3 MATHEMATICAL PRELIMINARIES 3.1 Vector Representation Orthogonal set of base vectors e1, e2 , e3 vector x = x1e1 + x2e2 + x3e3 3 x = xi ei i =1 3.2 Indicial/Tensor Notation ➢ Summation convention • Repeated indices indicate summation x = xi e i through 1, 2, 3 u = ui e i i = 1,2,3 ➢ Indices can only appear twice per term 3.2.1 Define Kronecker Delta 0 ei e j = ij = 1 3.2.2 1 0 0 i j I = 0 1 0 i= j 0 0 1 Dot Product Between Two Vectors ab = a = a1e1 + a2e 2 + a3e 3 = ai ei b = b1e1 + b2e 2 + b3e 3 = bi ei 1 a b = ( ai ei ) ( b j e j ) = ai b j ( ei e j ) = ai b j ij = a1b111 + a1b212 + a1b313 __ i, j = 1,2,3 + a 2b121 + a2b222 + a2b323 + a3b13 + a3b232 + a3b333 = ai bi = bi ai 3.2.3 Simplified Representation We can drop the base vectors for vector representation: ai a1 a = a2 , bi a 3 b1 b = b2 , cij b 3 a b = a b = a1 a2 bT ca = b1 b2 c13 c23 , dij d c33 b1 a3 b2 = aibi = a1b1 + a2b2 + a3b3 b 3 T c11 c12 b = ca = c21 c22 c31 c32 c11 c12 c = c21 c22 c31 c32 c13 a1 c23 a2 = cij a j = bi c33 a3 = a j cij = bi all equivalent = ck a = bk c11 c12 b3 c21 c22 c31 c32 c13 a1 c23 a2 bi cij a j c33 a3 The order of the terms in the indicial notation representation is irrelevant. 3.2.4 Matrix Multiplication Some common operations: cd cij d jk cT d cij dik cdT cij d kj summation on middle summation on first summation on last 2 3.3 Transformation of Vector and Tensor Coordinate Reference Frame v = vi e i v = vj ej v j e j = viei v j e j = viei dot with ek v j ( e j ek ) = vi ( ei ek ) ( e e ) v k j j = viik akj v j = vk vk = akj v j akj = ek e j v = av , a is direction cosines Similarly, v j e j = viei dot with e k v j ( e j e k ) = vi ( ei e k ) vk = viaik vk = aik vi , aik = ei e k v = aT v / v = aT v v = av v = aT av only true if aT a=I Thus, aT = a−1 and a is orthonormal. 3 An Inplane Example: vi = aij v j v = av a = ei e j a11 = e1 e1 = e1 e1 cos = cos a12 = e1 e 2 = cos − = sin 2 a21 = − sin a22 = cos a13 = 0 cos sin 0 a = − sin cos 0 0 1 0 a23 = 0 a33 = 1 a31 = 0 a32 = 0 v1 v1 v2 = a v2 v v3 3 3.4 Transformation of Matrix/Higher-Order Tensors Tensor: A mathematical representation of a physical quantity. They have components that transform from one coordinate system to another according to “transformation equations” (rules), e.g., v = av vector v is a first-order tensor u = au vector u is a first-order tensor 4 u1 w = uv = u2 v1 v2 u 3 T v3 = ui v j = wij Matrix w is a second-order tensor because it is the product of two first-order tensors. w = uvT , u = au , v = av , vT = v T aT w = uvT = a uvT aT w = awaT rule for transformation of a second-order tensor wij = air a js wrs Similarly, w = aT wa wij = ari asj wrs where aij = ei e j For example, stress is a second-order tensor: ij = air a js rs , s = as aT Later we’ll see the fourth-order tensor, Cijk , a generalized Hookean stiffness tensor = air a js akt a uCrstu Cijk Four dimensions—can no longer be written in vector format. 