EXAM Review #2 Please Sign In ↓ CHM 142 #1 Given the reaction below, which of the following would cause an increase in the concentration of reactant(s)? 2HF(g) ⇋ F2 (g) + H2 (g) ΔH = -12.0 kJ/mol I. II. III. IV. removal of H2 addition of HF Increasing the temp of the reaction An increase in the volume of the container A. B. C. D. E. I only II only III only IV only III and IV #1 ANSWER Given the reaction below, which of the following would cause an increase in the concentration of reactant(s)? 2HF(g) ⇋ F2 (g) + H2 (g) +HEAT ΔH = -12.0 kJ/mol I. II. III. IV. removal of H2 remove product → shift to products addition of HF add reactant → shift to products Increasing the temp of the reaction add product → shift to reactants An increase in the volume of the container no effect (same # moles on each side) A. B. C. D. E. I only II only III only IV only III and IV “The System always kicks back” 1. Contin Add reactants → shift to PRODUCTS Add products → shift to REACTANTS Remove products → shift to PRODUCTS Remove reactants → shift to = Le Chatelier's principle 2. Prer/Vol 3. Temtu Decrease volume (increase pressure) → shift to THE SIDE WITH Temp increase → shift to PRODUCTS (endo) or to REACTANTS (exo) Increase volume (decrease pressure) → shift to THE Temp decrease → shift to REACTANTS (endo) or PRODUCTS (exo) THE FEWER MOLES SIDE WITH THE MORE MOLES REACTANTS *Explanations in speaker notes below* #2 The value of K for the formation of H2 (g) + Cl2 (g) ⇋ 2HCl (g) is 2.13 Determine the reaction quotient, Q, and which way the reaction will shift if H2= 15 mol, Cl2= 4 mol, and HCl = 9 mol in a 1.00 L vessel at 10°C. A. B. C. D. E. Q = 1.35, shift to form more reactants Q = 1.35, shift to form more products Q = 0.15, shift to form more reactants Q = 0.15, shift to form more products Can not be determined. #2 ANSWER Q = Keq at equilibrium!!! The value of K for the formation of H2 (g) + Cl2 (g) ⇋ 2HCl (g) is 2.13 Determine the reaction quotient, Q, and which way the reaction will shift if H2= 15 mol, Cl2= 4 mol, and HCl = 9 mol in a 1.00 L vessel at 10°C. A. B. C. D. E. Q = 1.35, shift to form more reactants Q = 1.35, shift to form more products Q = 0.15, shift to form more reactants Q = 0.15, shift to form more products Can not be determined. #3 An aqueous solution is considered to be acidic if: The hydroxide ion concentration is 10-6 M. The hydrogen ion concentration is 10-8 M. The hydroxide and hydrogen ion concentration are equal. They hydroxide ion concentration is greater than the hydrogen ion concentration. E. The hydroxide ion concentration is 10-10 M. A. B. C. D. #3 ANSWER An aqueous solution is considered to be acidic if: The hydroxide ion concentration is 10-6 M. The hydrogen ion concentration is 10-8 M. The hydroxide and hydrogen ion concentration are equal. They hydroxide ion concentration is greater than the hydrogen ion concentration. E. The hydroxide ion concentration is 10-10 M. A. B. C. D. #4 When [H+] = 4.0 × 10-9 M in water at 25°C, then pOH = ________ A. B. C. D. E. 8.40 -8.40 7.00 5.60 - 6.1 #4 ANSWER When [H+] = 4.0 × 10-9 M in water at 25°C, then pOH = ________ A. B. C. D. E. 8.40 -8.40 7.00 5.60 - 6.1 #5 Use the following acid ionization