Circuits 2 Chapter 2: Impedance and Admittance PHASOR RELATIONSHIPS FOR CIRCUIT ELEMENT Summary of Voltage Current Relationships IMPEDANCE AND ADMITTANCE • • • The impedance Z of a circuit is the ratio of the phasor voltage V to the phasor current I, measured in ohms Ω. The impedance represents the opposition which the circuit exhibits to the flow of sinusoidal current. It is not a phasor Impedances and Admittances of Passive Elements • The impedance may be expressed in rectangular form a π = π + ππ where: R = Re Z (resistance ) X = Im Z (reactance). The reactance X may be positive or negative. 1 Circuits 2 Chapter 2: Impedance and Admittance • • • • the impedance is inductive when X is positive or capacitive when X is negative. T impedance Z = R + jX is said to be inductive or lagging since current lags voltage, impedance Z = R − jX is capacitive or leading because current leads voltage. The impedance, resistance, and reactance are all measured in ohms. The impedance may also be expressed in polar form as Admittance • • The Reciprocal of Impedance The admittance Y of an element (or a circuit) is the ratio of the phasor current through it to the phasor voltage across it, or Complex Form of Admittance: π = πΊ ± ππ½ where G = Re Y (the conductance) β = Im Y is called the susceptance. • Admittance, conductance, and susceptance are all expressed in the unit of siemens (or mhos). Examples: 1. What is the inductance of the inductor in millihenrys 2 Circuits 2 Chapter 2: Impedance and Admittance 2. Simplify: a. π(π‘) = 5 cos(2π‘ + 15°) − 4sinβ‘(2π‘ − 30°) b. π(π‘) = 8π πππ‘ + 4cosβ‘(π‘ + 50°) 3 Circuits 2 Chapter 2: Impedance and Admittance 3. The voltage v= 12 cos(60t + 45β¦) is applied to a 0.1-H inductor. Find the steady-state current through the inductor. 4. Determine the current that flows through an 8-β¦ resistor connected to a voltage source π£π = 110 cos 377π‘β‘π. 5. What is the instantaneous voltage across a 2- µ F capacitor when the current through it is π = 4 sin(106 + 25°) π΄ 4 Circuits 2 Chapter 2: Impedance and Admittance 6. A voltage π£(π‘) = 100 cos(60π‘ + 20°) π is applied to a parallel combination of a 40-kβ¦ resistor and a 50- µ F capacitor. Find the steady-state currents through the resistor and the capacitor. 7. Find v(t) and i(t) in the circuit shown: 5 Circuits 2 Chapter 2: Impedance and Admittance 8. The phasor form of voltage applied across the inductor is, V=100∠0βV The phasor form of current in the inductor is, I=20∠-90βA. Determining the impedance of the inductor: 9. Two voltages π£1 and π£2 appear in series so that their sum is v = v1 + v2. If v1 = 10 cos(50t - π/3)V and v2 = 12cos(50t + 30° ) V, find v. 6 Circuits 2 Chapter 2: Impedance and Admittance 7