5 3.5 Stress Matrix/tensor representation xx xy s = yx yy zx zy x 1 xz yz = ij , i = 1, 2,3 zz y2 12 = 12 z3 23 = 23 31 = 31 Equilibrium of moments and forces: xy = yx yz = zy zx = xz Six independent stresses in compact notation: 11 1 22 2 s = i = 33 = 3 23 4 31 5 12 6 6 3.5.1 Transformation of Coordinate Reference Frame for Stress ➢ For laminates, we are usually concerned with rotations in the x,y plane cos sin 0 aij = ei e j = − sin cos 0 0 1 0 c s 0 11 12 13 c − s 0 s = as a = − s c 0 12 22 23 s c 0 0 0 1 13 23 33 0 0 1 T Expand and put in compact form: 1 c 2 s 2 2 c2 2 s 0 3 0 = 0 4 0 5 0 0 6 − sc sc s = Ts 0 0 1 0 0 0 0 0 sin 2 0 0 − sin 2 0 0 0 c −s 0 s c 0 2 0 0 c − s2 1 2 3 4 5 6 s = T −1s 3.5.2 Simplify 3D Transformation for 2D Transformation 1 11 2 22 1 11 xx 3 33 2D = 2 = 22 = yy 4 23 5 31 6 12 xy 6 12 c2 s2 2 c2 s 0 0 T= 0 0 0 0 − sc sc 0 0 1 0 0 0 0 0 sin 2 0 0 − sin 2 0 0 0 c −s 0 s c 0 0 0 c 2 − s 2 7 T for 2D plane stress or plane strain s = Ts c 2 s 2 sin 2 11 11 2 c 2 − sin 2 22 22 = s − cs sc c 2 − s 2 12 12 = c211 + s 222 + sin 212 11 1 (1 − cos 2 ) 22 2 1 11 cos2 = (1 + cos 2 ) 11 2 22 sin 2 = For Mohr’s Circle, from your “strength of materials” class: = 11 11 + 22 11 − 22 + cos 2 + 12 sin 2 2 2 22 = 11 + 22 11 − 22 − cos 2 − 12 sin 2 2 2 − 22 = − 11 12 sin 2 + 12 cos 2 2 3.6 Strain Displacement Field u = ui e i u = u1 = u1 ( x, y , z ) v = u2 = u2 ( x, y , z ) w = u3 = u3 ( x, y , z ) From strength of materials, normal strains xx = u x 8 yy = v y zz = w z Engineering shear strain: xy = u v + y x yz = v w + z y zx = w u + x z xy = dv du + dx dy Mathematical/tensorial shear strain: ij = 1 ui u j + 2 x j xi xy = 1 u v + 2 y x yz = 1 v w + 2 z y zx = 1 w u + 2 x z so 12 = 212 23 = 223 31 = 231 9 Strain tensor: 11 12 ij = 22 sym 13 11 12 2 13 2 23 = 22 23 2 33 33 but, in compact form, 1 xx xx 2 yy yy zz zz i = 3 = = 4 2 yz yz 5 2 zx zx 6 2 xy xy 3.6.1 Coordinate Transformation of a Second-Order Strain Tensor Rules for transformation only apply to tensorial strain, NOT engineering strain, i.e., 11 12 13 e = 12 22 23 13 23 33 (tensorial strain matrix) From the rules for transformation, e = aeaT or ij = air a js rs where aij = ei e j For a rotation about x3 of , one needs to expand this relation for all 6 components and put into compact form, being very careful of the factors of 2! Multiplying out e = aeaT , where we have substituted the engineering shear strains for the tensorial shear strains, as shown by 10 12 13 c s 0 11 12 / 2 13 / 2 c − s 0 11 22 23 = − s c 0 12 / 2 22 e = 12 23 / 2 s c 0 23 33 0 0 1 13 / 2 23 / 2 33 0 0 1 13 yields 6 equations for the tensorial shear strains in the primed coordinate system = 11 cos2 ( ) + 22 sin 2 ( ) + 12 cos ( ) sin ( ) 11 22 = 11 sin 2 ( ) + 22 cos2 ( ) − 12 cos ( ) sin ( ) 33 = 33 = −11 cos ( ) sin ( ) + 22 cos ( ) sin ( ) + 12 12 cos ( 2 ) 12 = 13 1 2 23 = 1 2 ( ( 13 cos ( ) + 23 sin ( ) ) 23 cos ( ) − 13 sin ( ) ) However, we know that = 212 12 23 = 223 31 = 231 and with further simplifying this yields = −11 sin ( 2 ) + 22 sin ( 2 ) + 12 ( cos 2 ( ) − sin 2 ( ) ) 12 = 13 cos ( ) + 23 sin ( ) 13 23 = 23 cos ( ) − 13 sin ( ) Taking those 6 equations and rewriting them results in the following matrix system c2 s2 1 11 2 c2 2 22 s 0 3 33 0 = = 0 4 223 0 5 231 0 0 − sin 2 sin 2 6 212 0 0 1 0 0 0 0 0 sc 1 0 0 − sc 2 0 0 0 3 c −s 0 4 s c 0 5 0 0 c 2 − s 2 6 which can be expressed as e = ( T −1 ) e T 11 Inverting that system results in e = TT e Again, this representation could be simplified for two-dimensions similar to Mohr’s circle for strains. 12 1