DAILY LESSON LOG School Sapian National High School Teacher Cherose c. Lumbo Teaching Dates and Time 7:30 am - 9:30am Monday (6/17/19) Tuesday (6/18/19) Grade Level Grade 8 Learning Area Mathematics Quarter First Wednesday (6/19/19) Thursday (6/20/19) Friday (6/21/19) I. OBJECTIVES A. Content Standards B. Performance Standards C. Learning Competencies/Objecti ves Write the LC code for each. Demonstrates understanding of key concepts of factors of polynomials, rational algebraic expressions, linear equations and inequalities in two variables, systems of linear equations and inequalities in two variables and linear functions. Is able to formulate real-life problems involving factors of polynomials, rational algebraic expressions, linear equations and inequalities in two variables, systems of linear equations and inequalities in two variables and linear functions, and solve these problems accurately using a variety of strategies. Factors completely Factors completely Factors completely Factors completely Factors completely different types of different types of different types of different types of different types of polynomials (polynomials polynomials (polynomials polynomials (polynomials polynomials (polynomials polynomials (polynomials with common monomial with common monomial with common monomial with common monomial with common monomial factor , difference of two factor , difference of two factor , difference of two factor , difference of two factor , difference of two squares, sum and squares, sum and squares, sum and squares, sum and squares, sum and difference of two cubes, difference of two cubes, difference of two cubes, difference of two cubes, difference of two cubes, perfect square trinomials perfect square trinomials perfect square trinomials perfect square trinomials perfect square trinomials and general trinomials) and general trinomials) and general trinomials) and general trinomials) and general trinomials) (M8AL-Ia-b-1) (M8AL-Ia-b-1) (M8AL-Ia-b-1) a. Factor the difference of two squares . b. Solve equations by factoring the difference of two squares. c. Find pleasures in working with numbers. II. CONTENT III. LEARNING RESOURCES Factoring the Difference of Two Squares a. Find the factors of the sum or difference of two cubes. b. Completely factor a polynomial involving the sum and difference of two cubes. c. Find pleasures in working with numbers. a. Find the factors of the sum or difference of two cubes. b. Completely factor a polynomial involving the sum and difference of two cubes. c. Find pleasures in working with numbers. Factoring the Sum or Difference of Two Cubes Factoring the Sum or Difference of Two Cubes (M8AL-Ia-b-1) (M8AL-Ia-b-1) 1. Identify a perfect square trinomial. 2. Get the square of the numbers. 3. Factor a perfect square trinomial 1. Identify a perfect square trinomial. 2. Get the square of the numbers. 3. Factor a perfect square trinomial Factoring a Perfect Square Trinomial Factoring a Perfect Square Trinomial A. References pages 34-35 pages 36-37 pages 36-37 pages 38-39 pages 38-39 1. Teacher’s Guide pages pages 32-33 pages 34-35 pages 34-35 pages 36-38 pages 36-38 2. Learner’s Materials pages 3. Textbook Mathematics Activity Mathematics Activity Mathematics Activity Intermediate Algebra Intermediate Algebra pages Sourcebook pages UBD pages 24-25 UBD pages 24-25 pages Sourcebook pages 22- Sourcebook 25- 26 25- 26 23 4. Additional Materials from Learning Resource (LR) portal B. Other Learning Resources IV. PROCEDURES http://lmrds.deped.gov. http://lmrds.deped.gov http://lmrds.deped.gov http://lmrds.deped.gov http://lmrds.deped.gov ph. .ph. .ph. .ph. .ph. Grade 8 LCTG by Dep Ed Cavite Mathematics 2016 laptop, LCD Grade 8 LCTG by Dep Ed Cavite Mathematics 2016 laptop, LCD Grade 8 LCTG by Dep Ed Cavite Mathematics 2016 laptop, LCD Grade 8 LCTG by Dep Ed Cavite Mathematics 2016 laptop, LCD Grade 8 LCTG by Dep Ed Cavite Mathematics 2016 laptop, LCD A. Reviewing previous lesson or presenting the new lesson. SECRET MESSAGE Find the square roots and solve the secret message. 