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GRADE 8 MATH Memo

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QUESTION 1 (Whole Numbers)
1.1.
1.1.1
Calculate the following using the Column Method
7 826 + 888 + 367
2
1.1.2
7 826
+ 888 
+ 367
= 9 081
3 045 -2 572
2
1.1.3
3 045
- 2 572 
= 1 473 
75  1 756
3
1 756
75
8
780

+
122 920 
=881 700 
Calculate the following using the the Long Division Method
7 234 ÷ 48

1.1.4
3
150
48 √ 7 243
- 48 
244
240 
..43
00
43
1.1.5
150,43 
Write 2 475 as a product of prime factors. Write the final answer in
exponential form.
2 457
819
237
91
3
3 
3
91 
2 457 = 3  3  3  91 
= 33  91 
4
1.1.6
75 3
25 3
5 5
1
100
50
25
5
1
3

2
2
5
5
75 = 3  5  5 
100 = 2  2  5  5
LCM = 5 × 5
= 25 
1.1.7
36
18
9
3
1
3
3
3
3
40
20
10
5
1
2
2
2
5
3


36 = 2  2  3  3
40 = 2  2  5  5
HCF = 2  2 
1.1.8
56 
168
=
2
= 84
1.1.9
3
72 × 4
216
= 4
= 54
3
2

3





3
1.1.10
Speed =
𝑑𝑖𝑠𝑡𝑎𝑛𝑐𝑒
𝑡𝑖𝑚𝑒
180 𝑘𝑚
2 ℎ𝑟𝑠

Speed=
=

= 90 km/hr 
1.1.11
𝑑𝑖𝑠𝑡𝑎𝑛𝑐𝑒
𝑡𝑖𝑚𝑒
𝑑𝑖𝑠𝑡𝑎𝑛𝑐𝑒
=
3 ℎ𝑜𝑢𝑟𝑠
5

Distance = (90 km/ hrs )(3 hrs)
=270 km 
5 + 4 + 3  = 12 
5
5
Nathi : R 600 × 12
= R250 
4
Paul : R 600 × 12
= R200 
3
Tim : R 600 × 12
= R 150 
[36]
QUESTION 2 (INTEGERS)
2.1.1
2.1.2
2.1.3
2.2.1
2.2.2
2.2.3
Dead sea
2 230
86 
2 144 
Difference : 8 840
+ 398 
= 9 238 
[ -5 + (-3) ] × 7
= ( -5 -3) × 7
= -8 × 7 
=-56 
- 3 × 4 + ( -7) × 9
= -3 × 4 – 7 × 9
=12 – 63 
= - 75 
- 5 × (-3 + 7) + 20 ÷ (-4)
= -5 × 4 – 5 
= - 20 – 5 
= - 25 
1
2
2
3
3
3
[14]
THE END !
Grand total : 50 marks
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