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TOM Lab Manual - Student Copy

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Marwadi Education Foundation Group of Institutions
Department of Mechanical Engineering
EXPERIMENT NO. 1: – Flywheel
AIM
Study about working of flywheel in power press.
Theory:A flywheel used in machines serves as a reservoir, which stores energy during the
period when the supply of energy is more than the requirement, and releases it during the period
when the requirement of energy is more than the supply.
In case of steam engines, internal combustion engines, reciprocating compressors and
pumps, the energy is developed during one stroke and the engine is to run for the whole cycle
on the energy produced during this one stroke. For example, in internal combustion engines,
the energy is developed only during expansion or power stroke which is much more than the
engine load and no energy is being developed during suction, compression and exhaust strokes
in case of four stroke engines and during compression in case of two stroke engines. The excess
energy developed during power stroke is absorbed by the flywheel and releases it to the
crankshaft during other strokes in which no energy is developed, thus rotating the crankshaft
at a uniform speed. A little consideration will show that when the flywheel absorbs energy, its
speed increases and when it releases energy, the speed decreases. Hence a flywheel does not
maintain a constant speed; it simply reduces the fluctuation of speed. In other words, a flywheel
controls the speed variations caused by the fluctuation of the engine turning moment during
each cycle of operation. In machines where the operation is intermittent like punching
machines, shearing machines, riveting machines, crushers, etc., the flywheel stores energy from
the power source during the greater portion of the operating cycle and gives it up during a small
period of the cycle. Thus, the energy from the power source to the machines is supplied
practically at a constant rate throughout the operation.
Energy Stored in a Flywheel
A flywheel is shown in Fig. that when a flywheel absorbs energy, its speed increases and
when it gives up energy, its speed decreases.
Let m = Mass of the flywheel in kg,
k = Radius of gyration of the
flywheel in metres,
Marwadi Education Foundation Group of Institutions
Department of Mechanical Engineering
I = Mass moment of inertia of the flywheel about its axis of rotationin kg-m2 = m*k2,
N1 and N2 = Maximum and minimum speeds during the cycle in r.p.m.,
ω1 and ω2 = Maximum and minimum angular speeds during the cycle in rad/s,
We know that the mean kinetic energy of the flywheel,
1
1
𝐸 = ∗ 𝐼 ∗ πœ”2 = ∗ π‘š ∗ π‘˜ 2 ∗ πœ”2 … … … . 𝑖𝑛 𝑁 − π‘š π‘œπ‘Ÿ π½π‘œπ‘’π‘™π‘’π‘ 
2
2
As the speed of the flywheel changes from ω1 to ω2 the maximum fluctuation of energy.
β–³ 𝐸 = π‘€π‘Žπ‘₯π‘–π‘šπ‘’π‘š 𝐾. 𝐸. −π‘€π‘–π‘›π‘–π‘šπ‘’π‘š 𝐾. 𝐸.
1
1
1
= ∗ 𝐼(πœ”1 )2 − ∗ 𝐼(πœ”2 )2 = ∗ 𝐼[(πœ”)2 − (πœ”)2 ]
2
2
2
=
1
∗ 𝐼(πœ”1 + πœ”2 )(πœ”1 − πœ”2 ) = 𝐼(πœ”1 − πœ”2 )
2
∴πœ”=
πœ”1 + πœ”2
2
πœ”1 − πœ”2
) … … … … … … … … … . (𝑀𝑒𝑙𝑑𝑖𝑝𝑙𝑦𝑖𝑛𝑔 & 𝐷𝑖𝑣𝑖𝑑𝑖𝑛𝑔 𝑏𝑦 πœ”
πœ”
= 𝐼 ∗ πœ”2 𝐢𝑠 = π‘š ∗ π‘˜ 2 πœ”2 𝐢𝑠
∴ 𝐼 = π‘š ∗ π‘˜2
1
= 2𝐸𝐢𝑠 (𝑖𝑛 𝑁 − π‘š π‘œπ‘Ÿ π½π‘œπ‘’π‘™π‘’π‘ )
∴ 𝐸 = ∗ πΌπœ”2 … … . (1)
2
The radius of gyration (k) may be taken equal to the mean radius of the rim (R), because the
thickness of the rim is very small as compared to the diameter of the rim. Therefore, submitting
k = R, in equation (1), we have
β–³ 𝐸 = π‘š ∗ 𝑅 2 ∗ πœ”2 𝐢𝑠 = π‘šπ‘£ 2 𝐢𝑠
Where, v = Mean linear velocity (i.e. at the mean radius) in m/s = ω*R
= 𝐼 ∗ πœ”2 (
Conclusion:-
Marwadi Education Foundation Group of Institutions
Department of Mechanical Engineering
Example:1.
