Uploaded by Michael Owogowog

Lesson 1-Review on Functions and Limits

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Lesson 1-Functions and
Limits
Michael Buenly B. Owogowog
BS Chemical Engineering, Bicol University
Objectives:
• 1. Review functions and their operations;
• 2. Discuss the graphical interpretation of limits;
• 3. Discuss the theorem on limits and apply them to problems.
A. Functions
• When two quantities example x and y are related so
that for some range of values of x, the value of y is
determined by that of x, we say that y is a function of
x.
• 𝑦 = 𝑓(π‘₯)
• For a square with side length c, the area is given by:
2
•π΄ = 𝑐
• Correspondence from a set X of real number π‘₯ to a set π‘Œ of real
number 𝑦 where the number 𝑦 is unique for a specific value of π‘₯
• The set of number π‘₯ is called the domain, while the set of number 𝑦
is called the range
• Can be one-to-one relation or many-to-one relation
A.1.Types of Functions
• Algebraic Functions
• Linear Functions (𝑦 = π‘šπ‘₯ + 𝑏)
• Quadratic functions (𝑦 = π‘Žπ‘₯ 2 + 𝑏π‘₯ + 𝑐)
• Polynomial functions (𝑦 = π‘Ž0 π‘₯ 𝑛 + π‘Ž1 π‘₯ 𝑛−1 + π‘Ž2 π‘₯ 𝑛−2 +
β‹― + π‘Žπ‘›−1 π‘₯ + π‘Žπ‘› )
• Rational Functions (𝑦 =
𝑃 π‘₯
)
𝑄(π‘₯)
• Transcendental Functions
• Trigonometric functions (𝑦 = sin π‘₯ , 𝑦 = cos π‘₯ , 𝑦 =
tan π‘₯ , etc)
• Exponential functions (𝑦 = π‘π‘Žπ‘› , 𝑦 = 𝑐𝑒 𝑛 )
• Logarithmic Functions (𝑦 = 𝑐 log π‘Ž π‘₯ )
• Inverse Trigonometric Functions (𝑦 = arcsin π‘₯ , etc)
• Hyperbolic functions (𝑦 = sinh π‘₯ , 𝑒𝑑𝑐. )
1
1
π‘₯
−π‘₯
• sinh π‘₯ = 𝑒 − 𝑒
; cosh π‘₯ = (𝑒 π‘₯ + 𝑒 −π‘₯ )
2
2
Special Functions
• Piecewise
• 𝑦 =
𝑓1 π‘₯ 𝑖𝑓 π‘₯ ≥ π‘Ž
𝑓2 π‘₯ 𝑖𝑓 π‘₯ < π‘Ž
• Absolute value function
• 𝑦 = π‘₯ = π‘₯2
• Greatest integer function
• 𝑦 = π‘₯
• Signum Function
+1 𝑖𝑓 π‘₯ > 0
• 𝑦 = sgn π‘₯ = 0 𝑖𝑓 π‘₯ = 0
−1 𝑖𝑓 π‘₯ < 0
• Inverse Functions(anti-function)
