SKKU-CS-009 기초자연과학영역(BSM) 공동시험문제 Basic Science and Mathematics Common Examination 학기 Semester 학과/계열 Dept./Division 과목명 Subject 수업정보 Class Time 유의사항 Note 2015 년 2 학기 일반물리학2 요일 Day 시간 Time 시험구분 Exam Type 중간 Mid Term 기말 Final 학번 Student PIN 학수번호 Course Code 수업담당교수 Instructor ☑ ☐ 시험시간 Exam Time 60 분/Minutes 성명 Name 분반 Section Number 감독자확인 Proctor’s Signature GEDB010 1. Electronic calculator is not allowed!! 2. Answer the questions in English or Korean. 1. [25 points] Properties of a metallic sphere: 2. [25 points] An electron is placed under a uniform magnetic (a) (10 pts) How does a piece of metal respond to an external field of 0.01 T pointing to the positive x-axis. The electron has electric field and why? Describe the answer in words. You do an initial velocity of 3×106 i + 4×106 j m/s and is initially not need to use equations. located at the origin. The mass and charge of the electron are 9×10-31 kg and –1.6×10-19 C, respectively. You are given a charge-neutral, metallic (a) (5 pts) Describe the motion of the electron. solid sphere of radius . Suddenly, by (b) (5 pts) Describe the motion of the electron when the magnetic magic, a charge (>0) appears at the field is reversed. center of the sphere. (c) (5 pts) Find the period of the electron motion. (b) (10 pts) Describe the response of the (d) (5 pts) What is the speed of the electron at = 10 s? metallic sphere to this sudden change. (e) (5 pts) If an additional electric field of 2.8125×10-6 V/m is Note that the positive charge ( ) applied pointing to the negative x-direction from the beginning, remains at the center all the time. what will be the speed of the electron at = 10 s? (c) (5 pts) After reaching a new Answers: equilibrium, make a rough sketch of the induced charge density (a)) (5 pts) A helical motion: Along the x-axis, it is a constant and the radial electric field as a function of the velocity motion. Within the yz-plane, it is a counterclockwise distance from the center of the sphere. circular motion. Answers: (b)) (5 pts) A helical motion: Along the x-axis, it is a constant (a) (10 pts) A metal responds to electric field by generating a velocity motion (no change). Within the yz-plane, it is now a current in the direction of the field according to Ohm’s law. The clockwise circular motion. current flow continues until the new charge distribution creates (c)) (5 pts) an electric field that precisely cancels the external field, for a net electric field of zero inside the metal in the new equilibrium. (b) (10 pts) The sudden appearance of charge +Q will generate a radial electric field of a single, isolated charge. Electric current (d)) will flow radially, resulting in the accumulation of positive net (e)) charge +Q at the surface of the sphere and the charge –Q which surround the inserted charge. In effect, the inserted charge +Q is surrounded by a cloud of opposite charge distributed over a certain distance. Beyond this distance the net charge becomes zero and the metallic interior will experience zero net electric field. (c) (5 pts) The electric charge density and field distributions are roughly given by × × × (5 pts) × × × × (5 pts) × × × × × 이 부분은 출제자 및 채점자를 위한 공간입니다. / Do not write your answer here: this is only for grading/marking. 문제번호 합계 1 2 3 4 5 6 7 8 9 10 11 12 Problem No. Total 점수 Score Page 1/2 Copyright ⓒ 2014 College of Science, Sungkyunkwan University (SKKU) SKKU-CS-009 3. [25 points] In the circuit shown in the Figure below, the switch S has been opened for a long time. Then it is suddenly closed. (a) (7 pts) Determine the time constant before the switch is closed. (b) (8 pts) Determine the time constant after the switch is closed. (c) (10 pts) When the switch be closed at , determine the current in the switch as a function of time . Answers: (a) (7 pts) (b) (8 pts) (c) (10 pts) 4. [25 points] Force on a semicircular conductor: A wire bent into a semicircle of radius forms a closed circuit and carries a current . The wire lies in the xy plane, and a uniform magnetic field is directed along the positive y axis as shown in the Figure right. (a) (10 pts) Find the magnitude and direction of the magnetic force acting on the curved portion. The Magnetic field created by a long current-carrying wire: A long, straight wire of radius carries a steady current that is uniformly distributed through the cross section of the wire (refer to the Figure right). (b) (10 pts) Calculate the magnetic field a distance from the center of the wire in the regions (i) ≥ and (ii) . (c) (5 pts) Draw the graph of the magnitude of the magnetic field as a function of a distance from the center of the wire in both regions ≥ and . Answers: (a) (10 pts) (b) (10 pts) * Note that the total current passing through the plane of the circle is I and apply Ampere’s law: Solve for B: Solve for B: *Now consider the interior of the wire, where r < R. Here the current I’ passing through the plane of circle 2 is less than the total current I. Set the ratio of the current I’ enclosed by circle 2 to the entire current I equal to the ratio of the area enclosed by circle 2 to the cross-sectional area of the wire: Solve for I’: * Apply Ampere’s law to circle 2: Solve for B: (c) (5 pts) Page 2/2 Copyright ⓒ 2014 College of Science, Sungkyunkwan University (SKKU)