lOMoARcPSD|24824932 A.A.Lahiru Shamika-HND COM - Unit 18 - Discrete Mathematics Reworded 2021 HND in Computing (ESOFT Metro Campus) Studocu is not sponsored or endorsed by any college or university Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 Higher Nationals Internal verification of assessment decisions – BTEC (RQF) INTERNAL VERIFICATION – ASSESSMENT DECISIONS BTEC Higher National Diploma in Computing Programme title Assessor Internal Verifier Unit 18 : Discrete Mathematics Unit(s) Discrete mathematics in software engineering concepts Assignment title A.A.Lahiru Shamika / KUR00064943 Student’s name List which assessment Pass Merit criteria the Assessor has awarded. INTERNAL VERIFIER CHECKLIST Do the assessment criteria awarded match those shown in the Y/N assignment brief? Is the Pass/Merit/Distinction grade awarded justified by the assessor’s Y/N comments on the student work? Has the work been assessed Y/N accurately? 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Assessor signature Date Internal Verifier signature Programme Leader signature Date (if required) Date A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 Confirm action completed Remedial action taken Give details: Internal Verifier Programme Leader Date signature (if Date A.A.L.S.Amarasinghe Discrete Mathema琀椀cs Downloaded by adviu consulting (adviucons@gmail.com) ESOFT Metro Campus lOMoARcPSD|24824932 Higher Nationals - Summative Assignment Feedback Form Student Name/ID A.A.Lahiru Shamika / KUR00064943 Unit Title Unit 18 : Discrete Mathematics Assignment Number 1 Assessor Date Received Submission Date 1st submission Date Received 2nd Re-submission Date A.A.L.S.Amarasinghe submission Discrete Mathema琀椀cs Downloaded by adviu consulting (adviucons@gmail.com) ESOFT Metro Campus lOMoARcPSD|24824932 Assessor Feedback: LO1 Examine set theory and functions applicable to software engineering. Pass, Merit & P1 P2 M1 D1 Distinction Descripts LO2 Analyse mathematical structures of objects using graph theory. Pass, Merit & P3 P4 M2 D2 Distinction Descripts LO3 Investigate solutions to problem situations using the application of Boolean algebra. Pass, Merit & P5 P6 M3 D3 Distinction Descripts LO4 Explore applicable concepts within abstract algebra. Pass, Merit & P7 P8 M4 D4 Distinction Descripts Grade: Assessor Signature: Date: Resubmission Feedback: Grade: Assessor Signature: Date: Internal Verifier’s Comments: Signature & Date: * Please note that grade decisions are provisional. They are only confirmed once internal and external moderation has taken place and grades decisions have been agreed at the assessment board. A.A.L.S.Amarasinghe Discrete Mathema琀椀cs Downloaded by adviu consulting (adviucons@gmail.com) ESOFT Metro Campus lOMoARcPSD|24824932 Pearson Higher Nationals in Computing Unit 18 : Discrete Mathematics General Guidelines 1. A Cover page or title page – You should always attach a title page to your assignment. Use previous page as your cover sheet and make sure all the details are accurately filled. 2. Attach this brief as the first section of your assignment. 3. All the assignments should be prepared using a word processing software. A.A.L.S.Amarasinghe Discrete Mathema琀椀cs Downloaded by adviu consulting (adviucons@gmail.com) ESOFT Metro Campus lOMoARcPSD|24824932 4. All the assignments should be printed on A4 sized papers. Use single side printing. 5. Allow 1” for top, bottom , right margins and 1.25” for the left margin of each page. Word Processing Rules 1. The font size should be 12 point, and should be in the style of Time New Roman. 2. Use 1.5 line spacing. Left justify all paragraphs. 3. Ensure that all the headings are consistent in terms of the font size and font style. 4. Use footer function in the word processor to insert Your Name, Subject, Assignment No, and Page Number on each page. 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Failure to achieve at least PASS criteria will result in a REFERRAL grade . A.A.L.S.Amarasinghe Discrete Mathema琀椀cs Downloaded by adviu consulting (adviucons@gmail.com) ESOFT Metro Campus lOMoARcPSD|24824932 8. Non-submission of work without valid reasons will lead to an automatic RE FERRAL. You will then be asked to complete an alternative assignment. 9. If you use other people’s work or ideas in your assignment, reference them properly using HARVARD referencing system to avoid plagiarism. You have to provide both in-text citation and a reference list. 10. If you are proven to be guilty of plagiarism or any academic misconduct, your grade could be reduced to A REFERRAL or at worst you could be expelled from the course Student Declaration I hereby, declare that I know what plagiarism entails, namely to use another’s work and to present it as my own without attributing the sources in the correct way. I further understand what it means to copy another’s work. 1. I know that plagiarism is a punishable offence because it constitutes theft. 2. I understand the plagiarism and copying policy of the Edexcel UK. 3. I know what the consequences will be if I plagiaries or copy another’s work in any of the assignments for this program. 4. I declare therefore that all work presented by me for every aspects of my program, will be my own, and where I have made use of another’s work, I will attribute the source in the correct way. 5. I acknowledge that the attachment of this document signed or not, constitutes a binding agreement between myself and Pearson, UK. A.A.L.S.Amarasinghe Discrete Mathema琀椀cs Downloaded by adviu consulting (adviucons@gmail.com) ESOFT Metro Campus lOMoARcPSD|24824932 6. I understand that my assignment will not be considered as submitted if this document is not attached to the attached. lahirushamika12@gmail.com 2022/07/27 Student’s Signature: Date: (Provide E-mail ID) A.A.L.S.Amarasinghe (Provide Submission Date) Discrete Mathema琀椀cs Downloaded by adviu consulting (adviucons@gmail.com) ESOFT Metro Campus lOMoARcPSD|24824932 Feedback Form Formative feedback: Assessor to Student Action Plan Summative feedback Feedback: Student to Assessor Assessor’s Signature A.A.L.S.Amarasinghe Date Discrete Mathema琀椀cs Downloaded by adviu consulting (adviucons@gmail.com) ESOFT Metro Campus lOMoARcPSD|24824932 Student’s lahirushamika12@gmail.co Signature m Date 27/07/2022 Assignment Brief Student Name /ID Number A.A.Lahiru Shamika / KUR00064943 Unit Number and Title Unit 18 :Discrete Mathematics Academic Year 2021/22 Unit Tutor Discrete mathematics in Computing Assignment Title Issue Date Submission Date 27/07/2022 IV Name & Date Submission Format: This assignment should be submitted at the end of your lesson, on the week stated at the front of this brief. The assignment can either be word-processed or completed in legible handwriting. If the tasks are completed over multiple pages, ensure that your name and student