www.shsph.blogspot.com Basic Calculus Quarter 3 – Module 1: Limits of Algebraic Functions using Tables and Graphs www.shsph.blogspot.com Basic Calculus – Grade 11 Alternative Delivery Mode Quarter 3 – Module 1: Limits of Algebraic Functions using Tables and Graphs First Edition, 2020 Republic Act 8293, section 176 states that: No copyright shall subsist in any work of the Government of the Philippines. However, prior approval of the government agency or office wherein the work is created shall be necessary for exploitation of such work for profit. Such agency or office may, among other things, impose as a condition the payment of royalties. Borrowed materials (i.e., songs, stories, poems, pictures, photos, brand names, trademarks, etc.) included in this module are owned by their respective copyright holders. Every effort has been exerted to locate and seek permission to use these materials from their respective copyright owners. 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Layug : Danilo C. Caysido : Joan T. Briz : Rosita P. Serrano REGIONAL OFFICE 3 MANAGEMENT TEAM: Regional Director Chief Education Supervisor, CLMD Education Program Supervisor, LRMS Education Program Supervisor, ADM : May B. Eclar, PhD, CESO III : Librada M. Rubio, PhD : Ma. Editha R. Caparas, EdD : Nestor P. Nuesca, EdD Printed in the Philippines by the Department of Education – Schools Division of Bataan Office Address: Provincial Capitol Compound, Balanga City, Bataan Telefax: (047) 237-2102 E-mail Address: bataan@deped.gov.ph www.shsph.blogspot.com Basic Calculus Quarter 3 – Module 1: Limits of Algebraic Functions using Tables and Graphs www.shsph.blogspot.com Introductory Message This Self-Learning Module (SLM) is prepared so that you, our dear learners, can continue your studies and learn while at home. Activities, questions, directions, exercises, and discussions are carefully stated for you to understand each lesson. Each SLM is composed of different parts. Each part shall guide you step-bystep as you discover and understand the lesson prepared for you. Pre-tests are provided to measure your prior knowledge on lessons in each SLM. This will tell you if you need to proceed on completing this module or if you need to ask your facilitator or your teacher’s assistance for better understanding of the lesson. At the end of each module, you need to answer the post-test to self-check your learning. Answer keys are provided for each activity and test. We trust that you will be honest in using these. In addition to the material in the main text, Notes to the Teacher are also provided to our facilitators and parents for strategies and reminders on how they can best help you on your home-based learning. Please use this module with care. Do not put unnecessary marks on any part of this SLM. Use a separate sheet of paper in answering the exercises and tests. And read the instructions carefully before performing each task. If you have any questions in using this SLM or any difficulty in answering the tasks in this module, do not hesitate to consult your teacher or facilitator. Thank you. www.shsph.blogspot.com What I Need to Know One of the main reasons why this module was created is to ensure that it will assist you to understand the concept and know the process of solving limits of a function. When you finish this module, you will be able to: 1. illustrate the limit of a function using table of values and graph of the function; and STEM_BC11LC-IIIa-1 2. distinguish between lim π(π₯) and π(π). STEM_BC11LC-IIIa-2 π₯→π What I Know I. Answer the following questions. Write your answer on a separate sheet of paper. 1. Evaluate lim (π₯ + 2) π₯→3 A. 1 2. Calculate lim ( π₯→7 π₯+1 2 B. 2 C. 7 D. 5 B. 5 C. 4 D. 2 B. 2 C. 4 D. 6 B. 2 C. 7 D. 3 C. 17 D. 16 ) A. 3 3. Determine lim (√π₯ − 2) π₯→11 A. 3 π₯+5 π₯→1 π₯+2 4. Find lim ( ) A. 1 5. Provide the value of lim(π₯ 2 + 5π₯ − 7 ) π₯→3 A. 13 B. 12 1 www.shsph.blogspot.com II. Graph the following set of ordered pairs using one Cartesian plane. (item numbers from 6-10) x y III. 0 1 1 2 2 3 3 4 4 5 Answer the following questions. Write your answer on a separate sheet of paper. 