• 𝑦 = ln π‘₯
• Becomes 𝑒 𝑦 = π‘₯
• Applying the inverse
• 𝑒π‘₯ = 𝑦
• Even and odd functions
• If even, f(x)=f(-x); odd, f(-x)=-f(x)
• Example of even is 𝑦 = 𝑓(π‘₯) = cos π‘₯
• Example of odd is y = f(x) = π‘₯ 3
• 𝑓 −2 = −𝑓 2 = −8
A.2.Operations of Functions
• 1. Evaluation
• Given the function 𝑦 = 𝑓 π‘₯ = π‘₯ 2 + 1, find 𝑓(2)
• 𝑦 = 𝑓 2 = 22 + 1 = 5
1
3
2
• Given the function 𝑦 = 𝑓 π‘₯ = π‘₯ + π‘₯ + + 1, find 𝑓(−1)
• 𝑦 = 𝑓 −1 = −1
3
+ −1
2
+
1
(−1)
π‘₯
+1=0
• Given the function 𝑦 = 𝑓 π‘₯ = cos 2π‘₯ − 2 sin π‘₯, find 𝑓(πœ‹) and
𝑓 π‘₯ − 𝑓(−π‘₯)
• Given the function 𝑦 = 𝑓 π‘₯ = cos 2π‘₯ − 2 sin π‘₯, find 𝑓(πœ‹) and
𝑓 π‘₯ − 𝑓(−π‘₯)
• 𝑦 = 𝑓 π‘₯ = cos 2π‘₯ − 2 sin π‘₯
• 𝑦 = 𝑓 πœ‹ = cos 2πœ‹ − 2 sin πœ‹ = 1 − 2 0 = 1
• 𝑓 π‘₯ − 𝑓 −π‘₯ = cos 2π‘₯ − 2 sin π‘₯ − cos −2π‘₯ + 2 sin −π‘₯
= −4 sin π‘₯
2. Addition and Subtraction: 𝑓 ± 𝑔 π‘₯ = 𝑓 π‘₯ ± 𝑔(π‘₯)
3. Multiplication: 𝑓 • 𝑔 π‘₯ = 𝑓 π‘₯ • 𝑔(π‘₯)
4. Nested function: Circle Operation: π‘“βˆ˜π‘” π‘₯ = 𝑓 𝑔 π‘₯
Example 5-10 minutes
• Given 𝑓 π‘₯ = π‘₯ and 𝑔 π‘₯ = π‘₯ 2 + 1, find
• 1. 𝑓 π‘₯ + 𝑔 π‘₯
• 2. 𝑓 π‘₯ • 𝑔(π‘₯)
• 3.
𝑔(π‘₯)
𝑓(π‘₯)
• 4. π‘“βˆ˜π‘” π‘₯
• 5. 𝑓 𝑔 𝑓 π‘₯
• 6. 𝑓 𝑓 𝑔 𝑔 π‘₯
B.Limits
• Let 𝑓 π‘₯ be a function of x and let a be constant. If there is a number
L such that, in order to make the value of 𝑓(π‘₯) as close to L as may be
desired, it is sufficient to choose x close enough to a, but different
from a, then we say that the limit of 𝑓 π‘₯ , as x approaches a, is L. We
write:
• lim 𝑓(π‘₯) = 𝐿
π‘₯→π‘Ž
• The same idea is conveyed when writing:
• As π‘₯ → π‘Ž, 𝑓 π‘₯ → 𝐿
B.1. Theorems on Limits
• Limit of a constant
• lim 𝑐 = 𝑐
π‘₯→π‘Ž
• lim 𝑐 π‘₯ 0 = 𝑐 π‘Ž
0
π‘₯→π‘Ž
=𝑐
• Limit of a function
• lim 𝑓(π‘₯) = 𝑓 π‘Ž ; 𝑓 π‘Ž πœ–π‘…
π‘₯→π‘Ž
• Sum and difference of limits
• If lim 𝑓1 (π‘₯) = 𝐿1 , lim 𝑓2 (π‘₯) = 𝐿2 … , lim 𝑓𝑛 π‘₯ = 𝐿𝑛 , then
π‘₯→π‘Ž
