Mole Ratio Practice Problems
Name __________________________
Period ______
Date _____________
Instructions: Balance the following chemical equations and then determine the missing information for
each of the conditions given. The four questions related to each equation are independent of one another.
Answers for a particular numbered problem should be in the same units as the information given (i.e.
grams to grams, moles to moles, particles to particles). The idea is to maintain the mole ratio in the
20mol
balanced chemical equation. Complete work on another page.
olxol2x=
x 10
=
2
Al2O3(s)
→
4 Al(s)
mol, (mol 2
X
3 O2(g)
+
1.
5mol
10 mol
______
______
mol
7.5
2.
mol
1.25
______
2.5mol
1.875mol
______
3.
25g
______
509
______
37.59
4.
1.60x1024
______ molecules
______
mol=vTree
Two
2x
-59x
=
2.41x10 molecules
X
H2SO4(aq)
→
CuSO4(aq)
1.
______
0.75 mol
.75mol
______
0.75 mol
2.
50g
509
______
______
50g
3.
3.5 mol
______
______
3.5 Mol
3.5mol
4.
1.204x10"
______ molecules
K(s)
+
1.204x10"
______molecules
N2(g)
x
x
3.21
=
2x
75 mol
59 x
75
=
=
1024
x
37.5g
=
⑭1024,
H2O(l)
=
______
0.75 mol
3X = 1.6 x10
=
______
jog
molx
______
x
50g
=
9.64x10
amol,I
X
1.875
=
100
=
=
+
1.204x 102molecules
→
1.25mol
=
X
1024,3x
#x
+
mol
7.5
=
24
102 molecule
3.21 x
=
x
=
CuO(s)
x
=
mol
X = 3.5
mol
______
3.5 Mol
23
1.204x10 molecules
Fox #x102,
K3N(s)
2
1.
23
1.51x10 atoms
10"molecules
______
2.517 x
5.03 x102 molecules
______
6x
X
2.
7.5 mol
______
1.25mol
______
2.5 mol
3.
______
759
______
12.59
25 grams
1.51 x
=
= 2.5K x10
X
smolx2
x
2.5mol
=
259,2x
2x
x
25
=
2x 150
=
12.59X 75g
=
=
10"
6X 3.02x)02
=
2
x
5.03x102"
=
molx
x 7.5 mol
=