constants to identify the correct decreasing order of conjugate base strengths (strongest to weakest). HF Ka = 7.2×10-4 HNO2 Ka = 4.5×10-4 HCN Ka = 6.2×10-10 A. B. C. D. E. CN- > NO2- > FF- > NO2- > CNNO2- > F- > CNNO2- > CN- > FF- > CN- > NO2- #5 ANSWER Use the following acid ionization constants to identify the correct decreasing order of conjugate base strengths (strongest to weakest). HF Ka = 7.2×10-4 highest Ka = strongest acid = weakest conjugate base HNO2 Ka = 4.5×10-4 HCN Ka = 6.2×10-10 smallest Ka = weakests acid = strongest conjugate base A. B. C. D. E. CN- > NO2- > FF- > NO2- > CNNO2- > F- > CNNO2- > CN- > FF- > CN- > NO2- ☆ The larger the Ka, the STRONGER the acid = the WEAKER the conjugate base ☆ The smaller the Ka, the WEAKER the acid = the STRONGER the conjugate base #6 Which of the following is NOT a conjugate acid-base pair? A. B. C. D. E. NH3 and NH2HNO3 and HNO2 HI and IH2PO4- and HPO42H2O and OH- #6 ANSWER Which of the following is NOT a conjugate acid-base pair? A. B. C. D. E. NH3 and NH2HNO3 and HNO2 HI and IH2PO4- and HPO42H2O and OH- #7 Calculate the pH of a solution that initially contains 2.00 M of a weak acid, nitrous acid (HNO2). The Ka for nitrous acid is 4.5 × 10-4. HNO2 ⇆ H+ + NO2A. B. C. D. E. 2.5 1.5 2.7 2.3 3.4 #7 ANSWER Calculate the pH of a solution that initially contains 2.00 M of a weak acid, nitrous acid (HNO2). The Ka for nitrous acid is 4.5 × 10-4. HNO2 ⇆ H+ + NO2A. B. C. D. E. 2.5 1.5 2.7 2.3 3.4 Use approximation (get rid of the X in the denominator) because x/[HA]i ≤ 5% In this case, (0.03)/(2.00M) x 100 = 1.5% ≤ 5% #8 For the following reaction: HNO3 + NH3 ⇌ NH4+ + NO3Which compound is the strongest base and to which side does equilibrium lie? A. B. C. D. E. NH3 is the strongest base and equilibrium lies to the left NH4+ is the strongest base and equilibrium lies to the right NO3- is the strongest base and equilibrium lies to the right NH3 is the strongest base and equilibrium lies to the right NO3- is the strongest base and equilibrium lies to the left #8 Answer For the following reaction: HNO3 + NH3 ⇌ NH4+ + NO3Which compound is the strongest base and to which side does equilibrium lie? A. B. C. D. E. NH3 is the strongest base and equilibrium lies to the left NH4+ is the strongest base and equilibrium lies to the right NO3- is the strongest base and equilibrium lies to the right NH3 is the strongest base and equilibrium lies to the right NO3- is the strongest base and equilibrium lies to the left #9 Which of the following will have the highest pH? A. B. C. D. E. 0.5 M KOH 0.5 M Ca(OH)2 1.0 M KOH 0.75 M Ca(OH)2 0.75 M KOH #9 Answer Which of the following will have the highest pH? A. B. C. D. E. 0.5 M KOH 0.5 M Ca(OH)2 1.0 M KOH 0.75 M Ca(OH)2 0.75 M KOH #10 The Keq for the reaction 2NO + O2 ⇌ 2NO2 is 5.4 x 1013 at 480°C. What is Keq for the reaction 4NO2 ⇌ 4NO + 2O2 ? A. B. C. D. E. 3.4 x 10-28 3.7 x 10-14 2.9 x 1027 1.8 x 10-14 1.1 x 1014 #10 Answer The Keq for the reaction 2NO + O2 ⇌ 2NO2 is 5.4 x 1013 at 480°C. What is Keq for the reaction 4NO2 ⇌ 4NO + 2O2 ? A. B. C. D. E. 3.4 x 10-28 3.7 x 10-14 2.9 x 1027 1.8 x 10-14 1.1 x 1014 #11 What is the percent ionization of a 0.125-M solution of nitrous acid