π‘₯→π‘Ž
π‘₯→π‘Ž
• lim 𝑓1 (π‘₯) ± lim 𝑓2 (π‘₯) ± β‹― lim 𝑓𝑛 π‘₯ = 𝐿1 ± 𝐿2 ± β‹― 𝐿𝑛
π‘₯→π‘Ž
π‘₯→π‘Ž
π‘₯→π‘Ž
• Multiplication of limits
• If lim 𝑓1 (π‘₯) = 𝐿1 , lim 𝑓2 (π‘₯) = 𝐿2 … , lim 𝑓𝑛 π‘₯ = 𝐿𝑛 , then
π‘₯→π‘Ž
π‘₯→π‘Ž
π‘₯→π‘Ž
• lim 𝑓1 (π‘₯) • lim 𝑓2 (π‘₯) • β‹― lim 𝑓𝑛 π‘₯ = 𝐿1 • 𝐿2 • β‹― 𝐿𝑛
π‘₯→π‘Ž
π‘₯→π‘Ž
π‘₯→π‘Ž
• Power of a limit
• If lim 𝑓(π‘₯) = 𝐿, and n is any positive integer, then
π‘₯→π‘Ž
• lim 𝑓 π‘₯
π‘₯→π‘Ž
𝑛
= 𝐿𝑛
• Limits of a sum or difference
• lim 𝑓 π‘₯ ± 𝑔(π‘₯) = lim 𝑓 π‘₯ ± lim 𝑔 π‘₯
π‘₯→π‘Ž
π‘₯→π‘Ž
π‘₯→π‘Ž
• Limits of a product
• lim 𝑓 π‘₯ • 𝑔(π‘₯) = lim 𝑓 π‘₯ • lim 𝑔 π‘₯
π‘₯→π‘Ž
π‘₯→π‘Ž
π‘₯→π‘Ž
• Limits of a rational function
• If lim 𝑓(π‘₯) = 𝐿, lim 𝑔(π‘₯) = 𝑀, then
•
π‘₯→π‘Ž
𝑓(π‘₯)
lim
π‘₯→π‘Ž 𝑔(π‘₯)
π‘₯→π‘Ž
lim 𝑓(π‘₯)
= π‘₯→π‘Ž
lim 𝑔(π‘₯)
=
π‘₯→π‘Ž
𝐿
;𝑔
𝑀
π‘₯ ≠0, 𝑀≠0
• Limits of a radical
• If lim 𝑓(π‘₯) = 𝐿, and n is any positive integer, then
π‘₯→π‘Ž
• lim
𝑛
π‘₯→π‘Ž
𝑓 π‘₯ =
𝑛
𝐿
• Uniqueness Theorem
• If lim 𝑓(π‘₯) = 𝐿, and lim 𝑔(π‘₯) = 𝑀, then
π‘₯→π‘Ž
• 𝐿=𝑀
π‘₯→π‘Ž
Unit circle
https://www.mathsisfun.com/
algebra/trig-interactive-unitcircle.html
Trigonometric Identities
• sin2 π‘₯ + cos2 π‘₯ = 1
• sin(π‘Ž ± 𝑏) = sin π‘Ž cos 𝑏 ± cos π‘Ž sin 𝑏
• cos(π‘Ž ± 𝑏) = cos π‘Ž cos 𝑏 βˆ“ sin π‘Ž sin 𝑏
• tan(π‘Ž + 𝑏) =
tan π‘Ž±tan 𝑏
1βˆ“tan π‘Ž tan 𝑏
The number e as a limit
• lim 1 + 𝑛
𝑛→0
1
𝑛
= lim 1 +
𝑛→∞
1 𝑛
𝑛
•π‘’ = 2.718281828459045 …
=𝑒
Special Limits
sin 𝑑
•lim
=1
𝑑→0 𝑑
1−cos 𝑑
•lim
=0
𝑑
𝑑→0
𝑒 𝑑 −1
•lim
=1
𝑑→0 𝑑
Examples finish in 5-10 minutes
1. lim π‘₯ 2π‘₯ + 1
π‘₯→3
π‘₯
2. lim
π‘₯→4 −7π‘₯+1
π‘₯ 2 −25
3.lim
π‘₯→4 π‘₯−5
π‘₯−4
4.lim
π‘₯→4 π‘₯−2
2π‘₯ 2 +π‘₯−3
5.lim
π‘₯→1 π‘₯−1
1−cos 𝑦
6.lim
𝑦→0 sin2 𝑦
sin 𝑦 sin 2𝑦
7. lim
𝑦→0 1−cos 𝑦
3
Study
• One-sided limits
• Infinite limits
• Limits at infinity
• Limit of trigonometric functions
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