h *Ia,[eSimp SWfr lFormgfrysics CapeUrtit 2 PrestonKissoon DiplomaEducation, BSc.(Physics), Engineering DiplomaEngineering(UK Council) A n y u n a u t h o r i z ecdo p y i n go f t h e c o n t e n t so f t h i sb o o kw i l l b e i n v i o l a t i o no f t h e I n t e l l e c t u aPl r o p e r t y R i g h t sa c t o f T r i n i d a da n dT o b a g o T o o r d e rc o p i e so f t h i s b o o k ,p l e a s e c a l l 7 8 7 - 9 1 5 0o r e m a i l: k p r e s 1 8@ 2hotmail.com Printed201,2 CONTENTS TOPIC PAGE E l e c t r o m o t i vfeo r c ea n d P o t e n t i adl i f f e r e n c e Resistivity ElectriC c ircuita s n dC h a r a c t e r i s t i c s 12 Kirchoff'sLaws 18 Resistance 28 Electrostatics 44 Capacitors 61 M a g n e t i cF i e l d s 78 M a g n e t i cF o r c e s 86 Electromagnetism 93 HallEffect 97. E l e c t r o m a g n e tIincd u c t i o n 99 Alternating current 113 Semiconductors 121 O p e r a t i o n aAl m p l i f i e r s I29 D i g i t aE l lectronics 159 Photoelectricity 185 X-Rays 197 L i n eS p e c t r a 204 AtomicStructure 209 Radioactivity 222 %of,ufe1 tr fectricityanf,%-agnetism I M P O R T A NFTO R M U L A E (1-)Quanti.tyof Electri"c charge Q : It W =, * ( 2 ) P o t e n t i a l D t f f e r e n c eV Q ^v2 (3) Electri.calPower P : IV : I'R : T RA (4)Resi.stivi.ty p : I I ((s)Dri.ft uelocity v 71EA QtQ' 4rctsrz (6)Electrostattc Force on each of 2 potnt charge F Q (7)Etectrtcf teld due to apoint charge ' Av E Lr :- , ttesQ ( B ) E L e c t r i .Pco t e n t t a ld u e t o a p o i n t c h a r g e , # ( 9 ) C a p a c i t a n c eC - ? V ( 1 0 ) F o r a p a r a l l e l p l a t e c a p a c t t o r , C- ( 1 1 )E n e r gsyt o r e d t na c a p a c i . tW o r- r y eA z -y 222C -y - : +: +: \.r. cI c2 c3 (1,3)Threeapaci.torsi"nParallel C7 Cr * Cz* Cz (Iz)TlveeCapaci,tors tn rrrrc, ! ( 1 4 ) W h e no c a p o c i t o r d i s c h a r g e s Q : - Q o e - ' l c n; V : Voe-'lcn;I : I o e - t l c n' ELECTRICITY A b a s i ce l e c t r i c asly s t e mh a sf o u r ( 4 )m a i np a r t s : ( 1 ) T h es o u r c ee ' g ' b a t t e r y w - h i c hi s u s e dt o p r o v i d ee l e c t r i c aeln e r g y ; t h i si s c a l l e da n ACTIVE D E V I C,Ea si t s u p p l i e es n e r g y . ( 2 ) T h el o a d -e ' g .a r e s i s t o rl-t a b s o r b o s r converte s l e c t r i c aeln e r g ya n d i s c a l l e da PASSIVE DE V I C E . ( 3 ) T h et r a n s m i s s i osny s t e mw - h i c hi s a s e to f c o n n e c t i nign s u l a t e w d i r e st h a t c o n n e c t tsh e s o u r c e . t toh e l o a d . (a) The controlsystem-eg. A switchto controlthe periodsfor whichthe active device s u p p l i etsh e p a s s i v d ee v i c e . The e.m.f.in a circuitis associated with the totaramount of energy that is availablefrom the activedevicein the circuit'.The e.m.f.of a sourceis definedas the TOTALenergyper coulomb it deliversround a circuitjoinedto it. Theterminalpotentialdifferencein a circuitis associated with the amountof electrical energyavailableto the passivedevicesin the circuit. The terminatpotentialdifferenceof a- . sourceis'definedas the amountof energyper coulomb it deliversto the EXTERNAL circuitto which it is connected. I l n t h e c a s eo f a n e l e c t r i cf i e l d ,t h e p . d .b e t w e e nt w o p o i n t si n t h e f i e l d i s t h e w o r k d o n eo n u n i t c h a r g ea s i t i s m o v e db y t h e f i e l df r o mo n e p o i n tt o t h e other) A n ya c t i v ed e v i c es u c ha sa b a t t e r y h, a si n t e r n arl e s i s t a n c e t o t h e i n t e r n am l o v e m o not f c h a r g e . w h e n t h e d e v i c ei s n o t c o n n e c t e tdo a c i r c u i t , , a ntdh u s d o e sn o t h a v ea c u r r e n t t h r o u g iht , t h e p o t e n t i adl i f f e r e n c b e e t w e e ni t st e r m i n a l si s e q u a lt o i t s e m f . H o w e v e rw, h e nt h a t d e v i c eh a sa c u r r e n t h r o u g hi t , t h e p o t e n t i adl i f f e r e n c b e e t w e e ni t st e r m i n a l si s l e s st h a n i t s e m f . T h i si s becausp e a r to f t h e e m f i s d r o p p e da c r o s st h e i n t e r n a l resistanca en , dt h e r e s ti s d r o p p e d a c r o s st h e l o a do r e x t e r n arl e s i s t a n c e . L e t t h ei n t e r n arl e s i s t a n cbee r a n dt h e e x t e r n arl e s i s t a n coer l o a db e R .l f t h e e m f o f t h e s o u r c e i s E a n dt h e c u r r e n it n t h e c i r c u i its l , t h e n : E=lr+lR l o a da n di s t h e t e r m i n apl . d . a n d i s u s u a l l y H e r e t, h e q u a n t i t yl R r e p r e s e n t s t hpe. d .a c r o s s t h e of the the voltageacrossthe internalresistance by V. The quantity(lr), represents represented battery. H e n c ew e c a nw r i t e E = V + l r . lf however,a currentis beingsuppliedto the battery, then V = E + lr. Thiscan occurwhen the battery in questionis connectedto anotherone of a highere.m.f. Electriccharge: a l f a c o n s t a nct u r r e n tI ( A )f l o w si n a c i r c u i ft o r a g i v e nt i m e t ( s )i n a c i r c u i tt,h e n t h e q u a n t i t yo f p a s ta n yp o i n ti n t h e c i r c u i ti,s g i v e nb y Q = I t . c h a r g eQ t h a t w o u l dh a v e f l o w e d T h eu n i t o f e l e c t r i c h a r g ei s t h e C o u l o m b( C ). The Coulombis definedas the total chargethat would haveflowed pasta point in a circuit after one secondif a constantcurrentof 1 Ampereflows throughthat point. T h eC o u l o m bi s t h e r e f o r ed e f i n e da st h e A m p e r es e c o n d . i.e.1C= l-As. or loadbe R. lf the emf of the source be r and the externalresistance Letthe internalresistance i s E a n dt h e c u r r e n ti n t h e c i r c u i ti s l , t h e n : E=lr+lR l o a da n di s t h e t e r m i n apl . d . a n d i s u s u a l l y H e r e t, h e q u a n t i t yl R r e p r e s e n t s t hpe. d .a c r o s s t h e of the the voltageacrossthe internalresistance by V. Thequantity(lr), represents represented battery. Hencewe canwrite E = V + lr . tf however,a currentis beingsuppliedto the battery, then V = E + lr. Thiscan occurwhen the battery in questionis connectedto anotherone of a highere.m.f. Electriccharge: a l f a c o n s t a nct u r r e n tI ( A )f l o w si n a c i r c u i ft o r a g i v e nt i m e t ( s )i n a c i r c u i tt,h e nt h e q u a n t i t yo f c h a r g eQ t h a t w o u l dh a v ef l o w e dp a s ta n yp o i n ti n t h e c i r c u i ti,s g i v e nb y Q = I t . T h eu n i t o f e l e c t r i c h a r g ei s t h e C o u l o m b( C ). The Coulombis definedas the total chargethat would haveflowed pasta point in a circuit after one secondif a constantcurrentof 1 Ampereflows throughthat point. T h eC o u l o m bi s t h e r e f o r ed e f i n e da st h e A m p e r es e c o n d i . e .1 C= 1 A s . PotentialDifference: The unit of potentialdjfferenceis the Volt (V). 1 Volt = l- Jouleper coulomb,or LV=l-JCThe potentialdifferencebetweentwo pointsin a circuitis definedas the amount of electrical energyconvertedto other forms of energyper coulombof chargepassingfrom one point to the other. T h ev o l t i s d e f i n e da sf o l l o w s : The potentialdifferencebetweentwo pointsin a circuitis 1 volt if l Jouleof electricalenergy is convertedto other forms of etectricalenergywhen 1 Coulombof chargepassesfrom one point to the other. P otenttal di"ff erence = energy converted W char g e a R e c a lal n d u s et h e f o l l o w i n ge q u a t i o n s : V : I R , P _ I V , P_ I Z RP , -+, E _I(r+R) RESISTIVITY: F o ra u n i f o r ml e n g t ho f c o n d u c t ohr a v i n ga l e n g t hl , c r o s ss e c t i o n aal r e aA a n d r e s i s t a n cRe,t h e resistivity of the materialfrom whichthe conductoris made,is givenby the formula: 0- RA T The unitsof resistivity are Om. Notethat the resistivity is a propertyof the materialand is t h e r e f o r ei n d e p e n d e notf t h e d i m e n s i o n sh,e n c ea 2 c m 3s a m p l eo f c o p p e rh a st h e s a m e r e s i s t i v i toyf a 5 m 3 s a m p l e . F r o mt h e e q u a t i o na b o v e t, h e R e s i s t i v i t y w o ubl de e q u a lt o t h e r e s i s t a n ci e f the length'l'was L m a n dt h e c r o s ss e c t i o n aal r e aw a s 1 m 2 ' Henceresistivity can be definedasfoilows: I The Resistivityof a specirnenof materialis the productof its crosssectionalarea anUits etectricalresistanceper unit length. i DRIFTVELOCITY s c o n d u c t oAr B i n t h e c i r c u ist h o w n : C o n s i d ear p . d .b e i n ga p p l i e da c r o s a A E+ A n e l e c t r i cf i e l di s E i s s e t u p a c r o s sA B i n t h e d i r e c t i o nf r o m A t o B . E l e c t r ifci e l d sa r e a l w a y sd i r e c t e df r o m p o s i t i v et o n e g a t i v eT. h ee l e c t r i cf i e l di s a v e c t o r quantity. n h y ), a n di n t h e i r n t h e d i r e c t i o n- E , ( e x p l a i w E l e c t r o nisn t h e c o n d u c t oar r et h e n a c c e l e r a t ei d ) u t t h e y c o n t i n u et o m o t i o n ,t h e y c o n s t a n t lcyo l l i d ew i t h a t o m s( c a u s i nhge a td i s s i p a t i o n, b VELOCITY. movetowardsA with an avbrasevelocitv calledthe DRIFT Q u e s t i o nW : h y a r et h e y c o n s i d e r etdo h a v ea n a v e r a g ev e l o c i t y ? A n s w e r: T h e ya r e a c c e l e r a t ebdy t h e e l e c t r i cf i e l d, a n dt h e y c o l l i d ew i t h c o n d u c t oar t o m s , H.e n c et h e v e l o c i t yi s n o t c o n s t a nbt u t i n s t e a dc o n t i n u o u s l y w h i c hc a u s e s o m ed e c e l e r a t i o n i n c r e a s easn d d e c r e a s e s . Derivati"on of the equation I - nAve C o n s i d ear s e c t i o no f a u n i f o r ml e n g t ho f c o p p e rw i r e o f c r o s ss e c t i o n aal r e aA , t h r o u g hw h i c ha c u r r e n tI i s f l o w i n g . <-- Electronflow C u r r e n It Assumethat there are 'n' electronsper unit volume,with eachelectroncarrying a c h a r g e' e ' a n d e d c hh a v i n ga n a v e r a g e drift velocity'v'. T h ev o l u m ep e r s e c o n do f e l e c t r o n p s a s s i ntgh r o u g ht h e p l a n eA i s e q u a lt o A v . Vol _- Av .s T h e n u m b e ro f e l e c t r o n p t f t h e n u m b e ro f s e r s e c o n dw i l l b e t h e p r o d u c o e l e c t r o np s e r u n i tv o l u m ea n dt h e v o l u m ep e r s e c o n d . H e n c et h e n u m b e ro f e l e c t r o n p s e r s e c o n dw i l l b e g i v e nb y : A/ t T h ec u r r e n tI i s d e f i n e da st h e t o t a lc h a r g ef l o w i n gp e r s e c o n d . _ t- T otal cltar g e a time t Ne f L - nAve sheet TUTORIAL ( 1 ) A c o i lo f w i r e i s c o n n e c t e d a c r o s sa 1 . 2 Vs u p p l yw h i c hc a nd e l i v e r1 5 0 0 0 Ci n a o n e h o u r period. C a l c lua t e b y t h e p o w e rs u p p l y . (i) c u r r e n td e l i v e r e d T h ea v e r a g e (ii) T h et o t a l c h a r g et h a t w o u l dh a v ef l o w e dt h r o u g ht h e w i r e d u r i n gt h e f i r s t8 (iii) m i n u t e sa f t e rt h e s w i t c hi s c l o s e d T h et i m e f o r w h i c ht h e s t e a d yc u r r e n tm u s tf l o w i n o r d e rf o r t h e t o t a l e l e c t r i c c h a r g et o d r a w nf r o m t h e s u p p l yt o b e 2 2 5 C . ;5 4 s e c o n d s ) @ . I 7A ; 2 0 0 0 C l . d .d r o p st o z e r ow h e n a c u r r e n to f 2 5 A ( 2 ) A d r y c e l lh a sa n e m f o f 1 , . 5 2 Vl t st e r m i n a p p a s s etsh r o u g hi t . W h a t i s i t i n t e r n arl e s i s t a n c e( ?r = 0 . 0 6 1 O ) ( 3 ) A d i r e c tc u r r e n tg e n e r a t o rh a sa n e m f o f 1 2 0 V t; h a t i s ,i t st e r m i n avl o l t a g ei s 1 2 0 V l . d .i s 1 1 5 V .( a ) w h e n n o c u r r e n ti s f l o w i n gf r o m i t . A t a n o u t p u to f 2 0 At h e t e r m i n a p W h a t i s t h e i n t e r n arl e s i s t a n creo f t h e g e n e r a t o r(?b )W h a tw i l l b e t h e t e r m i n a l voltageat an outputof 40A? (r=0.250V=110V) . o wm a n ym e t r e so f ( 4 ) N u m b e r1 0 A l u m i n i u m w i r e h a sa d i a m e t eor f 2 . 5 8 m mH n u m b e r l 0a l u m i n i u mw i r e a r e n e e dt o g i v ea r e s i s t a n coef L O ,i f t h e r e s i s t i v i toyf i s 2 . 8x 1 0 - B O m(. A N S t = ( 1 8 6 m ) aluminium (b) t h r o u g ha n e x t r u d e sr o a st o m a k ei t A w i r e h a sa r e s i s t a n coef o f 5 0 a n d i s p a s s e d . h a ti st h e n e w r e s i s t a n c e ? i n t o a n e w w i r e t h r e et i m e sa s l o n ga st h e o r i g i n a lW ANS(r =45O) ( H i n t :T h ev o l u m eo f t h e w i r e i s u n c h a n g e ds ,o t h a t t h e a r e aw i l l c h a n g ef;i n dt h e n e w a r e ai n t e r m so f t h e o r i g i n aol n e ) (5) Two resistors of 40 and 12Oare connectedin parallelacrossa 22Vbattery,havingan i n t e r n arl e s i s t a n coef l O . C a l c u l a t(ea ) T h eb a t t e r yc u r r e n t (, b )t h e c u r r e n ti n t h e 4 0 the terminalvoltageof the battery,(d)the currentin the 12Oresistor. resistor,(c) (Ans 5.5A;/+:.A;t7V; 1.4A) 10 (6) Threeresistors of 40O,60Q,and1200,areconnected in parallel andthisparallel groupisconnected in series witha 15Oin series witha 25O.Thewholesystemisthen (a)Thecurrentin the 25O,(b)the p.d.across connected to.a120Vsource. Determine group,(c)the p,d.across the parallel the 25O,(d)thecurrentin the 600, (e)the currentin the40O. (2A;4Ov;50V;0.67A;1A.) (7) Two coilsof wire are madefrom l.0m of wire eachhavinga diameterof 0.05mm. Oneof the coilsis madeusingcopperwire, while the other is madefrom aluminiumwire. Ifthe resistivityofcopperis 1.59x10-8Om and the resistivityof aluminiumis 2.7x 10-80rn, find the resistanceof eachcoil.(Ans:81O;138O) ( 8 ) A l e n g t ho f w i r e h a sa d i a m e t e o r f 0 . 4 5 m ma n da r e s i s t a n coef 4 0 0 0 . F i n dt h e r e s i s t a n coef t h e s a m el e n g t ho f w i r e i f t h e d i a m e t e irs : (i) Doubled ' (ii) T r ip l e d. (Ans1000; 44.40) ( 9 ) H i g ht e n s i o nc a b l e sh a v ea d i a m e t e o r f 2 c ma n d a 3 0 k ml e n g t hh a sa r e s i s t a n coef - 4 . O . ' Determine: (i) T h er e s i s t i v i toyf t h e m a t e r i aul s e di n m a k i n gt h e c a b l e s . (ii) T h er e s i s t a n coef a n o t h e rc a b l eo f t h e s a m em a t e r i ahl a v i n ga d i a m e t e o r f 1.5cm a n d a l e n g t ho f 1 5 0 m . ( A n s4 . I x 1 0 - 8 O m0;. 0 3 6 0 ) (10) O n ep i e c eo f w i r e P h a sa l e n g t hI a n dd i a m e t e d r a n d r e s i s t a n cRe .W h a t i s t h e r e s i s t a n ci en t e r m so f R f o r a n o t h e rp i e c eo f w i r e Q o f t h e s a m em a t e r i ahl a v i n ga l e n g t h4 . 5 1a n dd i a m e t e2r . 4 d ( A n s0 . 7 8 R ) TT ELECTRICAL CIRCUITS A g r a p ho f c u r r e n ta g a i n svt o l t a g ef o r a n yp a r t i c u l acro m p o n e n ti ,s n o r m a l l yc a l l e dt h e I - V c h a r a c t e r i s tfiocr t h a t c o mp o n e n t . T h e r ea r ea f e w g r o u p so f c o m p o n e n ttsh a t h a v et h e i rd i s t i n cIt- V c h a r a c t e r i s t i casn,dt h e s ea r e ( a ) M e t a l l i c o n d u c t o r s I-V characteristic for a METALLIC CONDUCTOR at constant ( b ) S e m i c o n d u c tD o ri o d e temperature ( c ) F i l a m e nJta m p s . p.d./v T h eg r a p hi n d i c a t etsh a t t h e c u r r e n ti s a l w a y sd i r e c t l yp r o p o r t i o n at ol t h e a p p l i e dv o l t a g e a n dt h a t w h e nt h e v o l t a g ei s r e v e r s e dt h , e r ei s n o c h a n g ei n t h e b e h a v i oor f t h e m e t a l l i c c o n d u c t oirn t e r m so f i t s c o n d u c t i o n T h i st y p e o f c o n d u c t oirs a l s or e f e r r e dt o a sa n O H M I CC O N D U C T OsRi n, c ei t s g r a p h i n d i c a t etsh a t i t o b e y sO h m ' sL a wa t a l lt i m e s ,P R O V I D ETD H A TT H ET E M P E R A T Ul R SE C O N S T A N Tt .hI ef t e m p e r a t u r e i n c r e a s ehso w e v e rt,h e r e s i s t a n coef t h e c o n d u c t ow r ill a l s oi n c r e a s ea,n dt h e g r a d i e not f t h e g r a p hw i l l d e c r e a s eT.h i sd e c r e a s ien g r a d i e n its d u e t o t h e f a c tt h a t t h eg r a d i e n t - 1.2 :\ / R- : I - V characteristic for a FITAMENT LAMP. p.d./v a T h i sg r a p hs h o w st h a t t h e c u r r e n ti s p r o p o r t i o n a l t toh e a p p l i e dv o l t a g eo n l yw h e nt h e r ei s a r e l a t i v e lsym a l a l p p l i e dv o l t a g eF. r o mt h e p o i n t ' a ' t ot h e p o i n t ' b ' ,t h e g r a p hi s l i n e a a r n dt h e ' a ' f i l a m e n tl a m po b e y sO h m ' sl a w o n l yi n t h e r e g i o nf r o m t o ' b ' . B e y o p d ' a ' a n d ' b ' t hg e r a d i e not f t h e g r a p hD E C R E A SaEnSdt h i si n d i c a t etsh a t t h e R E S I S T A N C E I SI N C R E A S I N G . T h i si n c r e a s ien r e s i s t a n caet t h e h i g h e rc u r r e n t si s e x p l a i n e a d sf o l l o w sA : h i g h e rc u r r e n t m e a n st h a t t h e r ea r e m o r ee l e c t r o nfsl o w i n gp e rs e c o n dw , h i c hm e a n sm o r ee l e c t r o n cs o l l i d e w i t h t h e l a t t i c es t r u c t u r eo f t h e t u n g s t e n . T h en u m b e ro f c o l l i s i o npse r s e c o n di s a l s oa m e a s u r eo f t h e r e s i s t a n coef t h e m a t e r i a l . A t e a c hc o l l i s i o nt h , e r ei s a c o n v e r s i oonf s o m eo f t h e k i n e t i ce n e r g yo f t h e e l e c t r o ni n t o h e a t e n e r g yh, e n c et h e t e m p e r a t u r e rises. 13 DIODE for a SEMICONDUCTOR I-V characteristic I/mA I n t h i sc a s et h e c o n d u c t i ocnu r r e n its i n t h e o r d e ro f m i l l i a m pws h i l et h e a p p l i e d p o t e n t i adl i f f e r e n c ies i n t h e o r d e ro f V o l t s . T h ec o n d u c t i o cnu r r e n ti n t h e r e v e r s ed i r e c t i o ni s z e r oo r i t m a yb e s o s m a l tl h a t i t i s c o n s i d e r etdo b e n e g l i g i b l e . l n t h e f o r w a r dd i r e c t i o nt ,h e c o n d u c t i o cnu r r e n tr e m a i n sa t z e r ou n t i lt h e a p p l i e d whichis VOLTAGE voltagereachesa particularvaluecalledthe SATURATION a p p r o x i m a t e 0l y. 6 V . t h e nt h e a p p l i e dv o l t a g er e a c h e as n d e x c e e dtsh e T h ed i o d eo n l yb e g i n st o c o n d u c w s a t u r a t i o vn o l t a g e . e f t h e i n f i n i t e l yh i g h T h ed i o d ed o e sn o t c o n d u c itn t h e r e v e r s ed i r e c t i o nb e c a u s o r e s i s t a n ci en t h e r e v e r s ed i r e c t i o n . I n t h e f o r w a r dd i r e c t i o nt h e r e s i s t a n ci es i n i t i a l l yi n f i n i t eb u t b r e a k sd o w nt o a v e r yl o w v a l u ew h e nt h e a p p l i e dp o t e n t i adl i f f e r e n c ies i n c r e a s eudn t i lt h e s a t u r a t i o vno l t a g ei s a t t ai n e d . t4 THERMISTORS T h e r m i s t o rasr es p e c i asl o l i dt e m p e r a t u r e s e n s o rw s h o s er e s i s t a n cceh a n g e rsq p i d l ya n d p r e d i c t a b lwy i t h t e m p e r a t u r eT. h e i rn a m ei s a c o n t r a c t i oonf " t h e r m a l "a n d " r e s i s t o r , , . There are basically two broadtypes,NTC-Negative Temperature Coefficient, usedmostlyin temperaturesensingand PTC-Positive Temperature Coefficient, usedmosttyin electriccurrent control. T h ec o n v e n t i o n as ly m b o fl o r a t h e r m i s t o irs : / + J a A g r a p ho f R e s i s t a n cvee r s u sT e m p e r a t u ries c a l l e da n R - Tc h a r a c t e r i s t i c R-Tcharacteristic for a p . t . c .t h e r m i s t o r R-Tcharacteristic for a n . t . c t. h e r m i s t o r 15 THERMISTORS T h e r m i s t o rasr es p e c i asl o l i dt e m p e r a t u r se e n s o r w s h o s er e s i s t a n cceh a n g e rsq p i d l ya n d p r e d i c t a b lwy i t h t e m p e r a t u r eT. h e i rn a m ei s a c o n t r a c t i oonf " t h e r m a l "a n d " r e s i s t o r , , . There are basically two broadtypes,NTC-Negative Temperature Coefficient, usedmostlyin temperaturesensingand PTC-Positive Temperature Coefficient, usedmostlyin electriccurrent control T h ec o n v e n t i o n as ly m b o fl o r a t h e r m i s t o irs : / + -J a A g r a p ho f R e s i s t a n cvee r s u sT e m p e r a t u ries c a l l e da n R - Tc h a r a c t e r i s t i c R-Tcharacteristic for a p.t.c.thermistor R-Tcharacteristic for a n . t . c t. h e r m i s t o r 15 Typesof NTCThermistors: (1) Beadin glass T h e m o s tc o m m o nf o r m o f t h e t h e r m i s t oirs a b e a dw i t h t w o w i r e sa t t a c h e dT. h eb e a d d i a m e t ecr a nr a n g ef r o m a b o u t0 . 5 m m( 0 . 0 2 "t)o 5 m m ( 0 . 2 " ) . Lii::;*t lfifii !"h Ti-r*l-f-rii::;[t:if ,r'y'i t-ll;3.1"i,:":l-t E il,:-:;::.f:.,:j M e c h a n i c a ltl hy e t h e r m i s t o irs s i m p l ea n d s t r o n g p, r o v i d i n tgh e b a s i sf o r a h i g hr e l i a b i l i t y s e n s o rT. h e m o s tl i k e l yf a i l u y em o d ei s f o r t h e l e a dt o s e p a r a t fer o m t h e b o d yo f t h e t h e r m i s t o r - a n u n l i k e l ye v e n ti f t h e s e n s o ri s m o u n t e ds e c u r e l yT. h es i n t e r e dm e t a lo x i d em a t e r i ails i n g l a s so r e p o x ye n c a p s u l a t i o n . p r o n et o d a m a g eb y m o i s t u r es, o i t i s e n c a s e d , e r m i s t o ras r eo f t e nm o u n t e di n s t a i n l e ssst e e lt u b e s ,t o L i k eo t h e r t e m p e r a t u rsee n s o r st h . r e a s ei s t y p i c a l l yu s e dt o p r o t e c t h e m f r o m t h e e n v i r o n m e ni tn w h i c ht h e ya r et o o p e r a t eG r n dt h e t u b e . t e t w e e nt h e s e n s o a i m p r o v et h e t h e r m a lc o n t a c b T h e R - Tc h a r a c t e r i s toi cf a t h e r m i s t o cr a nb e m a d em o r el i n e a rb y c o n n e c t i nag r e s i s t oirn p a r a l l ewl i t h i t . T l-r+r nt i::lttr Fl+:iti r:rns+ rl t- -:r '',tiiIrErlrri.llEl 5 :l thernri,:tut !l[tt_lrt re:ri*tr]r ._._, thermistor rl' '= qr +] ii =\=\_ 1 iL' |I l'- I tlel tfrliitLrf ul-llU 10 T h ep l o t i n t h e d i a g r a ms h o w st h e impactof a 2200ohm resistorin parallelwith a 2252ohm (at 25'C) ill fiJ TernPer+tr.tre 1.6 (2) DiscThermistors: D i s ct h e r m i s t o ras r e m a d eb y p r e p a r i n tgh e v a r i o u sm e t a lo x i d ep o w d e r sb, l e n d i n g them w i t ha s u i t a b lb e i n d e ra, n dt h e nc o m p r e s s i ns gm a l a l m o u n t so f t h e m i x t u r ei n a d i e u n d e r s e v e r a l t o nos f p r e s s u r eT.h ed i s c sa r et h e n f i r e da t h i g ht e m p e r a t u r etso f o r m s o l i dc e r a m i c bodies. A t h i c kf i l m e l e c t r o d em a t e r i a lt,y p i c a l l ys i l v e ri,s a p p l i e dt o t h e o p p o s i t es i d e so f t h e d i s ct o p r o v i d et h e c o n t a c t fso r t h e a t t a c h m e not f l e a dw i r e s .A c o a t i n go f e p o x y p , h e n o l i co, r g l a s s i s a p p l i e dt o e a c hd e v i c et o p r o v i d ep r o t e c t i o n f r o m m e c h a n i c a ln de n v i r o n m e n t a l s t r e s s eT s .y p i c aul n c o a t e d i s cs i z e sr a n g ef r o m 0 . 0 5i n .t o 0 . 1 0i n .( 1 . 3m m t o 2 . 5m m ) i n y e a s u r 0e . 1 0i n .t o 0 . 1 5i n . ( 2 . 5m m t o 3 . 8m m ) i n d i a . ;c o a t e dd i s c t h e r m i s t ogr e s n e r a l lm di a . € -\' H- h= F ;*ri .LJ* (3) Rod-shapedthermistors: a viscouo s x i d e - b i n d emr i x t u r et h r o u g ha d i e , R o d - s h a p et h d e r m i s t o ras r e m a d eb y e x t r u d i n g e l e c t r o d e sa,n d a t t a c h i n g l e a d sR . od h e a t - t r e a t i ni gt t o f o r m a c e r a m i cm a t e r i a la, p p l y i n g t h e r m i s t o rasr e u s e dp r i m a r i l yf o r a p p l i c a t i o nr se q u i r i n vg e r yh i g hr e s i s t a n caen d / o rh i g hp o w e r di s s i p a t i o n . 17 LAWS KIRCHOFF'S Kirchoff's FirstLaw : T h i si s n o r m a l l yc a l l e dt h e j u n c t i o nr u l e ,a n d i t s t a t e st h a t t h e a l g e b r a iscu mo f t h e c u r r e n t sa t a j u n c t i o ni s z e r o .T h i sm e a n st h a t t h e s u mo f t h e c u r r e n t se n t e r i n ga j u n c t i o n ,i s e q u a lt o t h e thejunction. s u mo f t h e c u r r e n t sl e a v i n g Thisrule impliesthat there is neithera build-up of chargenor a depletionof chargeat a junction.The rule is thereforean applicationof the conservationof charge. or negative) of Sincethe law refersto the algebraic sum of the currents,then the signs(positive t h e c u r r e n t sm u s tb e t a k e ni n t o c o n s i d e r a t i oC n .u r r e n t es n t e r i n gt h e j u n c t i o na r eg i v e na p o s i t i v es i g n w t h e j u n c t i o na r eg i v e na n e g a t i v e sign. , h i l ec u r r e n t sl e a v i n g H e n c ei n t h e a b o v ej u n c t i o n, t h e f o l l o w i n ge q u a t i o nc a nb e a p p l i e d : 1 ,+ I s -I +- I s - l r = 0 o r 1 , + I s = I ++ I : + l r 18 Kirchoff'sSecondlaw Kirchoff's 2nd Lawstates: In any closedloop of a circuit,the algebraicsum of the emf's of the sourcesis equalto the algebraicsum of the potentialdifferencesof the loads;ORthe algebraicsum of all the voltagesin the loop is zero. ThissecondLawis an applicationof the conservation of energy.In its simplestform the f o l l o w i n gc i r c u i tc a nb e u s e dt o d e m o n s t r a t iet s m e a n i n g . T h ea l g e b r a iscu mo f t h e e m f ' s i s ( E 1- E z ) .T h em i n u ss i g ni s u s e da s t h ec e l l so p p o s ee a c h other. T h eA l g e b r a iscu mo f t h e p o t e n t i adl i f f e r e n c eiss V r + V , + V r . Henceby Kirchoff's secondlaw, (Et - Er) = Vr + V2 + V3 o r ( E t - E r ) = I R r + 1 P 2+ I R a T h es e c o n dl a w i n d i c a t etsh a t t h e t o t a le n e r g ys u p p l i e db y t h e s o u r c e si s e q u a lt o t h e t o t a l energyconvertedby the loads. I n m o s tq u e s t i o n sb,o t h l a w sm u s tb e a p p l i e ds i m u l t a n e o u st loy s o l v eu n k n o w nc u r r e n t s . 19 W o r k e de x a m p l e s U n k n o w nc u r r e n t sa n d p o t e n t i adl i f f e r e n c ei sn a c i r c u i ct o n t a i n i n g t w o r m o r el o o p sc a nb e c a l l e dM E S HA N A L Y S I S . s o l v e db y K i r c h o f f 'lsa w su s i n ga t e c h n i q u e ( 1 ) F i n dt h e c u r r e n t h r o u g he a c hr e s i s t oirn t h e f o l l o w i n gc i r c u i t : a 6V s r E P( 1 ): AssigncurrentsIr and Iz to the individualloops.The directionof the currentsis not important here. S T E P( 2 ) , Apply Kirchoff s secondlaw to eachloop separatelyso that two sets of simultaneousequationsinvolving Ir and lz canbe obtained. S T E P[ 3 ) ' Solvefor Ir andIz. 20 OV For loop 1, imagineyourselfwalking aroundthe loop in the direction of the current Ir'Remeberthat current flows from a high potential to a low potential and a negative sign is usedto indicatea drop in potentialand a positivesign to indicate a rise in potential. . starting from a ,movingto b then to c and back to a, we get: - 7 l t - 4 - 6= 0 > - 7 l r : 1 0 ; t ' : # . 4 H e n c et , : T A (anti.clockwi.se) For loop 2, startingfrom b to d to c and backto b and movingin the direction of lr*" get : -5lz+B+4=0 p 5Iz- 12; Iz = 2.4A [clockwise) The current through the 4v battery is equalto lz-[- Ir)=lz+lr=3.83A The minus sign for Ir indicatesthat the wrong directionwas assignedto it, and hence its correctdirectionshouldhavebeen anticlockwisein the loop. 2I what happensif we reversethe assumedcurrentsIr and Iz: Investigate F o rl o o p( 1 ), i n g o i n g f r o ma t o b t o c a n db a c k t oa : - 7 h + 6 + 4 = 0 ; H e n c e- 7 l r - - 1 0 D 1 r - | A Here we get a positivevalue for Ir,which indicatesour assumeddirection was correct. Considerloop (2) ,in going from d to a to c and back to d: -5lz -4-B'=0 ; Hence -5lz='J.2> Iz : + - -2.4A The minus sign indicatesthat the assumedanticlockwisedirection of Iz was incorrect,and that it should have been clockwise. This mesh analysistells us that Ir= +A [anticlockwise)and 12=2.4 A [clockwise)which is identicalto the result obtainedwhen we initially assumedthat both currentswere clockwise. 22 Considernow the casewherewe assumeIr to be clockwise,and lztobe anticlockwise initiallv F o r l o o p[ 1 J , w eg e t - 7 h - 4 - 6 - 0 ; H e n c e T l l _ - 1 0 , s o t h a t I t : ]e. Rememberthat the minr, ,ign is used as we drop from a high potential to a low a potential. Thismeansthat Ir : I e(anti"clockwi.se) F o rl o o p( 2 ) , w eg e t- 5 I z- 4 - B= 0 ; H e n c e- 5 / , - t 2 , s o t h a t I z : -1") ;A Thismeansthat Iz =?,4 [clockwise) Theseresultsare identicalto those obtainedwhen we assumeddifferent directionsfor the currents. It is thereforesafeto assumethat regardlessof which initial directionswe assumefor the currents,the results are the same,and that the negativesigns in the answerstell us that we must reverseour initial directionsof the currents. 23 SHEET TUTORIAL q u e s t i o ntso d e t e r m i n teh e c u r r e n t tsh r o u g he a c ho f t h e b a t t e r i e s : N o wt r y t h e f o l l o w i n g (1) I r =0 . 7 5 A ; Iz = -T- 1,1,4 rS BV ||l tl (2) I r =0 . 7 5 4; b : *A 9 lz:lz-2sA 12V ( 3 ) D e t e r m i n teh e c u r r e n ti n e a c hr e s i s t o r : S o l u t i o no n p g 2 6 12V 24 (4) _ ,I E O-g /rso : 1so: 2 A(anttclockwise) 1,1, 4SA (clockwi"se) 7 (upwards) 1,SA (s) I:cr: 24 clockwtse BA lrso : 1rca0.29Aclockwise 1so: 0'27A (6) '10Q Izsa : 0.37 7A(anticlo ckwise) lrso : lrocr - 0.1 37Aanttclockwi.se lscr: O.24Aupwards 25 f o r q u e s t i o n( 3 ) Solution 12V F o r l o o p [ 1 J ' - 2 0 1 r- 1 0 l 1+ 1 0 1 2- 1 2 = 0 ; - 3 0 1 r+ 1 0 l z= 1 ' 2- t ( 1 ) F o r l o o p [ 2 ) - 2 5 1 2 ' + 6 - 1 , 0+1120 l r - 0 ; - 3 5 1 2+ 1 0 l r = - 6 - s ( 2 ) Solvingsimultaneouslygives: Multiplyingeq'n (2)by 3 ; 30h -10512= -LB --> (3) R e w r i t i n g[ 1 ) : - 3 0 h + 1 0 1 2= L 2 t1) Adding [1J and [3J gives -9512--6; henceIz = 0.063A Ir= -0.379.The minus sign here indicatesthat the clockwise direction that we assignedfor Ir was actuallyin the reverse directionof what it was supposedto be. HenceIrwas 0.379Ain an anticlockwisedirection. 26 lroo : Izoa: 0.21A anttclockwi"se l r s o : / s o : 0 . 0 1 7 Ac l o c k w i s e I z s a: 0 ' 2 2 7A (8) I +e : I oa : 0'77A anttclockwise 1go: lrso : 0'0764 clockwtse /so : 0.8464 upwards 1 r s 0: 1 s o: 0 . 2 1 Ac l o c k w i s e It aa : It+a : 0.0066Aclockwise lrso : 0'2034 downwards 27 RESISTANCE S E R I ECSO M B I N A T I O N : R1 A current Ir leavesthe battery and enters into resistor R1.The current that leavesRL i s I r and this is equal to Ir by Kirchoff s first law. [The current enteringa componentmust b e equalto the current leavingit by the principle of conservationof charge) When Ir enters R2,it leavesasIz,but Iz = It by Kirchoffs First Law. Iz entersR: and the emergingcurrent is I3,but I:= Izby Kirchoffs first Law. Ir = Ir Iz = l : Kirchoff'sF i r s t Hencein the seriescircuit,all of the resistorshavethe SAMECURRENT.[By Law) By Kirchoff s secondLaw, the e.m.f.of the battery is equalto the algebraicsum of the voltagesacrosseachof the resistors. H e n c eE = V t + V z + V : a n d V r = I t R r = l r R r ; V z= l z R z= l r R z ; V : = I : R : = I r R : By Ohm'slaw, E = IrRr where Ir and Rr representthe total current and total resistance respectively. IrRr = IrRr+lrRz+lrR: If this equationis divided by Ir, w€ get Rr = Rr + Rz + Rs (You must learn this derivation). 28 PARALTELCOMBINATION: T h ed i f f e r e n lto o p sa r e i d e n t i f i e d w i t ht h e n u m b e r s h a v i n ga n o v a ls h a p ea r o u n dt h e m .H e n c et h e r ea r e 3 loops. C o n s i d et h r e p o i n ta . T h ec u r r e n te n t e r i n ga i s e q u a lt o I r a n d t h e t o t a l currentleavinga is equalto h + Iz+ I: . By Kirchoffs first law, the total current enteringa point, must be equalto the total current leavingthe p o i n t .H e n c e Ir=lr+lz+l: l f K i r c h o f f 'sse c o n dL a wi s n o w a p p l i e dt o L o o p1 , t h e nw e g e t E = I r R i A p p l y i n gK i r c h o f f ss e c o n dl a w t o l o o p z , w e g e t 0 = I r R r - I z R z ;I r R r = I z R z= E If the secondlaw is now appliedto loop 3 we get,0= IzRz-IsR: I:R: = IzRz=E ; This applicationof the secondlaw tells us that in a parallelcombination of resistorsor other components,the potentialdifferenceacrosseachbranch is the same. Henceif Vr ;Vz i and V: are the potentialdifferencesacrossRr Rz; and R: ; respectively,then Vr = Vz=Vs = E By Ohm'sLaw, -V:2_- E ,VtE It: &: ^'t'- R2 , -J R2' Sincelr=lt+lz+ E Rr -E+E E- + - ' R 3 R1 R2 And hence 1,1,1,I Rr Rl 29 R2 'R3 : _V :E_ R3 E R3 and T, ,R:T E DLI V I D E R T H EP O T E N T I A connectedin seriesand of threeterminals,two or more resistors The potentialdividerconsists a v o l t a g ea p p l i e da c r o s tsh e e n t i r ec o m b i n a t i oonf r e s i s t o r s . 'tap off' fractionsof the appliedvoltage,and in so Thefunctionof the potentialdivideris to d o i n g t, o p r o d u c ea v a r i a b l es u p p l yf r o m a s i n g l ed . c .s o u r c e ' a ss h o w n : c o n s i d etrh e f o l l o w i n gp o t e n t i adl i v i d e rc i r c u i t sc o n t a i n i ntgh r e er e s i s t o r s dividedby the total I n c i r c u i t( 1 ) ,t h e c u r r e n t h r o u g he a c hresistoris givenby the total voltage r e s i s t a n ci e. e . ' I J tr Ir : - : Rr E Rr * Rz+ R3 A n dt h e v o l t a g eV r t h a t i s t a p p e do f f i s e q u a lt o : Vt : IrRt: ERt Rr*R2+R3 s i m i l a r l yi ,n c i r c u i t( 2 )t h e v o l t a g eV zt h a t i s t a p p e do f f i s e q u a lt o : Vz: . It(Rt * Rr) : E [ R 1+ R 2 ] R;- & s u c ha sV r a n d T i r . .s S o v ee x a m p l es h o w st h a t w h i l et h e s o u r c eh a sa v o l t a g eE ,s m a l l evr o l t a g e V 2c d nb e o b t a i n e df r o m i t . 30 THEPOTENTIOMETER l f i n s t e a do f u s i n gt h r e er e s i s t o risn seriesa one metrelengthof resistance wire is usedand a s l i d i n gc o n t a c it s u s e d t, h e n s e v e r atla p p e do f f v o l t a g e cs a nb e o b t a i n e da, n d a v a r i a b l ed . c . s u p p l yc a nt h u s b e p r o d u c e d . A st h e s l i d i n gc o n t a c it s m o v e d a l o n gA B , t h e r e s i s t a n ci en c r e a s ef sr o m A t o B a n d hencethe tappedoff voltageincreases s i n c eV = l R ,w i t h t h e c u r r e n tI b e i n g c o n s t a ntth r o u g h o utth e e n t i r el e n g t ho f resistor. D r i v e rc e l l \. T h ew h o l er e s i s t ocr a nb e c o n s i d e r eadsa n i n f i n i t en u m b e ro f t i n y r e s i s t o rasl t connectedin series,so that the current t h r o u g ht h e m i s c o n s t a n t . W h e na s l i d ew i r e i s u s e da s i n t h e a b o v ea p p l i c a t i o nt h, e p o t e n t i adl i v i d e ri s r e f e r r e dt o a sa POTENTIOMETER. T h e b a t t e r yo r c e l lt h a t i s a p p l i e da c r o s st h e e n t i r el e n g t ho f t h e p o t e n t i o m e t ewr i r e , i s c a l l e d the CELL .D R I V E R D r i v e rc e l l S t a n d a r cde l l 31 ONFT H EP O T E N T I O M E T E R APPLICATIO ( 1 ) M e a s u r e m e not f e . m . f . i f a n o t h e rc e l l O n eo f t h e p r i m a r yu s e so f t h e p o t e n t i o m e t eirs i n t h e m e a s u r e m e notf t h e e . m . f .o f a c e l l c e l l )i s a v a i l a b l e o f k n o w ne . m . f .( c a l l e da s t a n d a r d c e l l . S a fyo r e x a m p l et h e s t a n d a r cd e l lh a sa n e . m ' f l e n g t hi s f o u n df o r t h e s t a n d a r d F i r s t l yt ,h e b a l a n c e o f 1 . 1 5 Va, n dt h e b a l a n c ep o i n tw a sf o u n dt o b e 3 6 c m . the T h e s t a n d a r dc e l li s t h e n t a k e no u t o f t h e c i r c u i ta n d r e p l a c e db y t h e c e l lo f u n k n o w ne . m . f .a n d b a l a n c ep o i n ti s a g a i nf o u n d .S a yf o r e x a m p l ea g a i n t, h e b a l a n c ep o i n tw a sf o u n dt o b e 5 4 c m . D r i v e rc e l l D r i v e rc e l l 4 C e l lo f u n k n o w n S t a n d a r cd e l l e.m.f. T h ec a l c u l a t i ofno r t h e u n k n o w ne . m . f .i s a sf o l l o w s : l e n g t ho f 3 6 c m . s a balance 1 . 1 5 Vc o r r e s p o n dt o 1.15 H e n c e1 c m w i l l h a v ea n e q u i v a l e nvt o l t a g eo f E ; 1.15 x 54 =1,.725V 5 4 c m w i l l h a v ea n e q u i v a l e nvt o l t a g eo f E H e n c et h e e . m .f . o f t h e u n k n o w nc e l li s 1 ' . 7 2 5 V 32 ( 2 1 M e a s u r e m e not f t h e i n t e r n a lr e s i s t a n c oe f a c e l l : T h eb a l a n c el e n g t ho f t h e e . m . f .o f t h e c e l li s f i r s tf o u n dw h e nt h e c e l li s o n o p e nc i r c u i ti,. e .n o l e n g t hi s 6 8 c m s c o n n e c t etdo i t . S a yf o r e x a m p l et ,h i sb a l a n c e e x t e r n arl e s i s t a n ci e D r i v e rc e l l E T h e n e x ts t e pi s t o i n s e r ta K n o w nr e s i s t a n cien s e r i e sw i t h t h e c e l lo f e . m . f .E .U s ef o r e x a m p l ea 2 0 Or e s i s t o rT.h en e w b a l a n c el e n g t hw i l l d e c r e a steo s a y4 6 c m ,f o r t h e n e w v o l t a g eV D r i v e rc e l l T h e e . m . f .E o f t h e c e l ln e e d not be known in this case E R R e c a ltlh e f o r mu l aV : 1 R - R*r VR46 Hence-: E R*r :68 i 68R=46R+46r 22R -- 46r, but R =20C), hence 46r = 440Q ; r = 9.560 33 THEWHEATSTONE BRIDGE T h i sb r i d g ec i r c u i w t a sd e s i g n e tdo p r o d u c ea v e r ya c c u r a t em e a n so f m e a s u r i nrge s i s t a n c e . I n n o r m a l a b o r a t o r py r a c t i c e t h e r e s i s t a n coef a c o m p o n e nits d e t e r m i n e d byapplying a p o t e n t i adl i f f e r e n c a e c r o s si t , m e a s u r i n g t hceu r r e n t t h r o u g iht , a n dt h e n a p p l y i n gR - y . H o w e v e rt,h e a b o v em e t h o di n t r o d u c eus n c e r t a i n t i ei ns t h e m e a s u r e m e ndtu et o U o t ht f ' r . i n s t r u m e n tasn dt h e o b s e r v e r . T h eW h e a t s t o n e B r i d g eu s e sa n u l lm e t h o d w , h i c hm e a n st h a t t w o o p p o s i n g c u r r e n t sa r e p r o d u c e dw h o s em a g n i t u d easr e a d j u s t e du n t i lt h e y b a l a n c e a c ho t h e r ,s o t h a t t h e r e s u l t a n t c u r r e n ti s Z E R Oa, n d a t t h i s p o i n t ,a n u n k n o w nr e s i s t a n ci en t h e c i r c u i ct a nb e d e t e r m i n e d . A current I leavesthe battery and entersthe junction of A and B, where it splits into Ir and Iz. The resistorsA and C are in seriesand thereforethe samecurrent Ir flows through both of them. Similarly, the resistorsB and D are in series,and the same current Iz flows through both of them. If the resistancesare adjustedso that no current flows from X to Y then the potential at X is equalto the potential at Y and a BALANCEPOINTis reached. This would also mean that the potential difference acrossA is equalto the potential differenceacrossB. The p.d.acrossA is equalto IrA and the p.d.acrossB is equalto IzB. Henceat the balancepoint IrA = IzB t1) A l s oa t t h e b a l a n c ep o i n t ,t h e p . d .a c r o s sC i s e q u a lt o t h e p . d .a c r o s sD , s o t h a t : I r C = l z D ( 2 ) If equation [1) is divided by equation[2) we get: AB CD I I I If the rraluesof three of the resistancesare known, then the fourth one can be calculated. I I 34 BRIDGE T H EM E T R E e r i d g ea, n d i t i s u s e dt o m e a s u r e T h em e t r eb r i d g ei s a m o d i f i e dv e r s i o no f t h e W h e a t s t o n B u n k n o w nr e s i s t a n c ewsi t h m u c hm o r ee a s et h a nt h e W h e a t s t o n vee r s i o n . DLI V I D E R . EO T E N T I A I t o p e r a t e sa s a D O U B L P e r i d g et,w o r e s i s t o rasn da I n s t e a do f u s i n g f o u r e s i s t o rass i n t h e c a s eo f t h e W h e a t s t o n b wire are used. metreof resistance and N is M is a knownresistance, M lz t h e u n k n o w no n e . T h es l i d ew i r ef r o m t h e g a l v a n o m e t ei sr m o v e da l o n gt h e r e s i s t a n cwei r e A B u n t i la b a l a n c e p o i n ti s o b t a i n e d . At the balancepoint,the lengthof 'c'can be consideredas one wire 'd' resistorand the length as another resistor. A currentI leavesthe battery,enterspoint A and splits into Ir and Iz.Letthe resistanceof 'c' be kc and the resistanceof d' be kd, where k is the resistanceper unit length of the wire. At the balancepoint Ir kc= IzM t1) ; and Irkd = IzN (2) When equation (1) is divided by equation(2J we get : CM dAl 'd' are measuredlengthson the resistance wire while M is a known resistance, and henceN can be calculated. 'c' 35 TUTORIAL on CurrentElectricity ( 1 ) A b a t t e r yo f e m f 6 V a n d i n t e r n arl e s i s t a n c1e. 8 Oi s c o n n e c t e a d c r o s sa 1 2 Or e s i s t o r . C a l c u l a t eh e t e r m i n apl . d .o f t h e b a t t e r y . ( H i nTth: et e r m i n apl . d .i s t h e v o l t a g ea c r o s s t h e e x t e r n arl e s i s t a n cie. e .a c r o s st h e 1 2 Or e s i s t o r ) (s.22V) ( 2 ) W h e na b a t t e r yo f e m f E a n d i n t e r n arl e s i s t a n cre i s c o n n e c t e a d c r o s sa 6 O r e s i s t o rt ,h e t e r m i n ap l . d .i s 8 . 4 4 V . l ft h e 6 Q r e s i s t oirs n o w r e p l a c e d b y a 1 0 Or e s i s t o rt ,h e t e r m i n a l p . d .i s n o w 8 . 6 5V . D e t e r m i n teh e e m f a n dt h e i n t e r n arl e s i s t a n coef t h e b a t t e r y . ( H i n t :D r a w2 s e p a r a t cei r c u i t as n da p p l yt h e e q u a t i o nE =V + l r f o r b o t ho f t h e m ;t h e n u s et h e s i m u l t a n e o uesq u a t i o ntso f i n dt h e r e q u i r e d quantities) ( r =0 . 3 9 Q E , =9V) ( 3 ) A b a t t e r yo f e . m . f .1 - 8 V a n d i n t e r n arl e s i s t a n crei s c o n n e c t e tdo a n e t w o r ko f r e s i s t o r s h a v i n gt w o r e s i s t o rish p a r a l l e(l8 Oa n d 1 2 O) i n s e r i e sw i t h a 6 0 r e s i s t oar ss h o w n : l f t h e c u r r e n it n t h e 8 O r e s i s t oirs 0 . 4 A c, a l c u l a t e : (i) T h ec u r r e n ti n t h e 1 2 Or e s i s t o r ( Y of iur s tn e e dt o f i n d t h e p . d .a c r o s st h e (ii) l 2 Q r e s i s t owr h i c hi s t h e s a m ep . d .a c r o s st h e 8 O r e s i s t o r ) T h ec u r r e n ti n t h e 6 e r e s i s t o r T h ei n t e r n arl e s i s t a n coef t h e b a t t e r y (iii) A n s .0 . 2 6 7 A , 0 . 6 6 7 A1, , 6 . 2 Q ., Z 7V 36 (41A b a t t e r yP o f e . m . f . 1 , 2 Va n di n t e r n arl e s i s t a n c4eO i s c o n n e c t e idn s e r i e sw i t h a b a t t e r y e with a 20Oresistorconnectedacrossthe Q o f e . m . f .8 V a n di n t e r n arl e s i s t a n c90, c o m b i n a t i oans ' s h o w n : L 2 V , 4n x |l l r-l V, 9Q | I 200 C a l c u l a t eh e t e r m i n apl . d .o f e a c hb a t t e r y . A n s :9 . 5 8 V1 , 3.45V) ( Ad e t a i l e d s o l u t i o ni s g i v e no n p a g e3 5 ) ( 5 ) D e t e r m i nteh e below: 24V ( T h ep . d .a c r o s X s Yi st h e p . d .a c r o s tsh e 8 O m i n u st h e p . d .a c r o s tsh e r z r ) ) ( A n s 0: V )( A d e t a i l e d s o l u t i o ni s g i v e no n p a g e3 5 ) (Ans.3.2V) Determine thevoltmeter r e a d i n gi n t h e g i v e n rzv 20v c i r c ui t . A ns :1 5. 2 V ( S e ep a g e 3 6 ) 37 (7) In the followingcircuit,a voltmeterof resistance 8000 is firstlyconnectedacrossthe 6000 resistorand then acrossthe 2200O resistorseparately. F i n dt h e r e a d i n go n t h e v o l t m e t e ri n e a c hc a s e . 