Earth. can be vaporized (‘shooting The bits stars’) that due to whereas arrive are the friction larger called ones with can the land meteorites Sun Comets are mixtures elliptical orbits of around rock the and Sun. ice (a Their ‘dirty ‘tails’ snowball’) always point in very away Jupiter from the Sun. Saturn Vie w from one pl ace on e arth If we look up at the night sky we see the stars – many of these Uranus ‘stars’ The the are, stars in in Milky fact, our other own galaxies galaxy but appear they as a are very band far across away. the sky – Way. Neptune Patterns of the of sky stars have have been been identied labelled as the and 88 different different regions constellations. Relative sizes of the planets Stars in a constellation are not necessarily close to one another. Over the period of a night, the constellations seem to rotate nebul ae around In many constellations there are diffuse but relatively one which are called nebulae. These are of dust, hydrogen, helium and other ionized gases. is M42 otherwise known as the rotation is a result of the of the Earth about its own axis. top of Orion this nightly rotation, there is a slow change in An thestars example apparent interstellar On clouds This large rotation structures star. and constellations that are visible from one night Nebula. tothe next. to rotation the Planetary This variation of the systems over Earth have the about been period the of one year is due Sun. discovered around many stars. Vie w from pl ace to pl ace on e arth If of you the move night latitude. same, 190 O p t i O n D – A s t r O p h y s i c s from sky The but total you place that is to pattern will see place visible of around over the different a the year Earth, changes constellations sections of the is the section with always pattern. the ojs vs (2) maximum During one Day height Hemisphere The most stars of remains stars sky important have have the same been been observation is that from one night identied and 88 labelled as the the to pattern the next. different different of the at midday. Sun is in a At this time southerly in the Northern direction. the Patterns regions of constellations. the A Sun particular The pattern constellations They appear Hemisphere It is is to not appear rotate to refer to in the move around everything common always over one seems to same place, the period direction. rotate measurements to In about the however. of the the ‘xed one night. Northern pole stars’ star. the looking south east patterns always some of the constellations. appears stars rise to rotate above The around the xed the horizon background pole and star. some of During stars set west stars the night, beneath it. During the ye ar Every pole star to night, each portion looking nor th of night same Sun rises movement slow The Sun the east is continued and sets in the location sky from change that night returns continues to is to in the the to same pole visible night. back rise have of above Over exactly the star east (and the the the and relative the horizon) period same set positions thus in of a year position. the west, but east during the day. the the west, year goes from winter into summer, the arc gets bigger The and in the slightly this as The constellations but changes west the other, reaching the Sun climbs higher in the sky. its unitS When the comparing distances astronomical unit on the (AU), astronomical the parsec (pc) scale, or the it can light be quite year unhelpful (ly). See to page remain 193 for in the SI units. Possible denition of the other rst units two of include these. 15 The light away. year Our Universe is the galaxy is 13.7 distance is about billion travelled 100,000 light years by light in light years any in given band observing of light can constellations. across the the be This night night seen a (or became The the are ‘way’) known as (9.5 × nearest centre direction faint crossing ‘path’ sky sky year The 10 m). galaxy The is next about a nearest million star light to our years Sun away is about and 4 the light years observable direction. The the milk y way gal ax y When one across. of of galaxy is orbiting our the galaxy rotating the lies constellation – centre all of in the the the a Sagittarius. stars galaxy result of their attraction. 250 The million mutual period gravitational of orbit is about years. as plan view side view Sun the Milky seeing that are a some make too stars. in is Way. up far The band What of our away that be that our are of galaxy seen they of they galactic nucleus rotation individual appear has to be a Sun spiral direction stars but as galaxy 100 000 light years actually millions own to reason is the you disc shape. globular clusters The Milky Way galaxy the uniVerSe 26 Stars are grouped together in stellar clusters. 1.5 These 3 can be open containing 10 stars e.g. located in the disc (= × 15 10 the m billion light years) visible Universe 5 of is our just galaxy one of or globular the billions containing of stars in 10 our stars. galaxy Our Sun (the 22 5 Milky Way galaxy). The galaxy rotates with a period × 10 local m group of (= 5 million light years) of galaxies 8 about 2.5 Beyond × our 10 years. galaxy, there are billions of other galaxies. 21 10 Some of them are grouped together into clusters m or (= super clusters space (like stars) appears the of galaxies, gaps but between the the vast majority planets or 100,000 light our galaxy our Solar years) of between 13 Everything to be empty together is – essentially known as the a vacuum. Universe 10 m (= O p t i O n 0.001 D – light years) System A s t r O p h y s i c s 191 t ss equilibrium energy flow for StarS The stars energy this is term. are is emitting the fusion referred The combustion). 1 4 to → 0 1 + 2 energy. into but reaction, reaction The helium. burning’ nuclear the of See it not source page this a is for all 196. not chemical a The this (such outer as stars, is mass in layers been the It of Sun radiating might the equilibrium + core the is be energy imagined should Sun stable a have long this the ago. there outward is past the forced time because between for that away Like a 4½ powerful the other hydrostatic pressure and the 2ν 1 inward The has years. reactions precise one Sun billion Sometimes + e 2 deal hydrogen a Overall He great ‘hydrogen is 4 p of as reaction a of the products is less than the mass of the reactants. gravitational force (see page 164). Using 2 ΔE = Δm c we 9 4 × 10 can work out that This takes place the Sun is losing mass at a rate of outward radiation 1 kg s . in the core of a star. Eventually all this ‘pressure’ 26 energy The is radiated structure from inside a the star surface does – not approximately need to be 10 known J in every second. detail. convective zone inward pull surface of gravity radiative zone core A stable star is in equilibrium (nuclear reactions) binary StarS A Both stars are night 0 Our Sun is a single star. Many ‘stars’ actually turn out to be two moving (or more) stars in orbit around each other. (To be precise to obser ver B orbit around their common centre of mass.) These are at 90° they called obser ver binary stars. night 12 Star A is moving A centre of mass towards obser ver B whereas star B is light from A moving away will be blue shifted obser ver light from B B will be red shifted binary stars – two stars in orbit around night 24 their common centre of mass There are different spectroscopic 1. A visual separate categories and binary stars of binary star – A visual, obser ver eclipsing. is one using a that can be distinguished as two 3. An eclipsing brightness telescope. shows 2. A spectroscopic the spectrum wavelengths An example of light show of star a this is from periodic is shown identied from the the Over time ‘star’. shift or splitting in a the periodic star light is identied from variation. the An from ‘star’. the Over example of analysis time this the is of the brightness shown below. analysis ssenthgirb of binary binary of the frequency. (below). wavelength night 0 time (nights) The Each wavelength night 12 of explanation its are orbit, of one equal for star the gets brightness, ‘dip’ in in brightness front then of this the is that other. would If cause as the the a total splits into two brightness A B A B A B A to drop to 50%. separate B star B wavelengths. When one star blocks the light night 24 coming from the other star, the overall brightness is reduced The explanation effect. As towards a star is shifted. 192 a for result the of Earth moving When it the its and shift orbit, the moving O p t i O n frequencies stars sometimes towards is in the D – they Earth, away , are it its involves sometimes are moving spectrum will be red the star A Doppler moving away . will be shifted. A s t r O p h y s i c s When blue result stars obser ver S principleS of me a Surement As you their move relative objects from positions. appear Objects that one to are position As move very far as when far to mathematicS – unitS another you are do not change concerned, compared away objects with appear far to The near for situation close that stars is gives shown rise to a change in apparent position below. objects. move at distant stars all. You can demonstrate this effect by closing one eye and close star moving you when This head example compared distant can your (for side tip with of to side. your objects An object nger) that are will far that is appear away (for near to to move example a building). apparent used galaxy. from the to All θ movement measure stars the appear is known distance to move as to parallax some over the of and the period the stars of a θ effect in our night, but stellar some stars appear to move in relation to other stars over the distance period of a year. d parallax angle θ θ Sun Ear th (January) If carefully obser ved, over the period Ear th of a year some stars can appear to move orbit of Ear th 1AU (July) between two ex tremes. The reason moved position has movement The for over closer this the meant when a apparent period star of that a a close compared is to the movement year. This star with Earth, a is will have more the that change the in an distant greater will Earth has observing be of parallax in star’s if apparent set The stars. a we out know the angle, position the can from (distance be the distance distance the θ, over measured period from the the Earth from of a by Earth to Earth the to observing year. to From the star, the changes trigonometry, Sun, we can work since Sun) __________________________ tan parallax Since all the = (distance stars are very distant, this effect is a very small parallax angle will be very small. It is usual to from Sun to Star) one Since and θ shift. θ is a very small angle, tan θ ≈ sin θ ≈ θ (in radians) quote 1 __________________________ This parallax angles not in degrees, but in seconds. An angle of means that θ ∝ 1 (distance second of arc ('') is equal to one sixtieth of 1 minute of arc In and 1 minute of arc is equal to one sixtieth of a other words, terms of angles, 3600'' = = angle and Earth distance to star) away If we use the right units we can are end up inversely with a 1° very 360° parallax degree. proportional. In from (') 1 full simple relationship. The units are dened as follows. circle. The distance from the Sun to the Earth is dened to be one 11 astronomical show that a unit star (AU). with a It is 1.5 parallax e x ample × 10 angle of m. Calculations exactly one second 16 of arc must be 3.08 × 10 m away (3.26 light years). This 18 The star alpha Eridani (Achemar) is 1.32 × 10 m away. distance Calculate its parallax is dened to be one parsec (pc). The name ‘parsec’ angle. represents ‘parallax angle of one second’. 18 d = 1.32 × 10 m If distance = 1 pc, θ = 1 second If distance = 2 pc, θ = 0.5 18 1.32 × 10 ___________ = pc second etc. 16 3.08 × 10 1 _________________________ = 42.9 Or, pc distance in pc = (parallax angle in seconds) 1 _____ parallax angle = 1 42.9 d = p = 0.02'' The that for parallax are less stars measure use the though method than that at it is The not It is = 1 used to distances an SI SI measure parsecs. common, standard strictly parsecs be 100 greater accurately. unit. 1000 are can about The becomes however, prexes can stellar parallax too to also distances angle small to continue be used to even unit. kpc 6 10 parsecs = 1 Mpc O p t i O n D etc. – A s t r O p h y s i c s 193 ls luminoSity anD apparent brightneSS The total The SI power units received radiated are by an watts. by This observer is on a star very the is called different Earth. The its to luminosity the (L). power It is thus possible apparent power received for brightness. two It very all different depends on stars how to far have away the the same stars are. per close star unit area is called the apparent brightness of the star. The SI (small luminosity) 2 units If are two then Stars W stars the m were one are, . at with the the however, at same distance greater away luminosity different distances from would from be the the Earth distant star brighter. Earth. (high luminosity) The 2 brightness is inversely proportional to the (distance) . Two stars have can have different the same apparent brightness even if they luminosities area 4A area A alternatiVe unitS The x SI units for luminosity and brightness have already x been introduced. brightness of In stars practice using astronomers the apparent often compare magnitude the scale. As distance increases, the brightness decreases since A magnitude 1 star is brighter than a magnitude 3 star. This the light is spread over a bigger area. measure distance brightness x b The of of brightness magnitude different account. scale stars, is sometimes can also provided Astronomers be the quote shown used to distance values of on star compare to the star absolute maps. the is luminosity taken into magnitude in b 2x order to compare luminosities on afamiliar scale. 4 inverse square b 3x 9 b 4x 16 b 5x 25 and so on L _____ apparent brightness b = 2 4πr e x ample on luminoSity bl ack-boDy raDiation 3 The star Betelgeuse has a parallax angle of 7.7 × 10 arc 7 seconds and Calculate its an apparent brightness of 2.0 × 10 Stars can m luminosity. . luminosity and to Betelgeuse analysed of a star temperature Wien’s Distance be as perfect emitters, or black bodies. The 2 W law can is related according be used to to to its the relate brightness, surface Stefan–Boltzmann the wavelength at area law. which the d intensity 1 is a maximum to its temperature. See page 90 for = p more details. 