Aim: Determination of iron by salicylic acid method.
Requirements: Fe(III) solution, 0.005M Salicylic acid etc.
Optical density
Graph:
V
Volume of salicylic acid in ml
Calculation:
10 mL of diluted Fe (III) solution = --V---ml of salicylic acid solution.
Therefore 250 ml of diluted Fe(III) solution = 25 * --V--ml of salicylic acid solution.
3 Salicylic acid = 1Fe
1 salicylic acid ==1/3 Fe
1000ml of 1M salicylic acid solution =55.83 g of Fe+3
3
=18.62 g of Fe
:. 25 * V ml of 0.005M Salicylic acid =X gms
x = 25* V* 0.005 *18.62
1000
= …………………g = ………..mg =………….μg
Result:
1) 10 ml of diluted Fe(III) solution required Vx= ….ml of 0.005M
salicylic acid.
2) Amount of Fe(III) present in the given solution is …………. μg