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10-25 - Discussion

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D- lls) -1321£
At -2
Ll -6
.
g)
0.362gal
0.945
×
1m01 At
26.98gal
goby
×
2m01
1m01 Cla
0.362
Ah
,
11;!¥gµ×}mm!¥ 71%11=14380102
✗
0.997g Alas produced
percent yield
=
0,711×100=84.49
1m01
Allbx
70.9g 612×3 molds
see
:
2mdAK% 1333488143
2mA At
Limitinyreatmt
Option 2
0.362gal
0.945yd
LAI ↳ (s )
-
:
Allots
133.348A 143
AKI}
1.79g
-_
1m01 Allots
1.18g
HONCIBRIF
Alas
Cla
how much
required
=
since
the
have
we
amount
limiting
reactant
.
%
less than
required, 42
is the
is
used with Al
=%
Dissolve
to
to
114.77g
make
KBR
1.00L
a
Mda#
114.77 gkbhrx
enough
water
solution
Motor ( m)
=
m÷of
" " " " " " " " " ""
in
.ogkBr
[KBr]=°?%YYm#
Incursion
=
into
=
0.964M
solute
{
Dilution
of solution
"
"
:
"
""
*
"
TBebe
Molarity
"
" "
Rafter
✗
Dilute
Volume
to
→
Mill
,
=
2.73
0.964M ( tool
=
Mavs
L
Ma( 2.731)
ME 0.353M
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