CHEMISTRY – A4 1. For the formation of which compound in Ellingham diagram G 0 becomes more and more negative with increase in temperature? (A) ZnO (B) Cu2O (C) CO (D) FeO Ans: C 2. Which of the following compound does not give dinitrogen on heating? (A) NH4NO3 (B) (NH4)2Cr2O7 (C) Ba(N3)2 (D) NH4NO2 Ans: A (A) NH4 NO3 ⎯⎯ (B) ( NH 4 )2 Cr2O7 ⎯⎯ → N2 +Cr2O3 + 4H 2O → N2O + 2H2O (C) Ba( N3 )2 ⎯⎯ → Ba + 3N2 (D) NH4 NO2 ⎯⎯ → N2 +2H2O 3. Aqueous solution of raw sugar when passed over beds of animal charcoal, it becomes colourless. Pick the correct set of terminologies that can be used for the above example. Adsorbent Adsorbate Process A) Animal Charcoal Colouring substance Adsorption B) Colouring Substance Animal Charcoal Adsorption C) Solution of Sugar Animal Charcoal Sorption D) Animal Charcoal Solution of Sugar Absorption Ans: A 4. For Freundlich adsorption isotherm, a graph of a log (x/m) v/s. log (P) gives a straight line. The slope of line and its Y-axis intercept respectively are 1 1 1 1 (A) log , log K (B) , K (C) log , K (D) , log K n n n n Ans: D 1 1 x x 1 intercept = log k = k p n log = log k + log p , Slope = , n m m n 5. When FeCl3 is added to excess of hot water gives a sol ‘X’. When FeCl3 is added to NaOH(aq) solution, gives sol ‘Y’. X and Y formed in the above processes respectively are (A) Fe2O3.xH2O / Cl − and Fe2O3.xH2O / OH − (B) Fe2O3.xH2O / Fe3+ and Fe2O3.xH2O / OH − (C) Fe2O3.xH2O / OH − and Fe2O3.xH2O / Fe3+ Ans: B FeCl3 + hot H2O → Fe2O3.xH2O / Fe+3 (D) Fe2O3.xH2O / H + and Fe2O3.xH2O / Na + FeCl3 + NaOH( aq ) → Fe2O3 .xH2O / OH − 6. The reducing agent in the given equations: 4 Ag( s ) + 8CN(−aq ) + 2H 2O( aq ) + O2( g ) → 4[ Ag (CN )2 ](−aq) + 4OH (−aq) − 2[ Ag (CN )2 ](−aq ) + Zn( s ) → [Zn(CN )4 ](2aq ) + 2 Ag( s ) (A) H2O (B) CNAns: C Zn acts as a reducing agent. (C) Zn (D) O2 7. Which of the following is CORRECT with respect to melting point of a transition element? (A) Mn > Fe (B) Ti > V (C) V > Cr (D) Cr > Mn Ans: D Due to more number of unpaired electrons. 8. aMnO4− + bS2O3−2 + H2O → xMnO2 + ySO4−2 + zOH − , a and y respectively are (A) 3;6 (B) 8;8 (C) 8;3 Ans: D 8MnO4− + 3S2O3−2 + H2O → 8MnO2 + 6SO4−2 + 2OH − (D) 8;6 9. Which formula and name combination in INCORRECT? (A) [CoCl2(en)2]Cl –Dichloridodiethylenediammine cobalt (II) chloride (B) [Co(NH3)4(H2O)Cl]Cl2 – Tetraammnieaquachlordiocobalt (III) chloride (C) K3[Al(C2O4)3] – Potassium trioxalatoaluminate (III) (D) [Pt(NH3)2Cl(NO2)] – Diamminechloridonitrito – N – platinum (II) Ans: A [CoCl2 (en)2 ]Cl Dichloridobis(ethylenediamine)cobalt(III) chloride 10. Which of the following system in an octahedral complex has maximum unpaired electrons? (A) d4 (low