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1819-3 MATH142 Formulas

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Course Outcome 1
1. 𝐹(π‘₯) = 𝑃(𝑋 ≤ π‘₯) = ∑π‘₯𝑖≤π‘₯ 𝑓(π‘₯𝑖 )
2. πœ‡ = 𝐸(𝑋) = ∑π‘₯ π‘₯𝑓(π‘₯)
3. 𝜎 2 = 𝑉(𝑋) = 𝐸[(𝑋 − πœ‡)2 ] = ∑π‘₯(π‘₯ − πœ‡)2 𝑓(π‘₯)
4. 𝜎 2 = 𝑉(𝑋) = ∑π‘₯ π‘₯ 2 𝑓(π‘₯) − πœ‡2
5. 𝐸[β„Ž(𝑋)] = ∑π‘₯ β„Ž(π‘₯)𝑓(π‘₯)
6. 𝑓(π‘₯𝑖 ) = 1⁄𝑛 , π‘₯ = π‘Ž, π‘Ž + 1, π‘Ž + 2, … , 𝑏, for π‘Ž ≤ 𝑏
7. πœ‡ = 𝐸(𝑋) = (𝑏 + π‘Ž)⁄2
8. 𝜎 2 = [(𝑏 − π‘Ž + 1)2 − 1]⁄12
9. 𝑓(π‘₯) = (𝑛π‘₯)𝑝 π‘₯ (1 − 𝑝)𝑛−π‘₯ , π‘₯ = 0, 1, … , 𝑛
10. πœ‡ = 𝐸(𝑋) = 𝑛𝑝
11. 𝜎 2 = 𝑉(𝑋) = 𝑛𝑝(1 − 𝑝)
π‘₯−1
12. 𝑓(π‘₯) = (1 − 𝑝) 𝑝, π‘₯ = 1, 2, …
13. πœ‡ = 1⁄𝑝
14. 𝜎 2 = (1 − 𝑝)⁄𝑝2
15 𝑓(π‘₯) = (π‘₯−1
)(1 − 𝑝) π‘₯−π‘Ÿ π‘π‘Ÿ , π‘₯ = π‘Ÿ, π‘Ÿ + 1, π‘Ÿ + 2, …
π‘Ÿ−1
16. πœ‡ = π‘Ÿ⁄𝑝
17. 𝜎 2 = π‘Ÿ(1 − 𝑝)⁄𝑝2
18. 𝑓(π‘₯) =
𝑁−𝐾
(𝐾
π‘₯ )( 𝑛−π‘₯ )
, x = max{0, n + K − N} to min{K, n}
(𝑁
𝑛)
22. 𝑓(π‘₯) = [𝑒 −πœ†π‘‡ (πœ†π‘‡)π‘₯ ]⁄π‘₯! , π‘₯ = 0, 1, 2, …
23. πœ‡ = 𝐸(𝑋) = πœ†π‘‡
24. 𝜎 2 = 𝑉(𝑋) = πœ†π‘‡
π‘₯
25. 𝐹(π‘₯) = 𝑃(𝑋 ≤ π‘₯) = ∫−∞ 𝑓(𝑒) 𝑑𝑒
∞
∞
29. 𝐸[β„Ž(𝑋)] = ∫−∞ β„Ž(π‘₯)𝑓(π‘₯) 𝑑π‘₯
30. 𝑓(π‘₯) = 1⁄(𝑏 − π‘Ž) , π‘Ž ≤ π‘₯ ≤ 𝑏
31. 𝜎 2 = 𝑉(𝑋) = (𝑏 − π‘Ž)2 ⁄12