1 __________ = pc Example: 3 7.7 × 10 e.g. = 129.9 pc = 129.9 × So our the sun’s temperature wavelength at is which 5,800k the intensity 3 2.9 × 10 __________ 16 3.08 × 10 m maximum is λ = = max 5800 18 = 4.0 × 10 m 2 L = 194 b × 4πd 31 = 4.0 × O p t i O n 10 D W – A s t r O p h y s i c s 500 nm of its radiation is at a S s abSorption lineS The radiation from stars is not a perfect continuous spectrum – there are particular wavelengths that are ‘missing’. bands of wavelengths emitted by the Sun ‘missing’ wavelength wavelength violet red The missing of number a that the The elements. from is the means star star – is that at was Although we The place have in its are a to it in the seems the way outer in in sensible spectra to atmosphere, would still A assume be this absent if outer telling layers what of the us to the stars classify same class. give stars type of out by spectrum Historically these its receding stars will now know exist that surface be be red blue to the spectrum. shifted Earth Light will show from stars light from whereas a that Doppler are approaching shifted Stefan–bolt zmann l aw spectra spectral are were these relative in class. allocated just of given to a light. Stars the This that same different allows emit a spectral letter, The Stefan–Boltzmann black body. body The different letters also (per unit important law links area) to correspond the the relationship but total power temperature is radiated of the by black that 4 power radiated ∝ T = σ A T to In different moving will Total we is absorption layers. different their that in star. elements cl a SSific ation of StarS Different star shift space. the of absorption Earth’s wavelengths analysed taking least correspond concerned incorrect. absorption This the of elements assumption light wavelengths symbols we have, temperatures. 4 Total The seven main spectral classes (in order of power radiated decreasing Where surface temperature) are O, B, A, F , G, K and M. The main σ spectral classes can be is a constant called the 8 σ Class Effective surface temperature/K 30,000–50,000 = 5.67 × 10 2 W constant. 4 m K Colour 2 A O Stefan–Boltzmann subdivided. is the surface area of the emitter (in m ) blue T is the absolute temperature of the emitter (in kelvin) 8 B 10,000–30,000 A 7,500–10,000 blue-white e.g. The radius of the Sun = 6.96 × 10 m. 2 white Surface F 6,000–7,500 yellow-white G 5,200–6,000 yellow K 3,700–5,200 orange If area temperature = 4π r = 5800 10 = 6.09 × 10 2 m K 4 then total power radiated = σ A T 8 = 5.67 × 10 18 × 6.09 × 10 4 M 2,400–3,700 × red (5800 ) 26 Spectral many classes text do not need to be mentioned but are used = in books. The radius of the star r is linked to 3.9 its × 10 surface W area, A, using 2 the • Summary If we the know star • the • the and the distance work chemical surface to a star we can analyse the light from out: • composition temperature (by analysing (using a the absorption measurement of spectrum) λ equation A = the luminosity the distance the surface . (using measurements of the brightness and away) area temperature 4π r of and the the star (using the luminosity, Stefan–Boltzmann the surface law). and max Wien’s law – see page 90) O p t i O n D – A s t r O p h y s i c s 195 nsss Stell ar typeS anD bl ack holeS The source There are Type Red of of energy however, for object giant our other Sun types is of the As the the dwarf name stars As fusion the of to hydrogen known variables These are hence are into to means forced a as that stars total neutrons. and when that useful Neutron of stars these They place, light stars turn elements hot. luminosity. very This stars out these They suggests, taking give cool. some name longer Neutron of are suggests, comparatively Cepheid that helium. exist in the This is also true for many other stars. Universe. Description stars comparatively White fusion object it are This stars white a little a the collapse The density the of a in one to is be just mass the them are neutron a star is It is then help of calculate is Since stages that have the not enormous. the larger as a a they down. variation distance to stars. of of energy and is in They is will no cease their brightness are – quite average and rare but luminosity. galaxies. gravitational stars it are dwarf some The they Fusion Eventually star. atoms neutron are white, stars. variation the they source are mass brown of red, The larger. smaller regular composed are star. even Since size mass Rotating a cooling known in are some is they for colour. for brightness some star in to oscillation of colour. stages observed an neutron white remnant period to in possible supergiants nal hot remnants of and cold. to red later Red the a They due between use and the size of sufciently post-supernova and size of hydrogen. unstable. can in one small be dwarf link astronomers are be than to thought is large to are out becomes is there other turn a are out it is have pressure essentially been has composed identied as pulsars Black holes Black the holes are the gravitational See page general nuclei of of takes be of how place candidates in the SL do process proton this by is cycle In creation is as a Sun do this known p–p need but the come take is an of larger object mass whose stars. escape There velocity is is no for two any of these positively or close place. helium enough reactions charged nuclei) for Obviously to need will The the to interactions they take particles star 1 1 0 1 to of stop light. stable the of inward But how did at high temperature size the because radiation gravitational is pull. the cloud of gas get to be one a in the rst place? means that they must be at a high of the mean an hence If a large cloud of hydrogen is enough, then these can place nuclear cloud take comes gravitational together, potential increase in temperature. kinetic In the energy loss must energy simple and terms the hot molecules speed up as they fall in reactions spontaneously. The the centre to form a proto-star. power 0 + e a pressure by gas H + speed to repel temperature. proton– 2 H → the balanced As This cycle 1 H + mechanism than remains outward towards 1 step 1 known greater another. to HL information. as remnant result (hydrogen result reaction not order place, of nucleosynthesis. overall candidates, need or the elements reactions recalled One for different ssion Details name The 150. main Sequence StarS The post-supernova collapse. + 1 ν 0 radiated power + by the temperature e star released is in is balanced these by reactions effectively Once the – constant. the ignition can remain See page has stable 205 for taken for place, billions more the of star years. details. p n p p ν 2 step 2 1 H + 1 3 H → 1 0 He + 2 F γ g 0 n F g p n γ p p F g p F g 3 step 3 3 He + 2 4 He → 2 2 p 1 p p p p p n n p p p the proton 196 proton cycle (p O p t i O n D With sucient KE, under gravity gives nuclear reactions molecular KE can take place. 1 He + 2 n n collapse of cloud – p cycle) A s t r O p h y s i c s cloud of gas t h s–rss d h–r Diagram The point of classifying the Hertzsprung–Russell the • various diagram. types Each of dot stars on is the to see if diagram any patterns represents a exist. A useful different star. way The of making following this axes comparison are used to is the position dot. The vertical axis is the luminosity of the star as compared with the luminosity of the Sun. It should be noted that the scale is logarithmic. • The the The horizontal star result axis a scale of decreasing temperature. Once again, the scale is not a linear one. (It is also the spectral class of OBAFGKM) of such a plot is shown below. 6 10 4 10 L/ytisonimul 2 10 our Sun 0 10 2 10 4 10 right. sequence helium. The 0 bottom temperature/K 3 to main to 0 hydrogen left a 0 4 is 0 5 top Sun 0 fusing 6 from Our 0 0 goes stars. 0 7 are 5 They 0 mass. 0 (roughly) sequence 0 their 1 that main 0 to This star. stars line These that is known stars are not are on the main sequence ‘normal’ stable stars the as main sequence – the can and only also be categories. the lines is line 0 are them a as 0 addition These into on known 0 between put fall 2 In stars are 5 broadly it 0 difference of on 0 5 are 0 number that 0 0 large stars 0 A surface broad going regions, from top lines left to of constant bottom radius can be added to show the size of stars in comparison to our Sun’s radius. right. 1 0 1 0 2 s o la r 3 s o la r r a d ii ra d ii red giants instability strip main Sun sequence 1 0 2 s o la r ra d iu s white dwarfs 0 0 0 0 0 0 0 0 0 0 0 0 eective 3 6 1 0 5 0 temperature/K ma SS -luminoSity rel ation for main Sequence StarS For stars the main on the main sequence sequence, (i.e. higher there up) are is a correlation more massive between and the the star's mass, relationship M, and its luminosity, L. Stars that are brighter on is: 3.5 L ∝ M O p t i O n D – A s t r O p h y s i c s 197 cd vs principleS Very small satellite these 100 mathematicS parallax angles observations measurement kpc observe know away. the the The light can (e.g. are Gaia difference a measured mission) limited essential from be to stars difculty very distant between a but that is The even are that star, bright using away and principal of dimmer problem astronomical When we that away this of then stars a luminosity. ‘standard to other do source • Locate • Measure What make their that we in all the a of that variable need In is other a star provide a • Use • the Use light we the had other words of Cepheid variable layers contraction its the variable variation in in the a galaxy as (in which the follows: galaxy. brightness luminosity–period over a given period of time. relationship for Cepheids to estimate we known such star is undergo quite and this a a rare periodic a type of the average law to luminosity, estimate the the average distance to brightness the and the inverse star. star. produces a compression periodic 1 2 3 4 5 6 7 8 9 10 11 time/days and variation Variation in of apparent magnitude for a particular Cepheid variable luminosity. A Cepheid variable star undergoes NUS periodic compressions and L/ytisonimul kaep contractions. increased luminosity 6 10 5 10 4 10 3 10 2 10 10 lower 1 luminosity 1 General These stars period be of this related Cepheid. are to by to variation the Thus calculated useful astronomers in average the luminosity absolute luminosity observing of because turns a Cepheid the variations has a in 2 5 luminosity–period 10 20 graph the out magnitude to of can the be brightness. e x ample 11 A Cepheid variable star period of 10.0 days and apparent peak brightness of 6.34 × 10 luminosity Using the of the Sun is luminosity–period 3.8 × graph 10 W . Calculate the distance peak luminosity = 10 L = 5012 × 3.8 × sun L = b × 4πr ____ L ____ r = √ 4πb _________________ 30 1.90 × 10 ____________________ = √ 11 4 × π × 6.34 × 10 19 = 4.88 × 10 m 19 4.88 × 10 ___________ = pc 16 3.08 = 198 1590 × 10 pc O p t i O n D – Cepheid 26 × 2 ∴ the (above) 3.7 ⇒ to A s t r O p h y s i c s 10 30 = 1.90 × 10 W variable in 2 W 26 The the luminosity. O outer to be candle’. Cepheid Its might stars If with distance the distance galaxy. is stars the the imaged) is is square same really the luminosities. – This determination comparisons candle’ Cepheid closer. be not galaxies. galaxy, luminosity ‘standard is experimental another could judge that approximately Earth. known we and need are the the distances observe galaxy from source in source can ssenthgirb tnerappa in A a estimating we average far of stars about when we process individual pc. m 50 100 period / days rd ss If af ter the main Sequence The the mass–luminosity amount fuel is used. of time relation different Consider a star (page mass that is 197) stars 10 can take times be used before more to the can hydrogen massive than it has higher compare sufcient and mass, higher a red elements giant and can the continue process of to fuse nucleosynthesis continue. our newly formed red giant star 3.5 Sun. = This 3,162 means times that more this luminosity star effectively is the luminosity luminous the mass of that of the our larger Sun. hydrogen in star Since the star, will the be (10) source then the of dormant hydrogen- 400 million km larger burning shell more than has 3000 10 times times the more rate. ‘fuel’ The but more is using massive the star fuel will at nish helium-burning 1 ___ its fuel in of the time. A star that has more mass exists for a shell 300 shorter A star amount cannot of time. continue in its main sequence state forever. It is carbon–oxygen core fusing hydrogen into helium and at some point hydrogen in core of star the core less will often. and the become This rare. means gravitational that force The the fusion star will, is once reactions no longer again, will in cause happen nucleosynthesis equilibrium the core to collapse. This collapse increases the temperature of the core still old, high-mass red giant star further the and star that the to helium increase outer fusion is now massively layers are in cooler. possible. size It – this becomes The net result expansion a red is for hydrogen-burning shell means giant 700 million km helium-burning shell star. carbon-burning shell red giant star neon-burning shell oxygen-burning shell silicon-burning shell iron core star runs out helium fusion possible of hydrogen due to increased ∴ collapses temperature fur ther ∴ This end of process with the other of the greatest words fusion as a source nucleosynthesis binding the of energies fusion of iron of energy iron. per to The must iron nucleon form a come nucleus of higher all to nuclei. mass an has one In nucleus expansion would star on need cannot the to take in continue following energy to rather shine. What than release happens energy. next is The outlined page. O p t i O n D – A s t r O p h y s i c s 199 S v poSSible fateS for a Star (af ter reD giant h – r Diagram interpretation All of the possible evolutionary paths for stars that have been pha SeS) described Page 199 showed that the red giant phase for a star must common come to an end. There are essentially two possible routes nal states. The route that is followed depends a initial mass of the star and thus the