4.9 −0.3 2.7 7.2 ο§ 2.5 0.1 − −5.1 0.4 = −3.8 1.7 4.4 0 ο§ -4 −7 2 = 2 −9 ο§π΄= ο§3 5 9 3 −6 9 −5 π΅= −3 3 9 −5 −1 4 5 −3 −4 − = 2 −3 0 4 3 π΅−π΄= ο§New lesson: notes about the equations ο§Practice ο§Homework ο§Missing assignments Ms. Cardenas ο§ Solving equation is the process of rewriting the equation to make what is says about its variable(s) as simple as possible. ο§ SWBAT solve one and two step equations. ο§ SWBAT solve multi-step equations. ο§ SWBAT solve equations with variables on both sides. ο§ SWBAT solve literal equations and formulas. ο§ Equation: is made up of two expressions connected by an equal sign. Example ο 2π₯ + 5 = 7 6x − 2 = 3x + 9y − 4 ο§ Algebraic expression: mathematical phrase that includes 1 or more variables. Example ο 2π₯ + 5 ο§ Numerical expression: mathematical phrase including numbers and operations symbols but no variables. Example ο 5 + 75 − 23 STEPS: 1. Isolate the variable on one side of the equation. 2. Use the inverse operations (addition/subtraction, multiplication/division). 3. Whatever we do on one side, we must do it on the other side. π₯ + 5 = 11 π₯ − 4 = 14 w = 11 5 π − 7 = 20 13 = 9 + π −15 = −7 + π 4π₯ = −32 −3π₯ = 21 2π₯ + 6 = 24 5 − 3π₯ = 35 4π₯ =8 9 24 = 6 − 6π₯ π₯ + 9 = 14 6 π 18 = − 2 3 ο§ Solving multi-step equations and variables on both sides TODAY’S ACTIVITIES ο§ Practice ο§ Solve proportions (grade book) ο§ Math XL assignment: A1.Multi-step equations (grade book) π₯ − 10 = 7 π¦ + 8 = −16 10w = −6 2 π₯ 16 = +8 −4 STEPS: 1. Remove the parentheses using the distributive property. 2. Combine the variables. 3. Isolate the variable (to keep it positive). 4. When working with fractions, cross multiply or use the butterfly method. 5. Use the inverse operations. 84 = −7(π₯ − 4) 3 2π₯ − 5 + 6 = 5π₯ + 12 135 = 5 −6π + 1 + 4π π₯ 2π₯ + 3 = 8 5 x 6 = 5 3 π₯ + 2 10 = 5 7 25 − 7π¦ = −4π¦ + 5(5 + 7π¦) −7 −2 + 2π₯ = −8π₯ − 34 −2π + 32 = 8 −3π − 5 − 2π −2π + 4π = −8(1 − 4π) 7 3π − 1 − 7π = −38 − 3π −8 π₯ − 4 = −4(π₯ − 6) ο§ MATH XL ο A1.Multi-step equations (grade book) TODAY’S ACTIVITIES ο§ New topic ο Solving equations “special cases” and rearranging formulas ο§ Math XL assignment ο A1.Special cases and rearranging formulas (grade book) ο§ We refer to special cases when the variables drop out (the variables cancel). ο§ Remove the parentheses if any, and follow the steps learned to solve the equations. ο§ If 0 = 0, the solution is true, and the solution is all real numbers. ο§ If −5 = 0, the solutions is untrue, and we said there is no solution. 0 = 2π₯ − 2π₯ −9 + 4π¦ = −(4 − 4π¦) −5π₯ = 8π₯ − 8π₯ −3π₯ + 2 = −3 1 + π₯ + 5 −π − 3 π + 6 = 11 − 4π −3 − 7 1 + 5π₯ = −7(5π₯ + 3) Steps: ο§ Focus on the specific variable you are solving for. ο§ Follow the same steps as solving linear equation. ο§ The answer will NOT have like terms so it will look “messy”. Solve for a: ππ₯ − π = π Solve for r: π΄ = 1 + ππ‘ Solve for P: π΄ = π(2 + ππ‘) Solve for x: π₯−π¦ π΄= π Solve for x: π₯β + π₯ = 10 Solve for x: π₯π + π₯π = 6 ο§ Math XL assignment ο A1.Special TODAY’S ACTIVITIES cases and rearranging formulas (grade book) ο§ New topic ο Problems using equations ο§ Solving equations REVIEW ο§ A truck can be rented from Company A for β$120 a day plus β$0.20 per mile. Company B charges β$80 a day plus β$0.70 per mile to rent the same truck. Find the number of miles in a day at which the rental costs for Company A and Company B are the same. ο§ Angie and Kenny play online video games. Angie buys 2 software packages and 4 months of game play. Kenny buys 1 software package and 1 month of game play. Each software package costs β$25. If their total cost is β$135β, what is the cost of one month of gameβ play? PROBLEM 2 DFA ο Tuesday 19th ο§ −7 3π₯ + 3 = −21π₯ + 21 ο§ −3 4π₯ + 4 = −12π₯ + 12 ο§ −4 −π − 24 = −4π − 24 ο§ −3 −π − 6 = −3π − 6 ο§ Solve for b π= π−π π¦ ο§ Solve for d π= π−π π€ ο§ Solve for r π 2 ο§ Solve for x π₯ 2 = π+7 4 = π₯+3 8 3 ο§ π₯ 4 − 7 = 10 2 ο§ π₯ 3 + 10 = 9 2 ο§− π₯ 5 +8=4 FIRST PART OF THE CLASS ο§REVIEW ο§ Solve the equation. Note if the equation is an identity or if it has no solution. −4 −π − 16 = −4π − 16 ο§ Solve forβ x: 5 − π₯ 2 − 20 = 20 ο§ Solve the formula for x. π= π₯−π π ο§ Solve for m. π 4 = π+14 8 SECOND PART OF THE CLASS ο§ Math XL ο DFA1. 2B Solve equations ο§ 30 minutes ο§ NO CELL PHONES!