12V A n s1. 6 2 V ; 5 . 9 3 V I I I L__O_-, (8) ln the followingcircuit,a voltmeterof resistance 400Ois firstlyconnectedacrossthe 16000 resistorand then acrossthe 200 O resistorseparately. F i n dt h e r e a d i n go n t h e v o l t m e t e ri n e a c hc a s e . 18V A n s1 1 . 0 8 V 1 ; .38V r__o-, 38 FORQUESTION 4: SOLUTION 1,2V, 4A 8V, 9C) 200 S i n c et h e b a t t e r i e sh a v et h e i r e m f ' si n t h e s a m ed i r e c t i o nt ,h e n e t e m f i n t h e c i r c u i ti s 1 2 V+ 8 V = 20v T h e 1 2 V b a t t e r yh a sa g r e a t e re m f t h a n t h e 8 V b a t t e r ys o t h a t a c u r r e n tl e a v e st h e 1 2 V a n d entersthe 8V battery. 20 The total resi-stancels 330, and the current i"s TA T h e t e r m t n a l p . d . o f t h e I z V b a t t e r y t s o b t a t n e df r o m t h e e q n V t : E - I r v:rz-2fn>:e.sBV 55 T h ec u r r e net n t e r st h e 8 Vb a t t e r ys ot h a ti t st e r m i n apl . d .i sg i v e nb yV 2 =E+ l r Vz:B+*(9):1,3.45V 55 FORQUESTTON 5: soLUTroN T h e r ea r e2 p a r a l l ebl r a n c h e s o t h a t t h e p . d .a c r o s se - a c h b r a n c hi s 1 2 V . T h e c u r r e n ti n t h e t o p b r a n c hi s g i v e nb y : t' R: 2Y4 - 1 2 : 0 . 5 ^ 4 H e n c et h e v o l t a g ea c r o s st h e 8 Q r e s i s t o irs g i v e nb y V : I R : 0 . 5 x B - 4 V ; H e n c eV e v: l V N o w t h e n o t a t i o nV a ym e a n st h e p o t e n t i adl i f f e r e n c e a c r o s sA Y , : that is, VA Vy 4 T h ec u r r e n ti n t h e l o w e rb r a n c hi s g i v e nb y : , _v _ - 3r 2 6 _1 n a c r o s st h e 1 2 O T h e p o t e n t i adl i f f e r e n c e r e s i s t o irs V s xa n d i s : T h e p o t e n t i aal t A i s e q u a lt o t h e p o t e n t i aal t B s i n c et h e y a r e connectedto eachother by a conductoronly;Va- Vn H e n c eV A - V x : 4 a n d V A - V v : 4 F r o mt h e s et w o e q u a t i o n sw, e g e t : 1 Vsx:lR:;X12:4V Vx-Vy:0,soVyy:0 J VB-v,r::4 39 S O L U T I OF NO RQ U E S T I O5N: T h ev o l t m e t e r e a d i n gi s t h e p o t e n t i adl i f f e r e n c e acrose s i t h e rt h e b r a n c h 1,2V c o n t a i n i ntgh e 1 2 Vb a t t e r y t o g e t h e rw i t h t h e 4 0 r e s i s t oor r t h e b r a n c h c o n t a i n i ntgh e 2 0 Vb a t t e r y withthe 60 resistor. C o n s i d ef ri r s tt h e b r a n c hw i t h t h e j _ 2 Vb a t t e r y . T h en e t e m f i s 8 V a n dt h e c u r r e n tw o u l db e VB I-R:10:o'BA V : E t I r : 1 , 2 +( 0 . 8x 4 ) : I 5 . 2 V I f w e u s e dt h e b r a n c h w i t ht h e2 0 Vb a t t e r yw, e w o u l dg e t : V:E-lr V -20 -(0.8x6):I5.2V Remember that whencurrententersthe battery,we use V=E+lr, andwhencurrentleaves the batterywe use V =E - l r 40 WorkedExamples on Potentiometerand Metre Bridge ( 1 ) T h ee m f o f a b a t t e r yX i s b a l a n c e d b y a l e n g t ho f 5 8 c mo n a p o t e n t i o m e t ewr i r e w h i l s ta s t a n d a r dc e l lo f e m f 1 . 0 4 Vi s b a l a n c e b d y a l e n g t ho f 4 6 c m . (i) D e t e r m i nteh e e m f o f X (ii) T h ec e l lX h a sa n i n t e r n arl e s i s t a n coef 4 C ) , a n ids c o n n e c t e d i n s e r i e s t oa l - 2 O r e s i s t o rC. a l c u l a tteh e n e w b a l a n c el e n g t h . ( A n s .1 , . 5 4 V ; 5 0 . 9 c m Solution: (i)1.04h Va sa b a l a n c lee n g t ho f 4 6 c m . Lcm correspondsto a p. d. of 6 8 c mh a sa n e q u i v a l e npt. d .o f 1,.04 46 ( i i )T h ec i r c u i th a sa c e l lo f e m f 1 . 5 4 Vi n s e r i e s w i t h a 4 Q r e s i s t oar n da 1 2 Or e s i s t o r . T h ev o l t a g ea c r o s st h e 1 2 Or e s i s t oirs t h e t e r m i n apl . d .o f t h e b a t t e r ya n d i s e q u a tl o : 1,2 1,.54, 1,.1,5V tO- 68xry-Ls4v +6 T h eb a l a n cpeo i n tc o r r e s p o n d itnogl - . 1 , 5i V s g i v e nb y : ( 2 )A s t a n d a r dc e l lo f e m f 1 . 3 4 Vi s b a l a n c e b d y t h e p . d .a c r o s sa r e s i s t a n coef 2 8 0 0 0i n s e r i e sw i t h a 1 - ml e n g t ho f p o t e n t i o m e t ewr i r e P Qh a v i n ga r e s i s t a n coef 6 0 . A t h e r m o c o u p l e p r o d u c i n ga n e m f o f 1 . 2 m Vi s n o w c o n n e c t e idn s e r i e st o t h e s t a n d a r d c e l la s s h o w n C . a l c u l a tteh e l e n g t hP Ro n t h e p o t e n t i o m e t ewr i r et h a t p r o d u c etsh e n e w b a l a n c e point. Thetotal resistance i s e q u a lt o 2 8 0 6 0 . T h ep . d .a c r o s tsh e 1 m o f w i r ei s a6 x 1.34 2806 - 1,.6mV 1 . 6 m Vh a sa l e n g t h of 100cm 1..34V l - . 2 m Vw i l l h a v ea lengthof loox 1.2:75cm 1..6 41, on the Potentiometerand the metre bridge TUTORIAL ( 1 ) T h e e m f o f a b a t t e r y X i s b a l a n c e db y a l e n g t h o f 4 4 c m o n a p o t e n t i o m e t e r w i r e w h i l s t a s t a n d a r dc e l l o f e m f 1 . 2 0 Vi s b a l a n c e db y a l e n g t ho f 2 8 c m . (iii) D e t e r m i n et h e e m f o f X (iv) T h e c e l l X h a s a n i n t e r n a lr e s i s t a n c eo f 2 C ) , a n di s c o n n e c t e di n s e r i e s t o a l - 8 O : h e c kw o r k e d e x a m p l e ) resistorC . a l c u l a t et h e n e w b a l a n c el e n g t h . ( H i n tC ( A n s1 . 8 9 V ; 3 9 . 6 c m ) ( 2 ) T h e e m f o f a b a t t e r yZ i s b a l a n c e db y a l e n g t ho f 7 4 c m o n a p o t e n t i o m e t e rw i r e w h i l s t a standard.ceo l l f e m f 1 . t z V i s b a l a n c e db y a l e n g t ho f 3 8 c m . (v) D e t e r m i n et h e e m f o f Z (vi) T h e c e l l Z h a s a n i n t e r n a lr e s i s t a n c eo f 6 0 , a n d i s c o n n e c t e di n s e r i e st o a 4 4 O resistorC . a l c u l a t et h e n e w b a l a n c el e n g t h . (Ans2 : .18V;65.2cm) ( 3 ) T h e e m f o f a b a t t e r y . Yi s b a l a n c e db y a l e n g t ho f 8 8 c m o n a p o t e n t i o m e t e rw i r e w h i l s t a s t a n d a r dc e l l o f e m f 0 . 9 6 Vi s b a l a n c e db y a l e n g t ho f 3 6 c m . (vii) D e t e r m i n et h e e m f o f Y ( v i i i ) T h e c e l l Y h a s a n i n t e r n a lr e s i s t a n c eo f I . 2 Q , a n d i s c o n n e c t e di n s e r i e s t o a 3 6 O resistorC . a l c u l a t et h e n e w b a l a n c el e n g t h ( A n s2 . 3 5 V 8 ; 5cm ( 4 ) T h e d r i v e rc e l lo f a p o t e n t i o m e t ewr i r e h a sa n e . m . f .o f 1 . 8 Va n d n e g l i g i b l ien t e r n a rl e s i s t a n c e . T h e p o t e n t i o m e t ewr i r e h a sa r e s i s t a n coef 6 0 . C a l c u l a tteh e r e s i s t a n cteh a t i s n e e d e di n s e r i e s r i r e i f a p . d .o f 2 5 0 m Vi s r e q u i r e da c r o s st h e w h o l e l e n g t ho f t h e w i t h t h e p o t e n t i o m e t ew p o t e n t i o m e t ewr i r e . ( H i n t :D r a wa c i r c u i td i a g r a mo f t w o r e s i s t o r isn s e r i e sw i t h t h e d r i v e rc e l l ,t h e n f i n d t h e p . d s a c r o s st h e e x t r ar e s i s t a n c et h, e n u s eV = l Rt o d e t e r m i n eR , r e m e m b e r i ntgh a t f o r r e s i s t a n c ei n : 7.2O) s e r i e st,h e c u r r e n ti s t h e s a m e . () A n s 3 - ( 5 ) T h ed r i v e rc e l lo f a p o t e n t i o m e t ewr i r e h a sa n e . m . f o . f 4 . 0 Va n d n e g l i g i b lien t e r n arl e s i s t a n c e . T h e p o t e n t i o m e t ewr i r e h a sa r e s i s t a n coef 2 0 . C a l c u l a tteh e r e s i s t a n cteh a t i s n e e d e di n s e r i e s w i t h t h e p o t e n t i o m e t ewr i r e i f a p . d .o f 1 2 m Vi s r e q u i r e da c r o s st h e w h o l el e n g t ho f t h e p o t e n t i o m e t ewr i r e (Ans6 : 650) T.h e ( 6 ) T h e d r i v e rc e l !. r f a p o t e n t i o m e t ewr i r e h a sa n e . m . f .o f 6 V a n d n e g l i g i b l ien t e r n a rl e s i s t a n c e p o t e n t i o m e t ewr i r e h a sa r e s i s t a n coef 3 . 5 O .C a l c u l a tteh e r e s i s t a n cteh a t i s n e e d e di n s e r i e s w i t h t h e p o t e n t i o m e t ewr i r e i f a p . d .o f 8 m V i s r e q u i r e da c r o s st h e w h o l el e n g t ho f t h e potentiorneter wire.(Ans:26220) 42 ( 7 ) I nt h e c i r c u i b t e l o wt h e b a l a n c ep o i n ti s o b t a i n e df o r t h e l e n g t h si n d i c a t e od n t h e d i a g r a mF. i n d t h e r e s i s t a n coef R .( A n s3 2 . 6 O ) 20o. (8) I n t h e a b o v ed i a g r a mc, a l c u l a tteh e b a l a n c el e n g t h sc a n d d . ( A n s :c = 2 7. 5 c m ,d = 7 2 . 5 c m \ 43 ELECTROSTATICS E l e c t r o s t a tpi ch e n o m e n a i n c l u d em a n ye x a m p l eas ss i m p l ea st h e a t t r a c t i o no f t h e p l a s t i cw r a p t o y o u r h a n da f t e ry o u r e m o v ei t f r o m a p a c k a g et o, t h e a p p a r e n t lsyp o n t a n e o uesx p l o s i o on f g r a i ns i l o st,o d a m a g eo f e l e c t r o n ic o m p o n e n tdsu r i n gm a n u f a c t u r i ntgo, t h e o p e r a t i o no f photocopiers. E l e c t r o s t a t iicnsv o l v etsh e b u i l d u po f c h a r g eo n t h e s u r f a c eo f o b j e c t sd u et o c o n t a c w t ithother s u r f a c e sA. l t h o u g hc h a r g ee x c h a n g h ea p p e nw s h e n e v ear n y t w o s u r f a c ecso n t a c a t n ds e p a r a t e , t h e e f f e c t so f c h a r g ee x c h a n g ae r e u s u a l l yo n l yn o t i c e dw h e na t l e a s to n e o f t h e s u r f a c ehs a sa h i g hr e s i s t a n cteo e l e c t r i c af l o w .T h i si s b e c a u s teh e c h a r g e tsh a t t r a n s f e tro o r f r o m t h e h i g h l y r e s i s t i v seu r f a c ea r e m o r eo r l e s st r a p p e dt h e r ef o r a l o n ge n o u g ht i m e f o r t h e i re f f e c t st o b e o b s e r v e dT. h e s ec h a r g e tsh e n r e m a i no n t h e o b j e c tu n t i l t h e ye i t h e rb l e e do f f t o g r o u n do r a r e q u i c k l yn e u t r a l i z ebdy a d i s c h a r g e : e . tgh. e, f a m i l i a pr h e n o m e n oonf a s t a t i c ' s h o c k 'ci sa u s e db y t h e n e u t r a l i z a t i oonf c h a r g eb u i l tu p i n t h e b o d yf r o m c o n t a c w t i t h n o n c o n d u c t i vseu r f a c e s . Coulomb'sLaw: . T h ee l e c t r o s t a tfi o c r c eo f a t t r a c t i o no r r e p u l s i o a n c t i n go n e a c ho f t w o s t a t i o n a rpy o i n t c h a r g e si s, d i r e c t l yp r o p o r t i o n at ol t h e p r o d u c to f t h e c h a r g e sa,n d i n v e r s e lpy r o p o r t i o n at ol t h e s q u a r eo f t h e i rd i s t a n c oe f s e p a r a t i o n . i . e .l f t w o p o i n tc h a r g eQ s l a n de z a r ep l a c e da t a d i s t a n c rea p a r t t, h e nt h e f o r c ea c t i n go n e a c h ' o f t h e c h a r g e si s g i v e nb y ; l:x Thiscanbe re-written as QtQz - F : !3+ Byexperiment, the constant of proportionality wasfoundto U" g i v e nb y : F- fr, sothatthefinalformulais QrQz 4nesrz w h e r ee i s c a l l e dt h e p e r m i t t i v i t oy f t h e m e d i u mi n w h i c ht h e c h a r g e e s x i s tT . h ep e r m i t t i v i t iys a p h y s i c apl r o p e r t yo f t h e r n e d i u mM . o s tq u e s t i o n isn v o l v et h e m e d i u mb e i n ga v a c u u ma n dt h e permittivityis writtehds rs where ro=8.85x !0-t2c2N-tm-2. 1 T n e. , ' , ' r roef _ i s n o r m a l l tya k e na s9 x 1 0 ' N m ' C -.' 4ne. 44 I In orderto determinethe resultantforceactingon any chargethat is within an arrangement of charges, a vEcroR approachmust be used,that is,if a pointchargeis acteduponelectrostatic forcesfrom two or more charges,then the force DUETo EACHCHARGE is calculatedfrom the Coulomb'sLawformuraand then the resultantforcecanbe found by means of VECToR ADDITION. Considera simplecasewherea singrepointchargeB is actedupon by forcesfrom two other electricchargesas shown: Suppose we want to find the resultantforceactingon B A 20;rC @+ 8cm 7. 30sC 1,2cm I n t h i se x a m p l ea, l l c h a r g e sa r e positive. va 50uC T h ef i r s ts t e pi s t o f i n dt h e f o r c ea c t i n go n B D U ET o A o N L y . T h i si s d o n eb y a p p l y i n tgh e c o u l o m b ' L s a wF o r m u l a i.e. rtrA - 20 x10-6 x 30 x 10-6x 9 x 10e :843.75N 0.082 T h ef o r c ed u et o C o n l y i s g i v e nb y : ttrc - 5 0 x 1 0 - 6x 3 0 x 1 0 - 6x 9 x 1 0 e : 937.5N 0.1,22 45 T h et w o f o r c e sc a nb e d r a w no n a v e c t o rd i a g r a ma sf o l l o w s : F" - 937.5N Fn : 843.75N T h e h o r i z o n t aclo m p o n e not f F 6= 9 3 7' 5 c o s4 5 = 6 6 3 N ' forcesis 663+843.75=1506.75N Sothe total of the horizontal T h ev e r t i c acl o m p o n e not f F 6= 9 3 7' 5 s i n 4 5= 6 6 3 N ' l r c eo f 1 5 0 6 . 7 5 N . g i t h a h o r i z o n t af o S o n o w w e h a v ea v e r t i c aflt r c e o f 6 6 3 Nc o m b i n i n w a nb e u s e dt o g i v ea r e s u l t a n t f o r coef 1 6 4 6 N . P y t h a g o r a s ' t h e o r ecm H e n c et h e r e s u l t a nfto r c eo n B i s 1 6 4 6 N 46 ELECTRIC FIELD STRENGTH (AlsocalledElectricfield Intensityor simplyElectricField): T h eE l e c t r i F c i e l dS t r e n g t ha t a p o i n ti s d e f i n e da s t h ef o r c ea c t i n gp e r u n i t p o s i t i v ec h a r g e p l a c e da t t h a t p o i n t . E l e c t r ifci e l ds t r e n g t hi s a v e c t o rq u a n t i t ya n da s s u c h ,i t s d i r e c t i o nm u s tb e c o n s i d e r e d in any calculation. F r o mt h e d e f i n i t i o n , Electrtc Field Strength - Force Charge , h e n c et h e u n i t sa r e N C - 1 l f a p o i n tc h a r g eh a sa m a g n i t u d e o f c h a r g ee , t h e n a t a d i s t a n c er f r o m e t h e e l e c t r i cf i e l d strengthis givenby : E- 4nes rz A p a r tf r o m t h e e l e c t r i cf i e l dd u e a p o i n tc h a r g ee, l e c t r i cf i e l d sa l s oe x i s ti n t h e s p a c eb e t w e e n t w o o p p o s i t e lcyh a r g e dp a r a l l epl l a t e s N . o t et h a t t h e f i e l di s u n i f o r mb e t w e e nt h e p l a t e s m e a n i n g t h a t t h eF I E L D S T R E N G Ti sHc o n s t a nitn t h e s p a c eb e t w e e nt h e p l a t e s .A n o t h e r i m p o r t a nfte a t u r eo f t h e f i e l di s t h a t t h e f i e l dl i n e sa r e c u r v e da t t h e e n d so f t h e p l a t e s . ++++++ +++ C o n s i d et rw o p a r a l l em l e t a lp l a t e ss e p a r a t e b dy a d i s t a n c e d a n d h a v i n ga p o t e n t i adl i f f e r e n c e V b e t w e e nt h e m . Ti'i. ,-'iectric fieldstrengthbetweentheseplatesis givenby 47 V E- a V Thisquantity i (Unitsarevm-l) Gradient. ,talsocalledthe Potential for the parallel Hencethe potentialgradientis numericallyequalto the electricfield strength platearrangement. Pleasenote that the formula a E_ is usedto find the 4nesrz CHARGEONLY FIELDSTRENGTHFORA STATIONARYELECTRIC ELECTRIC a strengthin the FIELD is usedto findthe Electric \ a. regionbetweentwo chargedparallelmetalplates TheformulaE : i st h a t : A n o t h e rv e r yI M P O R T A NFTO R M U L A on Whenevera chargee is placedin a field that hasa field strengthE,the force that chargeis givenbY: p= EQ Hencefor a pair of parallelplatesthat are separatedby a distanced, and havinga potentialdifferenceV acrossthe plates,the force on a chargeQ that is placedin the spacebetweenthe platesis givenby: F: VQ d 48 ELECTRIC POTENTIAL : T h eE l e c t r i P c o t e n t i aal t a p o i n ti s d e f i n e da st h e w o r k d o n ei n b r i n g i n ga u n i t p o s i t i v ec h a r g e f r o m i n f i n i t yt o t h a t p o i n t . A t i n f i n i t yt ,h e e l e c t r i p c o t e n t i ai ls z e r os i n c et h e c h a r g ei s n o t u n d e r t h ei n f l u e n coef a n y f i e l d . C o n s i d e r au n i t p o s i t i v ec h a r g eb e i n gp l a c e di n t h e f i e l do f a n o t h e rp o s i t i v ec h a r g ea ss h o w n : B A s t h e p o s i t i v ec h a r g ei s m o v e df r o m p o i n tB w h i c hi s c o n s i d e r etdo b e a t i n f i n i t yt,o a p o i n tA i n t h e f i e l d ,w o r k h a st o b e d o n eo n t h e p o s i t i v e( + 1 C c) h a r g et o o v e r c o m e t h e f o r c eo f r e p u l s i o n b y t h e o t h e rp o s i t i v ec h a r g eQ + . T h i sw o r k d o n eo n t h e l - Cc h a r g ec a u s e a s nincrease i n i t s e l e c t r i cp o t e n t i ael n e r g yi n m o v i n g from infinityto A. T h i si n c r e a s e i n p o t e n t i ael n e r g yi s a s s i g n ead p o s i t i v ev a l u e . O n t h e o t h e rh a n d ,i f Q w a sa n e g a t i v e c h a r g et,h e n t h e i n c o m i n g+ 1 Cc h a r g ew o u l db e attractedto it, and it would loseits own electricpotentialenergyas it fallsfrom infinitytowards a. T h i sd e c r e a s e i n e l e c t r i cp o t e n t i ael n e r g yi s a s s i g n ead n e g a t i v ev a l u e . 49 Hence,at all pointsin the fieldof a positivecharge,the potentialis positive;and at all pointsin the fieldof a negativecharge,the potentialis negative. Potenttal: potenttal _ Work done per untt charge Electrtc potential Energy _ Work done chirge charge Let Potential= V V- + f or an isolated.charge *TEtsT When a chargeQ movesthrough a p.d. of V, the work done on the chargeis W = QV whichis equivalentto the Volt. The unit is the JC-1 QUANTITIES. BothPotentialand PotentialEnergyare SCALAR A v e r yu s e f u fl o r m u l at o r e m e m b e ri s t h a t : in electricpotentialenergyof a chargeQ when it is movedthrougha The CHANGE AV , is givenby A W= qAV. DIFFERENCE FOTENTIAL V is the differencein potentialsVr and Vz. DIFFERENCE The POTENTIAL of ENERGY in ElectricPotentialenergy is equalto the changein the KINETIC The CHANGE the charge.HenceA W= QAV=lmvz 2 where m is the massof the chargeand v is its speed. Note that smallv is speedand big V is potentialdifference. (Thesize of the future you actually experiencewill largely be determined by one factor: the people you choose to connect with. When you choosepeople who are truly committed to growth in every aspect of your life, your own potential for growth becomestruly unlimited--'---DanSullivan. 50 ELECTROSTATTCS (1) TUTORTAL SHEET ( 1 ) A h e l i u mn u c l e u s . h aasc h a r g eo f + 2 e a n da n e o nn u c l e u sh a sa c h a r g eo f + 1 0 e ,w h e r ee i s electroniccharge(1.6x 10 1eC) Findthe repulsive forceexertedon one by the otherwhen t h e y a r e3 n m a p a r ti n a v a c u u m (. A n s5 . 1 2 x 1 0 - 1 0 N ) (2) A chargeof 3;rCis 4mm awayfrom a chargeof 1.41tC in a vacuum.What is the electrostatic f o r c ea c t i n go n e a c ho f t h e c h a r g e s(?A n s 2 . 3 6x t 0 4 w ) (3) What is the distanceof separation of two pointcharges20pCand-45prC if the forceof a t t r a c t i o nb e t w e e nt h e m i s 1 5 N ?( A n s7 3 c m ) (4) Two identicalpointchargesare separatedby a distanceof 25cmand a forceof repulsionof 0 . 5 6 Na c t so n e a c hc h a r g eF. i n dt h e m a g n i t u d o e f e a c ho f t h e c h a r g e s( .A n s .L . 9 7 x1 0 6 C ) ( 5 ) T h r e ep o i n tc h a r r " , a r e p l a c e do n t h e x a x i sa ss h o w n .F i n dt h e n e t f o r c eo n t h e - 5 U C c h a r g ed u et o t h e o t h e rt w o . ( A n s . 0 . 6 2 5 N ) . ( HFi ni nt :dt h e f o r c ed u et o e a c hc h a r g e s e p a r a t e ltyh e n f i n d r e s u l t a n t ) -5uc 3uc 8pc ooo 20cm 30cm ( 6 ) F o rt h e s i t u a t i o ns h o w ni n t h e b e l o wd i a g r a mf,i n d (a)Theelectricfield at point P,(b)The forceon a -4 x 10-8C chargeplacedat P . -5x108C -20 x 10-"C ( A n s : 1 . 4 x 1 0 sN C - 1 ' t o w a r dtsh e l e f t ; 5 . 6 x t o 3 l v; ) 51 (7) A 20prC chargeas shown. chargeis placed50cmawayfrom a 60prC 50cm +€ (3<- 60PtC 20PrC D e t e r m i n et h e e l e c t r i cf i e l d s t r e n g t ht o g e t h e rw i t h i t s d i r e c t i o na t t h e f o l l o w i n gp o i n t s : ( i ) Exactlymidwaybetweenthe two charges. ( ii ) L0 cm to the left of the 20prC charge ( i i ) 4 0 c m t o t h e r i g h to f t h e 6 0 p Cc h a r g e ( A n s :5 . 7 6x L 0 6 N Ct-o1w a r d st h e l e f t ;1 . 9 5x 1 0 7 N Ct-ot w a r d st h e l e f t ; 3 . 6x 1 0 6 N C - l t o w a rtdhse r i g h t ) ( S ) A - 4 0 n C c h a r g e i s p l a c e d a t a d i s t aonf cl ,e2 c m a w a y f r o m a + 5 0 n C c h a r g e a s s h o w n . 1'2cm +g *.- +50nC -40nC D e t e r m i n teh e e l e c t r i cf i e l ds t r e n g t ht o g e t h e rw i t h i t s d i r e c t i o na t t h e f o l l o w i n gp o i n t s : (i) (ii) M i d w a yb e t w e e nt h e t w o c h a r g e s 5 c mt o t h e l e f t o f t h e - 4 0 n Cc h a r g e (iii) 8 c mt o t h e r i g h to f t h e + 5 0 n Cc h a r g e (Ans:2.25 -1 the right;6.13x l-04NC.1towards - 1w a r d st h e l e f t ;1. 2 8 x1 0 s N C towards x l - O s N Ct o the right) ( 9 . I) n t h e f o l l o w i n gd i a g r a mt,h e p o i n tA r e p r e s e n t sh e r e g i o nw h e r et h e r e s u l t a nfti e l d c h a r g e(.5 . 5 c m ) s t r e n g t hi s z e r o .D e t e r m i n teh e p o s i t i o no f p o i n tA r e l a t i v et o t h e - 2 0 p t C + 60;rC -10uC 52 ELECTROSTATTCS TUTORTAL (2) SHEET ( 1 ) T w o i d e n t i c am l e t a l b a l l sh a v ec h a r g e Q s l a n dq 2 T h er e p u l s i v e f o r ct h e a t o n e e x e r t so n t h e o t h e r w h e nt h e y a r e 2 0c m a p a r ti s 1 . 3 5x L 0 - 4N . l f t h e c h a r g eo n < i n eb a l ti s 3 . 2x L 0 6 c ,d e t e r m i n et h e c h a r g eo n t h e o t h e ro n e . ( A N 1 S, . g 7 s x1 0 - 1 0 c ) ( 2 ) W h a t i st h e m a g n i t u d o e f t h e c h a r g eo n e a c ho f t w o m e t a ls p h e r e si f t h e y h a v et h e s a m em a g n i t u d e o f c h a r g ea n d e x e r ta f o r c eo f a t t r a c t i o no f 1 . 9 8x L 0 - 4 N o n e a c ho t h e r w h e n t h e y a r es e p a r a t e b dy a d i s t a n c e o f 2 . 5c m . ( A N S 3nc) ( 3 ) T w o c h a r g e dm e t a lp l a t e si n a v a c u u ma r e 1 5 c m a p a r t .T h ep o t e n t i adl i f f e r e n c e b e t w e e nt h e p l a t e si s 2 0 0 V A . n e l e c t r o n( m a s s= 9 . i -x 1 0 - 3 1 kagn dc h a r g e1 . 6x L 0 - 1 e)C is r e l e a s e fdr o m r e s ta t t h e s u r f a c eo f t h e n e g a t i v e plate. F i n d( a )T h e E l e c t r ifci e l dt h e e l e c t r o ni s s u b j e c t e tdo . ( b )T h ea c c e l e r a t i bonf t h e e l e c t r o n ( c )T h et i m e t a k e nt o r e a c ht h e o t h e rp l a t e ( d ) T h es p e e do f t h e e l e c t r o nj u s t b e f o r ei t h i t st h e p o s i t i v ep l a t e . ( A n s ( a1) . 3 3x L 0 3 V mt ( u )2 . 3 4x 1 0 1 a m s('. ) 3 . 5x 1 - 0 - 8(sd;)g . 3 g xl - o 6 m 1s ) ( a ) W h a t i s t h e f o r c ee x p e r i e n c ebdy a p r o t o n( c h a r g e 1 = . 6x 1 0 - 1 e C w1h e n i t i s i n t h e s p a c e b e t w e e nt w o p a r a l l epl l a t e ss e p a r a t e b dy a d i s t a n c e o f 2 5 m ma n d h a v i n ga p . d .o f 5 0 O V 1 s N ; b e t w e e nt h e m (. A N S3 . 2x 1 0 ( 5 ) T w o i d e n t i c at li n y m e t a lb a l l sc a r r yc h a r g e o s f + 3 n C a n d- 1 , 2 n CT.h e ya r e 3 c ma p a r t . C a l c u l a tteh e f o r c eo f a t t r a c t i o n(.A N S3 . 6x L 0 - 4 N ) ( b )T h eb a l l sa r e n o w t o u c h e dt o g e t h e ra n dt h e n s e p a r a t etdo 3 c m .D e t e r m i n teh e f o r c e o n e a c hb a l ln o w . (H i n t ;W h e nt h e b a l l sa r e n o w t o u c h e dt o g e t h e rt,h e y a c q u i r et h e s a m ec h a r g ei . e . t o t acl h a r g ei s c o n s e r v e d ) ( A n s ( a ) 3 . 6 x1 0 o w( U )2 . 0 2 5 x1 0 4 Nr e p u l s i o n ) . ( 6 ) T w o i d e n t i c asl p h e r e sh a v ec h a r g e q . h e nt h e y a r e2 0 c m a p a r t ,t h e r e p u l s i v e s 1a n d q z . W 4 N . f o r c eb e t w e e nt h e m i s 1 . 3 5 x1 0 A f t e rt h e ya r et o u c h e dt o g e t h e ra, n ds e p a r a t e d . o n c ea g a i nt o 2 0 c m ,t h e r e p u l s i vfeo r c eb e t w e e nt h e m i s 1 . 4 0 6x 1 0 - o N F i n dQ l a n d q z( A n s 2: 0 n C , 3 0 n CS. )E ES O L U T I OONN p G5 4 . 53 Solutionfor question3: 0 . 15 m ; E - (t)V:200V;d:L\cm(tf.)Accelerati"on- Force MASS EQ MASS (ttt) Use the equatton .s_ ut l|or';1r V d 200v 0.1-5m (L\9: 200 x L . 6 x \d/ m 10-1e 0.15x9.1 x10-31 : 0 hencs e- - 3 . 5x 1 0 - 8 s (iv)U se ettlter v : 'tt * at or v2 : lr2 : Zas w h e r eu = 0 . 54 -7 : l-.33x 1.03Vm 1."8t : tot";t - 2 . 3 4x l g t a ^ r - z JT - x 1014 Solution for question6: - aflz l-9 -\ 1'0e- 1.35x 10-4A/ Initialty,g '' 4ft€sr2 (o.z)z H e n c e Q t Q z- 6 x -(1) 1g-togz W h e n t h e s p h e r e sa r e t o u c h e dt o g e t h e rt h e c h a r g e sa r e r e - d i s t r i b u t e db u t t h e t o t a l c h a r g ei s c o n s t a n ta n d e q u a lt o q r + Q z A f t e r t h e s p h e r e sa r e s e p a r a t e d e, a c h o n e w i l l a c q u i r ea c h a r g eo f Qr*Qz 2' (Since t h e s p h e r e sa r e i d e n t i c a tl h , e r ei s n o t e n d e n c yf o r o n et o g a i na g r e a t e rc h a r g et h a nt h e other.) T h ef o r c ea c t i n go n e a c hc h a r g en o w i s g i v e nb y (ry)'rexloe (0.2)' - 1 . 4 0 6x 1 0 - a ( q r + Q ) 2 - 2 . 5 x 1 0 - 1 s ; l t e n c e( q r + e z ) = 5 x 1 0 - B C -Q) F r o me q u a t i o n( 2 ) Q r =5 x l - 0 - 8g-z . S u b s t i t u t i n g t hi n i se q u a t i o n( 1 )g i v e s (5xL0-8 -a)Qz:6x10-16 Q z z- ( 5 x 1 0 - B )e z * ( 6 x t o - t o ) - 0 cives; S o l v i n tgh i sq u a d r a t i g 5x1o-B+( ) Qz: -3xl-0-BC:30nC; l f t h i sv a l u eo f q z i s s u b s t i t u t e idn e i t h e re q u a t i o n( 1 )o r ( 2 ) ,q 1w o u l db e f o u n dt o b e 2 0 n C . 55 Tutorialsheet(3) Electrostatics ( T h ec h a r g eo f a n e l e c t r o ni s - 1 . 6 x1 0 - 1 e C ) o f 5 m m ,t h e p . d . ( 1 ) F o rt w o c h a r g e dm e t a lp l a t e sA a n d B ,s e p a r a t e bd y a d i s t a n c e p o t e n t i aal n d p l a t eB t o a p o s i t i v e b e t w e e nt h e p l a t e si s 4 0 V .P l a t eA i s c o n n e c t e tdo a . a l c u l a tteh e w o r k d o n ei n m o v i n ga + 3 Cc h a r g ef r o m ( a )B t o A , ( b ) n e g a t i v ep o t e n t i a l C A to B. | 120J; -120J1 a fl a t 2 V b a t t e r y ( 2 ) H o w m u c hw o r k i s d o n e t o c a r r ya n e l e c t r o nf r o m t h e p o s i t i v e t e r m i n o 1 . 6 x ( A n s 1 . 9 x1 0 - 1 8 J 1 1 0 1 s C . t o t h e n e g a t i v tee r m i n a l .T h ec h a r g eo f t h e e l e c t r o ni s ( 3 ) A n e l e c t r o ns t a r t sf r o m r e s ta n df a l l st h r o u g ha p o t e n t i arl i s eo f 8 0 V .C a l c u l a tiet sf i n a l 1 ) { H i n tt :h e c h a n g ei n . . 3 x1 0 6 m s x g - 3 1(kAsn s 5 s p e e dT. h e m a s so f t h e e l e c t r o ni s 9 . 1 - 1 P . E=. c h a n g ei n K . E . ) l e t a lp l a t e sa r es e p a r a t e bdy a d i s t a n c eo f 4 . 5 f f i f f i ,a n d a p . d o f 1 2 0 0 V i s ( 4 ) T w o p a r a l l em -1.6x 10-1sc) a p p l i e da c r o s tsh e r i r .( m a s so f e l e c t r o n= 9 . 1 - x1 . 0 - 3 1 kcgh, a r g e= (i) (ii) (iii) (iv) (v) W h a t i s t h e v a l u eo f t h e e l e c t r i cf i e l db e t w e e nt h e p l a t e s ? l f a n e l e c t r o nt h a t i s h e l da t r e s ta t t h e n e g a t i v ep l a t ei s s u d d e n l rye l e a s e dw, h a t o f t h e e l e c t r o n 'as c c e l e r a t i o n ? w o u l db e t h e m a g n i t u d e W h a tw o u l db e t h e c h a n g ei n t h e e l e c t r o n ' ps o t e n t i ael n e r g y ? W h a tw i l l b e t h e e l e c t r o n 'ssp e e da s i t h i t st h e p o s i t i v ep l a t e ? H o w l o n gw o u l dt h e e l e c t r o nh a v et a k e nt o c r o s sf o r m o n e p l a t et o t h e o t h e r ? 1; ; 8 x1 0 - 1 0 s . ( A n s :z . O l x l g s v m 4 . 6 8 x1 0 1 6 m s; I-.29 2 x 1 0 - 1 62J.;O Sx L O T m s -41. 3 a p a r t .W h e nt h e y a r e r e l e a s e d , ( 5 ) T w o p r o t o n sa r e h e l da t r e s ta t a s e p a r a t i oonf 3 x 1 0 - 1 2 m t h e y r e p e le a c ho t h e ra n d m o v ea p a r t .H o wf a s tw i l l t h e y b e m o v i n gw h e nt h e y a r e ( i )8 m m a p a r t ( i i )a p m a p a r t , (iii)5pa mp a r t . 27kg' = 1.6x101eC; mass= !.67x10 Protoncharge s e p a r a t i oann dt h e n a t t h e 8 m m H i n t y: o un e e dt o f i n dt h ep o t e n t i af ilr s t l ya t t h e3 x L 0 - 1 2 m ee t w e e n e f t h e s et w o p o t e n t i a liss t h e p o t e n t i adl i f f e r e n c b s e p a r a t i o nT.h ed i f f e r e n c o Vn) d e q u a t et h i st o K . E >t o f i n d t h e s et w o p o i n t .T h e nf i n d t h e c h a n g ei n P . E . ( W = Q a speed. r; ( A n s 2 . I 4 x 1 0 s m s 1 ' . 0 x7 l O s m s - 1 ; 1 . 3 5l -60xs m s - 1 ) 56 ( 6 ) T w o p o i n t sA a n d B a r e a t L 0 0 c ma p a r t .A c h a r g eq r = 2 0 0 p ci s p l a c e da t A w h i l e a c h a r g eQ z =- 1 0 0 p Ci s p l a c e da t B . P o i n tC i s o n t h e l i n eA B a n d i s 2 0 c m a w a yf r o m B a n d p o i n t D i s a l s oo. n A B a n d i s 2 0 c m a w a yf r o m A . ( a )F i n dt h e p o t e n t i a l as t C a n d a t D . ( b ) How muchwork must be doneto transfera -5001.rC chargefrom C to D ( A n s .-:2 . 2 5 V; 7 . 8 7 5 V ;- 5 . 1 xl - 0 - 3 J ) Qr=2ooPC Q z =- 1 0 O P C 2Ocm 20cm _____+B c<#*r nrr-D ^\J- 100cm (7) Fourpointchargesare placedat the four cornersof a squarethat is 30 cm on eachside. Findthe potentialat the centreof the squareif eachchargeis 2pC. (Ans.:3.4x10sV) (8) Charges of +21tC,+3pC and -SpCare placedat the verticesof an equilateraltriangle of -8pC side10cm. Calculate the magnitudeof the forceactingon the chargedue to the othertwo charges.) Hint Drawa vectordiagramand resolvethe forcesverticallyand horizontally, then find the total verticaland the total horizontalforces. Afterthis,use Pythagoras'Theorem. ) (Ans31N) ( 9 ) F o u re q u a lp o i n tc h a r g e + a r e p l a c e da t t h e f o u r c o r n e r so f a s q u a r et h a t i s 4 0 t m o n s3prC : .97N a s i d e .F i n dt h e f o r c eo n a n yo n e o f t h e c h a r g e ds u et o t h e o t h e rt h r e e .( A n s 0 o u t w a r da l o n ga d i a g o n a H l ) i n tu s et h e s a m et e c h n i q u a e s i n t h e p r e v i o uqs u e s t i o n 57 l f t h e + 3 Cc h a r g eh a st o b e m o v e df r o m B t o A , i t m u s tb e p u s h e da g a i n stth e f o r c eo f r e p u l s i o n f r o m t h e p o s i t i v ec h a r g e f o r q u e s t i o n1 : Solution o n p l a t eA . T h i sm e a n st h e nt h a t w o r k m u s tb e d o n eO Nt h e +++++++++++++++ c h a r g ea s i t i s m o v e df r o m B t o A . 5mm R e c a ltlh a t w o r k d o n e= Q V W = 3 Cx 4 0 V = 1 2 0 J . l f t h e c h a r g el s m o v e df r o m A t o B ,t h e n n o e n e r g yn e e d st o b e a d d e dt o t h e c h a r g eI.n t h i ss i t u a t i o nt,h e c h a r g el o s e si t s o w n E l e c t r i c aplo t e n t i ael n e r g ya s i t i s a t t r a c t e dt o p l a t eB .T h i sl o s s o f P Ei s g i v e na n e g a t i v es i g ns o t h e w o r k d o n ef r o m A t o B i s t20J. Solutionfor question2: UseW =QV Solutionfor question4: (i) E - \ :d (ii) F o rc eac c el e ra tto n - (iii) A P E =Q V =1 . 6x 1 0 (iv) -!^u';v T h el o s si n P E =i n c r e a sien K E ;H e n c e1 , . 9 2 x 1 0 - 1 6 (v) UsetheequationofmotionV=u*dt,t-,+-ffi=4'38x].0-1os , # 4 .-5:x 1 0 - 2 . 6 7x 1 0 sV m - 1 Eq - vq d xmass 16J lex 1 2 0 0 =I . 9 2 x L 0 58 L2aoxL.6x1o-1e 4 . Sx 1 0 - 3 x 9 . 1 x 1 0 - 1 e : 4 . 6 8x ! 0 1 6 m s - 2 : 2 . 0 5 x 1 0 7 m s1 S o l u t i o nf o r q u e s t i o n5 : a p a r t ,t h e I n t h i sq u e s t i o nu s et h e f a c tt h a t t h e l o s so f P E= G a i no f K E .W h e nt h e p r o t o n sa r e 3 x 1 0 - 1 2 m i s g i v e n0 V , f f i . I n t h i s c d s eQ 1= Q 2 =1 . 6x 1 0 - 1 s C . P o t e n t i ael n e r g yo f t h e S Y S T E M = HencePEof system (t u'11 'llx(r'axro-'n) -: -i ' 6 8 x 1 ' 0 - 1 7 J +n'o*z'to- n f 8 m m ,t h e n e w PEof the systemis givenby W h e nt h e c h a r g e sm o v eo u t w a r d st o a s e p a r a t i o o ( 1 . 6x 1 0 - 1 e )x ( 1 . 6x 1 0 - 1 e ) = Z . B Bx 1 , 0 - 2 6 J 4nesxBx10-3 PE2 - N o t et h a t t h i sn e w P Ei s s e v e r am l i l l i o nt i m e sl e s st h a nt h e o r i g i n aPl Ea n d h e n c et h e c h a n g ei n P Ew h i c hc a n 17J 7.68x LO be lvrittenas Af E=PE1-PE2= F r o mt h e c o n s e r v a t i oonf e n e r g yt h e l o s so f P E= G a i no f K E , b u t t h i st o t a l K Ei s s h a r e de q u a l l ya m o n gt h e l a s sa n d c h a r g e . t w o p r o t o n ss i n c et h e y h a v ei d e n t i c am S ow e c a nw r i t e , ) m v ' + ) m u 2 = 7 . 6 8 x t 0 - 1 7J o r m v 2 : 7 . 6 8 x 1 0 - 1 7 7.68 x L0-17 7.68 x 1,0-17 a ,r2 - L . 6 7 x ! 0 - 2 7k g : 4 . 5 8x 1 0 1 o 4 . 5 8x 1 0 1 0: 2 . ! 4 x 1 0 s m s - 1 T h es a m em e t h o di s e m p l o y e df o r p a r t s( i i )a n d ( i i i ) S o l u t i o nf o r q u e s t i o n6 : Q z =- 1 0 0 P C Qr=200PC 2ocm nA{#n ALJj-- 20cm C n n B 100cm F i n d i n tgh e p o t e n t i aal t D : 'Firstly f i n d t h e p o t e n t i aal t D u et o t h e c h a r g ea t A O N L Y : t/-h' 200x1.0-12x9x1-0e 0.2 4tegr1 :9V The Potentiaa l t D d u e t o t h e c h a r g ea t B o n l y : vz: Qz -100x1,0-12x9x10e : -1,.725V 4rcesr2 0.8 T h ep o t e n t i aal t D i s : h e nf o u n db y a d d i n gV 1a n dV 2; V1 *V2= 9 V + ( - 1 . 1 2 5 V )7=. 8 7 5 V 59 T h ep o t e n t i aal t C i s f o u n di n a s i m i l aw r a y ,i . e . ( P o t e n t i aal t C d u e t o t h e 2 0 0 p Cc h a r g eo n l y) + ( P o t e n t i a l aCt d u et o - 1 0 0 p Cc h a r g eo n l y ) . 2 0 0 x L 0 - 1 2x 9 x 1 0 e I -100 x!0-12 x9 x 10e 0.8 02 2.25V ( i i i )l n t r a n s f e r r i nag - 5 0 0; r Cc h a r g ef r o m C t o D , i t i s n e c e s s a rt yo f i r s tf i n dt h e P O T E N T I A L differencb e e t w e e nC a n d D , V D- V c : 7 . 8 7 5 V- ( - 2 , 2 5 V ) : 1 0 . 1 2 5 V T h ew o r k d o n e ' w h e na c h a r g eQ m o v e st h r o u g ha p o t e n t i adl i f f e r e n c e V i s g i v e nb y W = Q V ; . H e n c eW - - 5 0 0 x 1 0 b x ( 1 0 . 1 2 5 V ) =5-. 0 6x 1 0 3 JT h e n e g a t i v es i g ni n d i c a t etsh a t t h e - 5 0 0 p Cc h a r g el o s e s P Ea s i t g o e sf r o m a n e g a t i v ep o t e n t i atlo a p o s i t i v ep o t e n t i a Solutionfor Question7: 30cm A t t h e c e n t r eo f t h e s q u a r ei,t i s n e c e s s a rtyo f i n d t h e d i s t a n c e b e t w e e na n yo n e o f t h e c h a r g ea n dt h e c e n t r ep o i n t . 1 U s i n gP y t h a g o r a s ' T h e o r etm h i,s d i s t a n c ei s f r 5 2 + 1 5 2 - ^,l4so- 2r.zcm. J T h e p o t e n t i adl u e t o E A C Hc h a r g ei s t h e n f o u n df r o m - 2x10--6-x9xloe =8.5 xro4v rQ' 4rc€sr1 0.212 T h e p o t e n t i aol f a l l f o u r c h a r g e sw o u l dt h e n b e 4 x 8 . 5 x 1 0 4 Vv 'j - 30cm | 3 . 4 vx l o s Z 60 CAPACITORS A c a p a c i t oirs a d e v i c et h a t i s u s e dt o s t o r ee l e c t r i c h a r g eT. h i ss t o r e dc h a r g e c a nt h e n b e u s e d w h e na r e l a t i v e llya r g eb u r s to f c h a r g ei s r e q u i r e de . g . t o s t a r ta m o t o r . t, o a c t i v a t e a camera flasho , r t o s w i t c ho n a f l u o r e s c e nt u t be. T h es t o r e dc h a r g ec a na l s ob e a l l o w e dt o b e r e l e a s e sdl o w l y t h r o u g ah r e s i s t o r in a smoothing c i r c u i ta, n dt h i s h a sp r a c t i c aal p p l i c a t i o ni n s c o n v e r t i n ag r e c t i f i e da l t e r n a t i ncgu r r e n ti n t oa n a l m o s tc o n s t a ndt i r e c tc u r r e n t . C a p a c i t o rcso n s i sot f t w o m e t a ls h e e t ss e p a r a t e bd y a n i n s u l a t o rT. h ei n s u l a t o r i s c a l l e dt h e DIELECTRIC. T h ew h o l ea r r a n g e m e notf t h e m e t a ls h e e t sw i t h t h e d i e l e c t r iicn b e t w e e n ,i s t h e n r o l l e di n t o a s m a l tl i g h tc y l i n d ear n ds e a l e di n a c a s ew i t h t w o t e r m i n a les x t e n d i nogu t . T h eC A P A C I T A N C o fEa c a p a c i t oirs g i v e nb y t h e e q u a t i o nc _ 3 W h e r eQ i s t h e c h a r g es t o r 6 da n dV i s t h e p o t e n t i adl i f f e r e n c b e e t w e e nt h e p l a t e s . Capacitance is definedas the chargerequiredto causeunit changein potentialdifference betweenthe plates. T h eu n i t o f c a p a c i t a n ci set h e F a r a d( F ). T h e F a r a di s d e f i n e da st h e c a p a c i t a n coef a c a p a c i t oirf a c h a r g eo f 1 Cc a u s e s a c h a n g eo f 1 V b e t w e e nt h e p l a t e s . T h ef a r a di s a n e x t r e m e l yl a r g ec a p a c i t a n caen, dt y p i c a cl a p a c i t o risn h o u s e h o l d a p p l i a n c easr e r a t e di n m i l l i - f a r a d(sm F )o r m i c r o - f a r a c i s ( p F ) . 6I CAPACITANCE: AFFECTING FACTORS d the F o rt w o p a r a l l epl l a t e sh a v i n ga n a r e ao f o v e r l a pA a n d s e p a r a t e bd y a d i s t a n c e c a p a c i t a n coef t h e p a r a l l epl l a t ec a p a c i t oirs g i v e nb y : C : 4 d Wheree is the permitivityof the medium,ORdielectricconstantof the medium. lf the spacebetweenthe platesis a vacuumthen we write : C : I A l yh e nt h e s p a c eb e t w e e nt h e p l a t e si s f i l l e dw i t h T h ec a p a c i t a n ci n e c r e a s essi g n i f i c a n tw i n s u l a t i nm g a t e r i asl u c ha s p o l y s t y r e noer g l a s so r p o l y t h e n e . is determinedby 3 factorsi.e Hencethe maghitudeof the Capacitance ( i ) T h ed i e l e c t r icco n s t a not f t h e m a t e r i abl e t w e e nt h e p l a t e s , ( i i ) T h eA r e ao f o v e r l a po f t h e p l a t e sa n d (iii)The o f s e p a r a t i oonf t h e p l a t e s . distance 62 DIELECTRICS RelativePermitivity: T h i si s t h e r a t i oo f t h e c a p a c i t a n cwei t h a n dw i t h o u t t h ed i e l e c t r ibc e t w e e n the plates. T h e r e l a t i v ep e r m i t t i v i t iys d e n o t e db y t h e s y m b o le , . a n di s g i v e nb y t h e t -' : or tr:; equation: Cap aci"tance w tth die lectr ic Capaci"tancewith vacuum ca D i e l e c t r i ccsa na l s ob e c l a s s i f i eadc c o r d i ntgo t h e i r D I E L E C T Rs ITcR E N G T H S . The DIELECTRIC STRENGTH of any materialis the electricfieldstrengthor potentialgradientat w h i c hi t s i n s u l a t i o bn r e a k sd o w n a n d i t b e g i n st o c o n d u c b t y a l l o w i n gs p a r k st o t r a v e lt h r o u g h it. T h ef o l l o w i n gt a b l eg i v e s6 o m et y p i c a dl i e l e c t r i ct so g e t h e rw i t h t h e i r c o r r e s p o n d i nr g elative p e r m i t i v i t i easn d d i e l e c t r isct r e n g t h sw , h i c hy o u M U S TL E A R N . MATERIAL R E L A T I VPEE R M I T I V I T DIELECTRIC Y STRENGTH ( n ou n i t s ) Air ParaffinWax Gl a s s M ica ( K i l o v o l tpse r m m ) 1.005 2 15-50 5-10 30-150 6 80- 200 Water 81 lce 94 63 lmportanceof the Dielectric T h eD I E L E C T RhIaCst h r e ev e r yi m p o r t a nftu n c t i o n sT. h e ya r e : (1) lt servesto keepthe platesat a smallconstantfixed distanceapart. (2) lt allowsthe capacitorto acquirea much highervoltagewhilst reducingthe possibility o f s p a r k i n gl.f t h e r ew a s n o d i e l e c t r ipc r e s e n tt,h e a i r b e t w e e nt h e p l a t e sw o u l db e c o m e i o n i z e dw h e n a s u f f i c i e n t lhyi g hv o l t a g ei s a p p l i e da, n d s p a r k sw o u l db e p r o d u c e da s o m t h e a i r m o l e c u l etso t h e p o s i t i v e lcyh a r g e dp l a t e sa n d p o s i t i v e e l e c t r o n s . m i g r af rt e i o n sm i g r a t et o t h e n e g a t i v e lcyh a r g e dp l a t e .A t t h i s p o i n t ,t h e a i r i s s a i dt o b e a n dt h e v o l t a g ea t w h i c ht h i so c c u r si,s c a l l e dt h e b r e a k d o w n e x p e r i e n c i nbgr e a k d o w n voltage. D i e l e c t r i ccsa nw i t h s t a n dm u c hh i g h e re l e c t r i cf i e l d st h a n a i r b e f o r ea n yc o n d u c t i o cna n t a k ep l a c eb e t w e e nt h e p l a t e si.. e .t h e d i e l e c t r i chsa v ea m u c hh i g h e rb r e a k d o w n v o l t a g et h a nt h a t o f a i r . ( 3 ) T h e d i e l e c t r i icn c r e a s etsh e c a p a c i t a n coef t h e c a p a c i t o rA. n y a i r f i l l e d . c a p a c i two irl l r i m e n s i o nasn d e a t i s m a n yt i m e sl o w e rt h a na n o t h e ro n e o f s i m i l a d h a v ea c a p a c i t a n ct h m a t e r i a ltsh a t h a sa d i e l e c t r ibc e t w e e nt h e p l a t e sT. h em o l e c u l eisn t h e d i e l e c t r i c m a t e r i aal c q u i r ei n d u c e dc h a r g eds u et o t h e c h a r g eosn t h e p l a t e s . c o l e c u l e as c q u i r ea p o s i t i v ec h a r g eo n S i n c et h e d i e l e c t r i m o n e e n d a n d a n e g a t i v ec h a r g eo n t h e o t h e re n d ,i t i s s a i dt o bepolarized. f e d i e l e c t r i ca,d j a c e ntto t h e T h ec h a r g e so n t h e s u r f a c e . ot h p l a t e sa r e o f o p p o s i t es i g nt o t h o s eo n t h e p l a t e sa, n d a s a h e p o t e n t i adl i f f e r e n c eb e t w e e nt h e r e s u l t h e y R E D U CtE plates. F r o mt h e f o r m u l a : c- ?,"decreaseinV would causean tncreasetn C ( S i n c et h e t o t a l c h a r g eQ i s c o n s e r v e d ) 64 Capacitors in Series: Vr V2 -olo V3 -lo C2 V1 A c h a r g eo f - Q l e a v e st h e n e g a t i v tee r m i n a ol f t h e b a t t e r ya n d a c h a r g eo f + q l e a v e st h e p o s i t i v et e r m i n a l H . e n c em a t h e m a t i c a ltlhye n e t c h a r g el e a v i n g t h e b a t t e r yi s z e r o ,a n d s i n c e t h e c h a r g eo s n t h e p l a t e so f t h e c a p a c i t oar r e+ Q a n d- e , t h e n e t c h a r g eo n e a c hc a p a c i t oirs zero. T h i si n d i c a t etsh a t c h a r g e ' icso n s e r v esdi n c eT O T A LC H A R GlE eaving t h e b a t t e r y= T O T A L C H A R GaEc q u i r e b d yt h ec a p a c i t o r s . T h ea c t i o no f t h e c a p a c i t oirs t h e n r e a l l yt o s e p a r a t teh e n e g a t i v e c h a r g e fsr o m t h e p o s i t i v e ones. F o r c o n v e n i e n ci ne c a l c u l a t i o nt sh ,e c h a r g eo n o n e p l a t ei s c o n s i d e r e id. .e .l f a c h a r g eo f + e a c c u m u l a t eosn t h e p o s i t i v ep l a t ea n da c h a r g eo f - Q a c c u m u l a t eos n t h e n e g a t i v ep l a t e t, h e n i n t h e c a l c u l a t i oanc h a r g eo f Q i s u s e d T . h es i g no f t h e c h a r g ei s n o t i m p o r t a n t . H e n c ef o r t h e s e r i e sc i r c u i ta b o v et,h e c h a r g eo n e a c hc a p a c i t oirs Q a n d t h e t o t a lc h a r g e leaving t h e b a t t e r yi s a l s oQ . l f V 1 , V z , d n d V 3 r e p r e s e n t h e v o l t a g e sa c r o s sC t , C z a n dC 3r e s p e c t i v e l yt ,h e n b y t h e Vr - v1 + Vz + V: c o N S E R V A T I OO N F E NE R G y , But Ilence Vr :: n Y L7 - v- 0 C a a,Q, C7 tl tl C2 C. _ J i f w e d i v i d et h e i a t : e re q u a t i o nb y q t h e n w e g e t : 65 11,,1_,L C7 Cr'Cr'C= Capacitorst n P a r a l l e l : V of charge,the total chargeQ 1 leavingthe battery,is equalto the sum of Bythe conservation t h e c h a r g ea s c c u m u l a t i nogn t h e c a p a c i t o r s . Therefore,Qr = Qr +Q2+Q3l of energy,the voltagesacross loop rulewhichis a statementof the conservation By Kirchoff's e a c hc a p a c i t oirs t h e s a m ea n d i s e q u a lt o t h e b a t t e r yv o l t a g e . S i n c eQ = ! V , t h e n Q r = C r V ; Q z= C z V ; a n dQ : = C i V Q, =CrV=C1V+CzV+CgV W h e n3 c a p a c i t o rasr ec o n n e c t e idn P a r a l l etlh, e t o t a l is givenby Cr= Cr+ C,+ C, capacitance 66 ENERGY STORED IN A CAPACITOR Energycanbe storedin a capacitorvia a batteryin the f o l l o w i ncgi r c u i t : I n t h e g r a p ho f V v e r s u sQ , t h e a r e au n d e rt h e g r a p h represents the energystored in the capacitor a W h e nt h e c a p a c i t ohr a si n i t i a l l yz e r oc h a r g eo n i t , t h e p o t e n t i adl i f t e r e n c b e e t w e e np o i n t s A a n d B i s V . i . e .t h e p . d .b e t w e e nt h e p o s i t i v ep o l eo f t h e b a t t e r ya n dt h e u n c h a r g elde f t p l a t ei s V. Hencethe chargesINITIALLY passthrougha potentialdifferenceof V volts. A s t h e c a p a c i t oar c q u i r e s . n . r r " ,t h e p o t e n t i aol n t h e l e f t p l a t er i s e sf r o m 0 + Vil Vz+ Vs etc. The potentialdifferencethat the chargepassesthrough will therrefore DECREASE from -------0 V + (V -vr)---+ (V - Vz), + etc.untilthe pointwherethe batteryvoltageis e q u a lt o t h e c a p a c i t ovro l t a g ew , h i c hc a u s e tsh e p . d .b e t w e e nt h e b a t t e r ya n d c a p a c i t otro b e zero. Duringthe entirechargingprocess, the potentialdifferencethat the chargepasses through, would havechangedfrom V to zero.Hencethe AVERAGE potentialdifferencethat the total c h a r g eQ p a s s etsh r o u g ,hr t T -f, T h ew o r k d o n ei n m o v i n ga c h a r g eQ t h r o u g ha n a v e r a g ep o t e n t i adl i f f e r e n c o e f Y is givenby 2 W:V 2 T h ew o r k d o n ei n m o v i n gt h e c h a r g ei s e q u a lt o t h e e n e r g ys t o r e di n t h e c a p a c i t o r S u b s t i t u t i nC g = o | givesthree usefulequationsfor energystoredin the capacitor; - ---Q2 w- QV 22C2 Y o um u s tl e a r nt h e s ee q u a t i o n s ! ! ! ! ! 