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Common Math Mistakes in Algebra

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Common Student’s Mistakes in Mathematics
I NDICES
This tells your teacher that you are bad at math.
(π‘₯ + 5)2 𝐼𝑆 𝑁𝑂𝑇 π‘₯ 2 + 25
Proof:
(π‘₯ + 5)2 = (π‘₯ + 5)(π‘₯ + 5)
= (π‘₯ + 5)(π‘₯ + 5)
= π‘₯ 2 + 10π‘₯ + 25
Another example:
(π‘₯ + 𝑦)2 = π‘₯ 2 + 𝑦 2
Proof:
= (π‘₯ + 𝑦)(π‘₯ + 𝑦)
= π‘₯ 2 + 2π‘₯𝑦 + 𝑦 2
π‘₯ 2 + 2π‘₯𝑦 + 𝑦 2 𝐼𝑆 𝑁𝑂𝑇 π‘₯ 2 + 𝑦 2
You can multiply them here, because inside the parenthesis the variables are
multiplied by each other
(π‘₯ 2 𝑦 3 )2 = π‘₯ 4 𝑦 6
Proof:
(π‘₯ 2 𝑦 3 )2 = (π‘₯ 2 𝑦 3 )(π‘₯ 2 𝑦 3 )
= π‘₯2 ∗ π‘₯2 ∗ 𝑦3 ∗ 𝑦3
= π‘₯ 2+2 𝑦 3+3
Therefor:
= π‘₯ 4𝑦6
The same thing applies to square roots,
2
√π‘₯ 2 + 𝑦 2 = π‘₯ + 𝑦?
2
π‘œπ‘Ÿ √π‘₯ 2 + 25 = π‘₯ + 5?
You cannot simplify those equations
2
π‘‘π‘Žπ‘˜π‘’ √32 + 32
2
= √9 + 9
2
= √18
≈ 4.24
2
π‘›π‘œπ‘€ π‘‘π‘Ÿπ‘¦ √32 + 32
2
= √3 2 + 3 2
=3+3
=6
4.24 ≠ 6
2
√3 2 + 3 2 ≠ 3 + 3
What about this?
2
2
2
√π‘₯ + 𝑦 ≠ √ π‘₯ + √𝑦
Try to prove it by changing [x, y] to integers.
2
√3 + 6
2
= √9
=3
2
2
√3 + √6
= 1.73 + 2.45 = 4.18
3 ≠ 4.18
2
2
√3 + 6 ≠ √3 + √6
2
F RACTIONS
Fractions is where most students don’t really understand. or worse invent
new mathematics
2
3
3
4
𝑖𝑠 𝑖𝑑
2 3
3
÷
π‘œπ‘Ÿ 2 ÷ 3 ÷ π‘œπ‘Ÿ … ?
3 4
4
First of all, look at the biggest fraction sign
2
3
3
4
=
2 3
÷
3 4
Now if you don’ remember elementary math, to divide two fractions. Flip the
sign to multiplication (*) then flip the 2nd fraction. Finally, multiply.
2 3
÷
3 4
2 4
= ∗
3 3
8
=
9
You can make sure by inputting the operation into calculator like this
2 ÷ 3 = 0. 6Μ‡
3 ÷ 4 = 0.75
0. 6Μ‡ ÷ 0.75 = 0. 8Μ‡
8 ÷ 9 = 0. 8Μ‡
Therefor
2
3
3
4
=
2 3
÷
3 4
Try the other form of fractions and see the answer, it’ll be different thus
implying which is the correct one.
Canceling in fractions, could you cross out any number/variable in this
equation? Well, let’s try
3π‘₯ + 4
π‘₯+4
3π‘₯ + 4
=3
π‘₯+4
Now let’s do it again using the same fraction but different form
→
3π‘₯ + 4
π‘₯+4
=
3π‘₯
4
+
π‘₯+4 π‘₯+4
It is the same fraction, but we cannot cancel them out? So how come we did
in first solution?