mass of the mistake star the red giant star leaves behind: with no sequence. collapse taking of the place gravitational remnant. An forces important continue ‘critical’ represented on a H – R diagram. A examinations moves along is for the candidates line that to imply represents It does not. Once formed it stays at a the stable remnant further and spectral class – i.e. it is represented by one nuclear xed reactions in somehow luminosity that be on main the can with that different here eventually point in the H – R diagram. the mass is called evolution of a low-mass star Chandrasekhar limit 1.4 times our called a star will mass electron collapse If the be of the has less a Sun. degeneracy it is equal Below to this pressure approximately limit a prevents process the further remnant. mass than Chandrasekhar planetary of and ytisonimul the less 1.4 limit. nebula than Solar In and 4 Solar masses this case becomes masses, and the a so it red its is white ‘planetary’ nebula to white dwarf remnant below giant ejection of the forms dwarf a red giant which m ultimately another would Solar becomes term not that be invisible. could planets The cause in the name ‘planetary confusion. same sense The as nebula’ ejected the a i n is material planets in phase s e q u e n c e our System. surface temperature planetary nebula evolution of a high-mass star ytisonimul low-mass star to black hole / neutron star (e.g. type G) white dwarf red giant red giant phase If a star have a is greater mass greater Chandrasekhar sufcient to than a Solar than limit prevent experiences 4 and 1.4 masses, Solar electron collapse. supernova. It In its remnant masses. It is degeneracy this then case the becomes a will above red m a the pressure is in s e q u e n c e not supergiant neutron star or surface temperature collapses to a black hole. The nal state again depends on mass. pulS arS anD qua S arS Pulsars very large-mass that are pulsate cosmic at a sources very rapid of very and weak precise radio wave frequency. energy These have larger-mass supernova now been theoretically linked to rotating neutron stars. A star (e.g. type rotating A, B, O) neutron star would be expected to emit an intense red supergiant beam black hole the of radio star’s pulsation waves rotation, that we in this a specic beam receive direction. moves on As around a and result of causes the Earth. large-mass Quasi-stellar objects or quasars appear to be point-like sources supernova of light shifts and are radio very waves large that indeed, are very which far places away. them Their at the red limits neutron star of our this A neutron star is stable due to neutron degeneracy observations distance they of the must Universe. be emitting If a they great are deal indeed of at power for pressure. 40 their It should be emphasized that white dwarfs and neutron size not have a source of energy to fuel their radiation. be losing temperature all the time. The fact that is released can still exist for many millions of years shows that mass a Volkoff limit limit will 200 and neutron form masses star and can is black involved have 2–3 is Solar are called enormous. the masses. The above holes. O p t i O n D – largest Oppenheimer– Remnants is not well process understood, have been developed A s t r O p h y s i c s black holes. that The rely energy on but by which some the this theoretical existence radiated the whole temperatures The of these super-massive stars W!). They models must 10 stars energy do (approximately this stars ‘falling’ into the black hole. is as a result of t b b d e xpanSion of the uniVerSe the uniVerSe in the v v A D If a galaxy is moving away from pa St – the big bang A the Earth, the light from it D will If be red fact is shifted. that The light surprising from almost us (at rest) the have shows red shifts all of them are moving v v from us. The Universe all C B away in is currently the past all expanding, the galaxies at would been closer together. If we examine C – the almost time all B galaxies Universe some current the expansion matter in the in detail we observable nd that universe is would have been together at the SAME As far as we are concerned, most galaxies expanding. point approximately 15 billion years ago. are moving away from us. This is v At rst sight, this expansion known the A point, the to suggest middle of that the we creation the in Big the of the Bang. Universe It Universe, pictures being all crushed vD are Universe, as matter together seems the (very high density) and being very in hot indeed. has been Since the Big Bang, the Universe but v us this is a mistake. We only average, to be in the middle expanding because it the we who worked out which temperature means and that, density of on the D A Universe was – seem have been decreasing. The rate of the v C velocities of the other expansion as If we imagine being in a exactly galaxy, the we same would picture a result between the Any galaxy would see all the other galaxies Note moving away from it. explain way to picture this expansion is to think of the Universe as a sheet stretching off into the distance. The galaxies are placed on this If the tension in from everything the the the rubber is increased, everything on the this how All sheet gravitational masses in attraction the Universe. model the it does not Universe does is attempt was analyse to created, what or by happened this creation imagine the took place. expansion is The to best think way of the moves expansion away decrease huge to sheet. to of after rubber of all that Whom. good expected get of Universe. A be C B (at rest) different would galaxies. of space itself rather than the else. galaxies was the theory of of space imagine and background coSmic microwaVe from the radiation Universe is itself the radiation which 2. has Big links so was Some of time the after the we need to sense ask the Big Big to Big and the able Bang of before became Big Einstein’s creation before in The time. measurements make created radiation the as not notion void. and properly Bang does a space happened the itself) time It what because time the into of relativity and time. about As the section of rubber sheet expands, everything moves away from everything else. expanding creation space Bang, after (i.e. Bang. Bang, to travel through backgrounD raDiation now A further piece of evidence for the cooled down to an average the of 2.73 came with the discovery Cosmic has microwave all radiation by been this Penzias and discovered that microwave coming space. towards The strange us that from thing all was was to a source. this to theoretical by temperature This is in ways 1. of All was not a in of analysis very of 2.73 understanding objects radiation. predicted model of give The out the linked that match cold object with There – a the are two this. electromagnetic frequencies using be showed K. Bang. wavelength this of will have increased this (space stretched). Seepage210 for the radiation agreement Big time – in the CMB. directions to good extremely just all seem black-body an perfect predictions same did Further radiation produced the and this expanded directions that can be egnar htgnelevaw tinu rep ytisnetnI (isotopic) has the anisotropies radiation towards During radiation has in travelling time. Universe radiation was details). Wilson. means They for background the (CMB) 210 of us the page K. It model (see Big temperature Bang Universe peak wavelength ~1.1 mm (microwaves) individual data points for background microwave radiation theoretical line for 2.73 K black-body radiation theoretical black-body radiation. wavelength The O p t i O n D – A s t r O p h y s i c s 201 g DiStributionS of gal axieS Galaxies are clustered or so galaxies The Virgo in region a are not distributed together. in less galactic 7 grouped For into than cluster million galaxies though randomly 2.5 (50 light huge involve randomly example, in million million years together throughout region light light across. superclusters arranged throughout the in of an empty away even galaxies. joined space. the They Milky tend Way to be there found are twenty years. years On of from larger In us) general, ‘laments’ has scale, (or over the these bands) 1,000 galactic galaxies clusters superclusters that are often arranged as space. motion of gal axieS As has been majority distant does of galaxies not, observed As seen are however, wherever explained itself on space) of light can of space. be page are It mean we is that 201 201, is a at we good of in as the the a in at of the the to observational us. greater way expansion results from are located a surprising away away that are the thought it moving moving page expanding. through on galaxies The general speed centre as of the the fact trend Universe of vast the more expands. – this This would be Universe. imagine space galaxies’ (as this relative expansion of expansion opposed the to the velocities. In wavelength is to think motion this due of model, to the of the space galaxies the red shift ‘stretching’ light wave when it arrives at Ear th star the page of the that light wave as emitted from a distant galaxy esrevinU fo noisnapxe dna emit a is Universe Examle mathematicS If that or a light 102). the galaxy will If a galaxy calculated be moves altered galaxy with from is red as from us, predicted going respect the away to away an shift of by from observer the light then the the on the wavelength Doppler Earth, the from the Earth the effect (see speed can galaxy. be As A characteristic ionized has helium. this line recession at absorption It a speed occurs measured of the (499.3 ∆λ velocity is small when compared with the velocity of light, = simplied red shift equation can be If wavelength – of star? 468.6) 468.6 used. 2 Z = = 6.55 × 10 = 6.55 × 10 v ∆λ ___ ≈ c λ 2 ∴ 0 v Where = ∆λ = change in wavelength wavelength λ = wavelength is of of observed light (positive increased) light emitted 0 v c Z = = = 202 8 × 3 7 relative speed red of velocity of source of light light shift. O p t i O n D – A s t r O p h y s i c s if 1.97 × 10 × 1 m s 10 1 m s in the = λ 0 a seen nm. _______________ ___ the often 468.6 long Z as line at stars is due spectrum 499.3 nm, of to a what star is the h’s d s s e xperimental obSerVationS Although galaxies the is uncertainties that the are recessional large, hiStory of the uniVerSe the velocity general is trend proportional for to If the a galaxy velocity is to at be a H distance x. If it x, has then been Hubble’s travelling law at predicts this its constant 0 distance away from Earth. This is Hubble’s law. speed has since the elapsed beginning can be of the calculated Universe, then the time that from 1 10 000 s mk / yticolev lanoissecer distance ________ Time = speed 8 000 x ____ = H x 0 6 000 1 ___ = H 4 000 0 This is an upper limit for the age of the Universe. The 2 000 gravitational speed of attraction recession between decreases all galaxies the predicts that the time. 0 0 20 40 60 80 100 120 140 size of R distance / Mpc obser vable Mathematically v ∝ v = this is expressed universe as d or H d 0 1 T ≈ where H is a constant known as the Hubble constant. The H 0 0 uncertainties in the data mean that the value of H is not 0 known to any degree of precision. The 1 constant are s SI units 1 , but the unit of km of the Hubble 1 s Mpc is often used. time now 1 H 0 the coSmic Sc ale factor (R) v Δλ ___ Page 202 shows how the Doppler red shift equation, = ≈ , can be used to calculate the recessional velocity, v, of certain c λ 0 galaxies. the than 1.0. quantity As This speed of equation light, This introduced object the on means 10 stretched over The cosmic was emitted used when plenty their speed of scale factor (R). page time 10 be however that a years scale only are cosmic that million can There implies called Universe c. 201, the ago, and this factor, million will R, be can is a years the and considered way ago of undertaken stretched be of ≪ as or in is at some be λ words, night than is best time in recorded rescaling the wavelength the greater will a other in Universe quantifying with c objects recession expansion measurement v of of the the as the recessional (e.g. speed pictured the expansion when the sky of as a larger Universe that scale has light. the distant for value (the was place. R by Δλ to a larger value λ (λ = λ + Δλ). , of space the getting the to be small observed it itself. is now. The All in red comparison shift, helpful to of light z, is of a the emitted measurement to greater consider expansion wavelength measured In the has the situations example when v, which these Universe 0 increased In for expansion past, taken factor velocity, quasars) will by an be bigger). above wavelength example, if measured the wavelength today would have 0 This is because the cosmic scale factor has increased by ΔR (to the larger value 0 λ R R = R + ΔR). All measurements will have increased by the ratio, 0 . The ratio of the measured wavelengths, R , is equal to the λ 0 0 R ratio of the cosmic scale factors, , so the red shift ratio, z is given by: R 0 λ Δλ ____ z = λ λ ___ 0 _____ = λ = 1 = 0 0 0 1 R λ λ 0 R ___ R ___ or z = - 1 R 0 R So a measured red shift of 4 means that = 5. If we consider R to be the present ‘size’ of the observable Universe, then the light R 0 must have been emitted when the Universe was one fth of its current size. O p t i O n D – A s t r O p h y s i c s 203 t vs SupernoVae anD the accelerating uniVerSe Supernovae (the last one observed. over a An light whereas aspects Type be Ia is of type at which Ia a no and can its be single sees months. into light in a a I a in 1604) increase different II development the in of exceeds type the but amounts often two occur in rapid Huge from type can place supernova The hydrogen that took Earth or categorized many main types There stars (see further the stars stars the are or page indicates are some of (hence energy local of number brightness radiated supernova supernova. large in word emitted for subdivisions of of a 200). = new short Supernovae means star) period of that which time are many then and, rare have events been diminishes at its peak, the galaxies. more presence page Universe ‘nova’ in individual 207 (see the details) according hydrogen these (from types (Ia, to the Ib, a spectral absorption etc.) based analysis spectra) on different spectrum. are