32. 𝑓(π‘₯) = 𝑁(πœ‡, 𝜎 2 ) =
−(π‘₯−πœ‡)
1
2𝜎2
𝑒
√2πœ‹πœŽ
2
, −∞ < π‘₯ < ∞
33. Φ(𝑧) = 𝑃(𝑍 ≤ 𝑧) 34. 𝑍 = (𝑋 − πœ‡)⁄𝜎
35. 𝑓(π‘₯) = πœ†π‘’ −πœ†π‘₯ for 0 ≤ π‘₯ < ∞
36. πœ‡ = 𝐸(𝑋) = 1⁄πœ† 37. 𝜎 2 = 𝑉(𝑋) = 1⁄πœ†2
38. 𝑃(𝑋 < 𝑑1 + 𝑑2 |𝑋 > 𝑑1 ) = 𝑃(𝑋 < 𝑑2 )
∞
39. Γ(π‘Ÿ) = ∫0 π‘₯ π‘Ÿ−1 𝑒 −π‘₯ 𝑑π‘₯, for π‘Ÿ > 0
40. 𝑓(π‘₯) = πœ†π‘Ÿ π‘₯ π‘Ÿ−1 𝑒 −πœ†π‘₯ ⁄Γ(π‘Ÿ), for π‘₯ > 0, πœ† > 0, π‘Ÿ > 0
41. πœ‡ = 𝐸(𝑋) = πœ†⁄π‘Ÿ 42. 𝜎 2 = 𝑉(𝑋) = π‘Ÿ⁄πœ†2
𝛽 π‘₯ 𝛽−1
43. 𝑓(π‘₯) = 𝛿 (𝛿 )
π‘₯ 𝛽
𝛽
44. 𝐹(π‘₯) = 1 − 𝑒 −(π‘₯⁄𝛿 ) 45. πœ‡ = 𝐸(𝑋) = 𝛿à (1 + 𝛽1 )
46. 𝜎 2 = 𝑉(𝑋) = 𝛿 2 Γ (1 + 𝛽2 ) − 𝛿 2 [Γ (1 + 𝛽1 )]
√
πœƒ+πœ”2 ⁄2
(ln(π‘₯)−πœƒ)2
2πœ”2
]
49. 𝑉(𝑋) = 𝑒
2
0<π‘₯<∞
2πœƒ+πœ”2
(𝑒
πœ”2
− 1)
Γ(𝛼+𝛽)
50. 𝑓(π‘₯) = Γ(𝛼)Γ(𝛽) π‘₯ 𝛼−1 (1 − π‘₯)𝛽−1 , for x in [0, 1],
α > 0, β > 0
51. πœ‡ = 𝐸(𝑋) =
0.01
±2.33
±2.575
69. πœ‡: π‘₯Μ… ± 𝑧𝛼⁄2 𝜎⁄√𝑛
70. 𝑛 = [(𝑧𝛼⁄2 𝜎)⁄𝐸 ]
71. πœ‡ ≤ 𝑒 = π‘₯Μ… + 𝑧𝛼 𝜎⁄√𝑛 72. π‘₯Μ… − 𝑧𝛼 𝜎⁄√𝑛 = 𝑙 ≤ πœ‡
73. πœ‡: π‘₯Μ… ± 𝑧𝛼⁄2 𝑠⁄√𝑛 74. πœ‡: π‘₯Μ… ± 𝑑𝛼⁄2,𝑛−1 𝑠⁄√𝑛
75. 𝑣 = 𝑛 − 1
2
76. [(𝑛 − 1)𝑠 2 ]⁄πœ’π›Ό2⁄2,𝑛−1 ≤ 𝜎 2 ≤ [(𝑛 − 1)𝑠 2 ]⁄πœ’1−𝛼
⁄2,𝑛−1
2
77. [(𝑛 − 1)𝑠 2 ]⁄πœ’π›Ό,𝑛−1
≤ 𝜎2
2
78. 𝜎 2 ≤ [(𝑛 − 1)𝑠 2 ]⁄πœ’1−𝛼,𝑛−1
79. 𝑝̂ = 𝑋⁄𝑛 80. 𝑝: 𝑝̂ ± 𝑧𝛼⁄2 √[𝑝̂ (1 − 𝑝̂ )]⁄𝑛
