AEE465/565 – Rocket Propulsion – Professor Dr. Werner J.A. Dahm
Thrust Performance
Isentropic Nozzle Flow
Total-to-Static Relations:
Normal Shock Relations: (M = Mach before shock)
Thrust Equation:
π = πΜπ ππ + (ππ − π∞ )π΄π
*First term is jet (momentum) thrust, the second term is
pressure thrust.
π = πΜπ πππ
*Valid in all cases
Equivalent Velocity:
Total Relations:
2
ππ‘ 2
(πΎ + 1) π
=[
]
(πΎ − 1) π2 + 2
ππ‘ 1
ππ‘
πΎ−1 2
= [1 +
π ]
π
2
πΎ+1
]
2πΎπ 2 − (πΎ − 1)
πΎ
πΎ−1
π2 2πΎπ 2 − (πΎ − 1)
=
π1
πΎ+1
1
πΎ−1
π2 [2πΎπ 2 − (πΎ − 1)][(πΎ − 1)π2 + 2]
=
(πΎ + 1)2 π2
π1
Specific Impulse:
πΌπ π =
π22 =
1
πΎ+1 2
πΎ−1
2
)
πΜπ =
[πΎ (
πΎ+1
√π
ππ‘
Thrust Coefficient:
π
(ππ )πππ‘π’ππ =
ππ‘ π΄∗
(πΎ − 1)π12 + 2
2πΎπ12 − (πΎ − 1)
πΎ+1
]
(ππ )πππππ
]} +
(ππ − π∞ ) π΄π
ππ‘
π΄∗
πΎ−1
πΎ
2
2 πΎ−1
ππ
)(
) [1 − ( )
= πΎ {(
πΎ−1 πΎ+1
ππ‘
1
2
]}
*Isentropic and fully expanded nozzle flow (ππ = π∞ )
1 πΎ+1
1
πΎ+1 2
(ππ )πππππ π£πππ’π’π
given Exit Mach number or solve numerically to
find Exit Mach from
1
2
πΎ+1
π΄
1
2
πΎ − 1 2 2 πΎ−1
) [1 +
= {(
π ]}
π΄∗ π πΎ + 1
2
π΄∗
πΎ−1
πΎ
Oblique Shock Jump Relations:
Isentropic Area-Mach Number Relation:
π΄π
(ππ )ππ πππ‘πππππ =
2
2 πΎ−1
ππ
)(
) [1 − ( )
πΎ {(
πΎ−1 πΎ+1
ππ‘
^This is valid for any choked nozzle.
*Find
πππ
π
=
π0 πΜπ π0
*Equivalent time that 1 lbf of combustion products could
produce 1 lbf of thrust, units of seconds
(πΎ + 1)π2
π2
=
π1 (πΎ − 1)π 2 + 2
πΜ(π₯) = πΜ∗ = π∗ π’∗π΄∗
(ππ − π∞ ) π΄π
π
=
πΜπ
πΜπ
*Would be the exit velocity from a fully expanded nozzle
that produces same thrust as actual nozzle.
Shock Jump Relations:
Mass Flow Rate:
ππ‘ π΄∗
[
πππ = ππ +
1
πΎ−1
ππ‘2
=1
ππ‘1
ππ‘
πΎ−1 2
= [1 +
π ]
π
2
ππ‘
πΎ−1 2
= [1 +
π ]
π
2
πΎ
πΎ−1
2
2 πΎ−1
)(
) }
= πΎ {(
πΎ−1 πΎ+1
π΄π
π΄∗
Angle-Mach Relations:
*Once ππ is known, can solve or ππ and ππ using
isentropic relations (above).