explosions and apparent used with Universe gravitational supernovae it explosions galaxy the emit. accurately expanding of on been light our weeks of they supernovae technique result some have the supernova a of there of in observer that predicted The catastrophic occur brightness Supernovae the to period apparent of are increases involving brightness galaxies (which is as up larger to dwarf be in with a provided time the expect as galaxy, 1,000 Big Bang rate at evidence In When other these ‘standard given the strong passes. stars. used approximately might as can observed consistent we however, getting white supernovae attraction, has, is these a Mpc distance model) that take By place, the comparing measurement amount the to known that of energy released luminosity galaxy can be of a can type calcuated. Ia This away. which means R not words events candles’. the that increases only is that to the expansion be the cosmic of cosmic slowing the scale scale down. factor, Universe is factor, Analysis R, R, of is a increasing accelerating. increasing. large but The As number the rate evidence 2 from type Ia supernovae identies this effect from a time when the universe was approximately of its current size. Note that this 3 acceleration The different mechanisms counteract (see is page the that to the cause inward very an rapid period accelerating gravitational pull. of expansion Universe There must are not also be of the fully a early Universe understood source of but energy which must which is called involve has been an ination. outward given the accelerating name 212). dark energy accelerated expansion development of galaxies dark ages ination st 1 stars 13.7 billion years Source: 204 NASA/WMAP Science O p t i O n D Team – A s t r O p h y s i c s dark force energy to n s – Js HL the Je anS criterion As seen on hydrogen, in stable (e.g. a can such with as time, a the thought stars and equilibrium in be 196, helium collision incident point page nucle ar fuSion form other for many another total as a of interstellar materials. years cloud supernova) of out energy until or starts Such the can external inuence collapse. associated combination clouds an the clouds with the A exist gas is another any star the the given cloud The negative gravitational mass process energy, E , main sequence nuclei. proton–proton stars alternative of: potential the helium predominant small In • on produce event of At of this (up place reaction, chain method process, takes One to called at as for just fusing the hydrogen by outlined nuclear above higher carbon, is process the CNO which on page fusion mass to of is 196. take our to achieved This place Sun). is in An (carbon–nitrogen–oxygen) temperatures nitrogen nuclei this and in larger oxygen are mass used stars. as which P catalysts the cloud possesses as a result of its mass and how it and the in space. density of Important the factors are thus the to aid the fusion of protons into cycle is shown The positive random cloud. kinetic START 4 energy, E , that the particles 1 H H the cloud possess. temperature The cloud will of the An important factor is thus One 1 K in nuclei. below: mass He • helium is possible distributed γ the cloud. remain gravitationally bound together if 12 C E + E P that is < zero. Using this information allows us to 15 predict K 13 N the collapse greater than of an interstellar a certain a given critical cloud mass, may M . begin This is if the its Jeans ν J criterion. For cloud of gas, M N mass is dependent on the J cloud’s to density collapse if and it temperature and the cloud is more likely has: 15 13 O C • large mass 14 N • small • low size temperature. γ γ In symbols, the Jeans criterion is that collapse can start 1 H 1 if H M > M J γ proton ν neutron gamma ray neutrino positron time Spent on the main Sequence For so long as hydrostatic a star remains equilibrium (see on the page main 192) sequence, and have a hydrogen constant ‘burning’ luminosity is L. the A source star that of energy exists on that the allows main the star sequence to for remain a time in T MS must E in = total L × radiate an energy E given by: T MS This star energy M has release been comes converted from into the nuclear energy synthesis according to that has Einstein’s taken place famous over its lifetime. A certain fraction f of the mass of the relationship: 2 E = f × Mc L × T 2 ∴ = f × Mc MS 2 f × Mc _______ T = MS L 3.5 But the mass–luminosity relationship applies, L ∝ M M ____ ∴ T ∝ MS 3.5 M 2.5 ∴ T ∝ M MS Thus the higher the mass of a star, the shorter the lifetime that it spends on the main 2.5 Time on main sequence for star A Mass ____________________________ on main sequence for star of star A Mass ____________ = Time B ( Mass of star B sequence 2.5 of star B ____________ = ) ( Mass of star A ) 10 For example times its our mass be Sun is expected expected to to have a main sequence lifetime of approximate 10 years. How long would a star with 100 last? 2.5 1 ____ 10 Time on MS for 100 solar mass star = 10 × ( 100 ) 5 = 10 years O p t i O n D – A s t r O p h y s i c s 205 nsss s HL nucleoSyntheSiS off the main Sequence For so long ‘burning’ emitting more as is star remains source energy helium helium a the of whilst exists (helium in on the energy remaining the core. ‘burning’) in A does main that sequence, allows a the stable nuclear release state. to continue More synthesis energy hydrogen star the high that and the involve very high temperature massive and involving (since In nuclei the can mass of stars, the core continue release of to energy. gravitational can be produced. Typical binding of neon: nucleon of the products is greater than that of Production but can only take place at high + high mass stars, the helium burning of magnesium: can + and spread throughout the core whereas begin in Production stars this process starts suddenly. Whatever the mass star, a new equilibrium of oxygen: state is created: the red → C page common nuclear process reactions by C → addition giant if the or burning temperatures can the helium triple is converted alpha is process a in are high series enough, Two neon γ → helium nuclei ray), + He 2 4 + of 24 He → Mg 2 16 fuse releasing sulfur: O + + γ 12 16 32 O → S 8 + γ 16 into a beryllium nucleus (and reactions 4 He + and → Be 2 are and also other heavy produced. nuclei Some of such as these + nuclear reactions also produce neutrons, which can γ 4 easily beryllium produce possible phosphorus 8 He 2 are a energy. alternative 4 to 4 O 8 10 silicon The and produced. gamma 2. He 2 16 + Ne of which Many 1. 2 occur: 8 is + red Production carbon 4 O 8 200). which called γ 16 6 20 A + 12 + Ne (see He 2 Mg 6 12 10 phase + 24 20 supergiant 4 Ne of oxygen the all small In mass → 10 C 6 6 gradually reactions 20 C 12 C temperatures. process means more include: 6 12 For These and the 12 reactants) rise 12 C 6 per to reactions 12 Production energy contraction continue a nucleus carbon fuses with nucleus another (and a helium gamma ray), be captured by other nuclei to form new isotopes. This nucleus process of In high neutron capture is explored further below. releasing very mass stars, silicon burning can also take place energy. 56 which results in the formation of iron, Fe. As explained on 26 8 4 Be + 3. → C 2 Some can 12 He 4 of go the on oxygen. fuse + produced with this 4 C in another process the triple helium releases alpha nucleus nucleon process to 199, produce in a and fusion acquired, energy: iron has one of represents process but the the the that highest largest releases reactions binding nucleus energy. require an energies that can Heavier energy per be nuclei created can be input. 16 He 6 γ page carbon to Again 12 + 6 → O 2 + γ 8 nucle ar SyntheSiS of he aV y elementS – neutron c apture Many of involve any are the the charge, present reactions release it is in of easy the that take place neutrons. for star. them When to a in Since the core neutrons interact nucleus with of are stars other captures a also nuclei that neutron, s-process giant without than nucleus is said to be neutron rich. Given helium most of these neutron-rich nuclei would alternative undergo In emitting 1 this an process, electron 1 n → 0 + X + changes into a vast β A n + + 206 process, takes place numbers rapid when that neutron-rich nuclei neutrons captured. to A X + 1 are be created. → Z Y Z + catastrophic 0 + 1 able to be of a red heavier created. neutron the capture neutrons are or the present there is not sufcient time for in the to undergo The beta result is decay for before very several heavy more nuclei Typically β + known as slow result of the neutron s-process O p t i O n D explosion the that r-process is a takes supernova. place during Elements the that are v 1 capture or the s-process. is – a new element. Typically A s t r O p h y s i c s than iron, such as uranium and thorium, can only be The created overall are are proton, v 1 → 0 is iron stage that antineutrino: heavier This than burning elements 1 1 Z neutron an lighter helium that 0 p 1 A the and the means beta such decay. but during this enough r-process, time, place Typically the The resulting takes star. the in this way at very high temperatures and densities. ts sv HL SupernoVae Supernovae on their are light among curves – the a most plot gigantic of how explosions their in brightness the Universe varies with (see time page and a 200). The spectral two categories analysis of the of light supernova that they are emit. based Type I 10 supernovae quickly reach a maximum brightness (and an equivalent luminosity of 10 Suns) which then gradually decreases over 9 time. Type II supernovae often have lower peak luminosities (equivalent to, say, 10 Type II Type I ytisonimuL ytisonimuL 0 100 200 300 0 100 days after maximum brightness Supernovae the types elements • Type Ia • Type Ib • Type Ic All Suns). type II presence, The are distinguish identied and the by analysis different of the presence of singly shows the presence of non-ionized not show supernovae or reasons not, for of the show the different these presence Supernova Does Cause White Context Binary ionized of 300 400 light (Ia, spectra. Ib and All Ic) type are I supernovae based on a do more not include detailed the spectral hydrogen spectrum in analysis: silicon. helium. helium. presence of hydrogen. The different subdivisions (IIP , IIL, IIn and IIb) again depend on the elements. differences Spectra their subdivisions shows does 200 days after maximum brightness not are the Type show different mechanisms that are taking Ia place: Supernova hydrogen but does show singly ionized Shows Type II hydrogen. silicon. dwarf star orbiting exploding. system each with white dwarf and red giant other. Large mass Large star of its The gravity material mass of eld from the of the white the red white giant dwarf star, star thus attracts increasing When the dwarf. the cannot The The extra mass total mass limit (1.4 of Solar degeneracy the gained the release matter of (up to is the for no collapse. iron) energy being by beyond masses) pressure gravitational elements star a distributed white the star takes dwarf. the fusion the to to of heavier resulting explode throughout halt sudden with the star any and material moving Solar out of masses) elements fuel, further under degeneracy degeneracy be runs gravitational stable 8 lighter at up the to end the its the energy own iron by centre nuclear gravity core fusion. forming a star. Electron the Electron sufcient Nuclear and dwarf Chandrasekhar longer starts causes white the collapsing. iron. collapses neutron Explosion of star than fusing release star giant (greater lifetime, production Process red pressure rigid pressure collapse is and neutron bounces off outwards. the This of is the the star. core not sufcient core, core The but becomes rest creating causes all of of a the to halt neutron the a infalling shock outer wave layers to ejected. space. O p t i O n D – A s t r O p h y s i c s 207 t s d ds HL section the coSmologic al principle The cosmological structure The two of An isotropic large – but upon are scale that a pair which the of assumptions current Universe, structures in the about models are providing Universe, is the based. one only isotropic statement the Earth. in an the this is one the of galaxies in not Earth, all same this to see other. of the the same we on will the universe. structures the in validity used be that homogeneous expansion universe is one where the local galaxies and galaxy clusters that exists in one region of the turns universe. out to be Provided the one same is distribution considering a in all regions stars mass. in a galaxy Different rotate models around can be their used to reasonably common predict based if the the of the develop Hubble’s Universe and now Big He in large to scale question of of by general existence that model this galaxies is observational the model cosmological principle agree Bang a did between equations cosmological the very static. attraction physicists around space look of the of an correct, the discovery CMB Universe is expanding cosmological for the principle future of the is also linked Universe to (see three page 211). large The centre how The models of rotation curVeS – mathematic al moDelS The of to was yet-to-be-discovered analysis to hundreds of astrophysicists principle Universe non-static. many choose apparently some several the possible universe that we to volume distribution universe. of a that principle. gravitational by of equal in wherever cause the that, be radius discoveries Subsequent meant of galaxies cosmological the must the same which Universe of cosmological balanced non-static A the showed has the the in sphere Universe relativity of Earth observe. of a number Recent the Universe would (e.g. the effectively repulsion. the random on be space then proposing a they basic do be From universe, wherever as they to of Mpc), Einstein every observers clusters direction in any appears observers, to to structure apply galaxy whatever the different scale expected and is only universe are looks on large does isotropic true that direction observer about universe, distribution and an assumption In is particular of of the universe no perspective true are the is homogeneous direction the Universe assumptions considers and the principle the star