number are present on each sheet of paper. Unit Learning Outcomes: LO1 Examine set theory and functions applicable to software engineering. LO2 Analyse mathematical structures of objects using graph theory. LO3 LO4 Investigate solutions to problem situations using the application of Boolean algebra. Explore applicable concepts within abstract algebra. A.A.L.S.Amarasinghe Discrete Mathema琀椀cs Downloaded by adviu consulting (adviucons@gmail.com) ESOFT Metro Campus lOMoARcPSD|24824932 Assignment Brief and Guidance: Activity 01 Part 1 1. Perform algebraic set operations in the following formulated mathematical problems. i. Let A and B be two non-empty finite sets. If cardinalities of the sets A, B, and are 72, 28 and 13 respectively, find the cardinality of the set. ii. If n()=45, n()=110 and n()=15, then find n(B). iii.If n(A)=33, n(B)=36 and n(C)=28, find n(). Part 2 1. Write the multisets (bags) of prime factors of given numbers. i. 160 ii. 120 iii. 250 2. Write the multiplicities of each element of multisets (bags) in Part 2-1(i,ii,iii) separately. 3. Determine the cardinalities of each multiset (bag) in Part 2-1(i,ii,iii). Part 3 1. Determine whether the following functions are invertible or not and if a function is invertible, then find the rule of the inverse using appropriate mathematical technique. A.A.L.S.Amarasinghe Discrete Mathema琀椀cs Downloaded by adviu consulting (adviucons@gmail.com) ESOFT Metro Campus lOMoARcPSD|24824932 Part 4 1. Formulate corresponding proof principles to prove the following properties about defined sets. i. . ii. De Morgan’s Law by mathematical induction. iii. Distributive Laws for three non-empty finite sets A, B, and C. Activity 02 Part 1 1. Model two contextualized problems using binary trees both quantitatively and qualitatively. Part 2 1. State the Dijkstra’s algorithm for a directed weighted graph with all non-negative edge weights. 2. Use Dijkstra’s algorithm to find the shortest path spanning tree for the following weighted directed graph with vertices A, B, C, D, and E given. Consider the starting vertex as E. A.A.L.S.Amarasinghe Discrete Mathema琀椀cs Downloaded by adviu consulting (adviucons@gmail.com) ESOFT Metro Campus lOMoARcPSD|24824932 Part 3 1. Assess whether the following undirected graphs have an Eulerian and/or a Hamiltonian cycle. i. ii. A.A.L.S.Amarasinghe Discrete Mathema琀椀cs Downloaded by adviu consulting (adviucons@gmail.com) ESOFT Metro Campus lOMoARcPSD|24824932 iii. Part 4 1. Construct a proof of the five color theorem for every planar graph. A.A.L.S.Amarasinghe Discrete Mathema琀椀cs Downloaded by adviu consulting (adviucons@gmail.com) ESOFT Metro Campus lOMoARcPSD|24824932 Activity 03 Part 1 1. Diagram two real world binary problems in two different fields using applications of Boolean Algebra. Part 2 1. Produce truth tables and its corresponding Boolean equation for the following scenarios. i. If the driver is present and the driver has not buckled up and the ignition switch is on, then the warning light should turn on. ii. If it rains and you don't open your umbrella, then you will get wet. 2. Produce truth tables for given Boolean expressions. i. ii. Part 3 1. Simplify the following Boolean expressions using algebraic methods. i. ii. iii. iv. Part 4 1. Consider the K-Maps given below. For each K- Map i. Write the appropriate standard form (SOP/POS) of Boolean expression. ii. Design the circuit using AND, NOT and OR gates. iii. Design the circuit only by using NAND gates if the standard form obtained in part (i) is SOP. NOR gates if the standard form obtained in pat (i) is POS. A.A.L.S.Amarasinghe Discrete Mathema琀椀cs Downloaded by adviu consulting (adviucons@gmail.com) ESOFT Metro Campus lOMoARcPSD|24824932 (a) AB/C 0 1 00 0 0 01 0 1 11 0 1 10 1 0 (b) AB/CD 00 01 11 10 00 1 0 0 1 01 0 1 0 1 11 1 1 1 0 10 1 1 1 1 (c) AB/C 0 1 00 1 0 01 1 1 11 1 0 A.A.L.S.Amarasinghe Discrete Mathema琀椀cs Downloaded by adviu consulting (adviucons@gmail.com) ESOFT Metro Campus lOMoARcPSD|24824932 10 0 1 Activity 04 Part 1 1. Describe the distinguishing characteristics of different binary operations that are performed on the same set. Part 2 1. Determine the operation tables for group G with orders 1, 2, 3 and 4 using the elements a, b, c, and e as the identity element in an appropriate way. 2. i. State the relation between the order of a group and the number of binary operations that can be defined on that set. ii. How many binary operations can be defined on a set with 4 elements? 3. i. State the Lagrange’s theorem of group theory. ii. For a subgroup H of a group G, prove the Lagrange’s theorem. iii. Discuss whether a group H with order 6 can be a subgroup of a group with order 13 or not. Clearly state the reasons. Part 3 1. Validate whether the set is a group under the binary operation ‘*’defined as for any two elements. Part 4 1. Prepare a presentation for ten minutes to explore an application of group theory relevant to your course of study. (i.e. in Computer Sciences) A.A.L.S.Amarasinghe Discrete Mathema琀椀cs Downloaded by adviu consulting (adviucons@gmail.com) ESOFT Metro Campus lOMoARcPSD|24824932 A.A.L.S.Amarasinghe Discrete Mathema琀椀cs Downloaded by adviu consulting (adviucons@gmail.com) ESOFT Metro Campus lOMoARcPSD|24824932 Acknowledgement I would like to make this a moment to thank our dearest lecturer Mr Tharanga who gave his fullest support in teaching this subject to us and also I would like to thank my family and friends who gave me their fullest support in completing this assignment. A.A.L.S.Amarasinghe. Esoft Metro Campus Kurunegala A.A.L.S.Amarasinghe Discrete Mathema琀椀cs Downloaded by adviu consulting (adviucons@gmail.com) ESOFT Metro Campus lOMoARcPSD|24824932 Contents Acknowledgement................................................................................................................21 List of figures.......................................................................................................................22 List of tables.........................................................................................................................23 Activity 01....................................................................................................25 Part 1....................................................................................................................................25 Part 2....................................................................................................................................27 Part 3....................................................................................................................................29 Part 4....................................................................................................................................34 Activity 