4 = ___ 16 = ___ 16 = ___ 81 = ___ 49 = ___ 9 = ___ 81 = ___ 25 = ___ 16 = ___ 100 = ___ 9 = ___ 36 = ___ 121= ___ 16 = ___ 25 = ___ 9 = ___ 144 = ___ 64 = ___ 81= ___ 289 = ___ 225 = ___ 49 =___ 9 = ___ 81 = ___ 25= ___ 16 =___ 100 = ___ 9 =___ A 16 B 16 C 25 D 1000 E 299 F 100 G 400 H 4 I 36 J 81 K 64 L 81 M 144 N 100 O 9 P 64 Q 49 R 900 S 121 T 4 U 24 V 9 W 81 X 225 Y 8 B. Establishing a purpose for the lesson. X 9 Factoring the difference of two squares is the reverse process of the product of sum and difference of two terms. (x + y)(x – y) = x2 – y2 Purpose Setting Activity So here are the formulas that summarize how to factor the sum and difference of two cubes. Study them carefully using the following diagrams. Purpose Setting Activity So here are the formulas that summarize how to factor the sum and difference of two cubes. Study them carefully using the following diagrams. Observations: •For the “sum” case, the binomial factor on the right side of the equation has a middle sign that is positive. •In addition to the “sum” case, the middle sign of the trinomial factor will always be opposite the middle sign of the given problem. Therefore, it is negative. •For the “difference” case, the binomial factor on the right side of the equation has a middle sign that is negative. •In addition to the “difference” case, the middle sign of the trinomial factor will always be opposite the middle sign of the given problem. Therefore, it is positive. Factoring the sum or difference of two cubes is the reverse process of product of binomial and trinomial. (x + y)(x2 – xy + y2) = x3 + y 3 (x + y)(x2 + xy + y2) Observations: •For the “sum” case, the binomial factor on the right side of the equation has a middle sign that is positive. •In addition to the “sum” case, the middle sign of the trinomial factor will always be opposite the middle sign of the given problem. Therefore, it is negative. •For the “difference” case, the binomial factor on the right side of the equation has a middle sign that is negative. •In addition to the “difference” case, the middle sign of the trinomial factor will always be opposite the middle sign of the given problem. Therefore, it is positive. Factoring the sum or difference of two cubes is the reverse process of product of binomial and trinomial. (x + y)(x2 – xy + y2) = x3 + y 3 (x + y)(x2 + xy + y2) Find the square of the following: Find the square of the following: 1. 1 2. 4 3. 9 4. 16 5. 25 1. 1 2. 4 3. 9 4. 16 5. 25 6. 36 7. 49 8. 81 9. a2 10. x4 Factoring a perfect square trinomial is the reverse process of square o binomial. (x + y)2 = x2 + 2xy + y2 (x - y)2 = x2 - 2xy + y2 6. 36 7. 49 8. 81 9. a2 10. x4 Factoring a perfect square trinomial is the reverse process of square o binomial. (x + y)2 = x2 + 2xy + y2 (x - y)2 = x2 - 2xy + y2 = x3 - y3 C. Presenting examples/instances of the new lesson. 2 6 Factor 4y - 36y •There is a common factor of 4y2 that can be factored out first in this problem, to make the problem easier. 4y2 (1 - 9y4) •In the factor (1 - 9y4), 1 and 9y4 are perfect squares (their coefficients are perfect squares and their exponents are even numbers). Since subtraction is occurring between these squares, this expression is the difference of two squares. •What times itself will give 1? •What times itself will give 9y4 ? •The factors are (1 + 3y2) and (1 - 3y2). •Answer: 4y2 (1 + 3y2)(1 - 3y2) or 4y2 (1 - 3y2) (1 + 3y2) = x3 - y3 3 1: Factor x + 27 Currently the problem is not written in the form that we want. Each term must be written as cube, that is, an expression raised to a power of 3. The term with variable x is okay but the 27 should be taken care of. Obviously we know that 27 = (3)(3)(3) = 33. Rewrite the original problem as sum of two cubes, and then simplify. Since this is the "sum" case, the binomial factor and trinomial factor will have positive and negative middle signs, respectively. x3 + 27 = (x)3 + (3)3 = (x+3)[{x)2 –(x)(3)+(3)2] =(x+3)(x2-3x+9) 1: Factor x3 + 27 Currently the problem is not written in the form that we want. Each term must be written as cube, that is, an expression raised to a power of 3. The term with variable x is okay but the 27 should be