with a pH of 2.09. A. B. C. D. E. 81% 21% 6.5% 0.39% 13% #11 Answer What is the percent ionization of a 0.125-M solution of nitrous acid with a pH of 2.09. A. B. C. D. E. 81% 21% 6.5% 0.39% 13% #12 For the reaction N2O4 ⇌ 2NO2 , Keq= 4.64 x 10-3. If the initial concentration of N2O4 is 0.0367 M what is the concentration of both gases at equilibrium. A. B. C. D. E. [N2O4]= 0.0307 M ; [NO2]= 0.0119 M [N2O4]= 0.0367 M ; [NO2]= 0.00596 M [N2O4]= 0.0119 M ; [NO2]= 0.0307 M [N2O4]= 0.00596 M ; [NO2]= 0.0367 M [N2O4]= 0.0307 M ; [NO2]= 0.00596 M #12 Answer For the reaction N2O4 ⇌ 2NO2 , Keq= 4.64 x 10-3. If the initial concentration of N2O4 is 0.0367 M what is the concentration of both gases at equilibrium. A. B. C. D. E. [N2O4]= 0.0307 M ; [NO2]= 0.0119 M [N2O4]= 0.0367 M ; [NO2]= 0.00596 M [N2O4]= 0.0119 M ; [NO2]= 0.0307 M [N2O4]= 0.00596 M ; [NO2]= 0.0367 M [N2O4]= 0.0307 M ; [NO2]= 0.00596 M 4 #13 Which of the following is false about water? A. B. C. D. E. Water can either donate or accept a proton. The autoionization of water equation is H2O + H2O ⇌ H3O+ + OHThe ion-product constant of water (Kw) is 1.0 x 10-7 Kw = [H+][OH-] All of the above are true #13 Answer Which of the following is false about water? A. B. C. D. E. Water can either donate or accept a proton. The autoionization of water equation is H2O + H2O ⇌ H3O+ + OHThe ion-product constant of water (Kw) is 1.0 x 10-7 Kw = [H+][OH-] All of the above are true #14 At equilibrium of a certain reaction, the products are greatly favored. Which of the following are true. A. B. C. D. E. K << 1 K >>1 Q <<1 K=Q B and D are true #14 Answer At equilibrium of a certain reaction, the products are greatly favored. Which of the following are true. A. B. C. D. E. K << 1 K >>1 Q <<1 K=Q B and D are true #15 When the reversible reaction N2(g) + O2(g) <--> 2NO(g) has reached a state of equilibrium, A. No further reactions occur B. The total moles of products must equal the remaining moles of reactant C. The addition of a catalyst will cause formation of more NO D. The concentration of each substance in the system will be constant #15 ANSWER When the reversible reaction N2(g) + O2(g) <--> 2NO(g) has reached a state of equilibrium, A. No further reactions occur forward/reverse occurs simultaneously B. The total moles of products must equal the remaining moles of reactant equilibrium may favor more reactants/products C. The addition of a catalyst will cause formation of more NO catalyst lowers activation energy but doesn’t affect concentrations D. The concentration of each substance in the system will be constant #16 In which of the following equilibria is HPO42- acting as a Bronsted-Lowry base? #16 ANSWER In which of the following equilibria is HPO42- acting as a Bronsted-Lowry base? #17 Which of the following salts will not form a neutral solution in water? A. NaClO4 B. NaNO3 C. NaF D. NaI E. NaCl #17 ANSWER Which of the following salts will not form a neutral solution in water? A. NaClO4 B. NaNO3 C. NaF D. NaI E. NaCl #18 The reaction quotient, Qc, for a reaction has a value of 75 while the equilibrium constant, Kc, has a value of 195. Which of the following statements is accurate? A. The reaction must proceed to