Nozzle Choking Criterion:
πΎ
πΎ−1
ππ‘
πΎ+1
)
=(
π∗
2
π22 sin2(π − πΏ) =
ππ‘ π ∗ = 1
Trajectories
Tsiolkovsky Rocket Equation (velocity increment):
π0
Δπππ’ππ = πππ ln ( ) − π0 π‘π
ππ
(πΎ − 1)π12 sin2(π) + 2
2πΎπ12 sin2(π) − (πΎ − 1)
Total Relations:
πΎ
ππ‘ 2
*Unchoked if,
ππ‘ 1
πΎ
ππ‘
πΎ + 1 πΎ−1
)
<(
π∗
2
Exit Velocity:
ππ = ππ ππ
*Fully expanded flow in a vacuum (infinite nozzle length)
(πΎ + 1)π12
cot(πΏ) = tan(π) [
− 1]
2(π12 sin2(π) − 1)
=[
1
πΎ−1
(πΎ + 1) π12 sin2 (π) πΎ−1
πΎ+1
]
[
]
(πΎ − 1) π12 sin2 (π) + 2
2πΎπ12 sin2 (π) − (πΎ − 1)
Shock Jump Relations:
π2 2πΎπ12 sin2(π) − (πΎ − 1)
=
π1
πΎ+1
π€βπππ, ππ = √πΎ π
ππ
πΎ−1
πΎ
2πΎ
ππ
ππ = {
π
π [1 − ( )
πΎ−1 π‘
ππ‘
π2 [2πΎπ12 sin2(π) − (πΎ − 1)][(πΎ − 1)π12 sin2(π) + 2]
=
(πΎ + 1)2 π12 sin2(π)
π1
1
2
]}
(πΎ + 1)π12 sin2(π)
π2
=
π1 (πΎ − 1)π12 sin2(π) + 2
Where,
ππ½
(8314
)
π
Μ
πππ β πΎ
=
ππ
ππ
*Therefore, lower ππ gives higher ππ → higher thrust
π
=
Isentropic Model of Atmosphere:
Aerodynamic Drag:
1
π· = ππ 2 π΄πΆπ·
2
π
*Circular cross-section with diameter d has area π΄ = π 2
4
Gravitational Force:
π
π 2
)
π(π§) = ππ (
π
π + π§
*As a function of altitude π§ in π,
earth radius π
π = 6378 (103 ) π,
and acceleration of gravity at surface ππ = 9.8 π/π 2
Time and Altitude at Burnout:
πΎ
π(π§)
πΎ − 1 π§ πΎ−1
( ∗ )]
≈ [1 −
ππ
2
π§
*Where surface pressure, ππ = 101.3 (103 )
Nozzle Expansion:
- Larger velocity increment due to high thrust for short
burn time than due to lower thrust for long burn time.
- Short burn at high thrust reduces energy consumed
lifting propellant (for vertical launch)
βπ = πππ {1 −
π
π
*First term is dependent on Mass Ratio π
= ( 0 )
π2
ππ
∗
π§ = 8404 π
π‘π = (
Summerfeld Separation Criterion:
When nozzle flow is “highly” over expanded, when
ln(π
)
1
} π‘ − π π‘2
π
−1 π 2 π π
ππ
)
πΜπ
π‘π = (π‘ − π‘0 )
ππ
π∞
gets too small, flow in nozzle separates when,
ππ
β²πΎ
π∞
for 0.25 ≤ πΎ ≤ 0.4
*Boundary layer separation can cause highly turbulent
recirculating flow
Maximum Vehicle Altitude (vertical launch):
1 (Δππ )2
βπππ₯ = βπ +
2 ππ
βπππ₯ =
πππ2 (ln(π
))2
π
− πππ π‘π {
ln(π
) − 1}
2ππ
π
−1
*Minimizing π‘π maximizes βπππ₯
Rocket Staging
Staging Methods:
Velocity Increments for an Optimally Staged Rocket:
Δπ due to burnout of the π th-stage,
(ππ )π = (πππ ) ln(π
π ) − π0 (π‘π )π
π
