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motion-graphs-practice-solutions

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Drawing Motion Graphs = Level 1 =
Convert the following Displacement vs. Time graphs into Velocity vs. Time graphs
d
v
7
6
7
6
5
5
5
4
3
2
1
0
4
3
2
1
0
4
3
2
1
0
0 1
2
3 4
5 6 7
0 m/s
0 1
2
3 4
5 6 7
7
6
7
6
0 m/s
0 1
2
3 4
5 6 7
5
4
3
2
1
0
0 m/s
0 1
4
3
4
3
4
3
4
3
2
2
2
2
1
0
-1
-2
-3
1
0
-1
-2
-3
1
0
-1
-2
-3
1
0
-1
-2
-3
0 1
2
3 4
5 6 7
0 1
2
3 4
5 6 7
0 1
2
3 4
5 6 7
0 1
2
3 4
5 6 7
2
3 4
5 6 7
Drawing Motion Graphs = Level 2 =
Convert the following Velocity vs. Time graphs into Displacement vs. Time graphs
d
v
0 m/s
7
6
7
6
5
5
5
5
4
3
2
1
0
4
3
2
1
0 m/s
0
0 1 2 3 4
4
3
2
1
0
4
3
2
1
0
0 1
2
3 4
5 6 7
0 m/s
5 6 7
7
6
0 1
2
3 4
7
6
5 6 7
0 m/s
0 1
4
3
4
3
4
3
4
3
2
2
2
2
1
0
-1
-2
-3
1
0
-1
-2
-3
1
0
-1
-2
-3
1
0
-1
-2
-3
0 1
2
3 4
5 6 7
0 1
2
3 4
5 6 7
0 1
2
3 4
5 6 7
0 1
2
3 4
5 6 7
2
3 4
5 6 7
Drawing Motion Graphs = Level 3 =
Convert the following Displacement vs. Time graphs into Velocity vs. Time graphs
d
v
7
6
7
6
7
6
5
5
5
5
4
3
2
0 m/s
1
0
0 1 2 3 4
4
3
2
1
0
4
3
2
1
0
4
3
2
1
0
5 6 7
4
3
4
3
2
2
1
0
-1
-2
-3
1
0
-1
-2
-3
0 1
2
3 4
5 6 7
0 1
2
3 4
5 6 7
Changes
Direction
0 1
2
3 4
5 6 7
0 m/s
0 1
2
3 4
5 6 7
7
6
0 1
4
3
4
3
2
2
1
0
-1
-2
-3
1
0
-1
-2
-3
0 1
2
3 4
5 6 7
2
5 6 7
3 4
Changes
Direction
0 1
2
3 4
5 6 7
Velocity (m/s)
4
3
1
0
-1
-2
-3
2
4
2
Acceleration = slope = 0.5 m/s2 (or 0.5 m/s/s)
What the total displacement represented in this graph?
0 1
2
3 4
5 6 7
Velocity (m/s)
Time (s)
Displacement = area = (½)(4)(2)+(1)(2) = 6 m
What is the acceleration between 2-5 seconds?
4
3
2
2
1
0
-1
-2
-3
What is the acceleration between 2-5 seconds?
-2
0 1
2
Acceleration = slope = 0 m/s2 (or 0 m/s/s)
What the total displacement represented in this graph?
3 4
5 6 7
Time (s)
Displacement = area = (½)(2)(-2) + (½)(2)(2)
=0m
Velocity (m/s)
During which interval is it moving in the negative direction?
4
3
2
1
0
-1
-2
-3
-4
-1
0 1
2
3 4
Velocity is negative from 4 s to 7 s
What the total displacement represented in this graph?
5 6 7
Time (s)
Displacement = area = (½)(1)(-2) + (2)(-2)
Velocity (m/s)
= -5 m
What is the significance of the point at 6 seconds?
4
3
1
0
-1
-2
-3
4
2
2
-1
0 1
2
3 4
This is when the object changes direction
What the total displacement represented in this graph?
5 6 7
Time (s)
Displacement = area
= (½)(1)(4) + (½)(2)(4) + (½)(1)(-2) = 5 m
Velocity (m/s)
Describe the motion between 0-6 seconds
4
3
1
1
2
1
0
-1
-2
-3
-4
0 1
2
3 4
Moving backward (negative velocity) from 0-4 s
Moving forward (positive velocity) from 4-6 s
What the total displacement represented in this graph?
5 6 7
Time (s)
Displacement = area
Velocity (m/s)
= (½)(4)(-2) + (½)(2)(1) + (1)(1) = -2 m
Describe the motion between 0-6 seconds
4
3
4.5
2
1
0
-1
-2
-3
-1
-4.5
0 1
2
3 4
5 6
Time (s)
-1
7
Moving forward (positive velocity) from 0-3 s
Moving backward (negative velocity) from 4-6 s
What the total displacement represented in this graph?
Displacement = area
= (½)(3)(3) + (½)(3)(-3) + (1)(1) + (½)(1)(-2) = -2 m
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