PRG Gr.11 P2 June 2022 PAUL ROOS GYMNASIUM MATHEMATICS PAPER 2 GRADE 11 30 MAY 2022 TIME: 2 hours TOTAL: 100 marks Examiner: L van Niekerk Moderators: G Langenhoven L Day ______________________________________________________________________________ General instructions: 1. This paper consists of 6 questions. Answer all the questions. 2. Do Questions 3-6 on the answer sheet and staple to the back of your folios. If you need more writing space, use extra folios between the answer sheets. 3. Draw a margin on the right hand side of the page and keep this margin open. 4. If necessary, all answers must be rounded to two decimal digits. 5. Clearly show all calculations, diagrams or graphs that you have used in determining your answers. 6. Full marks won’t necessarily be awarded for an answer only. 7. Hand in your answer sheet and question paper separately. Page 1 of 7 PRG Gr.11 P2 June 2022 QUESTION 1 16 marks Do all the trigonometry without the use of a calculator. 1.1. If 17 cos π΅ + 8 = 0 and π΅π(180°; 360°), determine with the aid of a diagram the value of: 1.1.1 sin π΅ 1.1.2 1 tan2 π΅ (4) + 1 (3) sin2 π΅ 1.2. In the diagram π is the point (2; −2√3) and ππ ⊥ ππ . The reflex ππΜπ = π΄. Calculate the following: π(2; −2√3) 1.2.1 The length of ππ. (2) 1.2.2 cos(−π΄) (1) 1.2.3 tan(180° − π΄) (2) 1.2.4 1 −√3 sin π΄ − 1 (3) 1.2.5 π΄ (1) Page 2 of 7 PRG Gr.11 P2 June 2022 QUESTION 2 39 marks Remember to this question without the use of a calculator. 2.1. Simplify the following expressions fully: 2.1.1 2.1.2 tan(−30°).cos(370°) (7) tan(300°).sin 280° sin(π΄+180°)+2 cos(90°+π΄).cos(π΄−180°) 2 cos2 (180°−π΄)−cos(−π΄) (8) 2.2. Prove the following identities: 2.2.1 2.2.2 2.2.3 1 tan2 π₯ − cos2 π₯ 1 1−2 sin πΌ.cos πΌ sin πΌ−cos πΌ = = cos4 π₯ (4) sin2 π₯ sin2 πΌ−cos2 πΌ (3) sin πΌ+cos πΌ sin2 15°+sin2 105°−cos2 250° sin(−70°).cos 200° =1 (7) 2.3. If cos 36° = π, write the following in terms of π. 2.3.1. cos 324° (2) 2.3.2. sin 54° (1) 2.3.3. tan 144° (3) 2.3.4. cos2 216° − sin2 36° (4) Page 3 of 7 PRG Gr.11 P2 June 2022 QUESTION 3 17 marks 3.1. In the diagram the tangent at π· is parallel to chord π΄πΆ and π is the centre of the circle. π΅πΜπΆ = 60° and πΆπΊΜ π· = 50°. Determine with reasons the size of the following angles: 3.1.1. π΄Μ1 (2) 3.1.2. π΄Μ2 (2) Μ4 3.1.3. π· (2) 3.1.4. π΅πΆΜ π· (2) 3.1.5. π΄πΆΜ π· (2) Μ3 3.1.6. π· (2) 3.2 In the diagram, πΆ, π΅ and π΄ are points on the circle with centre π. π·π΄ is a tangent to the circle at π΄. Use the diagram to prove the theorem which states that π·π΄ΜπΆ = π΅Μ. Page 4 of 7 (5) PRG Gr.11 P2 June 2022 QUESTION 4 8 marks In the following sketch, π is the centre of the circle. ππ = 24 ππ. π π = 10 ππ and π΄π΅ = 7 ππ. π΄π ⊥ ππ , π π΅ = π΅π and ππ΄ = π₯. 4.1. Give a reason why π π΅Μ π = 90°. (1) 4.2. Show that π π2 = π₯ 2 + 14π₯ + 74. (2) 4.3. Calculate the value of π₯. (5) Page 5 of 7 PRG Gr.11 P2 June 2022 QUESTION 5 12 marks In the diagram, circle ππ π has tangents ππ and ππ. π is the centre of the circle, with π on ππ . π Μ = π₯ 5.1. Give, with reasons, three other angles equal to π₯ . (3) 5.2. Give, with reasons, three angles equal to 90°. (3) 5.3. Give a reason why ππππ is a cyclic quadrilateral. (1) 5.4. Prove that ππ β₯ ππ . (3) 5.5. Determine the size of πΜ1+2 in terms of π₯. (2) Page 6 of 7 PRG Gr.11 P2 June 2022 QUESTION 6 8 marks In the diagram, two circles πππ π and πππ΅ intersect at π and π. π΄π΅ is a tangent to the smaller circle, with πππ΄ a straight line. π΅π produced meets the larger circle at π such that ππ β₯ π΅π΄. ππ΄ intersects the larger circle at π . Μ π = π and π© Μπ = π Let π· 6.1. Determine, with a single reason, the size of πΜ1 in terms of π₯ and π¦. (2) 6.2. Prove that ππ π΄π΅ is a cyclic quadrilateral. (3) 6.3. Prove that π΄π΅ is a tangent to circle ππ π΅. (3) TOTAL =100 Page 7 of 7