Course Outcome 1 1. πΉ(π₯) = π(π ≤ π₯) = ∑π₯π≤π₯ π(π₯π ) 2. π = πΈ(π) = ∑π₯ π₯π(π₯) 3. π 2 = π(π) = πΈ[(π − π)2 ] = ∑π₯(π₯ − π)2 π(π₯) 4. π 2 = π(π) = ∑π₯ π₯ 2 π(π₯) − π2 5. πΈ[β(π)] = ∑π₯ β(π₯)π(π₯) 6. π(π₯π ) = 1⁄π , π₯ = π, π + 1, π + 2, … , π, for π ≤ π 7. π = πΈ(π) = (π + π)⁄2 8. π 2 = [(π − π + 1)2 − 1]⁄12 9. π(π₯) = (ππ₯)π π₯ (1 − π)π−π₯ , π₯ = 0, 1, … , π 10. π = πΈ(π) = ππ 11. π 2 = π(π) = ππ(1 − π) π₯−1 12. π(π₯) = (1 − π) π, π₯ = 1, 2, … 13. π = 1⁄π 14. π 2 = (1 − π)⁄π2 15 π(π₯) = (π₯−1 )(1 − π) π₯−π ππ , π₯ = π, π + 1, π + 2, … π−1 16. π = π⁄π 17. π 2 = π(1 − π)⁄π2 18. π(π₯) = π−πΎ (πΎ π₯ )( π−π₯ ) , x = max{0, n + K − N} to min{K, n} (π π) 22. π(π₯) = [π −ππ (ππ)π₯ ]⁄π₯! , π₯ = 0, 1, 2, … 23. π = πΈ(π) = ππ 24. π 2 = π(π) = ππ π₯ 25. πΉ(π₯) = π(π ≤ π₯) = ∫−∞ π(π’) ππ’ ∞ ∞ 29. πΈ[β(π)] = ∫−∞ β(π₯)π(π₯) ππ₯ 30. π(π₯) = 1⁄(π − π) , π ≤ π₯ ≤ π 31. π 2 = π(π) = (π − π)2 ⁄12 32. π(π₯) = π(π, π 2 ) = −(π₯−π) 1 2π2 π √2ππ 2 , −∞ < π₯ < ∞ 33. Φ(π§) = π(π ≤ π§) 34. π = (π − π)⁄π 35. π(π₯) = ππ −ππ₯ for 0 ≤ π₯ < ∞ 36. π = πΈ(π) = 1⁄π 37. π 2 = π(π) = 1⁄π2 38. π(π < π‘1 + π‘2 |π > π‘1 ) = π(π < π‘2 ) ∞ 39. Γ(π) = ∫0 π₯ π−1 π −π₯ ππ₯, for π > 0 40. π(π₯) = ππ π₯ π−1 π −ππ₯ ⁄Γ(π), for π₯ > 0, π > 0, π > 0 41. π = πΈ(π) = π⁄π 42. π 2 = π(π) = π⁄π2 π½ π₯ π½−1 43. π(π₯) = πΏ (πΏ ) π₯ π½ π½ 44. πΉ(π₯) = 1 − π −(π₯⁄πΏ ) 45. π = πΈ(π) = πΏΓ (1 + π½1 ) 46. π 2 = π(π) = πΏ 2 Γ (1 + π½2 ) − πΏ 2 [Γ (1 + π½1 )] √ π+π2 ⁄2 (ln(π₯)−π)2 2π2 ] 49. π(π) = π 2 0<π₯<∞ 2π+π2 (π π2 − 1) Γ(πΌ+π½) 50. π(π₯) = Γ(πΌ)Γ(π½) π₯ πΌ−1 (1 − π₯)π½−1 , for x in [0, 1], α > 0, β > 0 51. π = πΈ(π) = 0.01 ±2.33 ±2.575 69. π: π₯Μ ± π§πΌ⁄2 π⁄√π 70. π = [(π§πΌ⁄2 π)⁄πΈ ] 71. π ≤ π’ = π₯Μ + π§πΌ π⁄√π 72. π₯Μ − π§πΌ π⁄√π = π ≤ π 73. π: π₯Μ ± π§πΌ⁄2 π ⁄√π 74. π: π₯Μ ± π‘πΌ⁄2,π−1 π ⁄√π 75. π£ = π − 1 2 76. [(π − 1)π 2 ]⁄ππΌ2⁄2,π−1 ≤ π 2 ≤ [(π − 1)π 2 ]⁄π1−πΌ ⁄2,π−1 2 77. [(π − 1)π 2 ]⁄ππΌ,π−1 ≤ π2 2 78. π 2 ≤ [(π − 1)π 2 ]⁄π1−πΌ,π−1 79. πΜ = π⁄π 80. π: πΜ ± π§πΌ⁄2 √[πΜ (1 − πΜ )]⁄π 81. π = [π§πΌ2⁄2 π(1 − π)]⁄πΈ 2 82. π = [π§πΌ2⁄2 (0.25)]⁄πΈ 2 83. πΜ − π§πΌ √[πΜ (1 − πΜ )]⁄π ≤ π 84. π ≤ πΜ + π§πΌ √[πΜ (1 − πΜ )]⁄π 2 πΌ πΌ+π½ πΌπ½ 52. π 2 = π(π) = (πΌ+π½)2 (πΌ+π½+1) 53. πππ (π₯, π¦) = π(π = π₯, π = π¦) 54. ππ (π₯) = ∑π¦ πππ (π₯, π¦) 55. ππ (π¦) = ∑π₯ πππ (π₯, π¦) 2 π§πΌ⁄2 Μ (1−π Μ ) π§πΌ⁄2 π πΜ+ ±π§πΌ⁄2 √ + 2 85. π: exp [− (πΏ ) ], for π₯ > 0 exp [− 2π Critical values of z α 0.10 0.05 0.025 ±1.28 ±1.645 ±1.96 ±1.645 ±1.96 ±2.24 2 ∞ 48. πΈ(π) = π ∞ Course Outcome 2 One-tailed Two-tailed 28. π 2 = π(π) = ∫−∞ π₯ 2 π(π₯)ππ₯ − π2 1 π 59. π(π < π < π) = ∫π ∫−∞ πππ (π₯, π¦) ππ¦ ππ₯ 60. ππ|π₯ (π¦) = πππ (π₯, π¦)⁄ππ (π₯), ππ (π₯) > 0 61. ππ|π¦ (π₯) = πππ (π₯, π¦)⁄ππ (π¦), ππ (π¦) > 0 62. πππ (π₯, π¦) = ππ (π₯)ππ (π¦) 63. πΈ[β(π, π)] = ∑ ∑ β(π₯, π¦)πππ (π₯, π¦), X, Y discrete 64. πΈ[β(π, π)] = ∫ ∫ β(π₯, π¦)πππ (π₯, π¦) ππ₯ ππ¦, X, Y continuous 65. cov(π, π) = πππ = πΈ[(π − ππ₯ )(π − ππ¦ )] = ∑π₯ ∑π¦(π₯ − ππ₯ )(π¦ − ππ¦ ) πππ (π₯, π¦) 66. cov(π, π) = πππ = πΈ[(π − ππ₯ )(π − ππ¦ )] = ∞ ∞ ∫−∞ ∫−∞(π₯ − ππ₯ )(π¦ − ππ¦ )πππ (π₯, π¦)ππ₯ ππ¦ 67. cov(π, π) = πππ = πΈ(ππ) − ππ ππ 68. πππ = cov(π, π)⁄√π(π)π(π) = πππ ⁄(ππ ππ ) Type of Test 26. π = πΈ(π) = ∫−∞ π₯π(π₯) ππ₯ ∞ 27. π 2 = π(π) = ∫−∞(π₯ − π)2 