02....................................................................................................38 Part 1....................................................................................................................................38 Activity 02....................................................................................................38 Part 1....................................................................................................................................38 Part 2....................................................................................................................................42 Part 4....................................................................................................................................45 Activity 03....................................................................................................50 Part 1....................................................................................................................................50 Part 2....................................................................................................................................52 Part 3....................................................................................................................................54 Part 4....................................................................................................................................57 Activity 04....................................................................................................62 Part 1....................................................................................................................................62 Part 2....................................................................................................................................63 Part 3....................................................................................................................................67 Part 4....................................................................................................................................67 Bibliography..................................................................................................72 List of figures Figure 1.....................................................................................................................................37 Figure 2.....................................................................................................................................38 Figure 3.....................................................................................................................................38 Figure 4.....................................................................................................................................41 A.A.L.S.Amarasinghe Discrete Mathema琀椀cs Downloaded by adviu consulting (adviucons@gmail.com) ESOFT Metro Campus lOMoARcPSD|24824932 Figure 5.....................................................................................................................................41 Figure 6.....................................................................................................................................42 Figure 7.....................................................................................................................................44 Figure 8.....................................................................................................................................46 Figure 9.....................................................................................................................................47 Figure 10...................................................................................................................................47 Figure 11...................................................................................................................................49 Figure 12...................................................................................................................................49 Figure 13...................................................................................................................................50 Figure 14...................................................................................................................................50 Figure 15...................................................................................................................................51 Figure 16...................................................................................................................................51 Figure 17...................................................................................................................................62 Figure 18...................................................................................................................................62 Figure 19...................................................................................................................................63 Figure 20...................................................................................................................................63 Figure 21...................................................................................................................................64 Figure 22...................................................................................................................................71 Figure 23...................................................................................................................................72 Figure 24...................................................................................................................................72 Figure 25...................................................................................................................................73 Figure 26...................................................................................................................................73 Figure 27...................................................................................................................................74 Figure 28...................................................................................................................................75 Figure 29...................................................................................................................................76 List of tables Table 1......................................................................................................................................31 Table 2......................................................................................................................................54 Table 