(b) Calculate the magnitude and direction (clockwise or counterclockwise) of the current in this
case.
magnitude
__________ A Suppose the polarity of the battery E, in the figure below is reversed, where R =
9.50 and 8-12.9 V. 622 n 15.1 WWw
Solution
the battery will oppose the other battery when the polarity is reversed
this is because their positive terminals are connected to one another.
so, the resulting EMF is,
emf = 15-12.9 = 2.1 V
hence, the current is,
I = emf/R
= 2.1 /(15.1+6.22+9.5)
= 0.0681 A
= 68.1 mA, CLOCKWISE