circular of at a given motion gravitational speed distance because its r from the centre centripetal force will is orbit in provided by the attraction: 2 varies with distance from the galactic GMm _ centre. mv _ = 2 r r 1. Near the galactic centre GM _ 2 ∴ v = r A simple model to explain the different speeds of rotation of stars The near the galactic centre assumes that density of the galaxy total centre, ρ, is constant. A star of mass m feels a resultant of stars that orbit closer resultant force attraction is the in same towards as if the the total centre. mass M The of value all the of = volume to the galactic centre were concentrated in the density stars that 4 centre. An v point to note is that the net effect of all the M, is stars = that 3 πr × ρ 3 πr ρ 4πGρ 3 _ _ = = 2 r r important star, 3 G closer × this 2 are this force 4 gravitational of by M of than near given its mass 3 _____ are 4πGρ _ orbiting at radius that is greater than r sums to zero. ∴ v = r √ 3 i.e. v α r density of stars in galactic centre = ρ 2. Far away Far away from the galactic centre speed ν of visible reduced mass of star, m be from stars so much by galactic show considered unaffected the to that that be their centre, the individual freely observations effective stars orbiting neighbouring density at the these central stars. In this of of the the number galaxy distances mass and to be situation, radius r GM _ 2 v = where M is the mass of the galaxy r 1 i.e. v α √ Comparisons agreement r with with observations mathematical withmathematical model ν discussed stars outside r have overall no net eect M m r stars inside r have eect of total mass M at centre 208 O p t i O n D – A s t r O p h y s i c s on page 209. (2). of real model The galaxies (1) but proposed show no good agreement solution is has can r vs d d HL rotation curVeS 350 Galaxies this rotation analysis show an a this initial at speed be Most centre calculated speed A galactic for mass and individual with the speeds stars curve for distance from a an galaxy from the show: in orbital velocity with distance centre increasing rotation of rotation varies galaxies increase slightly of their spectra. orbital linear the or can star’s centre. within • the how galactic • of around )s/mk( deeps latibrO of rotate away curve from the showing galactic a roughly 300 NGC 4378 NGC 3145 250 NGC 1620 200 NGC 7664 150 100 constant 50 centre. 5 10 15 20 25 distance from centre of galaxy (kpc) that e ViDence for Dark matter As shown agree but above, with the theoretical orbital distance observed away from of the orbital velocity is the orbital velocity v radius, models velocity the rotation within stars centre roughly of a star curves is the not as real galactic observed would constant is for be at (v α decrease expected. whatever constant centre to the different we can matter. galaxies outside r) with matter Instead, radius. values Further In the Dark so the galactic could be that suggestion situation evidence neutrons If of see this it centre constitute is that to a only be that have forming suggests imagined would be halo a made ordinary, there to or around very up must small of be dark concentrated the baryonic, the galaxy. amount protons of this and matter. matter: then • gravitationally • does attracts ordinary matter GM _ 2 since v = r not emit radiation and cannot be inferred from its M _ = constant or M α r interactions r Thus the must be total mass increasing certainly not true that is with of keeping distance the visible the from mass star the (the orbiting galactic stars in its galaxy centre. emitting This • is unknown • makes • machoS, wimpS anD other theorieS explain of. • why There The are there are a matter could Halo evidence that or could lots of of account or be in for Massive matter of could light. small with and theories what it to short. does as There exist in low-mass even be black Evidence is some could These are ‘failed’ holes. Perhaps correct. simply these suggests the There so-called • Astronomical for up Universe majority stars made be the of into new of the Universe ordinary with particles that Interacting around the world baryonic less than 5% of we do not Massive are matter. know about. Particles. searching for Many these WIMPs our current Some a up Weakly experimenters consists theories: thought no a up matter MACHOs They or come possible ordinary can little to dark found planets. produce only be much Objects These high-mass would so number Compact groupings. attempting is structure light) the Astrophysicists in is theories theories failure of our try to of gravity explain current are the theories not completely missing to take matter as everything account. These that these proportion. O p t i O n D – A s t r O p h y s i c s 209 t s uvs HL projection fluctuationS in cmb The cosmic isotropic in the space (the early with precisely no to be any uniformly Further distributed (anisotropies) are in typically a as the few identical know, is the temperature with the If this projection in the Just 2.73 which CMB like of a The diagram highlights (with map K. the the effects – it includes all the our in received CMB from the would stars is and be would be not galaxies. uctuations of the temperature the right minor of variation was would early variations background Variation effective in Anisotropy temperature the matter matter matter distribution These compared all. and that into tiny that shows wholeUniverse. essentially Universe Universe however, is throughout at the everywhere reveals directions. µK of concentrated CMB implies variations throughout it This (CMB) distributed development We the different directions). uniformly the structure. of radiation temperature then distributed in all was absolutely analysis Universe background in random case uniformly without same Universe the expected be microwave is an observed own of the The variations galaxy countries CMB as Probe observed by the Wilkinson Microwave (WMAP) enhanced in removed). world, minute Universe this differences densities, which in allow temperature structures to imply be minor differences developed as the expands. the hiStory of the uniVerSe We can ‘work • Very • As • The soon the backwards’ after the Universe and Big imagine Bang, expanded it the the process Universe cooled. It had that must to took have cool to place been a soon very certain after the Big Bang. hot. temperature before atoms and molecules could be formed. 36 Universe underwent a short period of huge expansion (Ination) that would have taken place from about 10 s after the 32 Big Bang to 10 s. Time What 45 is happening Comments 36 10 s → 10 s → 10 36 s Unication s Ination of forces This is the starting point. 32 10 A rapid rapid 32 period of expansion expansion are not – fully the so-called inationary epoch. The reasons for this understood. 5 10 s → 10 Quark–lepton s era Matter and slightly 5 antimatter more matter (quarks than and leptons) are interacting all the time. There is antimatter. 2 10 s → 10 Hadron s era At the beginning protons 2 and of this neutrons) short to be period it is just cool enough for hadrons (e.g. stable. 3 10 s → 10 Nucleosynthesis s During nuclei. 3 this period some The matter that and antimatter The formation have of the now protons exists is and the neutrons ‘small have amount’ combined that is left to form over helium when matter interacted. 5 10 s → 3 × Plasma 10 era (radiation years era) plasma with of light nuclei electrons, has protons, now nished neutrons, and helium the Universe nuclei and is in the photons all form of a interacting. 5 3 × 10 years Formation → of atoms At the beginning of this period, the Universe has become cool enough for the rst atoms 9 10 to years exist. the Under matter. It microwave these is conditions, these photons radiation. The the that photons are Universe is now that exist being essentially stop received 75% having as part hydrogen to of and interact the with background 25% helium. 9 10 years → Formation now galaxies of and stars, Some galactic of matter clusters are the is matter dense expansion any radiation over time very (see short microwaves The the that 12 Universe has page approximately at of been 202). billion – spectrum the of CMB CMB emitted Thus years wavelengths is means the ago now that in the the radiation (shortly being will that after received was as hot ‘stretched’ emitted Big smaller enough, longer radiation was and corresponds to black- much λ the change radiation at a temperature of 2.73 K. The at two different calculation λ α so R uses ∴ law to link the peak wavelength, λ , of the radiation max the temperature, T, of the black body in kelvins: 3 2.9 × 10 __________ λ = max T 1 λ α max 210 T O p t i O n D – A s t r O p h y s i c s to was reactions emitted also 1 α T of times 1 Wien’s gravitational nuclear wavelength, max body by hotter, was stretching in wavelengths received together interactions. can take place If this and stars the the temperature cosmic scale proportionally of factor, much the R, was much smaller. max Since Bang) much the universe of radiation. radiation and When be the brought formed. wavelength past be enough coSmic Sc ale factor anD temperature The can R or T α R the Universe then must the be is ratio the the of same cause cosmic as the of the scale ratio factors of peak t uvs HL rotcaf elacs cimsoc future of the uniVerSe (without Dark energy) If the to do Universe in the is expanding future? are moving away the galaxies, As from then this a at result us. If the of the there expansion moment, Big were could what Bang, no be is it other forces going galaxies between thought of as being R open at closed constant. now rotcaf elacs cimsoc An open current rate force of expansion a of Universe gravity is slows one the that rate continues of to recession expand of the forever. galaxies The down 1 little halt. A bit The expansion uniform. means there force is The that is a of if two force must going of have to expansion the force do and gravity masses are attraction slowed in the the it is would closed not Universe back on the expansion the Universe strong happen to is one itself. an if is bring in the brought force This to density that The end. enough the of to gravity would the expansion Universe a is happen stop and enough if were the to a low. then to bring density in time Universe of but This collapses now it time R however, between moving pulling the depends of matter all apart them expansion future density cannot, acts from back down on in the the have masses. one been the This past. current What rate at and another together. in A This of down but The it is takes happen if a little make bit the high. the force an the electron-positron be Universe. Universe closed. only were mathematical of gravity innite Universe pair bigger. Universe time were more, Just possibility keeps and enough to on get to exactly the to between slowing rest. the the This right gravitational start the open expansion would density. force One would contraction and closed. critic al DenSity, ρ c The theoretical Universe is value called of the density critical that would density, ρ . create Its a value at is not c radius r certain because the current rate of expansion is 26 measure. Its order of magnitude is 10 not easy to 3 kg m or a few proton total mass in masses every cubic metre. If this sounds very small recessional remember sphere, M that enormous mass at amounts space exist that contain little or velocity = ν no all. The density It reasonably is of of the Universe easy to is not estimate an the easy mass quantity in a to galaxy measure. by The total energy E of the galaxy is the addition of its kinetic T estimating the number of stars and their average mass but the energy E and gravitational potential energy, E K majority of the mass in the Universe is dark = E T value of ρ can be estimated using Newtonian + E K P gravitation. 1 c E a consider recessional a galaxy at a distance velocity of v with r away respect to from the an observer 2 = K We by: matter. E The given P mv but Hubble’s law gives v = H r 0 2 with observer. 1 ∴ E 2 = m(H K r) 0 2 average density of universe GMm _ E inside sphere = ρ = 4 - but M = volume × density = r P 3 πr ρ 3 radius r 3 G4πr 2 ρm 4Gπr _ E = ρm _ - = P - 3r 3 obser ver recessional velocity = ν If E is positive, the galaxy will escape the inward attraction – T the If universe E is is open. negative, the galaxy will eventually fall back in – the T universe If The net effect of all the masses in the Universe outside the E on the galaxy is zero (see page 208 for an is exactly The galaxy is thus gravitationally to zero, rest – the the galaxy universe will is take at. an This innite will time occur to when be the analogous density situation). closed. T brought sphere is attracted in by of the universe ρ is equal to the critical density a ρ c 2 total mass M which acts as though it was located at the 4Gπr observer 1 ∴ as shown m(H r) m _ 2 = 0 2 (above). ρ 3 2 8Gπr 2 ∴ mH r ρ m _ 2 = 0 3 2 3H 0 _ ∴ ρ = c 8πG O p t i O n D – A s t r O p h y s i c s 211 D HL coSmic DenSity parameter The cosmic density parameter, Ω is the ratio of the average If Ω If Ω 0 density of matter and energy in > 1, the universe is closed. < 1, the universe is open. = 1, the universe is at. 0 the Universe, ρ, to the critical 0 density, ρ c If Ω ρ 0 ___ Ω = 0 ρ C Dark energy Gravitational of expansion with time. candles has in Currently fact, are on cause, been both and the the slowing brink of the single discovery for the dark of yet either down means that that expected Ia to the the time the • rate as Universe’s page rate to is of need of to new Universe’s name matter ‘dark are a that be our gravity 204). mass of for physics. • this theories modied. concepts. their basis existence that had to matter within been observation source different theoretical than to galaxies be explain for able adds to galaxies previously the to the ‘missing known explain the a laws galaxy’s attractive implying expected, matter’ of more hence rate force of unseen the name mass galaxies. energy’. implies acting opposes has within attraction of that means counteracting we the expansion The hypothesized Dark accelerating of Perhaps Whatever accelerating two evidence agree explanation is exist rotation. dark possible matter must gravitational standard expansion (see Dark that