taken care of. Obviously we know that 27 = (3)(3)(3) = 33. Rewrite the original problem as sum of two cubes, and then simplify. Since this is the "sum" case, the binomial factor and trinomial factor will have positive and negative middle signs, respectively. x3 + 27 = (x)3 + (3)3 = (x+3)[{x)2 –(x)(3)+(3)2] =(x+3)(x2-3x+9) Example 2: Factor y3 - 8 This is a case of difference of two cubes since the number 8 can be written as a cube of a number, where 8 = (2)(2)(2) = 23. Apply the rule for difference of two cubes, and simplify. Since this is the "difference" case, the binomial factor and trinomial factor will have negative and positive middle signs, respectively. Example 2: Factor y3 - 8 This is a case of difference of two cubes since the number 8 can be written as a cube of a number, where 8 = (2)(2)(2) = 23. Apply the rule for difference of two cubes, and simplify. Since this is the "difference" case, the binomial factor and trinomial factor will have negative and positive middle signs, respectively. D. Discussing new concepts and practicing new skills #1. Factor each of the following: 1. c² - d² 2. 1 - a² 3. ( a + b )² - 4c² 4. 16x² - 4 5. a²b² - 144 Factor the following: 1. x3 – 8 2. 27x3 + 1 3. x3y6 – 64 4. m³ + 125 5. x³ + 343 Factor the following: 1. x3 – 8 2. 27x3 + 1 3. x3y6 – 64 4. m³ + 125 5. x³ + 343 E. Discussing new concepts and practicing new skills #2. Fill in the blanks to make the sides of each equation equivalent. 1. ( _____ ) ( x – 9) = x² -81 2. ( 20 + 4) ( _____ ) = 20² -4² 3. ( _____ ) (2a +3 ) = 4a² - 9 4. ( 6x²y + 3ab)(6x²y -3ab) =( _____ ) - 9a²b² 5. ( 13 + x ) (13 – x) = _____ - x² Complete the factoring. 1. t3 - w3 =(t–w)( 2. m3 + n3 =(m+n)( 3. x3 + 8 = (x+2)( 4. y3 - 27 =(y–3)( 5. 8- v3 =(2–v)( Complete the factoring. 1. t3 - w3 =(t–w)( 2. m3 + n3 =(m+n)( 3. x3 + 8 = (x+2)( 4. y3 - 27 =(y–3)( 5. 8- v3 =(2–v)( ) ) ) ) ) Study the trinomials and corresponding binomial factors. 1. x2 + 10x + 25 = ( x + 5)2 2. 49x2 – 42 + 9 = ( 7x – 3)2 3. 36 + 20 m + 16m2 = (6 + 4m)2 4. 64x2 – 32xy + 4y2 = (8x – 2y)2 their Study the trinomials and corresponding binomial factors. 1. x2 + 10x + 25 = ( x + 5)2 2. 49x2 – 42 + 9 = ( 7x – 3)2 3. 36 + 20 m + 16m2 = (6 + 4m)2 4. 64x2 – 32xy + 4y2 = (8x – 2y)2 a. Relate the first term in the trinomial to the first term in the binomial factors. b. Compare the second term in the trinomial factor and the sum of the product of the inner terms and outer terms of the binomials. c. Observe the third term in the trinomial and the product of the second terms in the binomials. a. Relate the first term in the trinomial to the first term in the binomial factors. b. Compare the second term in the trinomial factor and the sum of the product of the inner terms and outer terms of the binomials. c. Observe the third term in the trinomial and the product of the second terms in the binomials. Supply the missing term to make a true statement. 1. m2 + 12m + 36 = (m + ___)2 2. 16d2 – 24d + 9 = (4d – ___)2 3. a4b2 – 6abc + 9c2 = (a2b ___)2 4. 9n2 + 30nd + 25d2 = (____ 5d)2 5. 49g2 – 84g +36 = ( ______)2 Factor the following trinomials. 1. x2 + 4x + 4 Supply the missing term to make a true statement. 1. m2 + 12m + 36 = (m + ___)2 2. 16d2 – 24d + 9 = (4d – ___)2 3. a4b2 – 6abc + 9c2 = (a2b ___)2 4. 9n2 + 30nd + 25d2 = (____ 5d)2 5. 49g2 – 84g +36 = ( ______)2 Factor the following trinomials. 1. x2 + 4x + 4 2. x2 - 18x + 81 3. 4a2 + 4a + 1 4. 25m2 – 30m + 9 5. 9p2 – 56p + 16 2. x2 - 18x + 81 3. 4a2 + 4a + 1 4. 25m2 – 30m + 9 5. 9p2 – 56p + 16 ) ) ) ) ) their Factor each completely. a) x ³ + 125 b) a ³ + 64 c) x ³ – 64 d) u ³ + 8 Factor each completely. a) x ³ + 125 b) a ³ + 64 c) x ³ – 64 d) u ³ + 8 G. Finding practical applications of concepts and skills in daily living. Factorize the following by taking the difference of squares: 1. x2 – 100 2. a2 – 4 3. ab2 – 25 4. 36𝑥2 – 81 5. 54𝑥2 – 6y2 Factor the following. 1. 100a2 – 25b2 2. 1 – 9a2 3. 