10/4/22, 8:30 PM EEI Practice Tests Graphic Problem Solving - Answers and Explanations Copyright © 2020 by Edison Electric Institute (EEI). All rights reserved under U.S. and foreign law, treaties, and conventions. No part of this work may be reproduced or copied in any form or by any means - graphic, electronic, or mechanical, including photocopying, recording, taping, or information storage and retrieval systems - without prior written permission of the publisher. These practice tests are for informational purposes only, and are not a guarantee that an applicant will pass a related test. Question 1 Correct! The answer is D. What is the width of Platform a? 417.0 m https://secure.eei.org/eeitests/onlineproducts/PracticeTests/Tests/GraphicProblemSolvingResults(a).aspx 1/17 10/4/22, 8:30 PM EEI Practice Tests 897.0 m 952.6 m 1008.2 m Explanation: D is the correct answer. To calculate this, look at the measurements given for the three parts of Platform a. So, you would add 208.5 m + 208.5 m + 591.2 m to obtain the correct answer: 208.5 + 208.5 + 591.2 1008.2 Graphic Problem Solving - Answers and Explanations Question 2 Incorrect. You chose C. The correct answer is B. What is the total height (B) of the structure from its base to the top of the flag? 1158.6 m https://secure.eei.org/eeitests/onlineproducts/PracticeTests/Tests/GraphicProblemSolvingResults(a).aspx 2/17 10/4/22, 8:30 PM EEI Practice Tests 1255.0 m 1325.0 m 1419.9 m Explanation: B is the correct answer. To calculate this, look at the information given regarding the height of the structure. First, notice that the height of the structure from its base to the base of the flag is 1163 m. Also notice that a portion of this segment (from the top of Platform a to the base of the flag) is 814.1 m. If you subtract 814.1 m from 1163 m, you will get the height of the bottom portion of the structure, from its base to the top of Platform a. 1163.0 814.1 348.9 348.9 m = height of the structure from its base to the top of Platform a. You should also see that the height of the mid-to-upper portion of the structure (from the top of Platform a to the top of the flag) is given at 906.1 m. This distance includes the height of the top part of the structure, but does not include the height of the bottom portion of the structure, which is the height you just calculated. Therefore, add 906.1 to 348.9 to obtain the total height of the structure. 906.1 + 348.9 1255.0 Graphic Problem Solving - Answers and Explanations https://secure.eei.org/eeitests/onlineproducts/PracticeTests/Tests/GraphicProblemSolvingResults(a).aspx 3/17 10/4/22, 8:30 PM EEI Practice Tests Question 3 Correct! The answer is C. What is three times the height (C) of Platform a? 27.6 m 55.8 m 82.8 m 193.2 m Explanation: C is the correct answer. To calculate this, first determine the height of Platform a and then multiply by 3. To calculate the height of Platform a (C), look at the information given that relates to this height. First, see that the height of the structure from its base to the base of the flag is given at 1163 m. In addition, the height from the top of Platform a to the base of the flag is given at 814.1 m. If you subtract these two distances, you will obtain the height from the bottom of the structure to the top of Platform a. - 1163.0 814.1 348.9 Next, see that the height from the bottom of the structure to the bottom of Platform a is given at 321.3 m. Therefore, subtract 321.3 from 348.9 to find the height of Platform a (C). https://secure.eei.org/eeitests/onlineproducts/PracticeTests/Tests/GraphicProblemSolvingResults(a).aspx 4/17 10/4/22, 8:30 PM EEI Practice Tests 348.9 - 321.3 27.6 27.6 m = the height of Platform a (C). Now that you have found the height of Platform a (C), multiply by 3 to find three times the height. 