SOME CALCULUS STEP-BY-STEP PLANS, 2WBB0 c MICHIEL HOCHSTENBACH, FALL 2022 Here an overview of some step-by-step plans from the slides. Try to learn these by heart by following them to solve exercises; work systematically. Zeros of 3rd and higher-degree polynomials p(x) = 0 1. 2. 3. 4. 5. First check if it is an easier special case, e.g. x3 − 8 = 0 or x4 + 2x2 + 1 = 0 If not, guess a zero, say x = a Divide: p(x)/(x − a) (should have rest 0), this gives a new polynomial q(x) If the degree of q(x) is still > 2, repeat this procedure If the degree of q(x) equals 2, try sum–product, or else quadratic (“abc”) formula Equations / inequalities with rational functions 1. Equations: collect everything into 1 fraction, or multiply crosswise 2. Inequalities: collect everything into 1 fraction with “> 0” or “< 0” on the right-hand side. Then make a table of signs of nominator and denominator; together this determines the signs of the rational function. Equations / inequalities with sin, cos, tan 1. Replace everything as much as possible by 1 type of function, you can use e.g.: sin2 (x) → 1 − cos2 (x) or vice versa sin(x) tan(x) → cos(x) sin(2x) → 2 sin(x) cos(x) cos( π2 − x) → sin(x) etc Goal is to get an equation or inequality in only 1 unknown; avoid square roots. Avoid having both sin(x) and cos(x), or sin(x) and sin(2x) 2. Carry out a substitution, e.g. y = sin(x), and solve the equation / inequality. This can contain a polynomial or rational function. 3. Replace y again by by e.g. sin(x), and solve, e.g. sin(x) = 21 ⇒ x = π6 or x = − π6 4. Think of “+k 2π” (for sin and cos) or “+k π” (for tan) Equations / inequalities with square roots 1. Equations: solve by squaring (possibly several times); always check solutions at the end. 2. Inequalities: first solve equality; for the solution also take care that all arguments under square roots should be ≥ 0. 1 Equations / inequalities with powers 1. Write both sides as power of the same basis 2. Then omit the basis; an inequality sign flips when the basis is between 0 and 1 3. Alternative for powers of basis e: we can also take the ln Equations / inequalities with ln 1. 2. 3. 4. Write both sides as ln (without something in front) Omit the ln’s Take the domains of the ln’s into account Alternative: you can also eliminate the ln’s by taking e-powers Differentiating f (x)g(x) 1. Write f (x)g(x) as eg(x) ln(f (x)) 2. Take the derivative: eg(x) ln(f (x)) times the derivative of the exponent 3. Write back eg(x) ln(f (x)) to f (x)g(x) Optimization: finding critical points of f (x) (for minima/maxima) 1. 2. 3. 4. 5. 6. 7. Solve f 0 (x) = 0 Make a sign scheme of f 0 Use this to determine: local max, local min, or reflection point Consider the boundary points if the domain is bounded Consider possible points where f 0 does not exist (“cusps”) Determine the function value in all these points Compare the local max/min’s to determine the global min/max Limits 1. Always first try to fill in the number if this gives no problem (see items 2–8): done! 2. 6=00 : consider lim and lim (ONLY for this type!) x→a+ 3. 4. 5. 6. 7. 8. NB: x→a− • If ∞ and ∞ then limit ∞ (some say: does not exist) • If −∞ and −∞ then limit −∞ (some say: does not exist) • If ∞ and −∞, or −∞ and ∞ then limit does not exist 0 : 0 l’Hò‚pital (possibly several times), or Taylor, or divide out factor ∞ ∞ : divide by largest in denominator (or l’Hò‚pital) oscillate ∞ : is 0, use Squeeze Theorem ∞ − ∞: write as 1 term 0 · ∞: write as 00 of ∞ ∞ ∞0 , 1∞ , 00 : trick with eln 0 ∞, 0∞ and ∞∞ are not problematic 2 Taylor series in a = 0 1. Use a standard series, which you can modify 2. Or use the definition: f (0) + f 0 (0) x + 12 f 00 (0) x2 + 16 f 000 (0) x3 + · · · Taylor series in a 6= 0 1. 2. 3. 4. 5. We want powers of y = x − a Write x = y + a and substitute this into f (x) Try to get a Taylor series with powers of y (and not, e.g., y − 1) Replace y by x − a Alternative: use the definition: f (a)+(x−a)f 0 (a)+ 12 f 00 (a) (x−a)2 + 61 f 000 (a) (x−a)3 +· · · Integration 1. Standard integrals 2. Substitution • Recognize derivative • u = the quantity of which you recognize the derivative • If you can choose: substitute hardest factor 3. Rational functions • Polynomial division if degree nominator ≥ degree denominator • Factorize denominator into linear or possibly quadratic factors • Partial fraction expansion: separate cases for linear, quadratic, multiple linear factors • Integrate each term separately (linear factor gives ln, quadratic ln or arctan) 4. Partial integration • Product of 2 functions: take hardest =G R • 1 function: take f = 1 (e.g.: arctan(x) dx) R 2 x • May have to repeat (e.g.: x e dx) R • May do twice and arrive at the same (e.g.: ex sin(x) dx) Differential equations (ODEs) dy 1. Separable differential equations dx = f (x) g(y) dy • Separation of variables: g(y) = f (x) dx R dy R • Integrate both sides g(y) = f (x) dx + C • Solve: integrate and express y in x dy 2. First-order linear ODE dx = p(x) y + q(x) dy • First solve homogeneous part dx = p(x) y by separation of variables dy (special case of separable dx = f (x) g(y)), this contains a constant C • Variation of constant: replace C by C(x) • Substitute into ODE with inhomogeneous term, we get a new ODE with C 0 (x), but this one can be solved by ordinary integration since the right-hand side does not contain C(x) • Solve for C(x) and determine solution ODE 3 Vectors step-by-step plans: Distance of point (p, q, r) to plane ax + by + cz = d 1. Find parametrization line through point perpendicular to plane: (x, y, z) = (p, q, r) + λ (a, b, c) 2. Compute intersection point line with plane: substitute x = p + λa, y = q + λb, z = r + λc into plane equation 3. Compute distance between (p, q, r) and intersection point Distance of point to line in R3 1. Give equation of plane through point perpendicular to line; ax + by + cz = d, with (a, b, c) the direction vector of the line 2. Compute d by substituting the point 3. Compute intersection point line with plane 4. Compute distance between point and intersection point Area triangle (a, b, c), (d, e, f ), (g, h, i) in R3 1. Compute cross product of (d, e, f ) − (a, b, c) and (g, h, i) − (a, b, c) 2. Area = 21 · length of this vector Area triangle (a, b), (c, d), (e, f ) in R2 1. Compute cross product of (c, d, 0) − (a, b, 0) and (e, f, 0) − (a, b, 0) 2. Area = 12 · length of this vector NB: there are also other methods; these may be used as long as they give the correct answer. Volume parallelepiped in R3 1. Compute 3 direction vectors a, b, c between the 4 points 2. Volume = |(a × b) · c| Intersection line of two planes in R3 1. Find two points in the intersection, for instance by substituting x = 0 and solving the 2 × 2 system, and then by doing the same for y = 0 2. OR compute the direction vector of the line as the cross product of the two normal vectors, and in addition 1 point in the intersection Angle between two planes in R3 1. Compute the angle between the two normal vectors 4