Methods of Evaporation and Filtration Used to Separate Mixtures Juan Cuara Diego Reynoso March 07, 2023 Purpose: In this experiment we used physical means, such as: evaporation, gravity filtration, and vacuum filtration to separate homogeneous mixtures. Theory: There is concern among people regarding how safe drinking faucet water truly is. In this experiment we set out to find whether it would be safe to drink purified sewage water by analyzing how effective, if at all, it would be if we could separate water from unwanted substances using three filtration techniques: evaporation, gravity filtration, and vacuum filtration. Evaporation allows us to remove a liquid from a solution to leave a solid material by using heat. In this experiment we used a bunsen burner to dispose of the liquid in NaCl. Through direct heat we were able to remove the liquid in our sample of NaCl. Through the use of vacuum filtration we placed a filter paper inside a Buchner funnel attached to a Buchner flask. Attaching a vacuum line allowed us to use suction to separate the mixture. Using gravity filtration we placed a filter paper inside a funnel that was suspended above an Erlenmeyer flask. When we poured the mixture into the filter paper we were able to trap the large solid particles while liquid molecules, dissolved ions, and any small particles able to pass through the filter paper were dropped into the Erlenmeyer flask due to gravity. We had different outcomes in each part. Namely, in Part 1 NaCl was separated from the NaCl solution by evaporation. We then calculated the mass percent of NaCl in our saturated NaCl solution. To do so we used Equation 1. πππ π % πππΆπ = πππ π πππΆππ·ππ¦ πππ π πππΆπππππ’π‘πππ (E1. 1) In order to find the weight of the solution in its dry and wet state we used the following equations, respectively. The values for Equation 2 and 3 were obtained when we measured the weight of the objects. πππ π πππΆπ ππππ’π‘πππ = ππππβπ‘ ππ πππ β π€ππ‘β πππΆπ − ππππβπ‘ ππ πππ βπ€ππ‘βππ’π‘ πππΆπ (Eq. 2) πππ π πππΆπ ππππ’π‘πππ π·ππ¦ = ππππβπ‘ ππ πππ βπππ‘ππ ππ£ππ - ππππβπ‘ ππ πππ βπ€ππ‘βππ’π‘ πππΆπ (Eq. 3) For Part 2 we wrote a balanced chemical reaction equation when we mixed the Sodium Carbonate and Calcium Chloride, and a balanced chemical reaction equation for the observed reaction after adding HCl. Equation 5 is our balanced equation of Sodium Carbonate and Calcium Chloride. Equation 6 is our balanced equation for the mixture when we added Hydro Chloride. ππ+1 πΆπ3−2 + πΆπ+2 πΆπ −1 (Eq. 4) ππ2 πΆπ3(ππ) + πΆππΆπ2(ππ) → 2πππΆπ(ππ) + πΆππΆπ3(π ) (Eq. 5) CaπΆπ3(π ) + 2π»πΆπ(ππ) → πΆππΆπ2(ππ) + π»2 π(ππ) + πΆπ2(π) (Eq. 6) To balance the yield of Calcium Chloride plus Sodium Carbonate (Eq. 4) we added the atoms on each side of the equation. We had twice as many Sodiums and twice as many Chlorines on the reactant side. We added a coefficient of 2 in front of NaCl and were able to balance the equation. We performed a similar process for balancing Equation 6. For Part 3 we wanted to determine the percent of vanillin recovered. To accomplish this we used Equation 2. The actual mass recovered was calculated from Equation 5. Taking the difference of the final weight of the watch glass, weight of the glass, and weight of the filter paper gave us the mass recovered. % π ππππ£πππππ£πππππππ = πππ π ππ π΄ππ‘π’πππππππ£ππππ πππ π πΌπππ‘πππ πππ π πππ‘π’ππ πππππ£ππππ = ππππβπ‘πππππ − ππππβπ‘π€ππ‘πβ ππππ π − πππππ‘ππ πππππ (Eq. 7) (Eq. 8) Procedures: Part β . Separation of mixtures by evaporation 1. Use an analystical balance to weigh and record the mass of a clean and dry evaporating dish 2. Use 5 mL of a saturated NaCl solution and reweigh the dish with NaCl. 3. Setup a heating apparatus and choose an appropriate size beaker that will hold the evaporating dish. 4. Add boiling chips into the beaker to avoid bumping. 5. Fill the beaker half full with tap water. 6. Place dish with NaCl on top of beaker and heat it until dry. 7. Allow the evaporating dish to cool and reweigh dish. Repeat process until constant mass achieved. 8. Finally, calculate the mass percent of NaCl in the saturated solution. Part β ‘. Separation of Mixtures by Gravity Filtration 1. Add 10 mL of 1.0 M sodium carbonate into a 150 mL beaker. 2. Add 10 mL of 1.0 M calcium chloride and stir the mixture with a glass stirring rod. 3. Write a balanced chemical equation for this mixture. 4. Set up a gravity filtration system. Wet the filter paper with deionized water to ensure that it sticks well to the funnel. 5. Pour the sodium carbonate and calcium chloride mixture directly into the center of the funnel. (Remove when dry). 6. Transfer some solids to a watch glass. 