Uploaded by هشام محمد

VxWTSPBwQOQgzCZJDcMZ3JXI8wl42MRXVl0ltvYI

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:
1
2
3
4
1
1
C= 3x108
1
2
∵ 𝝀𝒎 ∝
𝟏
𝑻
∴
𝝀𝒎𝟏
𝝀𝒎𝟐
=
𝑻𝟐
𝑻𝟏
2
1
2
3
4
λm
2
3
1
2
3
6.625 × 10−34 𝐽. 𝑠
h
𝐸 = ℎ𝜐
4
5
𝐸 = ℎ𝜐
6
𝐸 = 𝑛ℎ𝜐
7
3
1
←
1
←
2
1
1
2
3
2
x,y
4
–


←
←
1
KE = 2 m v2 = e V
4


2
𝒗𝒄
3
1
𝐸 = ℎ𝜐
∴𝐸=
ℎ𝐶
𝜆
2
𝐸𝑤 = ℎ𝜐𝑐
5
‫‪3‬‬
‫𝒘𝑬 = 𝑬‬
‫𝒄𝝊 = 𝝊‬
‫𝒄𝝀 = 𝝀‬
‫𝒘𝑬 < 𝑬‬
‫𝒄𝝊 < 𝝊‬
‫𝒄𝝀 > 𝝀‬
‫𝒘𝑬 > 𝑬‬
‫𝒄𝝊 > 𝝊‬
‫𝒄𝝀 < 𝝀‬
‫𝑬𝑲 = 𝒘𝑬 ‪𝑬 −‬‬
‫𝟏‬
‫𝟐𝒗𝒎 = 𝒄𝝊𝒉 ‪∴ 𝒉𝝊 −‬‬
‫𝟐‬
‫التيار الكهروضوئي‬
‫التيار الكهروضوئي‬
‫شدة اإلضاءة‬
‫شدة اإلضاءة‬
‫‪4‬‬
‫‪6‬‬
1
50%
0.8eV
0.5eV
𝐾𝐸 = 50%𝐸
0.8 − 0.5 = 50%𝐸
𝐸 = 0.6𝑒𝑉
𝐾𝐸 = 𝐸 − 𝐸𝑤
0.5 = 0.6 − 𝐸𝑤
𝐸𝑤 = 0.1𝑒𝑉
𝐸𝑤 = 0.1𝑥1.6𝑥10−19 𝐽 = 1.6𝑥10−20 𝐽
2
𝐸 = 𝐸𝑤 → 1
𝐾𝐸 =
ℎ𝑐
−𝐸
𝜆
4
→ 2
𝐾𝐸 = 4𝐸 − 𝐸 = 3𝐸
7
X
1
2
2
1
2
PL = m.C
3
X
E=h𝛎
8
1
2
C=3x10
3
4
5
𝑬 = 𝒎𝒄𝟐
𝑷𝑳 = 𝒎𝑪
𝑷𝑳 =
𝒉𝝊
𝑪
6
→ ∴ 𝑷𝑳 =
, 𝑪 = 𝝀𝝊
𝒉𝝊
×𝑪
𝑪𝟐
→→ ∴ 𝑷𝑳 =
→∴ 𝑷𝑳 =
𝒉𝝊
𝝀𝝊
𝒉𝝊
𝑪
→𝝀=
𝒉
𝑷𝑳
∴ 𝑭 = 𝟐𝒎𝑪. ∅𝑳
∵𝒎=
𝒉𝝊
𝑪𝟐
→∴𝑭=𝟐
𝒉𝝊
𝒉𝝊∅𝑳
𝑪.
∅
→∴
𝑭
=
𝟐
𝑳
𝑪𝟐
𝑪
∵ 𝑷𝒘 = 𝒉𝝊∅𝑳
→∴ 𝑭 =
8
𝟐𝑷𝒘
𝑪
3
𝟐𝟎𝟎𝑾
%20
𝐹=
𝐹=
2𝑃𝑤
𝐶
2 × 0.2 × 200
= 2.67 × 10−7
3 × 108
4
𝟔𝟎𝟎𝟎𝑨°
𝟑𝟗. 𝟔 𝒘
𝟐%
𝑃𝑤 = ℎ 𝜈 𝜙𝐿
𝑃𝑤 = ℎ 𝜈
𝑛
ℎ𝑐𝑛
, 𝑃𝑤 =
𝑡
𝜆𝑡
𝑛=
=
𝑃𝑤 𝜆 𝑡
ℎ𝑐
6000 × 10−10 × 39.6 × 1 × 0.02
= 2.4 × 1018 𝑒
6.625 × 10−34 × 3 × 108
5
𝟑𝒆𝑽
𝟎. 𝟗𝒎𝒘
𝟏𝟐𝝁𝑨
………….
𝑃𝑤 = 𝐸 𝜙𝐿
0.9 × 10−3
𝜙𝐿 =
= 3 × 10−4 𝑃ℎ𝑜𝑡𝑜𝑛 /𝑠𝑒𝑐
3
=
12 × 10−6
× 100 = 4%
3 × 10−4
9
V
1
1
υ
λ
2
2
λ
λ
3
3
hυ
𝒎𝒆 = 𝟗. 𝟏 × 𝟏𝟎−𝟑𝟏 𝒌𝒈
ℎ𝜐
𝑚 = 𝐶2
𝐸 = 𝑚𝐶 2
ℎ𝜐
𝒉
𝐶
𝝀
𝟐𝒆𝑽
𝒗 = √𝒎
8
3 × 10 𝑚/𝑠
𝒆
𝒉
𝝀 = 𝒎𝒗
10
105
2000