11. Solve lim (π₯ 2 + 5π₯ − 1) π₯→2 A. 11 12. B. 12 C. 4 D. 5 B. -2 C. – 3 D. 2 C. –3 D. 2 C. D. 6 Find lim (π₯ − 8) π₯→5 Determine lim (π₯ 2 − π₯ − 3) π₯→3 A. 3 15. B. 3 π₯→1 A. 3 14. D. 14 Evaluate lim ( 2π₯ 2 + 3π₯ − 2) A. 2 13. C. 13 B. –2 Provide the value of lim ( π₯→3 A. 3 π₯ 2 −9 π₯−3 ) B.4 2 5 www.shsph.blogspot.com Lesson 1 Limits of Algebraic Expressions using Tables and Graphs Everyone has their own limitation. Knowing your own limit helps you understand why some things are favorable to you and some are not. In this branch of Mathematics called Calculus, Limit is one of the important lessons that you need to understand because it plays a vital role in the application of differentiation towards a function. What’s In Complete the table of values and graph the ordered pairs using one Cartesian plane. Write your answer on a separate sheet of paper. π π=π−π 1 ? 2 ? 3 3 ? www.shsph.blogspot.com What’s New Read the situation and answer the question briefly. Situation: Have you experienced walking on a street and noticed an image of a small billboard from afar? Because of the distance, the message on that billboard is not readable. What action would you take to be able to see clearly and understand the message on that billboard? What is It • The limit of a function π(π₯) is the value it approaches as the value of π₯ approaches a certain value. “As π₯ approaches π, the limit of π(π₯) approaches L”. (Mercado, 2016) This is written in symbols as follows; π₯π’π¦ π(π) = π³ π→π • One sided limit is the value (πΏ) as the π value gets closer and closer to a certain value π from one side only (either from the left or from the right side). In symbols, π₯π’π¦ π(π) = π³ π₯π’π¦ π(π) = π³ π→π− π→π+ From the left side • From the right side Always remember that if the limit value from the left side is not equal to the limit value from the right, then the limit Does Not Exist or DNE. In symbols, if π₯π’π¦− π(π) = π³ π→π • ≠ π₯π’π¦ π(π) = π³ , then π₯π’π¦ π(π) π«π΅π¬ π→π+ π→π The limit of a function π₯π’π¦ π(π) = π³ is not the same as evaluating a function π→π π(π) because they are different in terms of concept. The limit of a function gets its value by providing inputs that approaches the particular number while evaluating a function is more like direct substitution process. 4 www.shsph.blogspot.com How to Illustrate the Limit of a Function Example: Express in mathematical symbol: limit of the function (π₯ + 3 ) as π₯ approaches 2 is equivalent to 5. Solution: Write down your given π(π₯) equivalent to (π₯ + 3). Your π is equal to 2 and your limit πΏ is 5. Then substitute into the limit expression lim π(π₯) = πΏ. π₯→π Answer: lim(π₯ + 3) = 5 π₯→2 How to Solve for the Limit of a Function Example: 1. With the given function π(π₯) = π₯ + 3, solve for its limit when π₯ approaches 2 and graph the function. Solution: Step 1: Create two tables of value, one for the inputs that approaches 2 from the left and the other is for the inputs that gets closer to 2 from the right side. (See figure below). π<π π(π) or π π>π π(π) or y Step 2: Choose π₯ − π£πππ’ππ that approach 2 from the left side and also from the right side. Remember that we cannot choose 2 because we are dealing with limits. (See the number line figure below). X – Values or (inputs) that approach 2 from the right side X – Values or (inputs) that approach 2 from the left side 5 www.shsph.blogspot.com After choosing π₯ − π£πππ’ππ that approach 2 from the left and from the right side, evaluate each input to its corresponding function and solve for its corresponding output. (Refer to the table of values below). π<π 0 1 1.5 1.9 1.99 1.999 1.9999 π>π 4 3 2.5 2.1 2.01 2.001 2.0001 π(π) or π 3 4 4.5 4.9 4.99 4.999 4.9999 π(π) or π 7 6 5.5 5.1 5.01 5.001 5.0001 Step 3: Now that the