spin) (B) d7 (high spin) (C) d9 (high spin) (D) d6 (low spin) Ans: B A) d4 (low spin) 2 unpaired electrons B) d7 (high spin) 3 unpaired electrons C) d9 (high spin) 1 unpaired electrons D) d6 (low spin) 0 unpaired electrons 11. The correct decreasing order of basicity of hydrides of Group-15 elements is (A) AsH3 > SbH3 > NH3 > PH3 (B) NH3 > PH3 > AsH3 > SbH3 (C) SbH3 > AsH3 > PH3 > NH3 (D) PH3 > AsH3 > SbH3 > NH3 Ans: B 12. Which one of the following oxoacids of phosphorus can reduce AgNO3 to metallic silver? (A) H4P2O6 (B) H3PO4 (C) H3PO2 (D) H4P2O7 Ans: C H3PO2 acts as reducing agent because it has two P-H bond. 13. In solid state, PCl5 is a/an (A) Ionic solid with [PCl4]+ and [PCl6](C) Octahedral structure Ans: A Ionic solid with [PCl4]+ [PCl6]− (B) Covalent solid present in the form of P2Cl10 (D) Ionic solid [PCl6]+ and [PCl4]- 14. In which one of the following pairs, both the elements does not have (n – 1)d10ns2 configuration in its elementary state? (A) Hg, Cn (B) Cu, Zn (C) Zn, Cd (D) Cd, Hg Ans: B PCC 15. CH3 − CH = CH − CH2OH ⎯⎯⎯ →CH3 − CH = CH − CHO . Hybridization change involved at C – 1 in the above reaction (A) sp2 to sp3 (B) sp to sp2 Ans: D (C) sp3 to sp (D) sp3 to sp2 16. If a didentate ligand ethane -1, 2-diamine is progressively added in the molar ratio en : Ni ::1:1, 2 :1,3:1 to [Ni(H2O)6]2+ aq solution, following co-ordination entities are formed. + I. [ Ni( H 2O)4 en](2aq ) - pale blue + II. [ Ni( H 2O)2 (en)2 ](2aq ) - blue/purple + III. [ Ni(en)3 ](2aq ) - violet The wavelength in nm of light adsorbed in case of I and III are respectively (A) 310 nm and 500 nm (B) 600 nm and 535 nm (C) 475 nm and 310 nm (D) 300 nm and 475 nm Ans: B 1 Strength of ligand . Visible light range 400 nm to 750 nm. absorbed 17. Which of the following is an organometallic compound? (A) (CH3COO)2Ca (B) CH3ONa (C) CH3COONa Ans: D Grignard reagent (D) CH3CH2MgBr 18. A pair of compounds having the same boiling points are (A) Benzene and naphthalene (B) (+) butan -2 – ol and (-1) butan – 2 – ol (C) cis but-2-ene and trans but-2-ene (D) n-hexane and neo-hexane Ans: B Boiling point depends on molar mass and optical isomers have same boiling point. 19. Identify A, B and C in the sequence LiAlH4 HNO2 KCN CH3CH2 Br ⎯⎯⎯ → A ⎯⎯⎯ → B ⎯⎯⎯ →C alc 00 C (A) CH3CH2CN, C2H5OH, C2H5N2Cl (B) CH3CH2CN, CH3CH2NH2, C2H5OH (C) CH3CH2CN, CH3CH2CH2NH2, CH3CH2CH2OH (D) CH3CH2NC, CH3CH2OH, CH3CH2CH2NH2 Ans: C LiAlH 4 KCN 0 C CH3CH 2 Br ⎯⎯⎯ → CH 3CH 2 − CN ⎯⎯⎯ → CH 3CH 2CH 2 NH 2 + HNO2 ⎯⎯ ⎯ → CH 3 − CH 2 − CH 2OH alc 0 20. Compounds P and R in the following reaction are (i) CH3MgBr (i) B2 H6 Conc.H2SO4 CH3CHO ⎯⎯⎯⎯ ⎯ → P ⎯⎯⎯⎯→ Q ⎯⎯⎯⎯⎯ →R heat (ii) H O+ ii) H O /OH3 2 2 (A) Metamers (B) Identical (C) position isomers (D) Functional isomers Ans: C (i) CH3MgBr (i) B2 H6 Conc.H2SO4 CH3CHO ⎯⎯⎯⎯ ⎯ → CH3 (CH3 )CHOH ⎯⎯⎯⎯→ CH3CH=CH 2 ⎯⎯⎯⎯⎯ → CH3CH 2CH 2OH heat (ii) H O+ ii) H O /OH3 2 2 P & R are positional isomers. 