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1st Periodic Test - Math 9

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Republic of the Philippines
Department of Education
REGION - V
SCHOOLS DIVISION OF MASBATE PROVINCE
LANTANGAN NATIONAL HIGH SCHOOL
ARC, LANTANGAN, MANDAON, MASBATE
1ST QUARTER EXAM IN MATH 9
SY 2019-2020
Write A if the statement is true and B if false.
1. The formula in getting the discriminant is b 2  4ac.
2. The factors of 6 is 1 and 6 only.
3. When the discriminant is zero, then the roots are real numbers and equal.
4. We use zero product property in factoring to get the solution.
5. 7 x 2  49  0 is a quadratic equation where the linear term is undefined.
6. When, x 2  9 , the solution is x=3.
7. In perfect square trinomial, you need to get first the factors of the constant term.
8. In getting the standard for quadratic equation, you need to arrange first the terms.
9. x 2  25 , can be solved easily by using quadratic formula.
10. The solutions of any quadratic equation ax 2  bx  c  0 can be determined using the quadratic
 b  b 2  4ac
.
2a
Direction choose the letter of the correct answer.
11. It is a polynomial equation of degree two that can be written in the form ax 2  bx  c  0 , where
a, b, and c are real numbers and a ≠ 0.
A. Linear Equation
B. Linear Inequality C. Quadratic Equation
D. Quadratic
Inequality
12. Which of the following is a quadratic equation?
A. 2r 2  4r  1  0
C. s 3  5s  14  0
B. 3t  7  12
D. 2 x 2  7 x  3
13. In the quadratic equation 3x 2  7 x  14  0 , which is the quadratic term?
A. x 2
B. 7 x
C. 3x 2
D. -14
2
14. In the quadratic equation 3x  7 x  14  0 , which is the linear term?
A. x 2
B. 7 x
C. 3x 2
D. -14
2
15. In the quadratic equation 3x  7 x  14  0 , which is the constant term?
A. x 2
B. 7 x
C. 3x 2
D. -14
2
16. Find the a, b and c in the s  6s  24  0
formula x 
A. a= 2, b= 6, c=24
B. a= 1, b= 6, c=24
C. a= -2, b= 6, c=24
D. a= -1, b= -6, c=-24
17. Find the a, b and c in the x 2  14  0
A. a= 1, b= 14, c=0
B. a= 1, b= 1, c=4
C. a= 0, b= 0, c=14
D. a= 1, b= 0, c=14
18. Which of the following is in standard form?
A. 5 x 2  2 x  6  0
B. 5 x 2  x  3
C. x 2  3 x  4
D. 2 x  6  5 x 2
19. The following are the values of a, b, and c that Edna and Luisa got when they expressed in standard
form. 5  3 x  2 x 2 in standard form.
Edna: a=2 ;
b=3 ; c= -5 Luisa a= -2 ; b= -3 ;c= 5
Who do you think got the correct answer?
A .Edna
B. Luisa
C. Both
D. None of them
2
20. What is the value of x if x  36 ?
A. -6
B. +6
C. -6, +6
D. none of the above
21. Which of the following is true?
I. If k > 0, then x = k 2 has two real solutions or roots: x =  k
II. If k = 0, then x= k 2 has one real solution or root: x =0 .
III. If k < 0, then x = k 2 has no real solutions or roots.
A.I and II only
B. I and III only
C. II and III only
D. I, II and III
2
22. What is the value of x if m  81 ?
A. -9
B. +9
C. -9, +9
D. none of the above
23. x + 7 = 0, by zero-product property x=_____?
A. 7
B. -7
C.0
D. Undefined
2
24. What are the roots/ solutions of this x  100  0
A. 10, - 10
B. 10
C. 100
D. -100
2
25. What are the roots/ solutions of this x  9 x  14  0 by factoring
A. x  7, x  2
B. x  7, x  2
C. x  7, x  2
2
26. What are the roots/ solutions of this x  7 x  6  0 by factoring
A. x  6, x  1
B. x  6, x  1
C. x  6, x  1
D. x  7, x  2
D. x  6, x  1
27. What is missing to make the quadratic equation x 2  12 x  ___  0 perfect square?
A. 12
B. 24
C. 36
D. 48
28. What is missing to make the quadratic equation x 2  32 x  ___  0 perfect square?
A. 24
B. 124
C. 200
D. 256
29. Mina wants to get the sum of the roots, she gets the values of a, b and c what process will she do
next?
b
b
A. substitute the values of a and b to
C. substitute the values of a and b to
a
a
c
c
B. substitute the values of a and c to
D. substitute the values of a and c to
a
a
30. When the discriminant is negative, then the nature of the roots are ________________.
A. real, equal and one solution
C. real, irrrational, not equal and two solutions
B. real, rational, not equal and two solutions
D. no real roots
31-37. Find the missing to make the equation
by completing the square correct.
x 2  6 x  5
(31) 5  ____
(32)
x 2  6 x  ___
6
(34)
(33)32  ____
 ____
2
x  32 (35)
____
x  3  2
x32
x  3  2
x23
x  2  3
x  (37)
___
x  (36)
___
38-42.Find the missing to make the equation correct.
x 2  6x  7  0
x



 b  b 2  4ac
2a
6  (6) 2  4(1)( 7)
2(1)
6  ____
(39)
(38)  _____
2
6  (40)
_____
2
68
2
6  8 ___ (41)
x1 

 ___
2
2
6  8 ___
(42)
x2 

 ___
2
2

43-44. Graph the quadratic function.
y=x2+ 1
x
-3
-2
-1
0
1
2
3
y
10
5
2
1
2
5
10
45-50. Transform the equation to standard form
a.
3𝑥 2
4
+
2𝑥
3
=5
b. (x+3)2 + (x-2)2 =5
c. 2x(x- 4)= 12
Prepared by:
Noted:
JANINE JOYCE D. RANA
Teacher I
JOEL M. LUPANGO
TIII/TIC
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