Find dy/dx when y = log (secΘ + tanΘ) and x = secΘ
Given:
y = log (secΘ + tanΘ)
x = secΘ
To find: dy/dx
dy/dx = (1/x) * [secΘ * tanΘ + secΘ]
Substituting the second equation into the third equation, we get:
dy/dx = (1/x) * [secΘ^2 + secΘ]
Simplifying the expression, we get:
dy/dx = secΘ/x
Therefore, the value of dy/dx when y = log (secΘ + tanΘ) and x = secΘ is secΘ/x.