decrease supernovae that over accepted it relativity experimental have type evidence indicate course, general and be increasing. no of general energy existence is and, reason cases physicists been there given Dark been masses would using strong currently has observation gravity between Universe provided Observations expansion the Measurements have not, attraction of the The the expansion that then attractive attractive resulting energy, of force force the be gravity. gravity in name Universe must of of increase hence the there energy dark a is force Dark that is energy between implies an unseen energy In but explains the concept. effect of Dark energy on the coSmic Sc ale factor The existence The graph of below dark energy compares counteracts how a at the attractive Universe is force predicted of to gravity. develop This with will and cause cosmic scale at Universe with dark energy factor, R (accelerating expansion) at Universe without dark energy (approaches maximum size) now 212 O p t i O n D – A s t r O p h y s i c s time the without cosmic dark scale energy. factor to increase over time. asss s HL • a StrophySicS reSe arch Much of the undertaken current in collaboration proud at the of time astrophysics and their fundamental the that the involves sharing record of research of close previous edition is Scientists collaboration. the Cassini spacecraft of had this been book in can For was orbit is be be • example, several years sending information about the and is currently (2014) continuing to Cassini–Huygens spacecraft was funded Space Agency), NASA (the planet back Administration of the United States of Life as Spaziale general mission was the the 23 information was moon and The scientic Dark countries research and against, nature Future of Survey by ESA they Arguments the • Is as and budget signicant this focus descended 120 resources for such dark as the Euclid Universe mission continues to for towards • on Earth future, will, we the new The rise to of technology life for many that people. at If some time in humankind’s the distant descendents future, are to become exist must be able to travel to distant stars in and planets. against: money and could be medical are suffering the world. If money is from to worthwhile the This example It is better rather scientic both offers improving for • map be give quality more care usefully to the spent many providing millions of food, people hunger, homelessness and disease who around the researching to will the probe scientists arguments into to well process. are important deserves ASI of among projects, than available There As Huygens shared current continue undertake. it is more The and therefore area. for, be to allocated invest the immediate the quality to than fund Sending a life great rocket research • Is information • calculated • showed the of for deal all into should research, resources possibility concentrating space the a on limited not gained funding a is is much more medical saving lives research. and sufferers. small space be of some of it into diverse into one expensive, research expensive thus funding priority. really worth the cost? the planned. for: fundamental Why Many Agency). important it and Universe. Understanding • an Titan. discovered (involving limited investing the of a can called interesting and (the Aeronautics America) Space information worldwide), research, geometry back Italian Saturn, Saturn community. have that the about of sent – information Energy institutions All • a released surface. entire Italiana research improve impossibility. shelter (Agenzia whole to • Space a data. jointly National as Saturn Arguments European fundamental, researched. eventually colonize The most being around produce the humankind fundamental this Earth of for properly All an for one may • published, It areas being international resources. international that are there the nature of philosophical we the Universe questions sheds light on like: here? (intelligent) life elsewhere in the Universe? current obSerVationS 1 Three recent in detail of the scientic have experiments together Universe. added Particular a that great have deal experiments to of studied our note the CMB NASA ’s Cosmic • NASA ’s Wilkinson Background • ESA ’s Explorer Hubble constant to be 67.15 km s 1 Mpc that their results were consistent with the Big Bang include: and • the understanding specic ination theories (COBE) • showed the Universe to be at, Ω = 1 0 Microwave Anisotropy Probe (WMAP) • Together Planck these space observatory. experiments have: In calculated the 23% matter summary, matter • mapped the anisotropies of the CMB in great detail and discovered 200 many • that million scientists calculated years the years the had age rst after generation the Big previously of the of Bang, stars much to shine earlier did and Universe current dark and to scientic energy be 71.4% are composed dark evidence taken into of 4.6% atoms, energy. suggests that, consideration, when the dark Universe: with precision • dark so • is • has a the critical • has an • is than at density that is, within experimental error, very close to density expected Universe as 13.75 ± 0.14 accelerating expansion billion composed mainly of dark matter and dark energy. old O p t i O n D – A s t r O p h y s i c s 213 ib qss – sss 1. This question Wolf about determining some properties of the star 3. a) The spectrum (i) (ii) star Wolf 359 Describe how Calculate toWolf has a this the parallax parallax distance in angle angle of is 0.419 seconds. measured. light-years from evitaler The ytisnetni a) is of light from the Sun is shown below. 359. [4] 1.0 0.8 Earth 359. [2] 0.6 (iii) State used why for the stars method at a of parallax distance of less can only than a be few 0.4 hundred b) The parsecs from Earth. [1] ratio [4] apparent brightness of Wolf _____________________________ 15 is apparent brightness of the 0.2 359 3.7 × 10 Sun 0 0 Show that the 500 1000 1500 2000 2500 3000 ratio wavelength / nm luminosity of Wolf 359 _____________________ 4 is 8.9 × 10 4 . (1ly = 6.3 × 10 AU) Use luminosity of the of c) The surface temperature of Wolf 359 is 2800 K is 3.5 × b) 10 W . Calculate the the radius Outline be By 2. The S = to white diagram onwhich (L a estimate the surface temperature [2] how the following quantities can, in principle, determined from the spectrum of a star. [2] reference neither to of Wolf359. d) spectrum Sun. and 23 itsluminosity this Sun the below the data dwarf shows positions luminosity of of the in nor (c), a the suggest red grid selected why Wolf 359 of an stars [2] HR are (i) The (ii) Its elements present in its outer layers. [2] is giant. diagram, 4. a) shown. speed Explain model how of relative to Hubble’s the the law Earth. supports [2] the Big Bang Universe. [2] Sun.) b) Outline saying one how other it piece supports of evidence the Big for the model, Bang. [3] B A 5 c) 1.0 × 10 The Andromeda about 700 kpc Virgo nebula away at galaxy from is 2.3 is a relatively the Milky Way, Mpc away. If close galaxy, whereas Virgo is the moving 1 3 1200 km s , show that Hubble’s law 1.0 × 10 predicts that Andromeda should be moving away 1 at roughly 400 km s . [1] luminosity L/L s 1 d) 1.0 × 10 Andromeda is in fact moving towards the Milky Way, 1 with a speed discrepancy 1 and of about from direction, the be 100 km s . prediction, How in can both this magnitude explained? [3] 1.0 × 10 e) If light of wavelength Andromeda, what 500 would nm be is emitted the from wavelength observed 3 from 1.0 × 10 4 4 3.0 × 10 Earth? [3] 3 1.2 × 10 3.0 × 10 5. A quasar has a redshift of 6.4. Calculate the ratio of the surface temperature T/K a) (i) (ii) Draw a circle Label this Draw a around circle circle (iii) Draw a line stars that are red this Explain, the circle through without stars that are astronomerscan diameterthan the c) Using the show emitted the light stars that are 6. main the following: calculation, that star B has how a Explain a) Why b) The more jeans from data that and star information A is at a from Mean being size when the quasar detected. [3] massive stars have shorter lifetimes [2] criterion [2] c) How d) How e) The elements distance type 1a heavier than supernovae can iron be are used produced as by standard stars candles [2] [2] the of signicance of observed anisotropies in the about Microwave background [2] Earth. brightness of the Sun = 1.4 × 10 brightness distance of of Sun star from A = 4.9 × Earth = 1.0 AU 10 = 2.1 × f) The signicance g) The evidence h) What of the critical density of universe [2] 2 W m 9 Apparent is its [3] 3 Apparent that to larger Cosmic 800pc universe [1] A. following HRdiagram, any deduce star the HL white W . [1] doing of [1] sequencestars. b) size giants. R. around dwarfs.Label the current 2 W m is for meant dark by matter dark [2] energy [2] 5 1 pc 10 AU [4] 7. d) Explain why determined 214 i B the by distance the of method star of Q u E s t i O n s A from stellar – Earth cannot be parallax. A s t r O p h y s i c s [1] Calculate the critical density for of 1 Hubble constant of 71 km s the universe using the 1 Mpc [3] 17 a P P e n d i x gp Plotting graPhs – axes and best fit The us f reasn t fr identify ltting trends. reresenting the a T grah be in the recise, variatin f it ne rst lace allws us quantity is a that it visual with allws • All • Errr the • A the When ltting fllwing ints grahs, have yu been need t make best-t sure that – it The grah shuld • The scales have a title. the axes shuld If the Smetimes they be – als need a curse, be any sudden r suitable there shuld The inclusin f the rigin uneven has If best-t the ‘jums’ in the be shuld have imrved by the this rigin being been thught abut. can always The nal draw a included missed secnd As – ut. it If is rare in fr dubt a grah shuld, if in either grah withut it if ssible, cver mre best-t a general The axes AND the are The (e.g. crsses are are ‘jins the is a curve, this line is a straight has been drawn as a single line, this has been added WITH rule, there the line shuld as be belw rughly the the same number line. Check that the ints Smetimes are ele randmly try t t a abve best-t and belw straight the line necessary. than half ints that shuld be reresented by a gentle curve. If the was dne then ints belw the line wuld be at the directin. labelled units ints just it. with bth the quantity (e.g. current) wuld clear. better be f at the the curve end, and r all vice the ints abve the line versa. ams). • • line abve beginning • NEVER trend. line. ints this aer line verall grah include t • This the Mst line. Yu added. shw numbers. • t is t RULER. f grahs line there nt, • • trend is key. A f crrectly. arriate. all • f ltted if remembered: smth • been included t • f have are way resect dts’ anther. ints bars Vertical than 45 and hrizntal degree crsses r lines t Any make ints that d nt agree with the best-t line have been identied. dts. The Me a suring intercePt, gradient and are a the gradient tangent f t a curve the at curve any at articular that int is the gradient f int. under the graPh Grahs fr be can be used straight-line used the fr curves intercept, 1. t analyse grahs, as the the thugh well. Three gradient data. many This f things and the the are area is articularly same articularly under easy rinciles the can useful: ∆y graph. P Intercept In general, times. A a grah can straight-line intercet grah can (cut) nly either cut axis each any axis number nce and f ften x it is the y-intercept that has articular imrtance. y-intercet is referred t as simly ‘the intercet’.) If at point P on the cur ve, a ∆y ∆y line = grah has an intercet f zer it ges thrugh the gradient = rigin. ∆x ∆x Proportional – nte that tw quantities are rrtinal if the 3. grah is a straight line THAT pASSES THRoUGH THE Area a grah has t be ‘cntinued n’ (utside under the range area under readings) in rder fr the intercet t be fund. This rcess as extrapolation. The rcess f assuming that the the alies between tw ints is knwn as the x-axis. average grah quantity n is the the rduct y-axis by f the This des nt always reresent a useful quantity hysical trend quantity. line graph straight-line is n knwn a f multilying the a oRIGIN. The Smetimes x ∆x (Smetimes gradient of straight the ∆y ∆x When wrking ut the area under the grah: interpolation. • If the grah cnsists f straight-line sectins, the area can be ex trapolation wrked • If the ut grah by is a dividing curve, the the shae area u can int be simle calculated shaes. by ‘cunting y-intercept the • squares’ The units and fr wrking the area ut under what the ne grah square are the reresents. units n the The line is interpolated The ex trapolation of the y-axis multilied by the units n the x-axis. between the points. graph continues the • If the mathematical equatin f the line is knwn, the area f trend line. the grah can be calculated y 2. gradient value The f divided A • The a by fllwing • rcess called integration y straight-line the increase ints straight-line triangle shuld grah used t has grah in be a the is the x-axis increase in the y-axis value. remembered: cnstant calculate the gradient. gradient shuld be as large x area under graph as x area under graph ssible. The gradient divided • a Gradient The • using only if by the reresent has the x-axis the units. units is RATE n a They the are the measurement at units n the y-axis x-axis. which the f time quantity des n the the gradient y-axis increases. A P P E N D I X 215 gp y m p Yu equation of a straight-line graPh All straight-line grahs can be described using ne the general been equatin y y = and the m mx x + are c the tw variables (t match with the y-axis and x-axis). and c shuld same are bth cnstants – they have ne xed = u y = c if x-axis • c reresents In is sme give a x straight we t intercet t Fr examle, a the y-axis (the value y we see that the hysics mathematical s as t equatin equatin. emhasize the The trlley this as is it v In a lt sme in f the ther rder straight calculate simle rlls = situatin u v has at these are the tw equatins, velcity ging t get n a the yu y-axis straight-line shuld and be the able time t n see the grah. t situatins get line, ther measured a we we straight then variable have line. use the t In will chse either gradient and 20 15 10 20 gradient = + values. exeriment dwn at and a sle. where t are u ur is 2 = 4 ms 5 5 1 