ASSIGNMENT UNIT-1
Topic: NUMBER SYSTEM CONVERSIONS AND BINARY
ARITHMETIC
Q.1:
Q.2:
Q.3:
Q.4:
Q.5:
Q.6:
Convert the following binary numbers to decimal equivalent.
(a)
100 (b)
11010 (c)
10110010
(d)
1.001
(e)
110100.010011 (f)
11010.10110 (g)
1000001.111
Convert the following decimal numbers to binary equivalent.
(a)
16
(b) 247
(c) 962.84
(d)
0.0132
(e)
6.74
Convert the following octal numbers to their decimal
equivalent:
(a)
148
(b)
2368
(c)
(e)
0.2548
(f)
(16742.3)8
14328 (d)
(g)
0.438
(206.104)8
Convert the following decimals numbers to their octal
equivalent:
(a)
29
(b)
68
(c)
125 (d)
243.67
(e)
419.95
(f)
645.7 ( g)
39.4475 (h) 49.21875
Convert the following octal numbers to their binary
equivalent:
(a)
138
(b)
278
(c)
658
(d)
124.3758
(e)
217.4368
Convert the following binary numbers to their octal
equivalent:
(a)
10110010
(b)
10101101
(c)
1110101
(d)
10111.101
(e)
111010.001
Q.7:
Convert 18  24 to binary form and then perform binary
multiplication.
Q.8:
Convert 58.75  23.5
operation.
Q.9:
Add the following binary numbers:
11
(a)
(b)
+11
…. …..
to binary form and then perform
1011
+ 1101
……….
(c)
101011
+ 110101
………...
(d)
1110101
+ 1011111
…………
Q.10: Add the following binary numbers:
(a)
1011
+ 1101
(b)
1010110
1011
1110101
…….
+ 1001010
….……….
(c)
1010110
1111011
+ 1011111
……….
(d)
10110110
11010101
+ 11010110
………...
Q.11: Subtract the following binary numbers:
(a)
11
–10
…. …..
(b)
111
– 101
……….
(c)
101011
– 100101
…............
(d)
11100001
 10011110
…………
Q.12: Multiply the following binary numbers:
(a)
11  11
(b)
101  10 (c) 110101
(d)
1011  1101
(e)
1010  101
Q.13: Divide the following binary numbers:
(a)
110 10
(b)
10110  10
(d)
101101 1.1
(e)
11001.11 1101
Q.14: Perform each of the subtraction operations indicated below using
addition andthe two’s complement of the subtrahend.
(100101)2 – (11011)2
(1101011)2 – (111010)2
(1110111)2 – (10110111)2
Q.15: Write the following decimal numbers in eight bit two’s complement, do the
addition/subtraction, convert your answer back to decimal.
a)
3 ++ 11
b) +125 +− 40
−