81. 𝑛 = [𝑧𝛼2⁄2 𝑝(1 − 𝑝)]⁄𝐸 2 82. 𝑛 = [𝑧𝛼2⁄2 (0.25)]⁄𝐸 2
83. 𝑝̂ − 𝑧𝛼 √[𝑝̂ (1 − 𝑝̂ )]⁄𝑛 ≤ 𝑝
84. 𝑝 ≤ 𝑝̂ + 𝑧𝛼 √[𝑝̂ (1 − 𝑝̂ )]⁄𝑛
2
𝛼
𝛼+𝛽
𝛼𝛽
52. 𝜎 2 = 𝑉(𝑋) = (𝛼+𝛽)2 (𝛼+𝛽+1)
53. π‘“π‘‹π‘Œ (π‘₯, 𝑦) = 𝑃(𝑋 = π‘₯, π‘Œ = 𝑦)
54. 𝑓𝑋 (π‘₯) = ∑𝑦 π‘“π‘‹π‘Œ (π‘₯, 𝑦)
55. π‘“π‘Œ (𝑦) = ∑π‘₯ π‘“π‘‹π‘Œ (π‘₯, 𝑦)
2
𝑧𝛼⁄2
Μ‚ (1−𝑝
Μ‚ ) 𝑧𝛼⁄2
𝑝
𝑝̂+
±π‘§π›Ό⁄2 √
+ 2
85. 𝑝:
exp [− (𝛿 ) ], for π‘₯ > 0
exp [−
2πœ‹
Critical values of z
α
0.10
0.05
0.025
±1.28 ±1.645 ±1.96
±1.645 ±1.96 ±2.24
2
∞
48. 𝐸(𝑋) = 𝑒
∞
Course Outcome 2
One-tailed
Two-tailed
28. 𝜎 2 = 𝑉(𝑋) = ∫−∞ π‘₯ 2 𝑓(π‘₯)𝑑π‘₯ − πœ‡2
1
𝑏
59. 𝑃(π‘Ž < 𝑋 < 𝑏) = ∫π‘Ž ∫−∞ π‘“π‘‹π‘Œ (π‘₯, 𝑦) 𝑑𝑦 𝑑π‘₯
60. π‘“π‘Œ|π‘₯ (𝑦) = π‘“π‘‹π‘Œ (π‘₯, 𝑦)⁄𝑓𝑋 (π‘₯), 𝑓𝑋 (π‘₯) > 0
61. 𝑓𝑋|𝑦 (π‘₯) = π‘“π‘‹π‘Œ (π‘₯, 𝑦)⁄π‘“π‘Œ (𝑦), π‘“π‘Œ (𝑦) > 0
62. π‘“π‘‹π‘Œ (π‘₯, 𝑦) = 𝑓𝑋 (π‘₯)π‘“π‘Œ (𝑦)
63. 𝐸[β„Ž(𝑋, π‘Œ)] = ∑ ∑ β„Ž(π‘₯, 𝑦)π‘“π‘‹π‘Œ (π‘₯, 𝑦), X, Y discrete
64. 𝐸[β„Ž(𝑋, π‘Œ)] = ∫ ∫ β„Ž(π‘₯, 𝑦)π‘“π‘‹π‘Œ (π‘₯, 𝑦) 𝑑π‘₯ 𝑑𝑦, X, Y
continuous
65. cov(𝑋, π‘Œ) = πœŽπ‘‹π‘Œ = 𝐸[(𝑋 − πœ‡π‘₯ )(π‘Œ − πœ‡π‘¦ )] = ∑π‘₯ ∑𝑦(π‘₯ −
πœ‡π‘₯ )(𝑦 − πœ‡π‘¦ ) π‘“π‘‹π‘Œ (π‘₯, 𝑦)
66. cov(𝑋, π‘Œ) = πœŽπ‘‹π‘Œ = 𝐸[(𝑋 − πœ‡π‘₯ )(π‘Œ − πœ‡π‘¦ )] =
∞ ∞