Final Δπ imparted on final payload ππΏ of stage π,
π
Circular Orbits: π(π) = π
= ππππ π‘πππ‘, π < 0, π = 0
Velocity:
π
π=√
π
Period:
ππ = ∑(π‘π )π
π
3
π = 2π√
π
π=1
π
1 + ππ
(ππ )π = ∑ [(πππ ) ln (
)] − ππ ππ
π
ππ + ππ
π=1
(Δππ )π = πππ π ln {π + (1 − π) [
1 −1
ππΏ π
π0
] }
Escape from Circular Orbit:
π
Δπ1 ≥ (√2 − 1)√
π
− ππ ππ
Ideal Case (infinitely many stages):
(Δππ )π→∞ = πππ (1 − π) ln [
*Equivalent Velocity πππ
=
π
πΜπ
π0
] − ππ ππ
ππΏ
Parabolic Trajectories: (not orbit) π = 0, π = ∞, π = 1
π∞ = 0
Escape Velocity:
2π
πππ π = √
π
≈ same for all stages
Escape from planet surface:
Orbital Dynamics
2π
πππ π = √
π
ππππππ‘
Gravitational Parameter:
π β π2
π€βπππ πΊ = 6.67 × 10−11
ππ
π = πΊπ ′
Radial Position (from vehicle to center of planet):
π(1 − π 2 )
1 + π cos(π)
π=
Semimajor Axis:
π = ππππ
1
1−π
π=
1
(π + ππ )
2 π
Eccentricity:
π=
ππ − ππ
ππ + ππ
π = √1 −
π2
π2
π =1−
ππππ
π
Circularization Burn:
Circularize at ππ :
2ππ
π
Δπ1 = √ β [1 − √
]
ππ
ππ + ππ
Circularize at ππ :
Vis-Viva:
Stage Mass Relation: π-stage vehicle, the π th-stage has,
π0π = πππ + πππ + ππΏπ
Payload Ratio:
π0(π+1)
ππΏπ
ππΏπ
ππ ≡
=
=
π0π − π0(π+1) π0π − ππΏπ πππ + πππ
*Equal for all similar stages, ππ = π(π+1) = β― = ππ
ππππ‘ππππ =
(ππΏ⁄π )
2 1
π = π( − )
π π
2
0
1⁄
π
Structural Coefficient:
πππ
πππ
πππ
ππ =
=
=
π0π − π0(π+1) π0π − ππΏπ πππ + πππ
*Equal for all similar stages, ππ = π(π+1) = β― = ππ
π0π
π0π
1 + ππ
=
=
π0π − πππ πππ + ππΏπ ππ + ππ
Inclination Change: (circular orbits)
ππ = π(1 − π)
Perigee Velocity:
π 1+π
)
ππ = √ (
π 1−π
π 2ππ
ππ = √
ππ (ππ + ππ )
1
*Both other angles are: π − π
2
π
π
Δπ1 = 2√ sin ( )
π
2
Apogee Radius:
ππ = π(1 + π)
Apogee Velocity:
π 1−π
)
ππ = √ (
π 1+π
2ππ
π
ππ = √
ππ (ππ + ππ )
Orbital Period:
π ππ
ππ = √
π ππ
Orbital Rendezvous:
Lead Angle:
πΌπΏ =
π (π
1 + π
2 )3
√
2
2(π
2)3
Transfer Time:
π3
π = 2π√
π
Mass Ratio:
π
π =
π
2ππ
Δπ1 = √ β [1 − √
]
ππ
ππ + ππ
Perigee Radius:
1⁄
π
π
(1 − πΏ⁄π )
0
Δ = −π√π 2 − 1
Orbital Maneuvers
*Where b = semi-minor axis
π < 1 → ππππππ π
π = 1 → ππππππππ
π > 1 → βπ¦πππππππ
π = 0 → ππππππ
*For Parallel Staging: Mass of 1st stage propellant from
large tank is equal to the total mass of the large tank’s
propellant times the fraction of the 1st stage burn time
over the total burn time of the 1st and 2nd stages.