The mass of flywheel of an engine is 6.5 tonnes and the radius of
gyration is 1.8 meters. It is found from the turning moment diagram that the fluctuation
of energy is N-m. If the mean speed of the engine is 120 r.p.m., find the maximum and
minimum speeds.
Marwadi Education Foundation Group of Institutions
Department of Mechanical Engineering
Experiment 2 :- UNIVERSAL GOVERNOR APPARATUS
DESCRIPTION
The apparatus is designed to exhibit the characteristics of the spring-loaded governor
and dead weight governor. The apparatus is driven by a D.C. Motor with variable speed
control unit. The Apparatus can perform following experiments.
A. Watt Governor
B. Porter Governor
C. Proell Governor
D. Hartnell type Governors.
Separate linkages for governor arrangements mentioned above are provided using same
motor and base. Speed measurement is to be done directly by digital RPM meter. Sleeve
displacement is to be noted on scale provided. Variable control unit is provided with the
apparatus i.e. for watt governor, porter governor and also on spring loaded governor
INTRODUCTION
The drive unit consists of a small electric motor connected through 'V' belt to drive
shaft. Motor and main shaft are mounted on a rigid M.S. Base plate in vertical fashion. The
spindle is supported in ball bearings.
The optional governor mechanism can be mounted on spindle. Precise speed control is
afforded by the speed control unit and counter hole over the spindle shaft and the speed is
directly indicated on digital RPM meter. A graduated scale is fixed to the sleeve and guided in
vertical direction.
The center sleeve of the porter and Proell governors incorporates a weight sleeve to
which weights may be added. The Hartnell Governor provided means of varying spring rate
and initial compression level and mass of rotating weight. This enables the Hartnell Governor,
to be operated as a stable or unstable governor.
Marwadi Education Foundation Group of Institutions
Department of Mechanical Engineering
EXPERIMENTATION
ο‚·
ο‚·
ο‚·
ο‚·
Determination of characteristics of sleeve position against controlling force and speed.
Plotting of characteristic of radius of rotation against force.
Obtaining the graph of governor speed V/s sleeve displacement.
Obtaining the governor characteristics i.e. the graph of controlling force v/s radius of
the ball center.
PROCEDURE
The governor mechanism under test is fitted with the chosen rotating weights and
spring, where applicable and inserted into the drive unit. The following procedure may then be
followed.
The control unit is switched on and the speed control slowly rotated, increasing the
governor speed until the center sleeve rises off the lower stop and aligns with the first division
on the graduated scale. The governor speed is then increased in steps to give suitable sleeve
movements, and readings repeated at each stage through out the range of sleeve movement
possible.
The result may be plotted as curves of speed against sleeve position. Further tests are
carried out changing the value of variable at a time to draw curves.
SPECIFICATIONS
ο‚·
Toggle switch
:
15 Amp, DPST, Qty:1 No.
ο‚·
Diode
:
4 Amp, bridge type, Qty:1 No.
ο‚·
Speed indicator
ο‚·
Dimmer
:Type – RC2100,
Range – 4.00 to 9999rpm,
Relay rating – 5A @ 230VAC/24VDC,
Sensor supply – 12VDC, 30mA,
Accuracy – 0.05%, Qty: 1 No.
ο‚· Proximity Switch
Max load – 300 mA, 8mm,
10 – 30VDC,
Qty:1 No.
:
2Amp – open type, 230 VAC, Qty:1 No.
:
M – 12, PNP/NO,
Marwadi Education Foundation Group of Institutions
Department of Mechanical Engineering
ο‚· Motor
PMDC, Flandge mounted,
0 – 180 VDC,
Qty:1 No.
:1/4th HP, 1500rpm,
Service Required: A.C. Single Phase 5 Amp Electrical Supply 230 V, 50 Hz standard Supply.