∫−∞ ∫−∞(π‘₯ − πœ‡π‘₯ )(𝑦 − πœ‡π‘¦ )π‘“π‘‹π‘Œ (π‘₯, 𝑦)𝑑π‘₯ 𝑑𝑦
67. cov(𝑋, π‘Œ) = πœŽπ‘‹π‘Œ = 𝐸(π‘‹π‘Œ) − πœ‡π‘‹ πœ‡π‘Œ
68. πœŒπ‘‹π‘Œ = cov(𝑋, π‘Œ)⁄√𝑉(𝑋)𝑉(π‘Œ) = πœŽπ‘‹π‘Œ ⁄(πœŽπ‘‹ πœŽπ‘Œ )
Type of Test
26. πœ‡ = 𝐸(𝑋) = ∫−∞ π‘₯𝑓(π‘₯) 𝑑π‘₯
∞
27. 𝜎 2 = 𝑉(𝑋) = ∫−∞(π‘₯ − πœ‡)2 𝑓(π‘₯)𝑑π‘₯
47. 𝑓(π‘₯) = π‘₯πœ”
𝑏
58. 𝑃(π‘Ž < 𝑋 < 𝑏) = ∫π‘Ž 𝑓𝑋 (π‘₯) 𝑑π‘₯
𝑁−𝑛
20. 𝜎 2 = 𝑛𝑝(1 − 𝑝) ( 𝑁−1) 21. 𝑝 = 𝐾 ⁄𝑁
19. πœ‡ = 𝑛𝑝
56. 𝑓𝑋 (π‘₯) = ∫𝑦 π‘“π‘‹π‘Œ (π‘₯, 𝑦) 𝑑𝑦 57. π‘“π‘Œ (𝑦) = ∫π‘₯ π‘“π‘‹π‘Œ (π‘₯, 𝑦) 𝑑π‘₯
2𝑛
𝑛
4𝑛
2 ⁄𝑛
1+𝑧𝛼
⁄2
𝑋̅−πœ‡0
√𝑛
86. 𝑍0 = 𝜎⁄
87. 𝑇0 =
𝑋̅−πœ‡0
𝑆⁄√𝑛
88. πœ’02 = [(𝑛 − 1)𝑆 2 ]⁄𝜎02
89. 𝑍0 = (𝑋 − 𝑛𝑝0 )⁄√𝑛𝑝0 (1 − 𝑝0 )
100. 𝑍0 =
(𝑋̅1 −𝑋̅2 )−Δ0
√(𝜎12 ⁄𝑛1 )+(𝜎22 ⁄𝑛2 )
101. πœ’02 = ∑π‘˜π‘–=1
(𝑂𝑖 −𝐸𝑖 )2
102. 𝑣 = π‘˜ − 𝑝 − 1
𝐸𝑖
∑𝑐𝑗=1 𝑂𝑖𝑗
103. 𝑒̂𝑖 =
104. 𝑣̂𝑖 = 𝑛1 ∑π‘Ÿπ‘–=1 𝑂𝑖𝑗
1
105. 𝐸𝑖𝑗 = 𝑛𝑒̂𝑖 𝑣̂𝑗 = 𝑛 ∑𝑐𝑗=1 𝑂𝑖𝑗 ∑π‘Ÿπ‘–=1 𝑂𝑖𝑗
1
𝑛
2
106. πœ’02 = ∑π‘Ÿπ‘–=1 ∑𝑐𝑗=1
(𝑂𝑖𝑗 −𝐸𝑖𝑗 )
𝐸𝑖𝑗
107. 𝑣 = (π‘Ÿ − 1)(𝑐 − 1)
108. πœ‡1 − πœ‡2 : π‘₯Μ…1 − π‘₯Μ…2 ± 𝑧𝛼⁄2 √(𝜎12 ⁄𝑛1 ) + (𝜎22 ⁄𝑛2 )
2
138.
109. 𝑛 = [(𝑧𝛼⁄2 )⁄𝐸 ] (𝜎12 + 𝜎22 )
𝑏
110. πœ‡1 − πœ‡2 ≤ π‘₯Μ…1 − π‘₯Μ…2 + 𝑧𝛼 √(𝜎12 ⁄𝑛1 ) + (𝜎22 ⁄𝑛2 )
111. π‘₯Μ…1 − π‘₯Μ…2 − 𝑧𝛼 √(𝜎12 ⁄𝑛1 ) + (𝜎22 ⁄𝑛2 ) ≤ πœ‡1 − πœ‡2
112. 𝑇0 =
(𝑋̅1 −𝑋̅2 )−Δ0
116.