81x2 – 1 4. – 64a2 + 169 b2 5. x2 – 144 Directions. Find the cube roots. Then, match each solution to the numbers at the bottom of the page. Write the corresponding letter in each blank to the question.In the survey, Best place for family picnic in Roxas City? Directions. Find the cube roots. Then, match each solution to the numbers at the bottom of the page. Write the corresponding letter in each blank to the question.In the survey, Best place for family picnic in Roxas City? H. Making generalizations and abstractions about the lesson. The factors of the difference of two squares are the sum of the square roots of the first and second terms times the difference of their square roots. *The factors of 𝑎2 − 𝑏2 =𝑎𝑟𝑒 ( 𝑎 + 𝑏 ) 𝑎𝑛𝑑 ( 𝑎 −𝑏 ). 1. The sum of the cubes of two terms is equal to the sum of the two terms multiplied by the sum of the squares of these terms minus the product of these two terms. a³ + b³ = ( a + b ( a² - ab + b² ) 1. The sum of the cubes of two terms is equal to the sum of the two terms multiplied by the sum of the squares of these terms minus the product of these two terms. a³ + b³ = ( a + b ( a² - ab + b² ) 2. The difference of the cubes of two terms is equal to the difference of the two terms multiplied by the sum of the squares of these two terms plus the product of these two terms. a³ - b³ = ( a - b ( a² + ab + b² ) Supply the missing expression. 1. 𝑚3 - 27 = (m – 3) _________ 2. 64 + 27𝑛3 = ____(16 – 12n + 9𝑛2 ) 3. _______ = ( 2p + 5q ) ( 4𝑝2 – 10pq + 25𝑞2 ) 4. 𝑥6 + 1000 = _____𝑥4 - 10𝑥2 + 100 ) 2. The difference of the cubes of two terms is equal to the difference of the two terms multiplied by the sum of the squares of these two terms plus the product of these two terms. a³ - b³ = ( a - b ( a² + ab + b² ) Supply the missing expression. 5. 1. 𝑚3 - 27 6. = (m – 3) _________ 2. 64 + 27𝑛3 = ____(16 – 12n + 9𝑛2 ) 3. _______ = ( 2p + 5q ) ( 4𝑝2 – 10pq + 25𝑞2 ) 4. 𝑥6 + 1000 = _____𝑥4 - 10𝑥2 + 100 ) 5. ________ = ( 6x – 7y ) ( 36𝑥2 + 42xy + 49𝑦2 ) Solve the following: 5. ________ = ( 6x – 7y ) ( 36𝑥2 + 42xy + 49𝑦2 ) Solve the following: 1. The product of two consecutive even integers is 528. Find the value of each integer. 1. The product of two consecutive even integers is 528. Find the value of each integer. F. Developing mastery (Leads to Formative Assessment #3). I. Evaluating learning. J. Additional activities for application or remediation. V. REMARKS Factorize the following by taking the difference of squares: 1. x2 – 9 2. a2 – 1 3. ab2 – 16 4. 16𝑥2 – 49 5. 54𝑥2 – 6y2 Factorize the following by taking the difference of squares: 1. 2. 3. 4. 5. x2 – 9 a2 – 1 ab2 – 16 16𝑥2 – 49 54𝑥2 – 6y2 1. 2. Factor the following: 1. x2 – 5x + 25 2. b2 -10b + 100 3. 36b2 – 12b + 1 4. 49p2 – 56p = 16 5. 49k2 – 28kp + 4p2 3. 4. Factor the following: 1. x2 – 5x + 25 2. b2 -10b + 100 3. 36b2 – 12b + 1 4. 49p2 – 56p = 16 5. 49k2 – 28kp + 4p2 Complete the perfect square trinomial and factor them. 1. ___ + 16x + 64 2. x2 - ___ + 49 3. x2 + 4x + ___ 4. x2 + ___ + 9y2 5. ___ + 10k + 25 In factoring a perfect square trinomial, the following should be noted: 1. The factors are binomials with like terms wherein the terms are the square roots of the first and the last terms of the trinomial. 2. The sign connecting the terms of the binomial factors is the same as the sign of the middle term of the trinomial. Complete the perfect square trinomial and factor them. 1. ___ + 16x + 64 2. x2 - ___ + 49 3. x2 + 4x + ___ 4. x2 + ___ + 9y2 5. ___ + 10k + 25 In factoring a perfect square trinomial, the following should be noted: 1. The factors are binomials with like terms wherein the terms are the square roots of the first and the last terms of the trinomial. 2. The sign connecting the terms of the binomial factors is the same as the sign of the middle term of the trinomial. Factor the following: 1. x2 – 6x + 9 2. b2 -12b + 36 3. 4b2 – 4b + 1 4. 49p2 – 56p = 16 5. 49k2 – 28kp + 4p2 Factor the following: 1. x2 – 6x + 9 2. b2 -12b + 36 3. 4b2 – 4b + 1 4. 49p2 – 56p = 16 5. 49k2 – 28kp + 4p2 7. 8. Complete the perfect square trinomial and factor them. Complete the perfect square trinomial and factor them. 1. ___ + 16x + 64 2. x2 - ___ + 49 3. x2 + 4x + ___ 4. x2 + ___ + 9y2 5. ___ + 10k + 25 1. ___ + 16x + 64 2. x2 - ___ + 49 3. x2 + 4x + ___ 4. x2 + ___ + 9y2 5. ___ + 10k + 25