−4
𝑛
7.00
×
10
𝑚𝑜𝑙
𝐾𝑂𝐻
−
[𝑂𝐻 ] =
=
= 0.0132 𝑀
𝑉𝑡𝑜𝑡
0.05300 𝐿
𝑛𝐾𝑂𝐻 7.00 × 10−4 𝑚𝑜𝑙
=
=
= 0.0132 𝑀
𝑉𝑡𝑜𝑡
0.05300 𝐿
−14
𝐾
1.00
×
10
𝑤
−13
[𝐻 + ] =
=
=
7.57
×
10
𝑀
−
[𝑂𝐻 ]
0.0132
𝑝𝐻 = 12.12
10.00 𝑚𝐿 − 3.00 𝑚𝐿
[𝑂𝐻 = (
) (0.02000 𝑀)
10.00 𝑚𝐿
50.00 𝑚𝐿
(
) = 0.0132 𝑀
50.00 𝑚𝐿 + 3.00 𝑚𝐿
−]
[𝑂𝐻
−]
10.00 𝑚𝐿 − 3.00 𝑚𝐿
=(
) (0.02000 𝑀)
10.00 𝑚𝐿
−14
𝐾
1.00
×
10
𝑤
−13
[𝐻 + ] =
=
=
7.57
×
10
𝑀
−
[𝑂𝐻 ]
0.0132
𝑝𝐻 = 12.12
10.50 𝑚𝐿 − 10.00 𝑚𝐿
[𝐻 = (0.1000 𝑀) (
)
50.00 𝑚𝐿 + 10.50 𝑚𝐿
= 8.26 × 10−4 𝑀
+]
𝑝𝐻 = 3.08
1
1
𝐾𝑎
𝐾=( )=
=
= 5.4 × 107
𝐾𝑤
𝐾𝑏
( ) 𝐾𝑤
𝐾𝑎
0.02000 𝑚𝑜𝑙 𝑀𝐸𝑆 1 𝑚𝑜𝑙 𝑁𝑎𝑂𝐻
𝑉𝑒 = 0.05000 𝐿 𝑀𝐸𝑆 (
)(
)∙
1 𝐿 𝑀𝐸𝑆
1 𝑚𝑜𝑙 𝑀𝐸𝑆
1 𝐿 𝑁𝑎𝑂𝐻
(
)
0.1000 𝑚𝑜𝑙 𝑁𝑎𝑂𝐻
= 0.01000 𝐿 𝑁𝑎𝑂𝐻
[𝐴− ][𝐻+ ]
𝑥2
𝐾𝑎 =
=
= 10−6.27
[𝐻𝐴]
𝐹−𝑥
𝑥 = 1.03 × 10−4
𝑝𝐻 = 3.99
[𝐴− ]
𝑝𝐻 = 𝑝𝐾𝑎 + 𝑙𝑜𝑔
[𝐻𝐴]
0.3
𝑝𝐻 = 6.27 + 𝑙𝑜𝑔
= 5.90
0.7
[𝐴− ]
𝑝𝐻 = 𝑝𝐾𝑎 + 𝑙𝑜𝑔
[𝐻𝐴]
0.5
𝑝𝐻 = 6.27 + 𝑙𝑜𝑔
= 6.27
0.5
𝐾𝑤 [𝐻𝐴][𝑂𝐻− ]
𝑥2
𝐾𝑏 =
=
=
−
[𝐴 ]
𝐾𝑎
𝐹′ − 𝑥
50.00 𝑚𝐿
′
𝐹 = (0.02000 𝑀) (
) = 0.01667 𝑀
50.00 𝑚𝐿 + 10.00 𝑚𝐿
𝐾𝑤 [𝐻𝐴][𝑂𝐻− ]
𝑥2
𝐾𝑏 =
=
=
−
[𝐴 ]
𝐾𝑎
𝐹′ − 𝑥
50.00 𝑚𝐿
′
𝐹 = (0.02000 𝑀) (
) = 0.01667 𝑀
50.00 𝑚𝐿 + 10.00 𝑚𝐿
𝑥 = 1.76 × 10−5 𝑀
𝑝𝐻 = 9.25
[𝑂𝐻
−]
10.10 𝑚𝐿 − 10.00 𝑚𝐿
= (0.1000 𝑀) (
) = 1.66 × 10−4 𝑀
50.00 𝑚𝐿 + 10.10 𝑚𝐿
𝑝𝐻 = 10.22