Hyperbolic Trajectories: (not orbit) π > 0
Excess Velocity:
π
π∞ = √2π
π∞ = √
−π
Asymptote Angle:
1
π∞ = π − cos −1 ( )
π
Turning Angle:
1
πΏ = 2 sin−1 ( )
π
Miss Distance:
πππ = ππ»πβππππ =
π (π
1 + π
2 )3
√
2
2π
Intercept Opportunity Times:
Energy (per unit mass):
π=−
π
2π
1
1
1
=
−
π (ππΆ )1 (ππΆ )2
π
π
π€βπππ (ππΆ )π = 2π√
π
Orbital Transfers
Standard Gravitation Parameters
Hohmann Transfer:
Combustion Tap-Off Systems:
3
Circular Orbit Velocities:
π
(ππΆ )1 = √
π
1
π
(ππΆ )2 = √
π
2
Transfer Orbit Parameters: (Trans time, see Rendezvous)
ππ = π
1
ππ = π
2
π 2π
2
ππ = √
π
1 π
1 + π
2
Body
π
π = πΊπ ′ [ 2 ]
π
Sun
1.327 × 1020
Mercury
2.203 × 1013
Venus
3.249 × 1014
Earth
3.986 × 1014
(Moon)
4.903 × 1012
Mars
4.283 × 1013
Jupiter
1.267 × 1017
Saturn
3.793 × 1016
Uranus
5.794 × 1015
Neptune
Pluto
6.837 × 1015
1.108 × 1012
Propellant Feed Systems
Pressure-Fed Systems:
π 2π
1
ππ = √
π
2 π
1 + π
2
Velocity Increments:
*Uses combustion product gas from combustion chamber
to drive gas turbine that then drives pumps.
Open Systems:
- Turbine exit gas pressure low, dumped overboard
Closed Systems:
- Turbine exit gas dumped into nozzle at low pressure
location to add πΜπ at nozzle exit
*Moderate/high thrust (Saturn I-B/Blue Origin)
Gas Generator Systems:
π
2π
2
Δπ1 = √ [√
− 1]
π
1
π
1 + π
2
π
2π
1
Δπ2 = √ [1 − √
]
π
2
π
1 + π
2
Bielliptic Transfer:
Deliver Pressure > Tank Pressure,
πβ = π(π + π)β
Circular Orbit Velocities:
π
(ππΆ )1 = √
π
1
π
(ππΆ )2 = √
π
2
Transfer Orbit Parameters: (π
ππ can be chosen)
π
1 = π
πππ1
*Part of fuel and oxidizer are burned in preburner to
produce high-pressure gas that drives turbopumps.
- Preburner operated very fuel-rich to keep
temperature sufficiently low
- Fuel-rich exhaust dumped overboard (open) or
dumped into nozzle (closed)
- Power controlled by adjusting fuel/ox rates into
preburner
- Can achieve higher CC pressure than expander sys.
Staged Combustion Systems:
π
ππ = π
πππ1
π
2 = π
πππ2
π
ππ = π
πππ2
1
π ππ1 = (π
1 + π
ππ )
2
1
π ππ2 = (π
2 + π
ππ )
2
Expander Systems:
Transit Time:
πππ = π
√(π ππ1 )3 + √(π ππ2)3
√π
Velocity Increments:
2
1
π
)−√
Δπ1 = √π ( −
π
1 π ππ1
π
1
2
1
2
1
) − √π (
)
Δπ2 = √π (
−
−
π
ππ π ππ2
π
ππ π ππ1
π
2
1
)
Δπ3 = √ − √π ( −
π
2
π
2 π ππ2
*Fuel is expanded to gaseous form to drive turbine that
powers pumps which then push propellant into CC.
- Low/moderate thrust applications
- Often used for upper stage engines
*All propellant is burned in two stages (nothing wasted).
First in fuel-rich preburner, then in main CC.
- Allows very high CC pressures (high thrust)
- Can be used with any liquid propellants
- More efficient than gas generator (all fuel burned)
- Requires very high-pressure turbopumps
Propellants and Aerothermochemistry
Propellant Types:
Hydrocarbon Combustion:
Turbines:
Liquid Propellants:
Fuels:
a) Cryogenic
- LH2 – liquid hydrogen (20 K) “deep cryogen”
- LCH4 – liquid methane (111 K)
b) Non-cryogenic
- RP-1 – kerosene [πΆ1 π»1.96 ]
- ethyl alcohol – [πΆ2 π»5 ππ»]
c) Hypergolic (πΈπ ≤ 0) (reacts on contact with oxi.)