the left B. The reaction must proceed to the right C. The concentration of the products will be much smaller than the concentration of the reactions at equilibrium D. The concentration of the products will be = to the concentration of the reactants #18 ANSWER The reaction quotient, Qc, for a reaction has a value of 75 while the equilibrium constant, Kc, has a value of 195. Which of the following statements is accurate? A. The reaction must proceed to the left B. The reaction must proceed to the right C. The concentration of the products will be much smaller than the concentration of the reactions at equilibrium D. The concentration of the products will be = to the concentration of the reactants #19 Rank the following from strongest to weakest acid: HNO₂ H2SO₄ HPO₄⁻² A. B. C. D. E. H₂SO₄ → HNO₂ → HPO₄⁻² HPO₄⁻² → H₂SO₄ → HNO₂ HNO₂ → H2SO₄ → HPO₄⁻² H2SO₄ → HPO₄⁻² → HNO₂ HPO₄⁻² → HNO₂ → H₂SO₄ #19 ANSWER Rank the following from strongest to weakest acid: HNO₂ H2SO₄ HPO₄⁻² A. B. C. D. E. H₂SO₄ → HNO₂ → HPO₄⁻² HPO₄⁻² → H₂SO₄ → HNO₂ HNO₂ → H2SO₄ → HPO₄⁻² H2SO₄ → HPO₄⁻² → HNO₂ HPO₄⁻² → HNO₂ → H₂SO₄ #20 What is the pH of a 0.20 M solution of ammonia? The Kb value for ammonia is 1.8×10–5 A. B. C. D. E. 9.56 9.26 4.74 11.28 2.72 #20 ANSWER What is the pH of a 0.20 M solution of ammonia? The Kb value for ammonia is 1.8 × 10–5 A. B. C. D. E. 9.56 9.26 4.74 11.28 2.72 Goodluck!! You got this! EXTRA practice on the following slides :) Extra #21 Which of the following are true of catalyst? I. II. III. IV. They enhance the rate of forward and reverse reactions They alter the equilibrium constant, K They do not change the position of equilibrium They so not affect how quickly equilibrium is reached A. B. C. D. E. I and II II only III and I IV only III and II Extra #21 ANSWER Which of the following are true of catalyst? I. II. III. IV. They enhance the rate of forward and reverse reactions TRUE They alter the equilibrium constant, K FALSE (do not alter K) They do not change the position of equilibrium TRUE They so not affect how quickly equilibrium is reached FALSE (they affect it) A. B. C. D. E. I and II II only III and I IV only III and II Extra #22 Which of the following is false? I. II. III. IV. V. Strong acids/bases fully dissociate Weak do notably dissociate The first hydrogen lost in a polyprotic acid is the most acidic Strong acids/bases represent an equilibrium condition, they have double arrows in their equation Weak bases generally don’t contain hydroxide A. B. C. D. E. I and II III only IV only V only IV and V Extra #22 ANSWER Which of the following is false? I. II. III. IV. V. Strong acids/bases fully dissociate TRUE Weak do notably dissociate TRUE The first hydrogen lost in a polyprotic acid is the most acidic TRUE Strong acids/bases represent an equilibrium condition, they have double arrows in their equation FALSE Weak bases generally don’t contain hydroxide TRUE A. B. C. D. E. I and II III only IV only V only IV and V Strong acids/bases are not represented by “⇋” because they are not an equilibrium condition. They dissociate completely and do not require an ICE table! Extra #23 What property will the salt AlBr3 have in water? A. B. C. D. E. Neutral Acidic