QUIZ 3
For Question 1 and 2
Question 1
FV of A = 600 sin(30) = 300N
FH of A = 600 cos(30) = 519.62N
FV of B = 300 (3/5) = 180N
FH of B = 300 (4/5) = 240N
FV of D = 800N
FH of D = 0N
MC = + (300N x 7m) – (519.62N x 2m) + (180N x 0m) + (240N x 2.5m) + (800N x 2m)
MC = + 3260.76 Nm
Question 2
Clockwise
For Question 3 and 4
Question 3
MA = + (1000N x 1) + (600N x 3m) + (750N x 4m) - (500N x 7m)
MA = + 2300 Nm
Question 4
Clockwise
Question 5
Mo = F x D
Mo = (100lb x 12)
Mo = 1200 lb⋅in
Question 6
Refer to the figure below and compute for moment at point O if F = 57.74 lb. -- (CW+) MO
d = 24 sin (60) = 20.78in
F = Mo/d
F = 1200lb / 20.78in
F = 57.75 lb
Question 7
d = 8 in. + 10 in. = 1.5 ft
M=FxD
M = - (20 lb x 1.5 ft)
M = - 30 lb⋅ft
Question 8
d = 3 in = .25ft
M=FxD
M = - (20lb x .25ft)
M = - 5 lb⋅ft