21. Aniline does not undergo (A) Friedel-Craft reaction (B) Bromination (C) Nitration (D) Sulphonation Ans: A AlCl3 coordinated with NH2 group of aniline. 22. The heat of phenyl methyl ether with HI produces an aromatic compound A which on treatment with con. HNO3 gives B. A and B respectively are, (A) Iodobenzene, 1-Iodo-4-nitrobenzene (B) Phenol, Picric acid (C) Methanol, Ethanoic acid (D) Picric acid, Phenol Ans: B O CH3 OH HI + strong bond CH 3I Phenol(A) NO 2 OH OH Conc. HNO3 O 2N NO 2 2,4,6-trinitrophenol or picric acid (B) 23. OH NaOH A (i) CO2 (ii) H+ B (i) (CH3CO)2O (ii) H+ Y (Major product) Y in the above reaction is (A) Cumene (B) Picric acid Ans: D OH ONa (B) Salycylaldehyde OCOCH 3 OH COOH COOH NaOH (D) Aspirin (i) CO2 (i) (CH3CO)2O (ii) H+ (ii) H+ Aspirin 24. A better reagent to oxidize primary alcohols into aldehyde is: (A) Acidified K2Cr2O7 (B) CrO3 (C) PCC (D) Alkaline KMnO4 Ans: C PCC is a mild oxidising agent. 25. In the reaction : ( i ) SnCl2 + HCl con. KOH C6 H5CN ⎯⎯⎯⎯⎯ → X ⎯⎯⎯⎯ →Y + Z , ( ii ) H O+ 3 Formation of X, formation of Y and Z are known by (A) Wolff-Kishner reduction, Wurtz reaction. (B) Stephen reaction, Cannizaro reaction. (C) Rosenmund reduction, Cannizaro reaction. (D) Clemmensen reduction, Sandmeyer reaction. Ans: B Y = C6 H5 − CH2OH Z = C6 H5 − COOK X = C6 H5 − CHO 26. In the reaction: NH2 P + N2 Cl - Q P,Q and R respectively are: (A) NaNO2 + dil.HCl, BF3 , Cu + NaNO2 (B) NaNO3 + dil.HCl, F2 , Cu + NaNO3 (C) NaNO2 + dil.HCl, HBF4 , Cu + NaNO2 + N2 BF 4 - NO2 R (D) NaNO2 + con.HCl, F2 , Cu + NaNO3 Ans: C NH2 + N2 Cl NaNO2 + dil.HCl - + N2 BF 4 HBF4 - NO 2 Cu + NaNO2 27. Thyroxine produced in the thyroid gland is an iodinated derivative of _____ (A) Tyrosine (B) tryptophan (C) threonine Ans: A (D) lysine 28. Sucrose is dextrorotatory but after hydrolysis the mixture show laevorotation, this because of (A) Racemic mixture is formed (B) Laevorotation of fructose is more than dextrorotation of glucose (C) Laevorotation of glucose is more than dextrorotation of fructose (D) Sucrose is a non-reducing sugar Ans: B 29. The correct order of match between column X and column Y is: X Y I. Vitamin A i.Muscular weakness II. Vitamin D ii. Increased blood clotting time III. Vitamin E iii. Night- blindness IV. Vitamin K iv. Osteomalacia (A) I-iii, II-ii, III-iv, IV-i (B) I-iii, II-iv, III-i, IV-ii (C) I-iv, II-iiii, III-ii, IV-i (D) I-ii, II-I, III-iii, IV-iv Ans: B 30. Which of