3......................................................................................................................................55 Table 4......................................................................................................................................56 A.A.L.S.Amarasinghe Discrete Mathema琀椀cs Downloaded by adviu consulting (adviucons@gmail.com) ESOFT Metro Campus lOMoARcPSD|24824932 Table 5......................................................................................................................................56 A.A.L.S.Amarasinghe Discrete Mathema琀椀cs Downloaded by adviu consulting (adviucons@gmail.com) ESOFT Metro Campus lOMoARcPSD|24824932 Activity 01 Part 1 1. Perform algebraic set operations in the following formulated mathematical problems. I. Let A and B be two non-empty finite sets. If cardinalities of the sets A, B, and are 72, 28 and 13 respectively, find the cardinality of the set. P(A) = 72 P(B) = 28 P() =13 ()=P(A)+P(B) - P() =72 + 28 – 13 =87 II. If n()=45, n()=110 and n()=15, then find n(B). P()= P()=P(A) - P()= 45 P()=110 P()= 15 P(A)= P() = 45 P(A)= 60 P(A)= 45 + P() P(A)= 45 + 15= 60 P()=P(A)+P(B) - P() 110= 60 + P(B) – 15 110= 60 – 15 + P(B) 110 – 45 = P(B) P(B) = 65 A.A.L.S.Amarasinghe Discrete Mathema琀椀cs Downloaded by adviu consulting (adviucons@gmail.com) ESOFT Metro Campus lOMoARcPSD|24824932 II. If n(A)=33, n(B)=36 and n(C)=28, find n(). P()= ? P(A)= 33 P(B)= 36 P(C)= 28 P()=P(A)+ P(B)+ P(C) - P() - P()-P() P(A)= 10+ a + 5+b = 33 15+a+b = 33 a + b = 18 1 15+a+5+c = 36 20+ a+ c =36 a + c = 16 2 13+ 5+b+c = 28 b + c= 28 – 18 b + c = 10 3 a + b = 18 1 b + c= 160 2 b + c = 16 3 1+3 a + b – b-c = 8 a - c =8 4 2+4 2a = 24 a= 12 A.A.L.S.Amarasinghe Discrete Mathema琀椀cs Downloaded by adviu consulting (adviucons@gmail.com) ESOFT Metro Campus lOMoARcPSD|24824932 b=6 c=4 P() = 33+ 36+28- 17-11-9 = 97 – 37 = 60 Part 2 I. Write the multisets (bags) of prime factors of given numbers. i. 160 = {2, 2, 2, 2, 2, 5} ii. 120 = {2, 2, 2, 2, 3, 5} iii. 250 = {2, 5, 5, 5} II. Write the multiplicities of each element of multisets (bags) in Part 2-1(i,ii,iii) separately. i. 160={2, 2, 2, 2, 2, 5} Multiplicity of 2 = 5 Multiplicity of 5 = 1 ii. 120={2, 2, 2, 2, 3, 5} Multiplicity of 2 = 3 Multiplicity of 3 = 1 Multiplicity of 5 = 5=1 iii. 250={2, 5, 5, 5} Multiplicity of 2 = 2 Multiplicity of 5 = 3 A.A.L.S.Amarasinghe Discrete Mathema琀椀cs Downloaded by adviu consulting (adviucons@gmail.com) ESOFT Metro Campus lOMoARcPSD|24824932 III. Determine the cardinalities of each multisets (bag) in Part 2-1(i,ii,iii). i. Cardinality of multi set = 5 + 1 = 6 ii. Cardinality of multi set = 3 + 1 +1 = 5 iii. Cardinality of multi set = 2 + 3 = 5 A.A.L.S.Amarasinghe Discrete Mathema琀椀cs Downloaded by adviu consulting (adviucons@gmail.com) ESOFT Metro Campus lOMoARcPSD|24824932 Part 3 I. Determine whether the following functions are invertible or not and if a function is invertible, then find the rule of the inverse using appropriate mathematical technique. N = {1,2,3,4,5,} Z = {…. -3, -2, -1,0,1,2,3,4, 5….} Z+ = {1,2,3,4, 5….} Z- = {…. -3, -2, -1,} I. f(x) = 2x f (-3) = 2*(-3) = (-6) →f2 * (-6) = (-12) f (-2) = 2*(-2) = (-4) →f2 * (-4) = (-8) f (-1) = 2*(-1) = (-2) →f2 * (-2) = (-4) f (0) = 2*(0) = (0) →f2 * (0) = (0) f (1) = 2*(1) = (2) →f2 * (2) = (4) f (2) = 2*(2) = (4) →f2 * (4) = (8) f (3) = 2*(3) = (6) →f2 * (6) = (12) II. A.A.L.S.Amarasinghe Discrete Mathema琀椀cs Downloaded by adviu consulting (adviucons@gmail.com) ESOFT Metro Campus lOMoARcPSD|24824932 X1, x2 be two different numbers from domain →① →② ①-② F(x1) = f(x2) x1=x2 1-1 function F(x) = y Y= 1/x X=1/y X→y→x Y= 1/x (inverse function) = x 1 2 4 5 25 X2 1 4 16 25 625 A.A.L.S.Amarasinghe Function() Discrete Mathema琀椀cs Downloaded by adviu consulting (adviucons@gmail.com) ESOFT Metro Campus lOMoARcPSD|24824932 0.1 0.0 0.01 0.000 1 Table 1 1 X1, x2 be two different numbers from domain →① →② ①=② X12= X22 Take the square root x1 = +x2 x1 = x2 then 1 – 1 function inverse exit. f(x) = y y = x2 Take the square root x=y&y=x (inverse) = III. = - sin =(-1) A.A.L.S.Amarasinghe =sin = 1 Discrete Mathema琀椀cs Downloaded by adviu consulting (adviucons@gmail.com) ESOFT Metro Campus lOMoARcPSD|24824932 sin (-x) = - sin (x) = -sin =sin A.A.L.S.Amarasinghe Discrete Mathema琀椀cs Downloaded by adviu consulting (adviucons@gmail.com) ESOFT Metro Campus lOMoARcPSD|24824932 Sin 0 = 0 onto function X1, x2 be two different numbers f (x1) = sin (x1) →① f (x2) = sin (x2) →② ①=② sin (x1) = sin (x2) f (x) = sin (x) y = f (x) y = sin (x) sin -1(y) = x x→y&y→x y = sin -1(x) = sin -1(x) IV. = - sin =(-1) =sin = 1 sin (-x) = - sin (x) = -sin =sin A.A.L.S.Amarasinghe Discrete Mathema琀椀cs Downloaded by adviu consulting (adviucons@gmail.com) ESOFT Metro Campus lOMoARcPSD|24824932 Sin 0 = 0 onto function X1, x2 be two different numbers f (x1) = sin (x1) →① f (x2) = sin (x2) →② ①=② sin (x1) = sin (x2) f (x) = sin (x) y = f (x) y = sin (x) sin -1(y) = x x→y&y→x y = sin -1(x) = sin -1(x) Part 4 I. Formulate corresponding proof principles to prove the following properties about defined sets. A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 . If , it must be (maximum; A<B or minimum ; A=B); B A But for become both of above condition, it must be A=B; Then it will be; It proof that De Morgan’s Law by mathematical induction. De Morgan’s Law is A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 Let P = (A U B)' and Q = A' ∩ B' Let x be an arbitrary element of P then x ∈ P ⇒ x ∈ (A U B)' ⇒ x ∉ (A U B) ⇒ x ∉ A and x ∉ B ⇒ x ∈ A' and x ∈ B' ⇒ x ∈ A' ∩ B' ⇒x∈Q Therefore, P ⊂ Q …………….. (i) Again, let y be an arbitrary element of Q then y ∈ Q ⇒ y ∈ A' ∩ B' ⇒ y ∈ A' and y ∈ B' ⇒ y ∉ A and y ∉ B ⇒ y ∉ (A U B) ⇒ y ∈ (A U B)' ⇒y∈P Therefore, Q ⊂ P …………….. (ii) Now combine (i) and (ii) we get; P = Q i.e. (A U B)' = A' ∩ B' Distributive Laws for three non-empty finite sets A, B, and C. A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 Figure 1 Distributive Laws for three non-empty finite sets A, B, and C A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 Figure 2 Activity 02 Part 1 Figure 3 Activity 02 Part 1 A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 I. Model two contextualized problems using binary trees both quantitatively and qualitatively. A binary tree is a tree data structure in which each node can have up to two child nodes, which form the tree's branches. The left and right nodes are the names given to the two offspring. Child nodes may include references to their parents, whereas parent nodes may contain references to their children. We broaden the definition of linked data structures to include nodes with multiple self-referenced fields. A binary tree is made up of nodes, each of which has a "left" and "right" reference as well as a data element. The root refers to the tree's topmost node. More tree terminology: 1. The depth of a node is the number of edges from the root to the node. 2. The height of a node is the number of edges from the node to the deepest leaf. 3. The height of a tree is a height of the root. 4. A full binary tree is a binary tree in which each node has exactly zero or two children. 