𝑇0∗
=
π‘Ž
√(𝑆12 ⁄𝑛1 )+(𝑆22 ⁄𝑛2 )
2
[(𝑠12 ⁄𝑛1 ) ⁄(𝑛1 −1)]+[(𝑠22 ⁄𝑛2 ) ⁄(𝑛2 −1)]
118. πœ‡1 − πœ‡2 : π‘₯Μ…1 − π‘₯Μ…2 ± 𝑑𝛼⁄2,𝑣 √(𝑠12 ⁄𝑛1 ) + (𝑠22 ⁄𝑛2 )
Μ… −Δ0
∑ π‘₯−∑ 𝑦
𝐷
119. 𝑇0 =
120. 𝑑̅ =
𝑠𝐷 ⁄√𝑛
𝑛
𝑛(∑ π‘₯ 2 −2 ∑ π‘₯𝑦+∑ 𝑦 2 )−(∑ π‘₯−∑ 𝑦)2
122. πœ‡π· : 𝑑̅ ± 𝑑𝛼⁄2,𝑛−1 𝑠𝐷 ⁄√𝑛
123. 𝑓1−𝛼,𝑒,𝑣 = 1⁄𝑓𝛼,𝑣,𝑒
124. 𝐹0 = 𝑠12 ⁄𝑠22
125. (𝑠12 ⁄𝑠22 )𝑓1−𝛼⁄2,𝑛2 −1,𝑛1 −1 ≤ 𝜎12 ⁄𝜎22 ≤
(𝑠12 ⁄𝑠22 )𝑓𝛼⁄2,𝑛2 −1,𝑛1 −1
148. 𝛽̂0 =
126. 𝑍0 =
153. π‘Ÿ =
𝑃̂1 −𝑃̂2
1
1
√𝑃̂(1−𝑃̂)(𝑛 +𝑛 )
1
2
128. 𝑝̂2 = 𝑋2 ⁄𝑛2
𝑝̂1 (1−𝑝̂1 )
𝑝̂ (1−𝑝̂2 )
+ 2
𝑛1
𝑛2
129. 𝑝1 − 𝑝2 : 𝑝̂1 − 𝑝̂2 ± 𝑧𝛼⁄2 √
𝑋 +𝑋
130. 𝑃̂ = 1 2
𝑛1 +𝑛2
π‘Ž
𝑛
π‘Ž
𝑦⋅⋅2
2
𝑆𝑆𝑇 = ∑ ∑(𝑦𝑖𝑗 − 𝑦̅⋅⋅ ) = ∑ ∑ 𝑦𝑖𝑗
−
𝑁
𝑖=1 𝑗=1
𝑖=1 𝑗=1
π‘Ž
π‘Ž
𝑆𝑆Treatments = 𝑛 ∑(𝑦̅𝑖⋅ − 𝑦̅⋅⋅
𝑖=1
133.
)2
𝑦𝑖⋅2 𝑦⋅⋅2
=∑ −
𝑛
𝑁
𝑖=1
π‘Ž
𝑛
2
𝑆𝑆𝐸 = ∑ ∑(𝑦𝑖𝑗 − 𝑦̅𝑖⋅ )
𝑖=1 𝑗=1
134. 𝑆𝑆𝑇 = 𝑆𝑆Treatments + 𝑆𝑆𝐸
135.
𝑆𝑆Treatments⁄(π‘Ž − 1) 𝑀𝑆Treatments
𝐹0 =
=
𝑆𝑆𝐸 ⁄[π‘Ž(𝑛 − 1)]
𝑀𝑆𝐸
136.
π‘Ž
𝑏
𝑛
2
𝑆𝑆𝑇 = ∑ ∑ ∑ π‘¦π‘–π‘—π‘˜
−
𝑖=1 𝑗=1 π‘˜=1
137.
π‘Ž
2
𝑦𝑖⋅⋅
𝑦⋅⋅⋅2
𝑆𝑆𝐴 = ∑
−
𝑏𝑛 π‘Žπ‘π‘›
𝑖=1
𝑦⋅⋅⋅2
π‘Žπ‘π‘›
𝑛
2
𝑛 ∑𝑛
𝑖=1 π‘₯𝑖 −(∑𝑖=1 π‘₯𝑖 )
(π‘₯
)
(𝑦
∑𝑛
Μ…)
−π‘₯Μ…
−𝑦
𝑖
𝑖=1 𝑖
2
∑𝑛
𝑖=1(π‘₯𝑖 −π‘₯Μ… )
𝑛
Μ‚
∑𝑛
∑
𝑦
−𝛽
1 𝑖=1 π‘₯𝑖
𝑖=1 𝑖
𝑛
𝑆π‘₯𝑦
√𝑆π‘₯π‘₯ 𝑆𝑦𝑦
147. 𝛽̂1 = 𝑆π‘₯𝑦 ⁄𝑆π‘₯π‘₯
149. 𝛽̂0 = 𝑦̅ − 𝛽̂1 π‘₯Μ…
∑ 𝑑π‘₯𝑑𝑦
154. π‘Ÿ = (𝑠𝑑π‘₯)(𝑠𝑑𝑦)(𝑛−1)
155. 𝑑π‘₯ = π‘₯ − π‘₯Μ…
156. 𝑑𝑦 = 𝑦 − 𝑦̅
2
157. 𝑒𝑖 = 𝑦𝑖 − 𝑦̂𝑖 158. 𝑆𝑆𝐸 = ∑𝑛𝑖=1 𝑒𝑖2 = ∑𝑛𝑖=1(𝑦𝑖 − 𝑦̂𝑖 )
159. 𝑆𝑆𝐸 = π‘›πœŽπ‘¦2 − π΅π‘›π‘ŸπœŽπ‘₯ πœŽπ‘¦ 160. 𝑆𝑆𝐸 = 𝑆𝑆𝑇 − 𝛽̂1 𝑆π‘₯𝑦
161. 𝜎 2 = 𝑆𝑆𝐸 ⁄(𝑛 − 2)
Μ‚ −𝛽
𝛽
162. 𝑇0 = 1 1,0
163. 𝑠𝑒(𝛽̂1 ) = √πœŽΜ‚ 2 ⁄𝑆π‘₯π‘₯
2
132.