π(π₯)ππ₯ 47. π(π₯) = π₯π π 58. π(π < π < π) = ∫π ππ (π₯) ππ₯ π−π 20. π 2 = ππ(1 − π) ( π−1) 21. π = πΎ ⁄π 19. π = ππ 56. ππ (π₯) = ∫π¦ πππ (π₯, π¦) ππ¦ 57. ππ (π¦) = ∫π₯ πππ (π₯, π¦) ππ₯ 2π π 4π 2 ⁄π 1+π§πΌ ⁄2 πΜ −π0 √π 86. π0 = π⁄ 87. π0 = πΜ −π0 π⁄√π 88. π02 = [(π − 1)π 2 ]⁄π02 89. π0 = (π − ππ0 )⁄√ππ0 (1 − π0 ) 100. π0 = (πΜ 1 −πΜ 2 )−Δ0 √(π12 ⁄π1 )+(π22 ⁄π2 ) 101. π02 = ∑ππ=1 (ππ −πΈπ )2 102. π£ = π − π − 1 πΈπ ∑ππ=1 πππ 103. π’Μπ = 104. π£Μπ = π1 ∑ππ=1 πππ 1 105. πΈππ = ππ’Μπ π£Μπ = π ∑ππ=1 πππ ∑ππ=1 πππ 1 π 2 106. π02 = ∑ππ=1 ∑ππ=1 (πππ −πΈππ ) πΈππ 107. π£ = (π − 1)(π − 1) 108. π1 − π2 : π₯Μ 1 − π₯Μ 2 ± π§πΌ⁄2 √(π12 ⁄π1 ) + (π22 ⁄π2 ) 2 138. 109. π = [(π§πΌ⁄2 )⁄πΈ ] (π12 + π22 ) π 110. π1 − π2 ≤ π₯Μ 1 − π₯Μ 2 + π§πΌ √(π12 ⁄π1 ) + (π22 ⁄π2 ) 111. π₯Μ 1 − π₯Μ 2 − π§πΌ √(π12 ⁄π1 ) + (π22 ⁄π2 ) ≤ π1 − π2 112. π0 = (πΜ 1 −πΜ 2 )−Δ0 116. π0∗ = π √(π12 ⁄π1 )+(π22 ⁄π2 ) 2 [(π 12 ⁄π1 ) ⁄(π1 −1)]+[(π 22 ⁄π2 ) ⁄(π2 −1)] 118. π1 − π2 : π₯Μ 1 − π₯Μ 2 ± π‘πΌ⁄2,π£ √(π 12 ⁄π1 ) + (π 22 ⁄π2 ) Μ −Δ0 ∑ π₯−∑ π¦ π· 119. π0 = 120. πΜ = π π· ⁄√π π π(∑ π₯ 2 −2 ∑ π₯π¦+∑ π¦ 2 )−(∑ π₯−∑ π¦)2 122. ππ· : πΜ ± π‘πΌ⁄2,π−1 π π· ⁄√π 123. π1−πΌ,π’,π£ = 1⁄ππΌ,π£,π’ 124. πΉ0 = π 12 ⁄π 22 125. (π 12 ⁄π 22 )π1−πΌ⁄2,π2 −1,π1 −1 ≤ π12 ⁄π22 ≤ (π 12 ⁄π 22 )ππΌ⁄2,π2 −1,π1 −1 148. π½Μ0 = 126. π0 = 153. π = πΜ1 −πΜ2 1 1 √πΜ(1−πΜ)(π +π ) 1 2 128. πΜ2 = π2 ⁄π2 πΜ1 (1−πΜ1 ) πΜ (1−πΜ2 ) + 2 π1 π2 129. π1 − π2 : πΜ1 − πΜ2 ± π§πΌ⁄2 √ π +π 130. πΜ = 1 2 π1 +π2 π π π π¦⋅⋅2 2 πππ = ∑ ∑(π¦ππ − π¦Μ ⋅⋅ ) = ∑ ∑ π¦ππ − π π=1 π=1 π=1 π=1 π π ππTreatments = π ∑(π¦Μ π⋅ − π¦Μ ⋅⋅ π=1 133. )2 π¦π⋅2 π¦⋅⋅2 =∑ − π π π=1 π π 2 