5. A complete binary tree is a binary tree, which is completely filled, with the possible exception of the bottom level, which is filled from left to right. A complete binary tree is very special tree, it provides the best possible ratio between the number of nodes and the height. The height h of a complete binary tree with N nodes is at most O(log N). We can easily prove this by counting nodes on each level, starting with the root, assuming that each level has the maximum number of nodes: Advantages of trees Trees are so useful and frequently used, because they have some very serious advantages: 1. Trees reflect structural relationships in the data 2. Trees are used to represent hierarchies 3. Trees provide an efficient insertion and searching 4. Trees are very flexible data, allowing to move sub trees around with minimum effort Binary Search Trees A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 We consider a particular kind of a binary tree called a Binary Search Tree (BST). The basic idea behind this data structure is to have such a storing repository that provides the efficient way of data sorting, searching and retrieving. A BST is a binary tree where nodes are ordered in the following way: 1. each node contains one key (also known as data) 2. the keys in the left sub tree are less than the key in its parent node, in short L < P; 3. the keys in the right sub tree are greater the key in its parent node, in short P < R; 4. Duplicate keys are not allowed. In the following tree all nodes in the left sub tree of 10 have keys < 10 while all nodes in the right sub tree > 10. Because both the left and right sub trees of a BST are again search trees; the above definition is recursively applied to all internal nodes: [ CITATION bin21 \l 1033 ] Implementation We implement a binary search tree using a private inner class BSTNode. In order to support the binary search tree property, we require that data stored in each node is Comparable: Figure 4 A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 Binary Trees quantitatively and qualitatively; Quantitatively mean we can use tree data structure for valuable examples. Let’s focus on following situation. For example; There is a school with two classes and need to know about number of girls and boys on these classes. Figure 5 Qualitatively mean we can use tree data structure for quality measurement examples. Let’s focus on following situation. For example; A recursive partitioning tree showing survival of passengers on the Titanic ("sibsp" is the number of spouses or siblings aboard). The figures under the leaves show the probability of survival and the percentage of observations in the leaf. [ CITATION Bin21 \l 1033 ] Figure 6 A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 Part 2 I. State the Dijkstra’s algorithm for a directed weighted graph with all non-negative edge weights. Dijkstra's algorithm is one method for determining the shortest path from a beginning node to a target node in a weighted network. The technique builds a tree of shortest routes from the source vertex to every other point in the graph. Dijkstra's method, named after its developer, Dutch computer scientist "Edsger Dijkstra," was released in 1959 and may be used on a weighted graph. There are two types of graphs: directed and undirected. One requirement for utilizing the technique is that every edge in the graph has a nonnegative weight. 1. Make a set called sptSet to keep track of the vertices in the shortest path tree. 2. For instance, whose minimal distance from the source has been determined and finalized. This collection is initially empty. 3. Assign a distance value to each of the input graph's vertices. All distance values should be set to INFINITE. Assign the source vertex a distance value of 0 to ensure that it is chosen first. 4. sptSet does not contain all vertices. 5. Choose a vertex u that is not in sptSet and has the smallest distance value. 6. Add u to the sptSet. 7. Update the distance between all of u's neighboring vertices. Iterate over all neighboring vertices to update the distance values. If the total of the distance value of u and the weight of edge u-v is less than the distance value of v for each neighboring vertex v, then update the distance value of v. [ CITATION Dij211 \l 1033 ] A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 II. Use Dijkstra’s algorithm to find the shortest path spanning tree for the following weighted directed graph with vertices A, B, C, D, and E given. Consider the starting vertex as E. Figure 7 A to B = 5 units A to C = 3 units A to D = 7units A to E = 7 units. First Strat from E. Then; A – B = 5. A– D = 3. Select D. Then; D – B = 2. D – B = 6. Select B. Then; B– E = 4. Select E. End is C. A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 Shortest path is A – D – B – E – C. Part 3 I. Assess whether the following undirected graphs have an Eulerian and/or Hamiltonian cycle. i. Figure 8 This is not Eulerian: “E” vertices cannot cover because there is only one edge to visit “E”. But this has Hamilton circuit. ii. A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 Figure 9 This is not Eulerian: Because one edge is needed to complete the route So, this has Hamilton circuit. iii. Figure 10 This is not Eulerian: Because one edge is needed to complete the route. So this has Hamilton circuit. A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 Part 4 1. Construct a proof of the five color theorem for every planar graph. The five color theorem is a graph theory conclusion that states that given a plane divided into regions, such as a political map of a state's counties, the areas may be colored using no more than five colors, with no two neighboring parts receiving the same color. Contradiction serves as proof. Let G be the smallest planar structure (in terms of vertices) that can't be colored with more than five colors. Let v be the vertex in G with the highest degree. The corollary to Euler's formula tells us that deg(v) = 6. 