λ

λ

λ
6
𝟔. 𝟔𝒏𝒎
𝜆=
𝑉=
ℎ
ℎ
=
𝑃𝐿 𝑚. 𝑉
ℎ
6.625 × 10−34
=
= 11 × 104 𝑚/𝑠
𝑚 . 𝜆 9.1 × 10−31 × 6.6 × 10−9
11
😂
1
2
3
4
5
6

2πr=nλ
(E2)
7
∆E = hυ=E2 –E1
(E2 >E1)
(
)
12
(E1)
E α𝒏𝟐
En = ∆E = E
(En)
ℎ𝑐
𝜆
(J)
ev
𝒏𝟐
-E
(En+1)
∆E = (hυ) =
𝟏𝟑.𝟔
(En)
(E∞ = 0)
∆E = (hυ) =
= En+1 - En
𝒉𝒄
𝝀
= E∞ - En = 0 - En
(ev)
(e)
1
-0.85ev
D
C
-1.51ev
B
A
1027.5Å
-3.4ev
B 
D 
-13.6ev
ΔE =
A
C 
hc 6.625 ∗ 10−34 ∗ 3 ∗ 108
=
= 1.93 ∗ 10−18 = 12.09ev
λ
1027.5 ∗ 10−10
ΔE = −1.51 + 13.6 = 12.09ev
C
2
E=
hc
−13.6ev −13.6ev
Emin = E2 − E1 =
−
λ
4
1
Emin = λmax = E
hc
𝑚𝑎𝑥
Emax = E∞ − E1 = 0 −
= 10.2ev
−13.6ev
1
= 13.6ev
hc
Emax = λmin = E
𝑚𝑖𝑛
λmax Emax 13.6ev 4
=
=
=
λmin Emin 10.2ev 3
13
3
Å974
n
O
k
N
ΔE =
n
M
L
hc
13.6
= 2.04 ∗ 10−18 = 12.75ev = 13.6 − 2
λ
n
13.6
n2
13.6
n = √0.85 = 4
= 0.85
4
-1.51ev
M
1.1 ∗ 10−36 𝑘𝑔 
-0.544ev
O
1.2 ∗ 10−36 𝑘𝑔 
1.5 ∗ 10−36 𝑘𝑔 
1.7 ∗ 10−36 𝑘𝑔 
ΔE = 0.966ev = mc 2
m=
0.966 ∗ 1.6 ∗ 10−19
= 1.7 × 10−36 kg
(3 ∗ 108 )2




14







X
– ray
1
2
3
4
15

1
2
3

1
2
3
1
2
ℎ𝐶
E= KE
λ = ∆𝐸
=eV
𝜆=
ℎ𝑐
eV

1
2
3
16
1
E = eV
ℎ𝑐
𝜆
eV
hυ = eV
1
mv2
2
=eV
2
E = V .I .t
3
–
ℎ𝑐
λ = ∆𝐸
4
5
17
𝜆2 
𝜆1 
𝜆3 𝜆2 
𝜆3 
𝜆2 
𝜆1 
𝜆3 𝜆2 
𝜆3 
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