mtin exactly link. might measure the velcity 2 3 4 5 f = 0 a has rder mx lt we t the takes grah. direct lt have the f a line. what nce the 0) gradient situatins, carefully case, = the n s m / v yticolev m intercet + + as 1 when • the able belw cmaring that value. changed v By be frm The the equatin initial variables, a that velcity and u describes f are the the time t / s the bject. In cnstants. The cmarisn • c • m (the In this als wrks y-intercet) (the gradient) must must fr be be the cnstants. equal equal t t the the initial velcity acceleratin u a choosing what to Plot to get a examle the grah tells us that the trlley must straight line have With a little rearrangement we can ften end u with started frm rest (intercet zer) and it had a cnstant the 2 acceleratin hysics equatin equatin • f Identify a in which symbls the straight same line. symbls reresent frm as the Imrtant reresent The the • If symbls symbls yu take that that a variables and which Example crresnd crresnd t t x and m reading and and y must be variables c must be cnstants. square it (r cube, and an image etc.) – the result is still a variable f 1 square and t lt this n ne f the Yu can lt any mathematical the 1 n ne axis – this is a is lens are f yur int f by the hysical quantities mass) seed symbls f invlved fr light). gradient frce F that acts n we get an distance image. u and The the fcal equatin. ssible straight–line ways frm. Yu t rearrange shuld check this in that rder all t these get are riginal use the symbls the same. + u = v r Be careful r nt t an u at a 1 1 r 1 = u f 1 - v f cnfuse intercet. bject v = m 1 gravitatinal fllwing distance v The the (e.g. lens bject u with c a the )u + v( these Example r f f many f (e.g. the t 1 uv _ Smetimes frnt variable. v • in related axes. cmbinatin still v = v algebraically readings laced yu it • is distance length There chse 2 bject + culd s cnstants. variable recircal m include u rt, 4.0 mathematical ints If • f r 1 gradient = away frm the centre f a lanet is given by the 1 equatin gradient = f GMm _ F f = where M is the mass f the lanet and the 2 r m is mass f the bject. uv v = 0 If we lt frce against distance we get a curve (grah 1). intercept = –1 GMm ____ We can restate the equatin as F = + 0 and if we lt F 2 r 1 y-axis and n the x-axis we will get a straight-line 2 r u the 1 n (grah2). 1 intercept = F F ecrof 1 A 2 f gradient = –1 A gradient = GMm B 1 B C v C distance r I intercept = 0 2 r 216 A P P E N D I X gp y – m hl logs – ba se ten and ba se Power l aws and logs Mathematically, Thus if ln n (l) we lt the ln (T) x-axis n we the will y-axis get a and straight- (log – log) line grah. b If a = 10 When a Then lg (a) = an wer exerimental law be abslutely is ften nly invlves ssible recise lg (a) = it int straight-line frm a them. But we dn’t lgs. the base. We can have use any Fr examle, the time t will be equal use be t equal p t a simle endulum, T, is (k) [s k = e ] erid buttn related t its gradient = p 10 length, as will (intercet) ln ‘lg’ T nI have f n intercet b] taking calculatrs gradient The by 10 Mst The t b transfrm [t it situatin l, by the fllwing equatin. number p T that we like. Fr examle we k use 2.0, 563.2, 17.5, 42 r = k l culd and p are cnstants. even intercept = ln (k) 2.7182818284590452353602874714. A Fr but it the values IS cmlex the mst reasns useful this last number number t use! It lt f is the nt variables clear f k will frm and p give this a curve, curve wrk ut what t be. In l on plt is given the symbl e and lgarithms t f this, if we d is, we can nt knw what this base are called logarithms. The lgarithms ln is natural symbl (x). This fr is value natural als n values = The e ln (p) werful means that = q nature we lt a calculate straight-line have f fllwing erid) versus (length) gives a straight-line grah the grah. Bth the gravity frce are inverse-square frce and the electrstatic relatinshis. This 2 means The that same generate lgarithms the (time the frce technique a ∝ (distance can straight-line be aart) used . t grah. ecrof Then t nt sdnoces / T q p p mst calculatrs. If f ln the ln t f k force = rules 2 (distance apar t) l / metres ln (c ln (c ln (c × d) = ln (c) ÷ d) = ln (c) + ln (d) ln (d) Time n ) = n ln (c) ) = -ln (c) erid versus length fr a simle endulum distance apar t The ‘trick’ is t take lgs f bth sides f 1 These c natural all have been lgarithms, lgarithms The be the rules int used f t exressed but they whatever lgarithms exress the is sme fr wrk equatin. used fr fr natural all The lgarithms belw but whatever base. that equatins lgarithms, have wuld the )ecrof( gol ( ln wrk base. p they ln (T) = ln (k l ) ln (T) = ln (k) + ln (T) = ln (k) + can intercept = log (k) gradient = -2 p ln (l ) relatinshis log (distance apar t) (articularly wer exnentials) means with A that amunt 2 scale each 3 be frm. ltting This grahs This is scales. y increases by the nw equatin (l) = c in fr + the a same straight frm as the line mx Inverse and same square lg-lg relatinshi – direct lt lt time. 4 5 6 7 8 9 10 11 lgarithmic scale increases by examle, the cunt rate R at R Fr A ln and straight-line will lgarithmic nrmal 1 in we laws p any the given time t is given by the equatin R 0 same rati all the λt time. R = R λt R = R 0 e e 0 0 10 1 2 10 3 10 10 R and λ are cnstants. 0 If 1 10 100 we take lgs, we get 1000 λt ln (R) = ln (R e ) 0 t λt (R) = ln (R ln (R) = ln (R ln (e λt ln ) ) (e) 0 (log – line ar) ln lgarithms + 0 e xPonentials and logs Natural ) )R( nl ln are very (R) = ln (R imrtant ) λt [ln (e) = intercept = ln (R gradient = because many exnential. imrtant natural rcesses Radiactive examle. In decay this are is case, an This fr the taking f lgarithms can a equatin fr t a be cmared straight with the λ equatin c + grah mx t allws with if we lt ln (R) n the y-axis and t the n equatin cmared straight-line = Thus the be nce y again ) 0 1] 0 the x-axis, we will get a straight line. line. Gradient Intercet = = - λ ln (R ) 0 A P P E N D I X 217 Answers Topic 1 (Page 8): Measurements and uncertainties Topic 9 (Page 104): Wave 2 1. (a)(i) 0.5 × acceleration down the slope (a)(iv) 0.36 phenomena λ 1 ms 1. B 2. (b) 27.5 m s 3. (a) 0.2°; 4. (a) (i) zero; (ii) π or ; 2 2 2. C 3. 6. (b)(i) D 4. D 5. (b) 2.4 ± 4 Topic 3; 2 (b)(ii) (Page 2.6 24): 0.1 s (c) 2.6 ± 0.2 10 ms (iii) zero; (b) 110 3 10 nm; 5. 19 Nm (d) Mechanics (ii) Topic 5.0 10 × (i) 1.5 × 10 m; J; (a)(ii) 2 10 (Page (b) m s 111): Fields 11 1. C 2. D 3. B 4. B 5. (a) 520 N; (b)(i) 1.2 MJ; (b)(ii) 270 W 1. A 2. C 1 6. (a) equal; 7. (c) 3.50 (b) left; (c) 20 km hr 3. C 4. (a)(i) 1.9 × -1 10 12 ; (e) car driver; (f) No 2.2 × 7.7 km hr (a)(iii) 2 10 J; (c) 2.6 hr 5. (b)(i) 2.5 m s N Topic 11 (Page 120): Electromagnetic induction 4 Topic 3 (Page 32): Thermal Physics 1. D 3. B 4. B 5. D 6. (b) 0.7 v 7. (a) 7.2 × 10 C; (b) 2.9 3 1. B 2. width D = 3. 5m, D 4. D 5. temp = 25 (a) °C; (i) length (a)(ii) $464; = 20 (b)(i) m, depth 84 = 2 m, × 10 s; (c)(ii) 5CR = 3.5 s; (c)(iii) No days Topic 12 (Page 130): Quantum and nuclear 1 6. (a)(i) 7.8 J K mol 1 1. C 2. B 3. (b) ln R & t; (c) Yes; (e) 34 Topic 1. C 4 2. (Page C 3. 50): (a) Waves 5. longitudinal (b) (i) 0.5 m; (ii) 0.5 (b)(i) 6.9 Option 330 m 0.510 ×10 Js; (b)(ii) 3.3 ; (h) 1.85 hr 4 ×10 J 6. 4.5 ×10 Bq A (Page 151): relativity 7 s 4. (c) (i) 2.0 Hz; (ii) 1.25 (1.3) cm; (f) (i) 4.73 ×10 m; 19 2. (ii) hr 19 mm; 1 (iii) 0.375 mm 5. (a)(i) 1.40c; (a)(ii) 0.95c; (c) 6.0 × 10 J 3. a) 2 yrs; 45° b) 4 yrs ; c) x = 5 ly; d) 0.5 c 4. (c) front; (d) T:100 m, S:87 m; 2 Topic 5 (Page 64): Electricity and magnetism (e) T:75m, S:87 m; 5. (a)(i) zero; (a)(ii) 2.7 m c ; (b)(i) 0.923 c; 0 15 1. C 2. A 3. (c) (ii) 7.2 × 2 10 m 2 s (c) (iv) 100 v 4. (d) B; (b)(ii) 2.4 m c 2 ; (b)(iii) 3.6 m 0 (e) (i) Equal; (ii) approx. 0.4A; (iii) lamp A will have 6 (Page 68): Circular motion and gravitation A 2. A 3. C 4. (a)(ii) No; (b) 1.4 m a) 300 agree. B 0 (Page 170): Engineering 0.95 J; N (d) m; b) 500 J; 25.2 (e) J; c) 500 J; 13.4 (f) N physics 3. 150 J; (a) (g) No; (b) 16% Equal; 4. (b) (c) 990K; (c) M _ 1 1. (c) dissipation; 2. Topic ; greater Option power c s 5. (b) (i) g = G ; (i) 1; (c) (ii) 2 & 3; (c) (iii) 3; 6. Laminar (R=1200) 7. (a) 2Hz; 2 1.9 × R M _ 27 (b)(ii) 10 kg 6. (a) g = G 24 ; (b) 6.0 × 10 (b) kg; 21 mW 2 R Topic 1. B 7 (Page 2. D 81): 3. fundamental; A Atomic 4. (iii) 3 D 5. quarks nuclear B 6. or 3 7. uu[π (a)(i) 2 ] 8. (b)(i) 12 (a) 12 C → (ii) (iv) + electron a quark 24 Mg → is 1. and an (a) C 14 (b) 24 (c) 4.5 (Page cm cm 189): behind behind Imaging mirror, diverging virtual, lens, upright, real, magnied inverted, (×2); magnied (×3); 4 Na 12 Option physics + 11 He cm behind second lens, real, upright & diminished (0.25) 2 0 N 6 uud; 26 H 1 9. particle antiquarks; 0 antiquark; and + +ν ; β 7 (b)(ii) 11600 years; 10. (a)(i) 3; 2. (d) upside down; 5. (a) 1 MHz; 6. (b)(ii) (e) 60 cm; 4. (a) – 10 dB; (b) 0.5 mW 1 19 (b)(i) 1.72 Topic 8 × 10 (Page 11. 94): A Energy (c) 15 MW (d)(i) 20% 4 mm; 9.3 mm; (b)(iii) d = 38mm, l = 130mm production (b)(iii) 1. →20 4. (a) 1000 (b)(iv) 18.6 mm MW; 1 (b) 1200 MW; (c) 17%; (d) 43 kg s 5. (c) 1.8 Option MW D (Page 214): Astrophysics 7 1. (ii) d = 7.78 4. (e) 499.83 ly, (c) r = 8.9 × 10 m; 3. (a) 5800 K 27 nm 5. 14% of current size 7. 9.5 × 10 3 kg m Origin of individual questions The questions Topic 1: detailed Measurement 1 N99S2(S2) 5 M98SpH2(A2) Topic 2: below 2 and M98H1(5) 6 are all taken from past IB examination Topic uncertainties 3 N98H1(5) 4 M99H1(3) N98H2(A1) M98S1(2) 6 N00H2(B2) 2 M98S1(4) 7 3 M98S1(8) 5 1 3: 2 1 4: (16) 3 N99H1(17) 5 M98 M98S3(C2) 6 M122H2(B2.1) 5: 4 HL2 N03 7 2 10: 11: 6: N10H1(15) Electricity N10S1(7) 5 M08 N98H2(A5) 3 M111H3(G3) 5 N09 HL3 G4 4 N98H2(B4) 5 N01H2(A3) induction 3 N03S2(A3) 4 5 N00H1(31) N98H2(A4) and 3 M98H1(33) 4 M112H1(24) 5 N99H1(34) N04H2(B4.1) 1 magnetism 12: Quantum N10H1(34) 2 and nuclear M01H1(35) 3 physics N00H2(A1) 2 motion and M111H1(4) 3 2 gravitation M101S1(8) 4 SpS3(A3) 6 N05H2(B2.1) – part A relativity M111H3(2) 4 M00H3(G1) 5 N01H3(G2) 6 M092H3(3) M1112(A5) question – sections B Engineering physics (d) N01H2(B2) 4 N98H2(A2) (g) Option Topic 7: Atomic, nuclear and particle N98S1(29) 2 M99S1(29) 3 8 M99S1(30 M98S2(A3) 9 4 M99S2(A3) 10 t o q u e s t i o n s D M03H3(D2) Astrophysics M99H2(B4) 1 A n s w e r s 5 M98SpS1(29) M122H1(32) 218 imaging N00H3(H1) Option M98SpS1(30) C physics 2 11 phenomena 2 Electromagnetic 6 3 5 M98SpS3(C2) Fields 1 Option 1 4 Q2.2 Circular 1 to M98SpS3(C3) M091S2(A2) Option Topic Wave N10H1(24) Topic Topic 9: N01H1(24) 3 Sp2(B2) Waves M01H1(14) production 5 3 Physics N99H1 M112H2(A5) Topic IB. M99S3(C1) Topic 6 Energy © M091S2(A2) Thermal N99H1(15) all 2 Topic Topic 8: are NO1S3(C1) 1 M101S2(A2) and 1 Topic Mechanics 1 papers M101H3(E1) 2 M111H3(E2) 3 N01H3(F2) 4 N98H3(F2) Index Page numbers in italics refer to question sections. A galactic absolute magnitude 194 absolute uncertainties absolute zero absorption 69 gases 9, 14, acceleration, during equations 34, experiment uniformly acoustic addition air alpha free-fall motion 11 178 187 90 alternating coil red 72 72, current rotating ac in bridges losses in the eld transformer of energy atomic physics atoms 26 mass power 115 183 39, impulse magnication angular momentum conservation 157 of 177 157, 165 angular series barium meals momentum 77 spectra 69 77 124 base becquerels 73 antineutrinos units 78 194 beta 164 scale 25 variables 198 reaction 76 Chandrasekhar charge coefcient 185 30 196 198 limit 3 Big capacity 60 law 51 54 acceleration Charles’s law chemical energy 22 units 190, (AUs) [RC] capacitor charging investigating circuit Universe astrophysics research model 213 194 parallel series 165 of circular the Bernoulli 198 equation and 208 213 212 Universe 72, shift Bohr Boyle’s 201 211 Brackett motion rectication 116 circuits 57 smoothing circuits motion 67, nucleon 76 41 196, 194 200 radius 150 of the atom 31 series 49 124 a time period vertical 66 plane 66 65 of of law circular circular of motion motion universal 65 65 gravitation 66 23 190 communications coaxial wire 184 cables bres pairs complex 184 184 184 numbers composite 123 in 79 comets optical conditions 68 and 68 radians colour 90, 65–7, circular Newton’s per 57 56 velocity collisions 150, circuits circuits mechanics 195 law and mathematics radiation model boundary 118 119 56 angular 75 energy holes circuits circuits diode-bridge divider examples 129 45 birefringence blue 165 72 Schwarzchild models observations equation model black-body discharge circuits potential sensor energy binding black principle mathematical the 204 201 variables energy 193, 92 experimentally rectication effect binoculars accelerating cosmological 191, 214 (CFCs) 55 capacitor 209 electric 31 73 178 and 145 73 73 decay Bang binding 200 51 116 radiation beta 190 of 163 60 2 Bernoulli principle 117 capacitor 163 charge 166 magnitude current engine 185 79 applications 48 parallel 92 theorem Coulomb’s 60 Bernoulli 129 and charged 118 119 163 Carnot 186 matter batteries Cepheid in circuits circuits 92 Carnot charge 123 78, 210 future model 123 count baryons 177 Bang cycles principles coefcient baryonic size astrophysics Carnot particle distortion anisotropies dark 69, xation chain radiation Balmer angular astronomical discharge series mathematics 81 atomic constant motion Big 77, atomic of dioxide carbon current angular assumptions in stored carbon circuits barrel 157 Archimedes’ energy Cepheid 129 matter background angular antiparticles charging Celsius 148 183 background 48 angular asteroids 207 shifts B amplitude antinodes [RC] capacitor chlorouorocarbons ampliers antimatter 117 116 capacitor cells 77 attenuation Avogadro 209 56 63 apparent 69, of spectra matter 200 levels for 190–1 195 model atomic 114 electrical sequence 193 frequency attenuation operation main dark supernovae atomic 114 transmission amperes of attenuation values ammeters spectra explanation power and stellar structure of criterion 199 parallax clock 114 72 capacitors the Universe stars atomic – 115 transmission the evolution evidence magnetic Jeans 196 off stellar 54 115 RMS C capacitors the stellar atomic generator diode – curves 127 a factor 119 in giant types decay scale 192 fusion rotation 16 radiation stars 41 210 cosmic 206 objects 5 alpha 164 capacitance nucleosynthesis angular accelerated resistance albedo