- Mark Scheme
Question
1(a)
Answer
(∆) p=mv in any form OR
((∆)p=) mv OR
0.8 × 0.72 (1)
Marks
AO Element
/
Notes
2
(∆p= ) 0.58 kg m/s (1)
1(b)
Ft= ∆p in any form OR
(F=) ∆p/t OR
0.58/6 (1)
2
accept rounding if
0.096 seen
(F=) 0.096 N (1)
2(a)
( p =) mv OR 0.046 × 65 (1)
2
3.0 kg m / s OR 3.0 N s (1)
2(b)
a = (v – u) / t
(F =)
AND F = ma
m(v–u) /t
or 0.046 × 65 /
OR
or 3.0 /
0.00050 or
0.00050
0.046 ×
130 000
(1)
2
6000 N (1)
3(a)
(impulse =) Ft in any form (1)
(impulse =) 2.4 N s (1)
2
Guidance
- Mark Scheme
Question
3(b)
Answer
Ft = mv − mu in any form OR
(v − u =) Ft / m (1)
Marks
AO Element
/
Notes
Guidance
2
43 m / s (1)
4(a)(i)
(p =) 3.2 x 4.0
2
13 kg m / s
4(a)(ii)
momentum conserved
3
12.8 − (3.2 x 1.5) OR
12.8 − 4.8 OR
8.0 OR
8.0 ÷ 1.6
5.0 m / s
4(b)
(F =)
OR
2
8.0 ÷ 0.050
160 N
4(c)
internal energy (of blocks)
increase OR
thermal energy/sound energy
(lost/produced at collision)
1
[Total: 20]