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2023-09-04 - Coulomb's Law

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EGR-326 ELECTROMAGNETIC FIELDS
COULOMB’S LAW
SEPTEMBER 4, 2023
DORDT UNIVERSITY
FALL 2023
DR. WYENBERG
SPHERICAL
CYLINDRICAL
CARTESIAN
π‘Ÿπ‘Ÿ
πœƒπœƒ
πœ™πœ™
SPHERICAL
CYLINDRICAL
CARTESIAN
π‘Ÿπ‘Ÿ
𝜌𝜌2 + 𝑧𝑧 2
π‘₯π‘₯ 2 + 𝑦𝑦 2 + 𝑧𝑧 2
πœƒπœƒ
πœ™πœ™
𝜌𝜌
π‘Ÿπ‘Ÿ sin πœƒπœƒ
𝑧𝑧
π‘Ÿπ‘Ÿ cos πœƒπœƒ
πœ™πœ™
tan−1
πœ™πœ™
𝜌𝜌
𝑧𝑧
𝜌𝜌
πœ™πœ™
πœ™πœ™
π‘₯π‘₯
π‘Ÿπ‘Ÿ sin πœƒπœƒ cos πœ™πœ™
𝜌𝜌 cos πœ™πœ™
𝑧𝑧
π‘Ÿπ‘Ÿ cos πœƒπœƒ
𝑧𝑧
𝑦𝑦
π‘Ÿπ‘Ÿ sin πœƒπœƒ sin πœ™πœ™
𝑧𝑧
𝜌𝜌 sin πœ™πœ™
π‘₯π‘₯ 2 + 𝑦𝑦 2
tan
𝑧𝑧
𝑦𝑦
−1
tan
π‘₯π‘₯
−1
π‘₯π‘₯ 2 + 𝑦𝑦 2
tan−1
𝑧𝑧
π‘₯π‘₯
𝑦𝑦
𝑧𝑧
𝑦𝑦
π‘₯π‘₯
SPHERICAL
SPHERICAL
π‘Ÿπ‘ŸΜ‚
πœƒπœƒΜ‚
CARTESIAN
CYLINDRICAL
πœ™πœ™οΏ½
𝜌𝜌�
πœ™πœ™οΏ½
π‘Ÿπ‘ŸΜ‚
πœƒπœƒοΏ½
πœ™πœ™οΏ½
sin πœƒπœƒ π‘Ÿπ‘ŸΜ‚ + cos πœƒπœƒ πœƒπœƒοΏ½
CYLINDRICAL
CARTESIAN
𝜌𝜌𝜌𝜌� + 𝑧𝑧𝑧𝑧̂
π‘₯π‘₯ π‘₯π‘₯οΏ½ + 𝑦𝑦𝑦𝑦� + 𝑧𝑧𝑧𝑧̂
𝜌𝜌2 + 𝑧𝑧 2
π‘§π‘§πœŒπœŒοΏ½ − πœŒπœŒπ‘§π‘§Μ‚
𝜌𝜌2 + 𝑧𝑧 2
πœ™πœ™οΏ½
𝜌𝜌�
πœ™πœ™οΏ½
πœ™πœ™οΏ½
π‘₯π‘₯οΏ½
sin πœƒπœƒ cos πœ™πœ™ π‘Ÿπ‘ŸΜ‚ + cos πœƒπœƒ cos πœ™πœ™ πœƒπœƒοΏ½ − sin πœ™πœ™ πœ™πœ™οΏ½
cos πœ™πœ™ 𝜌𝜌� − sin πœ™πœ™ πœ™πœ™οΏ½
𝑧𝑧̂
cos πœƒπœƒ π‘Ÿπ‘ŸΜ‚ − sin πœƒπœƒ πœƒπœƒοΏ½
𝑧𝑧̂
𝑧𝑧̂
𝑦𝑦�
cos πœƒπœƒ π‘Ÿπ‘ŸΜ‚ − sin πœƒπœƒ πœƒπœƒοΏ½
sin πœƒπœƒ sin πœ™πœ™ π‘Ÿπ‘ŸΜ‚ + cos πœƒπœƒ sin πœ™πœ™ πœƒπœƒοΏ½ + cos πœ™πœ™ πœ™πœ™οΏ½
𝑧𝑧̂
sin πœ™πœ™ 𝜌𝜌� + cos πœ™πœ™ πœ™πœ™οΏ½
π‘₯π‘₯ 2 + 𝑦𝑦 2 + 𝑧𝑧 2
π‘₯π‘₯ 2
𝑧𝑧 π‘₯π‘₯ π‘₯π‘₯οΏ½ + 𝑦𝑦𝑦𝑦�
+
𝑦𝑦 2
+
𝑧𝑧 2
π‘₯π‘₯ 2
+
𝑦𝑦 2
−
π‘₯π‘₯ 𝑦𝑦� − 𝑦𝑦π‘₯π‘₯οΏ½
π‘₯π‘₯ 2 + 𝑦𝑦 2
π‘₯π‘₯ π‘₯π‘₯οΏ½ + 𝑦𝑦𝑦𝑦�
π‘₯π‘₯ 2 + 𝑦𝑦 2
π‘₯π‘₯ 𝑦𝑦� − 𝑦𝑦π‘₯π‘₯οΏ½
π‘₯π‘₯ 2 + 𝑦𝑦 2
𝑧𝑧̂
π‘₯π‘₯οΏ½
𝑦𝑦�
𝑧𝑧̂
π‘₯π‘₯ 2
π‘₯π‘₯ 2 + 𝑦𝑦 2
+
𝑦𝑦 2
+
𝑧𝑧 2
𝑧𝑧̂
PROBLEM 1.27
The dipole field is described as:
Where A is constant, and π‘Ÿπ‘Ÿ > 0.