27.6 x 3 82.8 82.8 m = three times the height of Platform a. Graphic Problem Solving - Answers and Explanations Question 4 Correct! The answer is A. What is the width of distance D? 175.6 m https://secure.eei.org/eeitests/onlineproducts/PracticeTests/Tests/GraphicProblemSolvingResults(a).aspx 5/17 10/4/22, 8:30 PM EEI Practice Tests 120.0 m 197.1 m 212.2 m Explanation: A is the correct answer. From the drawing, you can see that the distance (D) is the sum of the distance Y and X. Distance X is given; therefore, you need to find Y. To calculate this, look at the information given that relates to distance, D. First, you will see that you can subtract 240 m (the distance under Platform b) from 480 m (the distance between the two structure legs). - 480 240 240 Now, this distance is the total length of the remaining segments (Y on the right and left of Platform c. To calculate distance Y, divide 240 by 2. 120 2 240 2 04 4 0 Now that you have distance Y, you can add distance Y (120 m) and X (55.6 m) to get distance D. + 120.0 55.6 175.6 175.6 m = distance D. Graphic Problem Solving - Answers and Explanations https://secure.eei.org/eeitests/onlineproducts/PracticeTests/Tests/GraphicProblemSolvingResults(a).aspx 6/17 10/4/22, 8:30 PM EEI Practice Tests Question 5 Incorrect. You chose B. The correct answer is C. What is the total of distance E + distance F? 147.3 m 147.6 m 184.2 m 212.0 m Explanation: C is the correct answer. To calculate this answer, you must obtain the values for distances, E and F, and then add them together. From the drawing, you can see that distance E can be calculated by subtracting the height of the structure from the top of Platform a to the top of the flag (906.1 m) from the height of the structure from Platform a to the base of the flag (814.1 m). 906.1 - 814.1 92.0 92.0 m = distance E https://secure.eei.org/eeitests/onlineproducts/PracticeTests/Tests/GraphicProblemSolvingResults(a).aspx 7/17 10/4/22, 8:30 PM EEI Practice Tests Next, calculate the value for distance F. This can be done by finding the value Y, and subtracting it from distance R (27.8 m). To find the value of Y, subtract 240 (the distance under Platform b) from 480 m (the distance between the two structure legs). 480 - 240 240 This is the width of the two Y segments put together. These two segments are equal; therefore, to obtain Y, divide 240 by 2. 120 2 240 2 04 4 0 To calculate F, subtract the distance R (27.8 m) from the distance Y (120 m). 120.0 - 27.8 92.2 92.2m = distance F Now add distance E and distance F to get the correct answer. 92.0 + 92.2 184.2 184.2 m = distance E + distance F. Graphic Problem Solving - Answers and Explanations https://secure.eei.org/eeitests/onlineproducts/PracticeTests/Tests/GraphicProblemSolvingResults(a).aspx 8/17 10/4/22, 8:30 PM EEI Practice Tests Question 6 Correct! The answer is A. What is half the length of G (the height from the top of Platform c to the base of the flag)? 142.4 m 188.4 m 218.6 m 284.8 m Explanation: A is the correct answer. To answer this question, you must first look at information given regarding the height of the structure relevant to distance G. From the drawing, you will see that distance G can be calculated by subtracting the height of the structure from the top of Platform a to the base of the flag (814.1 m) from the height of the top of Platform a to the top of Platform c (529.3 m). 814.1 - 529.3 284.8 284.8 = distance G. Once you calculate distance G, the question asks you to determine what half the length is. https://secure.eei.org/eeitests/onlineproducts/PracticeTests/Tests/GraphicProblemSolvingResults(a).aspx 9/17 10/4/22, 8:30 PM EEI Practice Tests Therefore, divide distance G by 2: 142.4 2 284.8 2 08 8 04 4 08 8 0 142.4 m = half the length of distance G. Graphic Problem Solving - Answers and Explanations Question 7 Incorrect. You chose C. The correct answer is B. What is the temperature of Substance 3 at a density of 0.48 kg/m^3? 