- hydrazine [π2 π»4 ]
- monomethyl hydrazine (MMH)
- unsymmetrical dimethyl hydrazine (UDMH)
Oxidizers:
a) Cryogenic
- LOX – liquid oxygen
- LF2 – liquid fluorine
- FLOX – fluorine-enhanced LOX
- N2O4 – dinitrogen tetroxide
b) Non-cryogenic
- N2O – nitrous oxide
- N2O4 – dinitrogen tetroxide
- ClF5 – chlorine pentafluoride
Overall Stoichiometric Reaction:
π
π
1 πΆπ π»π + (π + ) π2 → ππΆπ2 + π»2 π
4
2
π = ππππππ ππ‘πππ , π = βπ¦ππππππ ππ‘πππ
Application of 1st Law:
(Δβπ‘ )1,2 = π1,2 − π€1,2 = 0
Monopropellants:
* Both fuel and oxidizer are contained in the same
molecule; contact with a catalyst bed initiates reaction
(breaks oxidizer and fuel components apart).
* Usually used for RCS and in-space propulsion at low-mid
thrust applications.
- hydrazine (N2H4) + granular Al w/iridium coating
- hydrogen peroxide (H2O2) + many possible catalysts
- nitromethane (CH3NO2)
- ethylene oxide (C2H4O)
- nitrous oxide (N2O)
- hydroxylammonium nitrate (HAN) (H4N2O4)
Solid Propellants:
* Both fuel and oxidizer are initially in solid form.
Homogenous Propellants:
* Fuel and oxidizer are contained in the same
molecule or in a homogeneous mixture.
- nitroglycerine + nitrocellulose
C3H5(NO2)3 + C6H7O2(NO2)3
- Single/Double/Triple base propellants
Metal powders often added to increase heat of
combustion.
Heterogeneous (composite) Propellants:
* Heterogeneous mixture of oxidizing crystals held in
an organic plastic-like fuel “binder”
a) Fuel Component (common binders)
- hydroxyl-terminated polybutadiene (HTPB)
- rubber/asphalt
b) Oxidizer Component (ground crystals of one or
more of the following)
- ammonium perchlorate (AP)
- ammonium nitrate (AN)
- nitronium perchlorate (NP)
- potassium perchlorate (KP)
- potassium nitrate (PN)
- cyclotrimethylene trinitomine (RDX)
- cyclotetramethylene tetranitramine (HMX)
* The combination of fuel/ox specifies the propellant
(e.g. AP-HTPB, KP-HTPB, …)
Many possible combinations.
→ βπ‘2 − βπ‘1 = 0
→ πΆπ (ππ‘2 − ππ‘1 ) = 0
Mixture Ratio:
ππ
π = ( 2)
ππ
∴ ππ‘2 = ππ‘1
Turbine Work:
Stoichiometric Mixture Ratio:
32π + 8π
ππ =
12π + π
Equivalence Ratio:
ππ
π=
π
π = 1 → π π‘πππβπππππ‘πππ πππππ’π π‘πππ
π > 1 → ππ’ππ − πππβ πππππ’π π‘πππ
π < 1 → ππ’ππ − ππππ πππππ’π π‘πππ