𝐴𝐴
𝑬𝑬 = 3 2 cos πœƒπœƒ π’‚π’‚π‘Ÿπ‘Ÿ + sin πœƒπœƒ π’‚π’‚πœƒπœƒ
π‘Ÿπ‘Ÿ
a) Identify the surface on which the field is entirely perpendicular to the π‘₯π‘₯π‘₯π‘₯ plane and express the field on
that surface in cylindrical coordinates.
b) Identify the coordinate axis on which the field is entirely perpendicular to the π‘₯π‘₯π‘₯π‘₯ plane and express the
field there in cylindrical coordinates.
c) Specify the surface on which the field is entirely parallel to the π‘₯π‘₯π‘₯π‘₯ plane.
CHAPTER 2 – COULOMB’S LAW AND ELECTRIC FIELDS
An electric charge 𝑄𝑄2 separated from a charge 𝑄𝑄1 by a distance π‘Ÿπ‘Ÿ21 will experience a force:
𝐹𝐹⃗21 =
𝑄𝑄1 𝑄𝑄2
Μ‚
2 π‘Ÿπ‘Ÿ21
4 πœ‹πœ‹ πœ–πœ–0 π‘Ÿπ‘Ÿ21
(Here 𝐹𝐹⃗21 reads “the force on charge 2 by charge 1” and π‘Ÿπ‘Ÿ21
Μ‚ reads “the unit vector pointing in the direction
of charge 2 with respect to charge 1)
CHAPTER 2 – COULOMB’S LAW AND ELECTRIC FIELDS
𝐹𝐹⃗21 =
𝑄𝑄1 𝑄𝑄2
Μ‚
2 π‘Ÿπ‘Ÿ21
4 πœ‹πœ‹ πœ–πœ–0 π‘Ÿπ‘Ÿ21
Graphically, this is perhaps a little clearer. In the case that both charges are the same sign:
𝑄𝑄1
π‘Ÿπ‘Ÿβƒ—21
𝑄𝑄2
𝐹𝐹⃗21
CHAPTER 2 – COULOMB’S LAW AND ELECTRIC FIELDS
𝐹𝐹⃗21 =
𝑄𝑄1 𝑄𝑄2
Μ‚
2 π‘Ÿπ‘Ÿ21
4 πœ‹πœ‹ πœ–πœ–0 π‘Ÿπ‘Ÿ21
If both charges are opposite sign, note that 𝐹𝐹⃗21 points in the opposite direction of π‘Ÿπ‘Ÿ21
Μ‚ :
𝑄𝑄1
π‘Ÿπ‘Ÿβƒ—21
𝐹𝐹⃗21
𝑄𝑄2
But don’t worry; we don’t have to keep track of all this; it’s encoded in the vector formula above.
𝑄𝑄?
CHAPTER 2 – COULOMB’S LAW AND ELECTRIC FIELDS
If the second charge is absent, we can still visualize what force would be caused by charge 1 at each
location in space. It would have a magnitude:
π‘Ÿπ‘Ÿβƒ—?1
π‘Ÿπ‘Ÿβƒ—?1
𝑄𝑄?
𝑄𝑄1
π‘Ÿπ‘Ÿβƒ—?1
𝑄𝑄?