output values on both tables are solved, notice that it approach 5 as the inputs gets closer and closer to 2. We can illustrate both tables as one sided limits from the left lim−(π₯ + 3) = 5 and lim+(π₯ + 3) = 5 from the right. π₯→2 π₯→2 Step 4: Since both one sided limits from the left and right side is equivalent to 5, therefore the limit of the function π₯ + 3 as π₯ gets closer and closer to 2 is 5. In symbols, lim (π₯ + 3) = 5 π₯→2 How to Graph the Limit of a Function Use the coordinates from the table of values and plot them into a Cartesian plane. Graph of π(π₯) = π₯ + 3 On this area, it is evident that as the x-values approach 2 from the left and from the right, the y-values approach 5 from the left and from the right as well. 6 www.shsph.blogspot.com Example: π₯ 2 −1 ) π₯→1 π₯−1 2. Calculate lim ( and graph the function. On this particular given, evaluating the function π(1) = ( (1)2 −1 ) will (1)−1 result into 0 0 or indeterminate answer. But in the application of limits, there is a possibility that you’ll get a defined value. For this reason, we can say that solving for the limit of a function is different from evaluating a function. Solution: Step 1: Make two table of values, one for the inputs that approaches 1 from the left and the other is for the inputs that gets closer to 1 from the right side. (See figure below). π₯<1 π(π₯) or π¦ π₯>1 π(π₯) or y Step 2: Choose π₯ − π£πππ’ππ that approaches 1 from the left side and also from the right side. Remember that we cannot choose 1 because we are dealing with limits. After choosing π₯ − π£πππ’ππ that approaches 1 from the left and from the right side, evaluate each input to its corresponding function and solve for its corresponding output. (Refer to the table of values below). π₯<1 π(π₯) or π¦ 0.5 0.9 0.99 0.999 1.5 1.9 1.99 1.999 π₯>1 π(π₯) or y 1.5 1.1 1.01 1.0001 2.5 2.1 2.01 2.0001 Step 3: Once the output values on both tables were solved, notice that it approaches 2 as the inputs gets closer and closer to 1. We can illustrate both tables as one sided limits from the left lim− ( π₯→1 π₯ 2 −1 ) π₯−1 = 2 and lim+ ( π₯→1 π₯ 2 −1 ) π₯−1 = 2 from the right. Step 4: Since both one sided limits from the left and right side is equivalent to 2, therefore the limit of the function ( In symbols, π₯ 2 −1 ) π₯−1 as π₯ gets closer and closer to 1 is 2. lim ( π₯→1 π₯ 2 −1 π₯−1 )=2 Graph of the function: In a single Cartesian plane, plot the coordinates from the table of values. 7 www.shsph.blogspot.com Notice that a “hole’’ is visible on the graph because of the Graph of π (π₯ ) = 0 0 or indeterminate result when x=1. Nevertheless, the limit is obvious because it is evident here that as the xvalues approach 1 from the left and from the right, the yvalues approach 2 from the left and from the right as well. π₯ 2 −1 π₯−1 What’s More Read and answer the following items. Write your answers on a separate sheet of paper. 1. Evaluate lim(4 + π₯). π₯→2 π₯<2 Input from the left side π(π₯) or π¦ Output from the left side π₯>2 Input from the right side π(π₯) or y Output from the right side 0 1.5 1.99 1.9999 ? ? ? ? 3 2.5 2.01 2.0001 ? ? ? ? 8 www.shsph.blogspot.com One sided limits from the right One sided limits from the left lim (4 + π₯) = ____ lim (4 + π₯) = ____ π₯→2+ π₯→2− πππ (4 + π₯) = ____ π₯→2 Graph of the function: Use the coordinates from the table of values and plot them on the Cartesian plane below. π₯ 2 −2π₯−3 ). π₯−3 π₯→3 2. Solve lim ( π<π π(π) or π π>π π(π) or y 2.5 2.9 2.999 2.99999 ? ? ? ? 3.5 3.1 3.001 3.00001 ? ? ? ? One sided limits from the left πππ− ( π₯→3 One sided limits from the right π₯ 2 − 2π₯ − 3 ) = ___ π₯−3 πππ ( π₯→3 πππ+ ( π₯→3 π₯ 2 − 2π₯ − 3 ) = ___ π₯−3 9 π₯ 2 − 2π₯ − 3 ) = ___ π₯−3 www.shsph.blogspot.com Graph of the function: Use the coordinates from the table of values and plot them on the Cartesian plane. What I Have Learned Express what you have learned in this lesson by completing the sentences below. Use a separate paper for your answers. 