the following monomers form biodegradable polymers? (A) Phenol and formaldehyde (B) 3- hydroxybutanoic acid and 3- hydroxypentanoic acid (C) Ethylene glycol and phthalic acid (D) Caprolactum and 1, 3- Butadiene Ans: B 31. Match the list-I with List-II in the following: List-I List-II 1. Caprolactum (a) ( CH 2 − CH )n | CH 3 2. Vinyl chloride (b) ( CH 2 − CH | 3. Styrene C H 6 5 )n (c) ( CH 2 − CH | Cl )n O || (d) ( C ( CH 2 ) 5 N ) n | 4. Propene (A) 1-d, 2-c, 3-a, 4-b (C) 1-c, 2-d, 3-a, 4-b Ans: B H (B) 1-d, 2-c, 3-b, 4-a (D) 1-a, 2-d, 3-c, 4-b 32. Which one of the following is a non- narcotic analgesic? (A) Aspirin (B) Morphine (C) Heroin Ans: A (D) Codeine 33. Receptors are proteins and crucial to body communication process. These receptors are embedded in (A) Endocrine gland (B) Chromosomes (C) Cell membrane (D) Protein Ans: C 34. A gas at a pressure of 2 atm is heated from 25 0C to 323 0C and simultaneously compressed to of its original value. Then the final pressure is (A) 2 atm (B) 4 atm Ans : D PV PV 1 1 = 2 2 T1 T2 (D) 6 atm V1 = V T1 = 25 C + 273 = 298K P1 = 2 P2 = ? (C) 1.33 atm 2 rd 3 2 T2 = 323 C + 273 = 596K , V2 = V 3 2 v 596 596 3 1788 PV T = = = 6 atm P2 = 1 1 2 = 298 298 2 T1.V2 298 v 3 35. Lattice enthalpy for NaCl is + 788 kJ mol-1and ΔHyd H0 = −784kJ mol−1 . Enthalpy of solution of NaCl is (A) − 572 kJ mol −1 (B) − 4 kJ mol −1 Ans : D sol H = L H + Hyd H = 788 − 784 = +4kJ / mol (C) + 572 kJ mol −1 (D) +4 kJ mol −1 36. At 500 K, for a reversible reaction A2( g ) + B2( g ) 2 AB( g ) in a closed container. KC = 2 10−5 . In the presence of catalyst, the equilibrium is attaining 10 times faster. The equilibrium constant KC in the presence of catalyst at the same temperature is (A) 2 10−10 (B) 2 10−5 (C) 2 10−4 (D) 2 10−6 Ans : B Equilibrium constant does not affect by adding catalyst. 37. A weak acid with pKa 5.9 and weak base with pKb 5.8 are mixed in equal proportions. pH of the resulting solution is (A) 7 (B) 7.05 (C) 7.005 (D) 7.5 Ans : B 1 1 1 pH = 7 + pK a − pK b = 7 + 5.9 − 5.8 = 7 + 0.1 = 7 + 0.05 = 7.05 2 2 2 38. Temperature of 25 0C in Fahrenheit and Kelvin scale respectively are (A) 45 0F and 260.16 K (B) 47 0F and 312.15 K (C) 77 0F and 298.15 K (D) 17 0F and 298.15 K Ans : C 9 0 F = 0C + 32 K = 0C + 273.15 5 39. The number of protons, neutrons and electrons in the ion (A) 18, 16, 16 (B) 16, 16, 16 Ans : D 32 2 − no. of protons = 16 16 S no. of neutrons = 32 – 16 = 16 16, 16, 18 32 16 S 2− respectively are (C) 16, 18, 16 (D) 16, 16, 18 no. of electrons = 16 + 2 = 18 40. The correct order of first ionisation enthalpy of given elements is (A) C < B < Be < Li (B) Li < Be < B < C (C) Li < B < Be < C Ans : C Li < B < Be < C 520 kJ < 801 kJ < 899J < 1086 kJ (D) Be < Li < B < C 41. Which of the following statement is INCORRECT? (A) Bond length of O2 < Bond length of O22− (B) Bond length of O2 > Bond length of O22− (C) Bond length of O2 > Bond length of O22+ Ans : D (D) Bond length of O2+ < Bond length of O22− Bond order of O2+ = 2.5 and Bond order of O22− = 1.0 Bond order of O2+ Bond order of O22− 42. IUPAC name of the compound is (A) 1, 1, 2, 2 – tetra methylethene (C) 2, 3 – dimethylbut-2-ene Ans : C (B) 2, 3 – dimethyl butene (D) 2, 3 – dimethyl butyne 43. Among the following : .. I II III IV The set which represents aromatic species is (A) II and III (B) I, II and IV Ans : B According to Huckle’s Rule V (C) I, II and III (D) III, IV and V 44. Which one of the following gases converts haemoglobin into carboxy haemoglobin ? (A) NO (B) CO2 (C) CO (D) O2 Ans : C CO gas strongly bonds to haemoglobin complex to form carboxy haemoglobin. 45. What is the oxidation of S in H2S2O8 ? (A) +7 (B) +6 Ans :B O HO S O (C) +5 O O O S OH O 46. A 30% solution of hydrogen peroxide is (A) ‘50 volume’ hydrogen peroxide (C) ‘30 volume’ hydrogen peroxide Ans : B 3% H2O2 is labelled as 10 V 30% H2O2 will be 100 V (B) ‘100 volume’ hydrogen peroxide (D) ‘10 volume’ hydrogen peroxide (D) +4 47. A pair of amphoteric oxides is (A) BeO, MgO (B) BeO, ZnO Ans : B BeO and ZnO are amphoteric. 48. The composition of water gas is (A) CO( g ) + H2O( g ) (B) CO( g ) + H 2( g ) (C) Al2O3, Li2O (D) BeO, BO3 (C) CO( g ) + N2( g ) (D) CH 4( g ) Ans : B 49. The swelling in feet and ankles of an aged person due to sitting continuously for long hours during travel, is reduced by soaking the feet in warm salt water. This is because of : (A) Edema (B) Diffusion (C) Reverse Osmosis (D) Osmosis Ans : D w w 50. A sample of water is found to contain 5.85 % of AB (molecular mass 58.5) and 9.50 % w w XY2 (molecular mass 95). Assuming 80 % ionisation of AB and 60 % ionisation of XY2 , the freezing point of water sample is [Given : K f for water 1.86 K kgmol −1 , Freezing point of pure water is 273 K and A, B and Y are monovalent ions] (A) 280.44 K (B) 281.75 K Ans : D w ×1000 ΔTf = iKf m = iK f 2 M2 ×w1 (C) 264.25 K (D) 265.56 K For AB ΔTf = 1.8×1.86× 5.85×1000 = 3.348K 58.5×100 For XY2 9.5×1000 = 4.092K 95×100 Total ΔTf = 3.348K + 4.092K = 7.44K ΔTf = 2.2×1.86× Freezing point of water = 273K - 7.44K = 265.56K 51. Match the column A(type of crystalline solid) with the column B (example for each type) : A B P. Molecular Solid i. SiC Q. Ionic Solid ii. Mg R. Metallic Solid iii. H2O S. Network Solid (A) P- ii, Q-iv, R-iii, S-i iv. MgO (B) P- iii, Q- iv, R-ii, S-i (C) P-iii, Q-I, R- ii, S-iv Ans: B (D) P-iv, Q-iii, R-ii, S – i 0 52. A metal crystallises in a body centered cubic lattice with the metallic radius 3 A . The volume of the unit cell in m3 is (A) 6.4 10−29 Ans: A For BCC (B) 4 10−10 (C) 64 10−29 (D) 4 10−29 3 4 3×10-10 m 4r 4r −29 3 a= a3 = = = 6.4 10 m 3 3 3 53. If ‘a’ stands for the edge length of the cubic systems – The ratio of radii in simple cubic, body centered cubic and face centered cubic unit cells is 3 (A) 1 3 2 a: a: a 2 2 2 (C) 1a : 3a : 2 a (B) 1 1 a : 3a : a 2 2 (D) 1 3 1 a: a: a 2 4 2 2 Ans: D 54. Dimerisation of solute molecules in low dielectric constant solvent is due to : (A) Co-ordinate bond (B) Ionic bond (C) Hydrogen bond Ans: C (D) Covalent bond 55. For a reaction, the value of rate constant at 300 K is 6.0 105 s −1 . The value of Arrhenius factor A at infinitely high temperature is : 5 6 10−5 (A) (B) 6 10 300 Ans: B At temperature K = Ae− Ea / RT K = Ae− Ea / R K = Ae0 K = A (C) 6 105 e− Ea / 300 R (D) e− Ea / 300 R 56. The rate constants k1 and k2 for two different reactions are 1016 e−2000/ T and 1015 e−1000/ T respectively. The temperature at which k1 = k2 is : 1000 K (B) 1000K 2.303 Ans: A K1 = 1016 e−2000/ T K2 = 1015 e−1000/ T (A) According to Arrhenius equation (C) 2000 K 2.303 (D) 2000K If K1 = K2 1016 e−2000/ T = 1015 e−1000/ T 1016 e−1000/ T = 1015 e−2000/ T 10 = e−1000/ T + 2000/ T 10 = e1000 / T 1000 ln10 = T 1000 1000 1000 T= = = k ln10 2.303log10 2.303 57. During the electrolysis of brine, by using inert electrodes, (A) Na deposits on cathode (B) Cl2 liberates at anode (C) O2 liberates at anode (D) H2 liberates at anode Ans: B 58. Consider the following 4 electrodes A : Ag + ( 0.0001 M ) / Ag( s ) ; B : Ag + ( 0.1M ) / Ag( s ) C : Ag + ( 0.01 M ) / Ag( s ) ; D : Ag + ( 0.001 M ) / Ag ( s ) ; E 0 + = + 0.80 V Ag / Ag then reduction potential in volts of the electrodes in the order (A) A > D > C > B (B) A > B > C > D (C) B > C > D > A (D) C > D > A > B Ans : C According to Nernst equation, Eo [Ag+ ] 59. The resistance of 0.1 M weak acid HA in a conductivity cell is 2 103 Ohm. The cell constant of the cell is 0.78 cm−1 and m0 of acid HA is 390 S cm2 mol −1 . The pH of the solution is (A) 5 (B) 3 (C) 3.3 (D) 4.2 Ans : B G* 0.78 0.39 10−3 Scm −1 −3 −1 = = = 0.39 10 Scm , = = = 3.9 S cm 2 mol-1 m 3 −3 −3 R 2 10 C 0.110 mol cm 2 -1 3.9 S cm mol = 0m = = 110−2 [H + ] = C = 0.110−2 = 10−3 2 -1 m 390 S cm mol pH = − log[H + ] = − log[10−3 ] = 3 60. In which one of the following reactions, rate constant has the unit mol L -1 s-1 ? (A) 2 NO( g ) + O2( g ) → 2 NO2( g ) (B) Decomposition of HI on the surface of Gold (C) Acid catalysed hydrolysis of CH3COOCH3 (D) CHCl3 + Cl2 →CCl4 + HCl Ans : B ******