67 CVz C a p a c i t oQr u e s t i o n s ( 1 ) F i n dt h e e q u i v a l e ncta p a c i t a n ci n e e a c hc a s e : (i) r-IHH 471tF A n s7 . 6 2 p r F 100prF 10;tF 100uF (ii) 108.25;rF :f 10uF 47p,F 80prF ]H 20prF A n s1 1 6 U F 100prF 80prF Ans.200;rF ( 2 )T h et e r m i n a l sa t A a n d B a r e n o w c o n n e c t e tdo a 2 0 Vs o u r c ei n e a c hc a s e R . e d r a we a c h c a p a c i t o(rb )T h e c i r c u i t o i n c l rJ e t h e p o w e rs u p p l ya, n df i n d ( a ) T h ep . d .a c r o s sE A C H c h a r g es t o r e di n E A C Hc a p a c i t o ra n d ( c )T h eenergystoredin EACHcapacitor. 68 20v (1) V + z: 3 . 2 4 V ; V r c o : 1 , . 5 2 V ; V r-c I S . Z 4 V Q + z: Q r c : 0 r o o - I . S 2 x 1 , 0 - 4 C E+z=2.45x1.0-4J E r . o o_ 1 , 1 5x 1 0 - 4 J 471tF 1009F 10pF El,o:1'15x10-3J 100sF V r c o: 2 0 V ; V t o= 1 , 6 . 5 V ; V +: z 3 . S V (2) Q r c o_ 2 x 1 , 0 - 3 c Q+z=Qrc:1.65x1'0-4C Erco_ 0.02J E + z: 2 . 9 x L 0 - 4 J 20v 80uF E t : 1 . 3 6x 1 0 - 2 J 201tF Veo: 4V; V2s- 16V; Vlss : 20V Q e o: Q z o: 3 . 2 x i . 0 - 4 C Q r o o_ 2 x . 1 , 0 - 3 C 100pF E e o= 6 . 4 x 1 0 - 4 J Ezo:2.56x1,0-3J Erco_Z.0xI0-2J 20v 69 A CAPACITOR. AND DISCHARGING CHARGING it acrossa resistoras shown: d connecting A c a p a c i t oirs n o r m a l l yd i s c h a r g eby C R d e c r e a s ewsi t h t i m e ,a n d h e n c et h e c h a r g e s t o r e d R a c r o s s d i s c h a r g e s ,its A st h e c a p a c i t o r e i t ht i m e . t i l l a l s od e c r e a sw o f t h e c u r r e n ti n t h e c i r c u i w magnitude and of currentdependson the magnitudeof the productof resistance The rateof decrease c a p a c i t a n c ie. e , o n t h e v a l u eo f R C . T h eq u a n t i t yR Ci s c a l l e dt h e T I M EC O N S T A N Ta n d h a su n i t so f s e c o n d s . Hence 10 x 1F= lsecond . = D u r i n gt h e d i s c h a r g et h, e c u r r e n th a st h e m a x i m u mv a l u el oa t t i m e 0 . "/nc o f t h e c u r r e n ta t a n yt i m e t , i s g i v e nb y / = l o € T h em a g n i t u d e -ft S i m i l a r lfyo r c h a r g eQ a t a n Yt i m e t ; Q - Qse-tl*c Thevoltagea t a n y t i m e t d u r i n gd i s c h a r g ei s g i v e n b y : V : Vor-tlnc following Thegraphsof eithervoltagev . st i l T € i ,c u r r e n vt . s .t i m e o r c h a r g ev . s .t i m e h a v et h e shapefor DISCHARGE "/nc I : Ioe -ft (V,l, or Q) -/nc -ft Q - Qoe -/nc V - Voe -ft time 70 CHARGtNG OFA CAPACTTOE W h e na c a p a c i t oirs b e i n gC H A R G E D t h e V O L T A Ga En d C H A R G E i n c r e a sw e i t h t i m e u n t i lt h e y r e a c ha m a x i m u mv a l u e T . h ec u r r e n th o w e v e rd, e c r e a s ewsi t h t i m e a n d h a st h e s a m es h a p ef o r discharging. Voltage c ur r e n t charge time -fr I : Ioe "/RC Q - Q o( 1 - e - t / n c ) V - Vo(I - ,-t /nc) N o t et h e d i f f e r e n c eisn e q u a t i o n fso r charging a n dd i s c h a r g i n T g .h eV o , Q o a n d l ev a l u e sr e p r e s e nt th e m a x i m u m v a l u e si n t h i sc a s e . time 7t C O M P A R I S OONFC H A R G I NAGN D D I S C H A R G I N G c a . s e:s C o n s i d et rw o s e p a r a t e t o a v o l t a g eo f 2 0 V a n dt h e n m a d et o ( 1 ) A c a p a c i t ohr a v i n ga c a p a c i t a n coef 2 5 p r iFs c h a r g e d d i s c h a r gteh r o u g ha 5 0 k Or e s i s t o rD. e t e r m i n teh e t i m e t a k e nf o r t h e p . d .a c r o s tsh e c a p a c i t o r t o f al l t o 5 V . a n dt h e p . d .a c r o s ist i s 5 V .l t i s ( 2 )A c a p a c i t ohra v i n ga c a p a c i t a n coef 2 5 ; r Fi s p a r t i a l lcyh a r g e d t h e n c h a r g e dt h r o u g ha 5 0 k Or e s i s t otro a p . d .o f 2 0 V .D e t e r m i n teh e t i m e t a k e nf o r t h i s process. charging l n t h e f i r s tc a s e tlnc, V - Voe -t / 51 v v -RC :1..73s (-s0000 x 25x 10-t)(r"^) r"uot t"% -# ; l n t h e s e c o n dc a s e , tlnc) V - Vo(I - e V' -r, Vo / 5t tn(r-fi) - / 7\ \ vo/ -tr / I/l -t \ Vo/ RC -t soooffi; r : 5 0 0 00 x 2 5 x 1 0 - 6x l n ( 0. 7 5 ) : 0 . 3 6 s from20Vto 5Vis for discharging thatthe time required Th" resultsindicate throughthe samepotentialdifference. totallydifferentfromthat for charging 72 Significance of the TimeConstant R e c a lt lh a t f o r D I S C H A R G I N t hGe,V o l t a g ea t a n yi n s t a n it s g i v e nb y : V : V o r - t l * r , w h e r eR Ci s t h e T i m eC o n s t a n t l f w e c o n s i d ear t i m e t w h e r et = R Ct,h e nt h e e q u a t i o nb e c o m e s : V - V o e "- 1 ' o, r v - - V o ev Thisequationtellsus that the TimeConstantis the time for whichthe potential differenceacrossthe capacitorfallsto 1of its initialvalueduringa discharge. e 11, T h e u a l u eo f e - 2 . 7 1 8 , h e n c e 0.368 ; LTIBHencewhen t : CR, V : 0.36BVo A f t e ra p p r o x i m a t e 3 l yt i m e c o n s t a n t st h, e c a p a c i troi s o l m o sct o m p l e t e ldy i s c h a r g e d . T h i sc a nb e d e m o n s t r a t eadsf o l l o w sw h e nt = 3 C R V - V o e - = ; V : 0 . 0 5 7 0w h i c h i . sc l o s et o z e r o . S i m i l a r lfyo r t h e c h a r g i npgr o c e s s V -Vo(I -e tlnc);wheftt:3RC, V -VoI-e-3); H e n c ea f t e r3 t i m e c o n s t a n ttsh e c a p a c i t oirs a l m o s tf u l l yc h a r g e d . 73 V - 0.9SI/0 SHEET TUTORIAL DISCHARGE CAPACITOR t o 6 V a n dt h e n m a d et o d i s c h a r gaec r o s sa L 2 0 k Qr e s i s t o r . ( 1 ) A 5 0 p Fc a p a c i t oirs c h a r g e d C a l c u l a t:e ( i )T h et i m e c o n s t a not f t h e d i s c h a r gcei r c u i t ( i i ) T h et i m e st h a t w o u l dh a v ee l a p s e fdo r t h e p . d .a c r o s tsh e c a p a c i t o r t foa l lt o 3 V a n d 1 V ( i i i )T h ec h a r g et h a t w o u l dh a v ef l o w e dt h r o u g ht h e r e s i s t oar f t e r5 s e c o n d s ( i v )T h ee n e r g yd i s s i p a t ebdy t h e r e s i s t oar f t e r2 s e c o n d s . ( H i n t ; f itnhde i n i t i ael n e r g ya n d , e n f i n dt h e d i f f e r e n c e ) t h e n t h e e n e r g ya f t e r2 s e c o n d st h 4t.) t.7 x 10-4C (Ans:6s;4.1,6s;1'0.75s; ; 4.4 x tO ( 2 ) A 1 0 O 0 p cFa p a c i t oirs c h a r g e dt o 1 2 Va n dt h e n m a d et o d i s c h a r gaec r o s sa L . 5 M O resistor. C a l c u l a t:e ( i )T h et i m e c o n s t a not f t h e d i s c h a r gcei r c u i t f o r t h e p . d .a c r o s st h e c a p a c i t otro f a l lt o 9 V ,6 V ( i i )T h et i m e st h a t w o u l dh a v ee l a p s e d ' and l-V ( i i i )T h ec h a r g et h a t w o u l dh a v ef l o w e dt h r o u g ht h e r e s i s t oar f t e r8 7 5 s e c o n d s s n dt h e c u r r e n ti n t h e c i r c u i t ( i v )T h ee n e r g yd i s s i p a t ebdy t h e r e s i s t oar f t e r2 0 0s e c o n d a at thatinstant (v) T h ep . d .a c r o s st h e c a p a c i t oar f t e r3 0 0 s 1,.7xIOZJ;7 x10-6A;9.82V) 3727s;5.3x1-0-3s; (Ans:1500s;432s;1040s; t o 8 V a n dt h e n m a d et o d i s c h a r gaec r o s sa 3 0 0 k O ( 3 ) A 2 5 0 0 p rcFa p a c i t oirs c h a r g e d resistor. C a l c u l a t:e ( i )T h et i m e c o n s t a not f t h e d i s c h a r gcei r c u i t f o r t h e p . d .a c r o s st h e c a p a c i t otro f a l lt o O Va n d ( i i )T h et i m e st h a t w o u l dh a v ee l a p s e d 4V ( i i i )T h ec h a r g et h a t w o u l dh a v ef l o w e dt h r o u g ht h e r e s i s t oar f t e r5 0 0 s e c o n d s ( i v )T h ee n e r g yd i s s i p a t ebdy t h e r e s i s t oar f t e r5 0 0s e c o n d s (750s;2t6s;520s;0.01C;0.06J ) 74 (4) A 1500;rFcapacitoris chargedto 6V andthen madeto discharge acrossa 800kO resistor. C a l c u l a t:e ( i )T h et i m e c o n s t a not f t h e d i s c h a r gcei r c u i t ( i i )T h et i m e t h a t w o u l dh a v ee l a p s e d f o r t h e e n e r g yo f t h e c a p a c i t otro f a l lt o S O % of its i n i t i avl a l u e (iii)Thetime that would haveelapsedfor the energyof the capacitorto fallto 2O%ofits i n i t i a vl a l u ea n dt h e c u r r e n ti n t h e c i r c u i a t t thatinstant. (iv)Theenergystoredin the capacitorafter its initialchargefallsto 30%ofits initial value ( v )T h e p . d .a c r o s st h e c a p a c i t owr h e n i t s e n e r g ys t o r e di s 4 5 %o f t h e i n i t i a vl a l u e . (Ans:1200s; 4I7s; 967s;3.35x10' A; 2.43xt03t;+.OZV) ( 5 ) A 2 0 p Fc a p a c i t oirs c h a r g e d t o a p . d .o f 6 V b y a b a t t e r y l.t i s t h e n d i s c o n n e c t ef rdo m t h e b a t t e r ya n d c o n n e c t e a d c r o s sa n i n i t i a l l yu n c h a r g e4d0 p r F capacitor. (i) D e t e r m i n e J hpe. d .a c r o s st h e c o m b i n a t i oann dt h e e n e r g ys t o r e d . (ii) T h ec o m b i n a t i oonf t h e t w o c a p a c i t o r(sc o n n e c t eidn p a r a l l e li)s t h e n c o n n e c t e d a c r o s sa 4 5 0 k Or e s i s t oirn o r d e r t o d i s c h a r giet . D e t e r m i n teh e t i m e t h a t m u s t e l a p s ef o r t h e e n e r g ys t o r e di n t h e c o m b i n a t i otno f a l lt o o n e q u a r t e ro f i t s i n i t i a l v a l u ea n dt h e c u r r e n t h r o u g ht h e r e s i s t oar t t h a t i n s t a n t . (Ans: 2V; 1..2x1,0-a J; 1,8.7s; Z.22x1,0-6 A) 75 Solutionsfor CapacitorDischarge ( 1 ) ( i ) T i m eC o n s t a nrt = C R= 5 0 x L 0 - 6 x 1 , 2 0 x1 0 3 =6 s e c o n d s . (ii) Use7 - Vor-il^, where Vo : 6V, and"V : 3V -rt H e n c e3 - 6 e - t l n cb u t R C : 6 , s o 3 : 6 e - t l u ; 3-t-t ln= : . ; -0.693 :: 666 3 Z- ,-tlu ;t : 0.693x 6 x- 4.I6s - 'r//o ; l n 1 , - t WhenV : IV ;I _ 6e ; t :10.75s 6: 6 ( i i i )U s e Q: Q or . - t l n cb u t f i r s t f i . n d "Q s ; Q o : C V s - 5 0 x 1 0 - 6 x 6 : 3 x 1 0 - 4 C H e n c eQ - 3 x 1 0 - a e - s l o- 1 . 3 x I 0 - 4 C T h a tv a l u eo f Q r e p r e s e n ttsh e c h a r g er e m a i n i n ign t h e c a p a c i t oar f t e r5 s e c o n d sT.h ec h a r g e t h a t w o u l dh a v eb e e nl o s tf r o m t h e c a p a c i t oi rs e q u a l t ot h e D I F F E R E NbCeEt w e e nt h e i n i t i a l c h a r g ea n dt h e f i n a lc h a r g e . i . e .3 x 1 0 - + 6 - 1 . 3x 1 0 - 4 C: 1 , . 7x I 0 - 4 C ( i v )F i n d . I n i t t a l E n e r g y s t o r e d .t . e . E s - ) t u & - 1* 50 x 10-6 x 62 9 x r0-4J A f t e r 2 s e c o n d sf ,i - n dt h e n e w v o ' I t a g et . r . V - V o r - t l n c ; V - 6 e - z l o- 4 . 3 V 1,^1 50x 10-6x4.32:4.6 xI0-4J. . ThenuseagatnEZCVt:rx T h ed i f f e r e n c ien t h e t w o v a l u e so f t h e c a l c u l a t eedn e r g i e rse p r e s e n ttsh e e n e r g yd i s s i p a t ebdy t h e c a p a c i t oi .re . 9 x 1 0 - + 1- 4 . 6 x 1 0 - a - 4 . 4 x t 0 - 4 J 76 ( 2 ) ( i ) T i m ec o n s t a n rt = c R= 1 0 0 0x l - 0 ' 6x 1 . 5x 1 0 6 =1 5 0 0s e c o n d s ( i i ) U s e7 - V o r - t l n cw h e r e V o: 1 2 V , a n d V : 9 V H e n c e9 : 7 2 r - t l a cb u t R C : 1 5 0 0 , s o 9 : L 2 e - t l r c o o; *: ,-t/rroo 9-t-t l n - : - : : i ; - 0 '.228888 : ' r ; t : 0 , 2 8 8 x 1 5 0 0: 4 3 2 s 1,2 15oo 15oo W h e n V: 6 V ; 6 : 1 2 r - t l r c o o ; l n ; t:1040s *:# W h e n V: i , V; 1 : r 2 r - t l r c ;ol o n+ : # : ; t : 3727s ( i i i ) U s e Q : Q o r - t l n cb u t f i " r s t f i . n d . Q s ; Q o : C V s - 1 0 0 0 x 1 0 - 6 x 1 2 : 1 , 2 x H e n c eQ - t 2 x 1 0 - 3 r - u " / r r 0 0 - 6 . 7 x 1 0 - 3 C 10-3C T h a tv a l u eo f Q r e p r e s e n ttsh e c h a r g er e m a i n i n ign t h e c a p a c i t oar f t e r8 7 5s e c o n d sT.h ec h a r g e t h a t w o u l dh a v eb e e nl o s tf r o m t h e c a p a c i t oirs e q u a lt o t h e D I F F E R E N C b eEt w e e nt h e i n i t i a l c h a r g ea n dt h e f i n a lc h a r g e . i . e .1 2 x I 0 - 3 C - 6 . 7 x I 0 - 3 C : 5 . 3 x 1 0 - 3 C ( i v )F f . n d I. n t t i a l E n e r g y s t o r e di . . e . E s: ) t U & -! x 1 0 0 0 x 1 0 - 6 x 1 . 2 2: 7 2 x I0-3J Af ter 200 second.s, f ind"the new voltage t. e.V - Vor-tlnc;V : 1.2r-'oolrs00 I0.SV 1^1 : 2 x 1 0 0 0 x 1 0 - 6 x 1 0 , 5 2: 5 5 x t 0 - 3 J . T h e n u s ea g a i n E tCVt T h ed i f f e r e n c ien t h e t w o v a l u e so f t h e c a l c u l a t eedn e r g i e rse p r e s e n ttsh e e n e r g yd i s s i p a t ebdy t h e c a p a c i t oi .r e . 7 2x 1 0 - : 7 - 5 5 x 1 0 - 3 : 1 . 7 x t 0 - 3 J T h ec u r r e n ti n t h e c i r c u iat t t h a t i n s t a nits f o u n df r o m I - Y R r j ' s v- 7 x 1,0-6A 1 . 5x 1 0 b ( i v )U s eV : V o r - t l * , w h e r e V o: 1 , 2 V , a n dt ": 3 0 0 s , R C : 1 5 0 0 s r sl o o- g . B z V V : 1,ze-=oo 77 MAGNETIC FIELDS co g n d u c t oor f l e n g t h/ i s p l a c e di n a m a g n e t i c f i e l da,f o r c ei s W h e n e v ear c u r r e n t - c a r r y i n e x e r t e do n t h e c o n d u c t opr r o v i d i n tgh a t t h e c u r r e n ti s n o t p a r a l l et lo t h e f i e l d . T h ef o r c ea c t i n go n t h e c o n d u c t oirs g i v e nb y t h e e q u a t i o n : F : Bllstn 0 W h e r e0 i s t h e a n g l eb e t w e e nt h e d i r e c t i o no f t h e c u r r e n ta n dt h e d i r e c t i o no f t h e m a g n e t i c field. T h e q u a n t i t y/ r e p r e s e n ttsh e l e n g t ho f c o n d u c t otrh a t i s i n t h e m a g n e t i fci e l da n d " 8 " i s c a l l e d t h e m a g n e t i fcl u x d e n s i t y . T h ea b o v ee q u a t i o ni n d i c a t etsh a t t h e f o r c ei s m a x i m u mw h e ns i n O= 1 , a n dt h i so c c u r sw h e n0 = 9 0 " , i . et h . e f o r c ei s m a x i m u mw h e nt h e c u r r e n ta n dt h e d i r e c t i o no f t h e m a g n e t i c f i e ladr ea t 9 0 "t o e a c ho t h e r . H e n c eF : B I L w h e nt h e c u r r e n ta n dt h e f i e l da r ea t r i g h ta n g l e st o e a c ho t h e r . F r o mt h i s l a t t e re q u a t i o nw, e c a nd e d u c et h a t B - I , 1 * h " n 0 = 9 0 " ) IL Definitionof FluxDensity: T h em a g n e t i fcl u xd e n s i t yB ,c a nb e d e f i n e da st h e f o r c ea c t i n gp e r u n i t c u r r e n ti n a w i r e o f u n i t l e n g t ha t r i g h t anglesto the field.It is a vector T h eu n i t o f m a g n e t i fcl u x d e n s i t yi s t h e T e s l a( T ) . T h eT e s l ai s d e f i n e da sf o l l o w s : A Teslais the magneticflux densityof a uniform field that causesa force of 1N to act on a conductor.1m long and carryinga currentof 1A,when the conductoris placed perpendicularto the magneticfield 78 W h e na c u r r e n t c- a r r y i n g c o n d u c t oirs p l a c e di n a m a g n e t i fci e l d ,t h e d i r e c t i o nof the forceon the conductoris givenby FLEMING'S LEFTHANDRULE R e c a ltlh a t fhumb Forefinger I iI I THRUST seCond Itunnrrur I V FIELD In Fleming'sLeft hand Rule,the current,field and force are alwaysat right anglesto each other. Forceon a Charge W h i l et h e e x p r e s s i oFn= B l Ls i n 0i s u s e dt o d e t e r m i n et h e f o r c ea c t i n go n t h e c o n d u c t o rt ,h e e q u a t i o nc a nb e m o d i f i e dt o d e t e r m i n et h e f o r c eo n e a c hc h a r g et h a t c o n s t i t u t teh e c u r r e n t . F o ra c o n d u c t ocr a r r y i n ga c u r r e n t| , l e t t h e T o t a ln u m b e ro f c h a r g etsh a t w o u l dh a v ef l o w e d a f t e rs o m et i m e b e " n ". ' L e tt h e m a g n i t u d e o f o n e c h a r g eb e " q " . Hence the current nq t- t B u tt h e f o r c eo n t h e c o n d u c t o irs e q u a lt o F r= B I Ls i n 0 Substituttng f or I gi"uesFt: Bnql x stn? T h i sF 1r ep r e s e n t tsh e forceon "n" charges i n t h e c o n d u c t o rh, e n c et h e f o r c eo n o n e c h a r g ei s givenby : BqIx stn? I d"i"stance :5f teedv. rtr2 b u t t h e q u a n t i " t y- t t ttrn HenceF, - Bqv sin? The force on a chargemovingwith a speedv througha magneticfield of flux densityB is givenby F - Bqv sin9 79 l f t h e c h a r g em o v e sa t r i g h ta n g l e st o t h e f i e l d ,t h e nt h e f o r c ew i l l b e a t r i g h ta n g l e st o b o t ht h e f i e l da n dt h e v e l o c i t yo f t h e c h a r g e C o n s i d ear p o s i t i v ec h a r g ee n t e r i n ga u n i f o r mm a g n e t i fci e l da t r i g h ta n g l e st o t h e . f i e l d : T h ef i e l di s d i r e c t e di n t ot h e p l a n eo f t h e p a p e r . a n db y F l e m i n g l' se f th a n dR u l e ,t h e f o r c ei s . o w e v e irf F l e m i n g 'lse f t h a n dr u l ei s a p p l i e da t a l m o s te v e r yp o i n ti n i n i t i a l l yd i r e c t e du p w a r d sH t h e p a t ho f t h e c h a r g ei,t w i l l b e s e e nt h a t t h e m o t i o no f t h e c h a r g ei s c i r c u l aar s l o n ga st h e c h a r g er e m a i n si n t h e f i e l d . T h ec h a r g eu n d e r g o ecsi r c u l a r m o t i o na n dt h e M a g n e t i cF o r c e= C e n t r i p e t aFlo r c e . BQv Hence BQY : LEARN mvz wherem is r t h e m a s so f t h e c h a r g ea n d r i s t h e r a d i u so f t h e c i r c l e . mvz r 80 M A G N E T IF CI E L DTSU T O R I ASLH E E T ( 1 ) A w i r ec a r r y i n g a c u r r e n to f 8 A a n d 1 . 5m e t r e si n l e n g t hi s p l a c e di n a f i e l do f f l u xd e n s i t y 0 . 4 5 T. W h a ti s t h e f o r c eo n t h e w i r e i f i t i s p l a c e d ( a ) A t r i g h ta n g l e st o t h e f i e l d ( b ) A t 6 0 ' t ot h e f i e l d ( c ) A t 4 5 = t ot h e f i e l d ( d ) A l o n gt h e f i e l d ( A n s 5: . 4 N ; 4 . 6 8 N 3 .; 8 2 N ; 0()U s eF = B r Ls i n 0 ) ( 2 ) A t h i n c o n d u c t o6r m l o n ga n d c a r r y i n g a c u r r e n to f 0 . 4 5 Ai s p l a c e di n a u n i f o r mm a g n e t i c f i e l da t r i g h ta n g l e st o t h e f i e l d . O n l yp a r to f t h e c o n d u c t oirs e n v e l o p e d i n t h e f i e l dw i t h 3 . 6 me x t e n d i nogu t o f t h e r e g i o nc o n t a i n i ntgh e f i e l d .l f t h e f o r c eo n t h e w i r e i s 7 . 2 Nf,i n d t h e m a g n e t ifcl u xd e n s i t y . ( H i n t O : n l y2 . 4 mo f t h e w i r e i s s u b j e c t etdo t h e f i e l d . ( A n s 6: . 6 7 T \ ( 3 ) A p i e c eo f w i r e 6 5 c m l o n g c a r r y i n ga c u r r e n to f 1 . 2 A i s p l a c e da t a n a n g l e0 t o a u n i f o r m m a g n e t i cf i e l d o f F l u x d e n s i t y4 . 5 T . l ft h e f o r c eo n t h e w i r e i s 2 . 8 8 N ,c a l c u l a t et h e v a l u eo f 0 . ( A n s :5 5 " ) ( a ) W h a t l e n g t ho f c o n d u c t ocr a r r y i n ga c u r r e n to f 3 . 3 4p l a c e da t a n a n g l eo f 7 0 "t o a m a g n e t i c f i e l do f f l u xd e n s i t y1 . 8 T , w i lcl a u s ea f o r c eo f 1 . 9 5 Nt o b e e x e r t e do n t h e c o n d u c t o r ? - . ( A n s .3:5 c m ) ( 5 ) l f 1 . 5 5 mo f w i r e c a r r y i n g a c u r r e n to f 3 . 4 Ap l a c e di n a u n i f o r mf i e l do f f l u xd e n s i t y2 . 2 T , w h a t m u s tb e t h e a n g l eb e t w e e nt h e c o n d u c t oar n dt h e f i e l di f t h e f o r c eo n t h e c o n d u c t o r i s5 N ? ( A n s : 2 5 . 5 " ) . ( 6 ) A n e l e c t r o ne n t e r sa u n i f o r mm a g n e t i c f i e lodf f l u x d e n s i t2y . 5 f w i t h a v e l o c i t y o f 3 . 5x L 0 6 m 1 s a t a n a n g l eo f 4 0 " t ot h e f i e l d .C a l c u l a t e h e f o r c eo n t h e e l e c t r o n . = ( A n s 9: x 1 0 ' 1 3 N ) B q v s i n 0 l tF '(7)Aproton(mass=!.67x1027Kgandcharge=1.6x1-0-1eC) isfiredataspeedof6.5xl06ms-1 a t r i g h ta n g l e st o a m a g n e t i fci e l do f f l u xd e n s i t y3 x l - 02 T .D e t e r m i n teh e r a d i u so f t h e p a t ho f t h e p r o t o nw h i l ei t i s i n t h e f i e l d .( H i n t U : s eF - r y a n d .F - B q v ) ( A n2s . 2 6 m ) ( 8 ) A n e l e c t r o ni s a c c e l e r a t ef dr o m r e s tt h r o u g ha p . d .o f 3 7 5 0 V l.t e n t e r sa r e g i o nw h e r e perpendicula B= 4 x L0-3T t or i t sv e l o c i t yC. a l c u l a tteh e r a d i u so f t h e p a t hi t w i l l f o l l o w . 31 { A n s5 . 2 c m ) R e c a i r, ' I r d sosf e l e c t r o ni s 9 . 1 x 1 0 k g a n d c h a r g e= 1 . 6 x l - 0 - 1 e c F t r s t f i r t d s p e e do f e L e c t r o nf r o m W - Q V : 81 1, ,^r' 1_ t h e nuseBQ mu2 r MagneticFluxPatterns T h em a g n e t i cF i e l dP a t t e r nd u et o : (1) A longstraightconductor-- C u r r e n itn t o p l a n eo f P a P e r Thefield linesare Circular C u r r e n to u t o f p l a n eo f P a P e r t a n dG r i pR u l e . T h ed i r e c t i o no f t h e f i e l dl i n e si s g i v e nb y t h e R i g h H Thisrulestatesthat i f t h e r i g h th a n di s u s e dt o g r i pt h e c o n d u c t o rw, i t h t h e t h u m bp o i n t i n gi n t h e d i r e c t i o no f t h e c u r r e n tt,h e n t h e d i r e c t i o no f c u r lo f t h e f i n g e r sw i l l givethe directionof the m a g n e t ifci e l dl i n e s . (2)Aflat circularcoil: A L O N GS O L E N O I D Thernagnsti* fi*ld is O n l o o k i n ga t t h e c o i l f r o m o n e e n d ,i f t h e ffi= FI"nl *snceRtr*ted int*a n*arly nifsrmfield n ths *sntsr c ur r e n ti s aN t i c l o c k w i s, e then a l*ng t h a t e n d i s a N - p o l ei;f s*lsnsid.Ths fieldoutside is wsakand dir,erge*t. i t i s c l o c k w i s ei t, i s a S pole T h e r i g h th a n dg r i pr u l ec a nb e a p p l i e dh e r ea g a i nt o g e t t h e d i r e c t i o no f t h e f i e l d .H o l dt h e c o i l w i t h t h e r i g h th a n ds o t h a t t h e c u r lo f t h e f i n g e r sg i v et h e d i r e c t i o no f t h e C U R R E NtTh;e t h u m bp o i n t i n g o u t w a r d sg, i v e st h e d i r e c t i o no f t h e FIELD. 83 FLUXDENSITY: OF MAGNETIC CALCULATION trg_r a c u r r e n tl ; B = . * t , t i r ec a r r y i n g ( 1 ) A t a d i s t a n c e" r " f r o m a l o n gs t r a i g hw w h e r e$ oi s c a l l e dt h e p e r m e a b i l i t y offr e e s p a c ea n d h a sa v a l u eo f 4 n x 1 0 - ' H m T h es y m b o H l i s t h e u n i tc a l l e dt h e H e n r yw h i c hi s a m e a s u r eo f I n d u c t a n c e n o t r e q u i r e db y s y l l a b u s . ( 2 ) A I t h e c e n t r eo f a f l a t c i r c u l acr o i lo f N t u r n s' 2,gr= * N I , w h e r e " r " i s t h er a d i u s ofthecoil. ( 3 ) N e a rt h e c e n t r eo f a l o n gs o l e n o i,d B : V o n I , w h e r e" n " i s t h e n u m b e ro f turns per unit length B - P t f o r a l o n gs t r a i g hwt i r e ,w h e r er i st h e zfir d i s t a n c fer o m t h e a x i so f t h e w i r e E r u f f o r t h e c e n t r eo f a f l a t c i r c u l acr o i l , 2r w h e r er i s t h e r a d i u so f t h e c o i l B - B : VonI n e a rt h e c e n t r eo f a l o n gs o l e n o i d N i s t h e n u m b e ro f t u r n sa n dn i s t h e n u m b e ro f t u r n s per unit length 84 MAGNETIC FIELDS TUTORIAL SHEET ( 1 ) C a l c u l a t teh e m a g n e t i cf l u x d e n s i t ya t a p o i n t ( a ) 1 2 c m a n d ( b ) 1 . 5 mf r o m a l o n gs t r a i g h t w i r e c a r r y i n ga c u r r e n to f 5 . 8 A . ( A n s : 9 . 6 11x 0 6 T ;7 . 7 3x t O 7 t ) ( 2 1A w i r e c a r r y i n ga c u r r e n to f 8 A p r o d u c e as f i e l do f f l u x d e n s i t y7 . 4 x 1 0 6 Ta t a d i s t a n c ex c m a w a yf r o m t h e w i r e .D e t e r m i nteh e v a l u eo f x , ( A n s2 1 . 6 c m ) ( 3 )W h a t m u s tb e t h e m a g n i t u d e o f t h e c u r r e n ti n a w i r e i f t h e c u r r e n tp r o d u c e a s f i e l do f f l u xd e n s i t y5 . 8x 1 0 6 Ta t a d i s t a n c e o f 2 2 c mf r o m t h e w i r e . (A n s6 . 3 8 A ) ( 4 ) A f l a t c i r c u l a rc o i l h a s 5 0 t u r n s o f w i r e , a n d t h e d i a m e t e ro f t h e c o i l i s 4 4 c m .W h a t i s t h e magnitude o f t h e f l u xa t t h e c e n t r ei f 1 . 8 Af l o w st h r o u g ht h e c o i l ? ( A N2S. 5 7x t 0 4 t ) ( 5 ) H o w m a n yt u r n so f w i r e a r e t h e r e i n a f l a t c i r c u l acr o i lo f w i r e o f d i a m e t e r6 8 c mi f a c u r r e n t s m a g n e t i fcl u xd e n s i t yo f 6 x 1 0 4 T ?( A n sI 2 O ) o f 2 . 7A p r o d u c e a ( 6 )W h a t i s t h e m a g n i t u d e o f t h e c u r r e n ti n a f l a t c i r c u l acr o i lo f w i r e i f i t h a s2 5 0 t u r n so f w i r e , i t s d i a m e t e ri s 7 5 c ma n ' dt h e f i e l da t i t s c e n t r ei s 9 x 1 0 4 T ? ( A n2s. 1 5 4 ) ( 7 ) A n e l e c t r o no r b i t sa n u c l e u sw i t h a s p e e do f 1 . 8 x L 0 6 m s - ' . T hr e a d i u so f t h e c i r c u l a o r rbitis 7 . 8 x i - 01 0 m . F i nt hd e m a g n i t u d oe f t h e f l u xd e n s i t ya t t h e n u c l e u ds u et o t h e e l e c t r o n 'm s otion.. T h ee l e c t r o n icch a r g ei s 1 . 6x 1 0 1 s C . ( H i n t : F i n dt h e c u r r e n td u e t o t h e e l e c t r o n ' m s o t i o n ;C u r r e n = t c h a r g ep e r s e c o n dy; o u r i r u s t m a n i p u l a t teh e c i r c u m f e r e n cteh,e s p e e da n dt h e c h a r g et o g e t c h a r g ep e r s e c o n d ) . ( A n s0 . .047T) ( 8 )A n a i r - c o r es o l e n o i dh a s1 5 0 0l o o p sa n d i s 8 0 c ml o n gw i t h a d i a m e t e o r f 3 c m .l f a c u r r e n to f 6 4 i s s e n tt h r o u g hi t . W h a t w i l l b e t h e m a g n i t u d eo f t h e f l u xd e n s i t yi n s i d eo f i t ? ( 0 . 0 1 4 T ) ( 9 )A l o n gw i r e c a r r i e sa c u r r e n to f 2 0 A a l o n gt h e a x i so f a s o l e n o i dw, h i c hh a sa i a d i u s0 f 1 O c m . T h es o l e n o i d h a sa n i n d e p e n d e nc tu r r e n ta, n dt h e f i e l dd u et o t h e s o l e n o i d i s 4 x 1 0 - 3 TF.i n dt h e r e s u l t a nfti e l da t a p o i n t3 m m f r o m t h e s o l e n o i da x i s .( H i n t ;T h e l o n gw i r e p r o d u c e si t s o w n f i e l d t h a t i s p e r p e n d i c u l at or t h e f i e l d o f t h e s o l e n o i dc; o n s i d e trh e t w o f i e l d sa s v e c t o r st h a t a r e perpendicula t or e a c ho t h e r ,a n df i n dt h e r e s u l t a nvt e c t o r . ( A n4s. 2 2x t O 3 l ) Soiution f o r q u e s t i o n7 : F i n dt h e c urrrreenntti n L r e v o l u ttiiooninn w h i c hc a s eN ( n o o f t u r n s = 1 ) x s?eed -Q t ctrcumf erence 4 n x L 0 - 7 x 1 . . 6 x 1 0 - 1 ex 1 . 8 x 1 0 6 : 0.0477 2 x 7 . 8 x 1 0 - 1 0x 2 x r x 7 . B x 10-10 I - charge per er u rge p unit n i t ttime ime -9 B5 - FORCES MAGNETIC of Force: Direction LEFT W h e na c h a r g em o v e si n a n e l e c t r i cf i e l d ,t h e d i r e c t i o no f t h e f o r c ei s g i v e nb y F L E M I N G ' S H A ND R UL E . Recall: ,Thumb tl , seCond Forefinger lt rl ++ Thrust C ur r e n t ( c o n v e n t i o|n )a Field T h ed i r e c t i o no f t h e c u r r e n ti s t h e d i r e c t i o no f m o t i o nof P!SI[!VE charge. C o n s i d et h r e f o l l o w i n gD i a g r a m s : xxxxxx'x E-' X XX XX c h a r g eh a sa n i n i t i a l T h ep o s i t i v e v e l o c i t yt o w a r d st h e r i g h t ,h e n c et h e c o n v e n t i o n aclu r r e n ti s t o w a r d st h e l n t h e a b o v ed i a g r a mt,h e e l e c t r o n h a sa n i n i t i a vl e l o c i t yt o w a r d st h e r i g h t ,h e n c et h e C O N V E N T I O N A L C U R R E Ni sTt o w a r d st h e l e f t 'T h ef i e l d i s d i r e c t e di n t o t h e P a P e ra, n d b Y F l e m i n g ' Ls e f th a n dR u l e t, h e f o r c ei s r i g h t .T h ef i e l di s d i r e c t e di n t o t h e p a p e ra n d b y F l e m i n g 'Ls e f th a n dr u l e , t h e f o r c eo n t h e P o s i t i v ec h a r g ei s initialld y ownwards. initialld y i r e c t e du P w a r d s . force A s l o n ga st h e m o v i n ge l e c t r i c h a r g ei s p e r p e n d i c u l taor t h e a p p l i e dm a g n e t i fci e l d ,t h e o n t h e c h a r g ec a u s e si t t o u n d e r g oC I R C U L AMRO T I O Na, n dt h e f o l l o w i n ge q u a t i o ni s a p p l i e d BQv - mvz r 86 Considerthe casewhen the moving chargeis perpendicular to an ELECTRIC FIELD. W h e nt h e e l e c t r i c h a r g ep a s s e s t h r o u ga hn E L E C T RFI ICE L D t h a t i s p e r p e n d i c u l a r t o t hmeo t i o n o f t h e c h a r g et,h e p a t ho f t h e c h a r g ei n t h e f i e l di s p A R A B o L l c . H e n c ew h i l et h e m a g n e t i fci e l dp r o d u c e C s I R C U L AMRO T I O Nt ,h e e l e c t r i cf i e l dp r o d u c e s P A R A B O LM I CO T I O N . The force experiencedby the chargedue to the ELECTRIC FIELDis given by F - Eq where E is the Electri.c Field Strength. 87 C o n s i d et h r e c a s en o w w h e r et h e c h a r g ep a s s etsh r o u g ha c o m b i n a t i oonf a n E l e c t r iac n d MagnetiF c i e l dt h a t a r ep e r p e n d i c u ltaor e a c ho t h e ra n da l s op e r p e n d i c u ltaort h e i n i t i a l v e l o c i t yo f t h e c h a r g e . , n dt h e E l e c t r iFc o r c ew i l l b e T h eM a g n e t i fco r c ew i l l b e d o w n w a r d(sF l e m i n gl' es f th a n dr u l e ) a u p w a r d s ( A t t r a c t ioofno p p o s i t ec h a r g e s.) ( 1 ) P a t hA i n d i c a t etsh a t t h e u p w a r df o r c ei s g r e a t e tr h a nt h e d o w n w a r df o r c ei . e . Eq ( 2 ) P a t hB i n d i c a t e s t h a t t h e E l e c t r i cf o r c e i s e q u a l t o t h e M a g n e t i cf o r c e E Q : ( 3 ) P a t h C i n d i c a t e st h a t t h e M a g n e t i cF o r c ei s g r e a t e rt h a n t h e E l e c t r i cF o r c ei . e , Bqv > Eq 88 BqV The Earth's Magnetic Field The Earth has a substantialmagneticfield, a fact of somehistoricalimportancebecauseof the role of the magneticcornpassin explorationof the planet. Structureof the Field The Jield lines defining the structure of the magneticfield are similar to thoseof a simple bar magnet,as illustratedin the following figure. lnnerYan A l l e nB e l t Outer Allen i ! I 't I II I I M a g n e t i cF i e l dL i n e s The Harth's rnasnetis field an* Van Allen nadiation belts It is ll'ell knorvn that the axis of the magneticfield is tipped with respectto the rotation axis of the Earth. Thus, true north (definedby the directionto the north rotational pole) does not coincidervith magneticnorth (definedby the directionto the north magneticpole) and compassdirectioirsmust be correctedb,vfixed amountsat given points on the surfaceof the 8,.:rc"th to vield true directions. 89 Van Allen Radiation Belts A fundamental propcrtr of magneficfields is t h a t t h e r c r e r t l ' o r c e so n m o v i n g e l e c t r i ea l c h a r g e s .T h u s . a n t a g n e t i ei i e l d t ; u l t r a p c h a r g e d p a r t i c l e s: u c l t x - -r i * c t r r ; n s * n d p r o t o n s a s t h c " \ a r c f o r c e d t o c r e ' eu I e i t s g * * ; ' . : l ! i ;i .: ;: , : : : , : :b: i t C ka n t l l r - t f t ha i O n gt h e ?, ! {ield lines. Earth *- 'Mirror Fcints A s i l l u s t r a t e d i n t h e a d j a c c * t f * i l l u r r .t h t ' . _1--.-J :l I charged particles are rellectedat "rnirror p o i n t s " u h e r c t h r l l c l i l l i n c s c { ) m cc l o s e t l ,* {agn* ti cFi + l d Lin* t o g e t h e ra n d t h e s p i r a l s t i g l i t r ' ; : .i l n e * f t h e f i r s t f r u i t s o f e a r l v s p a c ee r p l o r a t i o n n a s t h e d i s c o v e n i n t h e l a t e 1 9 5 0 st h a t t h e E a r t h i s s u r r o u n d e d b v t r v o r e g i o n s o f p a r t i c u l a r l v h i g h concentration of charged p*rticles called the l/an Allen rucliation belts. T h e i n n e r a n d o u t e r V a n A l l e n h c l f s a r e i l l u s t r a t e d i n t h e t o p t i g r r r e .T h e p r i m a r v s o u r c e o f thesechar.gedparticlesisthe.=,.ii-:':-::::::ig-:::s"lE*:E*=emanatingfromtheSunthatwecallthe' i d , , r i ; s i ' E " g ' ; - ,r,r"e: , s: ih- .a. l{lss c e i n ; r s u h s e q u e n ts e c t i o n ,t h e c h a r g e d p a r t i c l e s t r a p p e d i n t h e E a r t h ' s m a g n c t i c f i e l d a r r r e s p c r r s i b l ef n r t h e ; : . ; : ; i . ''' . {' :l 't:i a r t h e r n a n d S o u t h e r n L i g h t s ) . Origin of the t{agnetic Field l{agnetic fieldsare producerlhr the motion of electricalcharges.For example,the magneticlield of a bar magnetresultsfrom the motion of negatively'chargedelectronsin the magnet.The origin of the Earfh's magneticfield is not completel_-v understood,but is rrith tlcctrical currentsproducedby'the couplingof convective thought to bc irssttciirtcd effectsand rotation in the spinningliquid metallicouter core of iron and nickel.This mechanismis termt'd the il-t'ttutn*e.ff'et't. Rocksthat are lbrmed from the molten statecontain indicatorsof the magneticfield at the 'f time of their solidification. hc studv of such "magneticfossils"indicatesthat the Earth's magneticlield re\er-cs ifself everv million vearsor so (the north and south magneticpoles suir.i'). This is br-rtonc detailof thc magnetictield that is not rvellunderstood. 90 The Earth's Magnetosphere The solar wind mentionedaboveis :: a stream of ionizedgasesthat ,', blows outward from the Sun at about 400 km/secondand that variesin intensitvwith the amount ..,', of surfaceactil'itv on the Sun. The Earth's magneticfield shieldsit from much of the solar wind. When the solar lvind encountersEarth's magneticfield it is deflectedlike water around the bow of a ship' as illustratedin the adjacent image(F{*eer**). The imaginarv surfaceat which the solar wind is first deflectedis calledthe bow shock.The correspondingregionof ipace sitting behindthe borvshockand surroundingthe Earth is termed the s;trs*rl<'F*;sgJe{'i'i'; it representsa region of spaceclominatedbv the Earth,s magneticfield in the sensethat it largely preventsthe solar u,ind from entering.However, somehigh energvchargedparticlesfrom the solar wind leak into the magnetosphere and are the sourceof the chargedparticlestrapped in the yan Allen belts. 91 Electricand MagneticFields Applicationof Mutuallyperpendicular The MassSpectrometer: T h i si n s t r u m e nits u s e dt o d e t e r m i n et h e m a s s e os f a t o m sa n d i o n st o a v e r yh i g hd e g r e eo f accuracy. I t u s e si o n s i e dg a s ,a sa s o u r c eo f p o s i t i v ei o n s ,a d e f l e c t i o n s y s t e mc a l l e da V E L O C I TSYE L E C T O R r h i c hi s u s u a l l a y s h e e to f p h o t o g r a p hfiicl m . a n d a d e t e c t ow l e t a lp l a t e sw i t h m u t u a l l y T h ev e l o c i t ys e l e c t ocr o n s i s tos f t w o s e p a r a t e pd a r a l l em p e r p e n d i c u lealre c t r i a c n d m a g n e t ifci e l d sb e t w e e nt h e m . W h e ni o n so f a c h a r g eq a n d s p e e dv p a s st h r o u g ht h e f i e l d st,h e M a g n e t i cF o r c eo n e a c h B tQV; chargeis givenb.y F ! T h e E l e c t r ifco r c ea c t i n go n e a c hc h a r g ei s g i v e nb VF Z - E q . l f t h e f i e l d sa r ea d j u s t e ds o t h a t t h e r ei s n o d e f l e c t ino, t h e nE Q : B tQV E :B1' T h i su n - d e f l e c t ebde a mi s t h e n p a s s e d t h r o u g ha r e g i o no f a n o t h e rm a g n e t i fci e l da l o n ew h e r e t h e f l u x d e n s i t yi s 8 2 .T h i sf i e l dc a u s e tsh e b e a mo f i o n st o u n d e r g oc i r c u l am r o t i o n ,w i t h t h e r a d i u so f t h e p a t hb e i n gr . T h i si m p l i e st h a t V - Hehce Bzgv: mvZ l f w e s u b s t i t u,:t V : r _+ t Ur, Bze thenBzg : q m mv r mE rB r' E rB 11Bz T h eq' u a n t i 'tnyat i s c a l l e dt h e c h a r g et o m a s sr a t i o ,a n d o n l yi o n so f a p a r t i c u l acrh a r g et o m a s s r a t i o ,w i l l b e d e f l e c t etdh r o u g ha p a r t i c u l ar ra d i u sr t o r e a c ht h e d e t e c t o r . X B2 q1 X DETECTOR ELECTROMAG NETISM W h e na s o f t i r o nc o r ei s p l a c e di n s i d ea s o l e n o i d carrying a c u r r e n tt,h e M a g n e t i cF l u xD e n s i t y B o f t h e c o i li s s i g n i f i c a n tilny c r e a s e d T h et e r m " S o f tl r o n "d o e sn o t r e f e rt o t h e t e x t u r eo r t o u g h n e sosf t h e i r o n ,b u t i n s t e a di t i s a m e a n so f d e s c r i b i ntgh e a b i l i t yo f t h e i r o nt o b e c o m em a g n e t i z ewd h e na c u r r e n ti s i n t r o d u c e d AROUND i t a n dt h e a b i l i t y t ol o s ei t s m a g n e t i s m w h e nt h e c u r r e n it s r e m o v e d . A s o f t m a t e r i ails o n e t h a t c a nb e c o m em a g n e t i z eadn d b e d e m a g n e t i z eeda s i l y . T h i se f f e c to f p l a c i n ga s o f ti r o nc o r ei n a c u r r e n tc a r r y i n gs o l e n o i di s s i m i l a tro t h a t o f t h e p l a c e m e notf i h e d i e l e c t r iicn a c a p a c i t o r . T h e ' M A G N E T ' p r o d u ci en dt h e s o f ti r o nb y m e a n so f a n e l e c t r i c u r r e n its r e f e r r e d t o a sa n ELECTROMAG NET. T h ep r i n c i p loef t h e e l e c t r o m a g niesta p p l i e di n ( i ) E l e c t r i dc o o r l o c k s- W h e nn o c u r r e n ft l o w si n t h e c o i l ,t h e l a t c ho f t h e l o c ki s t h e i n t h e 'locked'position a n d r e m a i n tsh e r eb y t h e e f f e c o g n i t . W h e nt h e t f a s m a l sl p r i n gp u s h i n o s w i t c hi s p r e s s e da,n d a c u r r e n t f l o w si n t h e c o i l ,t h e s o f ti r o nc o r eb e c o m e sm a g n e t i z eadn d e x e r t sa f o r c eo f a t t r a c t i o no n t h e l a t c h ,p u l l i n gi t d o w n a n d c a u s i n g t h el o c k t o b e c o m eo p e n . W h e nt h e c u r r e n ti s s h u to f f , t h e s p r i n gt h e n p u s h e st h e l a t c hb a c ki n t ot h e ' l o c k e dp' o s i t i o n . latch 93 RELAY: ( i i )S w i t c h e sA : n e x a m p l eo f a n e l e c t r o m a g n e t i sc w i t c h i s t h e E L E C T R O M A G N E T I C { contacts Connections t o l o a de . g . T h er e l a yi s a n . h i g hv o l t a g e e l e c t r o m a g n e tsi cw i t c ht h a t operatesfrom a low voltage equipment s u p p l ya n d i s u s e dt o c o n t r o l Ys u a l l Y a h i g hv o l t a g es u P P | u t o i n d u s t r i aml a c h i n e r Y L o w ' ; o l t a q el n P u t i i I' i :!a v m a g n e t i z e da n d a t t r a c t s t h e W h e n t h e s w i t c h i s c l o s e d ,t h e s o f t i r o n c o r e i n t h e c o i l b e c o m e s t h e c o n t a c t st h a t c o m p l e t e m e t a l a r r n a t A . L a L i s i ntgh e e n i i a i B t o b e p u s h e du p a n d c l o s i n g t h e c i r c u i tf o r t h e h i g hv o i t a g ee q u i p m e n t ' 94 FORCES BETWEEN C U R R E N T . C A R R Y IC NO GN D U C T O R I T h e f o r c e st o b e c o n s i d e r e da r e t h o s e b e t w e e n: ( a )p a r a i i e {i c n , j u e t o r sa n d i n )p e r n e n d i c u l a r conductors I n p a r a l l e lc o n d u c t o r st,h e i " ' :ai i " et w o s i t u a t i o n st o L r ec c n s i d e r e c ( 1 ) P a r a l l ecl o n d u c t c r sc a r r y i n gc u r r e n t si n t h e : ; a r : r ed i r e c t i o n . al 1e F i e l dd u e t o B o n i y a Y Fi..rd c i u et o A o n l y ,,i rql \-{ l1 XXX i 'iI i I V XXX i I XXX €-F C o n s i d e tr h e f o r c e a c t i n go n P . T h e c o n d u c t c ri : i s p l a c e di n t h e F I E L Do f Q . l f w e u s e t h e R i g h t C t r : s i c l E n: "c w , t h e i i ; r t . a c i i n g o n Q . .T h e c o n d u c _ t o r Q : s p l a c e cijn t h e F l L r - Do f P . l f w e u s e t h e R i g h t H a n dG r i p R u l ef o r Q , i t w i l l b e s e e nt h a t t h e H a n d G r i p R u l ef o r P , i t w i i l b e s e e nt h a t t h e f i e l c jo n f i e l d o n t h e l e f t s i d eo f Q w h i c h i s e x p e r i e n c e d t h e r i g h t s i d e o f P w h i c h i s e x p e r i e n c e db y Q , g o e s b y P , g o e si n t o t h e p l a n eo f t h e p a p e r .U s i n g o u t o f t h e p i a n e o f t h r p a p e r .L l s i n gF l e m i n g ' sL e f t F l e m i n g ' sL e f t H a n d R u l ef o r t h e f c r c e o n P , i t ! - l a n dR u i ei o r t i : e i . ; r r e o n Q , i t w i l l b e s e e nt h a t w i l l b e s e e nt h a t t h e f o r c e i s d i r e c t e dt o w a r C s t h e f o r c e i s d i r e c t e dt o w a r d s P . a. l f t h e p e r p e n d i c u l adri s t a n c e b e t w e e nt h e c o n d u c t o riss Q d u e t o P , i s g i v e n0 v b p t h e n t h e f i e l de x p e r i e n c e a dt l -L onl 7nr a n dt h e f o r c ee x p e r i e n c ebdy O .i s g i v e nb y F q =B t q l s i nB * t f u k l {sin g0) Jo-l'Iq S i m i l a r l y t h e f c- e e x p e r i e n c e d b y P i s g i v e n b y F p = B I p L s_i n O I. lsine=11 2nr f J H E N C U R R E N TA S R E I N T H E S A M E D I R E C T I O NT, H E R EI S A F O R C EO F A T T R A C T I O N A C T I N GO N E A C HC O T { D U C T O RI F. T H E C U R R E N T A S R E I N O P P O S | T TD I R E C T I O N S T ,H E R EI S A F O R C EO F REPULSION A C T I N GO N E A C HC O N D U C T O R C o n s i d et rh e f o l l o w i n ga r r a n g e m e notf c u r r e n t - c a r r y icnogn d u c t o r s - A X X X X XX Y T h ef i e l dd u e t o C o n i t s l e f t ,i s i n t ot h e p l a n e , h i l eo n i t s r i g h t ,i t i s o u t o f o f t h e p a p e rw t h e p l a n eo f t h e p a p e r . ( R i ghhat n dg r i p l f w e e x a m i n et h e f i e l dd u e t o A a t t h e u n d e r s i do e f A , i t w i l l b e s e e nt h a t b y t a n dG r i pR u l et,h e a p p l y i n tgh e R i g h H f i e l di s d i r e c t e di n t ot h e p a p e r . Rule) F l e m i n g 'Lse f th a n dR u l e ,t h e B ya p p l y i n g by C at its lower forceF1experienced W h e nF l e m i n g l' se f th a n dr u l ei s a p p l i e d, t h a t p o r t i o no f t h e w i r eA w h i c hi s t o t h e l e f t e n d i s d i r e c t e dt o w a r d st h e R I G H T . o f w i r e C ,w i l l e x p e r i e n caef o r c et h a t i s u p w a r d sw , h i l et h a t p o r t i o no f w i r e A t h a t i s H o w e v e ra, t t h e u p p e rs i d eo f A , t h e f i e l d i s o u t o f t h e p l a n eo f t h e p a p e ra, n dt h e by C at its upperend, forceexperienced w i l l b e F za n d i t i s d i r e c t e dt o w a r d st h e L E F T . ( F l e m i nLge' fstH a n dR u l e ) T h ew i r eC w i l l e x p e r i e n caen A N T I C L O C K WM I SOEME N T . 