B
8
8
0
0
A
8
10
18
18
18
18
8
8
8
8
8
D
C
E
2
20
20
20
20
20
20
12 20
29
G
3
F
10
30
30
30
33
23
30
32
30
14
32
26 6 32
32
I
6
36
39
H
32
39
2
32
39
J
7
39
39
K
2
41
41
1.WHAT IS THE EXPECTED (ESTIMATED) TIME FOR ALL ACTIVITIES?
ANS 41 WEEKS
2.WHAT IS THE VARIANCE FOR ALL ACTIVITIES?
ANS A = [(10-4)/6]2 = 1.00
F = [(20-6)/6]2 = 5.44
K = [(3-2)/6]2 = 0.03
2
2
B = [[24-2)/6] =13.44
G = [(4-2)/6] =0.11
2
2
C = [[16-8)/6] = 1.78
H = [(2-2)/6] = 0.00
2
2
D = [[10-4)/6] = 1.00
I = [(6-6)/6] = 0.00
2
2
E = [[3-1)/6] = 0.11
J = [(12-4)/6] = 1.78
VARIANCE = 1.00 + 13.44 + 1.78 + 1.00 + 0.11 + 5.44 + 0.11 + 0.00 + 0.00 + 1.78 + 0.03 = 24.69
3.BASED ON THE CALCULATION OF ESTIMATED TIMES, WHAT IS THE CRITICAL PATH?
ANS A - B - E - F - H - J - K
C
4.WHAT IS THE ESTIMATED TIME OF THE CRITICAL PATH?
ANS 41 WEEKS
5.WHAT IS THE ACTIVITY VARIANCE ALONG THE CRITICAL PATH?
2
2
ANS A = [(10-4)/6] = 1.00
F = [(20-6)/6] = 5.44
2
B = [[24-2)/6] = 13.44
H = [(2-2)/6]2 = 0.00
2
2
C = [[16-8)/6] = 1.78
J = [(12-4)/6] = 1.78
E = [[3-1)/6]2= 0.11
K = [(3-2)/6]2 = 0.03
VARIANCE = 1.00 + 13.44 + 1.78 + 0.11 + 5.44 + 0.00 + 1.78 + 0.03 = 23.58
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