Uploaded by Robert Franklin

Cubic Equations Factor By Grouping

Cubic Equations Name_________________________________________ Pd_____ Date_____________
1) x3 + 2x2 - x - 2 = 0
2) 2x3 - x2 - 4x + 2 = 0
Factor by grouping:
x²(x + 2) – 1(x + 2) = 0
Factors are the common factor (x + 2)
and the terms that were factored
out (x² and – 1) together in parentheses:
(x + 2) and (x² - 1)
x = -2 and x² = 1
Solve for x: √(x²) = √(1)
Answer: x = -2 and x = ±1
Cubic Equations Name_________________________________________ Pd_____ Date_____________
1) x3 + 2x2 - x - 2 = 0
Factor by grouping:
x²(x + 2) – 1(x + 2) = 0
Factors are the common factor (x + 2)
and the terms that were factored
out (x² and – 1) together in parentheses:
(x + 2) and (x² - 1)
x = -2 and x² = 1
Solve for x: √(x²) = √(1)
Answer: x = -2 and x = ±1
2) 2x3 - x2 - 4x + 2 = 0
3) x3 - 2x2 - 3x + 6 = 0
4) 4x3 + 4x² + 3x + 3 = 0
5) x3 - 23x2 + 2x - 46 = 0
6) 4x3 - 8x2 + 3x - 6 = 0
7) x3 - x² - 6x + 6 = 0
8) x3 + 13x2 + 2x + 26 = 0
3) x3 - 2x2 - 3x + 6 = 0
4) 4x3 + 4x + 3x + 3 = 0
5) x3 - 23x2 + 2x - 46 = 0
6) 4x3 - 8x2 + 3x - 6 = 0
7) x3 - x² - 6x + 6 = 0
8) x3 + 13x2 + 2x + 26 = 0