Molar Enthalpy of Combustion:
ΔβΜπΆ = [∑ π΅πππ πΈπππππ¦ ]
π
− [∑ π΅πππ πΈπππππ¦ ]
πππππ‘
π
ππππ
ΔβΜπΆ < 0 → ππ₯ππ‘βπππππ
ΔβΜπΆ > 0 → πππππ‘βπππππ
Convert to mass-specific enthalpy:
ΔβΜπΆ
ΔβπΆ =
πππ»πΆ
πππ»πΆ = 12π + 1π [
ππππ
]
π
Convert to [ππ½⁄ππ]:
ΔβπΆ [
ππππ
1000 πππ 1000π 4.1814 π½
1 ππ½
)(
)(
)(
)
]β(
π
ππππ
ππ
πππ
1000π½
Turbopumps and Turbines
Turbopumps:
Shaft Power from Turbine:
πΜ = π β ΩΜ
Ideal Pump Work:
|π€|πππππ =
1
|π|ππππππππ = π π Δππ‘
π
Temperature Change Across Turbine:
Δππ‘
Δπ = (1 − π π )
π β ππ
Turbine Work: (per unit mass)
|π€π | = |πΆπ (ππ‘π − ππ‘π )|
Turbine Power:
πΜπ = πΜ|π€π |
Turbine Stage Efficiency:
|π€|
ππ =
|π€|π
Total Turbine Efficiency:
π
1 − ( π‘3 )
ππ‘1
ππ =
πΎ−1
ππ‘3 πΎ
1−( )
ππ‘1
Turbine Total Temperature Ratio:
1
(π − ππ‘1 )
π π‘2
Ideal Pump Power:
1
|π€Μ |πππππ = πΜ|π€|πππππ = πΜ (ππ‘2 − ππ‘1 )
π
Pump Efficiency:
|π€|πππππ
|π€Μ |πππππ
ππ =
=
|π€|πππ‘π’ππ |π€Μ |πππ‘π’ππ
Non-Ideal Pump Work:
11
(π − ππ‘1 )
|π€|πππ‘π’ππ =
ππ π π‘2
Non-Ideal Pump Power:
1 1
(π − ππ‘1 )
|π€Μ |πππ‘π’ππ = πΜ|π€|πππ‘π’ππ = πΜ
ππ π π‘2
*ππππ π‘βπ ππππ£π
π
Δππ‘ = (ππ‘2 − ππ‘1 ) = π€π ππ
πΜ
1st Law for Liquid Flow Through Pump:
1
1
ππ = (π2 − π1 ) + (π2 − π1 ) + (π22 − π12 ) = |π€|
π
2
1
ππ = (π2 − π1 ) + (ππ‘2 − ππ‘1 ) = |π€|
π
Temperature Change Across Pump:
1 − ππ (ππ‘2 − ππ‘1 )
(π2 − π1 ) = (
)
ππ
π β ππ
πΎ−1
πΎ
ππ‘3
ππ‘3
= 1 − π π [1 − ( )
ππ‘1
ππ‘1
]
Turbine Total Pressure Ratio:
πΎ
ππ‘3
1
ππ‘3 πΎ−1
= [1 − (1 − )]
ππ‘1
ππ
ππ‘1
Total-to-Static Temperature Relation:
πΎ − 1 2 −1
π3 = ππ‘3 [1 +
π3 ]
2
Total-to-Static Pressure Relation:
πΎ
πΎ − 1 2 −πΎ−1
π3 ]
2
Entropy Change Across Turbine:
ππ‘3
ππ‘3
Δπ = π 3 − π 1 = πΆπ ln ( ) − π
ln ( )
ππ‘1
ππ‘1
πΎ−1
)
π
= πΆπ (
πΎ
π
= πΆπ£ (πΎ − 1)
Temperature-Velocity Relation:
π2
(ππ‘ − π) =
2 β πΆπ
π3 = ππ‘3 [1 +
Nozzle Design
Simple Conical Nozzles:
Axial Thrust:
1 + cos(πΌ)
πΜπ ππ + (ππ − π∞ )π΄π
2
*See notes for Rao and TOP nozzle stuff
πππ₯πππ =
Combustion Chamber Performance
DOF and Molecular Energy
Non-Isentropic Nozzle Flow
(π·ππΉ)πππ‘ = 0
Application of 1st Law:
(Δβπ‘ )2,π = π2,π − π€2,π = 0
→ βπ‘2 − βπ‘π = 0
→ πΆπ (ππ‘2 − ππ‘π ) = 0
∴ ππ‘2 = ππ‘π
→ (π·ππΉ)ππ£πππ = 3
Temperature-Velocity Relation:
Monatomic Molecules:
