DC Circuits | First Order Circuits The Source-Free RC Circuit A source-free RC circuit occurs when its dc source is suddenly disconnected. The energy already stored in the capacitor is released to the resistor(s). Consider the circuit with an initially charged capacitor, Figure 1: A source-free RC circuit. R and C may be the equivalent resistance and capacitance of combinations of resistors and capacitors. The objective is to determine the circuit response, which we assume to be the voltage across the capacitor. Since the capacitor is initially charged, we can assume that at time , the initial voltage is , with the corresponding value of the energy stored as Applying KCL at the top node of the circuit yields . Thus, . By definition, and This is a first-order differential equation, since only the first derivative is involved. Solving the equation, The voltage response of the circuit is an exponential decay of . This is the natural response of the circuit. The natural response refers to the behavior (in terms of voltages and currents) of the circuit, with no external excitation sources; graphically shown in Fig. 2. Created with CircuitBread.com 1/11 Figure 2: The voltage response of the RC circuit At , the initial condition is satisfied. As increases, the voltage approaches zero. The rapidity with which the voltage decreases is expressed in terms of the time constant . The time constant of a circuit is the time required for the response to decay to a factor of initial value. At , . Thus, or 36.8% of its . In terms of the time constant, . Since is less than 1% of after 5τ, it is customary to assume that the capacitor is fully discharged/charged after 5τ. The smaller the time constant, the faster the response/the faster the circuit reaches the steady state. Whether is small or large, the circuit reaches steady state in 5τ. With the voltage expressed in τ, we can find the current , The power dissipated in the resistor is The energy absorbed by the resistor up to time is . As , which is the same as , the energy initially stored in the capacitor. This energy in the capacitor is eventually dissipated in the resistor. In summary, the key to working with a source-free RC circuit is finding: 1. The initial voltage 2. The time constant . across the capacitor. With these, we obtain the response as the capacitor voltage Once is obtained, other variables (capacitor current , resistor voltage , and resistor current determined. In finding , is often the Thevenin equivalent resistance at the terminals of the capacitor. Created with CircuitBread.com ) can be 2/11 The Source-Free RL Circuit Consider the series connection of a resistor and an inductor. The goal is to determine the circuit response, which is assumed to be the current through the inductor. Figure 3: A source-free RL circuit We select the inductor current as the response in order to take advantage of the idea that it cannot change instantaneously. At t = 0, we assume that the inductor has an initial current stored in the inductor as Applying KVL around the loop in Fig.3, , or with the corresponding energy . . But and . Thus, Rearranging terms and integrating gives The natural response of the RL circuit is an exponential decay of the initial current. The current response is shown in Fig. 4. Created with CircuitBread.com 3/11 Figure 4: The current response of the RL circuit It is evident from that the time constant for the RL circuit is . Thus, can be written as . With the current, we can find the voltage across the resistor as The power dissipated in the resistor is . . The energy absorbed by the resistor is As the same as in the inductor is eventually dissipated in the resistor. . , the initial energy stored in the inductor. This energy The key to working with a source-free RL circuit is to find: 1. The initial current through the inductor. 2. The time constant of the circuit. With these, we obtain the response as the inductor current Once we determine , other variables (inductor voltage , resistor voltage obtained. Note that in general, in . , and resistor current ) can be is the Thevenin resistance at the terminals of the inductor. Singularity Functions Singularity functions (switching functions in circuit analysis) are either discontinuous functions or functions with discontinuous derivatives. Unit Step Function u(t) is 0 for negative values of and 1 for positive values of . Created with CircuitBread.com 4/11 undefined at , where it changes abruptly from 0 to 1 Figure 5: The unit step function dimensionless, like other mathematical functions such as sine and cosine The unit step function may be delayed or advanced. When When is delayed by seconds is advanced, Figure 6: (a) The unit step function delayed by to, (b) the unit step advanced by to Step function is used to represent an abrupt change in voltage or current. For example, the voltage Created with CircuitBread.com 5/11 may be expressed in terms of the unit step function as If we let , then is simply the step voltage . A voltage source of is shown in Fig. 7(a); its equivalent circuit is shown in Fig. 7(b). It is evident in Fig. 7(b) that terminals a-b are short-circuited ( ) for and that appears at the terminals for t>0. Figure 7: (a) Voltage source of Vo u(t), (b) its equivalent circuit Similarly, a current source of is shown in Fig. 8(a), while its equivalent circuit is in Fig. 8(b). Figure 8: (a) Current source of Io u(t), (b) its equivalent circuit. Notice that for t<0, there is an open circuit ( ), and flows for t>0. Unit Impulse Function derivative of the unit step function is zero everywhere except at t=0, where it is undefined. Created with CircuitBread.com 6/11 Figure 9: The unit impulse function The unit impulse may be regarded as an applied or resulting shock; a very short duration pulse of unit area, expressed mathematically as where denotes the time just before t=0 and is the time just after t=0. The unit area is the strength of the function. When an impulse function has a strength other than unity, the area of the impulse is equal to its strength; an impulse function has an area of 10. Figure 10: Three impulse functions To illustrate how the impulse function affects other functions, evaluating the integral below where This shows that we obtain the value of the function at the point where the impulse occurs; known as the sampling or sifting property. The special case is when , the integral becomes Unit Ramp Function r(t) Created with CircuitBread.com 7/11 Integrating the unit step function u(t) results in the unit ramp function r(t) In general, a ramp is a function that changes at a constant rate. The unit ramp function is zero for negative values of t and has a unit slope for positive values of t. Figure 11: The unit ramp function The unit ramp function may be delayed or advanced as shown: Figure 12: The unit ramp function (a) delayed by to, (b) advanced by to. For the delayed unit ramp function, and for the advanced unit ramp function, Created with CircuitBread.com 8/11 The three singularity functions are related by differentiation as or by integration as Step Response of an RC Circuit The step response of a circuit is its behavior when the excitation is the step function; the response due to a sudden application of a dc voltage/current. Consider the RC circuit in Fig. 13(a) which can be replaced by the circuit in Fig. 13(b), where Vs is a constant dc voltage source. Figure 13: An RC circuit with voltage step input We break the complete response into two components—one temporary and the other permanent, that is The transient response is the circuit’s temporary response that will decay to zero as time approaches infinity. The steady-state response is the response a long time after an external excitation is applied; it remains after the transient response has died out. To find the step response of an RC circuit requires three things 1. The initial capacitor voltage 2. The final capacitor voltage Created with CircuitBread.com . . 9/11 3. The time constant . Let the response be the sum of the transient response and the steady-state response, The transient response is always a decaying exponential, that is After the transient response dies out, . Let be the initial capacitor voltage: switching and Substituting . . immediately after. From this, we obtain to , we get . is the capacitor voltage just before . which can be written as where is the voltage at If the switching takes place at time where If and is the initial value at is the final or steady-state value. instead of , there is a time delay in the response so that . , The current through the capacitor is Step Response of an RL Circuit To find the step response of an RL circuit requires three things: 1. The initial inductor current 2. The final inductor current 3. The time constant at Consider the RL circuit in Fig.14(a), which may be replaced by the circuit in Fig. 14(b). The inductor current i is the circuit Created with CircuitBread.com 10/11 response. Figure 14: An RL circuit with a step input voltage Let the response be the sum of the transient response and the steady-state response, . The transient response is always a decaying exponential, that is After the transient response dies out, the inductor becomes a short circuit. The entire source voltage across Let . Thus, . be the initial current through the inductor: Substituting appears . and . From this, we obtain to , we get which can be written as If the switching takes place at time If , instead of , . The voltage across the inductor is Created with CircuitBread.com 11/11