Introduction to Electricity and Magnetism B38EM Assignment 1 0 = 8.85x10-12 Fm-1, e = 1.6x10-19 C, 1 nC = 10-9 C 1) Gradient of scalar function: Find the gradient of the following scalar function and then evaluate it at the given point. V1 = 24V0 cos (π y/3) sin (2π z/3) at (3, 2, l) in Cartesian coordinates. (3 marks) 2) Calculating the Divergence: Determine the divergence of the following vector field and then evaluate it at the indicated point: E = x^ 3x2 + y^ 2z + z^ x2z at (2, −2, 0) in Cartesian coordinates. (3 marks) 3) Circulation: Given that F = x2ax − xzay − y2az, calculate the circulation of F around the (closed) path shown in the Figure. (3 marks) 4) In a certain region, the electric flux density is given by: D = 2ρ(z+1)cosφ aρ – ρ(z+1)sinφ aφ + ρ2 cosφ az μC/m2. a) Show that the charge density is equal to ρv = 3(z+1)cosφ μC/m2 b) Calculate the total charge enclosed by the volume 0<ρ<2, 0<φ<π/2, 0<z<4. (5 marks) 5) A spherical shell with outer radius b surrounds a charge-free cavity of radius a < b (Fig. 2). If the shell contains a charge density given by 𝜌𝑉 = − 𝜌𝑉0 , 𝑅2 𝑎 ≤ 𝑅 ≤ 𝑏, where ρV0 is a positive constant, determine the electric flux density D in all regions. Fig. 2 for problem 5. (5 marks) 6) Spherical Capacitor: Show that the capacitance of two concentric spherical metal shells with radii a and b is equal to C = 4πε0[ab/(b−a)]. Assume the inner shell has charge +Q and the outer -Q. (3 marks) 7) Consider a straight non-magnetic conductor of circular cross-section and radius a carrying a current with uniform current density J (A/m2) in the vertical direction. Using Ampere’s law find the magnetic field inside and outside the conductor. (3 marks) 皉 1 ⽐ ⼆ 背成⼗奇成⼗器āz 0 8元Vosinwy137Szhl2 元⼄ 右 āy 16元Vows叫6370522E 3 āz Tffsuinōmòtomiinsàz At13,2.1 in Cartesiancoordinatesi 2 TE ⼆碧⼗⼦ at 2 2,0 2 录13加⼗号 答 哥 点位 6Noān 6X10⼗九三 奸60 ㄑ 22⼗ 年6⼤ ⼆⼆⼗6 ㄨ 2 16 TE ⼆九 3 It's a lineintegrationforaclosedpath sofF.dklftftftGJF.de herethepathisdividedintofourpartsasshownin thecoordination as Forpart1 thelineisalongx axis soy zi i.io Forpart2 theline isalongy axis so x ǗǗǗǙǗǗ㲮 1 刈班 0 0 i Forpart3 thelineisparalleltothe planeformed andy 1 F x我 ⼀站 y x axisandZ axis o'lx2dx dz dlidxaxtdz thenbF.dk nnerex z.sodx dz SO that Ǐ GF.dk iindx lIx3 x 6 Forpart4 the line isparadedto theplaneformedbyy axisandtaxis and x 1 F xzag yzd.dk dygtdzc tenfF.dk i zgy2dE wherey Z.sody dz 1 刘三刻到0 so thatheFdnicyysdg 来Fdlr ⼀号 0 ⼀号 t Et Ī Answer thecirculationof Faround pathis to 4 a FTD⼆⼗号PDPt fine 孨⼝ ⽅⾔12 录⼼⽈⼗⽉cosy ⼗录 pig 1cosy⼗⽅ 4Etncosy cztncoc.pt0 3 Z11 cosyt.hn2 b Et17054 dv 皆咨gfǖ pdpdyd .io yofo3pEnwsYdpd4d 3fpdgosydqflz DdZ so thenǗǖǚgeismuc 5 D is radiallyoriented SOWehaveD DRI DRE.Eds 4元⼼DR Gauss'Slaw Q Dds sothat 贩 Qlznz meansQ 0 In Ra thereis nochargeinthecavitywhich so DRE0 12 ateb.QEhiafdvt.fi 器4midr ⼀ 4观 仅⼀ 器 Thus DR⼆ 华顾2 Ra 13 Rob Qtǘapvdtfǎ 4班 b a D a ThusDR Answer 器R ⼀ i a D 器Rami 器 4uidr ⼝ Ā as Rcb 1 4班BIG i C4npu.BE b a成 6 ApplyGauss'slaw to thissphericalsurface Q E Eds EE.at thatis E ⼆ 点 hepotentialdifferencebetweentheinnerandoutersurfaces is V fE.dk 1 畚 ⼼⻔drār 先幻法 吞 六⽅ so that C⼆ thatis C 点 咗彘给⼀⽅ 蕊 4 巺 4元红abkb a when红⾐ thereis C 4硍 abkb a 7 WehavefrmulaE 7ds J.nr EQH.dk Huzur Outsidetheconductor In a I 后起 H r so that Hcr 器 Insidetheconductorco area I J 2 H 2亿 so thatHer⼆歪 AnswerThemagnetic fieldhas ārlocrsa HYE 等 ārlna B P器 ⼀ arlo.rs a ārcrsas