(π·ππΉ)π‘ππππ = 3
Combustion Chambers:
(π·ππΉ)π£ππ = 0
Diatomic Molecules:
(π·ππΉ)π‘ππππ = 3
(ππ‘ − π) =
Total Pressure Ratio:
Δπ
ππ‘π
= π− π
ππ‘2
*where, ππ‘π < ππ‘2 and Δπ > 0
(π·ππΉ)π£ππ = 2
(π·ππΉ)πππ‘ = 2
→ (π·ππΉ)ππ£πππ = 7
Total-to-Static Pressure Ratio:
Nozzle Efficiency:
2(3π − 5) ππ ππππππ
(π·ππΉ)πππ‘ = {
2(3π − 6) ππ πππππππππ
5 + 2(3π − 5) ππ ππππππ
→ (π·ππΉ)ππ£πππ = {
6 + 2(3π − 6) ππ πππππππππ
Thrust Coefficient:
π
πΆπ =
ππ‘2 β π΄∗
Thrust:
ππ‘2 β π΄∗
) πΆπ
π = πΜπ (
πΜπ
C* “Characteristic Velocity”:
ππ‘2 β π΄∗
πΆ∗ =
πΜπ
1
πΎ+1 2
∗
πΆπππππ
ππ‘2
2 πΎ−1
) ]
=
√π
ππ‘2 [πΎ (
ππ‘1
πΎ+1
C* Efficiency:
ππΆ ∗ =
∗
πΆπππ‘π’ππ
∗
πΆπππππ
Specific Heat and Gas Constant Relations:
Specific Heat - Constant Volume:
Specific Impulse:
πΌππ
Energy Stored in One Molecule:
1
π ′ = ππ(π·ππΉ)πππ‘ππ£π
2
π
Μ
8.314 π½⁄πππ β πΎ
(π΅πππ‘π§ππππ πΆπππ π‘πππ‘)
π=
=
π΄π£ 6.022 × 1023 ππππ‘
πππ
1
πΜ = π΄π£ β π ′ = π
Μπ β (π·ππΉ)πππ‘ππ£π (πππ ππππ)
2
1
π = πΜ ⁄ππ = π
π β (π·ππΉ)πππ‘ππ£π (πππ πππ π )
2
*(π·ππΉ)πππ‘ππ£π depends on temperature
- Low T = only trans. active
- Med T = trans. and rot. active
- High T = trans., rot., and vib. are active
1
= πΆ ∗ πΆπ
π
Pressure Ratio:
π2 (1 + πΎπ12 )
=
π1 (1 + πΎπ22 )
Temperature Ratio:
π2
1 + πΎπ12
π2 2
)
=[
2] β (
π1
1 + πΎπ2
π1
Total Temperature Ratio:
πΎ−1 2
2
1+
π2
ππ‘2
1 + πΎπ12
π2 2
2
)
( )
=[
]β(
2
πΎ−1 2
ππ‘1
1
+
πΎπ
π1
2
1+
π1
2
ππ‘2
π1,2
=
+1
ππ‘1 πΆπ ππ‘1
Total Pressure Ratio:
πΎ
πΎ − 1 2 πΎ−1
1+
π2
ππ‘2
1 + πΎπ12
2
)
=[
]
β(
πΎ
−
1
ππ‘1
1 + πΎπ22
1+
π12
2
Combustion Chamber-to-Throat Area Ratio:
1πΎ+1
π΄πΆ
1
2
πΎ − 1 2 2πΎ−1
{(
) [1 +
=
π2 ]}
π΄∗ π2 πΎ + 1
2
Thermal Choking Criterion:
(1 + πΎπ12 )2
ππ‘2
1
≥
ππ‘1 2(1 + πΎ) [1 + πΎ − 1 π 2 ] π 2
1
1
2
*subtract 1 from result to get max allowable ππ‘2
1
πΆΜπ = π
Μ (π·ππΉ)πππ‘ππ£π
2
1
πΆπ = π
(π·ππΉ)πππ‘ππ£π
2
Specific Heat - Constant Pressure:
1
πΆΜπ = π
Μ [1 + (π·ππΉ)πππ‘ππ£π ]
2
1
πΆπ = π
[1 + (π·ππΉ)πππ‘ππ£π ]
2
Gas Constant Relations:
π
= πΆπ − πΆπ
π
Μ = πΆΜπ − πΆΜπ
*given πΆπ and πΎ
π
= πΆπ (1 −
πΆπ
1
πΎ−1
) = πΆπ (1 − ) = πΆπ (
)
πΆπ
πΎ
πΎ
*given πΆπ and πΎ
πΆπ
π
= πΆπ − πΆπ£ = πΆπ ( − 1) = πΆπ (πΎ − 1)
πΆπ
Specific Heat Ratio:
2
πΎ =1+
(π·ππΉ)πππ‘ππ£π
Monatomic:
(π·ππΉ)πππ‘ππ£π = 3 (independent of temp.)