650 K https://secure.eei.org/eeitests/onlineproducts/PracticeTests/Tests/GraphicProblemSolvingResults(a).aspx 10/17 10/4/22, 8:30 PM EEI Practice Tests 700 K 445 K 550 K Explanation: B is the correct answer. To answer this question, look at the major markers on the vertical axis of the graph. You will see that density increases are marked for every .10 kg/m^3. This axis begins at a minimum density of 0.20 kg/m^3 and ends at a maximum density of 1.0 kg/m^3. The grid lines between these major divisions represent 0.02 increases in density. For example, starting from the bottom value (0.20 kg/m^3), the next horizontal line represents 0.22 kg/m^3, the next 0.24 kg/m^3, the next 0.26 kg/m^3, the next 0.28 kg/m^3, and finally you reach the next major division marker (0.30 kg/m^3). This is the same for the rest of the axis. Next, look at the major markers on the horizontal axis. You will see that temperature increases are marked for every 50 K. This axis begins at a minimum temperature of 300 K and ends at a maximum temperature of 900 K. The grid lines between these major divisions represent 25 K increases in temperature. Therefore, starting from the 300 K, the next vertical line represents 325 K, and then you reach the next major marker, 350 K. This is the same for the rest of the axis. To solve this problem, find the line for Substance 3 from the key in the upper right corner of the graph and the point on the graph where its density is 0.48 kg/m^3. Once you find this point, look at the horizontal axis to see what the corresponding temperature is for Substance 3. When Substance 3's density is 0.48 kg/m^3, its temperature is 700 K. Graphic Problem Solving - Answers and Explanations https://secure.eei.org/eeitests/onlineproducts/PracticeTests/Tests/GraphicProblemSolvingResults(a).aspx 11/17 10/4/22, 8:30 PM EEI Practice Tests Question 8 Incorrect. You chose B. The correct answer is D. At 475 K, what is the density shown for Substance 4? 0.50 0.49 0.62 0.48 Explanation: D is the correct answer. First, find the line for Substance 4 from the key in the upper right corner of the graph and the point on the graph where its temperature is 475 K. Once you find this point, look at the vertical axis to see the corresponding density for Substance 4. When substance 4's temperature is 475 K, its density is 0.48 kg/m^3. Graphic Problem Solving - Answers and Explanations Question 9 https://secure.eei.org/eeitests/onlineproducts/PracticeTests/Tests/GraphicProblemSolvingResults(a).aspx 12/17 10/4/22, 8:30 PM EEI Practice Tests Incorrect. You chose D. The correct answer is C. What is the difference in density for Substance 2 between 400 K and 875 K? 0.28 0.30 0.36 0.46 Explanation: C is the correct answer. First, find the line for Substance 2 from the key in the upper right corner of the graph. At 875 K, the density of Substance 2 is 0.34 kg/m^3. At 400 K, the density of Substance 2 is 0.70 kg/m^3. To find the difference, subtract 0.34 kg/m^3 from 0.70 kg/m^3. 0.70 - 0.34 = 0.36 The difference in density is .36 kg/m^3. Graphic Problem Solving - Answers and Explanations Question 10 Incorrect. You chose A. The correct answer is C. https://secure.eei.org/eeitests/onlineproducts/PracticeTests/Tests/GraphicProblemSolvingResults(a).aspx 13/17 10/4/22, 8:30 PM EEI Practice Tests At 0.46 kg/m^3, Substance 3 is _________ times as hot as at 0.55 kg/m^3. 1.26 1.75 1.25 1.55 Explanation: C is the correct answer. To solve this problem, find the line for Substance 3 from the key in the upper right corner of the graph. At 0.46 kg/m^3, Substance 3 is 750 K. At 0.55 kg/m^3, Substance 3 is 600 K. To calculate how many times hotter 750 K is than 600 K, divide 750 by 600. 1.25 600 750.00 600 150.0 120.0 30.00 30.00 0 Substance 3 is 1.25 times as hot at a density of .46 kg/m^3 (when it is 750 K) than it is at .55 kg/m^3 (when it is 600 K). Graphic Problem Solving - Answers and Explanations https://secure.eei.org/eeitests/onlineproducts/PracticeTests/Tests/GraphicProblemSolvingResults(a).aspx 14/17 10/4/22, 8:30 PM EEI Practice Tests Question 11 Incorrect. You chose A. The correct answer is B. Between which two points is the change in density the greatest for Substance 1? 