OPERATING INSTRUCTIONS
ο‚·
Arrange the set up as a watt, proell governor. This can be done by removing the upper
sleeve on the vertical spindle of the governor and using proper linkages provided.
ο‚·
Make proper connections of the motor.
ο‚·
Increase the motor speed gradually.
ο‚·
Note the sleeve displacement on the scale provided and speed on digital RPM meter.
ο‚·
Plot the graph of speed v/s sleeve displacement for watt, porter and proell
ο‚·
Plot the graph of speed v/s governor height for watt governor.
ο‚·
Plot the governor characteristics after doing the necessary calculations.
governor.
PRECAUTIONS
ο‚·
ο‚·
ο‚·
ο‚·
ο‚·
Do not keep the mains ‘ON’ when the trial is complete.
Increase the speed gradually.
Take the sleeve displacement reading when the pointer remains steady.
See that at higher speed the load on sleeve does not hit the upper sleeve of the governor.
While closing the test bring the dimmer to zero position and then switch 'OFF' the
motor.
Marwadi Education Foundation Group of Institutions
Department of Mechanical Engineering
A. WATT GOVERNOR
AIM
Evaluate the performance of watt governer.
INTRODUCTION
The simplest form of a centrifugal governor is a Watt governor as shown in figure. It is
basically a conical pendulum with links attached to a sleeve of negligible weight.
OBSERVATION
ο‚·
ο‚·
ο‚·
ο‚·
Length of each link (L)
Initial height of governor (ho)
Initial radius of rotation (ro)
Weight of each ball (W)
= 0.125 m
= 0.95 m
= 0.132 m
= 0.298 Kg.
Go on increasing the speed gradually and take the readings of speed of rotation 'N' and
corresponding sleeve displacement 'X', radius of rotation 'r,' at any position.
OBSERVATION TABLE
Sr.No.
N (rpm)
X (m)
1
2
3
4
5
Where,
x = Sleeve Displacement in m
N = Speed of Governor in RPM
 = Angular velocity in rad / sec
FC = Centrifugal Force in kg.
W = Weight of each ball in Kg
r = Radius of rotation in m
Marwadi Education Foundation Group of Institutions
Department of Mechanical Engineering
CALCULATION
ο‚·
h = Height of the Governor in meter
h = ho - x/2
ο‚·
 = Angle of inclination of the arm (or upper link) to the vertical
Cos  = h / L = (ho - x/2) / L
ο‚·
r = Radius of Rotation in meter
r = 50 + L Sin  or 
ο‚·
 = Angular Velocity in rad /sec
 = (2  N) /60
ο‚·
Fc = Centrifugal force in Kg
Fc= (W/g) 2 x r
GRAPH:
ο‚·
Force V/s radius of rotation.
ο‚·
Speed V/s sleeve displacement
Marwadi Education Foundation Group of Institutions
Department of Mechanical Engineering
B. PORTER GOVERNOR
AIM
Evaluate the performance of porter governor.
INTRODUCTION
The porter governor is a modification of a Watt’s governor. With the center load
attached to the sleeve as shown in figure. The load moves up and down the central spindle.
This additional down word force increase the speed of revolution required to enable the balls
to rise to any predetermine level.
OBSERVATION
ο‚·
ο‚·
ο‚·
ο‚·
Length of each link (L)
Initial height of governor (ho)
Initial radius of rotation (ro)
Weight of each ball (W)
= 0.125 m
= 0.95 m
= 0.132 m
= 0.298 Kg.
Go on increasing the speed gradually and take the readings of speed of rotation 'N'
and corresponding sleeve displacement 'X', radius of rotation 'r,' at any position.
OBSERVATION TABLE
Sr. No.
N (rpm)
X (m)
W (Kg)
1
2
3
4
5
Where,
X = Sleeve Displacement in m
N = Speed of Governor in RPM
 = Angular velocity in rad / sec
FC =Centrifugal Force in kg.