πππΈ = ∑ ∑(π¦ππ − π¦Μ π⋅ ) π=1 π=1 134. πππ = ππTreatments + πππΈ 135. ππTreatments⁄(π − 1) ππTreatments πΉ0 = = πππΈ ⁄[π(π − 1)] πππΈ 136. π π π 2 πππ = ∑ ∑ ∑ π¦πππ − π=1 π=1 π=1 137. π 2 π¦π⋅⋅ π¦⋅⋅⋅2 πππ΄ = ∑ − ππ πππ π=1 π¦⋅⋅⋅2 πππ π 2 π ∑π π=1 π₯π −(∑π=1 π₯π ) (π₯ ) (π¦ ∑π Μ ) −π₯Μ −π¦ π π=1 π 2 ∑π π=1(π₯π −π₯Μ ) π Μ ∑π ∑ π¦ −π½ 1 π=1 π₯π π=1 π π ππ₯π¦ √ππ₯π₯ ππ¦π¦ 147. π½Μ1 = ππ₯π¦ ⁄ππ₯π₯ 149. π½Μ0 = π¦Μ − π½Μ1 π₯Μ ∑ ππ₯ππ¦ 154. π = (π ππ₯)(π ππ¦)(π−1) 155. ππ₯ = π₯ − π₯Μ 156. ππ¦ = π¦ − π¦Μ 2 157. ππ = π¦π − π¦Μπ 158. πππΈ = ∑ππ=1 ππ2 = ∑ππ=1(π¦π − π¦Μπ ) 159. πππΈ = πππ¦2 − π΅ππππ₯ ππ¦ 160. πππΈ = πππ − π½Μ1 ππ₯π¦ 161. π 2 = πππΈ ⁄(π − 2) Μ −π½ π½ 162. π0 = 1 1,0 163. π π(π½Μ1 ) = √πΜ 2 ⁄ππ₯π₯ 2 132. π¦⋅⋅⋅2 − πππ΄ − πππ΅ πππ 150. ππ₯π₯ = ∑ππ=1(π₯π − π₯Μ )2 151. ππ¦π¦ = ∑ππ=1(π¦π − π¦Μ )2 = πππ 152. ππ₯π¦ = ∑ππ=1(π₯π − π₯Μ )(π¦π − π¦Μ ) 164. π0 = π π − 140. πππΈ = πππ − πππ΄π΅ − πππ΄ − πππ΅ 141. πΉ0 = πππ΄ ⁄πππΈ 142. πΉ0 = πππ΅ ⁄πππΈ 143. πΉ0 = πππ΄π΅ ⁄πππΈ 144. π¦Μ = π½Μ0 + π½Μ1 π₯ π ∑π π₯ π¦ −(∑π π₯ )(∑π π¦π ) 145. π½Μ1 = π=1 π π π=1 π π=1 2 146. π½Μ1 = π(π−1) Course Outcome 3 131. 2 π¦ππ⋅ π=1 π=1 (π 12 ⁄π1 +π 22 ⁄π2 ) 127. πΜ1 = π1 ⁄π1 π πππ΄π΅ = ∑ ∑ 2 121. π π·2 = ππ π¦⋅⋅⋅2 πππ 139. (πΜ 1 −πΜ 2 )−Δ0 2 117. π£ = π=1 − 113. π£ = π1 + π2 − 2 ππ √(1⁄π1 )+(1⁄π2 ) 2 ππ = [(π1 − 1)π12 + (π2 − 1)π22 ]⁄[π1 + π2 − 2] 115. π1 − π2 : π₯Μ 1 − π₯Μ 2 ± π‘πΌ⁄2,π1 +π2 −2 ππ √(1⁄π1 ) + (1⁄π2 ) 114. πππ΅ = ∑ 2 π¦⋅π⋅ 166. π0 = Μ 2 ⁄ππ₯π₯ √π Μ0 −π½0,0 π½ 1 π₯−2 √π Μ 2[ + ] π ππ₯π₯ + π −0.5π 0.5√π 1 π₯ −2 165. π π(π½Μ0 ) = √πΜ 2 [π + π ] π₯π₯ 167. π0 = π + −π(π+1)⁄4 √π(π+1)(2π+1)⁄24