1 LAKSHYA JEE (2024) Electrostatic Potential and Capacitance 1. 2. The potential energy of a particle in a force field is: A B U = 2 − , where A and B are positive constants r r and r is the distance of particle from the centre of the field. For stable equilibrium the distance of the particle is: (1) B/A (2) B/2A (3) 2A/B (4) A/B Two charges of equal magnitude q are placed in air at a distance 2a apart and third charge –2q is placed at mid-point. The potential energy of the system is: (0 = permittivity of free space) (1) − –q x 6. q2 8 0 a (2) 5.5 (3) 4 (4) 1.5 Four equal point charge Q each are placed in the xy-plane at (0, 2), (4, 2), (4, -2) and (0, -2). The work required to put a fifth charge Q at the origin of the coordinate system will be 5q 2 (3) − 8 0 a (2) Q2 1 1+ 4 0 5 Two equal point charges q are fixed at x = –a and x = +a on x-axis. Another point charge Q is placed at the origin. The change in electrical potential energy of Q, when it is displaced by a small amount x along x-axis, is approximately proportional to: (1) x (2) x2 1 (3) x3 (4) x In bringing an electron towards proton, the electrostatic potential energy of the system: (1) decreases (2) increases (3) remains same (4) becomes zero x (1) 2 Q2 1 1+ 4 0 3 7q 2 8 0 a –q +Q (1) (4) − 4. Three charges –q, +Q and –q are placed in a straight line as shown. If the total potential energy of the q system is zero, then the ratio is: Q 3q 2 8 0 a (2) − 3. 5. DPP-02 Q2 (3) 4 0 (4) 7. Q2 2 2 0 Four point charges – Q, – q, 2q and 2Q are placed, one at each corner of the square. The relation between Q and q for which the potential at the centre of the square is zero is (1) Q = – q (2) Q = – (3) Q = q (4) Q = 1 q 1 q 2 8. Three identical charges are placed at corners of an equilateral triangle of side l. If force between any two charges is F, the work required to double the dimensions of triangle is (1) – 3 Fl (3) (–3/2) Fl 9. (2) 3 Fl (4) (3/2) Fl 10. Six unit points charges are kept at the vertices of a regular hexagon of side L and centre O, as shown in 1 , which of the the figure. Given that K = 4 0 L2 following statement is wrong? Charges + q and – q are placed at points A and B respectively which are a distance 2L apart, C is the mid-point between A and B, The work done in moving a charge + Q along the semicircle CRD is (1) (3) qQ 4 0 L qQ 6 0 L (2) − (4) − qQ 4 0 L qQ 6 0 L (1) (2) (3) (4) The electric field at O is 6 K along OD The potential at O is zero The potential at all points on the line PR is same The potential at all points on the line ST is same 3 Note: Kindly find the Video Solution of DPPs Questions in the DPPs Section. Answer Key 1. (3) 6. (2) 2. (4) 7. (1) 3. (2) 8. (3) 4. (1) 9. (4) 5. (3) 10. (4) PW Web/App - https://smart.link/7wwosivoicgd4 Library- https://smart.link/sdfez8ejd80if