W = weight of each ball in Kg
r = Radius of rotation in m
Marwadi Education Foundation Group of Institutions
Department of Mechanical Engineering
CALCULATION
ο‚·
h = Height of the Governor in meter
h = ho - x/2
ο‚·
 = Angle of inclination of the arm (or upper link) to the vertical
Cos  = h / L = (ho - x/2) / L
ο‚·
r = Radius of Rotation in meter
r = 50 + L Sin  or 
ο‚·
 = Angular Velocity in rad /sec
 = (2  N) /60
ο‚·
Fc = Centrifugal force in Kg
Fc= (W/g) 2 x r
GRAPH :
ο‚·
Force V/s radius of rotation.
ο‚·
Speed V/s sleeve displacement
Marwadi Education Foundation Group of Institutions
Department of Mechanical Engineering
C. PROELL GOVERNOR
AIM
Evaluate the performance of proell governor.
INTRODUCTION
In the Proell Governor, with the use of flyweights (Forming full ball) the governor
becomes highly sensitive. Under these conditions large sleeve displacement is observed for
very small change in speed.
In order to make it suitable, it is necessary to carry out the experiments by using half ball
flyweight on each side.
OBSERVATION
ο‚·
ο‚·
ο‚·
ο‚·
ο‚·
Length of each link
= 0.125 m
Initial height of governor ho = 0.95 m
Initial radius of rotation ro
= 0.140 m
Weight on sleeve
= 0.458 Kg. each
Weight of each ball
= 0.228 Kg
Go on increasing the speed gradually and take the readings of speed of rotation 'N' and
corresponding sleeve displacement 'X' complete the following table draws the following
graphs.
ο‚· Speed Vs sleeve displacement ‘X’.
ο‚· Then for any displacement 'X' of the sleeve it is possible to find 'r' and 'N'. Force
'F' any be found by knowing 'r' and 'N'
OBSERVATION TABLE
Sr. No.
1
2
3
4
5
N (rpm)
X (m)
W (Kg)
Marwadi Education Foundation Group of Institutions
Department of Mechanical Engineering
CALCULATION
ο‚·
h = Height of the Governor in meter
h = ho - x/2
ο‚·
 = Angle of inclination of the arm (or upper link) to the vertical
Cos  = h / L = (ho - x/2) / L
ο‚·
r = Radius of Rotation in meter
r = 50 + L Sin  or 
ο‚·
 = Angular Velocity in rad /sec
 = (2  N) /60
ο‚·
Fc = Centrifugal force in Kg
Fc= (W/g) 2 x r
Where,
x = Sleeve Displacement in m
N = Speed of Governor in RPM
 = Angular velocity in rad / sec
FC = Centrifugal Force in kg.
W = Weight of each ball in Kg
r = Radius of rotation in m
GRAPH :
ο‚·
Force V/s radius of rotation.
ο‚·
Speed V/s sleeve displacement
Marwadi Education Foundation Group of Institutions
Department of Mechanical Engineering
D. HARTNELL GOVERNOR
AIM
Explore the working of Hartnell Governor.
INTRODUCTION
A hartnell governor is a spring loaded governor as shown in figure. It consists of two
bell crank levers pivoted at the points O, O to the frame. The frame is attached to the governor
spindle and therefore rotates with it. Each lever carries a ball at the end of the vertical arm OB
and a roller at the end of the horizontal arm OR. A helical spring in compression provides equal
downward forces on the two rollers through a collar on the sleeve.
OBSERVATION
ο‚·
ο‚·
ο‚·
ο‚·
ο‚·
ο‚·
Length of the vertical (a)
= 0.075 m
Length of the horizontal (b)
= 0.121 m
Initial radius of rotation (ro)
= 0.160 m
Free height of spring
= 0.132 m
Weight of sliding sleeve
= 0.712 kg.
Weight of sliding sleeve
= 0.226 kg
Measure initial compression of the spring. Go on increasing the speed gradually and
take the readings of speed of rotation ‘N’ and corresponding sleeve displacement 'x' radius of
rotation r at any position could be found as follows:
OBSERVATION TABLE
Sr. No.
1
2
3
4
5
N (rpm)
X (m)
W (Kg)
Marwadi Education Foundation Group of Institutions
Department of Mechanical Engineering
CALCULATION
ο‚·
r = Radius of Rotation in meter
r = ro + x (a) / (b).