300 K and 375 K 400 K and 550 K 500 K and 600 K 650 K and 900 K Explanation: B is the correct answer. Find the line for Substance 1 from the key in the upper right corner of the graph. Next, look at each answer choice and calculate the differences between each set of points to determine which has the greatest change in density for Substance 1. For answer choice A, the density of Substance 1 is 0.70 kg/m^3 at 300 K and 0.57 kg/m^3 at 375 K. To calculate the change in density, subtract 0.57 from 0.70. 0.70 kg/m^3 - 0.57 kg/m^3 = 0.13 kg/m^3. For answer choice B, the density of Substance 1 is 0.55 kg/m^3 at 400 K and 0.39 kg/m^3 at 550 K. To calculate the change in density, subtract 0.39 from 0.55. 0.55 kg/m^3 - 0.39 kg/m^3 = 0.16 kg/m^3. For answer choice C, the density of Substance 1 is 0.44 kg/m^3 at 500 K and 0.36 kg/m^3 at 600 K. To calculate the change in density, subtract 0.36 from 0.44. 0.44 kg/m^3 - 0.36 kg/m^3 = 0.08 kg/m^3. For answer choice D, the density of Substance 1 is 0.34 kg/m^3 at 650 K and 0.25 kg/m^3 at 900 K. To calculate the change in density, subtract 0.25 from 0.34. 0.34 kg/m^3 - 0.25 kg/m^3 = 0.09 kg/m^3. Based on the above calculations, a change in density of .16 for Substance 1 is the greatest of the four answer choices (.16 > .13 > .09 > .08). Graphic Problem Solving - Answers and Explanations https://secure.eei.org/eeitests/onlineproducts/PracticeTests/Tests/GraphicProblemSolvingResults(a).aspx 15/17 10/4/22, 8:30 PM EEI Practice Tests Question 12 Incorrect. You chose B. The correct answer is D. If you were to sum the temperatures in each answer choice, which would result in the highest combined temperature? Substance 1's temperature at a density of 0.44 kg/m^3 + Substance 4's temperature at a density of 0.44 kg/m^3 Substance 2's temperature at a density of 0.52 kg/m^3 + Substance 3's temperature at a density of 0.50 kg/m^3 Substance 4's temperature at a density of 0.35 kg/m^3 + Substance 1's temperature at a density of 0.55 kg/m^3 Substance 4's temperature at a density of 0.40 kg/m^3 + Substance 3's temperature at a density of 0.55 kg/m^3 Explanation: D is the correct answer. To determine which answer choice would result in the highest temperature, refer to the graph to identify each temperature at the corresponding densities and sum the values. For answer choice A, Substance 1's temperature at a density of 0.44 kg/m^3 is 500 K and Substance 4's temperature at a density of 0.44 kg/m^3 is 575 K. To calculate their combined temperature value, add 500 K to 575 K. 500 K + 575 K = 1075 K. For answer choice B, Substance 2's temperature at a density of 0.52 kg/m^3 is 575 K and Substance 3's temperature at a density of 0.50 kg/m^3 is 650 K. To calculate their combined temperature value, add 575 K to 650 K. https://secure.eei.org/eeitests/onlineproducts/PracticeTests/Tests/GraphicProblemSolvingResults(a).aspx 16/17 10/4/22, 8:30 PM EEI Practice Tests 575 K + 650 K = 1225 K. For answer choice C, Substance 4's temperature at a density of 0.35 kg/m^3 is 700 K and Substance 1's temperature at a density of 0.55 kg/m^3 is 400 K. To calculate their combined temperature value, add 700 K to 400 K. 700 K + 400 K = 1100 K. For answer choice D, Substance 4's temperature at a density of 0.40 kg/m^3 is 650 K and Substance 3's temperature at a density of 0.55 kg/m^3 is 600 K. To calculate their combined temperature value, add 650 K to 600 K. 650 K + 600 K = 1250 K. Based on the above calculations, a combined temperature value of 1250 K is the greatest of the four answer choices (1250 K > 1225 K > 1100 K > 1075 K). https://secure.eei.org/eeitests/onlineproducts/PracticeTests/Tests/GraphicProblemSolvingResults(a).aspx 17/17