Basic Amphiprotic Can not be determined Extra #23 ANSWER What property will the salt AlBr3 have in water? A. B. C. D. E. Neutral Acidic Basic Amphiprotic Can not be determined 1) 2) 3) Split the salt up into its two ions a) Al3+ b) BrDetermine the property of each ion a) Al3+ → cation → transition metal → acts acidic b) Br- → anion →comes from strong acid → acts neutral Compare acidities a) If acidic and neutral, the acidic will outweigh the neutral Extra #24 What is the pH of a 0.400 M HCl solution? A. B. C. D. E. 7.1 13.6 3.0 0.222 0.398 Extra #24 ANSWER What is the pH of a 0.400 M HCl solution? A. B. C. D. E. 7.1 13.6 3.0 0.222 0.398 Extra #25 An equilibrium that strongly favors products has ____ A. B. C. D. E. A value of K << 1 A value of K >> 1 A value of Q >> 1 A value of Q << 1 K=Q Extra #25 ANSWER An equilibrium that strongly favors products has ____ A. B. C. D. E. A value of K << 1 A value of K >> 1 A value of Q >> 1 A value of Q << 1 K=Q K = products/reactants If products are big, then the K value is very big! Extra #26 What is the Kb for the benzoate ion, given that the Ka for benzoic acid is 6.46 x 10-5? A. B. C. D. E. 1.55 x 10-10 6.46 x 109 6.46 x 10-19 3.52 x 10-9 7.43 x 10-5 Extra #26 ANSWER What is the Kb for the benzoate ion, given that the Ka for benzoic acid is 6.46 x 10-5? A. B. C. D. E. 1.55 x 10-10 6.46 x 109 6.46 x 10-19 3.52 x 10-9 7.43 x 10-5 Extra #27 Which statement, A–D, is not correct? If all are correct, respond E. Pure water at 25°C has __________ A. B. C. D. E. Kw = 1.0 × 10–14. pOH = 7. [H3O+] = [OH–] pH = 7. A–D are all correct. Extra #27 ANSWER Which statement, A–D, is not correct? If all are correct, respond E. Pure water at 25°C has __________ A. B. C. D. E. Kw = 1.0 × 10–14. pOH = 7. [H3O+] = [OH–] pH = 7. A–D are all correct. pOH = pH for pure water! They add up to be 14. Kw is the autoionization constant for water. [H3O+] has to be = to [OH-] in order for the pH and pOH to be 7 Extra #28 In the following reaction in aqueous solution, the acid reactant is ________ and its conjugate base product is ________. CH3NH2 + HSO4- ⟷ CH3NH3+ + SO42A. B. C. D. E. CH3NH2; SO42HSO4-; H3O+ CH3NH2; CH3NH3+ HSO4-; CH3NH3+ HSO4-; SO42- Extra #28 ANSWER In the following reaction in aqueous solution, the acid reactant is ________ and its conjugate base product is ________. CH3NH2 + HSO4- ⟷ CH3NH3+ + SO42A. B. C. D. E. CH3NH2; SO42HSO4-; H3O+ CH3NH2; CH3NH3+ HSO4-; CH3NH3+ HSO4-; SO42- CH3NH2 + HSO4- ⟷ CH3NH3+ + SO42Base Acid C.A. C.B. Extra #29 The equilibrium constant for the formation of hydrogen iodide from hydrogen and iodine is 45.0 at a certain temperature. H2(g) + I2(s) ⟷ 2HI(g) Which of the following is true regarding this equilibrium? I. The reaction is product-favored. A. II and III II. The reaction is reactant-favored. B. II and IV III. Equilibrium lies to the right. C. I and IV IV. Equilibrium lies to the left. D. I and III E. None are true, as the concentrations of reactants and products are essentially the same Extra #29 ANSWER The equilibrium constant for the formation of hydrogen iodide from hydrogen and iodine is 45.0 at a certain temperature. H2(g) + I2(s) ⟷ 2HI(g) Which of the following is true regarding this