𝑄𝑄1 𝑄𝑄?
𝐹𝐹?1 =
2
4 πœ‹πœ‹ πœ–πœ–0 π‘Ÿπ‘Ÿ?1
π‘Ÿπ‘Ÿβƒ—?1
𝑄𝑄?
𝑄𝑄?
CHAPTER 2 – COULOMB’S LAW AND ELECTRIC FIELDS
Without knowing what charge we will be measuring the force on, we can find the force per unit charge by
dividing by the unknown charge:
π‘Ÿπ‘Ÿβƒ—?1
π‘Ÿπ‘Ÿβƒ—?1
𝑄𝑄?
𝑄𝑄1
π‘Ÿπ‘Ÿβƒ—?1
𝐹𝐹?1
𝑄𝑄1
=
2
𝑄𝑄? 4 πœ‹πœ‹ πœ–πœ–0 π‘Ÿπ‘Ÿ?1
π‘Ÿπ‘Ÿβƒ—?1
𝑄𝑄?
CHAPTER 2 – COULOMB’S LAW AND ELECTRIC FIELDS
𝐹𝐹?1
𝑄𝑄1
=
2
𝑄𝑄? 4 πœ‹πœ‹ πœ–πœ–0 π‘Ÿπ‘Ÿ?1
And then remember that this force field exists everywhere in space; no matter where we place the second
charge, it will feel a force from the first charge
𝑄𝑄1
CHAPTER 2 – COULOMB’S LAW AND ELECTRIC FIELDS
𝐸𝐸?1 =
𝐹𝐹?1
𝑄𝑄1
=
2
𝑄𝑄? 4 πœ‹πœ‹ πœ–πœ–0 π‘Ÿπ‘Ÿ?1
This collection of forces is a force field – specifically, we call it the Electric Field
CHAPTER 2 – COULOMB’S LAW AND ELECTRIC FIELDS
𝐹𝐹⃗?1
𝐸𝐸?1 =
𝑄𝑄?
The Electric Field has a magnitude and a direction at every point in space.
CHAPTER 2 – COULOMB’S LAW AND ELECTRIC FIELDS
𝐹𝐹⃗?1 + 𝐹𝐹⃗?2 + 𝐹𝐹⃗?3 + β‹―
𝐸𝐸? =
𝑄𝑄?
More generally, the Electric Field is the net force on a test charge at a given location. It is caused by every
other charge in the Universe pushing and pulling on the test charge.
Dropping all the messy subscripts, we have:
𝐹𝐹⃗
𝐸𝐸 =
𝑄𝑄
Which reads: “The electric field is defined at every point in space as the net coulomb force per unit charge
at that point in space caused by ALL OTHER CHARGES IN THE UNIVERSE.”
CHAPTER 2 – COULOMB’S LAW AND ELECTRIC FIELDS
An electric charge of +1 C is placed at the origin. What is the electric field vector (both magnitude and
direction) at every point in space in:
a) Cartesian Coordinates
b) Cylindrical Coordinates
c) Spherical Coordinates
CHAPTER 2 – COULOMB’S LAW AND ELECTRIC FIELDS
An electric charge of +1 C is placed at 𝑧𝑧 = +𝑑𝑑/2. Another electric charge of −1 C is placed at 𝑧𝑧 = −𝑑𝑑/2.
What is the electric field vector (both magnitude and direction) at every point in space in:
a) Cartesian Coordinates
b) Cylindrical Coordinates
c) Spherical Coordinates
CHAPTER 2 – COULOMB’S LAW AND ELECTRIC FIELDS
An infinitely long wire has a uniform charge density of πœŒπœŒπ‘™π‘™ = 1 C/m. Orient your axes such that the wire is
along the 𝑧𝑧-axis. What is the electric field vector (both magnitude and direction) at every point in space in:
a) Cartesian Coordinates
b) Cylindrical Coordinates
c) Spherical Coordinates
CHAPTER 2 – COULOMB’S LAW AND ELECTRIC FIELDS
Three electric charges of +1 C each are placed at π‘₯π‘₯, 𝑦𝑦, 𝑧𝑧 = +𝑑𝑑/2 (one charge at each point). An additional
three electric charges of −1 C each are placed at π‘₯π‘₯, 𝑦𝑦, 𝑧𝑧 = −𝑑𝑑/2 (one charge at each point). What is the
electric field vector (both magnitude and direction) at every point in space in:
a) Cartesian Coordinates
b) Cylindrical Coordinates
c) Spherical Coordinates
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