3π‘₯
4
+
≠3
π‘₯+4 π‘₯+4
This implies that in fractions, addition and subtraction not inside
parenthesis [for example (x+5)] cannot be crossed out or cancelled.
2π‘₯(𝑦 + 𝑧)
π‘₯(𝑦 − 𝑧)
We can cancel out here
2π‘₯(𝑦 + 𝑧) 2(𝑦 + 𝑧)
=
(𝑦 − 𝑧)
π‘₯(𝑦 − 𝑧)
Because:
(𝑦 + 𝑧)
2π‘₯(𝑦 + 𝑧)
2π‘₯
=
∗
(𝑦 − 𝑧)
π‘₯(𝑦 − 𝑧)
π‘₯
πΏπ‘’π‘Žπ‘‘π‘–π‘›π‘” π‘‘π‘œ
2(𝑦 + 𝑧)
(𝑦 − 𝑧)
π‘‘β„Žπ‘’π‘Ÿπ‘’π‘“π‘œπ‘Ÿ
2π‘₯(𝑦 + 𝑧)
π‘₯(𝑦 − 𝑧)
π‘π‘Žπ‘› 𝑏𝑒 π‘π‘Žπ‘›π‘π‘’π‘™π‘™π‘’π‘‘ π‘œπ‘’π‘‘
However, don’t forget that if this equation becomes the following
You cannot cancel out x here. With the same reasoning above
2π‘₯(𝑦 + 𝑧)
2
≠
π‘₯(𝑦 + 𝑧) + 1
1
But you can cross out in this equation
2π‘₯(𝑦 + 𝑧)
π‘₯(𝑦 + 𝑧)
Notice how inside the parenthesis are the same in fraction? You can cancel
them out
2π‘₯(𝑦 + 𝑧) 2π‘₯
=
=2
π‘₯(𝑦 + 𝑧)
π‘₯
F ACTORIZING
Let’s take this equation as an example, what’s the first step?
π‘₯ 2 − 5π‘₯ = 6π‘₯
1) We bring all terms to the left side to make the right side equal 0
π‘₯ 2 − 5π‘₯ = 6
π‘₯ 2 − 5π‘₯ − 6 = 0
What about this?
π‘₯ 2 − 2π‘₯ − 5 = 10
As stated above in step 1. Avoid putting terms to different side which will
make you prone to more silly mistakes
This is a longer and more thoughtless way to solve it:
π‘₯ 2 − 2π‘₯ − 5 = 10
π‘₯ 2 − 2π‘₯ = 10 + 5
π‘₯ 2 − 2π‘₯ = 15
How would you solve this one?
π‘₯2 = π‘₯
This is a guaranteed way to lose your marks.
π‘₯2 π‘₯
=
π‘₯
π‘₯
π‘₯2 π‘₯
π‘₯2
=
=
π‘₯
π‘₯
π‘₯
π‘‡β„Žπ‘–π‘  𝑖𝑠 π‘€π‘Ÿπ‘œπ‘›π‘”
Most of students make mistakes in those questions when it’s easier compared
to other questions. To solve this equation properly, as stated in step 1
previously. Move all same terms to one side
π‘₯2 = π‘₯
π‘₯2 − π‘₯ = 0
Great, now we can factorize
π‘₯2 − π‘₯ = 0
π‘₯(π‘₯ − 1) = 0
π‘₯ = 0 π‘œπ‘Ÿ π‘₯ = 1
Common basic arithmetic mistake given this fraction and calculating it using a
calculator
6
5πœ‹
Input in calculator: 6 ÷ 5πœ‹ is wrong. Following ‘BODMAS’. The 6 divided by 5 will
be computed first.
Correct input into the Calculator is
6
(5πœ‹)
We can say the same thing for π‘₯ 2 = 𝑦
Put -17 for x. but instead put (−17)2 so the calculator computes -17 squared with
the sign.
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