2
→πΎ =1+
= 1.667
(3)
Diatomic:
- Medium temp
2
(π·ππΉ)πππ‘ππ£π = 5 → πΎ = 1 +
= 1.4
(5)
- High temp
2
(π·ππΉ)πππ‘ππ£π = 7 → πΎ = 1 +
= 1.286
(7)
πΎ
πΎ−1
(πΎ − 1)ππ2
ππ
1
= {1 − [
]}
ππ‘2
ππ 2 + (πΎ − 1)ππ2
Polyatomic Molecules:
(π·ππΉ)π‘ππππ = 3
2 ππ ππππππ (πΆπ2 )
(π·ππΉ)π£ππ = {
3 ππ πππππππππ (πππ ππ‘βπππ )
π2
2 β πΆπ
ππ =
πΎ − 1 2 −1
ππ ]
2
πΎ−1
π πΎ
1−( π)
ππ‘2
1 − [1 +
Area-Mach Relation:
π΄π
=
π΄∗
1 πΎ+1
πΎ
1
2
πΎ − 1 2 2 πΎ−1
1 πΎ − 1 2 −πΎ−1
{(
) [1 +
ππ ]}
β {1 + (1 − )
ππ }
ππ πΎ + 1
2
ππ
2
*from resulting ππ , get:
→ ππ from total-to-static (above)
πΎ − 1 2 −1
→ ππ = ππ‘π [1 +
ππ ]
2
πΎ−1
)
→ ππ = √πΎπ
ππ π€βπππ, π
= πΆπ (
πΎ
→ ππ = ππ β ππ
→ π = ππ ππ + (ππ − π∞ )π΄π
Non-Isentropic Thrust Coefficient:
πΎ+1
2
2 πΎ−1
ππ
πΆπ = πΎ {ππ (
)(
)
[1 − ( )
πΎ−1 πΎ+1
ππ‘2
πΎ−1
πΎ
1
2
]} +
(ππ − π∞ ) π΄π
ππ‘2
π΄∗
Injectors and Droplet Vaporization
Droplet Characterization:
Droplet Diameter Probability:
1
ππππ (π· + ππ·)
2
ππ·
*Sauter Mean Diameter (SMD): the droplet diameter with
same surface-to-volume ratio as the entire spray.
*Weber Number: ratio of inertia (mass) to surface tension
*Ohnesorge Number: ratio of friction to surface tension
πππ·
= π β ππ π β πβπ
β
β
πππΆπΆ π πβπΆπΆ
(πππ·)πΆπΆ = (πππ·)πππ β ( πΆπΆ ) (
) (
)
βπππ πππππ
πβπππ
π(π·) =
Droplet Vaporization:
Heat of Vaporization: (heat flux into droplet)
πΜπ β Δβπ = πΜππ
π€βπππ,
ππ
Μ
πππ = −π |
β 4ππ
2
ππ π
(π‘)
ππ
πΜπ = −4πππΏ π
2 (π‘)
ππ‘
Droplet Diameter: (as function of time)
8π
) ln(1 + π΅) β π‘
π· 2 (π‘) = π·0 − (
ππΏ πΆπ
πΆπ (π∞ − ππ )
π΅≡
ΔhV
Vaporization time:
ππΏ πΆπ
π·02
π‘π = π·02
=
8π ln(1 + π΅) ππ