Common Student’s Mistakes in Mathematics I NDICES This tells your teacher that you are bad at math. (π₯ + 5)2 πΌπ πππ π₯ 2 + 25 Proof: (π₯ + 5)2 = (π₯ + 5)(π₯ + 5) = (π₯ + 5)(π₯ + 5) = π₯ 2 + 10π₯ + 25 Another example: (π₯ + π¦)2 = π₯ 2 + π¦ 2 Proof: = (π₯ + π¦)(π₯ + π¦) = π₯ 2 + 2π₯π¦ + π¦ 2 π₯ 2 + 2π₯π¦ + π¦ 2 πΌπ πππ π₯ 2 + π¦ 2 You can multiply them here, because inside the parenthesis the variables are multiplied by each other (π₯ 2 π¦ 3 )2 = π₯ 4 π¦ 6 Proof: (π₯ 2 π¦ 3 )2 = (π₯ 2 π¦ 3 )(π₯ 2 π¦ 3 ) = π₯2 ∗ π₯2 ∗ π¦3 ∗ π¦3 = π₯ 2+2 π¦ 3+3 Therefor: = π₯ 4π¦6 The same thing applies to square roots, 2 √π₯ 2 + π¦ 2 = π₯ + π¦? 2 ππ √π₯ 2 + 25 = π₯ + 5? You cannot simplify those equations 2 π‘πππ √32 + 32 2 = √9 + 9 2 = √18 ≈ 4.24 2 πππ€ π‘ππ¦ √32 + 32 2 = √3 2 + 3 2 =3+3 =6 4.24 ≠ 6 2 √3 2 + 3 2 ≠ 3 + 3 What about this? 2 2 2 √π₯ + π¦ ≠ √ π₯ + √π¦ Try to prove it by changing [x, y] to integers. 2 √3 + 6 2 = √9 =3 2 2 √3 + √6 = 1.73 + 2.45 = 4.18 3 ≠ 4.18 2 2 √3 + 6 ≠ √3 + √6 2 F RACTIONS Fractions is where most students don’t really understand. or worse invent new mathematics 2 3 3 4 ππ ππ‘ 2 3 3 ÷ ππ 2 ÷ 3 ÷ ππ … ? 3 4 4 First of all, look at the biggest fraction sign 2 3 3 4 = 2 3 ÷ 3 4 Now if you don’ remember elementary math, to divide two fractions. Flip the sign to multiplication (*) then flip the 2nd fraction. Finally, multiply. 2 3 ÷ 3 4 2 4 = ∗ 3 3 8 = 9 You can make sure by inputting the operation into calculator like this 2 ÷ 3 = 0. 6Μ 3 ÷ 4 = 0.75 0. 6Μ ÷ 0.75 = 0. 8Μ 8 ÷ 9 = 0. 8Μ Therefor 2 3 3 4 = 2 3 ÷ 3 4 Try the other form of fractions and see the answer, it’ll be different thus implying which is the correct one. Canceling in fractions, could you cross out any number/variable in this equation? Well, let’s try 3π₯ + 4 π₯+4 3π₯ + 4 =3 π₯+4 Now let’s do it again using the same fraction but different form → 3π₯ + 4 π₯+4 = 3π₯ 4 + π₯+4 π₯+4 It is the same fraction, but we cannot cancel them out? So how come we did in first solution? 3π₯ 4 + ≠3 π₯+4 π₯+4 This implies that in fractions, addition and subtraction not inside parenthesis [for example (x+5)] cannot be crossed out or cancelled. 2π₯(π¦ + π§) π₯(π¦ − π§) We can cancel out here 2π₯(π¦ + π§) 2(π¦ + π§) = (π¦ − π§) π₯(π¦ − π§) Because: (π¦ + π§) 2π₯(π¦ + π§) 2π₯ = ∗ (π¦ − π§) π₯(π¦ − π§) π₯ πΏππππππ π‘π 2(π¦ + π§) (π¦ − π§) π‘βππππππ 2π₯(π¦ + π§) π₯(π¦ − π§) πππ ππ πππππππππ ππ’π‘ However, don’t forget that if this equation becomes the following You cannot cancel out x here. With the same reasoning above 2π₯(π¦ + π§) 2 ≠ π₯(π¦ + π§) + 1 1 But you can cross out in this equation 2π₯(π¦ + π§) π₯(π¦ + π§) Notice how inside the parenthesis are the same in fraction? You can cancel them out 2π₯(π¦ + π§) 2π₯ = =2 π₯(π¦ + π§) π₯ F ACTORIZING Let’s take this equation as an example, what’s the first step? π₯ 2 − 5π₯ = 6π₯ 1) We bring all terms to the left side to make the right side equal 0 π₯ 2 − 5π₯ = 6 π₯ 2 − 5π₯ − 6 = 0 What about this? π₯ 2 − 2π₯ − 5 = 10 As stated above in step 1. Avoid putting terms to different side which will make you prone to more silly mistakes This is a longer and more thoughtless way to solve it: π₯ 2 − 2π₯ − 5 = 10 π₯ 2 − 2π₯ = 10 + 5 π₯ 2 − 2π₯ = 15 How would you solve this one? π₯2 = π₯ This is a guaranteed way to lose your marks. π₯2 π₯ = π₯ π₯ π₯2 π₯ π₯2 = = π₯ π₯ π₯ πβππ ππ π€ππππ Most of students make mistakes in those questions when it’s easier compared to other questions. To solve this equation properly, as stated in step 1 previously. Move all same terms to one side π₯2 = π₯ π₯2 − π₯ = 0 Great, now we can factorize π₯2 − π₯ = 0 π₯(π₯ − 1) = 0 π₯ = 0 ππ π₯ = 1 Common basic arithmetic mistake given this fraction and calculating it using a calculator 6 5π Input in calculator: 6 ÷ 5π is wrong. Following ‘BODMAS’. The 6 divided by 5 will be computed first. Correct input into the Calculator is 6 (5π) We can say the same thing for π₯ 2 = π¦ Put -17 for x. but instead put (−17)2 so the calculator computes -17 squared with the sign.