1) Stack design:
Fuel cell function at low voltage → build up the voltage to desired level by electrically
connecting cells in series to form a “stack”
The bipolar plate is used to connect multi-stack.
The Bipolar stack must be relatively impermeable to gases, sufficiently strong to withstand
stack assembly and easily mass produced.
Bipolar plates should be as thin as possible so as to minimize both the electrical resistance
between individual cells and the stack size.
2) Efficiency and OpenβCircuit Voltage
Gibbs free energy:
(2.1)
ΔπΊπ = πΊπ(πππππ’ππ‘) − πΊπ(πππππ‘πππ‘π )
Faraday constant:
(2.2)
πΉ = ππ΄ π − = 96485 πππ’πππππ
Molar Gibbs free energy of formation for water, π»2 ,π2
1
− (ππ )
2
π»2 π
π»2
π2
2π»2 + π2 → 2π»2 π
1
(Derivative from chemical reaction: {
π»2 + 2 π2 → π»2 π
Δgπ = (ππ )
− (ππ )
Table 2.1.
Form of water product
Liquid
Liquid
Gas
Gas
Gas
Gas
Gas
Gas
Gas
(2.3)
Temperature (°C)
Δgπ (ππ½πππ −1 )
25
-237.2
80
-228.2
80
-226.1
100
-225.2
200
-220.4
400
-210.3
600
-199.6
800
-188.6
1000
-177.4
1
Table 2-1: π₯ππ for the reaction π»2 + 2 π2 → π»2 π at various temperatures
For the hydrogen fuel cell, two electrons pass round the external circuit for each water molecule
produced and each hydrogen molecule used. Thus, for each mole of hydrogen consumed, 2ππ΄
electrons pass round the external circuit. Given that each electron carries a unit negative charge
(π − ), the corresponding charge, in coulombs ©, that flows is
(2.4)
−2ππ΄ π − = −2πΉ
Expended in moving this charge round the circuit is
πΈππππ‘πππππ π€πππ ππππ = πβππππ . π£πππ‘πππ = −2πΉπ
(2.5)
If the system is thermodynamically reversible, then
Δππ = −2πΉππ ππ ππ = −
Δππ
2πΉ
(2.6)
Efficiency and Its Limits
The Carnot theorem as applied to a heat engine can be expressed as:
(π1 − π2 )
π
(2.7)
=
Δπ»
π1
For a fuel cell working ideally under isothermal condition, the free change of the reaction may
be converted into electrical energy with a (Maximum) efficiency given by:
πβπππ‘ ππππππ =
ππππ₯ =
ππππ₯ ΔπΊ (1 − πΔπ)
=
=
ΔH
Δπ»
Δπ»
(2.8)
Efficiency and Voltage
If all the energy from the hydrogen fuel, i.e., the heating value, or enthalpy of formation were
transformed into electrical energy, the voltage would then be given by:
ππ
(2.9)
100%(π»π»π)
1.48
In practice, however, it is found that not all the fuel can be used, for reasons discussed later,
some of it usually has to pass through unreacted. A fuel utilization ecoefficiency, ππ can be
defined as:
πΆπππ ππππππππππ¦ =
πππ π ππ ππ’ππ πππππ‘ππ ππ ππππ
(2.10)
πππ π ππ ππ’ππ ππππ’π‘ π‘π ππππ
This parameter is equivalent to the ratio of the current delivered by the fuel cell to that which
would be obtained if all the fuel were reacted. The fuel-cell efficiency, π, is therefore given by:
ππ =
π=
ππ ππ
100%
1.48
(2.11)
Influence of Pressure and Gas Concentration
Nernst Equation
General reaction:
ππ΄ + ππ΅ → ππΆ
(2.12)
Each of the reactants, as well as the product, has an associated ‘activitiy’, which is designated
by the symbol a. For the case of gases behaving as “ideal gases”
π=
π
ππ
(2.13)
Where P is the pressure, or partial pressure, of the gas and ππ is the standard pressure,
namely, 100 kPa.
The activity of a gaseous component in the system can be taken to be proportional to partial
pressure, whereas for dissolved chemicals, the activity is linked to the molarity (‘strength’) of
the solution, which is usually expressed in mol ππ−3. The case of the water produced in fuel
cell is somewhat difficult since this can be as either steam or liquid. For steam, the following
can be written.
ππ»2 π
(2.14)
ππ»π2 π
The activities of the reactants and products modify the Gibbs free energy change of a reaction.
By using thermodynamics principles, for a chemical reaction such as the general example given
(2.15)
ππ»2 π =
π
ππ΄ . ππ΅π
(2.15)
Δgπ =
− π
πππ ( π )
ππΆ
π
Where Δππ is the change in molar Gibbs free energy of formation at standard pressure.
π
Δππ
For the reaction in hydrogen fuel cell, equation (2.15)becomes:
1
ππ»2 . ππ22
π
Δgf = Δππ − π
πππ (
)
ππ»2 π
(2.16)
To see how activity influences the cell voltage, Δππ can be substituted into equation (2.6) to
obtain.
ππ = −
π
Δππ
2πΉ
+
1
ππ»2 . ππ2 2
1
ππ»2 π . ππ2 2
π
π
π
π
) = πππ +
ln (
)
ln (
ππ»2 π
2πΉ
ππ»2 π
2πΉ
(2.17)
It can be assumed that the steam behaves as an ideal gas, and so:
ππ»2
ππ2
ππ»2 π
,
π
=
,
π
=
π
π»
π
2
2
ππ
ππ
ππ
Then the Nerst equation will became:
ππ»2 =
(2.18)
1
ππ = πππ +
π
π
ln
2πΉ
ππ»2 ππ2 2
ππ . ( ππ )
ππ»2 π
ππ
(2.19)
(
)
In nearly all cases, the pressure will be the partial pressure, if the system pressure is P that is:
ππ»2 = πΌπ, ππ2 = π½π, ππ»π = πΏπ
Where πΌ, π½, πΏ are the constants that depend on the molar masses and concentrations of π»2 , π2
and π»2 π respectively. The Nernst equation then becomes:
1
π
π
πΌ. π½ 2 1
ππ = ππ0 +
ln (
. π2)
2πΉ
πΏ
= ππ0 +
1
πΌ. π½ 2
(2.20)
π
π
π
π
ln (
)+
ln(π)
2πΉ
πΏ
4πΉ
Hydrogen Partial Pressure:
Hydrogen can be supplied either pure or as part of a mixture. Isolation of the hydrogen pressure
term in Equation (2.20) yields:
ππ = ππ0 +
1
ππ22
π
π
π
π
ln (
)+
ln(ππ»2 )
2πΉ
ππ»2 π
2πΉ
(2.21)
So, if the hydrogen partial pressure changes: π1 → π2 with ππ2 and ππ»2 π unchanged, then:
π
π
π
π
π
π
π2
(2.22)
ln(π2 ) −
ln(π1 ) =
ln ( )
2πΉ
2πΉ
2πΉ
π1
The use of hydrogen mixture with Cox occurs particularly in phosphoric acid fuel cells (PAFCs)
that operate at about 2000 πΆ(400K). Substituting the values for R, T and F in the equation (2.22)
yields:
Δπ =
π2
(2.23)
Δπ = 0.02 ln ( )
π1
Fuel and Oxidant utilization
Air passes through the cathode compartment, oxygen is consumed→partial pressure is reduced.
For higher efficiency, fuel utilization should be as high as possible. OTH, (2.21) suggest that
high fuel utilization will lead to low average cell voltage or current density.