Uploaded by khadija.atrash

הרצאה 1

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‫הקדמה‬
x 11x
⑧
R1
=
=
n
=(y,yy,
R 1
=
·
PCNOD
48180
Cc58K N54/10). NRS
331794
218.00
QN 000
LION
NMC
(11817
NNN SYRS
NS3S3418
NIDDU
SUNION Y4
IN
=
20
IIM
N34110
OIC
SYMSN HOD
.
x
0132
MOJR
TO
QI44
KI
53N8
N5ON NIN
‫המישור המרוכב‬
a,bCIR
(916)
2
Z
a
=
ib:5(x)5i 45341:
+
80
01001
0024 /
0.13:19
&
V(cosO+isin0):5054234/2
=
1900
71151
U-9:ReSz3:0:4N
or 0.91
NiDaVic 73370's
p( b 7m5z3
-
=
: ‫סימונים‬
z x
iy r(c0s(
-
=
=
=
0) isin ( 0):2105
+
-
(0x(1
17 Im5z 3
=
is
z x
=
↑
↓
-
:3)
iy
+
(1)
·
>X R25z3
=
z x
=
-
jy
51 (5N9(26:(z1
x
=
-
y
+
=
r(2
: ‫תכונות‬
aRe5z3(1
z z
=
+
z
-
2i+m5z3(2
z
=
1212(3
2.z
=
: ‫חיבור וכפל‬
z1 x1
iyz
xz
iy,,zz
=
+
+
=
*
21 2a (X1 x2) i(y1 yz)
+
+
=
+
+
(X, Xz y,ya) i(X,yz Xzyc)
*
2.2a
=
+
-
+
: ‫דוגמאות‬
(11)2 9p5(1
=
(1
-
1)2 1
+
j)(1 39) 1
+
2i
=
=
3i
+
+
3
+
-
-
2i
*
1
=
p 4 2i
*
=
+
: ‫כפל בייצוג גיאומטרי‬
2.
v,(cs(0,) isin(01)), Za
+
=
Zizz
S
vz
=
V.Vz(c0s(0,
=
x2340 YON
487
(c0s(02) isin(02)
+
02)
+
isin(0, 02))
+
+
N800 6300
ES
K5
(‫הארגומנט )הזוית‬
z 1
1+9
=
i.in1212
+
I
!
o=
4
#
1
-
2 1
=
-
75
4N0
p
·
9
o
=
E
*1k
XSMMD
0 =-#
arg (z)
OCR:
=
z
r(cosotising 3:431047
=
1
00012717
=
: ‫הגדרה‬
ZC0
: ‫דוגמאות‬
arg(1-4) 5...... *, *, *,
=
04/191C
OCarg
a
(Z)
-
2+K:
+
48-3x
8159) 1c arg (0) (R (/S():1010 131270 (a
50
TOXH
35 7
=
....
=
kN
Z
NO DION QUATION
O FZCK
Arg
in
: ‫הגדרה‬
(E):2 1410(C17
·
o
=
Arg(z)
I
Arg(z)88x1b.3( 4j
Ov π
8
·
-
o
H
·
o
-
=
=
0
E
Arg(z,zz) Arg(z,) Arg(zc):00155135k5 : ‫אזהרה‬
=
+
‫טופולוגיה במישור המרוכב‬
: ‫תזכורות בכתיב מרוכב‬
d(z,,ze) zz
=
-
z
=
(
(yz y1)2
+
-
(zi z.)(z2 z,):477x5
=
-
-
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