1. The limit of a function is ___________________________________________. 2. One sided limit of a function is _____________________________________. 3. Is the limit of a function similar as evaluating a function? Explain briefly. ____________________________________________________________________ 4. How can you solve the limit of a function? Explain briefly based on your own understanding. ____________________________________________________ What I Can Do Read and answer the given question below. Use a separate paper for your answers. π₯ + 3, π₯ > 3 Suppose you are given a piecewise function π(π₯) = { , evaluate the π₯² − 3, π₯ ≤ 3 limit of this function as π₯ approaches 3. Use the steps shown to you to get the final answer. 10 www.shsph.blogspot.com Assessment I. Calculate the limits of the following functions. Write your answer on a separate sheet of paper. 1. lim (π₯ − 10) π₯→6 A. 4 B. -4 C. – 5 D. 5 B. -7 C. – 6 D. 6 B. -13 C. 12 D. -12 B. -2 C. 2 D. 3 B. 2 C. 3 D. 0 2. lim (π₯ 2 + 5π₯ − 7) π₯→2 A. 7 3. lim ( π₯ 2 −36 π₯→6 π₯−6 ) A. 13 4. lim (3π₯ − 10) π₯→4 A. – 3 5. lim (π₯ 2 + 4π₯ − 5) π₯→1 A. 1 II. Read, analyze, and write the letter of the correct answer on a separate sheet of paper. 6. If the left side limit of a function is not equal to the right-side limit, then the limit exists. A. True B. False C. Not Sure D. No answer 7. If the left side limit of a function is equal to the right-side limit, then the limit does not exist. A. True B. False C. Not Sure D. No answer 8. One sided limit from the left side is illustrated as lim+ π(π₯). π₯→π A. True B. False C. Not Sure D. No answer 9. One sided limit from the right side is illustrated as lim− π(π₯). π₯→π A. True B. False C. Not Sure D. No answer 10. There is no difference between the limit of a function and evaluating a function. A. True B. False C. Not Sure D. No answer 11 www.shsph.blogspot.com III. For questions 11 to 15, refer to the graph below and write the letter of the correct answer on a separate sheet of paper. πΊπππβ ππ π(π₯) 11. Calculate lim+ π(π₯) π₯→3 A. 1 B. 2 C. 3 D. 4 B. 1 C. 3 D. 4 B. 1 C. 2 D. 4 B. 3 C. 1 D. DNE B. 2 C. 3 D. DNE 12. Solve lim− π(π₯) A. 2 π₯→3 13. Determine lim π(π₯) π₯→−3 A. 3 14. Evaluate lim π(π₯) π₯→3 A. 2 15. Find lim + π(π₯) A. 1 π₯→−3 12 www.shsph.blogspot.com Additional Activities Read, understand, and solve the given problem below. Use a separate sheet of paper for your answer. Vic and Joey argue about the limit of the function π(π₯) = 1 π₯ as π₯ approaches 0 . Vic’s opinion is that the limit is 0 while Joey claims that the limit does not exist. Write a short explanation that discusses the pros and cons of Vic and Joey’s opinion. 13 14 What’s More What’s More 1. 2. Assessment 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. B A C C D B B B B B A B C C B What's New Answers may vary. What I Know What's In x y 1 0 2 1 1. 2. 3. 4. 5. 3 2 D C A B C 6-10. Additional Activities Joey is correct and Vic is wrong base on their own answers about the limit of the function because their one sided limits is different from each other, therefore the limit does not exist. 11. 12. 13. 14. 15. C B C A D Answer Key www.shsph.blogspot.com www.shsph.blogspot.com References DepEd. 2013. Basic Calculus. Teachers Guide. Lim, Yvette F., Nocon, Rizaldi C., Nocon, Ederlina G., and Ruivivar, Leonar A. 2016. Math for Engagement Learning Grade 11 Basic Calculus. Sibs Publishing House, Inc. Mercado, Jesus P., and Orines, Fernando B. 2016. Next Century Mathematics 11 Basic Calculus. Phoenix Publishing House, Inc. Geogebra. Graphing application for android. Playstore. 15 www.shsph.blogspot.com For inquiries or feedback, please write or call: Department of Education – Region III, Schools Division of Bataan - Curriculum Implementation Division Learning Resources Management and Development Section (LRMDS) Provincial Capitol Compound, Balanga City, Bataan Telefax: (047) 237-2102 Email Address: bataan@deped.gov.ph