𝑦⋅⋅⋅2
− 𝑆𝑆𝐴 − 𝑆𝑆𝐡
π‘Žπ‘π‘›
150. 𝑆π‘₯π‘₯ = ∑𝑛𝑖=1(π‘₯𝑖 − π‘₯Μ… )2
151. 𝑆𝑦𝑦 = ∑𝑛𝑖=1(𝑦𝑖 − 𝑦̅)2 = 𝑆𝑆𝑇
152. 𝑆π‘₯𝑦 = ∑𝑛𝑖=1(π‘₯𝑖 − π‘₯Μ… )(𝑦𝑖 − 𝑦̅)
164. 𝑇0 =
𝑛
𝑛
−
140. 𝑆𝑆𝐸 = 𝑆𝑆𝑇 − 𝑆𝑆𝐴𝐡 − 𝑆𝑆𝐴 − 𝑆𝑆𝐡
141. 𝐹0 = 𝑀𝑆𝐴 ⁄𝑀𝑆𝐸 142. 𝐹0 = 𝑀𝑆𝐡 ⁄𝑀𝑆𝐸
143. 𝐹0 = 𝑀𝑆𝐴𝐡 ⁄𝑀𝑆𝐸 144. 𝑦̂ = 𝛽̂0 + 𝛽̂1 π‘₯
𝑛 ∑𝑛 π‘₯ 𝑦 −(∑𝑛 π‘₯ )(∑𝑛 𝑦𝑖 )
145. 𝛽̂1 = 𝑖=1 𝑖 𝑖 𝑖=1 𝑖 𝑖=1
2
146. 𝛽̂1 =
𝑛(𝑛−1)
Course Outcome 3
131.
2
𝑦𝑖𝑗⋅
𝑖=1 𝑗=1
(𝑠12 ⁄𝑛1 +𝑠22 ⁄𝑛2 )
127. 𝑝̂1 = 𝑋1 ⁄𝑛1
𝑏
𝑆𝑆𝐴𝐡 = ∑ ∑
2
121. 𝑠𝐷2 =
π‘Žπ‘›
𝑦⋅⋅⋅2
π‘Žπ‘π‘›
139.
(𝑋̅1 −𝑋̅2 )−Δ0
2
117. 𝑣 =
𝑗=1
−
113. 𝑣 = 𝑛1 + 𝑛2 − 2
𝑆𝑝 √(1⁄𝑛1 )+(1⁄𝑛2 )
2
𝑆𝑝 = [(𝑛1 − 1)𝑆12 + (𝑛2
− 1)𝑆22 ]⁄[𝑛1 + 𝑛2 − 2]
115. πœ‡1 − πœ‡2 : π‘₯Μ…1 − π‘₯Μ…2 ± 𝑑𝛼⁄2,𝑛1 +𝑛2 −2 𝑆𝑝 √(1⁄𝑛1 ) + (1⁄𝑛2 )
114.
𝑆𝑆𝐡 = ∑
2
𝑦⋅𝑗⋅
166. 𝑍0 =
Μ‚ 2 ⁄𝑆π‘₯π‘₯
√𝜎
Μ‚0 −𝛽0,0
𝛽
1 π‘₯−2
√𝜎
Μ‚ 2[ +
]
𝑛 𝑆π‘₯π‘₯
+
𝑅 −0.5𝑛
0.5√𝑛
1
π‘₯ −2
165. 𝑠𝑒(𝛽̂0 ) = √πœŽΜ‚ 2 [𝑛 + 𝑆 ]
π‘₯π‘₯
167. 𝑍0 =
π‘Š + −𝑛(𝑛+1)⁄4
√𝑛(𝑛+1)(2𝑛+1)⁄24
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