SAC 3 HOMEWORK PREPARATION – COMPONENT 0 Contents covered: Linear combinations of random variables and hypothesis testing. BACKGROUND INFORMATION ON CANE TOADS https://australian.museum/blog/amri-news/canetoads-mammal-declines/ (July 2022) Cane toads were introduced in Australia, in North Queensland, in 1935, in order to control the cane beetle which destroyed sugar cane crops. Cane toads are native to South and Central America. In Australia, they have no predators and are a threat to native species. They are hardy and adaptable, and it is understood that their numbers grew from 102 to an estimated 200 million in 2020. They are an invasive species which destroys the native ecosystem, typically devastating local native predators by 90% within a few months of arrival, and their habitat expands at a rate of around 50km per year. For more information, refer to • https://www.wwf.org.au/news/blogs/10-facts-about-cane-toads#gs.xpptpb • https://www.dcceew.gov.au/environment/invasive-species/feral-animals-australia/cane-toads • https://www.biorxiv.org/content/10.1101/344796v1.full • https://pestsmart.org.au/toolkit-resource/methods-for-the-field-euthanasia-of-cane-toads/ • https://www.canetoadsinoz.com/ https://www.business.qld.gov.au/industries/farms-fishing-forestry/agriculture/landmanagement/health-pests-weeds-diseases/pests/invasive-animals/other/cane-toad The numbers used in this SAC try to be realistic but should not be considered a true reflection of the actual numbers, which differ according to location and time. MLC – 12 SM – UNIT 4 – SAC 3 -2022 – COMPONENT 0 1 PROBABILITY DENSITY FUNCTION; MEASURE OF CENTRE AND OF SPREAD. A random variable X has a probability density function given by 1 2 ππ(π₯π₯) = οΏ½9 (4π₯π₯ − π₯π₯ ) ππππ 0 < π₯π₯ < 3 0 ππππβππππππππππππ a) Find its expected value (=mean) b) Find its variance. c) Find its standard deviation. d) Find Pr(X≤ 2) MLC – 12 SM – UNIT 4 – SAC 3 -2022 – COMPONENT 0 2 LINEAR COMBINATION OF RANDOM VARIABLES 1 1. Let πποΏ½ be such that πποΏ½ = ππ (ππ1 + ππ2 + β― . ππππ ) where the random variable ππ1 is distributed with mean μ and variance ππ 2 and the random variables ππ2 , … ππππ are independent and identically distributed to ππ1 . a) Using properties of the expected value E, show that E(πποΏ½)=μ for all ππ∈β b) Find an expression for Var(πποΏ½) in terms of σ and ππ. c) Hence, find an expression for the standard deviation of πποΏ½, π π π π (πποΏ½) MLC – 12 SM – UNIT 4 – SAC 3 -2022 – COMPONENT 0 3 2. The notation ππ~ππ(0,9) means that ππ is normally distributed where E(X)=0 and Var(X)=9. If ππ~ππ(4,1.5), describe the distribution of 2X+5Y. CONFIDENCE INTERVALS 1. Let X be a random variable with mean μ and standard deviation σ, and πποΏ½ the sample mean. The central limit theorem states that, for large ππ, πποΏ½ is approximately normal with mean μ and standard deviation ππ √ππ ππ 2 , that is πποΏ½~ππ(μ, οΏ½ οΏ½ ). Using this in conjunction with the fact that Pr(−1.96 ≤ ππ ≤ √ππ 1.96) = 0.95, derive the expression for the 95% confidence interval (π₯π₯Μ − 1.96 MLC – 12 SM – UNIT 4 – SAC 3 -2022 – COMPONENT 0 ππ √ππ , π₯π₯Μ + 1.96 ππ √ππ ) 4 2. After surveying 30 swimmers as they entered the local sports and aquatic centre, it was found that the average distance they intended to swim was 1.2 km. The sample standard deviation was 0.5km. a) Estimate the average distance people were intending to swim that day. b) Find a 95% confidence interval for your estimate. c) What sample size would be needed to reduce the interval to ±0.1km at the 95% level of confidence. MLC – 12 SM – UNIT 4 – SAC 3 -2022 – COMPONENT 0 5 d) Discuss the effect of the sample size on the confidence interval for a 95% level of confidence. Use mathematical language, notation and/or method to explain and describe the changes observed. e) Discuss how the level of confidence impacts the confidence interval. Use mathematical language, notation and/or method to explain and describe the changes observed. MLC – 12 SM – UNIT 4 – SAC 3 -2022 – COMPONENT 0 6 HYPOTHESES TESTING The drying time for a particular type of paint is known to be normally distributed with μ=75minutes and σ=9.4 minutes. A new additive has been developed that is supposed to change the drying time. After testing 100 samples, the observed drying time is π₯π₯Μ = 71.2 minutes. We are investigating whether the new additive changes the drying time or not. a) State the null and alternative hypotheses. b) Test the claim at the 1% level of significance. c) If π₯π₯Μ = 72.9, what is the conclusion , using πΌπΌ = 0.01? MLC – 12 SM – UNIT 4 – SAC 3 -2022 – COMPONENT 0 7 d) What is the ππ −value if π₯π₯Μ = 72.9? What would the conclusion be at a 1% level of significance? e) What is the significance level α for the test procedure that rejects π»π»0 when ππ < −2.88 or ππ > 2.88? MLC – 12 SM – UNIT 4 – SAC 3 -2022 – COMPONENT 0 8 f) Give an average observed drying time from 100 samples, that would lead to π»π»0 being rejected, using this level of confidence (as determined in e) above). MLC – 12 SM – UNIT 4 – SAC 3 -2022 – COMPONENT 0 9