ο‚·
 = Angular Velocity in rad /sec
 = (2  N) /60
ο‚·
Fc = Centrifugal force in Kg
Fc= (W/g) 2 x r
Where,
x = Sleeve Displacement in m
N = Speed of Governor in RPM
 = Angular velocity in rad / sec
FC = Centrifugal Force in kg.
W = Weight of each ball in Kg
r = Radius of rotation in m
GRAPHS :
ο‚· Force V/s radius of rotation.
ο‚· Speed V/s sleeve displacement
Marwadi Education Foundation Group of Institutions
Department of Mechanical Engineering
EXPERIMENT NO. :3 – Clutch and Break
AIM
Study of different clutches and breaks
EXPERIMENT NO. :4 – Dynamo-meter
AIM
Study of dynamo-meters
EXPERIMENT NO. :5 – Dynamics
AIM
Static force analysis of 4-bar mechanism and slider crank mechanism
Dynamics force analysis of 4-bar mechanism and slider crank mechanism
Marwadi Education Foundation Group of Institutions
Department of Mechanical Engineering
EXPERIMENT NO. 6: – MOTORISED GYROSCOP
AIM
Study of Gyroscopic couple on Motorised Gyroscope.
INTRODUCTION
Gyroscope:
It is a body while spinning about an axis is free to rotate in other directions under the
action of external forces. Examples: Locomotive, automobile and aeroplane making a turn. In
certain cases, the gyroscopic forces are undesirable whereas in other cases the gyroscopic effect
may be utilized in developing desirable torque. See fig. no. 1
Motorized Gyroscope:
The reaction couple exerted by the body on its frame is equal in magnitude to that of C
but opposite in direction.
DESCRIPTION AND WORKING INSTRUCTIONS
The motor is coupled to the disc rotor, which is balanced. The disc shaft rotates about
XX axis in two ball bearings housed in the frame No.1. This frame can swing about YY axis
in bearing provided in the yoke type frame No.2. In steady position, Frame No.1 is balanced
by providing a weight pan on the opposite side of the motor. The yoke frame is free to rotate
about vertical axis ZZ. Thus, freedom of rotation about three perpendicular axes is given to the
rotor.
SPECIFICATION
ο‚·
Toggle Switch
: 15 amp, DPST,
Qty:1 No.
ο‚·
Diode
: 4 Amp, Bridge type,
Qty: 1 No.
ο‚·
Universal Motor
6500 rpm - AC/DC,
: 1/6 H.P. single phase,
Marwadi Education Foundation Group of Institutions
Department of Mechanical Engineering
Qty:1 No.
ο‚·
Speed Indicator
:Type – RC2100,
Range – 4.00 to 9999rpm,
Relay rating –5A @ 230VAC/24VDC,
Sensor supply – 12VDC, 30mA,
Accuracy – 0.05%,
Qty: 1 No.
ο‚·
: M – 12, PNP/NO,
Proximity Switch
Max load – 300mA, 8mm,
10 - 30VDC,
Qty: 1 No.
ο‚·
Dimmer
:
2Amp – open type, 230VAC
:
4 Amp, 5mm,20mmL,
Qty: 1 No.
ο‚·
Glass Fuse
Qty:1No.
Marwadi Education Foundation Group of Institutions
Department of Mechanical Engineering
THEORY
A) Axis of Spin :
If a body is revolving about an axis, the latter is known as axis of spin, where OC is the
axis of spin)
B) Precession :
Precession means the rotation of axis of spin about the axis OY which is
perpendicular to the both axis of spin OX and that of couple OZ.
C) Axis of Precision :
The third axis OZ is perpendicular to both the axis of spin OX and that of precession
OY is known as axis of precession.
D) Gyroscopic Effect :
To a body revolving (or spinning) about an axis say OX (refer Fig. 1) if a couple
represented by a vector OZ perpendicular to OX is applied, then the body tries to process
about an axis OY which is perpendicular both to OX and OZ. Thus, the plane of spin, plane
of precession and plane of gyroscopic couple are mutually perpendicular.
The above combined effect is known as precessional or gyroscopic effect.
GYROSCOPIC COUPLE OF A PLANE DISC:
Let a disc of weight 'W' having of inertia I be spinning at an angular velocity about axis
OX in anticlockwise direction viewing from front. (Refer Fig. 2) Therefore the angular
momentum of disc is Iw. Applying right hand, screw rule, the sense of vector representing the
angular momentum of disc which is also a vector quantity will be in the direction OX as shown.