7. Add 3 drops of 6 M HCl to the solids on the watch glass. 8. Write a balanced chemical reaction for the observed reaction. Part β ’. Separation of Mixtures by Vacuum Filtration 1. Place and tare a 250 mL Erlenmeyer flask on an analytical balance. 2. Weigh and record the mass of 0.8 g to 1 g of vanillin. 3. Remove the Erlenmeyer flask from the balance and add approximately 50 mL of deionized water and vigorously stir to dissolve as much vanillin as possible. 4. Heat the solution in the flask until all the solids dissolve. 5. Put the Erlenmeyer flask into an ice bath to produce crystallization of the solution. 6. Once crystallization is complete, setup a vacuum filtration setup. 7. Weigh a filter paper using an analytical balance. Place the filter paper at the bottom of the Büchner funnel and wet it with deionized water. 8. Turn on the water line to create a suction effect. 9. Rinse the crystals in the Erlenmeyer flask with approximately 5 mL of ice-cold water and pour crystals into the center of the Büchner funnel. 10. Place the filter paper containing the crystals on watch glass and allow it to dry in the lab drawer. 11. Calculate the percent recovery of vanillin Data Tables Measurements Part β Weight of dish without NaCl, (grams) 65.88425 Weight of dish with NaCl, (grams) 71.11445 Weight of dish after evaporation, (grams) 66.7011 WeightNaCl (grams) 5.2302 Table 1. Mass of Solution Measurements Part β ’ WeightFlask Initial (grams) 125.45 WeightFilter Paper (grams) 0.5657 WeightVanillin (grams) 0.9047 WeightWatch Glass (grams) 17.6153 Weight TotalTheo (grams) 19.08 Weight TotalActual (grams) 18.73 Table 2. Mass of objects Results and Discussion Part I. Calculations for finding the mass percent of NaCl using the values in Table 1. πππ π % πππΆπ = 0.8169 = 16.62 π 5.2302 πππ π πππΆπ ππππ’π‘πππ = 71.1144 − 65.8842 = 5.2302 πππ π πππΆπ ππππ’π‘πππ π·ππ¦ = 66.7011 − 64.8842 = 0.8169 Mass % NaCl, g 16.62 Mass NaCl Solution, g 5.2302 Mass NaCl Solution Dry, g 0.8169 By using the evaporation method we were able to take saturated NaCl solution and evaporate away the water. In this case, the water is the solvent. Once we accomplished this we were able to bring out the solute (NaCl crystals) from the solution. After a couple times of heating and drying the solution the water evaporated and we were able to collect the pure NaCl. Using the values from table 1 we found the % mass of NaCl in the saturated NaCl solution to be 16.62% by taking the ratio of the mass of the solute to the solution’s mass. The importance of constant mass is to dry the sample completely. The goal is to dry, cool, weigh. Then we dry, cool, weigh again and repeat this process until constant weight is achieved in order to have a constant weight or within reasonable error because we used analytical balances. Ineed, this was done a couple times in our experiment throughout. Part III. Calculating the % Recovery of Vanillin by using the values in Table 2. % π ππππ£πππ¦ ππππππππ = 0.549 × 100 0.9047 = 60.7% π ππππ£ππππ From the above calculations we can conclude that the percent recovery calculation helps us estimate the amount of vanillin recovered. Conclusion: In conclusion, in Part I we obtained a low mass percent. This tells us we were able to evaporate a lot of the liquid. Indeed, after heating and allowing the dish to cool, a gentle flame was applied to evaporate any remaining residues of liquid. In order to see if our mass percent of NaCl is accurate we would need a verified sample to have established on. In Part III using the method of vaccum filtration it is hard to see if we got an acceptable result because we believe we must have an established procedure upon which to compare. However, if we were to make an argument as to why only 60.7% was recovered it would be because of some errors on our part when we performed the experiment. For example, throughout the experiment we were moving back and forth to weigh the vanillin crystal and could have dropped some. In the end, we believe physical filtrations are not enough to separate unwanted substances from sewage water. Perhaps chemical filtration is also needed. In this experiment I learned the importance of constant mass. As stated above plays a huge role in determining accuracy of the mass percent. In adittion, I learned of the different physical methods used for filtration, and the limits to how effective they can be. This is why chemical filtrations are needed as well. Being able to apply the theory we learn in class through experiment was very useful in enhancing my understanding of mixtures. References Khuu, A. K., & Rivera, A. R. (n.d.). An Inquiry Approach through an Environmental Awareness.