96 t o t h e r i g h to f C w i l l e x p e r i e n caef o r c et h a t is downwards. T h ew i r e A w i l l t h e r e f o r ee x p e r i e n cae C L O C W I SMEO ME N T . THEHALLEFFECT i f e l e c t r o n isn a b e a ma r e d e f l e c t e db y a m a g n e t i fci e l d ,t h e n e l e c t r o n isn a s o l i dC O N D U C T O R s h o u l da l s ob e d e f l e c t e b d y a n e x t e r n am l a g n e t i c f i e lT dh . i sw a sd e m o n s t r a t ebdy E d w i nJ .H a l l i n 1 . 8 7 9w, h o w a st h e n a 2 4 y e a ro l d g r a d u a t ea t J o h nH o p k i n sU n i v e r s i t yT. h ed e f l e c t i o n of c h a r g ec a r r i e r si n a c o n d u c t obr y a m a g n e t i fci e l di s k n o w na st h e H A L LE F F E C T . T h i sH a l lE f f e c te n a b l e os n et o d e t e r m i n e w h e t h e rt h e c h a r g ec a r r i e r isn a c o n d u c t oar r e p o s i t i v eo r n e g a t i v e . C o n s i d ear M E T A L L cI C o n d u c t oirn f o r m o f a t h i n s t r i po f w i d t h ' w ' a n dc a r r y i n ag c u r r e n t ' l ' a s s h o w nA . m a g n e t ifci e l cB i i s a p p l i e dp e r p e n d i c u ltaort h e c u r r e n at n di n t ot h e p l a n eo f t h e p ap e r XXXXXXXX B 1A X X X X .x X X X t I W I pV Letus makethe ASSUMPTION that the chargecarriersin the metalare positively charged.- . lf Flemirig's Lefthandrule is applied,the forceactingon the chargecarrierswill be upwards, and all of the positivechargeswill accumulate on the sideAB, leavingCDwith a negative charge. Therewouldthereforebe a potentialdifferencecalledthe HALIVOLTAGE set up acrossthe width 'w'and if our assumption wascorrect,then AB shouldhavea higherpotentialthan CD, sinceAB shouldbe positively chargedand CDnegatively charged. However,when a voltmeter is connectedacrossthe width, it is found that the side AB is at the lower potential and is therefore negativelycharged.This impliesthat our ASSUMPTION .WAS WRONG,and that the chargecarriersin a metallicconductorare negativelycharged (electrons|. 97 OFTHEHALLEFFECT APPLICATION whichis madefrom a The HallEffectis usedto measuremagneticflux density.A HALLPROBE h a n d l ei,s p o w e r e db y a l o n g i n s u l a t i n g t h i n d i s co f s e m i c o n d u c t i nmga t e r i a la n df a s t e n e dt o a s m a l ld . c .s o u r c et o d r i v ea s m a l lc u r r e n t h r o u g hi t . A m i l l i v o l t m e t eorr a m i c r o v o l t m e t ei sr c o n n e c t ea d c r o s st h e l e a d sa, n d w h e nt h e p r o b ei s i n s e r t e di n a m a g n e t i fci e l dt h e H a l lv o l t a g e bythe millivoltmeter. ismeasured T h ep r o b ei s f i r s tc a l i b r a t e bd y p l a c i n gi t i n a f i e l do f K N O W NF L U XD E N S I TsYo, t h a t t h e m i l l i v o l tp s e rT e s l ac a nb e o b t a i n e d .W h e ni t i s t h e n p l a c e di n a n u n k n o w nf i e l d ,a n dt h e H a l l o f B c a nt h e n b e c a l c u l a t e d . v o l t a g eo b t a i n e dt,h e m a g n i t u d e FLUX MAGNETIC 'A' to a magneticfieldof flux densityB. Considera loopor a coilof area placedperpendicular T h ef l u x t h r o u g ht h e c o i li s t h e n u m b e ro f m a g n e t i fci e l dl i n e sp a s s i n tgh r o u g ht h e c o i la n d i s g i v e nb y t h e f o r m u l a : 0=BA' The unit of magneticflux is the Weber (Wb) FLUXLINKAGE: y ,t h e f l u x l f a c o i lh a s ' N ' t u r n sa n di t s a r e a ' A ' i sh e l dp e r p e n d i c u l a rat of i e l do f f l u x d e n s i t B l i n k a g et h r o u g ht h e c o i li s t h e p r o d u c to f t h e f l u xa n dt h e n u m b e ro f t u r n si n t h e c o i l . H e n c ei n t h i sc a s e , o-NBA l . W e b e r= l T e s l ax L m 2 O R l T e s l a= 1 W b . m - 2 The Weber is the magneticflux or numberof magneticfield linesthat passesthrough a loop of area 1m2if the loop is at right anglesto a magneticfield of flux density1 Tesla. 98 ELECTROMAG NETICINDUCTION W h i l ee a r l ye x p e r i m e n tdse m o n s t r a t etdh a t a c u r r e n tp r o d u c e as m a g n e t i c f i e l dF,a r a d a y w a s a b l et o d e m o n s t r a tteh e R E V E R S eE f f e c ti . e .A m a g n e t i fci e l dc a np r o d u c ea n e l e c t r i c u r r e n t . l f a b a r m a g n e ti s m o v e di n a n d o u t o f a l o o po f w i r ew h i c hi s c o n n e c t e to d a galvanometer, a c u r r e n it s I N D U C EiD n t h e c o i lw h e n e v e r t h e m a g n e its i n m o t i o n . S T h ef o l l o w i n go b s e r v a t i o nwse r e m a d e : ( 1 ) A c u r r e n te x i s t si n t h e c i r c u i o t n l yf o r t h e i n s t a n t w s h e nt h e r ei s r e l a t i v em o t i o n b e t w e e nt h e m a g n e ta n dt h e l o o p .T h ec u r r e n g t o e st o z e r ow h e nt h e m o t i o ns t o p s . ( 2 ) T h eg r e a t e tr h e s p e e do f r e l a t i v em o v e m e n tt,h e g r e a t e ri s t h e m a g n i t u d e of the c ur r e n t . ( 3 ) W h e nt h e m o t i o no f t h e m a g n e ti s r e v e r s e dt h , e d i r e c t i o no f t h e i n d u c e dc u r r e n ti s a l s o reversed. i cd u c t i o n w a sf o r m u l a t e d . F r o mt h e s eo b s e r v a t i o nFs a , r a d a y 'Lsa wo f E l e c t r o m a g n e It n Faraday'sLaw statesthat the MAGNITUDE of the inducede,m.f.in a coil, is directly proportionalto the rate of changeof flux linkagein the coil. 99 R e c a l l t h aftl u x a n df l u x l i n k a g er e f e rt o t h e n u m b e ro f m a g n e t i fci e l dl i n e sp a s s i ntgh r o u g ht h e coil. Faradaye ' sx p e r i m e n tssh o w e dt h a t t h e n u m b e ro f f i e l dl i n e sp a s s i ntgh r o u g ht h e c o i li s p r i m a r i l yb y t h e R A T Ea t unimportanT t . h ei n d u c e de . m . f .a n d i n d u c e dc u r r e n ta r ed e t e r m i n e d w h i c ht h a t n u m b e ro f f i e l dl i n ec h a n g e s . r o v e si n a m a g n e t i c f i e l dI n. t h i sc a s et h e C o n s i d enr o w a d i f f e r e n ct a s ew h e r ea c o n d u c t om , n dt h e c o n d u c t om r o v e sd o w n w a r d w s itha f i e l di s d i r e c t e di n t ot h e p l a n eo f t h e p a p e r a v e l o c i t yv . T h e l e n g t ho f t h e c o n d u c t oirs l . XXXX XXXX -AXX l" I I XXXI XX XX YV XX XX T h eM A G N I T U DoEf t h e e . m . f .i n d u c e da c r o s st h e e n d so f t h e c o n d u c t oirs g i v e nb y E -dQ - Bdo. dt . d"A dt T h eq u a n t i t y r e p r e s e n ttsh e r a t eo f c h a n g eo f a r e at h a t t h e c o n d u c t ocr u t st h r o u g ha n d h a s fr u n i t so f m ' s - t . F r o mt h e s eu n i t sa l o n ei t c a nb e d e d u c e dt h a t - I e n g t h x u e l o c i . t y # HenceE - BIv. LEARN 100 l n t h e c a s ew h e r ea m a g n e ti s p l u n g e di n a n do u t o f a l o o po f w i r e ,t h e i n d u c e de . m . f .i s s t i l l g i v e nb y E s i n c e@= B A ,t h e a r e ao f t h e l o o pi s c o n s t a nitn t h i sc a s e b , u t t h e v a l u eo f # "nd B c h a n g e ds e o e n d i n o g n i t s p o s i t i o na w a yf r o m t h e l o o p .H e n c ef o r t h i s p a r t i c u l acra s e , E_A9 dt l f h o w e v e tr h e c o i lh a s' N ' t u r n st h e nt h e M A G N I T U DoEf t h e e . m . f .i n d u c e di s p r o p o r t i o n at ol t h e r a t eo f c h a n g eo f F L U XL I N K A GaEn dE - N # . T h ea b o v ee q u a t i o nh o w e v e ri s i n c o m p l e t a e st h e D I R E C T I OoN f t h e i n d u c e de . m . fm u s ta t s ob e considered. T h ed i r e c t i o ni s g i v e nb y L e n z ' sL a wa n dt h e r e s u l t i n e g q u a t i o ni s : -dQ E- dt LEARN!! 101 LAW LENZ,S T h i sl a w d e t e r m i n etsh e d i r e c t i o no f t h e i n d u c e dc u r r e n t ' to Lenz,sLaw statesthat when an emf is inducedin a conductor,the inducedemf tends circuit. opposethe changecausingit, and it doesopposeit when a currentflows in the p r o d u c ea T h i sl a w c a nb e r e s t a t e da s : T h e p o l a r i t yo f t h e i n d u c e de . m . f. i s s u c ht h a t i t t e n d st o w h i c hc a u s e s f l u x c u r r e n t h a t w i l l c r e a t ea m a g n e t i fcl u xt o o p p o s et h e c h a n g ei n t h e m a g n e t i c t h e i n d u c e de . m . f . The combinationof Lenz'slaw and Faraday'sLawgivesthe all important equationfor both the magnitudeand directionof the inducede.m.f. _da F_ Ll dt The negativesignindicatesthat the inducede.m.f.is in the opposite directionto the changeof flux n t f l o w si n t h e c i r c u i tt,h e m a g n e t i c T h i sc a nb e i n t e r P r e t etdo m e a n f i e l dd u et o i n d u c e dc u r r e n tw i l l o p p o s et h e m o t i o nt h a t c a u s e tsh e e l e c t r o m a g n e ti incd u c t i o n ' m u s tb e T h ed i r e c t i o no f t h e i n d u c e de . m . f .i s t h e s a m ea st h a t f o r t h e i n d u c e dc u r r e n t b, u t i t n n l yo c c u r sw h e na c u r r e n tf l o w i n t h e c i r c u i ti n w h i c ht h e c o i l r e m e m b e r etdh a t t h e o p p o s i t i o o o r l o o pi s c o n n e c t e dT.h i sc a nb e d e m o n s t r a t eidn t h e a r r a n g e m e nbte l o w . of thecoil' T h e m a g n g ti s s e t i n t o o s c i l l a t i osno t h a t i t w i l l b e c o n t i n u o u s lbye m o v i n gi n a n d o u t i n ane.m.f. duced W h e nt h e s w i t c hi s o p e n ,n o c u r r e n ft l o w si n t h e c i r c u i tb, u t t h e r ew i l l b e m a g n e ti s a c r o s st h e l e n g t ho f t h e c o i l .S i n c et h e r ei s n o i n d u c e dc u r r e n tt,h e o s c i l l a t i oonf t h e n o t h a m p e r e di n a n Yw a y . sets W h e nt h e s w i t c hi s c l o s e da, n i n d u c e dc u r r e n t f l o w si n t h e c i r c u i ta, n dt h i s i n d u c e dc u r r e n t gagnet. u p a m a g n e t i fci e l dt h a t o p p o s e tsh e m o t i o no f t h e o s c i l l a t i nm to T h i so p p o s i t i o tno m o t i o nc a u s e tsh e o s c i l l a t i o nt os d i e d o w n a n dc a u s e tsh e m a g n e eventuallycometo rest. 1,02 Lenz'sLaw is an exampleof the Principleof Conservation of Energy. s i a g r a mw, h e nt h e s w i t c hi s c l o s e da, n dt h e m a g n e ta p p r o a c h et sh e c o i l ,t h e F r o mt h e p r e v i o u d i n d u c e dc u r r e n tf l o w si n a d i r e c t i o nt o p r o d u c ea N o r t hp o l ea t t h e t o p e n d o f t h e c o i lt o r e p e l t h e i n c o m i n gN o r t hp o l eo f t h e m a g n e tT. h ew o r k d o n ei n o v e r c o m i ntgh i sf o r c eo f r e p u l s i o ni,s c o n v e r t e di n t o e l e c t r i c aeln e r g ya n d a s i g n i f i c a n tsl ym a l l e a r m o u n to f h e a t . W h e nt h e N o r t hp o l eo f t h e m a g n e ti s m o v i n gu p w a r d sa w a y f r o mt h e c o i l ,t h e i n d u c e dc u r r e n t flowsin sucha way to producea Southpoleon the top of the coilto attractthe departingNorth poleof the magnet,and the work done in overcoming thisforceof attraction,is convertedto e l e c t r i c ael n e r g ya n da s m a l l e ar m o u n to f h e a te n e r g y . 103 INDUCTION OF ELECTROMAGNETIC APPLICATIONS ( 1 ) T h e A . C .G e n e r a t o r : W h e n a c o i li s m a d et o r o t a t ei n a m a g n e t i cf i e l d ,a n e . m . f .i s i n d u c e da c r o . stsh e e n d so f the coil. T h ed i a g r a ms h o w sa n a l t e r n a t i n g curreng t e n e r a t oar l s oc a l l e da n A L T E R N A T OTRh.i sc a nb e c o n v e r t e d t o a d . c .g e n e r a t obr y r e p l a c i ntgh e T INGS s l i pr i n g sw i t h S P L I R S l i pr i n g s T h e c o i l r o t a t e sr n a c i o c k w i s em o t i o n , a n d t h e m a g n e t i cf i e l d i s d i r e c t e df r o m l e f t t o r i g h t . A t t h e i n s t a n tw h e n t h e c o i l i s i n a h o r i z o n t apl o s i t i o nd u r i n gi t s r o t a t i o n t, h e R A T Eo f c h a n g eo f f l u x i s m a X i m u m a, n d t h e m a x i m u me . m . f .i s i n d u c e d . t h e r ei st h e n i a x i n - r unmu m b e ro f f i e l dl i n e sp a s s i n g W h e nt h e c o i li s i n t h e v e r t i c apl o s i t i o n O FF L U XC H A N GiESA M l N l M U N 4a, n dt h e i n d u c e de . m . f i. s z e r o . t h r o u g hi t , b u t t h e R A T E l n d u c e de . m . f T i me 1"04 i (2) TheTransformer: T h et r a n s f o r m eirs a d e v i c et h a t i s u s e dt o c h a n g et h e m a g n i t u d e of analternating voltage I t c o n s i s tos f t w o a d j a c e nst e p a r a t e c o i l so f w i r e ,w o u n do n a n i r o nc o r e . T h ec o i lo f w i r e t h a t i s c o n n e c t e tdo t h e i n p u tc u r r e n ti,s c a l l e dt h e P R I M A RC YO I La, n d t h e o u t p u ti s o b t a i n e df r o m t h e S E C O N D A R CY OIL. ) Power Station vP/ \ ) W h e na n a l t e r n a t i ncgu r r e n ti s a p p l i e da c r o s st h e p r i m a r yc o i l ,t h e c u r r e n t h a t f l o w s t h r o u g hi t , w i l l p r o d u c ea n a l t e r n a t i nm g a g n e t i fci e l d .T h i sa l t e r n a t i nm g a g n e t i fci e l d , i l l b e s t r i k i n gt h e c o i l so f t h e s e c o n d a rcyo i l .H e n c et h e s e c o n d a r y a r o u n dt h e p r i m a r yw c o i li s e x p o s e tdo a n a l t e r n a t i nogr c h a n g i nm g a g n e t ifci e l d 'By F a r a d a y 'Lsa w ,a n a l t e r n a t i neg. m . f .w i l l b e i n d u c e di n t h e s e c o n d a rcyo i l . For an IDEALtransformer,there are no power losses. = O U T P UP H e n c el NP U TP O W E R TOWER L e tt h e p r i m a r yv o l t a g e= V pa n d p r i m a r yc u r r e n t= l p L e tt h e s e c o n d a rvyo l t a g e= V , a n ds e c o n d a rcyu r r e n t= l , S i n c ep o w e r - V l , t h e n f o r n o p o w e r l o s s e sV o l o= V r l , T h e p r i m a r yv o l t a g ei s p r o p o r t i o n a tl o t h e n u m b e r o f t u r n s o n t h e p r i m a r yc o i l i.e. Vp x N, and si"mi"Iarly V, x IV, v,- n, _', w 1/, 105 Ip ER IM PORTANTREATURESOF THE TRANSFORM (1) lron Core: T h em a g n e t i fci e l dc o u p l i n gt h e c i r c u i t s ( p r i m aar ny d s e c o n d a rcyo i l s c) a nb e i n a i r ,b u t i s sf t h) e, c o r e ,i n w h i c ht h e f i e l dc a nb e t h o u s a n d o c aterial(IRON u s u a l l yi n a f e r r o m a g n e t im timesgreaterthan it would be in air, makingthe transformerefficientand small. (2) Laminations of the core: W h e na n a l t e r n a t i ncgu r r e n tp a s s etsh r o u g ht h e c o i l s ( w h i cahr ew o u n do n t h e i r o nc o r e ), a n a l t e r n a t i nm g a g n e t i c f i e lids s e t u p a r o u n dt h e c o r ew h i c hc a u s e cs u r r e n t sc a l l e dE D D Yc u r r e n t s to flow in the core. o f h e a te n e r g yw h i c hw o u l dl e a dt o a d e c r e a s ien t h e T h e s ee d d yc u r r e n t sc a u s et h e p r o d u c t i o n energyinput is converted of the transformersincenow someof the electrical overallefficiency to heatenergywhichwould.bewastedenergy. y u t n o t t o t a l l ye l i m i n a t e d ) b y o f E D D yc u r r e n t sc a nb e r e d u c e ds i g n i f i c a n t(l b T h i sp r o d u c t i o n l a m i n a t i ntgh e c o r e ,i . € .b y m a k i n gi t f r o m t h i n s h e e t so f m e t a lw h i c ha r et h e n a d h e r e d t o g e t h e rw i t h a t h i n f i l m o f i n s u l a t i nggl u e .T h e s et h i n f i l m so f g l u ep r e v e n t h e c o n d u c t i o on f e d d yc u r r e n t sf r o m o n e l a m i n a t i o tno t h e o t h e r .T h i sd e s i g ni s m u c hm o r ee f f i c i e ntth a n h a v i n g s etal. t h e c o r em a d ef r o m o n e s o l i db l o c ko f c o n t i n u o um (3) Efficientcore design: T h ec o r ei s m a d eo f E s h a p e dl a m i n a t i o ntsh a t a r e i n t e r l e a v esdo t h a t t h e m a g n e t i fcl u x d o e s i s e l i m i n a t e dT.h i sc o r ed e s i g ni s n o t p a s st h r o u g ht h e a i r a t a l l h e n c em a g n e t i fcl u x l e a k a g e e x p l a i n ea d sf o l l o w s : Shell-CoreTransformers (4). T h e m o s tp o p u l a ra n d e f f i c i e nttr a n s f o r m ecro r ei s t h e S = i r i a * = i = a s i l l u s t r a t eidn f i g u r e sectionsof metal.Thesesections of I- =:=*i:=i=*L:r:* As shown,eachlayerof the coreconsists s .h el a m i n a t i o nasr e i n s u l a t e fdr o m e a c ho t h e ra n d a r e b u t t e dt o g e t h e rt o f o r m t h e l a m i n a t i o n T then pressedtogetherto form the core. 106 LAMINATEDCORE .Fii E AND LAMINATIONS TRANSFORMW E RI N D I N G S A s s t a t e da b o v e t, h e t r a n s f o r m ecr o n s i s tos f t w o c o i l sc a l l e dW I N D I N Gw Sh i c ha r ew r a p p e d a r o u n da c o r e .T h et r a n s f o r m eor p e r a t e sw h e na s o u r c eo f a c v o l t a g ei s c o n n e c t e tdo o n e o f t h e w i n d i n g sa n d a l o a dd e v i c ei s c o n n e c t e tdo t h e o t h e r .T h ew i n d i n g t h a it s c o n n e c t e tdo i h e s o u r c ei s c a l l e dt h e P R I M A RW Y I N D I N GT.h ew i n d i n gt h a t i s c o n n e c t etdo t h e l o a di s c a l l e dt h e S E C O N D AW RY I N D I N G( N . o t e I: n t h i sp a r tt h e t e r m s" p r i m a r yw i n d i n g a" n d " p r i m a r ya" r eu s e d i n t e r c h a n g e a btl hy e ; t e r m : " s e c o n d a rwy i n d i n g "a n d " s e c o n d a r ya"r ea l s ou s e d i n t e r c hnag e ab l y . ) F i g u r e( 5 )s h o w sa n e x p l o d e dv i e wo f a s h e l l - t y pter a n s f o r m e T r .h ep r i m a r yi s w o u n di n l a y e r s d i r e c t l yo n a r e c t a n g u l acra r d b o a r fdo r m E. t-*rtdt{ATtoH IHSULATING PAPER I LAMINATION 1.07 l n t h e t r a n s f o r m esr h o w ni n t h e c u t a w a yv i e wi n f i g u r e( 6 ) ,t h e p r i m a r yc o n s i s tos f m a n y l i r e .T h ew i r ei s c o a t e dw i t h v a r n i s hs o t h a te a c ht u r n o f t h e w i n d i n gi s t u r n so f r e l a t i v e lsym a l w i n s u l a t e fdr o m e v e r yo t h e rt u r n . ! n a t r a n s f o r m edr e s i g n e fdo r h i g h - v o l t a gaep p l i c a t i o nssh, e e t s g a t e r i a sl ,u c ha s p a p e ra, r ep l a c e db e t w e e nt h e l a y e r so f w i n d i n g s t op r o v i d e o f i n s u l a t i nm a d d i t i o n ai nl s ul a t i o n . PAPER INSULATIOH LAMINATED CORE LEADS I / PRIMARY WINDING SECONDARY WINDING . he W h e nt h e p r i m a r yw i n d i n gi s c o m p l e t e lwy o u n d ,i t i s w r a p p e di n i n s u l a t i npga p e ro r c l o t h T s e c o n d a rwyi n d i n gi s t h e nw o u n do n t o p o f t h e p r i m a r yw i n d i n gA. f t e rt h e s e c o n d a rwyi n d i n gi s . e x t t, h e s e c t i o nosf t h e i r o nc o r ea r e . c o m p l e t e , ,t iot o i s c o v e r e dw i t h i n s u l a t i npga p e r N i n t oa n da r o u n ct ih e w i n d i n g as ss h o w n . inserted y r o u g h ot u t t h r o u g ha h o l ei n t h e e n c l o s u roef t h e T h el e a d sf r o m t h e w i n d i n g as r en o r m a l l b t r a n s f o r m e rS. o m e t i m e st e, r m i n a l sr n a yb e p r o v i d e do n t h e e n c l o s u rfeo r c o n n e c t i o nt so t h e w i n d i n g sT. h ef i g u r es h o w sf o u r l e a d st,w o f r o m t h e p r i m a r ya n dt w o f r o m t h e s e c o n d a r y . T h e s el e a d sa r et o b e c o n n e c t e tdo t h e s o u r c ea n d l o a d ,r e s p e c t i v e l y . 108 INDUCEE D M FT U T O R I ASLH E E T , ( 1 ) A r o d A B S O c m . l o nr go t a t e si n a u n i f o r mm a g n e t i fci e l dw i t h p o i n t A a c t i n ga st h e p i v o t . T h er o t a t i o ni s p e r p e n d i c u l a rtthoe f i e l dl i n e sa n dt h e f r e q u e n coyf r o t a t i o ni s 5 r e v o l u t i o npse rs e c o n dl .f t h e m a g n e t ifcl u xd e n s i t yi d O . 3 Td e t e r m i n teh e e m f i n d u c e d b e t w e e nt h e e n d so f t h e r o d . ( A n:s3 V ) ( 2 ) A 5 o c o i lo f 1 0 0 t u r n sa n dd i a m e t e 6 r c m i s p l a c e db e t w e e nt h e p o l e so f a m a g n e ts o t h a t t h e f l u xi s m a x i m u mt h r o u g hi t sa r e a W . h e nt h e c o i li s s u d d e n l rye m o v e df r o m t h e f i e l d , a c h a r g eo f 1 x l - 0 4 C f l o w st h r o u g ha 5 9 5 Og a l v a n o m e t ecro n n e c t e tdo t h e c o i l . C o m p u t eB b e t w e e nt h e p o l e so f t h e m a g n e t . ( 0 . 2 1 T ) l HU i nst e;V = r n = T ,a n d1 - f t ( 3 ) A f l a t c o i lo f r a d i u s8 c mh a s 1 5 0l o o p so f w i r e .l t i s p l a c e di n a s i n u s o i d a l m a g n e t ifci e l d t h a t v a r i e sa t a r a t eo f 1 . 6 T s -i 1 n s u c ha w a y t h a t t h e m a x i m u mf l u xg o e st h r o u g hi t . F i n d t h e a v e r a g e m f i n d u c e db e t w e e nt h e t e r m i n a los f t h e c o i l . (ANS;4.82v) ( 4 ) A c o p p e rd i s co f l d c m r a d i u si s r o t a t i n ga t 2 0 r e v i s a b o ui t sa x i sa n d w i t h i t sp l a n e perpendicula t or a u n i f o r mf i e l dw i t h B =0 . 6 T W . h a t i s t h e p o t e n t i adl i f f e r e n c b eetween t h e c e n t r ea n dt h e r i m o f t h e d i s c . r r- e ( A n s: 0 . 3 8 V )f H i n t ;I r e v o l u t i o n = a r e ao f' O"I S C = T t l)" , d ' A: --v d, ttO. Ol 1 ATee Of diSC] ( 5 ) H o wm u c hc h a r g ew i l lf l o wt h r o u g ha 2 0 0 0g a l v a n o m e t ce or n n e c t e d t o a 4 0 0 0c i r c u t a r c o i lo f 1 0 0 0t u r n sw o u n do n a w o o d e ns t i c k2 c mi n d i a m e t e r , i f a m a g n e t i fci e l dB = 0 . 0 1 1 - 3pTa r a l l et lo t h e a x i so f t h e s t i c ki s d e c r e a s esdu d d e n l y t o zero. ( A n s 5: . 9 p C ) (6)A solenoi6 d 0 c ml o n gh a s5 O 0 C t u r n sa n d i s w o u n do n a n I R O Nr o d o f 0 . 7 5 c mr a d i u s . F i n dt h e f l u xd e n s i t ya n df l u x t h r o u g ht h e s o l e n o i w d h e nt h e c u r r e n itn i t i s 3 4 . T h e r e l a t i v ep e r m e a b i l i toyf i r o n i s 3 0 0 . ( b )T h ef l u xi s r e d u c e d t o a v a l u eo f l m W b i n a t i m e o f 0 . 0 5 0 s. F i n dt h e i n d u c e de m f i n t h es o l e n o i d . ( A n s: 9 . 4 2 ;T1 . 7 m W b ; 67V) 109 for previoustutorial Solutionguidelines o n e .H e n c ef o r e a c hr e v o l u t i o n L . T h es h a p et h a t t h e r o d c u t so u t a s i t r o t a t e si s a c i r c u l a r t h e r a d i u sr i s t h e l e n g t ho f t h e t h e a r e ao f f i e t dl i n e st h a t a r ec u t i s e q u a lt o n r 2 w h e r e rod. o f t h e i n d u c e de m f ,i t i s n e c e s s a r y tdoe t e r m i n et h e r a t e e agnitude ln determiningthm of Area)' at whichthe flux is cut whichin this caseis B x (rateof change w h i c hw o u l db e e q u a lt o t h e T h e r a t eo f c h a n g eo f a r e ai s t h e a r e ac u t o u t p e r s e c o n d , o f r e v o l u t i o npse r p r o d u c to f t h e a r e ao f t h e c i r c l e ( i . e1.r e v o l u t i o na)n dt h e n u m b e r second.' is equalto 600 o, the radiusis 0.03m,N= 100Q= l- x 10-4c' 2. Thetotal resistance e x p e r i e n c easc h a g ei n T h e m o v e m e not f t h e c o i lo u t o f t h e f i e l dm e a n st h a t t h e c o i l causea s n e m ft o b e t h e n u m b e ro f m a g n e t i c f i e lldi n e sc u t t i n gi t , a n dt h i sc h a n g e L 'asw ) i n d u c e di n t h e c o i l ( F a r a d a Y a n d h e n c ea c u r r e n tw i l l T h ei n d u c e de m f i s a p p l i e da c r o s sa t o t a l r e s i s t a n coef 6 0 0 0 f l o w t h r o u g ht h i s r e s i s t a n c e ' m o v e d ,h e n c ei t i s w e d o n o t k n o wt h e v a l u eo f t h e t i m e f o r w h i c ht h e c o i lw a s n e c e s s a r y tsoe t u p a n e q u a t i o nw h e r et h e t i m e c a nb e e l i m i n a t e d ' F r o m O h m ' sL a w , ,: NBAIt V I n d u c e d " e m:f ,4\ tr/ l n: T - g'e A r s o c u r r e n t r - T o t attme '.|'charg t Q) (1) and (2) Thecurrent ts the sametnboth equattonsso we c&nequate NBAI. n v lt : R t, NBA ;-Q 110 henceBcanbefound 3 . T h ei n d u c e e dm . f i . sg t v e n b yE _ - #: -rO# wttere#: r.6Ts-l 4 . T h eh i n t i s a l r e a d yg i v e ni n t h e q u e s t i o n 5. Applythe samemethodas in question2. Thewood doesNOTaffectthe Flux 6. ln usingthe formulafor Fluxdensityincludethe relativeperrrreability of iron, so the f o r m u l an o w b e c o m e B s - V oV r n I lJT 2 lVl.of,ufe I I M P O R T A NETQ U A T I O N S (1)A sinusoidal voltage or current i.srepresented by i x - xssinat (2)Ther . m.s.ualueof an a.c.ts Ir.^.r.: 'ff (3)Gainof an inverttngamplifter ts gtvenby:Gatn+ L ( 4 ) G a t n o f I N O N - I N V E R T I N Ga m p l i f t e r t s g t v e n b y G a i n - t * Rr & $ ) f h e G a t n o f a c o m b t n a t i o no f C a s c a d e dA m p l i f t e r s i s A A r A z A 3. . . "Everythingis determined... by forces over which we have no control.lt is determinedfor the insecfsas well as for the star. Human beings, vegetables,or cosmic dusf - we all dance t.oa mysteriousfune, intonedin the distanceby an invisiblepiper." - Albert Einstein 112 A L T E R N A T I NC GU R R E N T A n a l t e r n a t i ncgu r r e n it s o n e i n w h i c ht h e d i r e c t i o cn h a n g eps e r i o d i c a l l y . s i nu s o i d Ia s qu ar e w a v e a . c . rrnllroo o r c ur r e n t VALUE o f t h e c u r r e n ot r v o l t a g ew, h i c hi s I n b o t hc a s e s t, h e r ei s a m a x i m u mv a l u eo r P E A K u s u a l l yw r i t t e na s I n . . uo ,I V r u ^ . T h ef r e q u e n coy f t h e a . c .i s t h e n u m b e ro f c y c l e p s e rs e c o n da n di s m e a s u r eidn H e r t z( H z ) . v a l u eo f a n a . c .i st h a tf r a c t i o no f t h e p e a kv a l u et h a t w o u l dd i s s i p a t e T h eR O O TM E A NS Q U A R E h e a ta t t h e s a m er a t ea sa s t e a d yd . c .t h r o u g ha g i v e nr e s i s t o r . H e n c ef o r a n yr e s i s t o r ' R t' ,h e c u r r e n dt i s s i p a t ebdy a s t e a d yd . c .i s g i v e nb y P - l z d . r .aRn dt h e e q u i v a l e npto w e rd i s s i p a t ebdy a n a l t e r n a t i ncgu r r e n t ,i s P - I ? . ^ . r R . r h e nt h e S I N U S O I D A aL . c .p a s s etsh r o u g hi t , i s t h e T h ep o w e rd i s s i p a t ebdy t h e r e s i s t ow A V E R AE GP O W E R . AVERAGE POWER= MAXiMUM POWER t2p + ( S I N U S O I D cAaLs e ) T h i sa v e r a g ep o v / e i , a l s oe q u a l t o I i ^ r R . ,.) HencellrnrR : lmK -------\ t-- z #-, Ir^, 113 :lm <- ,tz LEARN S i m i l a rV l yr * r : ' r , +- LEARN. Another useful f ormula is i Vr^-I--n , I r ^ , -jry'+ i O- V^I^ t: AveragePower In the caseof the squarewave from the abovegraph,the magnitudeof the currentand voltageis constant,and the power dissipatedis constant. Hencefor the squarewave shown above,the r.ms.valuesof both voltageand currentwill be the sameas the steadymaximum value. Sincean alternating voltageor currentcanbe represented by a sinewave,the voltageor currentat any instantcanbe expressed as : V:Vmsinat and I - I^sinat, where a is the AN GULAR FREQUEN CY of the pd. or current. The angularfrequencyu = 2nf, where'f is the frequencyof the currentor voltage. F o re x a m p l et h e m a i n ss u p p l yi n T r i n i d a dh a sa f r e q u e n c o y f 6 0 H z .H e n c et h e a n g u l a r frequencyu,ris givenby ul = 2n x 60 = 1,20nrad.s-1. ( R e c a tl h l a t f o r t h e s i n ew a v e ,1 c y c l er e p r e s e n t2sn r a d i a n s ) . W h e na l t e r n a t i ncgu r r e n t sa n dv o l t a g e a s r e m e a s u r e dt h, e i n s t r u m e n tm s easure the r.m.s. v a l u e sr a t h e rt h a nt h e p e a kv a l u e s . 1.1.4 Advantagesof transmissionof currentsusingalternatingcurrentsand highvoltages: (1) Alternatingcurrentsareeasierand cheaperto producethan directcurrents.The alternating currentis producedby rotatinga coilin a magneticfield and the mechanical energyfor rotation comesfrom steamwhich is producedfrom the heatingof water with naturalgasbeingthe fuel. Directcurrentsare producedfrom chemicalreactionsin a batterywhich is relatively expensiveto manufacture. (2) The alternating voltagescan be increased or decreased as requiredwith minimum energywastageby meansof a transformer,whereasthe direct voltagehasto be altered by meansof resistors whichhavesignificant energydissipation. (3) Thereis significantlandpollutionwith the disposalof batterieswhereaswith a.c. generationthere is the issueof fossilfuel emissions. (4) When alternating€u rrentsare transmittedat high voltages,there is significantlyless powerlossesin the cablesas comparedto low voltagetransmission. Thisis explainedasfollows:The currentpassing throughthe cablesfor a particular street or district, is determinedby the power requirementof that district.lf a district hasan averagepowerrequirementofsay 2MW, and the resistance ofthe overhead'' cablesis 0.20. Whenthe a.c.is transmittedat 240V,the currentthroughthe cableswill be: P ower Cut'rent - Voltag e 2,000,000 . = 8333/, and the power lossesin the cableswould be l2R,whichwould give I ='# a a value of 1.39x 106W,which is in fact almostthe power requiredby the district. Howeverif highvoltagesare usede.g.24000V,the currentin the cableswill be 2'000'000 = 83,4and the oowerlossin the cablesis 832xo.2= 1378W. f 24000 ' The highvoltagescanbe steppeddown to 110Vor 220Vby meansof a transformeron reaching the district 115 QUESTIONS ( 1 ) I n t h e f o l l o w i n gw a v e f o r m sr e p r e s e n t i nagn a l t e r n a t i ncgu r r e n tt,h e p e a kv a l u eo f t h e a . c .i s 5 A .C a l c u l a t eh e r . m . sc. u r r e n it n e a c hc a s e . c ur r en t (a) currenI A N S: 3 . 5 4 A ,3 . 5 4 A 5 , A. (c) ( 2 ) A v o l t m e t e r e a d s1 1 0 Vw h e n i t i s c o n n e c t e d a c r o s st h e t e r m i n a l so f a s i n u s o i d aplo w e r W r i t e d o w n t h e e q u a t i o nf o r t h e i n s t a n t a n e o u s s u p p l yt h a t h a s a f r e q u e n c yo f 6 0 H 2 . v o l t a g ep r o v i d e db y t h e s o u r c e . ( 3 ) A s i n u s o i d aal l t e r n a t i n gc u r r e n ti n a 4 0 O r e s i s t o rp, r o d u c e sh e a t a t a r a t e o f 7 5 0 W . D e t e r m i n teh e m a x i m u mv a l u e so f v o l t a g ea n d c u r r e n t. 1.16 (4) Determine t h e r . m s .v a l u eo f t h e c u r r e n ti n ( i )a n dt h e r . m . sv. o l t a g ei n ( i i ) V A N S :4 4 , 1 1 0 V ( 5 ) W h e na n a . c .s u p p l y . o1f 2 0 V , . *i s, c o n n e c t e tdo a c i r c u i t i n w h i c ht h e r e is a fuse in series w i t h a l o a d ,t h e f u s eb r e a k st h e c i r c u i tw h e nt h e c u r r e n jtu s t e x c e e d gs A r . m . s .l f t h e a . c .s u p p l y i s r e p l a c e db y a 8 0 V d . c .s u p p l y w , h a t m u s t b e t h e m a x i m u mc u r r e n tp a s s i n through g the fuse j u s t b e f o r ei t b r e a k st h e c i r c u i t ? ( 6 ) T h es i n u s o i d a l l t a g eV r a p p l i e da c r o s sa r e s i s t o r ' R ' p r o d u chees a ta t vo a m e a nr r t u p . ' l f t h e s i n u s o i d aal. c .i s n o w r e p l a c e dw i t h s q u a r ew a v ea . c .a s s h o w ni n ( i i ) with the same p e a kv a l u ea s b e f o r e w , h a t i s t h e n e w r a t eo f h e a tp r o d u c t i o n ? v- IT7 Solutions ( 1 ) I n t h e c a s eo f t h e s i n u s o i d aglr a p h t, h e r . m . s c. u r r e n ti s g i v e nb y : r-*--'^y-:-3.s4A rrms- O-O-rrr ( b )T h eg r a p hi n ( b ) i s a l s oc y c l i cw i t h e a c hc y c l eh a v i n ga c o n t i n u o u5s A r e g i o nf o l l o w e db y a zeroregion l f t h i s c u r r e n tw a sa l l o w e dt o p a s st h r o u g ha r e s i s t o rt ,h e p o w e rd i s s i p a t ebdy t h e r e s i s t o r f o r t h e c o n s t a nct u r r e n to f 5 A w o u l dh a v eb e e nP = l 2 R= 2 5 R . r o u l dh a v eb e e n0 . D u r i n gt h e i n t e r v aol f z e r oc u r r e n tt,h e p o w e rd i s s i p a t ebdy t h e r e s i s t ow IzR + 0 The average power dtsstpated - Z 25R : z B yd e f i n i t i o nt ,h i sw o u l dh a v eb e e nt h e p o w e rd i s s i p a t ebdy t h e r . m . s c. u r r e n t H e n cIe? ^ r R: ' + t i l , m s :+ - 3 . 5 4 A 12 ( c )l n t h i s p a r t ,e a c hc y c l eo f t h e c u r r e n th a sa c o n s t a npt o s i t i v e5 A . f o l l o w ebdy a c o n s t a n t negative5A. r d u r i n gt h e p o s i t i v eh a l fc y c l ei s T h ep o w e rd i s s i p a t ebdy a r e s i s t oR Pt: I z R - 5 2 R- 2 5 R r is D u r i n gt h e n e g a t i v eh a l fc y c l et,h e p o w e rd i s s i p a t ebdy a r e s i s t oR P z : 1 2 R- ( - 5 ) 2 R - 2 5 R Average power dtssipated - Pt * Pz : 25R + 25R T T h i si s t h e p o w e rd i s s i p a t ebdy t h e r . m . s c. u r r e n tb y d e f i n i t i o n , Hence I?*rR : 25Ri Ir^s : 5A 118 : 50R Z : 25R (2) V- V^orsinl)t : V*o* stnZrcft We first needto find the valueof V.r". T h e 1 L O Vr e c o r d e db y t h e v o l t m e t e ri s i n f a c t h e r . m . s v. o l t a g eA. l l a . c .m e a s u r i nign s t r u m e n t s a r e d e s i g n e tdo g i v et h e r . m . s v. a l u e s . Recallvro, ,t : . v^o* fi; h, e n c e V ^ o ,- \n x 110V : 1.55.6V T he g eneral equati"onbecomesV - 155.6 sinZrcx 60t V : 155.6sin 12Ont ( 3 )T h eh e a td i s s i p a t ebdy t h e r e s i s t oirs o b t a i n e df r o m t h e f o r m u l a P - I?^rR; 500 : I?^, x 40 i lrms : I*o*:lr^rx12:3.54 x ..12= 500 :3.54A 40 54. V*o*: I^o, x R - 5 x 4 0 : 200v ( a ) F o rt h e p o s i t i v eh a l fc y c l et,h e m a x i m u mc u r r e n ti s 8 A . I f t h e c u r r e n tw a sa c o m p l e t es i n e wave,the powerdissipated by a resistorR would havebeen 12D P :'^7" z wave the power d.i"sstaptedwouldbe P; Howaver f or a HALF si"ne IhorR B yd e f i n i t i o nt ,h e p o w e rd i s s i p a t ebdy t h e r . m . s c. u r r e n tw o u l db e e q u a lt o t h i s l a t t e rv a l u e , I?.*.r.R: IlnorR ; hence Ir.^.r. : 119 I?,o* - I*o* B : 4 2 t: 44 r for a F o rt h e v o l t a g eg r a p h t, h e p o w e rt h a t w o u l dh a v eb e e nd i s s i p a t etdh r o u g ha r e s i s t oR F U L Ls i n eg r a p hw o u l dh a v eb e e n : Io -- v"1n' :zR is H e n c ef o r a H A L Fs i n eg r a p ht h e p o w e r t h a t w i l l b e d i s s i p a t e d , - v'?''n' I 4R Vl,n, :P: Bydefinltiort,f L { e n cver ^ r . - v r y ' - 2 : 22 V|o, * - 1,i,ov . ence q u e s t i o nT.h ef u s ew i l l b r e a kw h e n e v etrh e c u r r e n et x c e e d8sA r . m . s H ( 5 )T h i si s a T R I C K t h e s u p p l yv o l t a g ea, c u r r e n to f 8 A r . m . s i.s r e q u i r e dt o m e l tt h e f u s ew i r e . R E G A R D L EoSf S a s g i v e nb y ( 6 )I n t h e c a s eo f t h e s i n u s o i d a l v o l t a tghee, p o w e rd i s s i p a t ei d 'Dl Vior zR F o rt h e s { u a r ew a v e ,t h e v o l t a g eh a sa C O N S T A NMTA G N I T U DoEf V . . " , a n d i n t h i sc a s et,h e p o w e rd i s s i p a t eids g i v e nb Y 'D2 - _ V v t2 nQx R Hence P2:2P1 124 (Ans.2P) SEMICONDUCTORS T h ee l e c t r o n cs o n t a i n e d i n s o l i d sa, r ec o n t a i n e d i n v a r i o u sb a n d so f e n e r g yl e v e l s . T h eh i g h e sbt a n di s c a l l e dt h e C O N D U C T I OBN A N Da n d i n m e t a l st,h e r ea r ef r e ee l e c t r o ntsh a t m o v ew i t h i nt h e c o n d u c t i obna n d . I n i n s u l a t o r es l, e c t r o nasr eh e l di n a l o w e rb a n dc a l l e dt h e v a l e n c e b a n d ,a n dt h e r ei s a r e l a t i v e llya r g eg a pb e t w e e nt h e v a l e n c eb a n da n dt h e v a c a n ct o n d u c t i o b na n d . H e n c ef o r i n s u l a t o rtsh e e l e c t r o n m s u s tb e s u p p l i e d w i t h a r e l a t i v e llya r g ea m o u n to f e n e r g y t o j u m p i n t ot h e c o n d u c t i obna n di n o r d e rt o p a r t i c i p a ti en e l e c t r i c ac lo n d u c t i o n . I n s e m i c o n d u c t osr su c ha s s i l i c o nt,h e e n e r g yl e v e ld i f f e r e n c b e e t w e e nt h e v a l e n c eb a n da n d t h e c o n d u c t i obna n di s m u c hs m a l l etrh a nt h a tf o r i n s u l a t o r as n , dh e n c et h e ya r ea b l et o c o n d u cw t h e no n l ya s m a l lp o t e n t i adl i f f e r e n c ies a p p l i e da c r o s st h e c r y s t a l . Conductiob nand P a r t l yf i l l e dw i t h c h a r g e Conductiob nand E m p t yo f c h a r g ec a r r i e r s Conductiob nand A l m o s te m p t y { c o n t a i nos n e o r t w o c h a r g ec a r r i e r s c ar r ie r s V a l e n c eb a n d ( f i l l e d ) V a l e n c eb a n d ( f i l l e d ) E n e r g yb a n d sf o r M E T A L E n e r g yb a n d sf o r I N S U L A T O R E n e r g yb a n d sf o r SEMICONDUCTOR T h eg a pb e t w e e nt h e v a l e n c e b a n da n dt h e c o n d u c t i obna n di s c a l l e dt h e F O R B I D D E GN Ap. 1.21 Conductionin Semi-conductors: l n t h e c r y s t aol f s e m i c o n d u c t i nmga t e r i a li,f a n e l e c t r o ne s c a p efsr o m i t s p o s i t i o ni n t h e l a t t i c e , a v a c a n c yi s l e f t b e h i n da, n d s i n c et h i s p o s i t i o nw a si n i t i a l l yn e u t r a lt,h e l o s so f t h e e l e c t r o nw i l l l e a v ei t w i t h a p o s i t i v ec h a r g ea n d i s c a l l e da H O L E . T h i sh o l ea c t sa s a v a c a n c fyo r a n yo t h e re l e c t r o na n dw h e n i t i s f i l l e d ,a n o t h e rh o l ew i l l b e createdwherethe other electronwould haveleft. s o v ei n o n e d i r e c t i o nh, o l e sm o v ei n A l o n ga n ys t r a i g hlti n e ,i t w i l l b e s e e nt h a t w h i l ee l e c t r o n m t h e o p p o s i t ed i r e c t i o n . CARRIER. CHARGE as a POSITIVE The holecanthereforebe considered l n t h i sc a s et h e n u m b e ro f h o l e sw i l l b e e q u a tl o t h e n u m b e ro f m o b i l ee l e c t r o nasn ds i n c ea l lo f s o n o t c o m ef r o m a n ye x t e r n asl o u r c et,h e s e m i c o n d u c t oi srs a i dt o b e t h e c h a r g ec a r r i e r d INTRINSIC. s i l l e s c a p ef r o m t h e i r o f a s e m i c o n d u c t oi sr i n c r e a s e dm, o r ee l e c t r o nw W h e nt h e t e m p e r a t u r e n i l l i n c r e a s ae n d r e s i s t a n cwei l l s i t e sa n d m o r eh o l e sw i l l b e c r e a t e dh, e n c e t h ec o n d u c t i o w decrease. . h ea m o u n t e st h e i rc o n d u c t i o ins t o o l i m i t e dT I n t r i n s i sc e m i c o n d u c t oar sr e o f l i t t l ei m p o r t a n c a o f c o n d u c t i o tna k i n gp l a c ec a nb e i n c r e a s egdr e a t l yb y i n c r e a s i ntgh e n u m b e ro f a v a i l a b l he o l e s ' or electrons. T h i sc a nb e d o n eb y a d d i n ga s m a l la m o u n to f a n o t h e rm a t e r i atlh a t c a ns u p p l ya d d i t i o n a l a n dt h e m a t e r i atlh a t i s a d d e di s c a l l e da n h o l e so r e l e c t r o n sT.h i si s r e f e r r e dt o. a s D O P I N G IMPURITY. e m i c o n d u c t ba rn dt h e r e t hr a t i s p r o d u c e db y d o p i n gi s c a l l e da n E X T R I N SsI C T h es e m i c o n d u c t o aretwo types,i.e.n-typeand p-type. 122 The n-typesemiconductor: The 'n' refersto NEGATIVE type.When a siliconcrystalis dopedwith a penta-valent element s u c ha s p h o s p h o r o uosr a n t i m o n yt,h e i m p u r i t ya t o m r e p l a c eosn e o f t h e s i l i c o na t o m si n t h e c r y s t a lS. i l i c o nh a sa v a l e n c eo f f o u r a n d s h a r e sf o u r e l e c t r o nw s i t h n e i g h b o r i nagt o m s .W h e n t h e p h o s p h o r o uast o m r e p l a c eas s i l i c o na t o m ,f o u r o f i t sv a l e n c ee l e c t r o nw s i l l b e u s e di n c o v a l e nbt o n d i n gT. h ef i f t h e l e c t r o nw i l l b e a b l et o d r i f t i n t h e c o n d u c t i o b n a n da n dt a k ep a r ti n c o n d u c t i o na,n dt h e i m p u r i t ya d d e di s c a l l e da D O N O Ra s i t d o n a t e se l e c t r o nfso r c o n d u c t i o n . The majority chargecarriersin the n-type materialare electrons. T h ed o p e ds e m i c o n d u c t iosrh o w e v e sr t i l le l e c t r i c a lnl ye u t r aal s n e i t h e r t h es i l i c o n o r t h e d o n o ra t o mh a da n yn e t c h a r g eos n t h e m . The p-typesemiconductor: The 'p' refersto POSITIVE type and the majoritychargecarriersare holes. T h i si s m a d eb y d o p i n gs i l i c o n w i t h a t r i - v a l e ni tm p u r i t ys u c ha s B o r o no r A l u m i n i u m . A s i l i c o na t o m i s r e p l a c e db y t h e t r i v a l e n at t o ma n dt h r e eo f t h e v a c a n c i el se f t b y t h e m i g r a t e d s i l i c o nw i l l e db e f i l l e db y t h e t h r e ev a l e n c ee l e c t r o n isn t h e i m p u r i t yT. h ef o u r t hv a c a n c w y i l J. t h e na c L e p a t n e l e c t r o nf r o m t h e v a l e n c eb a n d ,t h u sc r e a t i n ga h o l ei n t h e v a l e n c eb a n d .T h e v a l e n c eb a n dw i l l t h e n b e a b l et o c o n d u c w t i t h t h e p r e s e n c oe f h o l e si n i t . T h e i m p u r i t yi n t h i s c a s ei s c a l l e da n A C C E P T O R . Material N u m b e rd e n s i t yo f Resistivity C h a r g eC a r r i e r s (r-') (o.m) Metal 9 x 1028 2 x 10' 8 Intrinsic Semiconductor 3x103 Extri nsic S e m i c o n d u c t o| r1 x 1 0 " t o 1 x 1 O 2 a 5 x 1 0 8 L23 LEARNTHE NUMBERS T H EP . NJ U N C T I O N A p - nj u n c t i o ni s a s e m i c o n d u c t corry s t at lh a t i s d o p e di n s u c ha w a yt h a t o n e r e g i o ni s n - t y p e a n dt h e a d j a c e nrte g i o ni s p - t y p e . T h i sc a nb e v i s u a l i z eadsa b l o c ko f n - t y p em a t e r i abl e i n gp r e s s e d a g a i n sat b l o c ko f p - t y p e material. C p C Fo o on o C clo <tO n -+t+- O O At the interface o f t h e p - nj u n c t i o nt h e r ei s a n i n i t i a d l i f f u s i o no f e l e c t r o nfsr o m t h e n - t y p e , n d a d i f f u s i o no f h o l e sf r o m t h e p - t y p et o t h e n - t y p e . t o t h e p - t y p ea T h em o t i o no f b o t ht h e H o l e sa n dt h e e l e c t r o npsr o d u c ea D I F F U S I OCNU R R E Nl 6T; 6 t h ai ts c o n v e n t i o n a ldl yi r e c t e df r o m p t o n , i . e .c o n v e n t i o n ac lu r r e n ti s t h e f l o w o f p o s i t i v ec h a r g e . W h e na n e l e c t r o nf r o m t h e n - s i d ec r o s s etsh e j u n c t i o na n d e n t e r st h e p - s i . d ei ,t f i x e si t s e l f i n t oa v a c a n st i t ea n dp r o d u c eas n e g a t i v ceh a r g eo n t h e p - s i d en e a r t h ej u n c t i o n . S i m i l a r l yw,h e na h o l ec r o s s etsh e j u n c t i o na n de n t e r st h e n - s i d ei ,t w i l l p r o d u c ea p o s i t i v e c h a r g eo n t h e n - s i d en e a rt h e j u n c t i o n . T h ed i f f u s i o no f c h a r g ec a r r i e r cs a u s e tsh e b u i l d -u p o f a n e t p o s i t i v ec h a r g ei n a n a r r o w s t r i po n t h e n - s i d ec l o s et o t h e j u n c t i o na, n d a n a r r o ws t r i po f n e g a t i v e c h a r g eo n t h e p - s i d e c l o s et o t h e j u n c t i o n T h e r e g i o no n e i t h e rs i d eo f t h e j u n c t i o nb e c o m e a s l m o s tf r e bo f m a j o r i t yc h a r g ec a r r i e r s a n d i s c a l l e dt h e D E P L E T I OLN AYER o r B A R R I ELRA Y E R . T h ee x i s t e n coef t h i sd e p l e t i o nl a y e rp r e v e n t sa n yf u r t h e rd i f f u s i o no f c h a r g ec a r r i e r s . r) a) .) n C 124 T h e r ei s a s m a l lv o l t a g ea c r o s st h e d e p l e t i o nl a y e rc a l l e dt h e j u n c t i o np . d .o r b a r r i e rv o l t a g e . The depletionlaye.ris approximately1Fm thick. S i n c et h e d i f f u s i o nc u r r e n ti s t h e f l o w o f h o l e s i,t i sj u s t b a l a n c e b d y t h e f l o w o f e l e c t r o n isn theopposite direction a n dt h e c u r r e n dt u et o t h e m o t i o no f t h e e l e c t r o niss c a l l e dt h e D R I F T C U R R E NlTa , i r , T h ed r i f t c u r r e n ti s a l w a y si n t h e o p p o s i t ed i r e c t i o nt o t h e d i f f u s i o nc u r r e n t . Recallthat diffusioncurrentis directedfrom p-typeto n-typewhile DRIFTcurrentis directed from n-typeto p-type. BIAS W h e na b a t t e r yi s c o n n e c t e a d c r o s st h e p - nj u n c t i o ns u c ht h a t t h e p o s i t i v ep o l eo f t h e b a t t e r y c o n n e c t tso t h e p - s i d eo f t h e j u n c t i o na n dt h e n e g a t i v e p o l eo f t h e b a t t e r yc o n n e c t tso t h e n s i d eo f t h e j u n c t i o nt,h e p - nj u n c t i o ni s s a i dt o b e F O R W A R B Dl A s E D . l f h o w e v e tr h e p o s i t i v eO o ' "o f t h e b a t t e r yw a sc o n n e c t e tdo t h e n - s i d eo f t h e p - nj u n c t i o n , and the negative p o l ec o n n e c t e tdo t h e p - s i d et,h e nt h e j u n c t i o nw o u l dh a v eb e e nR E V E R S E BIASED. F o r w a r dB i a s R e v e r s eB i a s I n t h e f o r w a r db i a sc o n n e c t i o nt h, e I n t h e r e v e r s eb i a sc o n n e c t i o nt ,h e n - d e p l e t i o nl a y e ri s o v e r c o m e ,becomes t y p e i s m a d em o r e p o s i t i v ea n d t h e p - n a r r o w e r a n d h o l e sf r o m t h e p - t y p e t y p e m o r e n e g a t i v eT. h i sc a u s e sa n w i l l f l o w t o t h e n - t y p e ,a n d e l e c t r o n s i n c r e a s ien t h e w i d t ho f t h e d e p l e t i o n f l o w i n gi n t h e o p p o s i t ed i r e c t i o nT. h e l a y e r ,c a u s i n ga v e r y h i g hr e s i s t a n c e c u r r e n ti s i n t h e o r d e ro f m i l l a m p e r e s . s o t h a t t h e c u r r e n ft l o w i n gt h r o u g h t h e j u n c t i o ni s a p p r o x i m a t e zl ye r o . . p - n j u n c t i o nt h e r e f o r ea c t s a s a r e c t i f i e r , a s i t a l l o w sc u r r e n tt o f l o w i n o n e d i r e c t i o no n l y . 