motion 13 impedance law buoyancy 194 nucleosynthesis determine doublets Universe and Brewster’s 197 205 152 acceleration of nuclear displacement harmonic uniform to 10 and 95 acceleration the law diagram cancer nature graphs velocity of of luminosity 108 simple [SHM] 202 203 92 acceleration-time achromatic history Hubble’s spectra acceleration 5 29 greenhouse motion Hertzsprung–Russell 125 particles compression 14, 78 16 I n d e x 219 compression concentration conduction conductors quantities of temperature constant volume constellations constructive 29, 190–1 interference continuous waves convection 40, 47 division 69 35 converging lenses lenses Copenhagen 173 173 density cosmic microwave parameter radiation uctuations 125 212 background (CMB) factor scale 210 dark scale and Coulomb’s coulombs couples temperature on the cosmic 208 speed drift velocity density and 45 211 tomography) scans 186 54 of the 168 energy of scale dark 204, gravity 212 on the cosmic 212 WIMPs and other theories 209 Davisson De and Broglie destructive basic 122 waves 35 of elastic collisions elastic potential elds light energy 52, Davisson Germer diffraction grating explanation multiple-slit single-slit diffraction of uses of of diffraction gratings with white 220 gratings 115 I n d e x 99 in of 46 101 light types and an and electric energy electrical energy 22 electrical meters 56 51–60, for work stars 22 22 192 22 energy 143 momentum energy and energy of in eld elds 53, 53, a 52 energy production power warming and primary 109 metal wind Coulomb’s law 51 55 54 sources 87, energy power 83 sources 88 91 transfer and other 89 technologies 83 energy difference of and 53, Kirchoff’s and electric 109 circuits 59 60 and and parallels electromagnetic force electromagnetic induction current 56 71 112–19, 120 power engineering charge 119 capacitor discharge law of force 112 83 22 152, 170 166 examples 155 thermodynamics uids at rest uids in motion 161 164 – oscillations Bernoulli and effect 165 resonance 168–9 engines rotational (emf) density 88 examples equilibrium second and second inertia 118 electromotive – 83 83 89 physics Newton’s capacitor energy transformations heat 117 and 35, 83 sources sources energy forced 114–15 energy energy sources energy transfer Bernoulli sensors energy energy wind laws cells of non-renewable specic 58 capacitance 88 85–6 energy sources rst alternating 87 technologies 90 renewable 52 series 92 power energy comparison resistance in 84 88 energy and divider production developing power thermal 54 82 82 93 effect power 94 production conversions fuel solar 162 82–93, power secondary 109 64 use 48 degradation new 57 induced and energy energy nuclear electric conduction resistivity 99 ow energy greenhouse 132 potential example 1 of hydroelectric electric electric resistors diffraction diffraction bridges 122 46 diffraction and 110 difference internal 97 diffraction electric potential potential experiment 97 diode 122 101 99 signicance resolvance experiment 22 78 energy energy fossil electric potential resolution diffraction of 97 51 69 of of radiation potential and practical difference electric and examples elds elds diffraction electron between current 46 range global elds electric 46, 22 between electric observations 16, energy 22 electrical 61 circuits 47 128 90 energy electric 40, 121 23 2 117 14, particles spectra wave 22 charge interference 200 experiment potential conservation 115 model electricity 113 144 electric material diffraction 122 relative 53 relativistic 14 units dielectric experiment hypothesis deformation derived Germer emf electrons electrostatic mass currents electrical by 125 concepts 191 emf pressure force energies, 20 representation 212 induced 112 electrostatic emission 54 89 60 112 of scattering elementary 53 209 MACHOs, 102 191 energy energy factor matter 102 190 magnetic dark nuclear energy friction comparison effect effect 54 comparison D dark Doppler 190 electric 113 circuits 77 electronvolts 103 102 gravitational damping 103 applications equation planets Einstein (computed 175 E eddy 154 current drift efciency critical broadening earthquake 51 53 angle lens electrons emissivity year emf 37, (emf) degeneracy orbital source day 212 principle law critical CT energy factor cosmological diverging 175 16 Earth of rays 203 factor induced production 102 moving dynamic 210 effect by observer dwarf CMB motion electron important moving drag 73 in displacement waves involving mathematics interpretation cosmic scale 54 172, and harmonic 175 and effect law smoothing force motion created examples current Faraday’s and transformer-induced Doppler 89 conventional velocity 5 Doppler and electromotive lenses images 165 law electromagnetic 34, denitions spectrum 60 95 diverging continuous rectication 116 simple [SHM] 29 Lenz’s 116 183 during 160 rectication 54 characteristics acceleration, 22 29 equation diode-bridge experimentally current discharge 126 energy constant cosmic 54 dispersion pressure cosmic circuit direct electrons constant convex investigating 42 51 conservation continuity 35 solutions 89 conduction conjugate waves of heat law pumps – 163 moment of 156 dynamics law of 157 thermodynamics and entropy solving 162 ideal rotational thermodynamic problems systems 158 and concepts 159 translational and equilibrium translational rotational 154 and rotational motion density 112 ux linkage 113 ux losses forces entropy an gas 160 162 equilibrium hydrostatic equilibrium translational and equilibrium equipotentials of bending to eld principle of 106 light lines estimation 146 6 free-fall exchange particles excited state exponential of 78 78 point 129 113 application and Feynman bre Faraday’s coils diagrams 105, moving 105 elds lines 106 energy and 107 108 and propagation uniform electric] eld strength Galilean dynamic affecting 110 gases 49 friction of of uid resistance rest 13 curves of buoyancy and Archimedes’ principle 164 denitions of density and pressure 164 of equilibrium principle variation of uid motion Bernoulli 165–6 164 107 107 shift support 22, 107 108 gravitational red 148 of gravity dark energy dark matter of 155 212 212 gravity greenhouse effect greenhouse gases on 92, spacetime 149 93 92 simulation half-value 30 heat investigations gases model gases of an 30 ideal gas heat ow heat pumps and 146 as a whole to the positioning 163 measuring heat matter heat capacity from systems lenses 148 latent capacities 27 heat 28 27 principle uncertainty 126 principle 126 Hertzsprung–Russell and heat capacities and uncertainty estimates 149 43 mirrors of of Heisenberg relativity 163 25 specic specic universe of 159 engines 31 73 optics 26, 185 49 heat phases general experimentally 74 thickness methods 78 relativity geometry 29 92 real half-life 74 72 and 74 investigating 29–30 gases geometric 78 74 example 131 transformation of global 148 71 half-life 209 applications 164 pressure 165–6 effect 164 67 147 hadrons 131 state counters general hydrostatic and 16 red harmonics bosons Geiger 34 H 203 202 208, Galilean molecular gauge 202 26 laws ideal galaxies galaxies greenhouse 164 strength 14, energy effect observations radiation 25, gas eld gradient 205 215 110 potential 2 transformations equation 16 electric potential gravity t [SHM] gravitational 76 experimental uid best gravitational centre fusion and elds potential shift area 11 lensing to and 10 between gravitational 20 units graphs speed 217 158 gravitational 20 factors uncertainty 217 motion force gravitational friction 216 215 axes motion elds evidence equations gamma 76 in 168 121 of gradient logs harmonic escape resonance – gravitational 188 and 10 graph 40 base graph and gravitational 148 straight 217 waves gravitational 13 shifts logs intercept, velocity-time free-fall 168 graphs and graphs gravitational 187 experimental 109 132 elds harmonic uids 142 of ten laws simple 16 of and the rotational determine a 191 failure potential Pascal’s 28, rotation and 105 at 5 frequency and motion [gravitational under 131 frequency distributions potential motion potential uids 14, galaxies base power potential 106 105, potential ssion stations G gravitational rst fusion – measuring 14 frequency nuclear and 84 133, 10 get straight-line representation interference 84 reference frequency ultrasound 110 109 orbital to clock fundamental energy power to 4 71 48 coefcient gravitational equipotentials eld of natural static potential 9, a comparison friction and fuel frequency friction 182–3 compared electric to 113 80 elds fossil Larmor 111 describing electric law forces disadvantages diagrams threshold rotating optics elds of of of graphical mediate 11 atomic 177 law and frame frequency F Faraday’s 154 and logs acceleration 72 73, (torque) plot 216 exponentials experience graphs to displacement-time 14 uncertainties driving far force experiment processes 78 what equation reference free-body 89 bosons 71, transformations inertial exchange choosing plotting fractional 3 evaporation 16 84 energy frames bars 14, 84 146 73 10 line forces that efciency 93 79 tubes 14 fundamental fuels 106 forces forces advantages 106 of 105 of particles causes acceleration-time vectors moment 4 error 154 as the surfaces 93 GM forces fossil 93 mechanisms gluons types 154 equipotentials relationship equivalence 164 rotational 165 93 for possible different measuring 106 equipotential examples 155 warming evidence graphs magnitude examples the 115 fundamental 16 equilibrium errors ideal equation and 14 couples by global streamlines ux 167 done 165 ow, continuity 152–3 viscosity work uid laminar 176 interpretation Higgs bosons 78, diagram 197 200 79 I n d e x 221 Hubble constant Hubble’s law Huygen’s 203 kinetic principle hydraulic 97 systems hydroelectric 164 power advantages hydrogen and hysteresis 87 gas laws gas processes done 29, of 192 constant an ideal gas pressure convex model of aberrations of compound images image diverging bre X-ray 171 in convex intensity magnifying glass equation 177 174 imaging 187–8 techniques 186 165 23 39, 90, of two-source 188 lms equation lens law 22, energy 26, of 47, 98 14, ideal 159 60 experimentally quantities square law resistance 60 of light bending of star circularly of radiation light clock 70 light curves light energy light gates light waves criterion 205 light light moving glass magnication of of mass mass and mass defect years (lys) 191 of monochromatic light of light liquid-crystal light 57 41 mass 41 effect duality displays 122 [LCDs] functions waves Lorentz 217 35 sound waves transformations of effect derivation of from length Lorentz transformation 123 49 scale 222 25 I n d e x 1–7, 9–23, and and power 138 weight and second Newton’s third friction free-fall 13 diagrams 14 19 impulse 23 law of motion law law of of 15 motion motion 17 18 20 21 78, 79 pathways meteorites methane 134 and free-body 9–12 72 190 92 micrometers example 22 16 rst metabolic 134 8 24 Newton’s solid 132 33 Newton’s mesons from 77 122 resistance work Lorentz transformation 194 pipe contraction factor series a 137 Lorentz luminosity in 134 47 88 momentum 217 logarithms 12 193 equations motion 147 202 interference position and 129 shift motion waves mass 42 red galaxies structure forces 198 102 decay matter uid 26 natural of 58 microscopes compound scanning microscopic microscopes tunnelling travelling Kelvin 5 equilibrium 41 75 183 variables power energy 132 light 1 units parallax mechanics 41 143 67 masses measurement light 3 75 matter mean 47 plane-polarized light (LDRs) 1, 152 dispersion Maxwell’s resistors 177 194 energy masses wind 40 177 19 two-source 22 62 41 parabolic 207 35, point 105, magnitude law 62 charge 177 far 1, to 177 size and due 61 angular motion 41 lines angular stellar light-dependent Lyman K 148 11 Lorentz J a gravitational 137 transformation 39 on Cepheid 146 polarized light derivation 136 force exponential bending longitudinal internal magnetic Doppler longitudinal resistance current unied 78 eld 62 a magnifying 63 64 on mathematics number magnetic force range 174 the eld point 178 16, of and 63 14, magnetic material family logarithmic monatomic 174 solenoid magnetic centre 16 liquids 159 an 172, 176 a wires force orders lenses in electric 132 63 currents mass and elds eld parallel Malus’s 172 wave–particle 26 178 78 lepton 61 wire magnitude 113 unpolarized 100 forces determining invariant thin speed 40 interference energy gas 185, 138 172 polarized waves from 175 mirrors magnication partially 89 parallel internal 172, of plane-polarized 51, intermolecular Jeans 173 185 interference isotopes lenses 181 89 insulators inverse in contraction 175 aberration light collisions infra-red internal noise 172, axis leptons and 23 inelastic internal 172 length 172 spherical Lenz’s and 1 principal 175 incompressibility thin 176 182 imaging X-rays impulse mirrors length aberration point lenses formation ultrasonic 179 28 140 curvature focal lift telescopes lens 184 heat Compact 209 between magnetic near of power and dilation transformation length 183 image thin 180 latent 138 time of focal bres formation simple 172 telescopes telescope lenses image radio 59 172 centre linear diverging of range geometry attenuation measuring of chromatic communication optics laws two contraction lenses 171 reecting and converging optical 173 176 formation microscope converging dispersion, lenses 189 astronomical of derivation 178 astronomical channels at 171 171–88, 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D I B S Physics T U D Y G U I D E S 2014 edition Author f o r T h e I B d I p l o m a Ti Kik Csy su ting t pysics Cus Bk , tis cnsiv stuy gui eectively reinforces t ky cncts t tst sybus t Sl n hl (st xin 2016). pck wit ti assessment guidance, it su ts t igst civnt in xs. O xford IB study guides build unrivalled assessment potential. Yu cn tust t t: ● Comprehensively cv t sybus, tcing IB scictins ● rinc all t ky tics in cncis, us-iny t, cementing understanding ● Eectively prepare stunts ssssnt wit visin su t n exam strategies ● Us c n stigtw ngug t suppor t E AL learners mti is snt in cncis cunks, helping students focus Su ting Cus Bk , v wit t IB 978 0 19 839213 2 digtic t bks wn cnging cncts, building understanding How 1 to get in contact: web www.oxfordsecondary.co.uk/ib email schools.enquiries.uk@oup.com tel +44 (0)1536 452620 fax +44 (0)1865 313472