equilibrium? I. The reaction is product-favored. A. II and III II. The reaction is reactant-favored. B. II and IV III. Equilibrium lies to the right. C. I and IV IV. Equilibrium lies to the left. D. I and III (Explanation in speaker notes) E. None are true, as the concentrations of reactants and products are essentially the same Extra #30 Write the equilibrium expression, Keq, for the reaction below: SnO2(s) + 2CO(g) ↔ Sn(s) + 2CO2(g) A. K = [Sn][CO2] / [SnO2][CO] B. K = [Sn][CO2]2 / [SnO2][CO]2 C. K = [CO]2 / [CO2]2 D. K = [CO2]2 / [CO]2 E. K = [SnO2][CO] / [Sn][CO2] Extra #30 ANSWER Write the equilibrium expression, Keq, for the reaction below: SnO2(s) + 2CO(g) ↔ Sn(s) + 2CO2(g) A. K = [Sn][CO2] / [SnO2][CO] B. K = [Sn][CO2]2 / [SnO2][CO]2 C. K = [CO]2 / [CO2]2 D. K = [CO2]2 / [CO]2 E. K = [SnO2][CO] / [Sn][CO2] Extra #31 Butyric acid is responsible for the odor in rancid butter. A solution of 0.25 M butyric acid has a pH of 2.71. What is the Ka for the acid? A. B. C. D. E. 1.5 x 10-5 0.26 2.4 x 10-2 7.8 x 10-3 none of the above Extra #31 ANSWER Butyric acid is responsible for the odor in rancid butter. A solution of 0.25 M butyric acid has a pH of 2.71. What is the Ka for the acid? A. B. C. D. E. 1.5 x 10-5 0.26 2.4 x 10-2 7.8 x 10-3 none of the above Extra #32 The equilibrium constant for the reaction is 17.5: What is the value of the equilibrium constant for the following reaction? A. B. C. D. E. 1.87 x 10-4 5.71 x 10-2 17.5 306 5360 Extra #32 ANSWER The equilibrium constant for the reaction is 17.5: What is the value of the equilibrium constant for the following reaction? A. B. C. D. E. 1.87 x 10-4 5.71 x 10-2 17.5 306 5360 Extra #33 Kc=.105 for the following reaction at 472℃, find Kp. N2+3H2↔2NH3 A. B. C. D. E. 1.17E-6 2.81E-5 7.00E-5 393 199 Extra #33 ANSWER Kc=.105 for the following reaction at 472℃, find Kp. N2+3H2↔2NH3 A. B. C. D. E. 1.17E-6 2.81E-5 7.00E-5 393 199 Extra #34 In the following reaction in aqueous solution, the acid reactant is ________ and its conjugate base product is ________. CH3NH2 + HSO4- ⟷ CH3NH3+ + SO42A. B. C. D. E. CH3NH2; SO42HSO4-; H3O+ CH3NH2; CH3NH3+ HSO4-; CH3NH3+ HSO4-; SO42- Extra #34 ANSWER In the following reaction in aqueous solution, the acid reactant is ________ and its conjugate base product is ________. CH3NH2 + HSO4- ⟷ CH3NH3+ + SO42A. B. C. D. E. CH3NH2; SO42HSO4-; H3O+ CH3NH2; CH3NH3+ HSO4-; CH3NH3+ HSO4-; SO42- Extra #35 Given that kf= 3.09E-2 for the following reaction, find Kr 2A→B where [A]= .15M and [B]=.90M at equilibrium A. B. C. D. E. .0052 7.7E-4 .0057 1.24 6.37 Extra #35 ANSWER Given that kf= 3.09E-2 for the following reaction, find Kr 2A→B where [A]= .15M and [B]=.90M at equilibrium A. B. C. D. E. .0052 7.7E-4 .0057 1.24 6.37 Extra!! 1) Conceptual Questions. Acids, Bases, and Conjugates, Miscellaneous 2) Recognizing Strong versus Weak Acids; Recognizing Basic versus Nonbasic 3) pH Calculations; Relationships between pH and pOH 4) Ka: Sense + Calculations. Using Ka or pKa to Calculate [H+] and/or pH; using pH to calculate Ka or pKa 5) Kb and pKb, Base Strength, and using Kb or pKb to Calculate [OH-], pOH, pH, and/or [H+] 6) Recognizing Acid/Base Properties when Ionics are Dissolved in Water