1,25 for a p-n iunction. The current - voltage characteristic Current/mA Forward lv T h ej u n c t i o ns t a r t st o c o n d u c itn t h e f o r w a r dd i r e c t i o na t o r a r o u n d0 . 6 V ,a n dt h i sp . d .i s c a l l e d t h e s a t u r a t i o vn o l t a g e . illiam nection DIODE: OFTHEP.NJUNCTION APPLICATIONS - h e n a n a . c .i s a p p l i e dt o t h e d i o d e ,t h e j u n c t i o nc o n d u c t si n t h e ( 1 ) A s a h a l f w a v e r e c t i f i e rW forwarddirection,but preventscurrentfrom flowingin the reversedirection. (2) As a full-waverectifier. l n t h i sc a s ef o u r d i o d e sa r ec o n n e c t e tdo f o r m a b r i d g e W h e n X i s p o s i t i v ec, u r r e n tf l o w st o B t o R t o C a n dt h e n t o Y . W h e nY i s p o s i t i v et,h e c u r r e n tf l o w s t o D t o R t o A a n dt h e n t o X . I n b o t h h a l fc y c l e st,h e c u r r e n ti n R i s i n t h e s a m ed i r e c t i o n . 126 (3) The manufactureof the light-emittingdiode(LED) W h e na n e l e c t r o nf r o m t h e c o n d u c t i o b n a n df a l l si n t o a h o l et h e v a l e n c eb a n d ,t h e r ei s a l o s so f e n e r g yo f t h e e l e c t r o nw s h i c hi s d i s s i p a t eads h e a t .T h e r em u s tb e a l a r g e n u m b e ro f e l e c t r o n - h o lceo m b i n a t i o nt so c a u s et h e e m i s s i o o n f l i g h t .T h i si s a c h i e v e d by a p p l y i n ga s t r o n gf o r w a r db i a so n a h e a v i l yd o p e dp - nj u n c t i o n (a) The photo diode: W h e na c u r r e n ti s p a s s e d t h r o u g ha p - nj u n c t i o nl i g h ti s e m i t t e d .l t f o l l o w st h e n t h a t i f l i g h ti s ' i n c i d e notn a p - nj u n c t i o na, c u r r e n tc a nb e p r o d u c e di n t h e c i r c u i ct o n t a i n i n g t h e p - nj u n c t i o n . T h i sa p p l i c a t i oins c o m m o ni n t h e o p e r a t i o no f a T V r e m o t ec o n t r o l . W h e nt h e r e m o t ec o n t r o li s c l i c k e da, l i g h te m i t t i n gd i o d ee m i t si n f r a r e dl i g h ti n a particularsequenc,e. The receiving deviceon the TV detectsthe infrared lightand p r o d u c ee s l e c t r i c asli g n a ltso c h a n g et h e T V s e t t i n g s . 1.27 THETRANSISTOR W h i l et h e p - nj u n c t i o ni s a t w o t e r m i n a dl e v i c ea n di s u s e dp r i m a r i l ya s a r e c t i f i e rt ,h e s a na l yo r ea p p l i c a t i o nt h i sR a t h r e et e r m i n a dl e v i c ea n d h a ss i g n i f i c a n tm TRANSISTO g n di s a n e s s e n t i a l , itchina s i n g l ep - nj u n c t i o na, s i s i t u s e df o r s i g n aal m p l i f i c a t i o sn w EIDR C U I T S ( l C ' s ) c o m p o n e ni tn a l l I N T E G R A TC T h eJ U N C T I OTNR A N S I S T Oi sRm a d eu p o f t w o p - nj u n c t i o n sc o n n e c t e idn s e r i e s, b a c k to back. T h ea r r a n g e m e no tf t h e j u n c t i o n cs a ng i v ee i t h e ra P N Po r a n N P Nt r a n s i s t o r . A n n p nt r a n s i s t o r A p n pt r a n s i s t o r emitter CIRCUIS TYMBOLS: NPN PNP I C -\ ( I c r28 T h ed i r e c t i o no f t h e a r r o w h e a do n n d i c a t ew s h e t h e rt h e t h e E M I T T EiR t r a n s i s t oi rs n p no r P n P T . h ea r r o w of conventional p o i n t si n t h e d i r e c t i o n c u r r e n ti . e .f r o m p t o n . O P E R A T I O N AAL M P L IF IE R S T h eo p e r a t i o n aalm p l i f i e r ( a b b r e v i a o t epd- a m p )i s a d e v i c et h a t c a np e r f o r mm p t h e m a t i c a l o p e r a t i o nssu c ha sa d d i t i o nm , u l t i p l i c a t i oann di n t e g r a t i o n . I t h a so n e O U T P U a Tn dt w o I N P U T Sa,n d h a sa s e p a r a t e s e to f c o n n e c t i o nt sh a t a r e u s e dt o p o w e ri t . T h ep o t e n t i a l d i f f e r e ntchea t i s u s e dt o s u p p l yp o w e r t oi t i s c a l l e dt h e S U p p L y VOLTAG E. T h eS U P P LVYO L T A Gm E u s tn o t b e c o n f u s e d w i t h t h e I N P U TV O L T A G E a s, t h e l a t t e ri s t h e o n e t h a t i s s e n tf o r A M P L I F I C A T I tOhN r o u g ht h e o p - a m p w , h i l et h e s u p p l yv o l t a g ei s u s e dt o p r o v i d e e l e c t r i c aeln e r g yf o r t h e o p - a m pt o b e c o m ef u n c t i o n a l . T h eo p - a m ph a st w o i n p u tt e r m i n a l m s a r k e da s ( + ) a n d( - ) T h e( + )t e r m i n ails c a l l e dt h e N O NI N V E R T I NTG E R M I N AaLn d R E T A I Nt hSe s i g no f t h e v o l t a g e a p p l i e dt o i t . i . e + . v er e m a i n sa s+ v ea f t e ra m p l i f i c a t i oann d s i m i l a r l -yv e r e m a i n sa s- v e a f t e r a m p l iifc a t i o n T h e( - )t e r m i n a il s c a l l e dt h e I N V E R T I NTGE R M I N AaLn d i t c o n v e r t s+ v et o - v e a f t e r a m p l i f i c a t i oann d- v e i s c o n v e r t e d t o + v ea f t e ra m p l i f i c a t i o n . T h et e r m i n a l s+ V ,a n d- V , a r et h e S U P P L Y v o l t atgeer m i n a l sa n dt h e s em u s tn o t b e c o n f u s e d w i t h t h e l NP U Tt e r m i n a l s . T h eS U P P L Y t e r m i n a rl set h e c o n n e c t i o nf so r w h i c ht h e o p - a m pr e c e i v eas p o t e n t i adl i f f e r e n c e t o t r i g g e ri t i n t oa c t i o nT . h es u p p l yv o l t a g e a s r et y p i c a l l 6 y V o r 9 V ,a n dt h e s ev o l t a g e a sre NEVEa Rm p l i f i e ad r e n yt i m e . 1,29 T h i ss u p p l yv o l t a g ec a nb e c o n s i d e r etdo b e s i m i l a tro t h e v o l t a g ew h i c hm u s tb e a p p l i e da c r o s s a m u s i ca m p l i f i e irn o r d e rt o g e t i t t o w o r k .E g .A m u s i c i a h n a st o p l u gi n a n a m p l i f i etro t h e L 2 0 Vm a i n si n o r d e rt o g e t h i se l e c t r i cg u i t a rt o o p e r a t eW . h i l et h e s o u n df r o m t h e g u i t a ri s convertedto an electrical signaland amplified,the t20V from the mainsis not amplified Bythe law of conservation of energy,the maximumoutputvoltageVocanneverexceedthe s u p p l yv o l t a g eV , .T h i ss i m p l ym e a n st h a t i f t h e m a x i m u mi n p u te n e r g y ( p ecro u l o m b i)s V , t h e n t h e m a x i m u mo u t p u ti s a l s oV , T h ec o n d i t i o nf o r w h i c ht h e O u t p u tV o l t a g e= V , i s c a l l e d 5-AIUBAIJSN. The OP-AMPis ialled a differentialamplifierbecause the output is directlyproportional to the D I F F E R E NiC nE v o l t a g eb e t w e e nt h e t w o i n p u t s . F r o mt h e a b o v ed i a g r a r nV, r i s a p p l i e dt o t h e N O N- I N V E R T I NTGE R M I N AaLn dV 2t o t h e I N V E R T I NTG ERMINAL. C o n s i d et rh e f o l l o w i n gs i t u a t i o n:s ( 1 ) V 1 > V ;zT h i sm e a n st h a t t h e r ei s a g r e a t e vr o l t a g ea t t h e n o n - i n v e r t i nt ge r m i n atl h a nt h a t a t t h e i n v e r t i n gt e r m i n a la n d s i n c et h e a m p l i f i c a t i o ins t h e s a m ef o r e a c h i n p u t ,w e w o u l d e x p e c ta N E TP O S I T I VoEu t p u tv o l t a g et;h a t i s V s i s p o s i t i v e0 1 s i m p l yw h e n t h e t w o i n d i v i d u aol u t p u t sa r ea d d e dt h e n e t r e s u l tw i l l b e p o s i t i v e . (2) Vz >Vr j Vowould be NEGATIVE as the output from V2 has greatermagnitudeand is n e g a t i v ea s c o m p a r e dt o t h e s m a l l e rp o s i t i v eo u t p u tf r o m V l . W h e nt h e t w o i n d i v i d u a l o u t p u t sa r e a d d e d t, h e n e t r e s u l tw i l l b e n e g a t i v e . ( 3 ) V r = Y z, T h e o u t p u tf r o m V 1w o u l d h a v et h e s a m em a g n i t u d e a s t h a t f o r V 2b u t t h e y w i l l h a v eo p p o s i t es i g n sT. h i sw o u l dr e s u l ti n t h e n e t o u t p u tb e i n gz e r oi . e .V 6= I 130 A M P L I F I EGRA I N : T h ep u r p o s eo f a n a m p . l i f i ei sr t o i n c r e a steh e m a g n i t u d o e f t h e i n p u ts i g n aal n d a s a r e s u l t h e o u t p u ts h o u l da l w a y sb e a n i n t e g r am l u l t i p l eo f t h e i n p u t . T h er a t i oo f t h e o u t p u tv o l t a g et o t h e i n p u tv o l t a g ei s c a l l e dt h e G A I No f t h e a n a p l i f i e r . G A I N: VOUt Vtn S i n c eG A I Ni s a r a t i oo f v o l t a g e si t, h a sn o u n i t s ,a n d i s u s u a l l yr e p r e s e n t ebdy t h e s y m b o "l A " H e n c ei f t h e v o l t a g e V s l a n d V 2 d r €a p p l i e dt o t h e i n p u tt e r m i n a l st ,h e n e t i n p u tv o l t a g ew i l l b e ( V r V z) a n d i f V o i s t h e o u t p u tv o l t a g et,h e n Vo: A(Vr-Vz) PRoIEBTIES-QE"T"H"r_"QP-""AMP"","" T h ep r o p e r t i eos f a t h e o r e t i c aild e a lo p - a m pa r ec o n s i d e r efdo r t h e p u r p o s eo f d e r i v i n g t h e relevantequationsfor it. Howevera REALOP-AMPhasproperties that areverycloseto but not i d e n t i c awl i t h t h o s eo f t h e i d e a lo p a m p . PROPERTtESOF THE B,E*A!=,_OJ:AMP: (1) A very high open loop gain of approximately 10sat low frequencies but it decreases as f r e q u e n c yo f t h e i n p u ts i g n a il n c r e a s e s( R e m e m b e r t h a t . t h e i n p u ts i g n adl o e sn o t h a v e t o b e a c o n s t a nvt o l t a g ei,t c a nb e s i n u s o i d aaln d h e n c ei t w i l l h a v ea f r e q u e n c y ) . T h et e r m " o p e nl o o p "m e a n st h a t t h e r ei s n o e l e c t r i c aclo n n e c t i ofnr o m t h e o u t p u tb a c k t o t h e i n p u t .C o n s i d et rh e f o l l o w i n gd i a g r a m s : In Diagraffi A, there is no connection from the output back D i a g rm a A t o t h e i n p u t ,o r t h e r ei s n o l o o p f r o m o u t p u tt o i n p u t ,a n dt h i s c i r c u i ti s c a l l e da n O P E NL O O P C I R CIUT . 1.31 I n d i a g r a mB t h e r ei s a l o o pf r o m t h e o u t p u tt o t h e i n p u ta n dt h i s D i a g r a mB c i r c u i ti s c a l l e da C L O S ELDO O P IRCUIT C I R C U IoTr a F E E D B A C K ( 2 ) A v e r y h i g h i n p u t r e s i s t a n c e ( i m p e d a n cr ie=)1 0 1 2 Oa,n d t h e r e f o r ed r a w s a m i n u t e e x t e r n a l l ay t c u r r e n tf r o m t h e s u p p l y . T h iisn p u t r e s i s t a n cies n o t o n e t h a t i s c o n n e c t e d t h e i n p u t sb , u t i n s t e a di t i s a r e s i s t a n ct eh a t i s m a n u f a c t u r ei dn t ot h e o p - a m p . r o =1 0 0 0 ; w h i c hm e a n st h a t i t s o u t p u tc a nb e (3) A very low output resistance(impedance) t r a n s f e r r e dw i t h o n l y l i t t l e l o s so f p o w e rt o l o a d sg r e a t e rt h a n a f e w k i l o h m s (. R e c a l l t h a t p o w e rl o s s= l 2 R ) Ri i n p u ti m p e d a n c e Ro output impedance 1.32 P R O P E R T IoEf tSh e I D E A LO PA M P ( 1 ) T h ei n p u ti m p e d a n cies l N F l N l T E , n c et h e i n p u tc u r r e n it s Z E R O . he ( 2 ) T h e i n p u t sa r e b o t h a t t h e s a m ep o t e n t i a lT. h i sc a n b e e x p l a i n e d a s f o l l o w s :F o ra v e r y h i g ho p e nl o o pg a i n ,t h e g a i n4 6 =o o R e c a lA o - b - Vi "o hence Vi _ vo-vo Ag co - o B u t V i= ( V z - V r ) = 0 H e n c eV z = V r ( 3 ) Z e r oo u t p u tl m p e d a n c e . l d e aO l PA m p R e aO l PA m p ( 1 ) I n f i n i t ei n p u ti m p e d a n c e F i n i t ei n p u t i m p e d a n c e1 0 1 2 0 ( 2 )Z e r oo u t p u ti m p e d a n c e L o wo u t p u t i m p e d a n c -e 1 0 0 0 ( 3 ) l n f i n i t eo p e n l o o p g a i n F i n i t eo p e nl o o pg a i n- 1 0 ' 133 CS. R CHARACTERISTI TRANSFE vs.INPUTVOLTAGE. is simplya graphof OUTPUTVOLTAGE CHARACTERISTIC TheTRANSFER Saturation Vrlt-tV R e c a lt lh a t t h e m a x i m u mo u t v o l t a g ei s e q u a lt o t h e s u P P l Y v o l t a g eV , a n dw h e nt h i sh a P p e n s , t h e o p a m p i s s a i dt o b e SATURATED Saturation in i n V o l t s t, h e i n p u tv o l t a g ei s m e a s u r e d Notethat whilethe cutPutvoltagei s m e a s u r e d .mlgrgyg.!!r, 134 l f t h e i n p u tv o l t a g ei s S I N U S O I D At hLe n t h e g r a p h so f I n p u tv s .t i m e a n d o u t p u tv s .t i m e d r a w n s e p a r a t e lwy i l l b e a sf o l l o w s : CLIPPING INPUT/microvolts Output/volts time T h eo u t p u ts i g t r ai ls n o t a n e x a c tr e p l i c ao f t h e i n p u tb e c a u s teh e o p a m p b e c o m e s a t u r a t e d . s o t h a t t h e m a x i m u mv a l u eo f V si s e q u a lt o V , w h i c hi s a c t u a l l yl e s st h a nA o V i a n tdh e p e a k so f t h e output graphare saidto be C[PP"E_,D_* In mostcases, the amplifier reaches saturation almostinstantaneously sothata sinewaveinputwould givea SQUARE WAVEOUTPUT l n p u t / mi c r o v o l t s Output/Volts 135 SPECIAL CASEWITHTWO INPUTS C o n s i d eT r h e c a s ew h e r e t h e r e i s a n i n p u t t o b o t h t h e i n v e r t i n a g n dn o n - i n v e r t i nt egr m i n a l s : t Vort I T h e i n p u t st o t h e i n v e r t i n ga n d n o n i n v e r t i ntge r m i n a l sa r ea ss h o w n : Output/V T h ei n i t i a pl o s i t i v ep a r to f t h e s q u a r ew a v eo u t p u ta r i s e sf r o m t h e f i r s tp a r to f t h e i n p u tv o l t a g e O sA w h e r et h e i n p u tt o t h e + v et e r m i n a il s g r e a t e trh a nt h a t o f t h e - v e t e r m i n a l , r e s u l t iinnga + v eo u t p u t . A f t e rt h a t ,t h e i n p u to n t h e - v e t e r m i n a bl e c o m e g s r e a t e trh a nt h a t o n t h e + v et e r m i n a l ( A B sCo) t h e o u t p u ti s- v e i . e .i n v e r t e dF. r o mC t o D t h e o u t p u tw i l l a l w a y sb e p o s i t i v eb e c a u s fei r s t l yt h e rragnitude o f t h e i n p u tv o l t a g eo n t h e + v et e r m i n ails g r e a t e trh a nt h a t o n t h e - v e t e r m i n a l . S e c o n d l yw,h e nt h e m a g n i t u d o e f t h e i n p u tv o l t a g eo n t h e - v e t e r m i n a il s g r e a t e trh a nt h a t o n t h e + v et e r m i n a lt,h e o u t p ; r ti st s t i l lp o s i t i v eb e c a u s n e o w t h e i n p u to n t h e i n v e r t i n tge r m i n ails - v e s o t h e o , ! i . :,,i w i l l b e i n v e r t e dt o a + v ev a l u e . 136 F E E D B A CAKN DT H EI N V E R T I NAGM P L I F I E R F e e d b a ci kn a n o p a m p i s a c h i e v e bd y m a k i n ga n e l e c t r i c ac lo n n e c t i ofnr o mt h e o u t p u t t oo n e o f t h e i n p u t s, u s u a l lvyi aa r e s i s t ocra l l e dt h e F E E D B A C RK E S I S T ORRr F o ra n I N V E R T I NaG m p l i f i e rt h , e o u t p u ti s c o n n e c t etdo ' t h ei n v e r t i n ign p u to f t h e a m p l i f i e r v i a R i3 ss h o w n : T h ef e e d b a ccku r r e n it s l i a n dt h e i n p u tc u r r e n its l ; n .T h eo p a m p h a sa h i g hi m p e d a n caen d t h u sd r a w sa m i n u t eo r n e g l i g i b lceu r r e n t . l f K i r c h o f f 'csu r r e n tl a w i s a p p l i e da t t h e j u n c t i o nP , t h e nl ; p+ 1 1 = 0 , o r l i n= - l r .T h i sa l s oi n d i c a t e s t h a t l 1 dp n d l i a r ei n A N T I P H A SwEh i c hi st r u ef o r t h e I N V E R T I NoG pamp. T h ef o l l o w i n g t w o I M P O R T A NATS S U M P T I OaNrS em a d e : ( 1 ) T h ef e e d b a ccku r r e n lt 1i s e q u a tl o t h e i n p u tc u r r e n lt i n d, u et o t h e i m p e d a n coef t h e o p a m p b e i n gs o h i g ht h a t i t d r a w sn e g l i g i b lceu r r e n t . ( 2 ) T h ep o t e n t i aal t t h e p o i n tP i s s o s m a l l t h a itt i s a p p r o x i m a t et od z e r o ,a n dt h e p o i n tp i s t h e r e f o r ec a l l e dt h e V I R T U AELA R T H . A point is saidto be at VIRTUAL EARTH when the potentialat that point is so small that it can Deapproximatedto earth potentiali.e.zeropotential. 1.37 e f t h e v e r yl a r g eG A I No f t h e o p a m p . T h ev i r t u a e l a r t hc o n d i t i o na r i s e sb e c a u s o e . g .l f g a i n A = 1 0 s , t f r e n f: 1 0 s a n di f V o = V , = g V t h e nV p : # = T h ef o l l o w i n gd e r i v a t i o fno r G a i ni s v e r yi m p o r t a n t : S i n c eV p =0 , V i n= l i n R iann dV o= l r R r B u t l i n- - l 1( a ss h o w np r e v i o u s l y ) Gain_*:(*,*l :(_ f^y^) G a i n o f I N V E R T I NoGp q m p - - X 138 O T H EN O N . I N V E R T I N AG MPLIFIER 1 I vi I t__T h e i n p u tv o l t a g eViii s; a p p l i e dt o t h e n o n -i n v e r t i n g t e r m i n a (l + ) .T h i sp r o d u c e as n o u t p u tV ot h a t i s i n p 1 hr a s ew i t h t h e i n p u t . Negativefeedbackis obtair n1 (ed( b y f e e d i n gb a c ka f r a c t i o no f t h e o u t p u tt o t h e I N V E R T I Ni nGp u t ( - ) . ThevoltageacrossRi_is equalto VnjO=Vn.The potentialat the non-inverting input is Vn.Fora largeopen loopgain.Vn=Vi.soin the derivations, we useVninsteadof Vi .because Vo_g_an be expressed in termsof a resistance. ie. Vo_lB;whereasV; hasno e.xpression in termsof a resistance O.u r a i m i s t o g e t a n e x p r e s s i ofno r t h e G A I Ni n t e r m so f t h e r e s i s t a n c et hsa t a r e a v a i l a b lien t h e c i r c u i t . Thevoltageacross(R6 Ri)= Vo S i n c eR r a n dR id r e i n s e r i e st h e s a m ec u r r e n ft l o w st h r o u g ht h e m t o t h e e a r t h ; V p = l R i a n d V o = l ( R t+ R i ) vo Rf+Ri vp R, Rr : 1 * J - G A I N f o r N O N I N V E R T I N GO P A M P rti G a i n o f I N V E R T I N Go p q m p - 139 - "t _^ SN D B A N D W I D T H G A I N . F R E Q U E NGCRYA P HA g r a p hi s p l o t t e d . i pe t w e e nG a i na n df r e q u e n c ya,l o g a r i t h m y r e l a t i o n s hb I n o r d e r t od i s p l a a T h i sl o gg r a p hi s u s e df o r t w o r e a s o n s : ( 1 ) l t a l l o w ss m a l l enr u m e r i c avla l u e st o b e u s e d ( 2 ) l t g i v e sa l i n e a vr a r i a t i o n b e t w e e nt h e p a r a m e t e rosn t h e x a n dy a x e s . 'Gain T h i s P o r t i o ni s t h e r e g i o no f n o f e e d b a c ka n d t h e g a i n h e r e i s c a l l e c t h e O P E NL O O PG A I N . 10s l-04 an d w i d t h 103 102 bandwidth .10 C 1, i.0 1,oz l-03 !04 10s 106 1,06 1,01 108 Frequency/Hz T h eh o r i z o n t al iln e sC Da n d E Fr e p r e s e n t t hgea i nw h e nf e e d b a ciks p r e s e n ti ,. e .c l o s e dl o o p s e g a i nw h e nn o f e e d b a ciks p r e s e n ti ,. e .o p e nl o o pg a i n . g a i nT . h es l a n t e dl i n eA B r e p r e s e n t h A t C D ,t h e r ei s m o r ef e e d b a ctkh a na t E F . T h ed i a g r a ms h o w st h a t t h e c l o s e dl o o pg a i ni s a l w a y sl e s st h a nt h e o p e nl o o pg a i nb u t i t i s m o r ed e s i r a b lbee c a u s e : ( 1 ) T h eg a i ni s p r e d i c t a b l e . ( 2 ) S t a b i l i t yi s g r e a t e rw h i c h m e a n st h a t t h e g a i n i s c o n s t a n to v e r a w i d e r r a n g eo f frequencies. n f g a i nw i t h f r e q u e n c y i ' , r U n l i k et h e o p e nl c o pg a i nt h e r ei s n o v a r i a t i o o I4A E.ANDIUDI.II; Thedifferencebetweenthe upperand rowerfrequencies for whichthe gainislonstant,is calledthe BANDWIDTH of the amplifierfor a particulargain. Forexample,on rookingat the previousgraph,for a gainof r.o, the Bandwidthis (108-1)Hz, and for a gainof 10OO the bandwidthis (101t)Uz. ln orderto havegreaterbandwidth,the negativefeedbackmust greater, be but this causesthe gainto drop.To compensate for this rowergaintwo or moreop ampscanbe coupredor typicallyreferredto as CASCADED C A S C A D EADM P L I F I E R S A1 A2 W h e nt h e t w o o p a m p sa r ec a s c a d eads s h o w na b o v e t, h e r e s u l t a ngt a i n = A 41xA2 S i m i l a r lfyo r 3 o p a m p st h a t a r ec a s c a d e dt h, e r e s u l t a ngt a i nA = A r 1,4L x 4 2x 4 3 OFTHEOPAMP APPLICATIONS (1) As a comparator-lt comparesthe two inputsand its outputdependson the differenceof thetwo inputs. t r a s a c o n v e r t eor f s i n e T h ec o m p a r a t ocr a nt h e n b e u s e da s a s w i t c hi n a n a l a r mc i r c u i o w a v es i g n a l tso s q u a r ew a v es i g n a l s . a m p l i f i e rT. h i si s u s e di n ( 2 ) A s a S U M M I N GA M P L I F I EwRh e n i t i s u s e da sa n i n v e r t i n g m i x i n gb o a r d si n m u s i ca n da l s oa sa d i g i t atl o a n a l o g u ce o n v e r t e r . the voltagefolloweris usedas a bufferor matchingamplifier FOLLOWER(3) As a VOLTAGE a n dw i l l b e e x p l a i n e sdh o r t l Y . THECOMPARATOR r form a T h et h e r m i s t o a r n d t h e f i x e dr e s i s t o R p o t e n t i adl i v i d e rw h i c hf i x e st h e v o l t a g ea t t h e ( a ) A s a s w i t c hi n a n a l a r mc i r c u i t : n o n - i n v e r t i ni n gp u t . A s t h e t e m p e r a t u r e ' r i s et sh,e v o l t a g ea t t h e n o n i n v e r t i n gi n p u ti n c r e a s e sa,st h e r e s i s t a n coef t h d t h e r m i s t o rr i s e s ( a s s u m ian gp o s i t i v ec o e f f i c i e n t t y p et h e r m i s t o r ) . T h ev o l t a g ea t t h e i n v e r t i n gi n p u ti s s e t b y t h e potentiometer. T h e p o t e n t i o m e t eirs s e tt h a t t h e v o i t a g ea t t h e i n p u ti s t h e s a m ea st h a t a t t h e n o n inverting i n v e r t i n gi n p u t .T h ed i f f e r e n c eb e t w e e nt h e t w o v o l t a g e sw i l l t h e n b e z e r o ,a n dt h e l a m po r buzzew r ill beoff. A s s o o na st h e t e m p e r a t u r ei n c r e a s e st h, e a t t h e i n p u tw i l l b e g r e a t e r v o l t a g ed i f f e r e n c e r illbe , n dt h e l a m po r b u z z ew t h a n z e r oa a c t i v a t e dC. o m p a r a t o rasr e v e r ys e n s i t i v e s w i t c h e sa n d t h e t e m p e r a t u r en e e d st o c h a n g e b y o n l ya s m a l la m o u n tt o t r i g g e ro n t h e a l a r m . r42 T H ES U M M I N GA M P L I F I EORRA D D E R W h e nt h e o p a m p i s u s e da s a m u l t i - i n p uitn v e r t i n ga m p l i f i e ri,t c a nb e u s e dt o a d d a n u m b e ro f v o l t a g e sb, o t h a . c .a n d d . c . C i r c u i t s u c ha st h e s ea r e u s e di n t h e m u s i ci n d u s t r y t oc o m b i n eo u t p u t sf r o m m i c r o p h o n e s , electricguitars,keyboards, voiceetc. A f o u r i n p u ts . u m m i nagm p l i f i e irs s h o w nb e l o w : RF v1 ll 1I vo t j v4 + W h e nK i r c h o f f ' sc u r r e n tl a w i s a p p l i e dt o t h e j u n c t i o na t P ,t h e t o t a lc u r r e n te n t e r i n gP i s e q u a l t o t h e t o t a lc u r r e n tl e a v i n g . Hence: It*lz*ls*l+=l I43 - + ( t h e riesa m i n u ss i g ns i n c et h e T h ec u r r e n t h r o u g ht h e f e e d b a c kr e s i s t oirs g i v e nb y I a m p l i f i eirs i n v e r tni g ) 1r:;: V. t(1 V, ;lz -i; -vo Rf Is: V, Io: &, V4 Rn - + V"" + \ _ V',^ + V? R1 R2 R3 Ra T h eG E N E R AELQ U A T I O fNo r t h e s u m m i n ga m p l i f i eirs t h e r e f o r e : vo: (3,, Rr * JV" RzL .frvs*P-r-) a A M P L I F I Ei sRt h e c o n v e r s i oonf d i g i t asl i g n a ltso O n ei m p o r t a nat P P l i c a t i oonf t h e S U M M I N G a n a l o g usei g n a l sT.h i st Y P eo f c o n v e r t eirs u s u a l l ya b b r e v i a t eadsa D / A c o n v e r t e r . t o e l e c t r i c apl u l s e st h a t h a v eo n l y t w o s t a t e si . e .1 ( h i g h )a n d l n d i g i t a ,t ' r n . l s , d a t ai s c o n v e r t e d O( l o w ) . l yv e ra r a n g eo f v a l u e s t o a v o l t a g et h a t v a r i e sc o n t i n u o u s o I n a n a l o g u se i g n a l sd,a t ai s c h a n g e d i . e .a w a v e f o r mo f t h e v o l t a g er e p r e s e n ttsh e d a t a ' ANALOGUE 144 Analoguesignalsare subjectedto noiseand distortion,whiledigitalsignalsare extremelyclean and undistorted. However,there are manyapplications whichcanonly operateon an analogue basise.g.thosewhichinvolvethe humansensessuchas hearingand seeing. The humanear candetectcontinuousvariationsin the intensityand pitchof sound;if it were to operateon a digitalbasisthen would eitherdetector not detectsoundbut it wouldnot be able to distinguish changesin intensityand pitch. The sametype of reasoning is usedfor the humaneyetd detectchangesin lightintensityand changesin colour. H e n c ef o r r a d i oa n dt e l e v i s i obnr o a d c a sitt,w o u l db e l o g i c a l t oc o n v e rat n a n a l o g usei g n aflr o m t h e r a d i oa n n o u n c et ro a d i g i t asl i g n a l t h at th e n l e a v e tsh e t r a n s m i t t e ar ,n dt h e n b a c kt o a n a l o g uaet t h e r a d i or e c e i v e T r .h er e a s o nf o r u s i n gt h e d i g i t asl i g n a l f otrr a n s m i s s i oi snt h a t i t i s f r e ef r o m n o i s ea n d d i s t o r t i o na n dw o u l dt h e r e f o r eg i v ea b e t t e rq u a l i t yo f s o u n da t t h e receiver. l n p r a c t i c eD, / A c o n v e r t e ri sn c o r p o r a taeS U M M I N G A M P L I F I E. R T h ei n p L lst i g n a las r et y p i c a l l5y V f o r a b i n a r yi n p u to f l a n d0 V f o r a b i n a r yi n p u to f 0 . 1.45 T h ef o l l o w i n ge x a m p l es h o w st h e c o n v e r s i oonf d i g i t atl o a n a l o g u e : A m a x i m u mp . d .o f 5 V i s a p p l i e dt o e a c hi n p u t . 1ko 2kC) VD VC 1 VB 16kO vo t I VA J F r o m t h e g e n e r a lf o r m u l a f o r t h e o u t p u t o f t h e s u m m i n ga m p l i f i e r , Vo: - Rr Rr f"Vr- nU, Rr -iV3- Rr rur* T h eo u t p u tv o l t a g ed u e t o t h e 2 k Or e s i s t oar l o n e- V p -lkfi Vo: Zkn x5:-2.5V - 1ko Vc:4kA x5:-1.25V -Iko x5: -0.625V B/.O -1k0" Ve:16k'x5:-0'31'3V Vs: r46 T h e m i n i m u mv o l t a g eo u t p u tt h a t i s n o n z e r o i s c a l l e dt h e L E A SsTl G N l F l c A NBTl r ( L S Ba) n d in t h e a b o v ee x a m p l et,h e L S Bi s e q u a lt o 0 . 3 1 3 V . T h ec a l c u l a t i o nssh o wt h a t w h i l et h e i n p u ti s o n l y0 o r 5 V ,t h e o u t p u tr a n g e sf r o m 0 t h r o u g h a s e r i e so f v o l t a g e u s p t o a m a x i m u mo f - ( 2 . 5 +j . . 2 5 + 0 . 6 2 5 + 0 . 3=1 -34). 6 g g v . A s e r i e so f i n t e r m e d i a toeu t p u t sc a nb e o b t a i n e df r o m t h e f o l l o w i n gb i n a r yd i g i t s : 0001i.e only outputfrom Va 0011- Va+Ve- -(0.625+0.3j.3)= -0.938V 0 1 0 1 = V c * V R = - ( j , . 2 5+ 0 . 3 1 3 )= _ 1 . 5 6 3 V 1 0 1 1- V p+ V s + V=a- ( 0 . 3 L 3+ 0 . 6 2 5 + 2 . 5=)- 3 . 4 3 g V = -0,.25+ 0.625+ 0.313)= _2.1ggv 0111=Vc*Ve*VR =Vo*Vc+Vs+V4 =- (0.313+ 0.625+ 1.25+ 2.5)=-4.6ggV 1J1,1. 0 1 0 0 = V c =- 1 , . 2 5 V Theabovecalculations showthat therecan be a seriesof differentbinarydigitsto givea wide rangeof outputvoltagesand in this way,the inputdigitalstatesof "on and off" can be converted t o a n A N A L O G USEI G N A L . r47 FOLLOWER THEVOLTAGE T h i si s a s i m p l e vr e r s i o no f t h e n o n - i n v e r t i nagm p l i f i e r . Rt=0 OV t o e a r t h ,w h i l ea v o l t a g ei s a p p l i e dt o t h e n o n - i n v e r t i ntge r m i n a l , t e r m i n a li s c o n n e c t e d T h ei n v e r t i r l g h e n c et h e a m p l i f i eirs N O NI N V E R T I N G . R e c a lt lh a t f o r t h e n o n - i n v e r t i nagm p l i f i e rt ,h e G A I Ni s g i v e nb y : Rr A_L+J 'R, t o l e a v ea n o p e nc i r c u i t . R,1i s m a d ez e r o ,a n dt h e R ii s r e m O v e d I n t h e v o L T A G EF O L L O W E R t m a k i n gR ii n f i n i t e . T h i si s e q u i v a l e nt o T h ec i r c u i tf o r t h e v o l t a g ef o l l o w e rw i l l t h e r e f o r eb e a ss h o w nb e l o w : 148 S i n c et h e g a i nA : ' 1 + y , t h e n i n t h i s R1' n case,A=1*"-1. oa) T h eg a i no f t h e v o i t a g ef o l l o w e r = 1 . T h ev o l t a g ef o l l o w e ri s n o t u s e da s a v o l t a g ea m p l i f i e rb, u t i n s t e a di t i s u s e da s a V O L T A G E BUFFER. T h ev o l t a g eb u f f e ra c t st o i s o l a t ea n i n p u ts i g n a l f r o ma l o a d ,w h i l ea l l o w i n gt h e v o l t a g eo u t p u t t o b e i d e n t i c at lo t h e i n p u ti n m a g n i t u d e a n d i n p o l a r i t yi.. e .V o= V i n T h ev o l t a g ef o l l o w e rh a sa h i g hi n p u ti m p e d a n cseo t h a t i t d r a w so n l ya m i n u t ec u r r e n ta, n da t t h e s a m et i m e ,i t h a sa l o w o u t p u ti m p e d a n cteh u sp r o d u c i n a g s u f f i c i e n t l ya r g ec u r r e n ta t t h e o u t p u t .( R e c atl hl a t 1 _ f r o t h a t w h e n R i s s m a l l I, w o u l db e s u f f i c i e n t l ya r g e . ) C o n s i d et rh e f o l l o w i n gc i r c u i t : A v o l t m e t e ri s c o n n e c t e d t o m e a s u r ea p . d .o f 1 V a c r o s sa 1 M O r e s i s t o rA. t y p i c a vl o l t m e t e rh a sa r e s i s t a n coef 1 0 0 k Oa n d i n t h i s c i r c u i tt,h e v o l t m e t e r w i l l d r a wm o s to f t h e c u r r e n a t n dg i v ea n i n a c c u r a t e . reading. T h ev o l t a g ef o l l o w e rc a n b e u s e da ss h o w nb e l o w . tv 1 M O\ 1MO l"Mo T h eo p a m p i n p u td r a w sf a r l e s sc u r r e n t h a n t h e v o l t m e t e r b , utthe OUTPUT p r o v i d e se n o u g hc u r r e n t f o r t h e v o l t m e t e rt o o p e r a t e . T h ei n p u tc u r r e n ti s a b o u t1 p A ( 1 01 2 A ;w, h i l et h e o u t p u ti s a f e w m i l l i a m p(st 0 3 n ) . T h i sc i r c u i ti s a l s ou s e f u fl o r d e t e r m i n i n g t h e c u r r e n t st h r o u g hv e r y h i g hr e s i s t a n c eis. e , .v e r ys m a l l c u r r e r r tw s h e n a v e i ' \ s. e n s i t i v a e m m e t e ri s n o t a v a i l a b l e . I n t h i sc a s et h e p . d .i s m e a s u r e a d s b e f o r ea, n dt h e c u r r e n ti s c a l c u l a t efdr o m r - v 1,49 R ON OP.AMPS TUTORIAL (1) t h e l a m pi s r a t e da t r nt h e a b o v ec i r c u i tt,h e o p - a m ph a sa n o p e n r o o pg a i no f 1 o 2 a n d s 0 m A ,t h e l a m pw i l l b u r n o u t . 2 V ,4 0 m A .l f t h e c u r r e n te x c e e d 4 op-amp is D e t e r m i n et h e v a l u e o f t h e p r o t e c t i v er e s i s t o rR , w h e n t h e saturated C a l c u l a tteh e p o t e n t i aal t t h e n o n - i n v e r t i nign p u t ii. e f t h e r h e o s t a t h a t w i l l a l l o w t h e p o t e n t i a la t t h e t h e r e s i s t a n co Calculate iii. i n v e r t i n gi n p u tt o a t t a i na v a l u eo f 2 ' 3 8 V ' j u s t c a u s e st h e w h a t m u s t b e t h e p o t e n t i a/ sl a t t h e i n v e r t i n gt e r m i n a lt h a t iv. o p - a m Pt o r e a c hs a t u r a t i o n' of the rheostatbe adjristed To what valuesof resistancemust the resistance v. same initial s o t h a t t h e o p - a m p j u s t r e a c h e ss a t u r a t i o n ? ( A s s u mt hee conditiona s t t h e n o n - i n v e r t i ntge r m i n a l ) Or 3 3 7 k Q ) ( R= 2 5 0 (;)2 . 4 V ; 3 2 9 k O2; . 2 8 Vo r 2 . 5 2 Y ; 3 2 3 k o i. 150 (2) l n t h e a b o v ec i r c u i tt,h 6 o p - a m ph a sa n o p e n l o o pg a i no f 1 0 a a n dt h e l a m pi s r a t e d a t 1 , . 2 V , 8 0 m A .l f t h e c u r r e n te x c e e d 8 s 0 m A ,t h e l a m pw i l l b u r no u t . i. ii. iii. ' iv. v. D e t e r m i n et h e v a l u eo f t h e p r o t e c t i v er e s i s t o R r ,w h e n t h e o p - a m pi s s a t u r a t e d C a l c u l a tteh e p o t e n t i aal t t h e n o n - i n v e r t i nign p u t Calculate the resistanco e f t h e r h e o s t a t h a t w i l l a l l o w t h e p o t e n t i a la t t h e i n v e r t i n g . i n p u tt o a t t a i na v a l u eo f 0 . 8 V . What must be the potentiad l i f f e r e n c ea c r o s st h e i n p u t t e r m i n a l st h a t j u s t c a u s e st h e o p - a m pt o r e a c hs a t u r a t i o n . T h e r e s i s t a n coef t h e r h e o s t a it s s e t i n i t i a l l ya t 2 0 0 k Qa n d t h e n a t 1 8 O O k OD.e t e r m i n ea t w h i c hs e t t i n go f t h e r h e o s t a w t i l l t h e l a m po p e r a t ea n d e x p l a i nh o w y o u a r r i v e da t y o u r conclusion. ( 2 2 . 5 0; I . 2 Y; 1 0 3 6 k O; 3 0 0 U V; 2 0 0 k 4 ) 151 (3) ( i ) F i n dt h e p o t e n t i aal t t h e n o n i n v e r t i nign p u t . ( i i )D e t e r m i n teh e v a l u eo f t h e r e s i s t a n coef t h e r h e o s t aitf t h e o u t p u to f t h e o p a m pi sz e r o . ( i i i ) T h el a m pi s r a t e da t 3 V ,1 . . 2 Ad,e t e r m i n e t h er e s i s t a n coef t h e p r o t e c t i v e r e si s t or . ( 1 , 8 V5; 4 M O ;5 O ) 1.s2 (4) I n t h e a b o v em u l t i s t a gaem p l i f i e rt ,h e i n p u tv o l t a g ei s 1 5 m V .D e t e r m i n teh e g a i no f t h e c i r c u i t a n dt h e o u t p u tv o l t a g e . A n s: 2 0 0 ; 3 V a (s) 500ko T h e i n p u tv o l t a g ei s V r =2 0 p t VD . e t e r m i n et h e o v e r a lgl a i na n dt h e o u t p u tv o l t a g e . ( 1 . 5 6x 1 0 " ; 0 . 3 1 2 V ) 153 (6) 76kO 200ko 600ko ( i ) l ft h e g a i n sf o r t h e c a s c a d e ad m p l i f i e r a s r e A z =4- 0 a n d 4 3 - - 8 0 , a n dt h e o v e r a l gl a i no f t h e s y s t e mi s s r , R za n d R 3. t h e v a l u e so f t h e r e s i s t o rR 6 . 4 x 1 0 4 d, e t e r m i n e ( i i )l f V r = 3 5 F V ,d e t e r m i n et h e o u t p u tv o l t a g e . A n s : 4 k O ; 5 k O; 7 . 5 k O; 2 . 2 4 V (7) 40ko 1s0ko 500ko s r e A r = -8 0 , a n dA r = -2 0 , a n dt h e o v e r a l gl a i no f t h e l f t h e g a i n sf o r t h e c a s c a d e ad m p l i f i e r a s r ,R za n d R 3 . a m p l i f i e ri s 3 0 0 0 ,d e t e r m i n et h e v a l u e so f t h e r e s i s t o r R (s00o; 80kct 2sko) 1.54 (8) 2MO lf V1=2mV,Vz= 10mV,and V3=6mV, d e t e r m i n et h e o u t p u tv o l t a g e . -141mV 1 (e) 220kO V z =1 2 m V D e t e r m i n et h e o u t p u tv o l t a g ef o r t h e a b o v ec i r c u i t . ( 0 . 2- 2 s v ) 155 500ko Solutionsfor tutorial (1) i . W h e nt h e o p a m p i s s a t u r a t e dt h, e o u t p u tv o l t a g ew o u l db e e q u a tl o t h e s u p p l y v o l t a g ew h i c hi s 1 2 V .I f t h e l a m pi s r a t e da t 2 V t h e nt h e p . d .a c r o s tsh e l a m pi s 2 V ,s o t h a t t h e p . d .a c r o s tsh e r e s i s t owr o u l db e 1 0 V( l . e '1 2 V- 2 V = 1 0 V ) ' T h er e s i s t oar n dt h e l a m pa r e i n s e r i e s o t h a t i f 4 0 m Ah a st o f l o w t h r o u g ht h e l a m p , t h e n 4 0 m Aw i l l h a v et o f l o w t h r o u g ht h e r e s i s t o rS. of o r t h e r e s i s t o rV, = 1 0 Va n d | = v10 :250Q 0 . 0 4 4. R 1 0.04 i i .T h e b r a n c ho f r e s i s t o rcso n n e c t etdo t h e n o n i n v e r t i n ign p u t h a sa B 0 k Or e s i s t o r , h et o t a l r e s i s t a n cies 2 0 0 k Oi n t h a t b r a n c ha, n dt h e p o t e n t i a l s e r i e sw i t h a 1 2 0 k OT differenceacrossthat branchis 12v-(-r2v)=12V+ r2Y = 2 4 V . T h ec u r r e n t t h e b r a n c h1 T h e o . d a c r o s st h e V R7 # :-' 24 zxros' x B 0x 1 0 3: 9 . 6 V o f p o t e n t i aal c r o s s l I F F E R E Na CcEr o s st h e 8 0 k O ,i . et h e d i f f e r e n c e T h i si s t h e p o t e n t i aD a c r o s sb o t h e n d s t h a t r e s i s t o rl.f t h e t o p e n d i s a t a p o t e n t i aol f L 2 Va n d t h e d i f f e r e n c e o f t h e r e s i s t oirs 9 . 6 V t, h e nt h e p o t e n t i aal t t h e l o w e re n d i s 1 2 V9- . 6 V = 2 . 4 Y 156 S o l u t i o nf o r q u e s t i o n1 c o n t i n u e d ; i i i .A t t h e i n v e r t i n gi n p u t ,t h e b r a n c ho f r e s i s t o rcso n t ai n a 2 2 O k Q r e s i s t o irn s e r i e sw i t h a r h e o s t a tl.f t h e p o t e n t i aal t t h e i n v e r t i n gi n p u ti s 2 . 3 8 V t, h e n t h e p o t e n t i adl i f f e r e n c e a c r o s st h e 2 2 O k Or e s i s t o irs ( 1 2 V -2 . 3 8 V ) =9 . 6 2 V T h e c u r r e n t h r o u g ht h e 2 2 0 k Or e s i s t o irs 1 , - # - # T h ep . d .a c r o s st h e r h e o s t a=t 2 . 3 8 V - ( - 1 2 V 1 4) . 3 8 V T h ec u r r e n t h r o u g ht h e r h e o s t aw t i l l a l s ob e t h e s a m ea st h a t c a l c u l a t eadb o v es i n c et h e t w o 14'38 resistorsare in series.I,' = ? - - s s3-, Rz=329ko. R2 R2 220x103 i v .T h ep o t e n t i aal t t h e n o n - i n v e r t i nt e g r m i n a il s f i x e da t 2 . 4 V T . h eo p a m p r e a c h e s a t u r a t i o n w h e nt h e o u t p u tv o l t a g ei s l - 2 V . vin=Ynf- # - a.rzv ; hence R e c a l lt h a t t h e g a i n o f a n o p a m p i s g i v e n b V A - l s t t vLn T h ed i f f e r e n c be e t w e e nt h e p o t e n t i a last t h e i n v e r t i n a g n d n o n -i n v e r t i p tge r m i n a l m s u s tb e 0 . 1 . 2 Vs,o t h a t i f V , = 2 . 4 i t h e nV , c a nb e e i t he r 2 . 2 8 Vo r 2 . 5 2 V . v ' T h i sp a r tr e q u i r e tsh a t y o u f i n dt h e v a l u e so f t h e r e s i s t a n ct e h a t w o u l dg i v ep o t e n t i a losf 2 . 2 g V a n d2 . 5 2 Va t t h e i n v e r t i n tge r m i n a l . C o n s i d efri r s ta p o t e n t i aol f 2 . 2 8 V T l I F F E R E NaCcEr o s st h e 2 2 O k Ar e s i s t o irs . h e p o t e n t i aD 1 ' 2 V- 2 . 2 8 V =9 . 7 2 V . T h ec u r r e n t h r o u g ht h e 2 2 0 k Oa n d h e n c et h r o u g ht h e b r a n c hi s g i v e nb y T h e p . d . a c r o s st h e r h e o s t a t v. 9.72 Rr 220xI03 2.28v-(-1Zv)=1.4.28v T h i sc u r r e n t i s t h e s a m e t h r o u g h t h e r h e o s t a t L e . 3 R2 1 4 - 2-8 - s ' 7 2 n R z = 323kA R2 ,To" ro= ; U s e t h e s a m e m e t h o d t o g e t t h e r e s i s t a n c ew h e n t h e p o t e n t i a li s 2 . 5 2 V . Q u e s t i o n2 a n d 3 c a n b e s o l v e ds i m i l a r l yt o q u e s t i o n1 I I I I 157 Solutionfor question4 I n t h e c i r c u i t t h ea m p l i f i e rasr e c a s c a d eadn dt h e o v e r a lgl a i ni s g i v e nb y : A : ArAzAz i n c et h e r ei s a s i g n atlo t h e n o n T h ef i r s ta m p l i f i e rt(o t h e e x t r e m el e f t )i s N O NI N V E R T I NsG l h i l et h e i n v e r t i n tge r m i n a il s c o n n e c t etdo t h e g r o u n d . i n v e r t i n tge r m i n aw Thegain f or thenon- tnuerttng amp is gtvenby At - t * Rr & 30c) Ar:1+200:2.5 s r e i n v e r t i n gs i n c et h e y h a v en o s i g n aal t t h e n o n i n v e r t i n g T h e s e c o n da n dt h i r d a m p l i f i e r a t e r m i n aw l h i l et h e r ei s a s i g n aal p p l i e dt o t h e i n v e r t i n tge r m i n a l . _Rr TheGainf or aninverttngop - emp ts gtvenby A - t -800 -20 ' Az=i--4 andA=- J 40 - -20 T h e o u e r a l l G o . t nA : 2 . 5 x ( - 4 ) x ( - 2 0 ) = 2 0 0 . The OutputVoltageVs- Gatn x Vn - 200 x 0'0tSV : 3V Solutionfor question5 T h ef i r s to p - a m pi s n o n i n v e r t i n gw h i l et h e o t h e rt w o a r e i n v e r t i n g . T h eg a i no f t h e f i r s to p - a m pi sA t : 1 * L* ff: # -'U - -40 T h eg a i no f t h e s e c o n do p - a m pi s A z : - + - T h eg a i no f t h e t h i r do p - a m pi s , 4 3- + - : 6 0 0- - 1 5 # - 1 ' ' 5 6x 1 0 4 T h e o v e r agl la i n i s g i v e bn y A - A 1 A , A 3 - ( 2 6 ) x ( - 4 0 ) x ( - 1 5 ) The output voltageVo= AV,n=1'56 x 10ax20 x 10-6=0'312V 158 Solutionfor question5 Overall Gatn A = A1A2A3 ; henceA, : - A 6.4 x l_04 AzAs 40 x B0 T h ef i r s ta m p l i f i e ri s n o n i n v e r t i n gs i n c et h e i n v e r t i n gt e r m i n a li s c o n n e c t e d t o 0 V w h i l et h e n o n i n v e r t i n gt e r m i n a li s c o n n e c t e d to analternating supply. Thegainisgib ve n , , : 2 0- 1 * vA ; h e n c e R r :r y - N-t*T T h es e c o n da m p l i f i e ri s i n v e r t i n ga n d i t s g a i ni s g i v e nb v A z - - 4 0 : 4ke a# : -200kQ henceR2: Skf) T h et h i r d a m p l i f i e ri s i n v e r t i n ga n dA z = - - ! f -J -600ko : -80: vvt R1 R3 R E: 7 . S k e ( i i )T h eo u t p u tv o l t a g eV o= A V t n : 6 . 4 x 1 0 a x 3 5 x 1 0 - 6 - 2 . 2 4 V Solutionfor question7 Allof the amplifiera s reinverting, rA1- 2 - 3000 - -1,.875 -80 x -20 A AA= _Rr 40k0" R, R1 -80 Az : -I'875 . A." R=i -20 -Rt i Rr : 5000 -15Okcr Ri _R, hence R2 ; Rz: BOkf) -500k0 R3 159 ; R s: 2 5 k A R2 D I G I T A LE L E C T R O N I C S L o g i cg a t e s : ( 1 ) T h e N O Tg a t e : T h i sg a t e h a s o n e i n p u t a n d o n e o u t p u t ; I N P U T OUTPUT 0 I 1 0 ( 2 ) T h eO Rg a t e : I N P U T OUTPUT A B c 0 0 0 0 1 I 1, 0 1 I I t T h i sg a t eh a st w o i n p u t sa n do n e o u t p u t ; A C. B T h eo u t p u ti s h i g h( 1 )w h e ne i t h e ro r b o t hi n p u t sa r eh i g h . (3) TheNOR gate: -; . ' T h i sg a t e c a n b e c o n s i d e r e dt o b e t h e N O T o f a n O R g a t e , i . e . N O R= N O T O R I N P U T OUTPUT A B C 1 0 0 0 I 0 1 0 0 1 I 0 A I B ( a ) T h eA N Dg a t e : T h eo u t p u ti s h i g ho n l yw h e n b o t h i n p u t sa r e h i g h . 