1.Case #1: deg(v) ≤ 4. G-v can be colored with five colors. G-v may be colored with five different colors in case #1: deg(v) = 4. The neighbors of v have been painted in a maximum of four colors. Then v. is available in at least one color. As a result, G may be colored in five different ways, which is a contradiction. Figure 11 A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 Deg(v) = 5 in case #2. G-v can be colored in five different ways. There is a color accessible for v if two of its neighbors are colored with the same color. As a result, we may suppose that all vertices next to v are colored in clockwise sequence with colors 1,2,3,4,5. Assume that colors 1 and 3 are used to color all of the vertices (and all the edges among them). Figure 12 We can flip the colors 1 and 3 in the component with v1 if this subgraph G is unconnected and v1 and v3 are in separate components. Figure 13 A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 G-v will still be colored in five colors. Furthermore, in this new 5-coloring, v1 is colored with color 3 and v3 is still colored with color 3. Color 1 would be accessible for v, which is incongruent. As a result, v1 and v3 must be in the same component in that sub graph, i.e. there must be a path from v1 to v3 that is colored with either color 1 or color 3. Figure 14 Assume that all of the vertices are colored in colors 2 and 4. (and all the edges among them). If v2 and v4 are not linked components, we can swap the colors in the chain starting at v2 and utilize the leftover color for v. Figure 15 If they are on the same linked component, a path exists from v2 to v4 along which every vertex has either color 2 or color 4. A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 Figure 16 This implies that there must be two intersecting edges. This violates the graph's planarity, bringing the evidence to a close.[ CITATION pro21 \l 1033 ] A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 Activity 03 Part 1 I. Diagram two real world binary problems in two different fields using applications of Boolean algebra. A sequence of logic gates are coupled together to turn on and off each part of a calculator's display. Consider only the lower right-hand section. If we're showing the numerals 0 (binary 00), 1 (01), 3 (11), 4 (100), 5 (101), 6 (110), 7 (111), 8 (1000), and 9 (1000), we'll need to turn this segment on (1001) But not if the number 2 is displayed (10). By wiring up three OR gates and one NOT gate like this, you can make the segment turn on and off appropriately for the digits 1–10. If you enter the binary number patterns into the four inputs on the left, each section will turn on and off appropriately. Representing numbers in binary; Computers and calculators have been created using a variety of switching devices that can be in one of two positions over the previous century or more. It just contains “one (1)” or “zero (0)” in it. As a result, computers and calculators employ binary code to store and process numbers, which requires only two symbols (0 and 1) to represent any number. So in binary code, the number 18 is written 10010, Which means; (1 × 16) + (0 × 8) + (0 × 4) + (1 × 2) + (1 × 0) =16+2 =18 Using logic gates with binary Someone wants to do the sum 3 + 2 = 5. A calculator solves a problem like this by converting the two integers to binary, resulting in 101 (5 in binary = 1 4 + 0 2 + 1 1) by adding 11 (which is 3 in binary = 1 2 + 1 1) and 10 (2 in binary = 1 2 + 0 1). So, how does the calculator calculate the total? It employs logic gates to compare the active switch pattern and generate a new switch pattern in its place. A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 A logic gate is a basic electrical circuit that compares two numbers and generates a third number based on the original numbers' values. There are 4 very common types of logic gates. 1. OR 2. AND 3. NOT 4. XOR An OR gate has two inputs and it produces an output of 1 if either of the inputs is 1; it produces a zero otherwise. An AND gate also has two inputs, but it produces an output of 1 only if both inputs are 1. A NOT gate has a single input and reverses it to make an output. So if feed it a zero, it produces a 1. An XOR gate gives the same output as an OR gate, but switches off if both its inputs are one. [ CITATION rea21 \l 1033 ] A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 Part 2 I. Produce truth tables and its corresponding Boolean equation for the following scenarios. i. If the driver is present and the driver has not buckled up and the ignition switch is on, then the warning light should turn on. P: - The driver is present Q: -The driver has buckled up R: - The ignition switch is on S: - The warning light should turn ON Pᴧ QᴧR=S Boolean equalization = P.Ǭ.R P Q R Q T T T T T F T F F T F T F F F F Table 2 T F T F T F T F F F T T F F T T Pᴧ Q F F T T F F F F Pᴧ QᴧR=S F F T F F F F F ii. If it rains and you don't open your umbrella, then you will get wet. P: - It rains Q: - you open your umbrella R: - you will get wet A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 (P ᴧ Q) → R P Q R Q T T T T T F T F F T F T F F F F Table 3 T F T F T F T F F F T T F F T T A.A.L.S.Amarasinghe Pᴧ Q F F T T F F F F Pᴧ Q→R T T T F T T T T Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 II. Produce truth tables for given Boolean expressions. I. A B 0 0 0 0 0 1 0 1 1 0 1 0 1 1 1 1 Table 4 C 0 1 0 1 0 1 0 1 1 1 1 1 0 0 0 0 1 1 0 0 1 1 0 0 1 0 1 0 1 0 10 0 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1 0 1 1 0 1 1 0 1 0 0 1 II. A 0 0 0 0 1 1 1 1 B 0 0 1 1 0 0 1 1 C 0 1 0 1 0 1 0 1 1 1 1 1 0 0 0 0 1 1 0 0 1 1 0 0 1 0 1 0 1 0 11 0 1 1 0 1 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 0 1 1 0 1 0 1 1 0 1 1 following Boolean expressions using algebraic methods. I. = AA + AB + BB + BC + CC + CA = A + AB + B + BC +C + CA Table 5 = A + B (A + 1) + C (B + 1) + CA = B + C + A (1 + C) =A+B+C II. A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) Part 3 I. Simplify the lOMoARcPSD|24824932 = AB + AC + B`B + B`C + AC + A`A + BC + BA` = AB + AC + 0 + B`C + AC + 0 + BC + BA` = AB + AC + C (B` + B) + BA` = B (A + A`) + AC + C = B + C (A + 1) =B+C III. =AAC + AAC` + BAC + BAC` + AB + B = A (C + C`) + BA (C + C`) + (A +1) B = A + BA + B = A + AB + B + AB = A (1 + B) + B (1 + A) =A+B IV. = AA` + A`B + BA + BB` + AA + AB` = A`B + AB + A + AB` = (A` + A) B + A (1 + B`) A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 = B+A A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 Part 4 I. Consider the K-Maps given below. For each K- Map I. Write the appropriate standard form (SOP/POS) of Boolean expression. The sum-of-products (SOP) form is a technique (or form) for reducing logic gates' Boolean statements. The variables are ANDed (summed or added) together in this SOP form of Boolean function representation to produce a product term, and all of these product terms are ORed (summed or added) together to make the final function. Part a) is for the left K-map, Part b) is for the right K-map. AB/C 0 00 0 01 AB/C 1 00 0 01 1 11 10 0 11 D 00 0 1 10 0 1 10 01 1 0 01 0 1 11 1 1 1 0 10 1 1 1 1 SOP=A′BC+ABC+AB′C′ POS=(A'B'+C')(A'B'+C)(A'B+C')(AB+C')(AB'+C)POS=(A′B′+C′)(A′B′+C)(A′B+C′)(AB+C′)(AB′+C) (A'B'+C')=(A'+C')(B'+C')=(A'+C'+B')(A'+C'+B)\times(A′B′+C′)=(A′+C′)(B′+C′)=(A′+C′+B′)(A′+C′+B)× \times (B'+C'+A')(B'+C'+A)=(A'+C'+B')(A'+C'+B))(B'+C'+A)×(B′+C′+A′)(B′+C′+A)=(A′+C′+B′)(A′+C′ +B))(B′+C′+A) (A'B'+C)=(A'+C)(B'+C)=(A'+C+B)(A'+C+B')\times(A′B′+C)=(A′+C)(B′+C)=(A′+C+B)(A′+C+B′)× A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 \times(B'+C+A)(B'+C+A')=(A'+C+B)(A'+C+B')(B'+C+A)×(B′+C+A)(B′+C+A′)=(A′+C+B)(A′+C+B′)(B′ +C+A) (A'B+C')=(A'+C')(B+C')=(A'+C'+B)(A'+C'+B')\times(A′B+C′)=(A′+C′)(B+C′)=(A′+C′+B)(A′+C′+B′)× \times(B+C'+A)(B+C'+A')=(A'+C'+B)(A'+C'+B')(B+C'+A)×(B+C′+A)(B+C′+A′)=(A′+C′+B)(A′+C′+B′) (B+C′+A) (AB+C')=(A+C')(B+C')=(A+C'+B)(A+C'+B')\times(AB+C′)=(A+C′)(B+C′)=(A+C′+B)(A+C′+B′)× \times(B+C'+A)(B+C'+A')=(A+C'+B)(A+C'+B')(B+C'+A')×(B+C′+A)(B+C′+A′)=(A+C′+B)(A+C′+B′) (B+C′+A′) (AB'+C)=(A+C)(B'+C)=(A+C+B)(A+C+B')\times(AB′+C)=(A+C)(B′+C)=(A+C+B)(A+C+B′)× \times(B'+C+A)(B'+C+A')=(A+C+B')(A+C+B')(B'+C+A')×(B′+C+A)(B′+C+A′)=(A+C+B′)(A+C+B′)(B′ +C+A′) Standard form: POS=(A'+C'+B')(A'+C'+B))(B'+C'+A)(A'+C+B)(A'+C+B')\timesPOS=(A′+C′+B′)(A′+C′+B))(B′+C′+A) (A′+C+B)(A′+C+B′)× \times(B'+C+A)(B+C'+A)×(B′+C+A)(B+C′+A) A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 II. Design the circuit using AND, NOT and OR gates. Figure 17 III. Design the circuit only by using NAND gates if the standard form obtained in part (i) is SOP. NOR gates if the standard form obtained in pat (i) is POS. OR gate using NAND gate: A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 Figure 18 AND gate using NAND gate: Figure 19 THEN; A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 Figure 20 A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 B) i. SOP=A′B′C′D′+A′B′CD′+A′BC′D+A′BCD′+ABC′D′+ +ABC'D+ABCD+AB'C'D'+AB'C'D+AB'CD+AB'CD'+ABC′D+ABCD+AB′C′D′+AB′C′D+AB′CD+AB ′CD′ POS=(A'B'+C'D)(A'B'+CD)(A'B+C'D')(A'B+CD)(AB+CD')POS=(A′B′+C′D)(A′B′+CD)(A′B+C′D′)(A ′B+CD)(AB+CD′) II. Figure 21 A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 Activity 04 Part 1 I. Describe the distinguishing characteristics of different binary operations that are performed on the same set. Just like when two numbers are combined, subtracted, multiplied, or divided, we obtain a number. Any two members of a set can be linked using binary operations. The resultant of the two is in the same set as the resultant of the two. Calculations that combine two items of a set (called operands) to generate another element of the same set are known as binary operations on a set. The binary operations * on a non-empty set A are functions from A × A to A. The binary operation, *: A × A → A. It is an operation of two elements of the set whose domains and co-domain are in the same set. Addition, subtraction, multiplication, division, exponential is some of the binary operations. Types of Binary Operations Commutative A binary operation * on a set A is commutative if a * b = b * a, for all (a, b) ∈ A (non-empty set). Let addition be the operating binary operation for a = 8 and b = 9, a + b = 17 = b + a. Associative The associative property of binary operations hold if, for a non-empty set A, we can write (a * b) *c = a*(b * c). Suppose N be the set of natural numbers and multiplication be the binary operation. Let a = 4, b = 5 c = 6. We can write (a × b) × c = 120 = a × (b × c). Distributive Let * and o be two binary operations defined on a non-empty set A. The binary operations are distributive if a*(b o c) = (a * b) o (a * c) or (b o c)*a = (b * a) o (c * a). Consider * to be multiplication and o be subtraction. And a = 2, b = 5, c = 4. Then, a*(b o c) = a × (b − c) = 2 × (5 − 4) = 2. And (a * b) o (a * c) = (a × b) − (a × c) = (2 × 5) − (2 × 4) = 10 − 6 = 2. Identity If A be the non-empty set and * be the binary operation on A. An element e is the identity element of a ∈ A, if a * e = a = e * a. If the binary operation is addition (+), e = 0 and for * is multiplication (×), e = 1. A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 Inverse If a binary operation * on a set A which satisfies a * b = b * a = e, for all a, b ∈ A. a-1 is invertible if for a * b = b * a= e, a-1 = b. 1 is invertible when * is multiplication. [ CITATION dis21 \l 1033 ] Part 2 I. Determine the operation tables for group G with orders 1, 2, 3 and 4 using the elements a, b, c, and e as the identity element in an appropriate way. Multiplication is a binary operation on each of the sets of Natural numbers (N), Integer numbers (Z), Rational numbers (Q), Real Numbers (R), and Complex numbers (C) (C). On the set of Natural numbers (N), integers (Z), Rational numbers (Q), Real Numbers (R), and Complex numbers (C), division is not a binary operation (C). As Binary Operation Properties On the set of Natural numbers, subtraction is not a binary operation (N). The binary operations on each of the sets of Natural numbers (N), Integers (Z), Rational numbers (Q), Real Numbers (R), and Complex numbers (C) are known as additions (C). As Properties of Binary Operation Exponential operation (x, y) → xy is a binary operation on the set of Natural numbers (N) and not on the set of Integers (Z). II. State the relation between the order of a group and the number of binary operations that can be defined on that set. Because the set has n items and binary operations (i.e., two operations) may be performed on each of them in relation, the total number of possible combinations is n. 2n.2n−1...22.2=21+2+...n=22n(n−1) . III. How many binary operations can be defined on a set with 4 elements? The formula is 2^{n(n-1)/2}2n(n−1)/2 where n is number of elements Therefore binary operations can be defined on a set with 4 elements A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 = 2^{4(4-1)/2} = 2^6 = 64=24(4−1)/2=26=64 iv. State the Lagrange’s theorem of group theory. Lagrange's theorem is a statement in group theory that may be thought of as an extension of Euler's theorem's number theoretical result. It's a crucial lemma in group theory for proving more complex conclusions. V. For a subgroup H of a group G, prove the Lagrange’s theorem. If G is a finite group and H is a subgroup of G, then ∣H∣ divides ∣G∣. As an immediate corollary, we get that if G is a finite group and g ∈G, then o(g) divides ∣G∣. In particular, ∣G∣=e for all g ∈G. ii. Before proving Lagrange’s Theorem, state and prove three lemmas. Lemma 1. If G is a group with subgroup H, then there is a one to one correspondence between H and any coset of H. Proof. Let C be a left coset of H in G. Then there is a g ∈ G such that C = g ∗ H. 1 Define f : H → C by f(x) = g ∗ x. f is one to one. If x1 6= x2, then as G has cancellation, g ∗ x1 6= g ∗ x2. Hence, f(x1) 6= f(x2). f is onto. If y ∈ C, then since C = g ∗ H, there is an h ∈ H such that y = g ∗ h. It follows that f(h) = y and as y was arbitrary, f is onto. This completes the proof of Lemma 1. Lemma 2. If G is a group with subgroup H, then the left coset relation, g1 ∼ g2 if and only if g1 ∗ H = g2 ∗ H is an equivalence relation. Proof. The