Uploaded by Hushi Natawaki

Module 3

advertisement
COMPONENTS
FV = F(3/5) = 200(3/5)
FV = 120 KN
FH= F(4/5)=200(4/5)
FH= 160 KN
PV = P(3/√13)=165(3/√13)
PV = 137.29 KN
PH = P(2/√13) = 165(2/√13)
PH = 91.53 KN
MOMENT OF FORCE
MA = F x D
MA = - (120KN x 0.3m) - (160KN x 0.9m) + (137.29KN x 0.6m) – (91.53KN x 0.9m)
MA = + 180.00 KN⋅m
MB = F x D
MB = + (120KN x 1.2m) + (160KN x 0.9m) - (137.29KN x 0.9m) + (91.53KN x 0.9m)
MB = + 246.82 KN⋅m
MC = F x D
MC = + (120KN x 1.5m) + (160KN x 0m) - (137.29KN x 1.2m) + (91.53KN x 0m)
MC = + 15.25 KN⋅m
MD = F x D
MD = - (120KN x 0.3m) + (160KN x 0.9m) + (137.29KN x 0.6m) + (91.53KN x 0.9m)
MD = + 272.75 KN⋅m
Download