160 I N P U T OUTPUT A B C 0 0 0 0 T 0 I 0 0 1 1 1 ( 5 ) T h e N A N Dg a t e : T h i si s e q u i v a l e nt to a n A N Dg a t ef o l l o w e dby a NOTgate. I N P U T OUTPUT A B c 0 0 1 0 I 1. t 0 t 1 I 0 A B ( 6 ) T h e E X C L U S I V E -gO aR t e( E X - o R ) T h i si s s o m e w h ast i m i l a r t oa n O Rg a t e ,b u t i t E X C L U D E t hSe c a s eo f t h e b o t h i n p u t sb e i n gh i g h . R e c a lt lh a t i n t h e c a s eo f t h e O Rg a t e ,t h e o u t p u ti s h i g hw h e n b o t h i n p u t sa r e h i g h ,h o w e v e r g a t e ,t h e o u t p u ti s l o w w h e n b o t h i n p u t sa r e h i g h ,b u t i n a l l o t h e rc a s e si,t withthe EX-OR b e h a v e s i m i l a tro t h e O Rg a t e . I N P U T OUTPUT A \\------.' \\ t -B--l___-/ /-c A B c 0 0 0 0 I I 1 0 1 I 1 0 A n o t h e re a s yw a y o f r e m e m b e r i n g t h e t r u t h t a b l ei s t h a t t h e o u t p u ti s h i g ho n l yw h e nt h e i n p u t sa r e N O T thesame. ( 7 1 T h e E X C L U S I VNEo-R g a t e( E X - N O R ) I N P U T OUTPUT --l) A -B \\----\ lL----/ >-. A B c 0 0 T 0 t 0 1 0 0 t 1. 1 I n ' i t i sg a t et h e o u t p u ti s h i g ho n l yw h e n b o t h i n p u t sa r ee q u a l ,h e n c ei t a c t so p p o s i t et o t h e E X O Rg a t e . t6r GATE DIAGRAM FUNCTION T h eo u t p u ti s o p p o s i t e of the input NOT OR T h eo u t p u ti s L o n l y w h e n e i t h e ro n e o f t h e i n p u t si s 1 O Rb o t h i nputsare l - T h eo u t p u ti s t h e opposi teof the ORgate. N O Rm e a n sN O TO R NOR The output i s 1-onl y w h e n b o t h i n p u t sa r e 1 AND NAND T h eo u t p u ti s t h e o p p o s i t eo f t h e A N D gate. N A N Dm e a n sN O T A N D EX-OR EX-NOR INPUTS T h eo u t p u ti s 1 o n l y w h e no n e o f t h e i n p u t s a r e1 b u t n o t w h e nb o t h i n p u t sa r e 1 T h eo u t p u ti s t h e opposi teof the E X -OR gate. r62 OUTPUT 1. 0 0 I 0 0 0 0 1. L 1. 0 1. L t 1. 0 0 T 0 0 I 0 0 I L 0 0 0 0 1 0 0 1 0 0 T 1. L 0 0 0 L T L T 0 L I T 0 0 0 0 0 L L 1. 0 T 1. 1. 0 0 0 1 0 T 0 t 0 0 L 1 1. t C o m b i n a t i o nosf l o g i cg a t e s A L Ll o g i cg a t e sc a nb e m a d ef r o m o n l yN A N Dg a t e so r o n l yN o Rg a t e s ( R E M E M I B E RT H t S ) . T h e m a i nb e n e f i ti s t h a t t h e s u b s t i t u t i odno e sn o t r e d u c et h e a m o u n t g a t e s of butinstead r e d u c e tsh e n u m b e ro f l cC' 'ssr e q u i r e d . ( lm c e a n sl n t e g r a t e cdi r c u i ta n d i s n o r m a l l yc a l l e da "chip") I n o r d e rf o r a n yg a t et o b e a b a s i cb u i l d i n gb l o c kf o r o t h e rg a t e s i,t m u s t h a v et h e I N V E R T I N G c a p a b i l i t yh,e n c eA N Dg a t e sa n d o R g a t e sc a n n o tb e u s e dt o b u i l do t h e r g a t e s . T h e r ea r es o m eb a s i cd e s i g n tsh a t y o u m u s tl e a r ni n o r d e rt o m a k eg a t e s f r o m N A N Do n l yo r N O Ro n l y . ( 1 ) F i r s t l ya, N o T g a t ec a nb e m a d ef r o m a s i n g l ei n p u tN A N D o r a s i n g l ei n p u tN o Rg a t e ; NAND Input Output 0,0 1 t,r 0 NOR Input Output 0,0 I r,t 0 In both cases,the output is the oppositeof the input,henceit is a NOTgate. ( 2 ) s e c o n d l ya, n A N Dg a t ec a nb e m a d eb y c o m b i n i n ga N A N Dt o 163 a N O Tg a t e : A B C c D 0 0 1. 1. 0 0 1 1 1. 0 1 0 1 T 0 1 I 0 0 T ( 3 ) T h eO Rg a t ei s f o r m e db y a d d i n ga N O Tg a t et o e a c hi n p u to f t h e N A N Dg a t e : A B c D E 0 0 1. 1, 0 0 1, I 0 1 T 0 0 t 1 T 1 0 0 ! ( a ) T h e N O Rg a t ec a nb e . m a d ef r o m i n v e r t i n g t h e O Rg a t e .T h i si s d o n eb y a d d i n ga N O T g a t ea t t h e o u t p u tf r o m t h e p r e v i o u O s Rg a t e . T h et r u t h t a b l ef o r t h e o u t p u to f t h i sc o m b i n a t i o ins t h e N O To f t h a t f o r t h e p r e v i o u tsa b l e . 164 B U I L D I NW GI T HN O RG A T E S I n o r d e rt o b u i l da n yg a t e sf r o m N O Rg a t e s i,t i s i m p o r t a ntto p e r f o r mt h e f o l l o w i n gs e q u e n c oe f actions: ( 1 ) D e s i g nt h e c i r c u i w t i t h N A N Dg a t e so n l y . ( 2 ) R e p l a c e a c hN A N Dg a t ew i t h a N O Rg a t e ( 3 ) A d d N O Tg a t e st o a l l t h e i n p u t sa n do u t p u t s . ( R e m e m bt h ea r t t h e N O Tg a t ei s m a d ef r o m a N O Rg. a t e ) . ( 4 ) R e m o v ea n y p a i r so f N O Tg a t e si n s e r i e sw i t h e a c ho t h e rs i n c et h e y c a n c eol u t e a c h other. E X A MP L E : ( 1 ) s h o wt h a t t h e f o l f o w i n gc i r c u i ti s e q u i v a l e nt to a N o Rg a t e : F i r s t l yr,e p l a c ea l l N A N Dg a t e sb y N O Rg a t e s : T i i e i t i n s e r t N O Tg a t e sa t A , B ,a n d C . 165 B yc a n c e l l i nogu t t h e p a i r so f N O Tg a t e st h a t a r e i n s e r i e sw i t h e a c ho t h e r ,t h e e n d r e s u l ti sj u s t t h e l o n eN O Rg a t eX . E x a m p l 2e : D e s i g na n A N Dg a t ef r o m u r i n gN O Rg a t e so n l y . Step1-;Designthe ANDfrom the NANDgatesi.e. A NANDgatefollowedby a NOTgate g i v e sa n A N Dg a t e .i . e N O To f N A N D =AND S t e p2 ; R e p l a cteh e N A N Dg a t e sw i t h N O Rg a t e s : 166 Step3; lnsertNOTgatesat A, B, and C. T h e N O Tg a t e s4 a n d 5 a r e i n s e r i e sa n d w i l l c a n c eol u t e a c ho t h e r ,a n dt h e r e s u l t i n gc i r c u i tw i l l b e : Tw o successi ve N OTgatesi n ser ies w i l l a l w a y sc a n c eol u t e a c ho t h e r = (posit ive) as (negati ve)(negati ve) T h ea b o v ec i r c u i tr e p r e s e n tasn A N Dg a t e O n l o o k i n ga t t h e i n p u t sA a n d B , i t i s s e e nt h a t t h e O U T P U Ti s i d e n t i c atlo t h a t o f a n A N Dg a t e A 0 0 1 I B 0 1 0 t NOT A 1, T 0 0 NOT B 1. 0 t 0 1.67 NOT A NOR NOT B 0 0 0 1 The Exclusive-OR Gate : Desired Gate NOR Construction TruthTable lnput A Input B OutputQ 000 011 101 110 The ExclusiveNORgate: Desired Gate NOR Construction t=DrTruthTable Input A Input B Output Q 0 01 0 1 0 1 0 0 1 1 I 168 B u i l d i n gW i t h N A N DG a t e s The ORgate: Desired Gate NAND Construction :-TFTruthTable Input A Input B Outpute 000 011 l0l 111 The NORgate : A NoR gateis simply an oR gatewith an invertedoutput: Desired Gate NAND Construction :IrTruthTable Input A Input B OutputQ 0 01 0 l0 I 00 I 10 169 TheExclusive ORgate A n X O Rg a t ei s c o n s t r u c t esdi m i l a r l tyo a n O Rg a t e ,e x c e p w t i t h a n a d d i t i o n aNl A N Dg a t e i n s e r t e ds u c ht h a t i f b o t h i n p u t sa r e h i g h ,t h e i n p u t st o t h e f i n a lN A N Dg a t ew i l l a l s ob e h i g h , a n dt h e o u t p u tw i l l b e l o w .T h i se f f e c t i v e lrye p r e s e n t sh e f o r m u l a :" N A N D ( A N A N D( A N A N D B ) )N A N D( B N A N D( A N A N DB ) ) " . Desired Gate NAND Construction lflTruthTable Input A Input B OutputQ 000 011 101 110 The X- NORgate : An XNOR gate is simply an XOR gate with an inverted output: Desired Gate NAND Construction lilrTruthTable Input A Input B OutputQ 001 010 100 111 170 NOTES 171 B IN A R YA D D E R S T h e r ea r et w o t y p e so f B I N A R A Y D D E RiS. e .t h e H A L FA D D E R a n dt h e F U L LA D D E R . T h e H A L FA D D E R i s u s e dw h e nt w o o n e b i t n u m b e r sa r ea d d e d T . h ew o r d " b i t " m e a n sb i n a r y digit. T h eo n e b i t n u m b e r sc a no n l yh a v et h e v a l u e so f 0 a n d L . T h e r ea r ef o u r d i s t i n cst i t u a t i o ntso c o n s i d ew r i t h t h e H A L FA D D E RT.h e ya r e : carry I n ( d ) ,t h e s u mo f L + L = 1 0 ,a n dt h e 0 i s c a l l e dt h e S U Ma n dt h e 1 i s c a l l e dt h e C A R R y . T h ev a l u eo f 1 0 o n t h e D E C I M A sL c a l ei s 2 . T h i si s e x p l a i n eadsf o l l o w s : t0 The0isequalto0x20=0 \ T h e1 i s e q u a tl o 1 x 2 r = 2 T h eH A L FA D D E R i s m a d ef r o m a n E X - O Rg a t ea n da n A N DG A T E : A sum A 0 0 B CARRY S U M 0 0 0 I 0 t I 0 0 1 1. 1. 1. 0 carry ( T h eE X - O R g a t eg i v e :l h e s u ma n dt h e A N Dg a t eg i v e st h e c a r r y ) 172 T h e H A L FA D D E Rc a na l s ob e b u i l tf r o m t w o N O R sa n d a n A N Dg a t e( L E A R N T H | S! ! ! ! ! ! ! ! ) SUM T h ec i r c u i tg i v e st h e f o l l o w i n gr e s u l t s : CARRY S U M A B c D E 0 0 1, 0 0 0 1' 0 0 1 I 0 0 0 1 I I 0 T 0 0+0=00 0+l-=01 1+0=01 1+1=10 173 T H EF U L LA D D E R The FULLADDERaddsthree bits at a time. C o n s i d et rh e f o l l o w i n gb i n a r ya d d i t i o n : I t + 1 . L ;t h i s i s r e w r i t t e ni n t h e f o l l o w i n gf o r m a tf o r s i m p l i f i c a t i o n : t1 0t L OL I 1.1.0 bitsfirst,i.e.the digitson the extremeright; Consider the leastsignificant , e n c et h e m i d d l ec o l u m ng i v e s 1 + 1 = l - 0 .T h e 1 i n t h i s r e s u l ti s c a r r i e dt o t h e n e x tc o l u m n h j 1 1 ( 3 b i t sh e r e ,s o t h a t t h r e eI N P U T aSr e n e e d e d ) A i s r e q u i r e df o r t h i s . F U L LA D D E R L + 1+1 part. T h e r e f o r e1 1 - + 1 1 , , =1 1 0 174 T h e F U L LA D D E R i s m a d ef r o m t w o H A L FA D D E RaSn d a n O Rg a t e .( H A ra n d H A 2a r e H A L F ADDERS) sum T h et r u t h t a b l ef o r t h e F U L LA D D E R i s g i v e nb e l o w : INPUTS OUTPUTS A B c 0 0 0 0 0 0 0 1 t 0 0 T 0 1 0 1 0 0 t 0 0 1 1 0 t T 0 T 0 1 1 0 0 1 0 T I I 1. 1, SUM CARRY {l*iriLis is ittr.'ilr-r LtL-nl i*spir"atiixi.ni*etv-i:ine p*r dcltt [']u-rs!lit'ation. T'homas .{. Edison. 1*irt;r-';"lE -ffi:;id:jr', jVr.: 175 CIRCUITS BISTABLE A BISTABLE circuithastwo stablestatesof L or 0 . . order A c i r c u i ti s c o n s i d e r etdo b e s t a b l ei f i t s o u t p u ts t a y sf i x e de v e na f t e r t h ei n p u tc h a n g e sI n f o r t h i sc i r c u i t o m a i n t a i ni t s o u t p u tw h i l et h e r ei s a c h a n g ei n i t s i n p u t , i t m u s ti n c o r p o r a t e in its design. sometype of LATCH i s s i m p l ya p a r to f t h e c i r c u i t h a t " l o c k s "o r " s e t s "t h e o u t p u t ,s o i t w i l l n o t c h a n g e T h eL A T C H w h e nt h e r ei s s o m ec h a n g ei n t h e i n p u ts i g n a l . c a nb e u n d e r s t o o idn t h e f o l l o w i n gc i r c u i t : o f o p e r a t i o no f t h e L A T C H T h ep r i n c i p l e A L AT C HC IR C U IT output input , n d h e n c et h e i n p u tt o B i s h i g h . W h e nt h e i n p u tA i s h i g ht h e o u t p u ta t C i s h i g h a g o e s l o w , t h e i n p u t a t B d o e sn o t c h a n g ea n d h e n c et h e o u t p u ta t C i s to W h e nt h e . i n p utto A s t i l lh i g h . t o u l db e t o a s s u m et h a t w h e nt h e i n p u ta t A w a sc u t A s i m p l ew a y o f u n d e r s t a n d i nt hgi sc i r c u i w o f f i . e .s e n tf r o m L t o 0 , t h e r ew a sa d e l a y e dr e a c t i o ni n t h e o u t p u t( e g .a m i c r o s e c o n d. )T h i s d e l a yi s s u f f i c i e nt to a l l o wt h e o u t p u ts i g n atlo f l o w t o B s o t h a t t h e i n p u tt o t h e O Rg a t ew o u l d b e l a n d0 , h e n c ei t s o u t p u tw o u l db e 1 , a n dt h i so u t p u tw i l l b e c o n t i n u o u s l y f ebda c k t oB s o t h e O Rg a t ew i l l h a v ea l w a y sa n o u t p u to f 1 T h ea b o v ec i r c u i th a so n e s t a b l es t a t e , b u t f o rp r a c t i c apl u r p o s e ss,o m ec i r c u i t sa r e d e s i g n e d ircuits. w i t h t w o s t a b l es t a t e sa n dt h e s ea r ec a l l e dB I S T A B Lc E A B I S T A B Lc E i r c u i tc a nb e m a d ef r o m t w o N O Ro r t w o N A N Dg a t e sa, n d s u c ha c i r c u i ti s c a l l e d a n S - RB I S T A B L E . The "S" refersto SETandthe "R" refersto RESET. 176 C o n s i d et rh e B I S T A B Lc E i r c u i t h a t i s m a d ef r o m N O Rg a t e s : a a Q' Q' OPERATION: C A S E1 : T h e o u t p u to f a N O Rg a t ei s L o n l y i f b o t h i n p u t sa r e 0 . H e n c ei f S o r R i s L , t h e o u t p u to f t h e p a r t i c u l a r g a t em u s t b e 0 . F o re x a m p l ei,f S = 1 a n d R = 0 , t h e o u t p u to f G A T E1 i s 0 i . e .Q = 6 . T h i so u t p u tQ i s f e d t o G A T E2 , s o t h a t n o w G A T E2 h a st w o i n p u t st h a t a r e0 , a n d i t so u t p u tw i l l b e 1 . i.e. Q' -1,. T h i s Q ' i s n o w f e d i n t o G A T E1 , s o t h a t G A T E1 n o w h a st w o i n p u t st h a t a r e 1 ( S = 1f r o m b e f o r e) , s ot h a t Q r e m a i n sa t 0 . I n s u m m a r v . w h esn= 1 a n d R = 0 . t h e c i r c u i t i s s t a b l e w i et h= 0 a n d e ' = 1 . CASE 2 'lf S is nowresetto0 sothatS = R =0, GATE l stillhasan inputof l from q, sothattheoutputat eis still0. ThisQ =0 isfed intoGATE2 sothat bothinputsto thisgate=0 andthe outputCf remainsat 1. CASE3 : R i s n o w r e s e t o l l e a v i n gs = 0 . T h e i n p u t st o G A T E2 a r e n o w l a n d0 ( e w a s 0 i n t h e p r e v i o u cs a s e ) , h e n c eQ ' = 0 a n d t h i s b e c o m e st h e s e c o n di n p u tt o G A T E1 . T h i sG A T E1 t h e r e h a st w o i n p u t so f 0 , s o t h a t i t so u t p u t Q = l w h i c hi s f e d b a c kt o G A T E2 t o e n s u r et h a t Q ' r e m a i n sa t O . CASE4: R r ss w i t c h e dt o 0 w i t h S = 0 , Q i s s t i l la t L s o g a t e2 h a si n p u t so f 0 a n d 1 s o t h e o u t p u tQ ' i s 0 . T h eo u t p u t sa r et h e r e f o : €U n c h a n g eads R i s s w i t c h e dt o 0 . 177 i s 'SET"by settingS = 1 and R=0. The BISTABLE i s 'RESET"by settingS =0 and R=1. The BISTABLE circuit TheTruth table for the BISTABLE (uslNGNoRGATEs) S R t T h et r u t h t a b l es h o w st h a t w h e n S i s "set" at 1-, with R beingkePtat 0, the o u t p u t sQ a n d Q ' a r e s t a b l e ( u n c h a n g e d ) I w h e n S i s c h a n g e dt o 1 . a a' 1 0 0 0 0 0 0 L I 0 0 1 0 H o w e v e tr h e o u t p u t sc h a n g ew h e n R i s " R e s e t "t o 1 , a n dt h e s eo u t P u t sr e m a i n 0 s t a b l e( u n c h a n g e dw)h e n R i s c h a n g e d to 0. T h e o u t p u t sc a n b e c h a n g e da g a i nb Y r e s e t t i n gt o t h e o r i g i n asl t a t ew i t h S =1 a n d R =0 . t78 BistablecircuitusingNANDgates S R a 0 0 Q' T h et r u t h t a b l es h o w st h a t w h e n S i s "set" at 1-, with R beingkept at 0, the 1 0 0 0 1 0 I 1, 0 0 0 1 0 L o u t p u t sQ a n d Q ' a r e s t a b l e ( u n c h a n g e d ) w h e n S i s c h a n g e dt o 1 . H o w e v e trh e o u t p u t sc h a n g ew h e n R i s " R e s e t "t o 1 - a , n dt h e s eo u t p u t sr e m a i n s t a b l e( u n c h a n g e dw)h e n R i s c h a n g e d to 0. T h eo u t p u t sc a n b e c h a n g e da g a i nb y resettingto the originalstatewith S=1 a n d R =0 . 179 F L I PF L O P S F l i pF o p sa r e b i s t a b l es t o r a g ed e v i c e tsh a t a r e c a p a b l eo f s t o r i n go n e b i t . T h ed i f f e r e n c b e e t w e e na L A T C H a n da F L I P - F L O i sPt h e m e t h o dt h a t i s u s e dt o c h a n g et h e i r states. L a t c h eas r ec o n s i d e r etdo b e " L e v eTl r i g g e r e d i".,et h e y c h a n g es t a t ed e p e n d i n o gn t h e v o l t a g e l e v ea l pplied. F l i p - F l o pasr es a i dt o b e " E d g eT r i g g e r e d " , i .teh.e o u t p u td e p e n d so n t h e T R A N S I T I Oo N f the gd g e ) . s i g n awl h i c hc a nb e L O Wt o H I G H ( r i s i n eg d g e )o r H I G Ht o L O W( f a l l i n e T h et e r m s" r i s i n ge d g e "a n d " f a l l i n ge d g e "r e f e r t ot h e s q u a r ew a v es i g n atlh a t i s a p p l i e dt o t h e deviceto causeit to changeits state. T h i ss q u a r ew a v es i g n ails c a l l e da c l o c kp u l s e . Rising edge F a l l i n ge d g e T h ed i a g r a . m s h o w st h a t f o r t h e c l o c kp u l s et h e " R l S l N G E D G Ei's a t t h e l e f t s i d eo f t h e GD G Ei"s a t t h e r i g h ts i d eo f r : e c t a n g u lparro j e c t i o n(sa r r o w sp o i n tu p w a r d sw ) h i l et h e " F A L L I N E t h e r e c t a n g u l aprr o j e c t i o n(sa r r o w sp o i n td o w n w a r d s ) . 180 ACTION OFFLIP FLOPS T y p i c aFl L I P - F L OaPrSe r i s i n ge d g et r i g g e r e di ,. e .t h e o u t p u tc h a n g eas t t h e r i s i n ge d g eo f e a c h c l o c kp u l s e . T h eT - t y p eF L I P - F L O P : The "T" in T-typestandsfor the word TOGGLEt h i s m e a n st h a t t h e o u t p u t sQ a n d Q ' t o g g l eo r e x c h a n g set a t e sa t e a c hr i s i n ge d g e . T a Q' T h ef l i p - f l o ph ' a st h e f o l l o w i n gd i a g r a m T h ee x p l a n a t i o n f o r t h e s ea r r o w s t o t h e r i g h ti s g i v e nb e l o w 0 0 1 1 I 0 0 I 0 1 0 I 0 0 I 1, L 0 + t + t T h eT r u t ht a b l ea n dt i m i n gd i a g r a masr eg i v e na s follows: I J-O I n t h e t r u t h t a b l et h e r ea r es o m ea r r o w st o t h e l e f t o f i t . T h ef i r s ta r r o wi n d i c a t etsh a t t h e c l o c k p . u l s ei s o n 0 b u t m o v e su p t o 1 . T h i si s a l s os h o w no n t h e c l o c kp u l s et i m i n gd i a g r a mT. h e s e c o n da r r o wf r o m t h e t r u t h t a b l e ,i n d i c a t etsh a t t h e i n p u tl e v e li s 1 a n dt h e r e f o r em o v e sd o w n t o 0 e t c .T h i si s n o t s h o w no n t h e t i m i n gd i a g r a mb e c a u s w e e a r e u s i n gt h e t i m i n gd i a g r a mt o s h o wo n l yt h e R I S I N E GD G E Sa,st h e f l i pf l o p i s o n l ya c t i v a t eodn t h e r i s i n ge d g e s . T h et r u t h t a b l ea l s os h o w st h a t t h e o u t p u t sQ a n d Q ' t o g g l ea t e a c hr i s i n ge d g eo f a c l o c kp u l s e . F o re x a m p l ea, t t h e f i r s tc l o c kl e v e l, Q = 0 a n d Q ' - 1 . A t t h e s e c o n dp u l s eo f L t h e i n p u tw o u l d h a v eR I S E N f r o m C t o 1 , i . e .i t i s a R I S I N G e d g e ,a n dt h e o u t p u t sw o u l dt o g g l es o t h a t Q = 1 a n d ( j" 1. 181 t o g g l ea s W h e nt h e c l o c kl e v e lf a l l sb a c kt o Ot h i s i s a f a l l i n ge d g ea n dt h e o u t p u t sw o u l dN O T n e x tr i s i n g t h e y r e s p o n do n l yt o r i s i n ge d g e s ,h e n c et h e o u t p u t sr e m a i nu n c h a n g e dA.t t h e states. edge,therewould againbe togglingi.e.the Q and Q' would exchange T h et i m i n gd i a g r a mfso r i n p u ta n do u t p u t sa r es h o w nb e l o w a Q' l & , a n do u t p u t sa r es h o w nh e r e .T h e lettersA, B, C, D, E,and F are not part of the diagrambut they have t oints. b e e ni n s e r t e da s l a b e l sf o r s o m ei m p o r t a n p A t A t h e i n p u ti s a t a r i s i n ge d g ea n d Q w o u l ds w i t c ht o 1 w h i l eQ ' wouldswitchto 0. A t B , t h e r ei s a n o t h e r i s i n ge d g ea t t h e i n p u t ,s o Q a n d Q ' w o u l d n o w t o g g l e. i . e .Q w o u l dg o t o 0 a n d Q ' w o u l dg o t o 1 ' A t C , t h e r i s i n ge d g eo n t h e i n p u tw o u l da g a i nc a u s et o g g l i n g Q to go to l- and Q' to 0. ,causing A t o B , B t o C ,C t o D , D t o E , a n d E t o F ,h a v eo n l y T h es p a c e s f r o m F A L L I NeGd g e so n t h e i n p u tt i m i n gd i a g r a ma n dt h e r e f o r ed u r i n g to both Q and Q'. thereare no changes theseintervals, 1,82 COUNTERS A THREE BITbinarycountercan be madefrom eitherthree fallingedgetriggeredtogglingFLlpFLOPsor three risingedgetriggeredtogglingFLlp-FLOpS. T h ea r r a n g e m e nf ot r t h e t h r e ef a l l i n ge d g eT - F L I PF-L O P iSs a sf o l l o w s : Qz(m.s.b.) Most SignificantBit Q' Q r ( 1 .bs .) LeastSignificantBit Clock pulses A I t i s i m p o r t a nt o n o t et h e s i g n i f i c a n coef t h e s y m b o l fso r R I S I N G EDGE TRIGGERE Dd F A L L I N G an EDGE TRIGGERED. The FALLING EDGE TRIGGERED is denotedby 1pr- T h eR I S I N E GD G E T R I G G E R iEsD d e n o t e db y + I t i s a n a r r o ww i t h a b u b b l ec l o s e to thetip T h e r ei s n o b u b b l e 183 T h et i m i n gd i a g r a masn dt h e c o r r e s p o n d i tnrgu t ht a b l ea r eg i v e nb e l o w : C l o c kp u l s e s a o( l . s . b . ) Q, (m.s.b.) Remembe : rL s . bm e a n L s E A SSTI G N I F I C ABNI TT m . s . bm e a n M s OSS TIGNIFICA BN I TT W h e nt h e c l o c kp u l s ei s 0 t h e t o t a l o u t p u ti s 0 . W h e nt h e c l o c kp u l s e= I , t h e o u t p u ti s 0 0 1 =1 , =2 0( o n l yt h e f i r s tf l i p - f l o pi s o n ) W h e nt h e c l o c kp u l s e= 2 , t h e o u t p u t= 0 1 0= 0 + 2 r + O =2 ( t h es e c o n df l i p - f l o pi s o n a n dt h e first is off) W h e nt h e . c l o c p k u l s e= T , t h e o u t p u t= ! ! L = 2 2+ 2 1+ 2 0= 7 e t c . ( A ltlh r e ef l i p - f l o p a s r eo n ) W h e nt h e c l o c kp u l s ei s 5 , t h e t i m i n gd i a g r a ms h o w st h a t t h e 3 ' of l i p f l o p i s o n , t h e s e c o n di s o f f a n dt h e f i r s ti s o n t o g i v e 2 2+ 0 + 2 0= 4 + 1 = 5 Outputs Numbeo r f Qz=22=4 Qt= 2'= 2 C l o c kP u l s e m . s b. . 0 0 0 I 0 0 2 0 I 3 0 1 4 1, c 5 1, 0 6 1, 1, 7 1, T 1.84 Q o = 2 u= 1 l.s.b. 0 1 0 I 0 I 0 1, MODULE 3 Atomic and NuclearPhysics I M P O R T A NFTO R M U L A E : (1) Photon Energy E - hf (2)Work functi.onenergy e: ltfo ( 3 ) E t n s t e t n 's P l t o t o e l e c t r ie c q u a t i " o n: h f : , *;mv2 OR ltf - E + eV, (4)Attenuatton of X ra"ys:I : Io€GFx) (S)Energy LeuelTransi"tton AE - hf : Ez - Er $ ) f h e d . eB r o g l i . eW a u e t e n g t l tl , : L p (7)Massnumber-A*Z (B)Einstei"n'sMassEnergy Relatton L,E = Lmc2 (e) Acti.utty A =#: -AN (I})Number of nuclei present N : Noe-At ( 1 1 )H a t fL i' fe r r , : Y /2 (1 2 )A c ti u i .ty A = Ao (;)" A w here n i s ttte number of hal f ti " ues 185 PARTIC EFFECT ThCPHOTOELECTRIC ROMAG TE NATUREOF E RA , , p a r t i c u l aN t ea t u r e "m e a n sp a r t i c l ep r o p e r t i eis. e .l i g h ta sw e l l a sa l l o t h e r t y p e so f T h et e r m X -rays,radiowavesetc,) behaveas particlesin radiation(eg.microwaves, electromagnetic g a v ep r o p e r t i e s . a d d i t i o nt o e x h i b i t i n w CE CoTf l i g h t . T h i sp a r t i c u l a tnea t u r ei s d e m o n s t r a t eidn t h e P H O T O E L E C TERFI F Thisphotoelectriceffectcanbestbe explainedasfollows:When lightof a suitablyhigh frequencyfallson a metalsurface,electronsare emittedfrom the metalsurface. t h e i re m i s s i o cn a nb e d e m o n s t r a t ebdy d r ec a l l e dP H O T O E L E C T RaOnNdS sm.ittea T h ee l e c t r o n e meansof a GoldLeafElectroscope. u . v .l i g h t lll-e lila Polished Zinc plate +++ l E x p ln aa t i o n : is givena negativechargeandthis causesits leavesto divergedue A Goldleafelectroscope nf charges. the repulsioo A sheetof polishedzincis placedat the top of the capof the ele.ctroscope. is U l t r a v i o l el it g h tf o r a m e r c u r yv a p o u rl a m pi s t h e n i l l u m i n a t e od n t h e z i n cp l a t ea n d i t to beginto collapse' observedthat the leavesof the electroscope c h a r g ew h i c hw o u l dh a v eo c c u r r e d e f t h e l e a v e si s d u et o t h e l o s so f n e g a t i v e T h i sc o l l a p s o were emittedfrom the zincsurface. rvhenphotoelectrons p l a t ep l a c e do n W h e nt h e e l e c t r o s c o pwea s i n i t i a l l yg i v e na p o s i t i v ec h a r g ea, n dt h e nt h e z i n c t h e c o p ,t h e r ew a sn o c h a n g ei n t h e d i v e r g e n coef t h e l e a v e sw h e nt h e z i n cw a si l l u m i n a t e d were with uv " Thismeansrhattherewas no changeof positivecharge,and photoelectrons attractionof the asthey were heldin placeby electrostatic to leavethe electroscope ur.lilr:l€ positivechargeson the electroscope. 186 Onesignificant otherobservation with the caseof the negatively chargedelectroscope, was t h a t w h e n a s h e e to f g l a s sw a s i n s e r t e db e t w e e nt h e u v . s o u r caen dt h e z i n cp l a t e ,t h e r ew a sn o collapso ef the leaves.. T h i so b s e r v a t i ocna nb e e x p l a i n e a d sf o l l o w s : . T h eg l a s sc a u s e tsh e R E F R A C T I o OfNl i g h t .T h eu v l i g h th a sa v e r ys m a l w l a v e l e n g t ah n d i s t o t a l l y i n t e r n a l l rye f l e c t e d s o i t i s u n a b l et o r e a c ht h e z i n cp l a t e . T h eo t h e rl o n g e rw a v e l e n g t hwsi l l p a s st h r o u g hb u t d o n o t h a v es u f f i c i e net n e r g yt o s u p p l yt o the electronsto causethem to escapefrom the metalsurface.As a result,the pHOTOELECTRIC EFFECT doesnot occur. L a w so f P h o t o e l e c t r iEcm i s s i o n : ( 1 ) T h e p h o t o c u r r e nw t h i c h i s t h e n u m b e ro f p h o t o e l e c t r o npse r s e c o n d i, s p r o p o r t i o n a l t o t h e I N T E N S I ToY f t h e i n c i d e n rt a d i a t i o n . ( 2 ) T h e m a x i m u m K i n e t i cE n e r g yo f t h e p h o t o e l e c t r o niss d i r e c t l yp r o p o r t i o n atlo t h e F R E Q U E N Co Y f t h e i n c i d e n tr a d i a t i o na, n d i s i n d e p e n d e not f t h e i n t e n s i t yo f t h e i n c i d e n tr a d i a t i o n (. t h e p h o t o e l e c t r o nasr e e m i t t e d w i t h a r a n g eo f k i n e t i ce n e r g i e s f r o m z e r ou p t o a m a x i m u mv a l u e . ( 3 ) F o r a n y p a r t i c u l am r e t a l ,t h e r e i s a m i n i m u mf r e q u e n c yo f r a d i a t i o nt h a t w i l l c a u s e p h o t o e m i s s i oT nh . i sm i n i m u mf r e q u e n c yi s c a l l e dt h e T H R E S H O LFD REeUENCY ,d an b e l o wt h i sf r e q u e n c yn, o p h o t o e m i s s i ot na k e sp l a c e . A c c o r d i ntgo W a v eT h e o r yt,h e i n t e n s i t yo f r a d i a t i o ni s t h e p o w e rp e r u n i t a r e a ,s o a g r e a t e r l n t e n s i t yi m p l i e sa g r e a t e ra m o u n to f e n e r g yi n c i d e not n t h e m e t a ls u r f a c el .t w o u l db e r e a s o n a b lteo a s s u m et h e n t h a t w h e nt h e i n t e n s i t yi s i n c r e a s e dt h, e p h o t o e l e c t r o nssh o u l d a c q u i r ea g r e a t e ra m o u n to f K i n e t i cE n e r g ya st h e y l e a v et h e m e t a ls u r f a c e . However, this is not observedand the fact that the kineticenergyof the photoelectrons is i n d e p e n d e notf i n t e n s i t y , ( L a2w) i s a c a s eo f t h e F A I L U RoEF T H EW A V ET H E o R yo F L t G H T . Alsoaccording to WAVETHEORY, the energytransportedby a waveis continuousand for f r e q u e n c i ebse l o wt h e t h r e s h o l df r e q u e n c yt h , e e l e c t r o ns h o u l db e a b l et o a c q u i r es u f f i c i e n t energyaftera periodof time to be ableto escapefrom the metalsurface.Thisis not observed a n d i s t h e r e f o r ea n o t h e rc a s eo f t h e F A I L U RoEF T H EW A V ET H E o R yo F L I G H T . T h eo b s e r v a t i o ni n s the photoelectre i cf f e c tc a no n l yb e e x p l a i n e b d y a s s u m i ntgh a t t h e r a d i a t i o nh a sa P A . : , T I C U L A NTAET U R E T .h a ti s ,e l e c t r o m a g n e triacd i a t i o nb e h a v e sl i k ea s t r e a m of iiiscreteparticles. 1.87 THEQUANTUMTHEORY A L B E RE T I N S T E IdNe v i s e da t h e o r yt h a t w o u l da c c u r a t e leyx p l a i nt h e P h o t o e l e c t rE i cf f e c t : T H E Q U A N T U MT H E O R Y . T h i st h e o r yi m p l i e st h a t a l l e l e c t r o m a g n e rt a i cd i a t i o ins m a d eu p o f i n d i v i d u auln i t sc a l l e d PHOTONS. A PHOTONis a basicunit of electromagnetic radiationthat behavesas a discreteparticle. ( L E A R)N E a c hp h o t o nh a sa f i x e da m o u n to f e n e r g yc a l l e da Q U A N T I . J o Mf e n e r g y . l f t h e i n c i d e net n e r g yh a sa f r e q u e n c y /t,h e nt h e q u a n t u mo f e n e r g yi n a p h o t o ni s g i v e nb y : E:hf W h e r eh i s a c o n s t a nct a l l e dt h e P l a n c k 'cso n s t a n(t h =6 . 6 3x 1 O - 3 a J s ) A l l e l e c t r o m a g n e triac d i a t i o nh a v ea s p e e dc = 3 x 1 0 8 m s1 i n a v a c u u ma, n dt h e w a v e l e n g tohf ( f r o mv : f 7 ) . a n ye . m .r a d i a t i o ins g i v e nA VA : | ht . H e n c et h e e n e r g yo f a s i n g l ep h o t o nc a na l s ob e w r i t t e na stE- ' 1' E_ hc 1 -hf !-EARNI i cf f e c ta sf o l l o w s : T h ep h o t o nm o d e lc a ne x p l a i nt h e r e s u l t so f t h e p h o t o e l e c t r e T h ei n t e n s i t yo f t h e i n c i d e nrt a d i a t i o ni s a m e a s u r eo f t h e n u m b e ro f i n c i d e npt h o t o . npse r s e c o n da, n dw h e nt h e s ep h o t o n ss t r i k et h e m e t a ls u r f a c et ,h e r ei s a d i r e c t r a n s f e o r f energy f r o m e a c hp h o t o nt o a p a r t i c u l aer l e c t r o nH . e n c ea g r e a t e ri n t e n s i t yo f i n c i d e nlti g h tm e a n sa g r e a t e rn u m b e ro f p h o t o n sp e r s e c o n ds t r i k i n gt h e m e t a ls u r f a c ea, n dt h i sw o u l dm e a na g f e a t e rn u m b e ro f p h o t o e l e c t r o nesm i t t e dp e r s e c o n da so b s e r v e d . W h e nt h e f r e q u e n c o y f t h e i n c i d e nlti g h ti s i n c r e a s e dt h, e e n e r g yo f e a c hp h o t o ni s i n c r e a s e(dE = h f ) ,c a u s i n tgh e p h o t o n st o n o w t r a n s f e a r g r e a t e ra m o u n to f e n e r g yt o t h e e l e c t r o n sw, h i c h i n t u r n c a u s e tsh o s ep h o t o e l e c t r o nt os n o w h a v ea g r e a t e rK Ew h e nt h e y l e a v et h e m e t a l surface. \ l / h e nt h e i n c i d e nrt a r J i a t i oi n s b e l o wt h e T H R E S H O L FD REQUENC t hYe, e n e r g yo f t h e p h o t o ni s 'low;:r,ij t h e e n e r g yt r a n s f e r r etdo e a c he l e c t r o ni n t h e m e t a li s t o o l o w f o r i t t o e s c a p ef r o m t h e 188 m e t a ls u r f a c eT. h ee n e r g yi s n o t c o n t i n u o uasn dt h e e l e c t r o ncsa n n o ta b s o r bm o r e t h a no n e q u a n t u ma t a n yt i m e ,a n da r et h e r e f o r eu n a b l et o e s c a p teh e m e t a l . PROPERTIES OFTHEMETALSURFACE F o re a c hp a r t i c u l am r e t a l ,t h e r ei s a m i n i m u mf r e q u e n c o y f l i g h tt h a t c a nb e r a d i a t e do n i t s s u r f a c et o c a u s ep h o t o e m i s s i o n T h i sm i n i m u mf r e q u e n c o y f e l e c t r o m a g n e triacd i a t i o n t h a t i s r e q u i r e dt o c a u s ep h o t o e l e c t r o n e m i s s i o ins c a l l e dt h e T H R E S H O F LR D E e U E N COYRC U TO F FF R E e U E N C f oYr t h e m e t a l . R e c a ltlh a t c = ' f l h e n c e l - : . l f t h e t h r e s h o l d f r e q u e n c yi s d e n o t e db y f o ,t h e n t h e I c o r r e s p o n d i nwga v e l e n g t ihs c a l l e dt h e T H R E S H o LWDA V E L E N G T oH r C U T - O FW F AVELENGTH and is denotedby trg. C Ao: r lo T h em i n i m u me n e r g yt h a t a p h o t o n m u s th a v et o c a u s ep h o t o e l e c t r oenm i s s i o n i s d e n o t e db y $ a n d i s c a l l e dt h e w o r k f u n c t i o ne n e r g yo f t h e m e t a l Q : hf o L E A RT NH I S : The WoRK FUNCTIoNenergyof a metal is the minimum energythat an incidentphoton must havein order to causethe emissionof a photoelectron. W h e nt h e e n e r g yo f t h e p h o t o ni s e q u a l t ot h e w o r k f u n c t i o ne n e r g yo f t h e m e t a l ,t h e e m i t t e d p h o t o e l e c t r odno e sn o t h a v ea n y i n c r e a s ien i t s K i n e t i ce n e r g y . H o w e v e ri,f t h e e n e r g yo f t h e p h o t o n( E : h f ) i s G R E A T Et hRa nt h e w o r k f u n c t i o ne n e r g y of t h e m e t a l ,t h e nt h e d i f f e r e n c ien t h e t w o e n e r g i e (si . e .h f g o e s i n t o i n c r e a s i n g t h e K I N ETIC il E N E R GoYf t h e p h o t o e l e c t r o n . T h ep h o t o e l e c t r o nasr e l i b e r a t e d w i t h a r a n g eo f K i n e t i ce n e r g i e u s p t o a m a x i m u mv a l u ew h i c h is denotedby KEr.". KE."*= hf - O. Thisis EtNSTE|N,S PHOTELECTRTC EeUAT|ON. L E A R NT H I : : Einstein's Photoelectric equation is:KE.",= hf - e ORKE.."=!^uko*: 189 hf - e POTENTIAL STOPPING W h e n l i g h ts t r i k e st h e m e t a l akes p l a t eC , p h o t o e m i s s i ot n C o n s i d et rh e f o l l o w i n gc i r c u i t : p l a c e( a s s u m i nt gh a t t h e V a c u u mc h a m b e r f r e q u e n c yo f l i g h ti s s u f f i c i e n t lhyi g h ) . P h o t o e l e c t r o nasr e l i b e r a t e d from C and moveto strikethe p l a t eA . T h e m i g r a t i o no f e l e c t r o n s f r o m C t o A c o m P l e t etsh e c i r c u i ta n d a c u r r e n ti s d e t e c t e da n d d i s P l a Y eodn t h e ammeter. a e c r o s sA Ca s s h o w n : C o n s i d enr o w t h e c a s ew h e r et h e r ei s a p o t e n t i adl i f f e r e n c a negative adjusteduntilthe plateA is sufficiently The reversepotentialis continuously t o i u s t r e p e la n y p h o t o e l e c t r o nf rso m r e a c h i n igt , t h u sc a u s i n tgh e p h o t o c u r r e n t r e c o r d e db y t h e a m m e t e rt o f a l lt o z e r o A t t h i s p o i n t ,t h e r e v e r s ep o t e n t i aal c r o s sA Ci s c a l l e dt h e s t o p p i n gp o t e n t i aal n d i s to crossthe gapacross denotedby V, , and the energyneededby the photoelectrons - O ACwould havebeenequafto ] mvlro, - llf the energyireededby an electronto overcomea barrierpotentialis equal Recallr!-rat the stopping s u s th a v et o o v e r c o m e i o e V ,i l e n c et h e K i n e t i ce n e r g yt h a t t h e e l e c t r o n m p o t e n t i ails e q u a lt o e V ' 190 H e n c e€ V , - K E ^ o * - ! * u , ^ q x : hf - O. i cq u a t i o nc a nt h e r e f o r eb e r e = w r i t t e na s : E i n s t e i n 'psh o t o e l e c t r e 'J- 't r €rV ,: ; m v k o * - h f - 0 . L B u t@: h f o ; €Vr: hf - hfo: h(f - f). T h i se q u a t i ocna nb e r e -a r r a n g eadsf o l l o w s : v' : h f - h f o ee l f a g r a p ho f S t o p p i n gP o t e n t i avl e r s u sf r e q u e n c iys p l o t t e d i, t w o u l dh a v et h e f o l l o w i n g shape: Stopping Potential fo frequency The pointwherethe graphcutsthe x-axisrepresents a stoppingpotentialof zeroand this is p o i n tw h e r et h e f r e q u e n c o y f t h e i n c i d e nrt a d i a t i o ni s e q u a lt o t h e T H R E S H o LFDR E Q U E N c y F O RT H EM E T A L . T h i sc a nb e d e d u c e df r o m t h e e q u a t i o n : v' : h f - h f o e V ,w i l l b e e r o w h e n hf l"l_- hfo ee W h i c hm e a n st h a t f =foat V, =0 191 Fromthe previousgraph,the gradientwould be equalto I can The stoppingpotentialfor a metal irradiatedwith photonsof sufficientlyhigh energy that must be appliedacross DIFFERENCE POTENTIAL thereforebe definedas the REVERSE preventthe the metal surfaceand a collectorplate in an evacuatedchamberto iust photoelectronsfrom reachingthe collector' T h e e n e r g yo f a p h o t o nc a nb e e x p r e s s eidn J o u l e so r a l t e r n a t i v e liyn E L E C T R o N V o L T S ( e V ) L e V= e l e c t r o n i c h a r g ex l V o l t = 1 ' 6 x L 0 1eJ' LRAPHS: O T H E RU S E F UG rrent Photocu 4rlntensitYr (C) Intensityz(B) \ I n t e n s i t v 3( A ) A<B <C -vr. t atures: T h eg r a p hs h o w s3 s i g n i f i c a nf e ( 1 ) A s t h e i n t e n s i t yi s i n c r e a s e dt h, e m a x i m u mp h o t o c u r r e ni tn c r e a s e s ' s u r f a c ea, n d a s a A g r e a t e ri n t e n s i t ym e a n st h a t t h e r ea r e m o r e p h o t o n sp e r s e c o n ds t r i k i n gt h e m e t a l > T h i sl e a d st o a r e s u l t h e r ew o u l d b e m o r ee l e c t r o n sp e r s e c o n db e i n ge j e c t e df r o m t h e m e t a ls u r f a c e g r e a t e rp h o t o c u r r e n t . ( 2 ) T h e p h o t oc u r r e n ti n c r e a s efsr o m z e r o( a t - V , ) u p t o a m a x i m u ma t the V = 0 .A s t h e p . d i s m a d el e s sa n d l e s sn e g a t i v et ,h e r e i s l e s sr e s i s t i v feo r c ea c t i n go n p h o t o e l e c t r o nhse n c em o r eo f t h e m w o u l d b e a b l et o t r a v e lf r o m t h e m e t a ls u r f a c et o t h e f r e et o a n o d e .A t V = 0 , t h e r ea r e n o r e s i s t i v feo r c e sa c t i n go n t h e p h o t o e l e c t r o nasn d a l l a r e e f V b e y o n dz e r od o e sn o t t .h e i n c r e a s o m o v et o t h e a n o d et o p r o d u c et h e p h o t o c u r r e n T remain i n c r e a s teh e p h o t o c u r r e nat st h e n u m b e ro f p h o t o e l e c t r o nl se a v i n gt h e m e t a ls u r f a c e s n l y i f i n t e n s i t yc h a n g e s ) u n c h a n g q (dt h i sc h a n g e o ( 3 ) R e g a r d l e sosf h o w t h e i n t e n s i t yi s c h a n g e dt,h e s t o p p i n gp o t e n t i a l( - V , )r e m a i n su n c h a n g e d ' which is T h e s t o p p i n gp, o t e n t i a li s o n l y d e t e r m i n e db y t h e e n e r g y o f t h e p h o t o e l e c t r o n s d e t e r m i n e db y t h e f r e q u e n c yo f t h e i n c i d e n rt a d i a t i o n 192 TUTORIAL SHEET (DATA: speed"of li"ghtls 3 x 1O8ms-1,Planck constanth _ 6.63 x 10-34Js m a s s o f e l e c t r o n : 9 , 1 x 1 0 - 3 t k g , c h a r g eo f e l e c t r o n : r . 6 L0-1eC) i (1) A metalsurfacehasa cut off wavelengthof O.7zgm.calculate ( a )T h ec u t o f f f r e q u e n c y ( b )T h ew o r k f u n c t i o ni n b o t hJ o u l e sa n d e l e c t r o n v o l t s ( c )T h e m a x i m u mK Eo f t h e p h o t o e l e c t r o nwsh e nt h e i n c i d e nlti g h th a sa w a v e l e n g t h of 0.42;rm. ( d )T h em a x i m u ms p e e do f t h e e m i t t e dp h o t o e l e c t r o nwsh e nt h e s u r f a c ei s i r r a d i a t ew d i t h l i g h to f w a v e l e n g tO h .42gm (Ans4 ; . r 7 x l , o r a H z ; 2 . 7x61 0 - 1 s1J .; 7 3 e V; 1 . 9 gx 1 O - i e; 6 J .6 x 10sms-1) ( 2 ) l f a m e t a ls u r f a c eh a sa w o r k f u n c t i o no f 3 . 2 e Vf,i n d : (i) T h et h r e s h o l dw a v e l e n g t h (ii) T h et h r e s h o l df r e q u e n c y ( i i i ) T h e m a x i m u mK Eo f t h e e m i t t e dp h o t o e l e c t r o ni fst h e s u r f a c ei s i r r a d i a t e d with ligfrtof wavelength O.2Zp,m. ( A n s :3 . 9x 1 , 0 m - 7; 7 . 7 xl O r a H z ; 3 . gx21 0 - 1 e J ) ( 3 ) A m e t a ls u r f a c eh a sa w o r k f u n c t i o no f 4 e V .W h a t m u s tb e t h e f r e q u e n c ya n d w a v e l e n g to h f i n c i d e nlti g h to n i t t o c a u s ep h o t o e l e c t r o nt os b e e m i t t e dw i t h a ' maximum speedof 4.4x1,0sms-t? ( A n s t: . L x L O 1 s H ; 2z. 7 3x 1 0 - 7 m ) ( a ) T h e m a x i m u mK Eo f p h o t o e l e c t r o nesm i t t e df r o m a m e t a ls u r f a c ei s 1 . 8e V w h e nt h e frequencyof the incidentlightis 7.9 xi,OraHz. Calculate (i) T h ew o r k f u n c t i o no f t h e m e t a l (ii) T h e m a x i m u ms p e e do f t h e p h o t o e l e c t r o n s ( i i i ) T h et h r e s h o l df r e q u e n c y (iv) The cut off wavelength (v) T h e m a x i m u mK Ea n d s p e e do f t h e p h o t o e l e c t r o nwsh e nt h e i n c i d e n lti g h t h a sa f r e q u e n c o y f 8 . 8x 1 0 ' o H z . (Ans:2.35x 10 1eJ; 7.96x 10sms-1;3.54 x l-o1aHz ;8.47 x r-0-7m ;3.4gx 10-1sJ ; 8.7 xl-Osms-1) 193 is when lightof frequency3x 101sHz (5) A metalsurfacehasa work functionof 4.4eV,and flowsin the circuitwith the metaland a incidenton it, a photocurrentof O.221tA c o l e c t o rp l a t e .D. e t e r mni e : (i) The KEof the photoelectrons (ii) T h e n u m b e ro f p h o t o n ss t r i k i n gt h e m e t a ls u r f a c e a c hs e c o n d . (Ans:1,.2gx 10-18J; 1012electronsper second) 1..375x a (6) When lightof frequency5.8x L0isHzstrikesa rnetalsurface,photoelectrons l i b e r a t e dw i t h a m a x i m u mK Eo f 2 . 8x 1 0 - 1 8 J yf light? ( a ) W h am t u s tb e t h e s t o p p i n gp o t e n t i aflo r t h i sf r e q u e n c o ( b )W h a t i s t h e w o r k f u n c t i o no f t h e m e t a l ? (c)What is the cut off wavelengthof the metal? ( A n s: 1 7. 5 Y ; 6 . 5 3 e V1;. 9x 1 0 - 7 m ) electronsare (7) When a metalsurfaceis irradiatedwith lightof frequency5.8 x LOlsHz, l i b e r a t e dw i t h a m a x i m u ms p e e do f 1 . 8x 1 0 6 m s - t . D e t e r m :i n e (i) T h ew o r kf u n c t i o no f t h e m e t a l (ii) T h es t o p p i n gp o t e n t i arl e q u i r e df o r t h i sf r e q u e n c y ( i i i ) T h et h r e s h o l df r e q u e n c fyo r t h e m e t a l ( A n s :2 . 3 7x 1 o - 1 8 J. 2; 9Y ; 3 . 6x 1 o 1 s H z ) 194 S O L U T I OG NU i D E L I N E S 3x108 t; ^ - c fo i: (l)a. lo:7.2xL0-7m;c:3x10ems-' ,.r r r* - 4'1'7x Lol4Hz (b) 0 - hfo : 6.63 x 10-34x 4.1'7x 1014- 2.76 x !0-7eJ L e V - t . 6 x r 0 - r r J , l t e n c ez . T 6 x 1 0 - 1 e 6 . 6 3x 1 0 - 3 4x 3 x 1 0 8 Itc KE:hf-0-T-Q- 4.2x L0-7 1' rrn KE -;mv-; 2 v - 2'76x 1'0--1e - L.7Z6eV t.6 x L0-1e - 2 . 7 6 x 1 o - l e - 1 . 9 8x 1 0 - 1 e / -2:K E zxr9Bx1o-1e m 9.1x1o-31 - 6 . 6x l , O s m s - 1 ( 2 ) 0 : 3 . 2 e v- 3 . 2 x L . 6x ' J , 0 - 7 e-J 5 . L Zx 1 0 - 1 e J hc UseQ:10, tro: hc 6 . 6 3x l - 0 - 3 4x 3 x 1 0 8 e: 5 . 1 , 2x 1 0 - 1 e c 3x108 :7'7x1'o14Hz fo:i- ( 3 ) E n e r g yo f p h o t o e l e c t r o -n ).*u' -)x : 3.9 x 1-0-7m o . t X L 0 - 3 tx ( + . +x L 0 s ' ) : B . Bx L 0 - 2 o J Work functton - 4eV - 4 x 1,.6x L o - r s J : 6 . 4 x 1 ' o - r s J hf - Q-KE; ft- hf :KE+ 7 . 2 8x 1 0 - 1 e6 . 6 3x 1 0 - 3 4 O - B . B x 1 ' 0 - 2 0 + 6 . 4 x 1 0 - 1 e- 7 . 2 8 x L } - r e J t . 1 x 1 0 7 s H z ; I J s1e- r t u l 195 fhdwavelength K E - l . B e V: 1 . 8x I . 6 X 1 0 - 1 e- 2.BBx L'0-1sJ (4) K E * o , - h f - Q ; O - h f - K E - ( 6 . 6 3 x 1 0 - 3 4x 7 . 9 x 1 g t o )_ Z . B Bx 1 0 - 1 e : 2 . 3 5x 1 0 - 1 e J ( t t ) U s eK E - ),^r' 2KE m : Z . B B x 1 0 - t e; u 2x2.BB x 10-1e 9.1 x 10-31 7.g6x l-0sms-1 (i.ii")Thecutof f frequency ts the frequency correspondtng to the work functfnn 6 hfo - Q t fo :;- (tv)l,: C n: 2 . 3 5x L 0 - 1 e : 3 . 5 4x L 0 1 4 H z ffi 3 x l-08 : 8.47 x 10-7m 3 . 5 4x 1 0 1 4 -3a x B.Bx L0t4 : 5.8 x 1,0-1e (v)lnci"d"ent energy E - hf : 6.63 x 10 J KE^o* - Itf'- Q - 5.8 x 10-1e- 2.35 x 10-1e : 3.48 x 1.0-1eJ 2KE -: m 2 x 3 . 4 8 x 1 0 - 1 e9.t x L0-31 8.7x l0sms-1 ( s ) I ( E - t r f - Q , ( w h e r e Q- 4 . 4 x 1 . 6 x 1 0 - I e : 7 . 0 4 x t 0 - 1 e 1 ) K E : ( 6 . 6 3x 1 0 - 3 ax 3 x 1 0 1 s )- 7 . 0 4 x 1 0 - 1 e- L . 2 9x L 0 - 1 8 / The number of photons striktng each second ts equal to the number of electrons leavtng each second. Stncethe photocurrent ts 2.2 x l0-7 A,ilre current - rate of f low of charge. I - n :o n tt where Q - electronf"ccharge and - - nltmber of electrons per second h':nce n I 2 . 2x ! 0 - 7 t a L . 6x 1 0 - 1 e - 1.375 x 1.012 per second 196 (6)eV, : KE^ox iVs : (it) K Emax - h f - Q ; KE*o, 2.8 x 1018 e 1 , . 6x 1 0 - 1 e - 17.5V Q - I t f - K E ^ o , - ( 6 . 6 3x L 0 - 3 4x 5 . 8 x 1 0 1 s )_ Z . B x 1 0 - 1 8 0 - 10.4x 1,0-7e J 1 0 . 4x L 0 - 1 e Q_ (tll)Q- hc 1, ) 7o: 1 , . 6x 1 0 - 1 e hc - 6 . 53 e V 6 . 6 3x 1 0 - 3 ax 3 x 1 0 8 - 1 . 9x I 0 - 7 m 1 , 0 . 4x 1 0 - 1 e O: ( 7 ) I n c i " d e nE t n e r g y - l ^ L -f 6 . 6 3 x 1 0 - 3 4x 5 . 8 x 1 0 1 s: 3 . 8 4 x L 0 - 1 8 / u m o r : 1 . 8x t O 6 m s - . ; K E * o r : ; m v f r " o * - ) r 9 . I x l - 0 - 3 1 x ( 1 . 8x t 0 6 ) z _ 1,.47x 10-18/ KE^o' -hf -Q; Q -hf -KE^o*:3.84x (i.i) eV, - KE^oy; W (tli)Q:hfoifo: 1 0 - 1 8- 1 . 4 7 x 1 0 - 1 8- 2 . 3 7x L 0 - 1 8 / KE*o, _t :r." :9-:rJ_ e.Zv e L6 x 10-1e a 2 . 3 7x 1 0 - 1 8 - It 6 . 