A couple, whose axis is OZ perpendicular to OX and is in the plane perpendicular to OZ, is
now applied to process the axis OX.
Let axis OX turn through a small angular displacement from OX to OX' in time t. The
couple applied produces a change in the direction of angular velocity, and the magnitude
remaining constant. This change is due to the velocity of precession.
Therefore OX' represents the angular momentum after time t.
Marwadi Education Foundation Group of Institutions
Department of Mechanical Engineering
Change of angular momentum
= OX' - OX = XX
OR
Angular Displacement
Rate of change of angular momentum = ---------------------------------Time
t.
OX x 
--------------------
XX'
-------------- =
t.
As XX’ = OX x  in direction of XX'.
Now, as rate of change of angular momentum = Couple applied = C = T
We get,
OX x 
T = -----------------t.
But OX = I.
Where,
I = Moment of Inertia of disc.
ω = Angular Velocity of disc.
And in the limit when  is very small.
We have

d
-------- = ----------t
dt
And,
d
------- = p = Angular velocity of precession of yoke @ vertical axis.
dt
Thus, we get,
T = I x xp
The direction of the couple applied on the body is clockwise when looking in direction OZ and
in the limit this is perpendicular to the axis of  and of p.
RULE No.1:
"The spinning body exerts a torque or couple in such a direction which
tends to make the
axis of spin coincides with that of the precession".
RULE NO. 2:
'' The spinning body processes in such a way as to make the axis of spin
Coincide with that of the couple applied, through 900 turn axis."
Marwadi Education Foundation Group of Institutions
Department of Mechanical Engineering
EXPERIMENTAL DETAILS: – MOTORISED GYROSCOP
AIM
Evaluate the Gyroscopic couple on Motorised Gyroscope.
EXPERIMENT:
ο‚·
To observe gyroscopic behaviouer
ο‚·
To measure torque applied & gyro-torque
ο‚·
To apply torque and measure developed precession.
PROCEDURE
To study the rule of gyroscopic behavior following procedure may be adopted.
ο‚·
Balance the rotor position on the horizontal frame.
ο‚·
Start the motor by increasing the voltage with the autotransformer and wait till the
disc attains constant speed.
ο‚·
Put weight (1 Kg., 2 Kg. or 1/2 Kg.) in the weight pan, and start the stop watch to
note the time in seconds required for precession, through 300, 600, 900 etc.
ο‚·
The vertical yoke processes about OZ axis as per the rule No. 2
ο‚·
Speed may be measured by the tachometer provided on control panel.
ο‚·
Enter the observations in the table.
OBSERVATION
ο‚·
ο‚·
ο‚·
Weight of Disc (W)
Diameter of Disc
Distance betn center of the disc
And center of the weight pan of Weight
= 6.216 kg.
= 0.300 m
= 0.150 m
Marwadi Education Foundation Group of Institutions
Department of Mechanical Engineering
OBSERVATION TABLE
Speed of Disc N = 2000 RPM
Sr. No.
Weight on Pan
Kg - w
Angle of Rotation

Time in t sec.
T
CALCULATION
A) The Gyroscopic Torque Relation:
T = I x xp
(Kg.m)
1) I = Moment of Inertia of disc in Kg.m.sec2
I = W/g x r2/2
Where,
W = weight of disc in Kg
r = radius of Disc in meter
2)  = Angular Velocity In rad / Sec
2N
 = -----------60
Where,
N =Speed of Disc in RPM
3) P = Angular velocity of precession of yoke @ vertical in rad / sec
d
P = -------dt
Where,
d = Angle of Precession = ( x ) /180 rad
dt = Time required for this precession in sec
N = Motor speed in RPM
Marwadi Education Foundation Group of Institutions
Department of Mechanical Engineering
4) Ttheo. = Theroetical torque relation in Kg.m
T = W x L.
Where,
W = Weight on pan in Kg
L = Distance betn center of the disc
And center of the weight pan of Weight
Precession is to be calculated for short duration of time, as the balance of
rotation of disc about the horizontal axis YY due to application to torque, because of which p
goes on reducing gradually.
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