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Assignment 1-Introduction to Electricity and Magnetism

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Introduction to Electricity and Magnetism B38EM
Assignment 1
0 = 8.85x10-12 Fm-1, e = 1.6x10-19 C, 1 nC = 10-9 C
1) Gradient of scalar function: Find the gradient of the following scalar function and then evaluate it
at the given point.
V1 = 24V0 cos (π y/3) sin (2π z/3)
at (3, 2, l) in Cartesian coordinates.
(3 marks)
2) Calculating the Divergence: Determine the divergence of the following vector field and
then evaluate it at the indicated point:
E = x^ 3x2 + y^ 2z + z^ x2z
at (2, −2, 0) in Cartesian coordinates.
(3 marks)
3) Circulation: Given that F = x2ax − xzay − y2az, calculate the circulation of F around the (closed)
path shown in the Figure.
(3 marks)
4) In a certain region, the electric flux density is given by:
D = 2ρ(z+1)cosφ aρ – ρ(z+1)sinφ aφ + ρ2 cosφ az μC/m2.
a) Show that the charge density is equal to ρv = 3(z+1)cosφ μC/m2
b) Calculate the total charge enclosed by the volume 0<ρ<2, 0<φ<π/2, 0<z<4.
(5 marks)
5) A spherical shell with outer radius b surrounds a charge-free cavity of radius a < b (Fig. 2). If the
shell contains a charge density given by
𝜌𝑉 = −
𝜌𝑉0
,
𝑅2
𝑎 ≤ 𝑅 ≤ 𝑏,
where ρV0 is a positive constant, determine the electric flux density D in all regions.
Fig. 2 for problem 5.
(5 marks)
6) Spherical Capacitor: Show that the capacitance of two concentric spherical metal shells with radii a
and b is equal to C = 4πε0[ab/(b−a)]. Assume the inner shell has charge +Q and the outer -Q.
(3 marks)
7) Consider a straight non-magnetic conductor of circular cross-section and radius a carrying a current with
uniform current density J (A/m2) in the vertical direction. Using Ampere’s law find the magnetic field inside and
outside the conductor.
(3 marks)
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答
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herethepathisdividedintofourpartsasshownin thecoordination as
Forpart1 thelineisalongx axis soy zi
i.io
Forpart2 theline isalongy axis so x
ǗǗǗǙǗǗ㲮
1 刈班
0
0
i Forpart3 thelineisparalleltothe
planeformed
andy 1 F x我 ⼀站
y x axisandZ axis
o'lx2dx dz
dlidxaxtdz
thenbF.dk
nnerex z.sodx dz
SO that
Ǐ
GF.dk iindx lIx3 x 6
Forpart4 the line isparadedto theplaneformedbyy axisandtaxis
and x 1 F xzag yzd.dk
dygtdzc
tenfF.dk
i zgy2dE
wherey Z.sody dz
1 刘三刻到0
so thatheFdnicyysdg
来Fdlr ⼀号
0 ⼀号 t
Et
Ī
Answer thecirculationof Faround
pathis to
4
a
FTD⼆⼗号PDPt fine 孨⼝
⽅⾔12
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3 Z11 cosyt.hn2
b
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yofo3pEnwsYdpd4d
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so thenǗǖǚgeismuc
5 D is radiallyoriented SOWehaveD DRI
DRE.Eds 4元⼼DR
Gauss'Slaw Q
Dds
sothat 贩 Qlznz
meansQ 0
In Ra thereis nochargeinthecavitywhich
so DRE0
12
ateb.QEhiafdvt.fi 器4midr
⼀
4观 仅⼀
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Thus DR⼆ 华顾2
Ra
13 Rob
Qtǘapvdtfǎ
4班 b a
D a
ThusDR
Answer
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⼀
i
a
D
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器 4uidr
⼝
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i
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b a成
6
ApplyGauss'slaw to thissphericalsurface
Q E Eds EE.at
thatis E ⼆ 点
hepotentialdifferencebetweentheinnerandoutersurfaces is
V fE.dk 1 畚
⼼⻔drār
先幻法 吞 六⽅
so that C⼆
thatis C
点 咗彘给⼀⽅ 蕊
4
巺 4元红abkb a
when红⾐ thereis C 4硍 abkb a
7 WehavefrmulaE 7ds
J.nr EQH.dk
Huzur
Outsidetheconductor In a
I 后起 H r
so that Hcr 器
Insidetheconductorco area
I J 2 H 2亿
so thatHer⼆歪
AnswerThemagnetic
fieldhas
ārlocrsa
HYE
等 ārlna
B
P器
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arlo.rs a
ārcrsas
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