6 3x 1 0 - 3 4 1.97 3.57 x 1,01s Hz X.RAYS Production: T h e P r i n c i p loef X - R a Y such strikea metal.target Whenvery highenergyelectrons(in the orderof kiloelectron-volts) s e c e l e r a trea p i d l ya, n dw h i l em o s to f t h e i rk i n e t i ce n e r g yi s a st u n g s t e nt,h e e l e c t r o n d in the form of heat,a smallpart (aboutt%|, is convertedto X radiation.Additionally, dissipated s i l l s o m e t i m ecsa u s ee n e r g yl e v e tl r a n s i t i o nosf e l e c t r o n isn t h e t h e h i g he n e r g ye l e c t r o nw targetatomsand causethe emissionof X rays two processes At the pointof collisionbetweenthe electronand the tungstenatom,thereare that leadto X-raYProduction: (1) Bremsstrahlun Pgr o c e s s s h e l l (2) K emission leadto two differenttypesof X-rayspectra. Thesetwo processes w h, i l et h e K - s h e lel m i s s i o n pg r o c e s lse a d st o a C O N T I N U O USSP E C T R U M T h eB r e m s s t r a h l u n a l s oc a l l e da c h a r a c t e r i s tsi cp e c t r u m ) l e a d st o w h a t i s c a l l e da L I N GS P E C T R U(M LUNG PROCESS: BREMSSTRAH m e a n s" r a d i a t i o n ' j ) , . i sgo f G e r m a no r i g i n (B r e m sm e a n s" b r a k i n g a" n d s t r a h l u n g Bremsstrqhlun X radiation a n d i s d u et o t h e c o n v e r s i oonf t h e k i n e t i ce n e r g yo f t h e h i g he n e r g ye l e c t r o nt o ' b r a k e sa' r e i m p o s e do n t h e e l e c t r o na s i t c o l l i d e w s ithanobstacle. w h e nt h e atoms,the When an incominghighspeedelectronof kineticenergyEostrikesone of the target of anX-ray e l e c t r o nw i l l l o s ea n a m o u n to f e n e r g yA E, a n d p a r to f t h i se n e r g yw i l l b e t h e e n e r g y photon.(Therestof AEwill be convertedto heat) Theelectronwill be deflectedby the collisionand it is now referredto asa SCATTERED electron. electron'whoseenergyis now lessthan Eswill now go on to collidewith This.scattered , h i c hw i l l h a v ea n e n e r g y t h a its d i f f e r e n t a n o t h e ra t o m a n d p r o d u c ea n o t h e rX - r a yp h o t o n w from that of the first Photon. processwill continueand a seriesof photonsof differentenergiesare Theelectronscattering p r o d u c e dc,a u s i n tgh e f o r m a t i o no f a c o N T I N U o U xS r a ys p e c t r u mT. h ee l e c t r o nw i l l s t o p producingphotonsrvhenit hascometo rest' 198 THEK-SHELL EMISSION PROCESS: W h e na n i n c o m i n gh i g hs p e e de l e c t r o ns t r i k e sa targetatom,that electronmay knockout one o f t h e e l e c t r o n isn t h e K - s h e l(ll o we n e r g ys h e l w l h i c hi s c l o s et o t h e n u c l e u s, )l e a v i n g a h o l ei n t h a ts h e l l . A n e l e c t r o ni n o n e o f t h e h i g h e rs h e l l sw i l l n o w j u m p i n t ot h a t l o w e rK s h e l tl o f i l l t h e v a c a n c y , a n d i n d o i n gs o ,i t w i l l g i v eu p s o m eo f i t s e n e r g yb y e m i t t i n ga n X - r a yp h o t o n . T h e K s h e l li s t h a t s h e l fl o r n = 1 , t h e L s h e l li s t h e o n ef o r w h i c hn = 2 a n dt h e M s h e t fl o r n = 3 . W h e na v a c a n c yi s c r e a t e di n t h e K s h e l ld u e t o t h e e j e c t i o no f a n e l e c t r o na, n d a n e l e c t r o n f r o m t h e L s h e l fl i l l st h a t v a c a n c yt ,h e e m i t t e dr a d i a t i o ni s c a l l e dt h e K ol i n ei n t h e s p e c t r u m . l f t h e v a c a n c yi n t h e K s h e l li s f i l l e db y a n e l e c t r o nf r o m t h e M s h e l l t, h e nt h e e m i t t e dr a d i a t i o n i s c a l l e dt h e K sl i n ei n t h e s p e c t r u m . T h ed i s t r i b u t i o on f w a v e l e n g t hi sn t h e e n t i r es p e c t r u ms h o w i n gb o t ht h e C O N T IU NO U S S P E C T R UaMn dt h e L I N ES P E C T R Ui M s g i v e nb e l o w . T h e K pl i n eh a s greaterenergy(due Relative t o i t ss m a l l e r intensity w a v e l e n g t hb) u t h a sa s m a l l e r INTENSITY. T h e s h a r pp e a k sa r e Continuous d u et o K s h e l l e m i s s i o nw, h i l et h e continuous s p e c t r u mi s d u e t o B16msstrahlune , trrin Wavelength(pm) E n e r g yl e v e l t r a n s i t i o n Diagram: M ( n = 3) L(n=2) K(n=1) 199 PRODUCTION OFX.RAYS Target anode Coolingoil+ Orwater :--------------* I E v a c u a t etdu b e C a t h o d e( t o e m i t e l e c t r o n s ) Lead T h ec a t h o d ei s a c o i lo f t u n g s t e na c r o s sw h i c hi s c o n n e c t e tdo t h e m a i n ss u p p l y( 2 2 0 Va . c . ). A s . h e s ee l e c t r o n as r et h e n a c c e l e r a t e d a c u r r e n ft l o w st h r o u g hi t , e l e c t r o nas r e e m i t t e d T t h r o u g ha p o t e n t i adl i f f e r e n c o e f a b o u t1 0 0 k Vw h i c hi s a p p l i e da c r o s st h e a n o d et o t h e cathode. T h ea n o d ei s m a d eo f c o p p e ra n d h a sa s m a l lb l o c ko f t u n g s t e nf i x e do n i t . T h et u n g s t e ni s t h e t a r g e tf o r t h e h i g hs p e e de l e c t r o n sA. st h e e l e c t r o ncso l l i d ew i t h t h e t u n g s t e n9, 9 %o f t h e i r I % i s c o n v e r t e di n t o X r a y p h o t o n s . k i n e t i ce n e r g yi s c o n v e r t e di n t o h e a ta n dt h e r e m a i n i n g i s a s u i t a b l em a t e r i a l f o r t h et a r g e ts i n c ei t c a nw i t h s t a n dv e r yh i g ht e m p e r a t u r e s Tungsten w i t h o u tm e l t i n g . T h el e a ds h i e l di s a n e c e s s a rsya f e t yd e s i g nt o p r e v e n t h e e s c a p eo f x r a y sf r o m a l l p o i n t s o t h e rt h a nt h e w i n d o w . T h eh i g ht e m p e r a t u r edse v e l o p e d b y t h e c o l l i s i o nbse t w e e nt h e e l e c t r o nas n dt h e t a r g e t , m u s tb e c o n t r o l l e db y m e a n so f a c o o l i n gf l u i d ,w h i c hi s t y p i c a l l o y i l .O i l d o e sn o t e v a p o r a t e as e u i l du p .W a t e rc a nb e u s e d w a t e rd o e s ,a n d h e n c et h e r ei s n o d a n g e ro f a v a p o u rp r e s s u r b ',,vhen there is a veryefficientflow design. I t_ 200 ABSORPTION OFX RAYS X r a y sa r ea b s o r b e db y m e t a l s ,w h i c hm e a n st h a t t h e i ri n t e n s i t yd e c r e a s easst h e y p a s st h r o u g h m e t a l sa n dw e s a yt h a t t h e y u n d e r g oA T T E N U A T I O N . Attenuation i s t h e g r a d u adl e c r e a s ien i n t e n s i t y . l f a b e a mo f X - r a y sh a sa n i n c i d e nitn t e n s i t y1 oo n a m e t a ls u r f a c et ,h e n a s i t p a s s etsh r o u g ha d e p t hx o f t h e m e t a l ,t h e i n t e n s i t y w o u ldde c r e a s e t o a n e w v a l u el w h e r e I : I o € - v r . T h eq u a n t i t yp i s c a l l e dt h e L T N E AARB S O R P I OcNo E F F t c l E N T . TUTORIAT SHEET (1) A beamof X raysof intensity leis irradiated on a pieceof material thathasan absorotron coefficient of 0.18cm-1. what mustbethethickness of the material to causethe intensitv of the beamto fallto: (a) 4Oo/o (bl 76% (c) 0.03% (Ans:5.1cm;10cm;45.Ocm) (2) What is the valueof the absorptioncoefficient of a materialif for a thickness of 0.4rnm 'the intensityof a beamof X raysis reducedto 4o/o of its initialvalue. (Ans8.05mm-1) ( 3 ) A b e a mo f X r a y so f i n t e n s i t y5 5 W m m - i2s i n c i d e not n a m a t e r i aw l h o s el i n e a ra b s o r p t i o n coefficientis 0.44mm-1. What is the intensityof the beamat a depthof : (a)0.75mm (b)2.6cm (Ans3 : 9 . 5 W mm - 2 ; 5 . x9 1 0 - 4 W m m - 2 ) ( a ) W h e na b e a mo f X r a y s i s i n c i d e not n a s p e c i m e nt h , e intensitd y e c r e a s eBsY3 5 %o f i t s i n i t i a vl a l u ef o r a d e p t ho f 0 . 8 5 c m . calculate t h e l i n e a ra b s o r p t i o cno e f f i c i e notf t h e m a t e r i a l . ( A n s0 . 5 L c . n ' 1 ) 20r SOLUTIONS ( 1 ) 1 : I o € - F x ; I = 0 . 4 I o . , l t e n c e0 . 4 l l 0 = -I s e - t t x ; 0 . 4 : s-Lrx where F : 0.1Bcm-7 T a k t n g I o g s : l n ( 0 . + )- - P x , -0.92 - -0.18x ; x - 5.1,cm -0.L8x ; ( i i ) l n ( 0 . 1 , 6 )- -1.8 : -0.18x ; x - 10cm -0.18x ; -8.11 :0.LBx ;x = 45cm ( l i l ) l n ( 0 . 0 0 0 3 )- (2)l-lse-ttx ; I=0.04 Is,x-0.4mm h e n c e0 . 0 4 / s = - I o e - j ' + u i 0 ' 0 4 - e - o ' 4 t t ln(0.04) - (3)1 ; -0.4t , -3.21t - -0.4tt ; lt: B'\Smm-r I s e - t r x ; I : $ J s - @ ' + + x 0 ' 7:s ) 3 9 . 5 W m m - 2 I z : 5 $ s - ( o ' + + x 2 6 -) 5 . 9 x L 0 - 4 W m m - 2 ( N o t e t h a t 2 . 6 c m - 2 6 m m ) (4)A d"ecreaseby 350/omeans that the new Intenstt! : 650/oIo I : I o e - F * ; 0 . 6 5 1 s: I o e - F x l n 0 . 6 5- -0.85p ; p: 202 ln 0.65 - S.Lcm-' _0S5 APPLICATION OFX RAYS IN MEDICINE C A N C EFRA C T N S a t i o n aCl a n c e !rn s t i t u t eN a t i o n aIln s t i t u t eos f H e a l t hR a d i o t h e r o payl,s oc a l l e dr a d i a t i o n t h e r a p y i,s t h e treatmeno t f cancea r n d o t h e rd i s e a s ews i t h i o n i z i n gr a d i a t i o n . l o n i z i n gr a d i a t i o nd e p o s i t e s n e r g yt h a t i n j u r e so r d e s t r o y cs e l l s i n t h e a r e ab e i n gt r e a t e d( t h e" t a r g e t i s s u e "b) y d a m a g i n g t h e i rg e n e t i cm a t e r i a lm , a k i n gi t i m p o s s i b lfeo r t h e s ec e l l st o c o n t i n u et o g r o w .A l t h o u g hr a d i a t i o nd a m a g e b s o t hc a n c e r c e l l sa n d n o r m a lc e l l st,h e l a t t e ra r ea b l et o r e p a i rt h e m s e l v e s A s * s n n s d ' l * v e rs l i c e How doesa CTscannerwork? l n 1 9 6 7a n E n g l i s h m abny t h e n a m eo f G o d f r e yH o u s n f i e lm d u l l e do v e rt h e p o s s i b i l i toyf producing a c r o s s - s e c t i o ni m a la g eo f a n o b j e c t .C o m p u t e da x i a tl o m o g r a p h (yC A Tt)h u sb e c a m e t h e f i r s tn o n - i n v a s i vt e c h n i q u e f o r d i s p l a y i nagn i m a g eo f t h e h u m a nb o d yf r e eo f s u p e r i m p o s i t i of rno m o v e r l y i n g organs. T h ef i r s tC Ts c a n n eur s e di n 1 . 9 7 2 w a se x t r e m e l yr u d i m e n t a r yb y t o d a y ' ss t a n d a r d s T . o p r o d u c eo n e r e c o g n i z a bilm e a g et o o k n i n ed a y s i, m a g er e c o n s t r u c t i ot w n o a n d a h a l fh o u r sa n d p u n c ht a p ef e e d - i nt i m e ' ag r e a td e a ll o n g e r E . a r l ys c a n n e rcso u l do n l yd i s p l a yi m a g e si n o n e p l a n e( a x i apl l a n e )h, e n c et h e t e r m C A Ts c a n- ' A ' m e a n i n ga x i a lS . c a n n e rnso w c a nd i s p l a y i m a g e si n a n yp l a n e i,n c l u d i n3gD s o t h e ' A ' w a sd r o p p e df r o mt h e t i t l e . T o d a yC , Ts c a n n e rcsa na c q u i r ea n i m a g e ( si )n l e s st h a no n e s e c o n dw , i t h t h e i m a g ed i s p l a y e d immediatelM y .o d e r n ' h i g h e n d ' s c a n n e rcsa na c q u i r eu p t o 6 4 i m a g e a s t onceS . u c hs c a n n e r s a r ec a l l e dM u l t iS l i c eu n i t s . A C Ts c a n n eer s s e n t i a l cl yo m p r i s eosf a t a b l e ,a c o m p u t e ra, n d a g a n t r y( t h e' d o n u t ' s h a p e rdi n g c a s i n g )l.n s i d et h e g a n t r yi s a n x - r a yt u b e a n d a r i n go f r a d i a t i o nd e t e c t o r w s h i c hs u r r o u n dt h e t a b l e . D u r i n ga C Ts c a n t, h e x - r a yt u b e s p i n sa r o u n dt h e p a t i e n te m i t t i n gx - r a y sw , h i c hp a s s t h r o u g ht h e p a t i e n t ' sb o d y . T h ea m o u n to f r a d i a t i o na b s o r b e d b y t h e p a t i e n ti s m e a s u r e d by t h e d e t e c t o r sT. h i si n f o r m a t i o n i s t h e n s e n tt o a c o m p u t e rw , h i c hu s e st h e s em e a s u r e m e n t s , t h e p o s i t i o no f t h e p a t i e n ta n dt h e a n g l et h e r a d i a t i o n w a sd e t e c t e da t , t o d e c i d ew h e t h e re a c h p a r to f t h e p a t i e n ts c a n n e d c o m p r i s eosf a i r ,f l u i d ,b o n e ,f a t , o r m u s c l e .T h i si n f o r m a t i o n is t h e n d i s p l a y e ad sa p i c t u r e .I n t h i sw a y ,a C Ts c a n n eer n a b l e sa d o c t o rt o l o o ka t t h e b o d ys l i c e byslice. a n df u n c t i o np r o p e r l y . l o c a l i z esdo l i dt u m o r s ,s u c ha s c a n c e r o s f t h e s k i n ,t o n g u e ,l a r y n xb, r a i n ,b r e a s to, r u t e r i n e c e r v i xl.t c a na l s ob e u s e dt o t r e a t l e u k e m i a n d l y m p h o m a( c a n c e rosf t h e b l o o d - f o r m i ncge l l s a n d l y m p h a t i sc y : ie m , r e s p e c t i v e l y ) . 203 LINESPECTRA . v i d e n coef t h i s i s t o e x i s ti n p a r t i c u l aer n e r g yl e v e l sE T h ee l e c t r o n isn a t o m sa r e b e l i e v e d o f l i n es p e c t r a . o b t a i n e db y t h e p r o d u c t i o n E l e c t r o nws i l l t e n d t o p o p u l a t et h e l o w e s te n e r g yl e v e l sf i r s t ,a n d a st h e s eb e c o m e f i l l e dt h, e e l e c t r o n s t a r to c c u p y i ntgh e h i g h e rl e v e l s . d ith W h e na n e l e c t r o na b s o r b se n e r g y f o re x a m p l ei f t h e m a t e r i ails h e a t e do r i f i t i s i r r a d i a t e w l o w e n e rgy e l e c t r o m a g n e twi ca v e s a, n e l e c t r o nm a ya b s o r be n e r g ya n d m o v ef r o m i t s i n i t i a l l y s t a t e( l e v e lt)o a h i g h e rl e v e l o b e u n s t a b l e* .T h e I n t h i sh i g h e rl e v e lt,h e e l e c t r o nh a sm o r ee n e r g ya n d i s c o n s i d e r et d b y t h e a m o u n to f e n e r g yi t p o s s e s s etsh;e g r e a t e r t h e s t a b i l i t yo f t h e e l e c t r o ni s d e t e r m i n e d a m o u n to f e n e r g yt,h e m o r eu n s t a b l ei t i s . T h ee l e c t r o na t t h e h i g h e rl e v e tl h e n t r i e st o r e g a i ni t s s t a b i l i t ya, n d i t d o e st h i s b y e m i t t i n gt h e e n e r g yt h a t i t p r e v i o u s layb s o r b e dT. h i se n e r g yi s e m i t t e di n t h e f o r m o f l i g h to r s o m eo t h e r f o r e x a m p l eX - r a y sg, a m m ar a y se t c . t y p e o f e l e c t r o m a g n e triac d i a t i o n F o rd i f f e r e n et n e r g yl e v e tl r a n s i t i o nisn t h e a t o m ,d i f f e r e n at m o u n t so f e n e r g i eas r ee m i t t e d , t a v e l e n g tahn dh e n c ea d i s t i n cct o l o u r a n de a c hp a r t i c u l aarm o u n t b fe n e r g yh a sa d i s t i n cw a s s o c i a t ewdi t h i t . is H e n c ef o r a s e r i e so f e n e r g yl e v e tl r a n s i t i o n sa,S P E C T R UOMFB R I G H T LCYO L O U R ELDI N E S produced. T h ef o l l o w j n gd i a g r a ms h o w ss o m ep o s s i b l e n e r g yl e v e tl r a n s i t i o nisn a n a t o m . n=5 ^-A tt - F o ra n e n e r g yl e v e lt r a n s i t i o n f r o m E 4t o E s, t h e e n e r g y r a d i a t e db y t h e a t o m i s g i v e n a n=3 by: l t - AE:hf: L Ea-En t n e r g yt r a n s i t i o ni s f r o m E 4t o E sa n d t h i s t r a n s i t i o nw i l l h a v e t h e I n t h e a h r o v ed i a g r a m , r e g r e a t e se hct t a v e l e n g t h( A E - h f : = l g r e r r. ' , ' r tf r e q u e n c y a n d t h e s h o r t e sw 204 A L i n es dencefor E a c hl i n ei n t h e s p e c t r u m i n d i c a t eas p a r t i c u l aern e r g yl e v e tl r a n s i t i o n a n d a n o b s e r v a t i oonf t h e s p e c t r u mo f I S O L A T EADT O M Sr e v e a l tsh a t t h e l i n e sa r es e p a r a t e a n dd i s t i n cftr o m e a c ho t h e r . T h ef a c tt h a t t h e l i n e sd o n o t t o u c he a c ho t h e rt o f o r m a c o n t i n u o ubs a n d ,i n d l c a t etsh a t t h e e n e r g yl e v e tl r a n s i t i o nasr eq u i t ed i s c r e t ea, n dt h e r ei s n o t a c o n t i n u u m( a c o n t i n u o u rse g i o n i)n t h e t r a n s i t i o np r o c e s s . The EMISSION SPRECTRUM for any atom is seenas a seriesof brightlycolouredlinesagainst a dark background. ABSORPTION SPECTRA E a c he l e m e n th a si t s o w n d i s t i n cst e t o f s p e c t r al li n e sa s s o c i a t ewdi t h t h e e n e r g yl e v e l t r a n s i t i o nt sh a t a r eu n i q u ef o r e a c he l e m e n t . R e c a ltlh a t e a c hc o l o u ri n t h e s p e c t r u mc o r r e s p o n dt o s a p a r t i c u l aar m o u n to f e n e r g yt h a t i s r a di a t e d , T h ee l e m e n st o d i u mh a s p n l yo r a n g es p e c t r al il n e s . C o n s i d enro w a n e l e m e n itn i t sg a s e o ufso r m (f o r e x a m p l e s o d i u mv a p o u r b) e i n gi r r a d i a t e d w i t h w h i t e l i g h t .T h ew h i t e l i g h ti s m a d eu p o f a s e r i e so f c o l o u r s( V I B G y O R w)h i c hc a nb e s p l i t u p b y m e a n so f a p r i s ma n dt h e l i n e so f t h e d i f f e r e nct o l o u r sc a nb e v i e w e d t h r o u g a h device c a l l e da L I G H S T PECTROMETER. W h e nt h e w h i t el i g h tp a s s etsh r o u g ht h e s o d i u mv a p o r ,t h e a t o m so f s o d i u ma b s o r bt h e e n e r g y c o r r e s p o n d i nt og t h e o r a n g el i g h t , c a u s i nt hge e l e c t r o n isn t h e a t o mt o m o v et o a h i g h e rl e v e l . A t t h i s h i g h e rl e v e tl h e e l e c t r o ni s u n s t a b l e a n df a l l sb a c kd o w nt o a l o w e rl e v e l a , n dr a d i a t e s t h e e n e r g ya s s o c i a t ewdi t h t h e o r a n g ew a v e l e n g t h . H o w e v etrh i s r a d i a t i o no f o r a n g el i g h to c c u r si n A L Ld i r e c t i o nasn d h e n c et h e s p a c et h a t w a s p r e v i o u s loyc c u p i e db y t h e o r a n g el i g h ti n t h e V I B G Y OsRp e c t ; u ma, p p e a r sa s a d a r kr e g i o n . T h i sr e s u l t a nst p e c t r u mw h i c hi s m a d eu p o f a b r i g h t l yc o l o u r e db r i g h tb a c k g r o u n d w,i t h a d a r k b a n di n i t , i s c a l l e da n A B S O R P T I O N SpECTRUM. An AbsorptionSpectrumfor sodium T h i si s t h e r e g i o nw h e r eO R A N GsEh o u l d h a v eb e e n 205 OF MAfiER NATURE THEWAVE-PARTICLE e f f e c t i, t i s p o s s i b l teh a t s i n c ew a v e se x h i b i tp a r t i c l ep r o p e r t i eas ss e e ni n t h e P h o t o e l e c t r i c t a v ep r o p e r t i e s ' p a r t i c l essh o u l de x h i b i w e x p e r i m e n tosn E L E C T R O N E v i d e n coef t h i sW A V EN A T U R Eo f m a t t e rw a s p r o v i d e db y DIFFRACTION. f i l m o f g r a p h i t ei,t w a sf o u n dt h a t a w h e n a b e a mo f h i g hs p e e de l e c t r o n iss d i r e c t e da t a t h i n g r a p h i t ef i l m ' r i n g sw a sp r o d u c e do n a s c r e e np o s i t i o n e bd e h i n dt h e s e r i e so f d i f f r a c t i o n Electron beam ring Diffraction pattern film Graphite and by meansthat they haveWAVEproperties, Thefact that electronscanundergodiffraction, t a v ep r o p e r t i e s ' e x t e n s i o na,l l m a t t e rs h o u l de x h i b i w OnNd t h e s et w o a cn E dD I F F R A C T I a E l e c t r o m a g n e rt iacd i a t i o n( e . g .l i g h t )e x h i b i tI N T E R F E R E N w h i l et h e i n d i c a t et h a t e l e c t r o m a g n e triacd i a t i o nh a v ea W A V EN A T U R E , phenomena radiation' of electromagnetic NATURE photoelectric effectindicatesa PARTIcuLATE Lu Ea l i t yo f m a t t e r . r t c a nb e d e d u c e dt h e n ,t h a t t h e r ei s a w A V E - p A R T l c d p, the wavelengthassociated DEBrogliesuggestedthat for eachmasshavinga momentum with its momentumis givenbY: h 1- p V , t l - , , ,h- e= P l a n c k 'cso n s i a n t . 206 TUTORIAL SHEET (1) An electronis accelerated througha potentialdifferenceof 2000Vin a vacuum. Determinethe speedof the electronand its corresponding wavelength.(themassof t h e e l e c t r o ni s 9 . 1 x 1 0 - 3 1 kagn d i t s c h a r g ei s 1 . 6x 1 0 - 1 e c ) ( A n s: 2 . 6 5x 1 0 7 m s - 12;J 5 x L 0 - 1 1 m ) (2) A protonis accelerated througha potentialdifferenceV and acquiresa speedthat allowsit to havea wavelengthof 8.7 x 10-13 m. The massof the protonis 1..67x Lo-27kg and its chargeis 1.6x l_0-1ec. Determine t h e p o t e n t i adl i f f e r e n c teh a t c a u s e dt h e p r o t o n ' sa c c e l e r a t i o n : (Ans:1087V) (3) A particlehavinga chargeq is accelerated througha potentialdifferenceof 2500Vso that its speedallowsit to havea wavelength of 4.9! x !O-12m. lf the massof the particleis 4.55.xL0-30kg, determineits chargeq. (Ans8 x 10-1eC) 207 SOLUTIONS ( I ) q = ! . 6 x 1 . 0 - r s C; p . d . : 2 0 0 0 V ; m a s s - g . 1x 1 0 - 3 r k g done onthe charge is gtue:nby When a cltarge q f"saccelerated"through ap.d.V,the work of the charge. W - q V .T h i sw o r k d o n ei s e q u a lt o t h e i n c r e a s ien K i n e t i ce n e r g y h e n c e W- q' zV : 1 * u ' 1 . 6x L 0 - 1 ex 2 0 0 0- 1 * 9 . 1 . x 1 0 - 3 x1 v 2 2 2 x 1 . 6x 1 0 - 1 ex 2 0 0 0: 9 . 1 ,x 1 0 - 3 1 2.65 x 1'07ms-r (ti")Thewavelength ts f ound f rom the DeBrogltef ormulatr lL p TI P:mv ; h e n c e1 - mu 6 . 6 3x 1 0 - 3 4 9 . 1 , x 1 0 - 3 1x 2 . 6 5 x 1 0 7 2.75 x I0-11m wher t , p - m o m e n t u m ; )- tr (2) ustngthe DeBroglteequatton, Hencev : 6 . 6 3x L 0 - 3 4 lt p ILh mv' - :" mA - 4 . 5 6x L 0 s m s - 1 tSZx!0-27x8.7x10-13 s n i n c r e a s ien i t s s u e s t i o nt ,h e w o r k d o n ei n a c c e l e r a t i nt hge p r o t o nc a u s e a A si n t h e p r e v i o u q K i n e t i cE n e r g Y . t 1? 1, zmu- 2x V_ (3)1 -- t^u' - qv 1 . 6 7 x 1 . 0 - 2 7x ( 4 . 5 6 x 1 0 s ) 2 1 . . 6x L 0 - 1 e 6 . 6 3x 1 0 - 3 4 1,087V : 2.97 x L07ms-I + s s r i o - 3 0x 4 . 9 !x 1 ' o - 1 2 1 0 - 3 0x ( z . o l x 1 , 0 7 ) 2 208 : B x 1,0-1eC ATOMICSTRUCTURE E a r l yT h e o r i e o s n A t o m . iS c tructure: ( 1 ) T h o m s o nM o d e l :C a l l e d t h e p l u m - p u d d i nmgo d e l T h i sm o d e lp r o p o s e d t h a t t h e p o s i t i v ec h a r g eo f t h e a t o mw a ss p r e a do v e r t h ee n t i r e v o l u m eo f t h e s p h e r eo f t h e a t o m a n dt h e e l e c t r o nw s e r ed i s p e r s erda n d o m l yl i k ep l u m s w i t h i nt h i ss p h e r e .T h ee l e c t r o nw s e r et h o u g h t o b e i n c o n s t a nvt i b r a t i o na b o u tt h e i r f i x e dp o s i t i o n s . electron O O'O OO S p h e r eo f p o s i t i v e charge (2) The Rutherford-Bohr model: T h ee l e c t r o n os r b i tt h e p o s i t i v e lcyh a r g e dn u c l e u sl i k ep l a n e t sa r o u n dt h e s u n . 209 The Geiger-MarsdenExPeriment: NxGp e r i m e n t . T h i se x p e r i m e nits k n o w na st h e A L P H AS C A T T E R I e was directedto strikea thin sheetof ln an evacuatedmetalbox,a streamof alphaparticles s e r ed e t e c t e db y z i n cs u l p h i d es c r e e nw h i c hw a s m o u n t e da t t h e g o l df o i l . T h ea l p h ap a r t i c l ew s c r e e na t i n y f l a s ho f l i g h t e n d o f a m i c r o s c o p eW. h e na n a l p h ap a r t i c l es t r i k e st h e z i n cs u l p h i d e r f t h e k i n e t i ce n e r g yo f t h e a l p h a . h i sf l a s hi s d u et o t h e t r a n s f e o c a l l e da s c i n t i l l a t i oi ns s e e n T a n dt h e s n e n e r g yl e v e tl r a n s i t i o n p a r t i c l et o a n e l e c t r o ni n t h e z i n cs u l p h i d ew, h i c hc a u s e a emissionof a photonof light. foil Gotd P l a nv i e w screen Z i n cs u l o h i d e Metal box with alpha source P i p et o v a c u u mp u m p revealedthat whilemostof the alphaparticlespassedstraightthroughwith Theobservations 90'andeven littleor no deflection, a few were deflectedin the rangefrom 5" to approximately fewer were deflectedat anglesgreaterthan 90". increased. T h en u m b e rt h a t w a sd e f l e c t e dd, e c r e a s eadst h e a n g l eo f d e f l e c t i o n 2r0 T h e r e s u l t so f t h e e x p e r i m e ni tn d i c a t et h a t : ( 1 ) T h ea t o m c o n t a i n e d a p o s i t i v e lcyh a r g e dn u c l e u w s h i c hw a sr e s p o n s i b fl e or deflection of t h e p o s i t i v e lcyh a r g e da l p h ap a r t i c l e . ( 2 ) T h i sp o s i t i v ec h a r g ew a s c o n t a i n e di n a v e r y t i n y v o l u m eo f t h e a t o m , w h i c hw a s t h e s x p e r i e n c eadn y d e f l e c t i o n . ( t h ew r e a s o nw h y o n l yf e w a l p h ap a r t i c l e e r ea s o n l y a s m a l l p r o b a b i l i toy f t h e a l p h ap a r t i c l ec o m i n gc l o s et o t h i s p o s i t i v e lcyh a r g e dn u c l e u s . ) ( 3 ) M o s t o f t h e m a s so f t h e a t o m w a sc o n t a i n e di n t h e n u c l e u s i n c ei f t h e m a s sw a ss p r e a d o u t o v e r t h e e n t i r ea t o m a s p r o p o s e db y T h o m s o nm s ould , o s t o f t h e a l p h ap a r t i c l e w h a v es t r u c kt h i s m a s sa n dw o u l dn o t h a v eb e e na b l et o p a s st h r o u g ht h e a t o m . USEFUL TERMSIN ATOMICPHYSICS: (1) NucleonT h ew o r d n u c l e o ni s a c o l l e c t i vtee r m f o r b o t h p r o t o n sa n d n e u t r o n sA. n u c l e o ni s a particle inthe NUCLEUS. (2) AtomicnumberT h i si s t h e n u m b e ro f p r o t o n si n t h e n u c l e u sa, n d i s r e p r e s e n t ebdy t h e s y m b o l Z . ( 3 ) N e u t r o nn u m b e rT h i si s t h e n u m b e ro f n e u t r o n si n t h e n u c l e u a s n d i s r e p r e s e n t ebdy t h e s y m b o N l . ( 4 ) N u c l e o nn u m b e r T h i si st h e t o t a ln u m b e ro f N U C L E O Nl NST H EN U C L E UlSt i.s a l s oc a l l e dt h e M A S S n u m b e ra n d i s r e p r e s e n t ebdy t h e s y m b o A l . T h ef o l l o w i n gr e l a t i o ni s u s e f u l t or e m e m b e rA: - Z + N i.e.Nucleonnllmber - Number of Protons * Number of Neutrons(5) NuclideT h i si s a n a t o m c h a r a c t e r i z ebdy t h e n u m b e ro f p r o t o n sa n d n e u t r o n si n t h e n u c l e u s . T h i st e r m i s u s e di n p r e f e r e n cteo t h e w o r d " a t o m "s i n c et h e t e r m a t o m i n c l u d etsh e o r b i t a le l e c t r o n as n df o r n u c l e a P r h y s i c st h, e o r b i t a le l e c t r o nds o n o t c o m ei n t o p l a y . (6) lsotopeA n u c l i d eh a sd i f f e r e n its o t o p e isf i t c a nh a v ed i f f e r e n m t a s sn u m b e r sw h i l eh a v i n g t h e s a r n ea t o m i cn u m b e rT . h ed i f f e r e n c ien t h e m a s sn u m b e ri s d u et o t h e n u c l i d eh a v i n g d i f f e r e nn t r i u t r o nn u m b e r sE. . g . t t c ; ' Z C ; t Z C a r ei s o t o p eos f c a r b o na n d l H ; ? n ; I U a r ei s o t o p eosf h y d r o g e n . 211, OFCHARGE THEQUANTIZATION t i l l i k a ni n 1 9 1 0 w)a sd o n eb y R o b e r M T h e m e a s u r e m e notf t h e e l e m e n t a rcyh a r g e ( 1 .x61 0 - 1 s C a n dt h e e x p e r i m e ni st n o w c a l l e dt h e M i l l i k a no i l d r o pe x p e r i m e n t . T h ea r r a n g e m e notf t h e a p p a r a t ufso r t h e e x p e r i m e ni ts g i v e nb e l o w : O i ld r o p l e t s ee €€ € e A t o m i s e re . g .p e r f u m e s p r a yb o t t l e P o s i t i v e lcyh a r g e dm e t a l plate X raysfor i o n i z i n tgh e a i r mtcroscooe N e g a t i v e l yc h a r g e dm e t a l plate L i g h ts o u r c ef o r illuminating droplets . h ef i r s tp a r ti n v o l v etsh e d e t e r m i n a t i oonf t h e t e r m i n a l T h ee x p e r i m e ni ts d o n ei n t w o p a r t s T a l l o w st h e R A D I UoSf t h e d r o pt o b e d e t e r m i n e d . s p e e do f a n o i l d r o p ,w h i c ht h e n T h ec i r c u i ti s l e f t O P E Ni n i t i a l l ys o t h a t t h e m e t a l p l a t e sa r e u n c h a r g eadn dw h e nt h e a t o m i z e r f ol r c ea c t i n go n s p r a y sd r o p l e t si n t ot h e e m p t ys p a c e , t h ed r o p l e t sf a l ld u e t o t h e g r a v i t a t i o n a them S o m eo f t h e d r o p l e t sp a s st h r o u g ht h e o p e n i n gi n t h e u p p e rp l a t ea n dt h e i rm o t i o ni s t i m e d "d". w h e nt h e yf a l lt h r o u g ha d i s t a n c e T h et e r m i n a sl p e e dc a nt h e n b e f o u n df r o m 1 ) .:t # T h ev i s c o u fso r c ea c t i n go n t h e d r o p i s g i v e nb y F - 6 r c n r uw h e r eq i s a c o n s t a nat n d i s t h e v i s c o s i toy f a i r ,r i s t h e r a d i u so f t h e d r o pa n dv = t e r r n i n asl p e e dw h i c hw a sp r e v i o u s l y determined. T h e r a d i u so f t h e d r o p h a st o b e f o u n da sf o l l o w s . W h e nt h e d r o pf a l l si n a i r i t s w e i g h ti s e q u a lt o t h e v i s c o u fso r c ea c t i n gu p w a r d sh, e n c e nng - 6n4re 1. or mg = kvr where k is a constant. 212 T h ed r o pi s s p h e r i c aaln d i t sv o l u m ei s V H e n c ef r o m t h e e q u a t i c j *n , a n d m a s s =V o l u m ex d e n s i t y = p. tnrt t"f t o r = p g = 6 n 4 r v t ,h e n c er c a nb e d e t e r m i n e d . l n t h e s e c o n dp a r to f t h e e x p e r i m e n t , t hpeo w e rs u p p l yi s s w i t c h e do n a n dt h e p l a t e sb e c o m e potentialdifferencebetweenthe platesis about charged.The O n ep a r t i c u l adr r o p l e ti s s e l e c t e d a n dt h e p . d .b e t w e e nt h e p l a t e si s a d j u s t e ds o t h a t t h e t e r m i n a vl e l o c i t yo f t h e d r o p l e td e c r e a s etso a v a l u €v z . T h ev i s c o u fso r c e n o w a c t i n go n t h e d r o pi s k v 2 T h et o t a l u p w a r df o r c ei s E q+ k v zw h i l et h e d o w n w a r df o r c ei s m g . HenceEq - mg - kur; butmg : kur; HenceEq _ k(v, _ v) By varyihBE,a seriesof corresponding valuesof (v1- vz)are obtainedand a graphof E versus (vt - v2)givesa straightline with a gradientof I fror which q can be determined.Thisgraph q is only to be usedfor a particulardroplet,sinceeachdifferentmass will haveits own particularset of valuesof (v1- vz). A seriesof graphscan be drawn and the valuesof q can be compared. In all casesq will be found to be an integralmultipleof 1.Gx 10-1s C. H o wd i d t h e d r o p l e t a s c q u i r ea c h a r g e ? A n s w e rS : o m eo f t h e d r o p l e t sw e r ea b l et o g e t a c h a r g ew h e nt h e y m o v e d t h r o u g ht h e a i r , k n o c k e de l e c t r o n o s u t o f s o m eo f t h e a i r m o l e c u l easn dt h e s ef r e ee l e c t r o nw s e r et h e n , U i " i o ' a d h e r et o s o m eo f t h e o i l d r o p l e t s . H o w e v e irn o r d e rt o i n c r e a steh e n u m b e ro f c h a r g e os n t h e d r o p l e t sa n d t o f a c i l i t a t em o r e d r o p l e t sb e i n gc h a r g e dt ,h e a i r i n t h e v e s s esl h o u i db e l o N l S E Db y X - r a v s o r b y u s i n ga radioactivesourceto ionizethe air. lmportant: The air will causethe drop to experience an upthrust,howeverthe magnitudeof t h i s i s s m a l la n d c a nb e A S S U M E tDo b e n e g l i g i b l e . (vr- vr) 213 SHEET TUTORIAL ( 1 ) ( i )C a l c u l a tteh e r a d i u so f a d r o po f o i l o f d e n s i t y8 7 0 k g m -itf i t f a l l sw i t h a t e r m i n a l Nsm-2' is 1'.7gx l-O-s in air wherethe viscosity velocityof 2.88mms-t ( i i ) l ft h e d r o p h a s2 0 e l e c t r o n os n i t a n dt h e p l a t es e p a r a t i oins 4 m m ,c a l c u l a tteh e p . d .t h a t m u s tb e a p p l i e db e t w e e nt h e t w o p l a t e si f t h e d r o pi s t o b e h e l ds t a t i o n a r y . ( A n s :5 . 2 x 1 0 - 6 m6; 2 6 8 V ) y h e n i t a c q u i r efso u r e l e c t r o n s t , d r o p i s h e l ds t a t i o n a rw ( 2 ) l nt h e M i l l i k a n ' e s x p e r i m e na a n dt h e v o l t a g ea c r o s st h e p l a t e si s 2 2 5 0 V . (i) (ii) W h a t i s t h e p l a t es e p a r a t i oinf t h e r a d i u so f t h e d r o p i s 1 . 7 5x 1 0 - 6 ma n dt h e o f o i l i s9 2 0 k g m - ' . densitY w h a t m u s tb e t h e r a d i u so f a n o t h e rd r o pi f i t i s t o b e h e l ds t a t i o n a ruy n d e r t h e s a m e c o n d i t i o nas sa b o v ei f i t h a s8 e l e c t r o nas t t a c h e dt o i t ? ( A n s7 . L m m ; 2 . 2 P m ) . a l c u l a tteh e ( 3 ) E l e c t r o nasr ea c c e l e r a t ei dn a n X r a yt u b et h r o u g ha p . d .o f 8 0 0 0 V C of electrorl= 9.1 x L0-31kg, the motionof the electrons.(mass wavelengthassociafed charge=l-.6x10-1sC) 11m) ( A n s: L . 3 7x 1 0 , a s sa n d 0 . C a l c u l a tteh e m o m e n t u mm h f 3 . 6x L 0 - 1m (4) A n X r a y p h o t o nh a sa w a v e l e n g t o energyof the X raYPhoton. 1;6.14 5 . 5x 1o-16J; x 1 0 - 3 3 k; g A n s . (1 , . 8 4 x1 0 - 2 a k g m s Ca . l c u l a tteh e m i n i m u mp o t e n t i a l ( 5 ) T h e K o Xr a y sh a v ea w a v e l e n g t oh f 6 . 8 8x L O - 1 0 m differenceacrossan X raytube that will producetheseX rays' W h a t i s t h e e n e r g yo f t h e X r a y p h o t o n si n e V ? (Ans:1,807V; 1807eV) s e a ta t ( 6 ) A n X - r a y t u b e i s o p e r a t e do n a d . cp o t e n t i adl i f f e r e n c e ' o3f8 0 0 0 Va, n d p r o d u c e h a rate of 660w. lf only 0.4%of the energyof the incidentelectronsis convertedto X r a y s c, a l c u l a t e : (i) T h e r a t ea t w h i c he l e c t r o n s t r i k et h e t a r g e t ' (ii) T h es p e e do f t h e i n c i d e net l e c t r o n s s e r s e c o n d; 1 . 1 8x l - 0 8 m s - 1 ) 7 l e c t r o np ( A n s : 1 . 0x91 0 1 e heat is generatedin the (7) An x ray tube operatesat a potentialdifferenceof 55000V,and of the energyof the electronsis what percentage target at a rrte of 85OW.Determine t o X r a y si f t h e c u r r e n ti n t h e X r a y t u b ei s 0 . 0 1 8 A(. A n st 4 % ) converted 214 SOLUTIONS (1) At Termtnalveloci,ty,theviscousForce - wetght of drop VtscousForceF - 6rnrv,the drop ts a spherei"tsmass- vol x densi.ty. V o l u m eo f s p h e r e- ! o r = , Hence 6m7rv ' 3 -!nr= , IBrTv l - a l pg 1 8 x 1 . 7 9x 1 0 - sx 0 . 0 0 2 8 8 - 5.2 x 1,0-6m 4 x 8 7 0x 9 . 8 1 +pg (ti")lf the drop i"sheld stati,on&ry,then the electrf.cf orce acttng upward"s, would be equal to the wei"ght Hence mg = Eq where E f"sthe Electric f teld strength Vq mqd . E_V ms-7; v -; 7; V_ 1"" psd ! r c 6 . 2 x 1 0 - 6 ) 3x 8 7 0x 9 . 8 1x 0 . 0 0 4: 20x1,.6x10-1e 6268V (2) When the drop f"sstattonary,wei.gltt(acti.ngdown) - Electri"c orce(acting up) f h e n c e m g : E qo r m g - r y t u d-Y- 2250x6'4x\o-Ie - m " LAa + //^ 2ftQ.75 -7.Lx!o-3m x 1 0 - 6 ) 3x 9 2 0 x 9 . 8 1 ( i " i ) C h a r g e- B x 1. 6 x ! } - l e , p l a t e s e p a r a t i o n : 7 . t x L 0 - 3 m i p . d . mg Vq 4 g d ' 1 o ' =P Vq d' 2 2 5 0x B x 1 , . 6 xL 0 - 1 ex 3 : 2.2 x L0-6 m 4 x 7 . 1 x 1 0 - 3x n x 9 2 0 x 9 . 8 1 215 2250V (3)Work done on electron - Increase tn i,tsKE h e n c eq V : 1, r*u, mornentumP: mv and 1- (4) 1- 2 x I . 6 x 1 0 - 1 ex 8 0 0 0 ;v - h mv 6 . 6 3x 1 0 - 3 4 9 . 1 x, 1 0 - 3 1x 5 . 3 x 1 0 7 mv : L.37 x't0-11m 6.63 x 1,0-34 - 1 . 8x ! 0 - 2 a k g m s - 1 3 . 6x 1 0 - 1 0 mv * Momentum - mass x speed, (ir)mass - : 5,3 x 107ms-I 9 . 1x l - 0 - 3 1 hence ma"ss- 1 . 8x ! 0 - 2 4 - momentum speed(of ltght) 6 . 1 4x 1 0 - 3 3 k g 3x 108 hc 6 . 6 3 x 1 0 - 3 a x 3 x 1 0 B : 5.5 x 1,0-16J (iii)Energy of a photon 1 3 . 6x 1 0 - 1 0 (S)TheEnergy of the X - rays would have come fromthe work d"onei"naccelerattng the electrons that produce them. Itc The energy of an X ray photon U : T ' The work done tn accelerattna the electron - q V henceqV:;i Itc 1 ' V: hc 6 . 6 3x 1 0 - 3 4x 3 x L O B ": qA 1 . 6 x 1 - 0 - 1 xe 6 . 8 8x L 0 - 1 0 : 1807V T h ec h a r g eo f a n e l e c t r o ni s e a n dt h e p . d .a c r o s si t i s 1 8 0 7 Vh, e n c et h e e n e r g ys u p p l i e d to the electronis 1807eV. 2r6 (6) 4o/oconverted"to X ray meqns that 99.6%Power conv'erted.to heat .Hence 660W - 99.60/o of totat power suppti.ed" : Totalpowersuppli"ed ffi - 66ZrSW Totalpower - (number of electrons per second) x (Energy of 1,electron) 6625W - number of electrons per second x qV number of electrons per second : ( i i , )q v - ) ^ u ' ;v - 662.65 I . 6 x 1 0 - 1 ex 3 8 0 0 0 2qv 2 x 1 . 6 x 1 0 - 1 ex 3 8 0 0 0 - m 9 . 1x 1 - 0 - 3 1 : 1 . 0 9x 1 0 1 7 1 . 1 5x L 0 8 m s - 1 ( 7 ) P o w e r s u p p l t e dP - V I - 5 5 0 0 0 x 0 . 0 1 8- 9 9 0 W Power lost to heattng : 850W, Hence Power avai"lablef or Xray production - 990W - BS\W _ 'J.40W Percentage of power used"f or Xray prod"ucti.on- Y x I00o/o990 217 L4o/o VIASSDEFECT AND BINDINGENERGY ble,i.e.Masscanbe showsthat massand energyare interchangea theorvof Relativity Einstein,s convertedinto energy,and energycan be convertedinto mass' by a releaseof is accompanied a decreasein massAm,this decrease When particlesexperlence an amountof energyAE. The equationrelatingmassand Energyis AE = Amcz WhereE is the energyin Joules,M is the massin kg and C = 3x 108ms-1 with 1 aswell asthe Energyassociated Thiseouationallowsthe massof a Jouleto be calculated kg to be calculated. E.g(1) Findthe massof l loule: L e t A E= l J o u l e ; L = A m c 2 . H e n c e/ m : ; = ,' .,;|ry = 1 . 1 1x L o - l 7 k s with the changein massof 1kg. 2) Findthe energyassociated ' A E= 1 x c 2= 1 x ( 3 x 1 0 8 ) ' z9=x 1 0 1 6 J . THEATOMICMASSUNIT: r h y s i ciss t h e U n i f i e dA t o m i cM a s sU n i t , A v e r yu s e f u u l n i t o f m a s sa n d e n e r g yi n N u c l e aP 'u'. which is alsocalledthe atomicmassunit and abbreviated T h ea t o m i cm a s su n i t i s d e f i n e da s o n et w e l f t ho f t h e m a s so f t h e c a r b o na t o m 'ZC. I n a m o l eo f c a r b o nt,h e r ea r e 6 . 0 2x 1 0 2 3a t o m sa n dt h e m a s so f 1 m o l ei s L 2 9 . Hencethemassof1carbonatom''ffie=ffikg_12u;Hence 12 Lu: - L.66 xl0-27kg. ffikg S i n c e1 l < g= 9 x l - 0 1 6 ia, n d 1 M e V = l - ' 6 x L 0 - 1 3 J 1 ' 6 6 x L O - 2 7x 9 x 1 0 1 6 t- l'L - r-6x10-13 21.8 -93LMev R e c a l:l T h ep r o t o n sa n d n e u t r o n si n t h e n u c l e u sa r ec o l l e c t i v e l y r e f e r r e dt o a s n u c l e o n s T h ee n e r g y t h a m t u s tb e s u p p l i e dt o t h e n u c l e u tso c o m p l e t e l y s e p a r a t teh e nvuvc'lsevuJsi n t o i t s "'l'| i n d i v i d u anlu c l e o n si ,s c a l l e dt h e B I N D I N G E N E R Goyf t h e n u c l e u s . A c c o r d i ntgo E i n s t e i n 'm s a s s -e n e r g yr e l a t i o n s h i p i f ,e n e r g yi s s u p p l i e d t o t h e n u c l e u st ,h e n w h e nt h e i n d i v i d u anl u c l e o n as r es e p a r a t e dt h, e t o t a l m a s sw o u l di n c r e a s ei ..e i f e n e r g yi s added,then this energyis convertedinto extramass. T h i sm e a n st h a t t h e s u mo f t h e m a s s e o s f t h e i n d i vei vdvu' a'In'lvu c l e o niss g r e a t e tr h a nt h e m a s so f the nucleus. T h eB I N D I N G E N E R GcYa nt h e r e f o r e a l s obe definedasthe ToTALenergythat is reteased when t h e i n d i v i d u anl u c t e o ncso r n et o g e t h e rt o f o r m t h e nucleus. T h ed i f f e r e n c ien m a s sb e t w e e nt h e s u mo f t h e m a s s e s o f t h e i n d i v i d u anl u c l e o n as n d t h e m a s s o f t h e n u c l e u si s c a i l e dt h e M A S SD E F E C T . = (sum of massesof Nucleons (Mass MAss DEFECT of Nucleus) )T h eb i n d i n ge n e r g yi s t h e e n e r g ya s s o c i a t ewith d the Binding Energ! massdefect,hence : mqss def ect x (3 x 108)2 Example: C a l c u l a tteh e b i n d i n ge n e r g ya n dt h e m a s sd e f e c tf o r t h e h e l i u mn u c l e u s . s y m b o fl o r h e l i u mn u c l e su i s l H e ; t h e n u c l e o n u m b e ri s 4 a n dt h e p r o t o nn u m b e ri s 2 . H e n c e i t h a s2 p r o t o n sa n d 2 n e u t r o n s . T h em a s so f a p r o t o ni s 1 ' 0 0 7 3 ua n dt h e m a s so f a n e u t r o n is1.00g7u. T h et o t a l m a s so f t h e i n d i v i d u anl u c l e o n iss e q u a l t o( m a s so f 2 p r o t o n s+) ( m a s so f 2 n e u t r o n s ) T o t a lm a s s= ( 2 x 1 . 0 0 7 3 u+) ( Z x 1 . 0 O g 7 u=)4 . 0 3 2 0 u T h eh e l i u mn u c l e u si s f o u n dt o h a v ea m a s so f 4 . 0 0 1 5 u . T h eM A S SD E F E Ci sTt h e r e f o r e4 . 0 3 2 0u - 4 . 0 0 1 5 u= 0 . 0 3 0 5 u . R e c a ltih a t L u h a sd F € : Q u i v a l e netn e r g yo f 9 3 1 M e V ,h e n c eo . 0 3 0 5 uw i l l h a v ea n e n e r g y €eu,''.,alence of 0.0305x 931MeV= 28.4MeV. 2t9 OFTHENUCLEUS STABILITY Nh. eg r e a t etrh e GN E R GpYe r N U C L E O T T h eS t a b i l i toyf a n u c l e u iss d e t e r m i n e bd y i t s B I N D I N E d sf o l l o w s : r i l l b e t h e s t a b i l i t yT. h i sc a nb e e x p l a i n e a b i n d i n ge n e r g yp e r n u c l e o nt,h e g r e a t e w s i l l h a v et h e g r e a t e sst t a b i l i t ya, n d b o d i e st e n d , o d i e st h a t h a v et h e l o w e s te n e r g i ew In natureb t o l o s ee n e r g yi n o r d e rt o i n c r e a steh e i rs t a b i l i t y . formed l n t h e a t o m ,t h e n u c l e o n cs o n g r e g a tteo f o r m t h e n u c l e u sa n d i n d o i n gs o ,t h e n u c l e u s g i v e su p s o m ee n e r g yt o a t t a i ns o m es t a b i l i t yT. h en u c l e ti h a t g i v eu p t h e m o s te n e r g y ,a r et h e m o s ts t a b l eo n e s . H e n c et h e e l e m e n t st h a t h a v et h e g r e a t e sbt i n d i n ge n e r g yp e r n u c l e o nw i l l h a v et h e m o s t s t a b l en u c l e i . t a s sn u m b e r t, h e f o l l o w i n g W h e na g r a p ho f B i n d i n gE n e i g yp e r n u c l e o ni s p l o t t e da g a i n sm s h a p ei s o b t a i n e d : B i n d i n ge n e r g y p e rn u c l e o n 238 56 M a s sn u m b e r t eh a st h e h i g h e sbt i n d i n ge n e r g yp e r n u c l e o na n di s T h eg r a p hs h o w st h a t t h e e l e m e n F t h e r e f o r et h e m o s ts t a b l e . that L i g h t eer l e m e n t s u c ha s H y d r o g e nh, e l i u m , A,l L i , e t c .a l l h a v em a s sn u m b e r sl o w e r t h a n c an T h e y p e r o f F e ,a n d a c c o r d i ntgo t h e g r a p h t, h e yw i l l h a v el o w e rb i n d i n ge n e r g i e s n u c l e o n . i n c r e a steh e i rb i n d i n ge n e r g i epse r n u c l e o nb y i n c r e a s i nt hg e i rm a s sn u m b e rc l o s etro 5 6 ,a n d f o r t h i st o h a p p e nt,h e ym u s tu n d e r g oF U S I O N ' 220 Elements with massnumbersgreaterthan 56 for exampleUranium,havebindingenergiesper nucleonlessthan that of Fe,and in orderfor elementssuchastheseto becomgmorestable(by increasing their bindingenergyper nucleon), they mustdecrease their massnumberto a varue closerto 56.Thiscanhappenif the elementundergoes FISSION. In FUsloN,two lightnucleiarefusedto form a heavierone with the releaseof bindingenergy. In FlssloN,a heavynucleusis splitinto two fragmentsof approximately equalmass,with the releaseof bindingenergy. In the both FISSION and FUSIONas well as all other nuclearprocessesthere is conservationof AtL of the following quantities: NUCLEONNUMBER,PROTONNUMBER, ENERGY-MASS and CHARGE. Example: Findthe energyreleasedwhen a Poloniumnuclideemitsan alphaparticle. tt|po -+ 23tpb+ lHe + E T h em a s s eos f t h e v a r i o u sn u c l i d easr eg i v e na sf o l l o w s : L e a d' | u r p a- 2 0 5 . 9 6 9 u ; q p a r t i c l e | H e - 4 . 0 0 4 u , p o l o n t u m z [ o n p-o z 0 g . 9 8 2 u T h eT o t a lm a s so n t h e l e f t s i d eo f t h e e q u a t i o ni s 2 0 9 . 9 g 2 u Thetotal masson the rightsideis (205.969+ 4.004)u= 209.973u Thereis a massdefecton the rightsideof (209.982- 209.973)u = 0.009u A n E N E R GTYE R Mm u s tb e i n c l u d e od n t h e r i g h ts i d es o t h a t i t s m a s se q u i v a l e n cweh e na d d e d t o t h e o t h e rm a s s e o s n t h e r i g h ts i d eo f t h e e q u a t i o nw, i l l b e e q u a lt o t h e m a s so n t h e l e f ts i d e of theequation Q u e s t i o n: W h e na n a l p h ap a r t i c l es t r i k e sa n i t r o g e nn u c l e u st ,h e f o l l o w i n gN U C L E ArR e a c t i o no c c u r s : l u e + ' \ w - , 1 $ o+ \ n B yc o n s i d e r i ntgh e r e s tm a s s e o s f t h e p a r t i c l egs i v e nb e l o w ,d e t e r m i n et h e K Ea n ds p e e dt h a t t h e a l p h ap a r t i c l em u s th a v ei n o r d e rt o e f f e c t h e r e a c t i o n . . M a s s o f H e = 4 . 