essence of this proof is that ∼ is an equivalence relation because it is defined in terms of set equality and equality for sets is an equivalence relation. The details are below. A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 • ∼ is reflexive. Let g ∈ G be given. Then, g ∗H = {g ∗h : h ∈ H} and as this set is well defined, g ∗H = g ∗H. 1We use “∗” to represent the binary operation in G. • ∼ is symmetric. Let g1, g2 ∈ G with g1 ∼ g2. Then by the definition of ∼, g1 ∗H = g2 ∗H. That is, {g1 ∗h : h ∈ H} = {g2 ∗ h : h ∈ H} and as set equality is symmetric, {g2 ∗ h : h ∈ H} = {g1 ∗ h : h ∈ H}. Hence, g2 ∼ g1 and as g1 and g2 were arbitrary, ∼ is symmetric. • ∼ is transitive. Let g1, g2, g3 ∈ G with g1 ∼ g2 and g2 ∼ g3. Then, g1 ∗ H = {g1 ∗ h : h ∈ H} = {g2 ∗ h : h ∈ H} = g2 ∗ H And g2 ∗ H = {g2 ∗ h : h ∈ H} = {g3 ∗ h : h ∈ H} = g3 ∗ H. As set equality is transitive, it follows that g1 ∗ H = {g1 ∗ h : h ∈ H} = {g3 ∗ h : h ∈ H} = g3 ∗ H, or g1 ∗ H = g3 ∗ H. That is, g1 ∼ g3, and as g1, g2, g3 ∈ G are arbitrary, ∼ is transitive. This complete the proof of the lemma. Lemma 3. Let S be a set and ∼ be an equivalence relation on S. If A and B are two equivalence classes with A ∩ B 6= ∅, then A = B. Proof. To prove the lemma, we show that A ⊂ B and B ⊂ A. As A and B are arbitrarily labeled, it suffices to show the former. Let a ∈ A. As A ∩ B 6= ∅, there is a c ∈ A ∩ B. As A is an equivalence class of ∼ and both a and a c are in A, it follows that a ∼ c. But as a ∼ c, c ∈ B and B is an equivalence class of ∼, it follows that a ∈ B. Armed with these three lemmas we proceed to the main result. Theorem 1. [Lagrange’s Theorem] If G is a finite group of order n and H is a subgroup of G of order k, then k|n and n k is the number of distinct cosets of H in G. Proof. Let ∼ be the left coset equivalence relation defined in Lemma 2. It follows from Lemma 2 that ∼ is an equivalence relation and by Lemma 3 any two distinct cosets of ∼ are disjoint. Hence, we can write A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 G = (g1 ∗ H) ∪ (g2 ∗ H) ∪ · · · ∪ (g` ∗ H) Where the gi ∗ H, i = 1, 2, . . . , ` are the disjoint left cosets of H guaranteed by Lemma 3. By Lemma 1, the cardinality of each of these cosets is the same as the order of H, and so This completes the proof. VI. Discuss whether a group H with order 6 can be a subgroup of a group with order 13 or not. Clearly state the reasons. Group H with order 6 can be a subgroup of a group with order 13 or not; however, as 6 does not divide 13, a group with order 13 elements cannot have a subgroup of 6 members. Because only this number has divisors of 13, it might have subgroups with 13 components. Part 3 I. Validate whether the set is a group under the binary operation ‘*’defined asfor any two elements. For Check whether the set is a group under the binary operation ‘*’defined as for any two elements ; need to think about group axioms. Assume that a * b = (-1) for this a = 1 and b = -1 or a = -1 and b = 1. If a = 1 and b = -1; LHS = -1 and RHS = -1 But . There for the set is a group under the binary operation ‘*’defined as for any two elements. A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 Part 4 Prepare a presentation for ten minutes to explore an application of group theory relevant to your course of study. (i.e. in Computer Sciences) Figure 22 A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 Figure 23 Figure 24 A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 Figure 25 Figure 26 A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 Figure 27 Figure 28 A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 Figure 29 Bibliography binary trees . (2021). Retrieved from https://www.geeksforgeeks.org/binary-tree-data-structure/ Binary Trees quantitatively and qualitatively. (2021). Retrieved from https://www.javatpoint.com/discretemathematics-binary-trees Dijkstra’s algorithm . (2021). Retrieved from https://www.geeksforgeeks.org/dijkstras-shortest-pathalgorithm-greedy-algo-7/ distinguishing characteristics of different binary operations . (2021). Retrieved from https://www.toppr.com/guides/maths/relations-and-functions/binary-operations/ proof of the five color theorem . (2021). Retrieved from http://cgm.cs.mcgill.ca/~athens/cs507/Projects/2003/MatthewWahab/5color.html#:~:text=5%2Dcolor %20theorem%20%E2%80%93%20Every%20planar,that%20has%20the%20maximum%20degree. real world binary problems in two different fields using applications of Boolean algebra. . (2021). Retrieved from https://oneclass.com/homework-help/mathematics/6552407-the-question-is-attached- below.en.html w3schools. (2019). w3schools. Retrieved from w3schools: https://www.w3schools.in/data-structurestutorial/binary-trees/ A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 www.cs.cmu.edu. (2018). www.cs.cmu.edu. Retrieved from www.cs.cmu.edu: https://www.cs.cmu.edu/~adamchik/15-121/lectures/Trees/trees.html A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 Grading Rubric Grading Criteria Achieved Feedback LO1 : Examine set theory and functions applicable to software engineering. P1 Perform algebraic set operations in a formulated mathematical problem. P2 Determine the cardinality of a given bag (multiset). M1 Determine the inverse of a function using appropriate mathematical technique. D1 Formulate corresponding proof principles to prove properties about defined sets. LO2 : Analyse mathematical structures of objects using graph theory. P3 Model contextualized problems using trees, both quantitatively and qualitatively. P4 Use Dijkstra’s algorithm to find a shortest path spanning tree in a graph. M2 Assess whether an Eulerian and Hamiltonian circuit exists in an undirected graph. A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 D2 Construct a proof of the Five colour theorem. LO3 : Investigate solutions to problem situations using the application of Boolean algebra. P5 Diagram a binary problem in the application of Boolean Algebra. P6 Produce a truth table and its corresponding Boolean equation from an applicable scenario. M3 Simplify a Boolean equation using algebraic methods. D3 Design a complex system using logic gates. LO4 : Explore applicable concepts within abstract algebra. P7 Describe the distinguishing characteristics of different binary operations that are performed on the same set. P8 Determine the order of a group and the order of a subgroup in given examples. M4 Validate whether a given set with a binary operation is indeed a group. D4 Explore with the aide of a prepared presentation the application of A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 group theory relevant to your course of study A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com) lOMoARcPSD|24824932 A.A.L.S.Amarasinghe Discrete Mathema琀椀cs ESOFT Metro Campus Downloaded by adviu consulting (adviucons@gmail.com)