0 0 2 : t 0mua; s s o f N = 1 4 . 0 0 3 0 7 u ; m a s s o f H = 1 . 0 0 7 8 3 u ; m a s s o f O = 1 6 . 9 9 9 1 3 u \''l-,:ts of Alphaparticle= 4 x 1.66xtO 27kg; ( A n s: 1 , . 9 2 x L O - 1 ;37J. 6 x l - 0 6 m s - 1 ) 221, RADIOACTIVITY process. R a d i o a c t i v iitsya S P O N T A N E OaUnSd R A N D O M s i l ld i s i n t e g r a t e I t i s S p o n t a n e o ubse c a u s teh e r ea r e n o i n d i c a t o rasst o w h e n a n u c l e u w t h i c hp a r t i c u l aar t o m sw i l l u n d e r g or a d i o a c t i v e I t i s R a n d o mb e c a u s iet i s i m p o s s i b lteo p r e d i c w decay. Therearetwo factorsthat affectnuclearstability: (i) (ii) p e r n u c l e o nt,h e T h e b i n d i n ge n e r g yP e r n u c l e o n -T h e g r e a t e rt h e b i n d i n ge n e r g y g r e a t e ri s t h e s t a b i l i t Y . and t[O tfre ratio is ]-. as 12uC i T h en e u t r o n -p r o t o nr a t i o .F o rl i g h tS T A B LnEu c l e such F o rh e a v yn u c l e it,h e r a t i oi n c r e a s et so w a r d sl - ' 6 ' i i t h a h i g h e rs t a b i l i t yT' h e i i l l s p o n t a n e o u sdl ye c o m p o steo f o r m n u c l e w a t o m i cn u c l ew Unstable s h i c ha r e r e l e a s e d . ee n e r g ya n d p a r t i c l ew d e c o m p o s i t i opnr o c e s iss c a l l e dr a d i o a c t i v i tTy h . h e nu n s t a b l en u c l e di e c o m p o s ien d u r i n gt h e d e c o m p o s i t i opn[ o c e s sa r ec a l l e dr a d i a t i o nW y .h e nt h e u n s t a b l en u c l e ai r e n a t u r et,h e p r o c e s iss r e f e r r e dt o a s n a t u r a rl a d i o a c t i v i tW p r e p a r e di n t h e l a b o r a t o r yt h, e d e c o m p o s i t i oi snc a l l e di n d u c e dr a d i o a c t i v i t y . '. T h e r ea r et h r e em a j o rt y p e so f n a t u r a rl a d i a t i o n 1. nlpha Radiation A l p h ar a d i a t i o nc o n s i s tos f a s t r e a mo f p o s i t i v e lcyh a r g e dp a r t i c l e sc,a l l e da l p h a p a r t i c l e sw, h i c hh a v ea n a t o m i cm a s so f 4 a n da c h a r g eo f + 2 ( a h e l i u mn u c l e u s ) . i s e j e c t e df r o m a n u c l e u st h, e m a s sn u m b e r o ft h e n u c l e u s W h e na n a l p h ap a r t i c l e d e c r e a s ebsy f o u r u n i t sa n dt h e a t o m i cn u m b e rd e c r e a s ebsy t w o u n i t s .F o r example: z l f t fn ; T h e h e l i u mn u c l e u si s t h e a l p h ap a r t i c l e . , 3 3 U|lle + , h i c hw o u l dc a u s e A l p h ap a r t i c l ee m i s s i o no c c u r sw h e nt h e n u c l e u sh a st o o m u c hp r o t o n sw causes p a r t i c l ee m i s s i o n t h e n e u t r o n -p r o t o nr a t i ot o b e t o o s m a l fl o r h e a v yn u c l e iT. h ea l p h a b v 2 ' d e c r e a s e t h e p r o t o nn u m b e r t od e c r e a sbey 2 a n da l s o t h en e u t r o nn u m b e r t o 2 3 r l Ut s ' f f - 1'587 F r o mt h e a b o v ee x a m p l et,h e n e u t r o n -p r o t o nr a t i o no f - r ' 6 , h e n c et h e a l p h ad e c a yc a u s e dt h e 2l[rn tt'# T h en e u t r o n -p r o t o nr a t i oo r n e u t r o n- p r o t o nr a t i ot o i n c r e a steo w a r d sL . 6w h i c hm e a n sa n i n c r e a s ien s t a b i l i t y . 222 (21 B e t aR a d i a t i o n, w h i c hh a st w o t y p e si . e .p a n d g * e m i s s i o n s . (i) B e t a . ( m i n u rsa) d i a t i o ni s a s t r e a mo f e l e c t r o n sc,a l l e dp p a r t i c l e s . W h e na beta particleis ejected,a neutronin the nucleusis converted to a proton,so t h e m a s sn u m b e ro f t h e n u c l e u si s u n c h a n g e db,u t t h e a t o m i c number , n c r e a s ebsy o n e u n i t .F o re x a m p l e : , 2llra;The e r e c t r o ni s t h e b e t a ( m i n u sp)a r t i c r e . 33rn - -?e + T h i so c c u r sw h e nt h e n u c l e u sh a st o o m a n yn e u t r o n sf o r s t a b i l i t y a n dt h e n e u t r o n protonratio is decreased by F-emission ( i i ) 9 * e m i s s i o nw h e r e t h ep * p a r t i c l ei s c a l l e da p o s l T R o N w h i c hi s e f f e c t i v e l y a p o s i t i v ee l e c t r o nI.n t h i s p r o c e s sa, p r o t o nc h a n g e isn t o a neutron. s c c u r sw h e nt h e n u c l e u si s d e f i c i e nitn n e u t r o n s . T h i sp r o c e s o tu -[n+le I t i s s o m e t i m e cs o n v e n i e nt to a s s u m et h a t a n e u t r o ni s m a d e u p o f a p r o t o na n d a n electroncombinedtogether,and when p-emissionoccurs, it is the electronfrom t h e n e u t r o nt h a t i s e j e c t e dl,e a v i n gb e h i n da p r o t o n .H o w e v e r t h i s a s s u m p t i oins incorrect. l n i t i a l l yi t w a sp r o p o s e d t h a t t h e n e u t r o ni s r e a l l ym a d eu p o f s i xe l e c t r o nas r r a n g e d s o t h a t t h e i re l e c t r i cf i e l d sc a n c eel a c ho t h e r ,w h i l ea p r o t o n a l s oh a sa s i m i l a r a r r a n g e m e notf t h e s i xe l e c t r o n b s u t w i t h a p o s i t r o na t t h e c e n t r eo f t h e a r r a n g e m e nH t . o w e v e trh e d i s c o v e royf t h e s u b - a t o m ipc a r t i c t e c a l l e dt h e q u a r k h a sl e dt o t h e d o w n f a lol f t h i se a r l i e rp r o p o s a T l . h en e u t r o ni s n o w t h o u g h t o b e composed o f 3 q u a r k s . E x p e r i m e ndtaatlah a ss h o w nt h a t t h e n e u t r o nh a s a negative chargeboth in its innercoreand its outer edgewith a positive . chargesandwiched i n t o m a k et h e p a r t i c r e r e c t r i c a inl ye u t r a r . (3) GammaRadiation Gammaraysare high-energy photonswith a veryshortwavelength(0.0005to 0.1 nm)' Theemissionof gammaradiationresultsfrom dn energv changeof electrons w i t h i n t h e a t o m i cn u c l e u sG - a m m ae m i s s i o cn h a n g e ns e i t h r et h r e a t o m i cn u m b e r n o r t h e a t o m i cm a s sA . l p h aa n d b e t ae m i s s i o n a r eo f t e na c c o m p a n i e d ' b g ya m m a e m i s s i o na,sa n e x c i t e de l e c t r o ni n t h e n u c l e u sd,r o p s t oa l o w e r a n d m o r es t a b l e energystate. A l p h a ,b e t a ,a n dg a m m ar a d i a t i o na l s oa c c o m p a niyn d u c e dr a d i o a c t i v i t y . R a d i o a c t i vi seo t o p e s a r e p r e p a r e di n t h e l a b u s i n gb o m b a r d m e nrte a c t i o ntso c o n v e r t a s t a b l en u c l e u si n t oo n e whichis radioactive. Positron(particlewith the samemassas an electron,but a charge of +1 i n s t e a do f - 1 ) e m i s s i o n i s n ' to b s e r v e di n n a t u r a rl a d i o a c t i v i tby u , t i t i s a c o m m o nm o d eo f d e c a y in inducedradioactivity. Bombardment reactions can be usedto produceveryheavyelements, i n c l u d i nm g a n yw h i c hd o n ' to c c u ri n n a t u r e . 223 ACTIVITY s i l l d e c a y b, u t i f a s a m p l ec o n t a i n sN t h e n a p a r t i c u l anr u c l e u w I t i s i m p o s s i b lteo p r e d i c w g i v e nb y n u c l e it,h e n t h e r a t eo f d e c a yc a l l e dt h e A C T-IdVt I TiYs p r o p o r t i o n at ol N w h i c hi s A= dt x N. t h a t a st i m e i n c r e a s etsh, e v a l u eo f s i g nt o i n d i c a t e T h e r a t eo f d e c a yi s g i v e na n e g a t i v e decreases. T h ep r o p o r t i o n a l i st yi g nc a nb e r e m o v e dt o g i v et h e g e n e r ael q u a t i o n : -dN = iN= A N I dt . a su n i t so f ( t i m e ) - ' I OONN S T A NlTt h Y O N S T A NoTr D I S I N T E G R A TC W h e r e . tirs c a l l e dt h e D E C A C will u lar nucl d as the probabil is Y CONSTANT The radioactivedecavat anv giventime. i n a s a m p l ea f t e r T h ee q u a t i o nc a nb e r e a r r a r l g et do d e t e r m i n et h e n u m b e ro f n u c l e ri e m a i n i n g s o m et i m e t , a n dt h e g e n e r ael x p r e s s i ofno r t h i s i s N - No e - A t sinceActivitYAo(N Similarly A - Aos-At l c t i v i t yo f t h e i r e s e n (t a tt = 0 ) , a n dA o i st h e i n i t i a A w h e r eN oi s t h e i n i t i a ln u m b e ro f n u c l e p s am p l e . RATEand is measuredin the numberof ORDECAY TheActivityis alsocalledthe coUNT RATE, disintegration Pse rs e c o n d . o n e d i s i n t e g r a t i opne r s e c o n di s c a l l e da B e c q u e r e( lB q ) . 224 H A L FL I F E . T h eh a l fl i f eo f a s a m p l ei s t h e t i m e t a k e nf o r b o t h t h e A c t i v i t yo f t h e s a m p l ea n dt h e n u m b e ro f r a d i o a c t i vneu c l eti o f a l lt o h a l fo f t h e i n i t i a vl a l u e . l e a t h a l fl i f eN s ) f a n dA s ) + . l f t h e s er e l a t i o n a s r e s u b s t i t u t e idn t h e p r e v i o u e s q u a t i o ntsh e n ; A t t = T r / r , * = T , h e n c e b y s u b s t i t u t i n g N = f i n t h e e q u a t i o n w i t h A- / N s e - t t , w e g e t : :-u - N69-AT112 z B ye l i m i n a t i n N g ow e g e t ; t 2 ,-ATr/z T a k i n gl o g sg i v e s- l n Z - -7Ttr OR /2 LEARN A very usefulequation to learnis : TL r1t A _ or\z) where n is the number of half ltves si.mi.tarlyN"r(;)" No The graphto the left represents the v a r i a t i o no f t h e n u m b e ro f a c t i v e n u c l ew i i t ht i m e . I t i s a l s oa r e p r e s e n t a t i oonf t h e v a r i a t i o no f t h e A c t i v i t yw i t h t i m e , i n w h i c hc a s et h e N 6o f l t h e y - a x i s ,c a n No b e r e p l a c e dw i t h 4 6 . 1 No 4 A/o a I 2Ttr T t^ ,/ 2 /2 22s 3Ttr /2 SOMEPROPERTIES OF RADIOACTIVE EMISSIONS ALPHAPARTICLES: ( 1 ) A l p h ap a r t i c l easr eh e l i u mn u c l e i . (2) Theyhavea chargeof +2e (2 x L.6x10-1eC1. ( 3 ) F r o ma n yp a r t i c u l asra m p l et,h e a l p h ap a r t i c l eas r ee j e c t e dw i t h a p p r o x i m a t etl hy e s a m e velocity. ( a ) T h ee n e r g i e os f a l p h ap a r t i c l e rsa n g ef r o m 4 M e Vt o 8 M e V ,a n dt h e r a n g ei n a i r i s a b o u t 8cm. (5) Theyare deflectedby both magneticand electricfields. ( 6 ) A l p h ap a r t i c l eas r et o t a l l ya b s o r b e db y a t h i c ks h e e to f p a p e ra sw e l l a s b y h u m a ns k i n . ( 7 ) C a u s es i g n i f i c a ni ot n i z a t i o dn u et o i t s r e l a t i v e llya r g em a s sa n ds i z e -t h e y h a v ea h i g h p r o b a b i l i toy f c o l l i d i n g w i t h g a sm o l e c u l easn d k n o c k i n o g f f e l e c t r o n sa,st h e i r m o m e n t u mc a u s et h e m t o k e e po n t r a v e l l i n a g f t e ri t s f i r s tf e w c o l l i s i o n s . Beta Particles: (1) A beta (-) particlei, .n electron (2) Theyare ejectedfrom a samplewith a rangeof speedsfrom about0.2 timesthe speed o f l i g h tt o a b o u t0 . 8t i m e st h e s p e e do f l i g h t . ( 3 ) T h e ya r e m u c hm o r ep e n e t r a t i ntgh a n a l p h ap a r t i c l eas n d c a nb e s t o p p e db y a b o u t 3 m mo f a l u m i n i u m . ( a ) T h er a n g ei n a i r i s f r o m a b o u t1 0 c m t o a b o u t1 0 0 c m . ( 5 ) T h e yc a u s es i g n i f i c a n tlley s si o n i z a t i otnh a n a l p h ap a r t i c l eds u et o t h e i rs m a l lm a s s t-h e y h a v e a m u c hs m a l l e p r r o b a b i l i toy f c o l l i d i n w g i t h g a sm o l e c u l e s . (6) Theyare deflectedby both electricand magneticfieldsin directionsoppositeto thoseof a l p h ap a r t i c l e sT.h e i rm a s s e as r e a b o u t7 0 0 0t i m e sl e s st h a n t h a t o f a l p h ap a r t i c l e sa,n d hencethey experience muchgreaterdeflections. GammaRays: (1) Theyare not particlesbut insteadthey are electromagnetic wavesof very highenergy. (2) Theytravelat the speedof light. (3) Theyare muchmore penetrating than beta particlesand canpenetratea few metresof concrete.Theycanbe stoppedby a wall of leadthat is at least10cmthick. ( a ) T h e r a n g ei n a i r i s u p t o s e v e r ahl u n d r e dk i l o m e t e r s . ( 5 ) T h e yc a u s ev e r yl i t t l ei o n i z a t i o on f g a sm o l e c u l e s . (6) Theyare deflectedby neitherelectricnor magneticfields. 226 EXPERIMENT TO DISTINGUISH BETWEEN THETHREE TYPES OF RADIATION: sincethe 3 typesof rad.iation havedifferentpenetratingpowers,then this property can be incorporated in an experimentto distinguish betweeneachtype. A n a r r a n g e m e notf t h e a p p a r a t uiss g i v e nb e l o w : C{ 88 A l u m in u m A G e i g eM r u l l e rt u b e i s p t a c e db e h i n de a c hb a r r i e (r G M t , G M z , G M :G , M+). F o ra l l r a d i o a c t i vm e e a s u r e m e n ttsh,e B A C K G R o u NcDo u N T R A T Ei s f i r s tm e a s u r e da,n dt h i s i s t h e n s u b t r a c t efdr o m a l l s u b s e q u e nr te a d i n g s . l f t h e G M r g i v e so n l yt h e v a l u eo f t h e b a c k g r o u ncdo u n t r a t e ,t h e n t h e s a m p l ew o u l dh a v eh a d o n l ya l p h ap a r t i c l e s . l f h o w e v e rt,h e r e a d i n go n G M 1i s g r e a t e tr h a n , t h eb a c k g r o u n d r a t et h e n t h e r ew o u l db e p a r t i c l eps a s s i n tgh r o u g ht h e t i s s u ew h i c hw o u l d b e e i t h e rb e t ap a r t i c l eos r g a m m ar a y so r b o t h 'T h er e a d i n gos n G M za n d G M : w i l l a l l o wt h e o b s e r v e r t o d e t e r m i n et h e n a t u r eo f t h e e m i s s i o ntsh a t a r e n o t a l p h a . 227 from T h ed e f l e c t i o nisn e l e c t r i ca n d m a g n e t i fci e l d sa l s oa l l o wt h e e m i s s i o ntso b e d i s t i n g u i s h e d o n ea n o t h e r : Alpha, Beta,and Gamma Historically,,the productsof radioactivitlzwere called alpha,beta,and gammawhen it was found thatthey couldbL analyzedinto threedistinctspeciesby eithera magneticfield or an electric field. XXXX tx X X x Y X XXXI fie1r1 1"1;:r1rrtti': XXX ij1,,;i3U f t-r:rTft X ',,"igr,',r;:1- XX + + + + + + I I I I - FX :;riflt trlE FiArlir:r;:r.:ti.',"E . i n I *id trlirr::l:: 228 EXPERIMENT TO DETERMINE THEHALFLIFEOFA RADIOACTIVE ISOTOPE WITHA SHORTHALFLIFE: T h eh a l fl i f ec a nb e m e a s u r e d by monitoring t h e i o n i z a t i o cnu r r e n tp r o d u c e db y t h e s a m p l eo f r a d i o a c t i vm e aterial. A t y p i c a sl a m p l et h a t i s u s e di n t h e l a b o r a t o riys R a d o ng a s . Centra I e l e c t r o d e valves 1-2Vbattery m i c r o am m e t e r d . c .a m p l i f i e r Polythene bottle R= 1011e w i t h r a d o ng a s T h ev a l v e sa r es e tt o t h e o p e np o s i t i o na n dt h e p o l y t h e n eb o t t l e i s s q u e e z etdo f o r c es o m e r a d o ng a si n t ot h e i o n i z a t i o cnh a m b e rm ( e t a lc a n ), a n dt h e v a l v e sa r et h e n c l o s e d . T h ec u r r e n to n t h e a m m e t e ri s r e c o r d e da n d a s t o p w a t c hi s started. R e a d i n gosf c u r r e n ta r e r e c o r d e da t e v e r y1 0 s e c o n dfso r a p e r i o d o f a b o u t5 m i n u t e s . 229 A graphof currentversus timeis plottedanda smoothcurveis drawnthroughthe points. T h ev a l u eos f I o ; 2 , ? t a n df r o mt h et h r e el a t t e rv a l u e st,h e h a l fl i f ec a nb e f o u n di n e a c h f, c a s ea, n dt h ea v e r a gvea l u et h e nc a l c u l a t e d . 16 ! 2 ------'l r! I I I 4 ---t- rI 0 I I B .l Trr /2 2Ttr /2 230 3Ttr /2 SAFETYPRECAUTIONS FOR HANDLINGAND DISPOSALOF RADIOACTIVE MATERIAL S i n c ea l p h aa n d b e t ap a r t i c l e d s o n o t p e n e t r a t et h e s k i nt h e y a r e u n l i k e l yt o b e h a r m f u fl r o m E X T E R N A L S O U R C Ei .Se .f r o m s o u r c e so u t s i d eo f t h e h u m a nb o d y . T h e yw i l l h o w e v e rp o s ea s e r i o u st h r e a ti f t h e y a r e i n g e s t e do r i n h a l e d . Personh s a n d l i n gr a d i o a c t i vm e a t e r i a l sm u s tn o t e a t s m o k eo r d r i n ki n t h e v i c i n i t yo f t h e r a d i o a c t i v e s a m p l e sM ' a s k sa s w e l l a s d i s p o s a b lgel o v e sa n d p r o t e c t i v ec l o t h i n gs h o u l db e w o r n . I n t h e c a s eo f X r a y sa n d g a m m ar a y s ,p e r s o n sm u s tb e s h i e l d e dt,h e r em u s tb e a l a r g ed i s t a n c eb e t w e e n t h e p e r s o na n d t h e s o u r c ea, n d e x p o s u r et i m e sm u s tb e a s s h o r ta s p o s s i b l e . P e r s o nw s o r k i n gi n r a d i o a c t i vaer e a ss h o u l dw e a r a F I L MB A D G Ew h i c hd a r k e n sa s i t i s e x p o s e dt o r a d i a t i o nT. h e d a r k n e s o s f t h e f i l m g i v e sa n i n d i c a t i o n o f t h e e x p o s u r et i m e . l n t h e c a s eo f r a d i o t h e r a payn d d i a g n o s i st h, e i s o t o p et h a t i s c h o s e nm u s t h a v ea s h o r th a l f l i f ea sw e l l a s i t m u s tp a s st h r o u g ht h e b o d ya n d b e e x c r e t e do u t i n a v e r ys h o r tt i m e . W o r k e r sm a y a l s oh a n d l er a d i o a c t i vm e a t e r i a l sb y u s i n gr e m o t ec o n t r o l l e dt o o l s . RADIOACTIVE WASTE RadioactiveWaste Description R a d i o a c t i vwea s t ec a nv a r y! r e a t l y i n i t s p h y s i c aal n d c h e m i c aflo r m . l t c a nb e a s o l i d ,l i q u i d ,g a s ,o r e v e n s o m e t h i n gi n b e t w e e n s, u c ha s s l u d g eA. n y g i v e nr a d i o a c t i vw e a s t ec a nb e p r i m a r i l yw a t e r ,s o i l ,p a p e r , p l a s t i cm , e t a l ,a s h ,g l a s sc, e r a m i co, r a m i x t u r eo f m a n yd i f f e r e n tp h y s i c af lo r m s .T h ec h e m i c a l form of r a d i o a c t i vw e a s t ec a nv a r ya s w e l l .R a d i o a c t i vwea s t ec a nc o n t a i nr a d i o n u c l i d eosf . v e r yl i g h te l e m e n t s , s u c ha s r a d i o a c t i v he y d r o g e n( t r i t i u m ) o, r o f v e r y h e a v ye l e m e n t ss, u c h ' a su r a n i u m R . a d i o a c t i vwea s t ei s c l a s s i f i eads h i g h ,i n t e r m e d i a t eo,r l o w l e v e l .D e p e n d i n og n t h e r a d i o n u c l i d ecso n t a i n e di n i t , a w a s t ec a n r e m a i nr a d i o a c t i vfer o m s e c o n d st o m i n u t e so, r e v e nf o r m i l l i o n so f y e a r s . Radioactive Waste Management R a d i o a c t i vwea s t em a n a g e m e ni tn c l u d e st h e p o s s e s s i o tnr,a n s p o r t a t i o nh,a n d l i n gs, t o r a g ea, n d u l t i m a t e d i s p o s aol f w a s t e .T h e s a f em a n a g e m e not f r a d i o a c t i vw e a s t ei s n e c e s s a rtyo p r o t e c tp u b l i ch e a l t h .l f h a n d l e di m p r o p e r l yp, o t e n t i ael x p o s u r eosf h u m a n st o h i g h - l e v er la d i o a c t i vw e a s t ec a nb e d a n g e r o u s , e v e nd e a d l y S . o m er a d i o a c t i vw e a s t e ss u c ha s c e r t a i nt y p e so f t r a n s u r a n i w c a s t ec a nc a u s eb i o l o g i c a l e f f e c t si n h u m a n so n l y i f t h e r a d i o n u c l i d ecso n t a i n e di n t h e w a s t ea r e d i r e c t l yi n h a l e do r i n g e s t e dM . ost l o w - l e v erla d i o a c t i vw e a s t e sc a n b e h a n d l e db y h u m a n sw i t h o u ta n y m e a s u r a b lbei o l o g i c ael f f e c t s . 'Neverthelesg s ,o o dh a n d l i n gp r a c t i c eos f a l l r a d i o a c t i vm e ateriala s n d w a s t es h o u l db e t h e g o a lt o p r o v i d eo p t i m u mp r o t e c t i o nt o h u m a n sa n d t h e e n v i r o n m e n tT. h e r eh a v eb e e nh i s t o r i cp r a c t i c e s a s s o c i a t ewd i t h t h e u s eo f r a d i o a c t i vm e a t e r i aw l h e r ew o r k e r sw e r e u n a w a r eo f p o t e n t i a rl i s k sT. h e r a d i u mw a t c hd i a lp a i n t e r so f t h e 1 9 2 0 si l l u s t r a t e t h e h e a l t he f f e c t st h a t c a nb e a s s o c i a t ew di t h i m p r o p e rh a n d l i n gp r a c t i c e sT.h e p a i n t e r se x p e r i e n c ehdi g ho c c u r r e n c eosf c a n c e ro f t h e l a r y n xa n d t o n g u ed u e t o i n g e s t i o n of radium. T h et r a n s p o r t a t i ocn. r a d i o a c t i vw e a s t ec a no c c u rv i a r o a d w d va, i r c r a f ts, h i p / b a r g ea,n d r a i l .T h e c l a s ' ; i f i c a t i oan d p h y s i c asl i z eo f r a d i o a c t i vw e a s t ed i c t a t et h e m e t h o do f t r a n s p o r tt,h e p a c k a g i n g i - € ( ; r : i r eadn, d t h e l a b e l i n gn e c e s s a rtyo a l l o wf o r t h e s h i p m e n o t f a s p e c i f i cw a s t e .T h e r ea r e i n t e r n a t i o n at rl a n s p o r t a t i orne q u i r e m e n tfso r r a d i o a c t i vw e a s t e ,a sw e l l a s m o r es p e c i f i cr e g u l a t i o nisn i n d i v i d u aclo u n t r i e s . 23r RS RADIOACTIVITYDETECTO ( 1 ) T h eS p a r kC o u n t e r : T h i sw o r k so n t h e p r i n c i p l teh a t r a d i o a c t i veem i s s i o ncsa u s ei o n i z a t i o on f t h e a i r a n d c a nc a u s e t h e a i r t o c o n d u citn a r e g i o nw h e r ea h i g hp o t e n t i adl i f f e r e n cies a p p l i e d . T h ea p p a r a t ucso n s i s tos f a f i n ew i r e g a u z ew h i c ha c t sa sa c a t h o d eb e i n gm o u n t e dcloseto a . h i g hv o l t a g ev a r i a b l ed . c .s o u r c e( 0 ) 5 0 0 0 V ) i s connected m e t a lr o d w h i c ha c t sa s a n a n o d e A a c r o s st h e a n o d ea n d c a t h o d e . anode + cathode€ tI I n s u l a t i nbga s e Radium -+ source H i g hv o l t a g e supply I n i t i a l l yw, i t h n o r a d i o a c t i vseo u r c ep r e s e n tt,h e v o l t a g ei s i n c r e a s eadc r o s st h e a n o d ea n d c a t h o d eu n t i ls p a r k sj u m p a c r o s st h e g a p .T h ev o l t a g ei s t h e n r e d u c e ds l o w l yu n t i lt h e s p a r k s j u s tf a i lt o b e p r o d u c e d . T h er a d i u ms o u r c ei s t h e n i n t r o d u c e cd l o s et o t h e w i r e g a u z ea, n dt h e s p a r k sr e a p p e a r . W h e nt h e r a d i o a c t i vseo u r c ei s p r e s e n tt,h e a i r b e c o m e si o n i z e da n dt h e i o n sa n df r e ee l e c t r o n s nf sparks. t n dt h i sc o n d u c t i o cna u s e tsh e p r o d u c t i o o c a i r s et h e a i rt o c o n d u c a 232 ( 2 ) T h e D I F F U S I OCNL O U D CHAMBER: T h i si n s t r u m e nits u s e dt o m a k et h e t r a c k so f r a d i o a c t i veem i s s i o n tso b e c o m ev i s i b l e . I t w o r k so n t h e f o l l o w i n gp r i n c i p l e : W h e na n i o n i z i n gp a r t i c l ep a s s etsh r o u g ha g a s ,i t l e a v e sa t r a i lo f p o s i t i v e g a si o n sa l o n gi t s path due to electronsbeingknockedoff from the gasparticles when the radioactive particle c o l l i d ew s ith it. l f t h e g a sc o n t a i n sa s a t u r a t e d v a p o u r f o re x a m p l ea l c o h ovl a p o u r a, l c o h odl r o p l e t sw i l l condensa e r o u n dt h e t r a i lo f p o s i t i v ei o n st o s h o wa v i s i b l et r a c k . perspex Saturated vaDour \ F e l ts o a k e dw i t h a l c o h o l Metal base R a d i o a c t i vseo u r c e Dry ice sponge T h ea p p a r a t ucso n s i s tos f a P e r s p ecxh a m b e w r i t h a s t r i po f f e l t a t t h e t o p t h a t h a sb e e n soakedin a mixtureof alcoholand water.The.darkmetalbaseat the bottom is kept at a temperaturo e f a b o u t- 5 0 ' Cb y d r y i c e .T h e r ei s a c o n t i n u o uds i f f u s i o no f a l c o h ovl a p o u r f r o m ' t h e t o p o f t h e c h a m b e tro t h e bottom. T h e r ew i l l b e a s u p e r s a t u r a t ev da p o u r a b o v e t h e c o l db a s e a , n dt h e r a d i o a c t i vseo u r c ew i l l p r o d u c ev i s i b l et r a c k st o a n yo b s e r v elro o k i n gf r o m t h e t o p o f t h e c h a m b e r . g l p h ao n l y ,t h e r ea r es o m e t i m eds i f f e r e n lte n g t h so f t r a c k sd u e t o t h e F o ra s o u r c ep r o d u c i n a d i f f e r e n et n e r g i e os n e m i s s i o n . 233 ( 3 ) T h e G E I G E R - V I u L lrrU nBE: l i r e A w h i c ha c t s s t h i n c e n t r aw T h i si n s t r u m e nits a l s or e f e r r e dt o a st h e G M t u b e .l t c o n t a i n a r w h i c ha c t sa st h e c a t h o d e . g E T A Lc y l i n d eC a sa n a n o d ea n d i s i n s u l a t e fdr o m t h e s u r r o u n d i nM +400V relativeto the cathodewhichis earthed. The anodeA is kept at a potentialof about A r g o na n d A n o d eA Halogen Protective To amplifier gauze Mica window cathode C W h e na n a l p h ao r b e t ap a r t i c l ee n t e r st h e t u b e v i at h e m i c aw i n d o w ,e l e c t r o n as n d i o n sa r e p r o d u c e dw h e nt h e i o n i z i n gp a r t i c l ek n o c k so f f e l e c t r o nfsr o m t h e g a sm o l e c u l e s . s n d i o n sc a nb e i n c r e a s esdi g n i f i c a n tilfyt h e p o t e n t i a+l V o n t h e T h i sn u m b e ro f e l e c t r o n a v o l t a g ei s t h e v o l t a g e v o l t a g eo f t h e g a s .( t h eb r e a k d o w n a n o d e ,i s l a r g e rt h a nt h e b r e a k d o w n a t w h i c ht h e g a sb e g i n st o c o n d u c t . T h ee l e c t r o n as r ea t t r a c t e dt o w a r d s t h eA N O D Ea n dt h e p o s i t i v ei o n sa r e a t t r a c t e dt o w a r d s t h e ODE. CATH T h e r ew o u l db e a p u l s ec u r r e n tp a s s i n tgh r o u g hR a n d h e n c et h e r ei s a p o t e n t i adl i f f e r e n c e acrossR. t o a n e l e c t r o n icco u n t e r . T h ep u l s ev o l t a g ei s a m p l i f i e da n d p a s s e d 234 lmportantfeaturesof the GM tube: ( 1 ) W h y i s a r g o na n d h a l o g e nu s e d ? T h ed i s c h a r goec c u r so n l y f o r a s h o r t t i m e ,a n d s e c o n d a reyl e c t r o nas r ee m i t t e db y t h e c a t h o d e w h e nt h e p o s i t i v ei o n sa r r i v et h e r e . particles. T h i sw o u l dt h e n u p s e t h e r e c o r d i n o gf t h e i o n i z i n g T h eg a si n t h e t u b e s h o u l dt h e r e f o r eb e a m i x t u r eo f a r g o na n d h a l o g e nw h o s em o l e c u l e s a b s o r be n e r g yo f t h e p o s i t i v ei o n so n c o l l i s i o a n n d h e n c et h e d i s c h a r gies q u i c k l yq u e n c h e d . ( 2 ) T h e a n o d ew i r e m u s t b e t h i n s o t h a t t h e c h a r g eo n i t c a n p r o d u c ea n e l e c t r i cf i e l d o f v e r y h i g h I N T E N S I TaYs a l l o f t h e c h a r g ew o u l d n o w b e c o n c e n t r a t e idn a v e r y s m a l l v o l u m eo f w i r e . l f t h e c h a r g e sw e r e d i s p e r s e d o v e r a l a r g e rv o l u m e ,t h e e l e c t r i cf i e l d i n t e n s i t ya r o u n dt h e w i r e w o u l dd e c r e a s e . T h eh i g he l e c t r i cf i e l dw o u l dt h e n c a u s et h e e l e c t r o ni-o n p a i rt o b e a c c e l e r a t et d o very h i g he n e r g i e n s e a rt o t h e w i r e a n dw o u l dt h e r e f o r ec a u s et h e p r o d u c t i o n o f m u c hm o r e i o n p a i r sb y c o l l i s i o nws i t h g a sm o l e c u l e s BACKGROUND RADIATION ORIGINS OF BACKGROUND RADIATION: ( 1 ) T h e r ea r e i n t e r n asl o u r c e o s f r a d i o a c t i vneu c l i d e ss,u c ha s p o t a s s i u m f l f w n i c hi s p r e s e nitn t h e h u m a nb o d y . ( 2 ) G a m m ar a y sa n d r a d o ng a si n t h e a i r c o m ef r o m n a t u r a l l o yccurring radioactive m a t e r i a lssu c ha s r a d i u mt,h o r i u ma n du r a n i u mi n t h e e a r t h ' sc r u s t . ( 3 ) G y p s u mw a l l se m i t r a d i a t i o n . ( 4 ) C o s m i cr a d i a t i o ni s m o s t l ya b s o r b e db y t h e a t m o s p h e r eb,u t a s m a l lp e r c e n t a gree a c h e s t h eg r o u n d . ( 5 ) I n d u s t r i aslo u r c e s u c ha s n u c l e a p r o w e rp l a n t st e n d t o l e a ks o m er a d i a t i o ni n t ot h e atmosphere. ( 6 ) N u c l e afra l l - o u tf r o m b o m bt e s t st e n d st o r e m a i ni n t h e a t m o s p h e rfeo r m a n yy e a r s . ( 7 ) L u m i n o ups a i n te m i t sr a d i a t i o n ( 8 ) T e l e v i s i osnc r e e n a s n d o t h e rc a t h o d er a yt u b e se m i t g a m m aa n dX r a d i a t i o n . EFFECTS OF RADIATION ON LIVINGTISSUE: d h i c ht h e ne i t h e rk i l l t h ec e l l so r c h a n g e W h e nc e l l sa b s o r br a d i a t i o ni o, n sa r ep r o d u c e w them i n a n u n d e s i r a bw l ea y . W h e na l a r g ea m o u n to f c e l l sa r e d e s t r o y e dt h , e o r g a n i s mm a yd i e . T h e r ea r ea l s om a n yd e l a y e de f f e c t ss u c ha s c a n c e rl,e u k a e m i aa,n d h e r e d i t a rdy e f e c t sa n d deformities. 235 U S E F UALP P L I C A T I OO NF SR A D I O I S O T O P E S : (1) Tracers: A t r a c e ri s t h e t e r m u s e df o r a p a r t i c u l acro m p o u n dt h a t c a nb e d e t e c t e da s i t m o v e s t h r o u g ha l i v i n gb o d y Radloisotopa e rse u s e f u al st r a c e r sb e c a u s a e p a r tf r o m b e i n ge a s i l yd e t e c t e di n t h e b o d y ,t h e y h a v et h e s a m ec h e m i c apl r o p e r t i eas st h e i r n o n - r a d i o a c t i vi seo t o p e s . F o re x a m p l es,o d i u mh a sa r a d i o i s o t o poef l l N a a n dt h i si s a l s oa b l et o f o r m N a C .l H e n c ei f a p a t i e n ti n g e s t s o m er e g u l a sr a l tt h a t h a s . as m a l la m o u n to f s o d i um - 2 4 ,a Geiger-Mulle t ur b e c a nb e u s e do v e rt h e p a t i e n t ' sb o d yt o t r a c et h e p a t ho f t r a v e lo f t h e s o d i u mc h l o r i d e . ( 2 ) D i a g n o s t ilcm a g i n g : l f a p a t i e n ti n g e s t a s c o m p o u n dt h a t c o n t a i n a s s m a l la m o u n to f g a m m a -e m i t t i n g r a d i o i s o t o p teh, e n w h b nt h e c o m p o u n dr e a c h e as p a r t i c u l aor r g a nf o r e x a m p l et h e l i v e r , t h e g a m m ar a y se m i t t e dc a nb e u s e dt o c o n s t r u cat n i m a g eo f t h e o r g a n w , i t h t h e a i do f a g a m m ac a m e r a . T h eg a m m ae m i t t e ri s c h o s e nb e c a u s e i t e s c a p efsr o m t h e b o d yw i t h o u tc a u s i n g any i o n i z a t i od n a m a g eA. l s oa r a d i o i s o t o pwei t h a s h o r th a l fl i f ei s u s e ds o t h a t t h e i n t e n s i t y r e a c h ea s v e r yi n s i g n i f i c a vnat l u ea f t e r2 4 h o u r s . (3) CancerTreatment: G a m m ar a d i a t i o ins u s e di n a h i g hi n t e n s i t by e a mt o k i l lc a n c ecr e l l s . T h e ' g a m m raa y sh a v eh i g hp e n e t r a t i npgo w e r sa n d c a nb e u s e dt o t a r g e ta l o c a t i o n i n s i d et h e b o d y ,u n l i k et h e c a s eo f a l p h aa n db e t ap a r t i c l ews h i c ha r es t o p p e db y t h e s k i no f a p e r s o n . P r e v i o u s lXy- r a y sw e r e u s e dt o k i l lc a n c e cr e l l sb u t X r a y m a c h i n eas l a r g ea n d c u m b e r s o mteo u s e , a n dt h e y a l s or e q u i r ev e r yh i g hv o l t a g e tso o p e r a t e . A g a m m as o u r c eo n t h e o t h e rh a n dc a nb e v e r ys m a l w l i t h d i m e n s i oonf a f e Wc m ,a n d d o e sn o t r e q u i r ea h i g hv o l t a g es o u r c e . 236 TUTORIAL SHEET ( S o l u t i o nsst a r tf r o m p g 1 8 9 ) ( 1 ) R a d i u m ( Rdae) c a y tso r a d o n( R n )b y t h e r e a c t i o n : '33no--' ,|ZRn+ /He+ y T h ea t o m i cm a s s e a s r e ;R a d i u m 3 . 7 5 2 4x L O - 2 s kr ga ;d o n3 . 6 5 6x 1 0 - 2 s k hg e; l i u m0 . 0 6 7x 10 2skg. P l a n c kc o n s t a n=t 6 . 6 3x 1 0 3 a i sa; n d s p e e do f l i g h ti n a v a c u u m= 3 x i - 0 8 m s - 1 . (i) E s t i m a t teh e e n e r g yi n J o u l e sw h e na n a t o mo f 2 2 " $ ndae c a y s . (ii) E s t i m a t teh e w a v e l e n g t oh f t h e g a m m ap h o t o ne m i t t e dd u r i n gt h i sd e c a yg, i v e n t h a t 4 % o f t h e e n e r g yr e l e a s etdu r n st o g a m m ar a d i a t i o n . ( i i i ) w h a t h a p p e ntso t h e r e m a i n i n9g6 %o f t h e e n e r g y ? ; ( A n s: 2 . 6 4 6x l - 01 0 J; 1 . 9x 1 0 1 a mC o n v e r t etdo K i n e t i ce n e r g yo f t h e p a r t i c l e s a n da l s ot o h e a te n e r g y . ) ( 2 ) A r a d i o a c t i vsea m p l eo f a n e l e m e n X t d e c a y st o a n o t h e re l e m e n Y t witha decay c o n s t a not f . 0 . 0 2 2h o u r s1 . (i) D e t e r m i nteh e h a l fl i f eo f X . (ii) W h a tf r a c t i o no f t h e o r i g i n asl a m p l ew i l l r e m a i na f t e r4 . 5 h a l fl i v e s ? ( i i i ) W h a tf r a c t i o nw i l l r e m a i na f t e r1 _ d 4a y s ? (Ans3 ; 1 . 5h o u r s 0 ; . 0 4 4 ; 6x 1 - 0 - 4 ) ( 3 ) O n eo f t h e d a n g e r sa s s o c i a t ewdi t h n u c l e a pr o w e rp l a n t si s t h e l e a k a g o ef plutonium w h i c hi s a b y - p r o d u c ti n t h e r e a c t o rl.t h a sa h a l fl i f eo f a p p r o x i m a t e 2l y. 4 x 1 - g a y e a rAs . l e t h a dl o s eo f p l u t o n i u mi s 1 . 6 5 m g . (i) D e t e r m i nteh e a m o u n to f p l u t o n i u m n u c l eiin a l e t h a dl o s ei f i t s r e l a t i v e atomic m a s si s 2 3 9 . (ii) C a l c u l a tteh e d e c a yr a t eo f t h i sd o s e ( A n s: 4 . 1 6x 1 0 1 81;, . 2x l - 0 l 4 d i s i n t e g r a t i o pn e sry e a r ) . ( 4 ) A r a d i o a c t i vsea m p l et h a t i s u s e df o r m e d i c i n apl u r p o s e hs a st o b e p r e p a r e di n a l a b o r a t o r yb e f o r ei t s i n t e n d e du s e .T h es a m p l eh a sa h a l fl i f eo f 9 6 . 7h o u r s . (i) W f r a ts h o u l di t s i n i t i a a l c t i v i t yb e i f t h e s a m p l em u s th a v ea n a c t i v i t yo f 6 . 6x L 0 ' B q ,w h e n i t i s u s e d 3 0 h o u r sa f t e ri t h a sb e e np r e p a r e d ? (ii) W h a tw i l l t h e a c t i v i t yo f t h e s a m p l ei n p a r t ( i ) b e 2 4 h r sa f t e ri t h a sb e e n administered? ( A n s 8: . 1 8x 1 0 s B q5; . 5 6x t O e a q . ) 237 ( 5 ) A r a d i o a c t i vsea m p l ei n a l a b o r a t o r y h aas m a s so f 2 0 ga n da n a c t i v i t y o f2 . 3 5x 1 0 6 B q . T hsea m p l eh a sa r a d i o a c t i vies o t o p ew h o s en a t u r aal b u n d a n cies 2 t % a n dw h o s e m a s sn u m b e ri s 1 4 8 . C a l c u l a t e : (i) T h ed e c a Yc o n s t a n t (ii) T h eh a l fl i f ei n Y e a r s ( i i i ) T h et i m e r e q u i r e df o r t h e a c t i v i t yt o f a l lt o 1 . 2x 1 0 3 B q . 16s1 I.6 x 1Osyea rs;t'75x l0eyears) (Ans:1'.37x 10 ; e a t e r i a lcso n t a i n s2 0 p g o fa t , m i x t u r eo f r a d i o a c t i vm ( 6 ) A t t h e s t a r to f a n e x p e r i m e n a r a d i o i s o t o pAe w h i c hh a sa h a l fl i f eo f 9 0 s e c o n d as n d 3 2 0I E o f r a d i o i s o t o pBew h i c hh a s a h a l fl i f eo f 3 0 s e c o n d s . sf each (i) A f t e rw h a t p e r i o do f t i m e w i l l t h e m i x t u r ec o n t a i ne q u a lm a s s e o W h a t i s t h e m a s so f e a c hi s o t o p ea t t h i st i m e ? isotope? g h e nt h e (ii) C a l c u l a tteh e r a t ea t w h i c ht h e a t o m so f i s o t o p eA a r ed e c a y i n w = Avogadro's and massesare the same,giventhat the molarmassof A 2209 c o n s t a n=t 6 . 0 2x 1 0 " ) 4, ( A n s: 1 8 0s d c o n d ;s5 t t g; 1 . 0 5 x1 0 ' " B q ) materialscontains160pgof a a mixtureof radioactive ( 7 ) At the startof an experiment, r a d i o i s o t o pAe w h i c hh a sa h a l fl i f eo f 8 0 s e c o n d as n d 8 0 0 p go f r a d i o i s o t o pBew h i c h h a sa h a l fl i f eo f 4 0 s e c o n d s . sf each ( i ), A f t e rw h a t p e r i o do f t i m e w i l l t h e m i x t u r ec o n t a i ne q u a lm a s s e o w h a t i s t h e m a s so f e a c hi s o t o p ea t t h i st i m e ? isotope? g h e nt h e (ii) C a l c u l a tteh e r a t ea t w h i c ht h e a t o m so f i s o t o p eA a r ed e c a y i n w , i v e nt h a t t h e m o l a rm a s so f A = L 4 0 ga n dA v o g a d r o ' s m a s s ea s r et h e s a m e g constant=6.02x1-0") (186seconds ; 32Vg;1'.rcx 101sBq) ( g ) ( a )E x p l a i n w h a t i s m e a n tb y t h e h a l fl i f ea n dt h e d e c a yc o n s t a not f a r a d i o i s o t o p e . t h a sa h a l fl i f eo f 5 8 d a y s .l t i s u s e dm e d i c a l l iyn t h e d i a g n o s iosf A r a d i o a c t i veel e m e n X t sr ec o m p l i c a t ebdy t h e f a c tt h a t X i s e x c r e t e d, i . e . b l o o dd i s o r d e r sM. e a s u r e m e n a r e m o v e df r o m t h e b o d ya t a r a t es u c ht h a t 8 7 d a y sa f t e ra d m i n i s t e r i nagd o s e ,h a l fo f t h e X a t o m si n t h e d o s eh a v eb e e ne x c r e t e dT. h a ti s e q u i v a l e n t t os a y i n g t h a t Xh a sa b i o l o g i c ahla l fl i f eo f 8 7 d a Y s . (i) l f t h e c o u n tr a t ef r o m a b l o o ds a m p l ei s 1 4 0 0c o u n t sp e r m i n u t e ,w h a t w i l l i t b e f r o m a s i m i l a rb l o o ds a m p l et a k e n1 7 4d a y sl a t e r ? (ii) H o w ' o n ga f t e rt h e f i r s ts a m p l ew a st a k e nw o u l da f u r t h e rs i m i l a sr a m p l eg i v ea couni rateof 1'2countsPerminute? (Ans:44 countsPerminute;65 daYs.) 238 (9) T h er a d i o a c t i vneu c l i d e' 3 2 U i s p r e s e n itn s o m er o c k sa n d h a sa h a l fl i f eo f 4 . 5 x lOeyears as it decaysinto zf;lPb(lead)according to the nuclearequation,32u- 2fl$eb + decay products A s a m p l eo f r o c ki s f o u n dt o c o n t a i n4 g m go f 2llu ana32mgot zflfnn. (i) (ii) (iii) (iv) C a l c u l a tteh e n u m b e ro f U r a n i u ma t o m si n t h e s a m p l e c a l c u l a tteh e n u m b e ro f l e a da t o m si n t h e s a m p l e Determine t h e i n i t i an l u m b e ro f u r a n i u ma t o m si n t h e s a m p l ea t f o r m a t i o n a s s u m i ntgh a t t h e r ew e r e n o i n i t i a l e a da t o m sp r e s e n t . Determine t h e a g eo f t h e r o c k . (Ans:1,.21, xL020;9.35 x 101e; 2.1,5x L020;3.73 x 10syr) (1 0 ) I n r a d i o a c t i vdea t i n gt,h e r a d i o i s o t oep, 2 c i s u s e da s i t h a sa longhalf life of 5 5 7 0y e a r s l. n a l l l i v i n go r g a n i s mtsh e c o n c e n t r a tni oo f L [ c t o l f C i s 1 . 1 6: l - 0 1 2W. h e n t h e o r g a n i s md i e st h e I [ c i s n o t r e p l e n i s h eadn d d e c a y st o t Z c . l n a n a r c h a e o l o g i csaal m p l eo f b o n e ,t h e c o n c e n t r a tni oo f r / C t o r f C w a sf o u n dt o be 3.4: 1,014 Determine t h e a g e . o tf h e b o n e . ( A n s :2 8 , 3 5 5y r ) 239 SOLUTIONS WORKED ( 1 ) T h ed e c r e a s ien m a s sf r o m R a d i u mt o i t s o t h e rp r o d u c t si s g i v e nb y : L m - t 0 - 2 sG . T S Z 4- [ 3 . 6 5 6+ 0 . 0 6 7 ] ): 0 . 0 2 9 4x 1 0 - 2 s k g L E : L m c z : 0 . 0 2 9 4x 1 0 - 2 5x 9 x 1 0 1 6 2 . 6 4 6 x 1 0 - 1 0 / EnergyduetoGammaradiationon|y=0.04x2.646x]-0-10=1.06x].0-1iJ o'osx 19-34 I ? x 1oB E -\,/ . t -rynsi.ns 1.06rro_rr::r.9x1o-14m E The 96%ofthe Energyis convertedinto heataswell as Kineticenergyof the emitted particles. (2) (i) Tr 2 Use the equatton N : No InZ 1 0.693 : 3l-.Shr 0.022 wltere nrepresents the number of half ltves "(;)" t ( 1 ) - : 0 . 0 4 4. i sg i v e nb y ( i i ) T hfer a c t i o o n f t h e o r i g i n asla m p l e # (iii) F i r s tf i n dt h e n u m b e ro f h a l fl i v e si n 1 ' 4d a y s . Numberof hoursin 3,4days= 1'4x24=336hr 336 - L0.67Tt 31,5 z Number of half ltves tn336 hr - - H ence (3) #:(;)"" :6x L0-4 239 g contatn 6.02 x !\z3parti"cles 6.02 x 1,023 1g contai,ns 239 6 . 0 2x 1 0 2 3 x 1 . 6 5x 1 0 - 3- 4 . t 6 x L 0 l 8 n u c l e i " 0 . 6 93 InZ x 4.16 x 1018 (tt)Acttvtty - )"N,where7 ; A: Z+ x tOT, 1,.65m9contatn 239 = '1..2x l-o1adi,s/yr 240 2 (4) (i)Halflife= 96.7hr. Aftera 30 hourperiod,the numberof halflivesisequalto 30 : 0.31half li.ves g6t (Jsing the equati"onA - o, (:)" , we setAo: (ii) t 1l#-11) - B.1B x Los Bq 24 hrsafterit trasbeenadm,r,r,!?/O meansthata totattimeof 54 hr woutd h a v ee l a p s eadf t e rp r e p a r a t i o n . 'A- - 0.558half ti"ves 54tv - Y g6i /l\o'sse / 1 1 0 ' s s-sB . 1 B x or\il = 5.56xtoeBq lorx(;,) ( 5 ) l f t h e s a m p l eh a sa m a s so f 2 O ga n dt h e r a d i o a c t i vpea r t i s c o n t a i n e d i n 2 L % o ft h e then the mass of the radioactive isotope .sample, is 20x0.21,= 4.2g T h em a s sn u m b e ro f t h e r a d i o i s o t o pies L 4 g 9 1,48g contains6.02x L023particles. 4 . 2 e w i l cl o n t a i n 6.02 x 1,023 x4.2 - 1.7Ix1,\zzparti"cles MB (i)Usi.ngtheequationA_trN';^_#-m_]-.37x1g-16,-1 (ii) The half tif e i.sgi"venby Tr - Y ";1 0 . 6 93 = - 5 x L0lsseconds - L.6x !\Byears T57 x 1n-r6 241 (iii) Useeither A - Ao(J)" or A : u stns A - Aoe-At Ao()" , si"ves I.Z x 103 *ffir-t (})" *: where n is the no.of ttalf ltves L /1\n : (;) ; n lni : ln(s'1x 10-a); n - 10'e4 HenceLO.g4halflivesare requiredfor the activityto fall to the desiredcount rate. ; 10.94half lives=10.94x1.6x \0Byears Sincet half Iife= I.6 x 1.0Byears 1.75x 10syears. (6) (i) B A 20 + 10 90 sec 320+ 160 30sec After 180 secondstheYwill both have5;rg 10+ 5 180sec 60sec 160+80 80 + 420 40 90sec 1-20sec 20 10 10 +$ 150sec L8Osec (ii)22Oghas6.02x1.023particles;5pgwitln^u"ffx5x].0-6-I.37x].016 particles. - ' # x 1 , . 3 7 x 1 0 1 6: 1 . 0 5 x 1 0 1 4 B q A c t i " u tA t y- ) . N: ' # x N t 242 (7) Usethe equationN = Noe-rt si.ncema"ssis proporti.onal to N we canwrite m: rftse-At The bothmasses are tlte same after the ttme t so that: m:ffte€-trrt-Tftge-lzt Hence 160e-Art - B00e-1zt 160 800 -: et(^r^z) ;h! - t(Ar- Ar):r(#-'#) -1.61 : (-8.67 x 10-3)t 'J.86 t = seconds (ii) The ma-ssx - 160 ,(#)186 - 3zttg 1,409has6.02xL023atoms 32Vghas1.376x1,017 atoms A = L N = X x 1 . 37 6 x 1 0 7 7- 1 . . 1 . 9 x 1,0rsBq (8) 174 daysrepresents 3 half livesfor process(1) and two half livesfor process(2). H e n c ei n a l l t h e s a m p l ew o u l dh a v eg o n et h r o u g h5 h a l fl i v e s . lf initialactivityis 1400per minute,then after5 half lives,the activitywould be A - 1400(+)"= 44 countsper mi"nute. \2/ (iii) T h i sp a r ti sa b i t m o r ec o m p l i c a t eadn dr e q u i r etsh a ty o uf i n dt h e E F F E C T hI V a lEf lifefromthe bothprocesses. For process(1')87days gives 1,.sTrwhi.tef or proces.s B,BTdays - LTt HenceinBT days there are z.s EFFECTIVEhaIflives. 1 ef f ectivehatf ti"fe i.sequaltu Y - 34.Bdays z.J usins A - o,(;)" ; 12= 44(;)",^(#)-= n("I) ; n: rB7 Hence1..87half liveswere neededto reachthe desiredactivity. T h et i m e f o r t h i s i s e q u a lt o 1 , . 9 7 x 3 4 . g= 6 5 d a y s 243 z ( 9 ) ( i ) 2 3 8 g o f U r a n i u mc o n t a i n6 . 0 2x 1 0 2 3p a r t i c l e s 49mg wi"Ucontain 6.02 x L023 x 48 x 10-3 : 1.2! x 1-\2oparticles Zn (ii) 206 gof leadcontain6.02x 1023particles 6.02 x !023 32mgwtttcontatnTx32x10_3:9.35x1019parti'cles (iii) T o t a li n i t i a ln u m b e ro f U r a n i u mp a r t i c l eas t f o r m a t i o n= 1 , . 2 Lx L 0 2 0+ 9 . 3 5 x 1 0 1 e- 2 . 1 5 x 1 , \ z o p a r t i " c l e s . (iv) S0 de:creasedfrom 2 . 1 5x 1 0 2 0t u 1 . 2 1 x L o 2 0 T h en u m b e ro f ur r a n i u mp arrtric lC:es i v ) S la sf o l l ; H e n c ef i n dt h e nr u m b e ro f Ih1aar fllive: r1'. ITn N_ro[z )' t 1,.2 2L1 x 1 0 20 ' ^ ^r L \ ' ;l 2 . I 5 x 1 0 2 0(,r2) L l''L . I2L. x 1 0 2 0 l=: = n I n 7 hn t lr, \ z . L Sx 1 0 2 )0I n - 0 . 8 |3 ,y, s = 0 . 8 3 x4 ,. 5Xx 1 O e = 3 . 7x31 0 / o tars T o t a ln u m b . , o f V . . rS Initial amount tn samPrc: # (1 0 ) Final amount in SamPIe: # trtn 3.4 L.I6 /L\' : u stng N - tr ; 1gr+ to- \Z) [Z,l ,n "'" t'lrr=-nm1 L 0 0x L . L 6 /. ;n-s.I Total numberof years - 5.1x 5570: 29365yr 244 BLANKPAGE THE END 245